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FUNGSI EKSPONEN DAN
FUNGSI LOGARITMA
Nerisa Agnesia W, SP., M.Si
FUNGSI Logaritma
1. Eksponen
a. Pengertian Eksponen
b. Sifat – Sifat Fungsi Eksponen
c. Persamaan Eksponen
d. Pertidaksamaan Eksponen
2. Logaritma
a. Pegertian Logaritma dan
Grafiknya
b. Sifat – Sifat Fungsi Logaritma
c. Pemodelan Fungsi Logaritma
 Fenomena Citayam Fashion Week ternyata berawal dari para remaja,
yang berkumpul di kawasan Sudirman, Jakarta Pusat, hanya untuk
sekadar nongkrong dan mencari hiburan dengan
mengenakan fashion atau outfit yang nyentrik. Hingga konsep catwalk ala
model profesional terealisasikan, untuk memenuhi kebutuhan konten di
sosial media.
 Asal mula nama Citayam Fashion Week muncul dan menjadi viral
 Remaja yang berkumpul di sana kebanyakan berasal dari daerah
Sudirman, Citayam, Bojonggede, dan Depok.
 Misalkan remaja yang berasal dari masing –masing daerah ada 5 orang
setiap minggunya yang nongkrong di kawasan Sudirman dan dalam waktu
1 bulan ada 40 orang yang ikut nongkrong.
 Berapa waktu yang dibutuhkan ketika jumlah remaja yang nongkrong
menjadi 100 orang?
Logaritma merupakan invers dari eksponen atau
perpangkatan sehingga bentuk dan hubungannya dengan
eksponen sebagai berikut:
0
b
Numerus,
b
1
a
dan
0
a
pokok,
Bilangan
a
:
dengan
c
b
log
b
a a
c








 Diberikan fungsi logaritma f(x) = ³log x,
tentukan nilai dari f(3) dan f (81)
 Penyelesaian :f(x) = f(3) = ³log 3 = 1
f(x) = f (81) =³log 81 =4
 Siswa secara berkelompok 3 -4
orang,meentukan penyelesaian soal Fungsi
Logaritma yang dibuat oleh mereka di masing
–masing kelompok
 1 kelompok minimal 2 soal
 https://www.konsep-
matematika.com/2016/11/menentukan-
fungsi-logaritma-dari.html
 
b
b
log
.
a
.
8
a
log
1
a
log
b
log
b
log
7.
c
log
c
log
.
b
log
6.
b
log
m
n
b
log
5.
b
log
n
b
log
4.
y
log
-
x
log
y
x
log
3.
y
log
x
log
x.y
log
2.
1
a
log
.
1
a
a
a
a
a
a
n
a
a
n
a
a
a
a
a
a
a
a
m


















b
Persamaan logaritma adalah persamaan yang variabelnya
sebagai numerus atau sebagai bilangan pokok dari suatu
logaritma
Contoh :
 
t
iabel
memuat var
pokonya
bilangan
dan
numerus
yang
logaritma
persamaan
Merupakan
-2
2t
log
2
-
t
log
x
iabel
memuat var
pokoknya
bilangan
yang
logaritma
persamaan
Merupakan
2
2
log
5
log
m
iabel
memuat var
numerusnya
yang
logaritma
persamaan
Merupakan
0
m
log
4m
log
x
iabel
memuat var
numerusnya
yang
logaritma
persamaan
Merupakan
1
1)
(2x
log
x
log
2
2t
x
x
2
5
5









t
 
      m
x
f
x
f
x
x
a
a
a
a
maka
,
0
m,
log
log
jika
m
log
log
.
1




   
      1
maka
b,
,
log
log
jika
log
log
.
2
b
b




x
f
a
x
f
x
f
x
f
x
f
a
a
   
           
x
g
x
f
x
g
x
f
a
a
x
g
x
f
x
g
x
f
a
a
a
a







maka
,
0
dan
,
0
,
1
,
0
,
log
log
jika
log
log
.
3
 
   
 
 
   
             
x
h
x
g
x
f
x
h
x
g
x
f
x
h
x
x
h
x
x
f
x
f
x
f
x
f







maka
,
1
dan
0
,
0
,
0
,
log
g
log
jika
log
g
log
.
4
   
 
  x
x
f
y
y
y
p
x
f
y
C
x
f
B
x
f
p
p
nilai
memperoleh
kita
sehingga
,
log
pemisalan
pada
kembali
usi
persubstit
kita
yang
Nilai
0
C
B
A
diperoleh
ini,
permisalan
Dari
.
log
misalkan
dahulu,
Terlebih
0
log
log
A
.
5
2
p
2
p








3
5
2
log
.
3
5
2
log
log32
.
5
1
-
5
1
log
4.
3
-
2
1
log
8
log
3.
1
3
1
log
2.
0
1
log
.
1
2
5
2
8
5
3
2
1
2
1
3
1
4
3















 
 
 
 
 
   
   
 
    2
atau
2
adalah
3
log
3
log
an
penyelesai
jadi,
2
atau
2
4
1
3
log
3
log
3
log
:
Jawab
?
3
log
3
log
an
penyelesai
h
Tentukanla
2.
18
adalah
4
2
log
an
penyelesai
jadi,
18
2
2
2
log
2
log
4
2
log
:
Jawab
?
4
2
log
an
penyelesai
h
Tentukanla
.
1
2
4
2
2
2
2
4
2
2
4
2
2
4
2
2
2
2
2






























x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x



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7._FUNGSI_LOGARITMA.ppt

  • 1. FUNGSI EKSPONEN DAN FUNGSI LOGARITMA Nerisa Agnesia W, SP., M.Si FUNGSI Logaritma
  • 2. 1. Eksponen a. Pengertian Eksponen b. Sifat – Sifat Fungsi Eksponen c. Persamaan Eksponen d. Pertidaksamaan Eksponen 2. Logaritma a. Pegertian Logaritma dan Grafiknya b. Sifat – Sifat Fungsi Logaritma c. Pemodelan Fungsi Logaritma
  • 3.  Fenomena Citayam Fashion Week ternyata berawal dari para remaja, yang berkumpul di kawasan Sudirman, Jakarta Pusat, hanya untuk sekadar nongkrong dan mencari hiburan dengan mengenakan fashion atau outfit yang nyentrik. Hingga konsep catwalk ala model profesional terealisasikan, untuk memenuhi kebutuhan konten di sosial media.  Asal mula nama Citayam Fashion Week muncul dan menjadi viral  Remaja yang berkumpul di sana kebanyakan berasal dari daerah Sudirman, Citayam, Bojonggede, dan Depok.  Misalkan remaja yang berasal dari masing –masing daerah ada 5 orang setiap minggunya yang nongkrong di kawasan Sudirman dan dalam waktu 1 bulan ada 40 orang yang ikut nongkrong.  Berapa waktu yang dibutuhkan ketika jumlah remaja yang nongkrong menjadi 100 orang?
  • 4. Logaritma merupakan invers dari eksponen atau perpangkatan sehingga bentuk dan hubungannya dengan eksponen sebagai berikut: 0 b Numerus, b 1 a dan 0 a pokok, Bilangan a : dengan c b log b a a c        
  • 5.  Diberikan fungsi logaritma f(x) = ³log x, tentukan nilai dari f(3) dan f (81)  Penyelesaian :f(x) = f(3) = ³log 3 = 1 f(x) = f (81) =³log 81 =4
  • 6.  Siswa secara berkelompok 3 -4 orang,meentukan penyelesaian soal Fungsi Logaritma yang dibuat oleh mereka di masing –masing kelompok  1 kelompok minimal 2 soal
  • 9. Persamaan logaritma adalah persamaan yang variabelnya sebagai numerus atau sebagai bilangan pokok dari suatu logaritma Contoh :   t iabel memuat var pokonya bilangan dan numerus yang logaritma persamaan Merupakan -2 2t log 2 - t log x iabel memuat var pokoknya bilangan yang logaritma persamaan Merupakan 2 2 log 5 log m iabel memuat var numerusnya yang logaritma persamaan Merupakan 0 m log 4m log x iabel memuat var numerusnya yang logaritma persamaan Merupakan 1 1) (2x log x log 2 2t x x 2 5 5          t
  • 10.         m x f x f x x a a a a maka , 0 m, log log jika m log log . 1               1 maka b, , log log jika log log . 2 b b     x f a x f x f x f x f a a                 x g x f x g x f a a x g x f x g x f a a a a        maka , 0 dan , 0 , 1 , 0 , log log jika log log . 3                             x h x g x f x h x g x f x h x x h x x f x f x f x f        maka , 1 dan 0 , 0 , 0 , log g log jika log g log . 4         x x f y y y p x f y C x f B x f p p nilai memperoleh kita sehingga , log pemisalan pada kembali usi persubstit kita yang Nilai 0 C B A diperoleh ini, permisalan Dari . log misalkan dahulu, Terlebih 0 log log A . 5 2 p 2 p        
  • 12.                         2 atau 2 adalah 3 log 3 log an penyelesai jadi, 2 atau 2 4 1 3 log 3 log 3 log : Jawab ? 3 log 3 log an penyelesai h Tentukanla 2. 18 adalah 4 2 log an penyelesai jadi, 18 2 2 2 log 2 log 4 2 log : Jawab ? 4 2 log an penyelesai h Tentukanla . 1 2 4 2 2 2 2 4 2 2 4 2 2 4 2 2 2 2 2                               x x x x x x x x x x x x x x x x x x x
  • 13.
  • 14.