You need to know the solubility rules in order to answer this question. When HCl is
added and forms a precipitate, we\'re looking for something that is insoluble when combined
with chlorine atoms. That would be Hg+. So we know that is in the starting solution for sure. The
first precipitate would be HgCl. Next, H2SO4 is added and a precipitate is formed so we\'re
looking for a cation that is insoluble when combined with sulfate (SO4^2-) This would be Ca2+.
(Hg+ would work too except we removed all of those ions when we removed the first
precipitate.) So, the second precipitate would be CaSO4 Next, NaOH is added and according to
the solubility rules, we know that hydroxides are generally all insoluble except when they are
combined with ammonium ion or any Group I ions. So since no precipitate is formed, none of
the other cations can be in the starting solution because if they were, then a precipitate would
have been formed with OH. So, the only cations that were present in the original solution were
Ca2+ and Hg+.
Solution
You need to know the solubility rules in order to answer this question. When HCl is
added and forms a precipitate, we\'re looking for something that is insoluble when combined
with chlorine atoms. That would be Hg+. So we know that is in the starting solution for sure. The
first precipitate would be HgCl. Next, H2SO4 is added and a precipitate is formed so we\'re
looking for a cation that is insoluble when combined with sulfate (SO4^2-) This would be Ca2+.
(Hg+ would work too except we removed all of those ions when we removed the first
precipitate.) So, the second precipitate would be CaSO4 Next, NaOH is added and according to
the solubility rules, we know that hydroxides are generally all insoluble except when they are
combined with ammonium ion or any Group I ions. So since no precipitate is formed, none of
the other cations can be in the starting solution because if they were, then a precipitate would
have been formed with OH. So, the only cations that were present in the original solution were
Ca2+ and Hg+..
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
You need to know the solubility rules in order to.pdf
1. You need to know the solubility rules in order to answer this question. When HCl is
added and forms a precipitate, we're looking for something that is insoluble when combined
with chlorine atoms. That would be Hg+. So we know that is in the starting solution for sure. The
first precipitate would be HgCl. Next, H2SO4 is added and a precipitate is formed so we're
looking for a cation that is insoluble when combined with sulfate (SO4^2-) This would be Ca2+.
(Hg+ would work too except we removed all of those ions when we removed the first
precipitate.) So, the second precipitate would be CaSO4 Next, NaOH is added and according to
the solubility rules, we know that hydroxides are generally all insoluble except when they are
combined with ammonium ion or any Group I ions. So since no precipitate is formed, none of
the other cations can be in the starting solution because if they were, then a precipitate would
have been formed with OH. So, the only cations that were present in the original solution were
Ca2+ and Hg+.
Solution
You need to know the solubility rules in order to answer this question. When HCl is
added and forms a precipitate, we're looking for something that is insoluble when combined
with chlorine atoms. That would be Hg+. So we know that is in the starting solution for sure. The
first precipitate would be HgCl. Next, H2SO4 is added and a precipitate is formed so we're
looking for a cation that is insoluble when combined with sulfate (SO4^2-) This would be Ca2+.
(Hg+ would work too except we removed all of those ions when we removed the first
precipitate.) So, the second precipitate would be CaSO4 Next, NaOH is added and according to
the solubility rules, we know that hydroxides are generally all insoluble except when they are
combined with ammonium ion or any Group I ions. So since no precipitate is formed, none of
the other cations can be in the starting solution because if they were, then a precipitate would
have been formed with OH. So, the only cations that were present in the original solution were
Ca2+ and Hg+.
