Write a method named convertInfixToPostfix that accepts an Infix exp.pdf
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Write a method named convertInfixToPostfix that accepts an Infix expression as a parameter and converts it to its Postfix equivalent by implementing the algorithm given in Figure 6.10 of the required text book. Note that the Infix expression does not need to be a fully parenthesized expression. Your method should have the following signature and should be included in a class called ExpressionConversion. public String convertInfixToPostfix(String infixExp) { /* your implementation here*/ } Solution import java.util.Scanner; //for user input public class ExpressionConversion { public static void main(String[] args) //main function { String infixExp,postfixExp; Scanner in = new Scanner(System.in); System.out.println(\"Enter Infix Expression : \"); infixExp = in.next(); postfixExp = convertInfixToPostfix(infixExp); System.out.println(\"Postfix Expression : \" + postfixExp); } public static String convertInfixToPostfix(String infixExp) //function to convert infix to postfix { int len = infixExp.length(); Stack s = new Stack(len); int i=0; char op; String postfixExp = \"\"; for(i=0; i < len; i++) { if(infixExp.charAt(i) == \'+\' || infixExp.charAt(i) == \'-\' || infixExp.charAt(i) == \'*\' || infixExp.charAt(i) == \'/\' || infixExp.charAt(i) == \'(\' || infixExp.charAt(i) == \')\') { switch(infixExp.charAt(i)) { case \'(\' : s.push(infixExp.charAt(i)); break; case \')\' : op = s.pop(); while(op != \'(\') { postfixExp = postfixExp + op; op = s.pop(); } break; default: while(preceed(s.peek()) >= preceed(infixExp.charAt(i))) postfixExp = postfixExp + s.pop(); s.push(infixExp.charAt(i)); } } else postfixExp = postfixExp + infixExp.charAt(i); } while(!s.isEmpty()) postfixExp = postfixExp + s.pop(); return postfixExp; } static int preceed(char st) //function to check the precedenceof operators { switch(st) { case \'*\' : case \'/\' : return 3; case \'+\' : case \'-\' : return 2; default : return 1; } } } class Stack //creating stack to implement infix to postfix conversion { int maxSize; char[] stackArray; int top; public Stack(int max) { maxSize = max; stackArray = new char[maxSize]; top = -1; } public void push(char item) { stackArray[++top] = item; } public char pop() { return stackArray[top--]; } public char peek() { if(!isEmpty()) return stackArray[top]; else return 0; } public boolean isEmpty() { return (top == -1); } }.
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![Write a method named convertInfixToPostfix that accepts an Infix expression as a parameter and
converts it to its Postfix equivalent by implementing the algorithm given in Figure 6.10 of the
required text book. Note that the Infix expression does not need to be a fully parenthesized
expression.
Your method should have the following signature and should be included in a class called
ExpressionConversion.
public String convertInfixToPostfix(String infixExp) { /* your implementation here*/ }
Solution
import java.util.Scanner; //for user input
public class ExpressionConversion
{
public static void main(String[] args) //main function
{
String infixExp,postfixExp;
Scanner in = new Scanner(System.in);
System.out.println("Enter Infix Expression : ");
infixExp = in.next();
postfixExp = convertInfixToPostfix(infixExp);
System.out.println("Postfix Expression : " + postfixExp);
}
public static String convertInfixToPostfix(String infixExp) //function to convert infix to
postfix
{
int len = infixExp.length();
Stack s = new Stack(len);
int i=0;
char op;
String postfixExp = "";
for(i=0; i < len; i++)
{
if(infixExp.charAt(i) == '+' || infixExp.charAt(i) == '-' || infixExp.charAt(i) == '*' ||
infixExp.charAt(i) == '/' || infixExp.charAt(i) == '(' || infixExp.charAt(i) == ')')](https://image.slidesharecdn.com/writeamethodnamedconvertinfixtopostfixthatacceptsaninfixexp-230904003515-fd08e937/85/Write-a-method-named-convertInfixToPostfix-that-accepts-an-Infix-exp-pdf-1-320.jpg)
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You will certainly have simpler approaches, correct my mistakes and complete the ones I did not finish. Some of the examples where as par my following lessons examples from the books I read, please observe and give all due copyrights to these wonderful authors.
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slide3:function advantages
slide4 -5: types of functions
slide6: elements of user defined functions
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You will certainly have simpler approaches, correct my mistakes and complete the ones I did not finish. Some of the examples where as par my following lessons examples from the books I read, please observe and give all due copyrights to these wonderful authors.
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You can look at the Java programs in the text book to see how comments are added to programs.
Minimal Submitted Files
You are required, but not limited, to turn in the following source files:
Assignment6.java (No need to modify)
Movie.java (No need to modify, modified version from the assignment 4)
Review.java (No need to modify)
CreatePane.java - to be completed
ReviewPane.java - to be completed
You might need to add more methods than the specified ones.
Skills to be Applied:
JavaFX, ArrayList
Classes may be needed:
Button, TextField, TextArea, Label, RadioButton, ListView, and ActionHandler. You may use other classes.
Here is the Assignmnet6.java:
import javafx.application.Application;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.control.Tab;
import javafx.scene.control.TabPane;
import javafx.scene.layout.StackPane;
import java.util.ArrayList;
public class Assignment6 extends Application
{
private TabPane tabPane;
private CreatePane createPane;
private ReviewPane reviewPane;
private ArrayList movieList;
public void start(Stage stage)
{
StackPane root = new StackPane();
//movieList to be used in both createPane & reviewPane
movieList = new ArrayList();
reviewPane = new ReviewPane(movieList);
createPane = new CreatePane(movieList, reviewPane);
tabPane = new TabPane();
Tab tab1 = new Tab();
tab1.setText("Movie Creation");
tab1.setContent(createPane);
Tab tab2 = new Tab();
tab2.setText("Movie Review");
tab2.setContent(reviewPane);
tabPane.getSelectionModel().select(0);
tabPane.getTabs().addAll(tab1, tab2);
root.getChildren().add(tabPane);
Scene scene = new Scene(root, 700, 400);
stage.setTitle("Movie Review Apps");
stage.setScene(scene);
stage.show();
}
public static void main(String[] args)
{
launch(args);
}
}
Here is Movie.java:
public class Movie
{
private String movieTitle;
private int year;
private int length;
private Review bookReview;
//Constructor to initialize all member variables
public Movie()
{
movieTitle = "?";
length = 0;
year = 0;
bookReview = new Review();
}
//Accessor methods
public String getMovieTitle()
{
return movieTitle;
}
public int getLength()
{
return length;
}
public int getYear()
{
return year;
}
public Review getReview()
{
return bookReview;
}
//Mutator methods
public void setMovieTitle(String aTitle)
{
movieTitle = aTitle;
}
public void setLength(int aLength)
{
length = aLength;
}
public void setYear(int aYear)
{
year = aYear;
}
public void addRating(double rate)
{
book ...
How to build to do app using vue composition api and vuex 4 with typescript
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Description of programYou are to write a program name InfixToPost.pdf
Description of program:
You are to write a program name InfixToPostfix.java that converts an infix expression entered
by the user to a postfix expression. The expression may contain the following tokens:
(1) Integer constants (a series of decimal digits).
(2) x (representing a value to be supplied later).
(3) Binary operators (+, -, *, / and %).
(4) Parentheses
Spaces between tokens are allowed but not required. The program will convert the expression to
postfix form and display the converted expression. Upload the file into A7 folder of icollege.
Sample Output:
Enter infix expression: (x + 1) * (x – 2) / 4
Converted expression: x 1 + x 2 - * 4 /
Enter infix expression: 1 2 +
Error in expression!! No operator between operands. Also last token must be an operand.
Enter infix expression: 10.4
Error in expression!! Cannot accept floating point numbers.
Enter infix expression: 1 ( + 2)
Error in expression!! No operator between operand and left parentheses.
Enter infix expression: 5 – (x – 2))
Error in expression!! No matching left parentheses for a right parentheses.
Enter infix expression: 1 ** 2
Error in expression!! The * operator cannot be preceded by a * operator.
Solution
//program for infix to posrtfix convertion
import java.io.*;
class stack
{
char stack1[]=new char[20];
int top;
void push(char ch)
{
top++;
stack1[top]=ch;
}
char pop()
{
char ch;
ch=stack1[top];
top--;
return ch;
}
int pre(char ch)
{
switch(ch)
{
case \'-\':return 1;
case \'+\':return 1;
case \'*\':return 2;
case \'/\':return 2;
}
retrun 0;
}
boolean operator(char ch)
{
if(ch==\'/\'||ch==\'*\'||ch==\'+\'||ch==\'-\')
return true;
else
return false;
}
boolean isAlpha(char ch)
{
if(ch>=\'a\'&&ch<=\'z\'||ch>=\'0\'&&ch==\'9\')
return true;
else
return false;
}
void postfix(String str)
{
char output[]=new char[str.length()];
char ch;
int p=0,i;
for(i=0;ipre(stack1[top])) || stack1[top]==\'(\')
{
push(ch);
}
}
else if(pre(ch)<=pre(stack1[top]))
{
output[p++]=pop();
push(ch);
}
else if(ch==\'(\')
{
while((ch=po())!=\'(\')
{
output[p++]=ch;
}
}
}
while(top!=0)
{
output[p++]=pop();
}
for(int j=0;j.
2. Stack. Write a program that uses the stack class (you can use.pdf
2. Stack. Write a program that uses the stack class (you can use the stack type defined in the
lectures, or you can define your own stack type) to solve a problem. The problem contains two
tasks, the first one is to convert an infix arithmetic expression into a postfix arithmetic
expression; the second task is to evaluate arithmetic expressions written in postfix form.
In infix form, the operator of an arithmetic statement is in-between every pair of operands. For
example:
1.5 + 2.3
2.0 * (3.3 + 4.5)
(2.1 + 3.0) * 4.8
In postfix form, the operands of an arithmetic statement appear followed by the operator. One of
the virtues of postfix form is that expressions can be written without the need for parentheses.
Here are some examples of arithmetic expressions written in postfix form:
1.5 2.3 + // Equivalent to 1.5 + 2.3
2.0 3.3 4.5 + * // Equivalent to 2.0 * (3.3 + 4.5)
2.1 3.3 + 4.8 * // Equivalent to (2.1 + 3.0) * 4.8
Please write a C++ program that uses an operator stack to convert an infix arithmetic expression
that the user enters into a postfix arithmetic expression, and then use a float stack to evaluate
postfix arithmetic.
Your program should support all five of the arithmetic operators, +, - , *, and /.
When users input the infix arithmetic expressions, the operands, operators and parenthesis
symbols are separated by spaces. The character # marks the end of the expression.
The infix arithmetic expressions only contain operands, operators and parenthesis. The operands
are float numbers, and the operators are +, -, * and /. If there are letters in the infix arithmetic
expressions, the “invalid expression” message should be displayed.
Here is an algorithm for evaluating an arithmetic expression written in postfix form with the aid
of a stack of floats.
• Scan the expression from left to right.
• When encounter an operand or a float, push it on the stack.
• When encounter an arithmetic operator, pop the top two numbers off the stack and use them as
operands for the indicated operation. Push the resulting number back on the stack.
• when you reach the end of the expression, the result of the calculation should be the sole item
on the stack.
Please show that that the program is working correctly by converting the following infix
arithmetic expressions and then computing the obtained postfix arithmetic expressions:
6.5 * 6.5 - 4 * 1.5 * 1.44 #
3.1 * (2.5 + 4.7 * 1.6) + 8.6 #
70.0 - (10.5 + 6) / 0.5 + 18.2 #
The following steps will convert an infix expression into a postfix expression:
1. Create an empty string stack called opStack for keeping operators. Create an empty string
array called postfixEx for postfix expression.
2. read the infix expression left to right.
2.1. If the string is an operand, append it to the postfixEx array.
2.2. If the string is a left parenthesis, push it on the opStack.
2.3. If the string is a right parenthesis, pop the opStack, append each operator to the postfixEx
array, until you see the corresponding left parent.
Description of a JAVA programYou are to write a program name Infi.pdf
Cost-Volume-Profit Analysis and Special Order Short-term decision making PART 1 Funai
Corporation is a Japanese manufacturer of video cassette recorders (VCRs) and was established
in 1987. There is now increased competition in its markets and the firm expects to find it difficult
to make an acceptable profit next year. You have been appointed as a management accountant at
the company, and have been given a copy of the draft budget for the next financial year. Draft
Budget for 12 months to 30th September 2019 (£m) (£m) Sales revenue 960 Cost of sales
Variable assembly materials 374.4 Variable labour 192 Factory overheads - variable 172.8 -
fixed 43 (782.2) Gross profit 177.8 Selling overhead - commission (variable) 38.4 - fixed 108
Administration overhead - fixed 20 (166.4) Net profit 11.4 The following information is also
supplied to you by the firm’s financial controller, John Smith: a) Planned sales for the draft
budget in the year to 30th September 2019 are expected to be 25% less than the total of 3.2
million VCR units sold in the previous financial year. b) The firm operates a Just-in-time stock
control system, which means that it holds no stocks of any kind. c) If more than 3 million VCR
units are made and sold, the unit cost of material falls by £4 per unit. d) Sales commission is
based on the number of units sold and not on turnover. 2 e) The draft budget assumes that the
factory will only be working at two-thirds of maximum capacity. f) Sales above maximum
capacity are not possible. Questions: 1) Calculate the Total contribution margin and contribution
margin per unit, showing your working. [5 marks] 2) Calculate the Break-even-point (BEP) in
units and BEP in sales revenues, showing your working. [3 marks] PART 2 John Smith explains
that the Board is not happy with the profit projected in the draft budget, and that the sales
director, Mary Ford, has produced three proposals to try and improve matters. Proposal A –
involves launching an aggressive marketing campaign: i. This would involve a single additional
fixed cost of £14 million for advertising. ii. There would be a revised commission payment of
£18 per unit sold. iii. Sales volume would be expected to increase by 10% above the level
projected in the draft budget, with no charge in the unit selling price. Proposal B – involves a 5%
reduction in the unit selling price: i. This is estimated to bring the sales volume back to the level
in the previous financial year. Proposal C – involves a 10% reduction in the unit selling price: i.
Fixed selling overhead would also be reduced by £45 million. ii. If proposal C is accepted, the
sales director believes sales volume will be 3.8 million units. Questions: 3) For Proposal A,
calculate: 3.1) the change in profit compared with the draft budget [4 marks] 3.2) the BEP point
in units and sales revenues. [3 marks] 4) For Proposal B, calculate: 4.1) the change in profit
compared with the draft budget [4 marks] 4.2) the BEP point in units and sal.
From object oriented to functional domain modeling
"From object oriented to functional domain modeling" by Mario Fusco
Malgrado l'introduzione delle lambda, la gran parte degli sviluppatori Java non è ancora abituata agli idiomi della programmazione funzionale e quindi non è pronta a sfruttare a pieno le potenzialità di Java 8. In particolare non è ancora comune vedere dati e funzioni usate insieme quando si modella un dominio di business. Lo scopo del talk è mostrare come alcuni principi di programmazione funzionale quali l'impiego di oggetti e strutture dati immutabili, l'uso di funzioni senza side-effect e il loro reuso mediante composizione, possono anche essere validi strumenti di domain modelling.
From object oriented to functional domain modeling
From object oriented to functional domain modeling
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7. Which statements about financial forecasting is most likely TRUE.pdf
7. Which statements about financial forecasting is most likely TRUE:
a. Net income flows through to cash flows from operations on the balance sheet
b. Net income flows to shareholders equity on the cash flow statement
c. Marketable securities is the same as cash on the balance sheet
d. Marketable securities is the same as short term debt on the balance sheet
e. Marketable securities is good to use as a plug figure when forecasting financial statements
Solution
e. Marketable securities is good to use as a plug figure when forecasting financial statements.
Thanks.
Inputs in the light reaction of photosynthesis Inputs in the li.pdf
Inputs in the light reaction of photosynthesis
Inputs in the light reaction of photosynthesis
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Inputs in the light reaction of photosynthesis are
Light energy, ADP, Pi, NADP and H2O
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Similar to Write a method named convertInfixToPostfix that accepts an Infix exp.pdf
You can look at the Java programs in the text book to see how commen
You can look at the Java programs in the text book to see how comments are added to programs.
Minimal Submitted Files
You are required, but not limited, to turn in the following source files:
Assignment6.java (No need to modify)
Movie.java (No need to modify, modified version from the assignment 4)
Review.java (No need to modify)
CreatePane.java - to be completed
ReviewPane.java - to be completed
You might need to add more methods than the specified ones.
Skills to be Applied:
JavaFX, ArrayList
Classes may be needed:
Button, TextField, TextArea, Label, RadioButton, ListView, and ActionHandler. You may use other classes.
Here is the Assignmnet6.java:
import javafx.application.Application;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.control.Tab;
import javafx.scene.control.TabPane;
import javafx.scene.layout.StackPane;
import java.util.ArrayList;
public class Assignment6 extends Application
{
private TabPane tabPane;
private CreatePane createPane;
private ReviewPane reviewPane;
private ArrayList movieList;
public void start(Stage stage)
{
StackPane root = new StackPane();
//movieList to be used in both createPane & reviewPane
movieList = new ArrayList();
reviewPane = new ReviewPane(movieList);
createPane = new CreatePane(movieList, reviewPane);
tabPane = new TabPane();
Tab tab1 = new Tab();
tab1.setText("Movie Creation");
tab1.setContent(createPane);
Tab tab2 = new Tab();
tab2.setText("Movie Review");
tab2.setContent(reviewPane);
tabPane.getSelectionModel().select(0);
tabPane.getTabs().addAll(tab1, tab2);
root.getChildren().add(tabPane);
Scene scene = new Scene(root, 700, 400);
stage.setTitle("Movie Review Apps");
stage.setScene(scene);
stage.show();
}
public static void main(String[] args)
{
launch(args);
}
}
Here is Movie.java:
public class Movie
{
private String movieTitle;
private int year;
private int length;
private Review bookReview;
//Constructor to initialize all member variables
public Movie()
{
movieTitle = "?";
length = 0;
year = 0;
bookReview = new Review();
}
//Accessor methods
public String getMovieTitle()
{
return movieTitle;
}
public int getLength()
{
return length;
}
public int getYear()
{
return year;
}
public Review getReview()
{
return bookReview;
}
//Mutator methods
public void setMovieTitle(String aTitle)
{
movieTitle = aTitle;
}
public void setLength(int aLength)
{
length = aLength;
}
public void setYear(int aYear)
{
year = aYear;
}
public void addRating(double rate)
{
book ...
How to build to do app using vue composition api and vuex 4 with typescript
In this tutorial, we will build a to-do app using Vue Composition API & Vuex 4 with Typescript. We will learn and explore Composition API & Options API as well
Description of programYou are to write a program name InfixToPost.pdf
Description of program:
You are to write a program name InfixToPostfix.java that converts an infix expression entered
by the user to a postfix expression. The expression may contain the following tokens:
(1) Integer constants (a series of decimal digits).
(2) x (representing a value to be supplied later).
(3) Binary operators (+, -, *, / and %).
(4) Parentheses
Spaces between tokens are allowed but not required. The program will convert the expression to
postfix form and display the converted expression. Upload the file into A7 folder of icollege.
Sample Output:
Enter infix expression: (x + 1) * (x – 2) / 4
Converted expression: x 1 + x 2 - * 4 /
Enter infix expression: 1 2 +
Error in expression!! No operator between operands. Also last token must be an operand.
Enter infix expression: 10.4
Error in expression!! Cannot accept floating point numbers.
Enter infix expression: 1 ( + 2)
Error in expression!! No operator between operand and left parentheses.
Enter infix expression: 5 – (x – 2))
Error in expression!! No matching left parentheses for a right parentheses.
Enter infix expression: 1 ** 2
Error in expression!! The * operator cannot be preceded by a * operator.
Solution
//program for infix to posrtfix convertion
import java.io.*;
class stack
{
char stack1[]=new char[20];
int top;
void push(char ch)
{
top++;
stack1[top]=ch;
}
char pop()
{
char ch;
ch=stack1[top];
top--;
return ch;
}
int pre(char ch)
{
switch(ch)
{
case \'-\':return 1;
case \'+\':return 1;
case \'*\':return 2;
case \'/\':return 2;
}
retrun 0;
}
boolean operator(char ch)
{
if(ch==\'/\'||ch==\'*\'||ch==\'+\'||ch==\'-\')
return true;
else
return false;
}
boolean isAlpha(char ch)
{
if(ch>=\'a\'&&ch<=\'z\'||ch>=\'0\'&&ch==\'9\')
return true;
else
return false;
}
void postfix(String str)
{
char output[]=new char[str.length()];
char ch;
int p=0,i;
for(i=0;ipre(stack1[top])) || stack1[top]==\'(\')
{
push(ch);
}
}
else if(pre(ch)<=pre(stack1[top]))
{
output[p++]=pop();
push(ch);
}
else if(ch==\'(\')
{
while((ch=po())!=\'(\')
{
output[p++]=ch;
}
}
}
while(top!=0)
{
output[p++]=pop();
}
for(int j=0;j.
2. Stack. Write a program that uses the stack class (you can use.pdf
2. Stack. Write a program that uses the stack class (you can use the stack type defined in the
lectures, or you can define your own stack type) to solve a problem. The problem contains two
tasks, the first one is to convert an infix arithmetic expression into a postfix arithmetic
expression; the second task is to evaluate arithmetic expressions written in postfix form.
In infix form, the operator of an arithmetic statement is in-between every pair of operands. For
example:
1.5 + 2.3
2.0 * (3.3 + 4.5)
(2.1 + 3.0) * 4.8
In postfix form, the operands of an arithmetic statement appear followed by the operator. One of
the virtues of postfix form is that expressions can be written without the need for parentheses.
Here are some examples of arithmetic expressions written in postfix form:
1.5 2.3 + // Equivalent to 1.5 + 2.3
2.0 3.3 4.5 + * // Equivalent to 2.0 * (3.3 + 4.5)
2.1 3.3 + 4.8 * // Equivalent to (2.1 + 3.0) * 4.8
Please write a C++ program that uses an operator stack to convert an infix arithmetic expression
that the user enters into a postfix arithmetic expression, and then use a float stack to evaluate
postfix arithmetic.
Your program should support all five of the arithmetic operators, +, - , *, and /.
When users input the infix arithmetic expressions, the operands, operators and parenthesis
symbols are separated by spaces. The character # marks the end of the expression.
The infix arithmetic expressions only contain operands, operators and parenthesis. The operands
are float numbers, and the operators are +, -, * and /. If there are letters in the infix arithmetic
expressions, the “invalid expression” message should be displayed.
Here is an algorithm for evaluating an arithmetic expression written in postfix form with the aid
of a stack of floats.
• Scan the expression from left to right.
• When encounter an operand or a float, push it on the stack.
• When encounter an arithmetic operator, pop the top two numbers off the stack and use them as
operands for the indicated operation. Push the resulting number back on the stack.
• when you reach the end of the expression, the result of the calculation should be the sole item
on the stack.
Please show that that the program is working correctly by converting the following infix
arithmetic expressions and then computing the obtained postfix arithmetic expressions:
6.5 * 6.5 - 4 * 1.5 * 1.44 #
3.1 * (2.5 + 4.7 * 1.6) + 8.6 #
70.0 - (10.5 + 6) / 0.5 + 18.2 #
The following steps will convert an infix expression into a postfix expression:
1. Create an empty string stack called opStack for keeping operators. Create an empty string
array called postfixEx for postfix expression.
2. read the infix expression left to right.
2.1. If the string is an operand, append it to the postfixEx array.
2.2. If the string is a left parenthesis, push it on the opStack.
2.3. If the string is a right parenthesis, pop the opStack, append each operator to the postfixEx
array, until you see the corresponding left parent.
Description of a JAVA programYou are to write a program name Infi.pdf
Cost-Volume-Profit Analysis and Special Order Short-term decision making PART 1 Funai
Corporation is a Japanese manufacturer of video cassette recorders (VCRs) and was established
in 1987. There is now increased competition in its markets and the firm expects to find it difficult
to make an acceptable profit next year. You have been appointed as a management accountant at
the company, and have been given a copy of the draft budget for the next financial year. Draft
Budget for 12 months to 30th September 2019 (£m) (£m) Sales revenue 960 Cost of sales
Variable assembly materials 374.4 Variable labour 192 Factory overheads - variable 172.8 -
fixed 43 (782.2) Gross profit 177.8 Selling overhead - commission (variable) 38.4 - fixed 108
Administration overhead - fixed 20 (166.4) Net profit 11.4 The following information is also
supplied to you by the firm’s financial controller, John Smith: a) Planned sales for the draft
budget in the year to 30th September 2019 are expected to be 25% less than the total of 3.2
million VCR units sold in the previous financial year. b) The firm operates a Just-in-time stock
control system, which means that it holds no stocks of any kind. c) If more than 3 million VCR
units are made and sold, the unit cost of material falls by £4 per unit. d) Sales commission is
based on the number of units sold and not on turnover. 2 e) The draft budget assumes that the
factory will only be working at two-thirds of maximum capacity. f) Sales above maximum
capacity are not possible. Questions: 1) Calculate the Total contribution margin and contribution
margin per unit, showing your working. [5 marks] 2) Calculate the Break-even-point (BEP) in
units and BEP in sales revenues, showing your working. [3 marks] PART 2 John Smith explains
that the Board is not happy with the profit projected in the draft budget, and that the sales
director, Mary Ford, has produced three proposals to try and improve matters. Proposal A –
involves launching an aggressive marketing campaign: i. This would involve a single additional
fixed cost of £14 million for advertising. ii. There would be a revised commission payment of
£18 per unit sold. iii. Sales volume would be expected to increase by 10% above the level
projected in the draft budget, with no charge in the unit selling price. Proposal B – involves a 5%
reduction in the unit selling price: i. This is estimated to bring the sales volume back to the level
in the previous financial year. Proposal C – involves a 10% reduction in the unit selling price: i.
Fixed selling overhead would also be reduced by £45 million. ii. If proposal C is accepted, the
sales director believes sales volume will be 3.8 million units. Questions: 3) For Proposal A,
calculate: 3.1) the change in profit compared with the draft budget [4 marks] 3.2) the BEP point
in units and sales revenues. [3 marks] 4) For Proposal B, calculate: 4.1) the change in profit
compared with the draft budget [4 marks] 4.2) the BEP point in units and sal.
From object oriented to functional domain modeling
"From object oriented to functional domain modeling" by Mario Fusco
Malgrado l'introduzione delle lambda, la gran parte degli sviluppatori Java non è ancora abituata agli idiomi della programmazione funzionale e quindi non è pronta a sfruttare a pieno le potenzialità di Java 8. In particolare non è ancora comune vedere dati e funzioni usate insieme quando si modella un dominio di business. Lo scopo del talk è mostrare come alcuni principi di programmazione funzionale quali l'impiego di oggetti e strutture dati immutabili, l'uso di funzioni senza side-effect e il loro reuso mediante composizione, possono anche essere validi strumenti di domain modelling.
From object oriented to functional domain modeling
From object oriented to functional domain modeling
CH.4FUNCTIONS IN C_FYBSC(CS).pptx
The shared ppt contains the syllabus for the C Programming subject Ch no 4-Functions in C. It is helpful for FYBSC(CS) students
Similar to Write a method named convertInfixToPostfix that accepts an Infix exp.pdf (20)
You can look at the Java programs in the text book to see how commen
You can look at the Java programs in the text book to see how commen
How to build to do app using vue composition api and vuex 4 with typescript
How to build to do app using vue composition api and vuex 4 with typescript
Description of programYou are to write a program name InfixToPost.pdf
Description of programYou are to write a program name InfixToPost.pdf
2. Stack. Write a program that uses the stack class (you can use.pdf
2. Stack. Write a program that uses the stack class (you can use.pdf
Description of a JAVA programYou are to write a program name Infi.pdf
Description of a JAVA programYou are to write a program name Infi.pdf
From object oriented to functional domain modeling
From object oriented to functional domain modeling
From object oriented to functional domain modeling
From object oriented to functional domain modeling
More from feelingsboutiques
7. Which statements about financial forecasting is most likely TRUE.pdf
7. Which statements about financial forecasting is most likely TRUE:
a. Net income flows through to cash flows from operations on the balance sheet
b. Net income flows to shareholders equity on the cash flow statement
c. Marketable securities is the same as cash on the balance sheet
d. Marketable securities is the same as short term debt on the balance sheet
e. Marketable securities is good to use as a plug figure when forecasting financial statements
Solution
e. Marketable securities is good to use as a plug figure when forecasting financial statements.
Thanks.
Inputs in the light reaction of photosynthesis Inputs in the li.pdf
Inputs in the light reaction of photosynthesis
Inputs in the light reaction of photosynthesis
Solution
Inputs in the light reaction of photosynthesis are
Light energy, ADP, Pi, NADP and H2O
2H2O + 2NADP+ + 3ADP + 3Pi O2 + 2NADPH + 3ATP
These reactions begin with the absorption of light energy by pigments, and end with the
production of stored chemical energy in the form of NADPH and ATP.
How do I obtain the solution Also, how would I convert the limit .pdf
How do I obtain the solution: ? Also, how would I convert the limit into a limit that I could apply
the L\'hopital rule to? Step-by-step solution would be appreciated.
Solution
e^x-1-x/(x*(e^x-1) apply the rule e^x-1/((e^x-1)+xe^x) apply the rule again
e^x/(e^x+e^x+xe^x) not putx=0 answer=1/2.
If both of Johns parents are heterozygous for sickle cell anemia a.pdf
If both of John\'s parents are heterozygous for sickle cell anemia and Sarah\'s parents are AA and
Aa what are the chances that John and Sarah\'s child will have Sickle Cell Anemia? (Sickle Cell
Anemia is an autosomal recessive disease)
Solution
Sickle cell disease is an autosomal recessive condition. Assume that the gene coding for normal
phenotype is A and the gene coding for sickle cell phenotype is a; A is dominant over a.
Given that, John\'s parents are heterozygous for sickle cell anemia.
Aa* Aa ----> AA (1/4), Aa (1/2), aa (1/4)
The probability of John to be a heterozygous carrier is 2/3. The probability of Sarah to be a
carrier is 1/2.
The probability that the Jogn and Sarah will have Sickle cell anemia is = 1/2*2/3*1/2*1/2 = 1/12.
I need help with ALL of the following bacteria -trypanosoma gam.pdf
I need help with ALL of the following bacteria:
-trypanosoma gambiense
-Radiolaria
-Euglena
-Paramecium
-Vorticella
I need to know about EACH BACTERIA :
-how they move
-how they reproduce
-what/who they effect
-how they live
-class/genus
**ALL general information **
Thank you!!
I need help with ALL of the following bacteria:
-trypanosoma gambiense
-Radiolaria
-Euglena
-Paramecium
-Vorticella
I need to know about EACH BACTERIA :
-how they move
-how they reproduce
-what/who they effect
-how they live
-class/genus
**ALL general information **
Thank you!!
-trypanosoma gambiense
-Radiolaria
-Euglena
-Paramecium
-Vorticella
I need to know about EACH BACTERIA :
-how they move
-how they reproduce
-what/who they effect
-how they live
-class/genus
**ALL general information **
Thank you!!
Solution
Trypanosoma gambiense: it is a protozoan parasite.
Movement- with the help of flagellum.
Reproduction: By longitudinal binary fission.
Who is affected- the disease caused by trypanosoma is known as sleeping sickness. The parasites
are transmitted to humans by tsetse fly.
How they live- eating habits the blood, lymph and the intercellular spaces of different tissues and
organs of man Hogs,goats, cattle and sheep are the potential Reservoir hosts.
Class mastigophora and genus trypanosoma.
2. Radiolaria: also called radiozoa are protozoans
Movement: amoeboid movement
Reproduction: the reproduce asexually and probably sexually also Asexual fission, binary fission
and Multiple Fission and budding.
Whom they effect: they are found as you plant on throughout the ocean and their skeletal
remains make up a large part of the cover of the ocean floor as siliceous ooze.
The skeletons of ancient radiolarians are used in geological dating including Oil exploration and
determination of ancient climates.
Classes: polycystinea, acantharea, sticholonchea.
3. Euglena: it is single celled flagellate it is the best known and most widely studied member of
the class Euglenoidea. They are autotrophic in nature due to the presence of chloroplast. All
euglenoids how two flagella rooted in basal bodies. The longer flagellum helps the organism to
swim. Euglena reproduces asexually through binary fission. It belongs to the class euglenoidea
and genus euglena.
4. Paramoecium: it belongs to the class oligohymenophorea and genus paramoecium it is
commonly studied as a representative of the ciliate group there are widespread in freshwater
brackish and Marine environments they prepare themselves by whiplash moments of their cilia
which are arranged around the outside of their body. They reproduce asexually by binary fission,
they also follow conjugation which is a sexual phenomenon.
5. Vorticella: it belongs to the class oligihymenophorea and genus vorticella. It is a genus of
ciliates with 16 known species they are stalked inverted bell shaped ciliates, live mainly in
freshwater Ponds and streams they reproduce by budding where cell undergoes longitudinal
fission. Each cell has a separate sta.
I having trouble with this problem. Can someone out there help me J.pdf
I having trouble with this problem. Can someone out there help me? John Thildore, a retired
army officer, opened Thildore\'s Catering Service. As his accountant, analyze the transactions
listed and present them in proper form. a. The analysis of the transactions by using the expanded
accounting equation. b. A balance sheet showing the financial position of the firm before
opening on October 31, 201X. C. An income statement for the month of November. d. A
statement of owner\'s equity for November. e. A balance sheet as of November 30, 201X. 201X
John Thildore invested $25,000 in the catering business from his personal savings account. Oct.
25 27 Bought equipment for cash from Small Co., $1,200. 28 Bought additional equipment on
account from Ryan Co., $800. 29 Paid $400 to Ryan Co. as partial payment of the Oct. 28
transaction (You should now prepare your balance sheet as of October 31, 201X.) Nov. 1
Catered a graduation and collected cash, $2,200. 5 Paid salaries of employees, $550. 8 Prepared
desserts for customers on account, $250. 10 Received $80 cash as partial payment of Nov. 8
transaction. 15 Paid telephone bill, $50 17 Paid his home electric bill from the company\'s
checkbook, $120. 20 Catered a wedding and received cash, $2,500 25 Bought additional
equipment on account, $1,300 28 Rent expense due but unpaid, $650. 30 Paid supplies expense,
$550.
Solution
a.
b.
c.
d.EventAssetsLiabilitiesOwners equityCash+Accounts receivable+Equipment=Accounts
payable+John capital-John withdrawl+Revenue-Salaries expense-Telephone bill-Rent expense-
Supplies expenseOct 25 25,000 25,000Oct 27 -1,200 1,200Oct 28
800 800Oct 29 -400 -400Total 23,400
- 2,000 400 25,000Nov 1
2,200 2,200Nov 5 -550 550Nov 8 250
250Nov 10 80 -80Nov 15 -50 50Nov
17 -120 120Nov 20 2,500 2,500Nov 25 1,300
1,300Nov 28 650 650Nov 30 -550
550Total 26,910 170 3,300 2,350
25,000 120 4,950 550 50
650 550.
ExplainAnswer these genetic questions please. A pure-breeding line .pdf
Explain/Answer these genetic questions please. A pure-breeding line of white flowering tulips is
crossed with a pure-breeding line of pink tulips. The F1 progeny all have pink flowers, Which
trait is dominant? You self the pink F1 progeny and observe a 15:1 ratio of pink:white flowering
F2 progeny. Draw a potential biochemical pathway for production of pink pigment, and indicate
how the gene(s) responsible for producing pink pigment fit into this pathway.
Solution
(a) Let us denote the genotype of the pure breeding white flowering tulips as WW and the
genotype of the pure breeding pink flowering tulips as PP.
The F1 generation cross will give all progeny as: WWPP
It is given that all the F1 generation tulips are pink in color. Therefore, according to Mendel\'s
laws of inheritance, the dominant phenotype is physically expressed in Mendelian crosses, when
present in homozygous or heterozygous condition.
Therefore n the heterozygous condition of WP, pink (PP) is the dominant trait.
(b) Now that it is known that pink is the dominant trait, let us rename the genotypes as:
Pink: PP
white: pp
So F1 generation offsprings will have genotype: Pp
When F1 offsprings are self-crossed, the offsprings are:
Pp x Pp
F2 offsprings: PP, Pp, Pp, pp
According to Mendel\'s law, the F2 offspring phenotype ratio should have been 3:1. But, the
observed ratio is 15:1 (Pink flower: white flower). This anomaly is due to duplication of genes in
the case of tetraploid genetics..
Early version of UNIX were available only with a command-driven inte.pdf
Early version of UNIX were available only with a command-driven interface. In more recent
years, graphical user interfaces have become popular. Explain in your own words why these GUI
made an impact on the popularity of this operating system.
Solution
Graphical user interface is important for the novice users. Linux is mostly used by developers or
guys from computer science background. It is easier to interact with the computer with the help
of GUI. Most of the user\'s are not familer with the command line interface. Also, to interact
efficiently wee need to remember many commands in the unix. GUI is visually intuitivie hence
most of the new users prefer GUI or windows based operating system over linux operating
system. User can viewe, control, manipulate and toggle through multiple programs. Using mouse
and keyboard it is much easier for novice user to interact with the opearting system..
Environmental sciencePlease answer it ASAP 1. Why do water man.pdf
Environmental science
Please answer it ASAP 1. Why do water managers care about turbidity? How do water managers
estimate the bacterial disease risk associated with drinking water? 3. What is eutrophication? 4.
In a stratified lake (has fayers), which layer has the best drinking water? Bonus: What facility is
the largest nonmilitary user of explosives in the world? It is located in Florida.
Solution
Q1).The measurement of turbidity is a key test ofwater quality.
Fluids can contain suspended solid matter consisting of particles of many different sizes. While
some suspended material will be large enough and heavy enough to settle rapidly to the bottom
of the container if a liquid sample is left to stand (the settable solids), very small particles will
settle only very slowly or not at all if the sample is regularly agitated or the particles arecolloidal.
These small solid particles cause the liquid to appear turbid.
Q2.Water, the environment and people’s health • Part 4
53
MANAGEMENT ISSUES FOR DOMESTIC WATER SUPPLY.
What factors are important in the management of the microbial quality of domestic
water supplies?
The important factors are (i) disinfected drinking water, (ii) sound disposal of faecal wastes, (iii)
application of good personal, food and water use hygiene, (iv) use only of safe water for crops
eaten raw.
In the management of water quality for domestic purposes it is important to bear in mind that the
achievement of the goal of providing safe water for drinking and food preparation rests on the
management of the safety of the water supply along the whole supply chain. The water
supply chain consists of the water source, treatment works, distribution system, the supply tap,
the
drinking water container, jug or cup. (See vol., 5, Management Guide, DWAF, DOH & WRC,
2002).
Dirt that has gained access to the water supply line or tank (e.g. high-rise buildings) often causes
problems in the management of water for domestic purposes,
• In the case of the repair of a burst pipe where dirt may gain access to the supply line, this may
cause a temporary elevation of the microbiological total plate count in the supply line, but the
consumer is usually alerted to the problem by brown water coming out of the tap. The situation
is usually remedied by flushing the tap and allowing the plug of contaminated water to flow
down the drain.
• Rodents may gain access to gravity feed tanks on top of high-rise buildings which may not be
covered properly. This typically results in foul smelling and tasting water, and the consumer
is alerted to the problem. Such tanks will need flushing and proper screening of any access
points.
The other situation which needs attention is to ensure that containers that are used in the home
for storing drinking water are clean and that they are properly covered to ensure that flies and
dirt
do not settle into the water in the container. One of the quickest ways to contaminate water in a
bucket, for example, is to dip an unwas.
Discuss a specific public health concern for each of the following g.pdf
Discuss a specific public health concern for each of the following groups:
a. Americans of Hispanic Origin
b. African Americans
c. Asian Americans
d. Pacific Islanders
e. American Indians & Alaskan Natives
Solution
a). The prevalence of diabetes is found to be different in different groups of people. In United
states, the prevalence is more in case of Hispanic Americans that that of the White Americans or
black population. Also, African Americans have higher incidence than the white Americans.
b). African Americans are at higher risk of developing heart diseases than any other population,
about 3/4th of the population develop high blood pressure after 40 years of age. Their health
access is very less and do not visit a physician for regular checkup. Means they are less likely to
take any preventive medicines, which increases the risk of developing high blood pressure and
lethal heart problems.
c). As per the health statistics, Asian Americans are less prone to diabetes and hypertension.
d). Pacific Islanders are at higher risk of developing type 1 diabetes..
Due to your interference with organisms on the planet, one species o.pdf
Due to your interference with organisms on the planet, one species of flying insectivorous
organism that formerly lived near Lake Agassiz on Wallace have moved to a location just south
of Lake Lyell. Unfortunately, there is already a different species of flying insectivorous organism
very similar to the first organism living near Lake Lyell. Describe in detail what things (multiple
things)might happen as these two species interact. and what methods they can adopt to avoid
extinction with example.
Solution
The migration of flying insectivorous organism from Lake Agassiz on Wallace to Lake Lyell.
This leads to a competition between two organisms for their sustainability. Interspecific
competition could be observed between these two species. The interspecific competition if it is
drastic might lead to complete change in the population size of unfitted organism through natural
selection. The species which has been gets suppressed due to over - aggressive species gets
completely excluded or the unfitted species gets change itself its natural characteristics if it is
competent. The adaptations such as flexibility of the newer species to change itself to newer
climatic conditions, acclimatization and learning helpful for the survival of a new species which
gets migrated to a newer habitat..
Complete the following chart, and then circle the layer that is found.pdf
Complete the following chart, and then circle the layer that is found beneath the skin. How do
the cells of stratum corneum and stratum basale differ? ____ State the specific location of
melanin observed in dark skin ____ Which is darker, the anterior forearm or the posterior
forearm ____ Explain why ____ What special qualities, due to the presence of fibers, does the
connective tissue of the dermis have? ___How is the structure of the thick skin of the palms of
the hands and soles of the feet properly suited for its function? ____
Solution
1. ANS:
A. Epidermis
Location: outermost layer of the skin
Tissues: Epithelial tissue
Characteristics: It is a protective waterproof barrier that also keeps pathogens at bay and
regulates body temperature
B. Dermis:
Location: Middle layer present in beneath the epidermis of the skin
Tissues: Connective tissue
Characteristics: It is a thick layer of fibrous and elastic tissue (made mostly of collagen, elastin,
and fibrillin) that gives the skin its flexibility and strength.
C. Hypo dermis:
Location: Deeper subcutaneous tissue layer of the skin
Tissues: Fat and connective tissue
Characteristics: It maintains the body temperature.
2. ANS:
Stratum corneum and stratum basale difference:
The cells of stratum basale are cuboidal to columnar and the stratum corneum cells are made
with keratin.
3. ANS:
In the location of stratum basale, melanin content specifically observed in dark (heavily
pigmented) skin.
4. ANS:
The dorsal side (posterior) of the forearm is the \"top\" side-- the side that usually faces upward
and is generally darker than anterioir side. It is mainly due to melanin and hair follicles.
5. ANS:
The special qualities of dermis connective tissue can contains with Collagenous fibers, elastic
fibers, and a gel-like substance.
6. ANS:
The sole of feet and the palms of hands are structured to perform day to day functions. The
hardness on the skin on these locations is due to the layers of epidermis that contain dead
keratinocytes are the Stratum corneum and stratum lucidum
Stratum lucidum: Thin, clear layer present in the thick skin of the palms and soles; no remaining
living cells.
Stratum corneum: Several layers of keratinized corneum; a collagenous matrix composed of the
products of dead cells. Keratin and the thickened plasma membrane protect the skin against
abrasion and penetration, and the glycolipid between its cells nearly waterproofs this layer..
1a. What kinds of deductions are prohibited as a matter of public po.pdf
1a. What kinds of deductions are prohibited as a matter of public policy? bribes, kickbacks, and
\"other\" illegal payments as nondeductibleT.
1b.Why might Congress deem it important to disallow deductions for expenditures against public
policy?
Solution
The IRC lists bribes, kickbacks, and \"other\" illegal payments as nondeductibleCongress didn\'t
want the tax benefits associated with deductions to benefit or subsidize wrongdoing of course,
this rationale doesn\'t really explain the prohibition against deducting political contributions
which is probably better explained by the potential perception that political efforts are being
subsidized by taxpayers..
3. IQ tests are given to fifteen pairs of siblings. In each pair, one.pdf
3. IQ tests are given to fifteen pairs of siblings. In each pair, one sibling has phenylketonuria
(PKU, a metabolism disorder); the other doesn\'t. Is there any evidence that, in general, the PKU
cases have higher or lower IQs from their siblings? Perform a nonparametric test with sufficient
power, and justify your choice of test
Solution.
A rectangular board is 9 by 17 units. A string is connected to the f.pdf
A rectangular board is 9 by 17 units. A string is connected to the foci and pulled taut by a pencil
in order to draw the ellipse. Find the length of the string
Solution
length of major axis = 2a = 17
a = 17/2 = 8.5
length of minor axis = 2b = 9
b = 4.5
foci c^2 = a^2 - b^2
c^2 = 8.5^2 - 4.5^2 = 52
c = 7.21
length of the string = two times foci = 2*7.21 = 14.42 units.
You have 20 marbles and 20 rocks. Place them into two boxes to incre.pdf
You have 20 marbles and 20 rocks. Place them into two boxes to increase chances of getting the
marbles. Boxes are mixed up. Marbles and rocks have to be seperated for best chance to win the
marbles.
Solution
SOl)
20 rocks in 1st box
20 marbles on 2nd box
Total boxes=2
Probability to choose 20 marbles box = 1/2.
X and Y are continuous random variables with joint p.d.f. f(x,y) = c.pdf
X and Y are continuous random variables with joint p.d.f. f(x,y) = c(1 + x + y)
A) find E(X + Y)
B) find Cov(X,Y)
I could use some helping finding the answer here. I managed to get one however my classmates
found a different answer
I forgot to mention but the steps would be extremelly helpful. Thanks
Solution.
What is meant by cultural emergent and how does this differ from oth.pdf
What is meant by cultural emergent and how does this differ from other approaches to culture?
Explain how culture can be both persistent and ever-changing.
Solution
Cultural emergent and how does this differ from other approaches to culture discussion of the
scope and limitations of current diagnostic practice criticisms from different quarters and the role
and relevance of culture in the diagnostic encounter precede the examination of advantages and
disadvantages of the approach the practical aspects include the acceptance of cultural
discordances as a component of an updated definition of mental disorder and the use of a
refurbished cultural formulation.
This is why the recognition of cultural diversity can help to ensure that ownership of
development and peace initiatives is vested in the populations concerned the message of
sustainable development is that the planet is essentially finite and that the resources humanity
hoped to discover in its environment must now be found within itself in its very diversity cultural
diversity invites us to think in terms of a plural humanity embodying a creative potential that
precludes any prescribed model of development.
The acknowledgement of cultural diversity and intercultural dialogue help to defuse the tensions
that can arise in multicultural societies when a majority and minorities confront each other over
recognition of their rights although outcome research is limited culturally responsive behavioral
health counseling results in greater counselor credibility.
An archaeological eye to an examination of human response to unpredictable environmental
conditions informed by an understanding of contemporary traditional peoples sustainable
Lifeways enhances our understanding of both the forces of conservatism and innovation which
may have been in play in major transitions in the past..
What are two main causes of recombination Errors in DNA replication.pdf
What are two main causes of recombination? Errors in DNA replication and damage to DNA
induced by chemicals or radiation Independent assortment of chromosomes and crossing over
between nonhomologous chromosomes during meiosis Independent assortment of chromosomes
and crossing over between homologous chromosomes during meiosis Fusion of male and female
gametes bearing different alleles and crossing over between homologous chromosomes during
mitosis Crossing over between sister chromatids during mitosis and crossing over between
homologous chromosomes during meiosis
Solution
The two main causes of recombination are:
3. Independent assortment of chromosomes and crossing over between homologous
chromosomes during meiosis
5. Crossing over between sister chromatids during mitosis and crossing over between
homologous chromosomes during meiosis.
Note: Mitotic recombination is primarily a result of DNA repair processes responding to
spontaneous or induced damages..
1.Developmental Biology brings together many different areas of stud.pdf
1.Developmental Biology brings together many different areas of study within Biology.What
types of questions can be asked about Development?
2.Describe a technique that would allow a developmental biologist to visualize the expression of
developmental genes in space and time. Be sure to describe how it works in as much information
as you can remember or give an example.
3.Describe (briefly) ONE historical experiment provided by Hans Driesch which refuted the
most accepted cell specification mechanism of the time period (1800s).
4.In developmental biology researchers often want to ‘drive’ gene expression within developing
tissues – sometimes expressing genes in different locations or at different times of development
so as to demonstrate the gene’s role during normal development. What research tools could you
use to ‘drive’ gene expression of Your Gene of Interest (YGI)? Explain.
5.What does it mean to be genetically equivalent? Describe how cloning demonstrates this?
6.Experiments with Xenopus (frog) in the late 1950s demonstrated that cells within the 3 germ
layers had an affinity for each other and thus indicated that they had differentiated enough to be
“biased” toward a specific cell layer (endoderm, mesoderm, ectoderm). Describe an experiment
that demonstrated how the 3 different layers of the gastrula have an affinity for each other.
7.Morphogenesis involves the orchestration of Cell Affinity, Cell Adhesion, and Cell Migration.
How do the adhesive molecules play a role as cells of the embryo change their affinity for one
another?
please help...
Solution
1.How biological discoveries and their applications can be shaped by social prejudices of the
time.
About The significance and conceptual value of a particular discovery.
What are theories involved in the development and what are the controversies regarding these
theories.
Studies of persistence of unicellular stages in life histories and studies of divergence in durations
of cell cycles.
How the evolution of development and dispersal differ in terrestrial and marine environments.
How organisms survive and reproduce in their environments
Regarding genetic heterogeneity within and among cells,Methods of studying gene action in
development,Genetic diversity in different organisms .
How reproduction takes place? How does the fertilized egg give rise to the adult body,and how
does that adult body produce yet another body?
How is the development of an organism integrated into the larger context of its habitat?.
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How do I obtain the solution Also, how would I convert the limit .pdf
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If both of Johns parents are heterozygous for sickle cell anemia a.pdf
If both of Johns parents are heterozygous for sickle cell anemia a.pdf
I need help with ALL of the following bacteria -trypanosoma gam.pdf
I need help with ALL of the following bacteria -trypanosoma gam.pdf
I having trouble with this problem. Can someone out there help me J.pdf
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ExplainAnswer these genetic questions please. A pure-breeding line .pdf
ExplainAnswer these genetic questions please. A pure-breeding line .pdf
Early version of UNIX were available only with a command-driven inte.pdf
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Environmental sciencePlease answer it ASAP 1. Why do water man.pdf
Environmental sciencePlease answer it ASAP 1. Why do water man.pdf
Discuss a specific public health concern for each of the following g.pdf
Discuss a specific public health concern for each of the following g.pdf
Due to your interference with organisms on the planet, one species o.pdf
Due to your interference with organisms on the planet, one species o.pdf
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