Specific heat of water = 4.184 J/g.oC Heat released by dissolution = Heat absorbed by solution = mass of solution (NaOH + water) x specific heat of water x temperature change = (2.0 + 49.0) x 4.184 x 10.5 = 2240.532 J Moles of NaOH = mass of NaOH/molar mass of NaOH = 2.0/40.00 = 0.05 mol Heat of dissolution H = -heat released by dissolution/moles of NaOH = -2240.532/0.05 = -4.48 x 104 J/mol (H is negative as the dissolution is exothermic) Solution Specific heat of water = 4.184 J/g.oC Heat released by dissolution = Heat absorbed by solution = mass of solution (NaOH + water) x specific heat of water x temperature change = (2.0 + 49.0) x 4.184 x 10.5 = 2240.532 J Moles of NaOH = mass of NaOH/molar mass of NaOH = 2.0/40.00 = 0.05 mol Heat of dissolution H = -heat released by dissolution/moles of NaOH = -2240.532/0.05 = -4.48 x 104 J/mol (H is negative as the dissolution is exothermic).