Why might a transposon screen for genes required for virulence in a .pdf
•
0 likes•2 views
Why might a transposon screen for genes required for virulence in a bacterium NOT identify a particular gene required for virulence in humans? Solution There is lack of transposons specific to vertebrates. Hence, the usage of transposons in vertebrates has been limited. Transposons present and compatible inside vertebrate genomes are inactive or \"junk\" DNA..
Report
Share
Report
Share
Download to read offline
Recommended
On this image, please label all marked structures Definedescribe t.pdf
On this image, please label all marked structures: Define/describe the following vocabulary
words pertaining to your Senses optic disc rightarrow Accommodation rightarrow Olfactory
Glomeruli rightarrow Photoreceptor Rods rightarrow Bone Deafness rightarrow Visual Acuity
rightarrow
Solution
1. Marked structures should be labeled as follows;
Left side marks (from top to bottom):
(a) Optic nerve
(b) Retina
(c) Choroid
(d) Sclera
Right side marks (from top to bottom)
(a) Lens
(b) Cornea
(c) Iris
(d) Ciliary body
2. Definitions of terminologies given;
(a) Optic Disc: Optic disc is the point of exit of ganglion cell axons from the eye. It is a blind
spot in the eye, as there are no rods and cone cells present on it. These ganglion cell axonsafter
leaving the eye form the optic nerve. Therefore, optic disc is also known as optic nerve head.
(b) Accomodation: Accomodation is considered as the reflex action of eye, i.e, the way one can
focus on nearby or distant object, thereby changing optical power frequently to maintain the
clear image of the object. In this manner, the shape of lens and and pupil size changes frequently.
(c) Olfactory glomeruli: Olfactory glomeruli is the point at which the information from the axons
of olfactory receptor neurons is received; the synapses are formed between the terminal end of
olfactory nerve with dendrites of mitral, tufted cells and periglomerular. It is a structure located
in the olfactory bulb in the mammalian central nervous system. Olfactory glomeruli are sperical
in shape.
(d) Photoreceptor rods: Phtotoreceptor rods are the cells in the retina of the eye that help in clear
sight in dim light. They are located towards the outer edges of the retina. They are present in
millions, and are more sensitive than cone cells.
(e) Bone deafness: Sond waves are conducted from outer ear, tympanic membrane to inner ear
through middle ear ossicles. In case of problems that lead blocking of conduction of sound waves
from outer to inner ear, leads to conductive hearing loss, also known as bone deafness. In such
cases, passage of sound across the ear drum and the inner ear is blocked.
(f) Visual Acuity: It refers to the \'clarity of vision\', which depends on both optical and neural
factors, such as focal capacity of retina, clarity of lens, interpretative functioning of the brain..
Meniere’s disease - named for its discoverer, the nineteenth-century.pdf
Meniere’s disease - named for its discoverer, the nineteenth-century French physical Prosper
Meniere - is associated with a build-up of fluid in the inner ear and is also known as
endolymphatic hydrops. Symptoms of Meniere’s disease include episodic attacks of vertigo,
nausea, and tinnitus, accompanied by hearing loss and a feeling of fullness in the ears. Vertigo is
a false sensation of spinning movement that patients often describe as dizziness.
Question 1: In which part of the brain is sensory information about equilibrium processed? Are
there any accessory areas that aid in equilibrium sensation and processing? Which of the special
senses organs play a role in regulating equilibrium?
Solution
Answer:
Brain stem is composed of midbrain and hind brain. Hind brain and fore brain is connected by
midbrain.The hind part of the brain composed of myelencephalon and metencephalon.Pons and
cerebellum are the special structures present in the metencephalon, which assist in equilibrium
and coordination and pass sensory information..
Iodine serves as a mordant in the Gram stain procedure. What is the .pdf
Iodine serves as a mordant in the Gram stain procedure. What is the best explanation of iodine\'s
role in the Gram stain?
Iodine will wash the primary stain from the cell wall of the bacteria.
Iodine will stain any organisms that lose the primary stain after rinsing with alcohol.
Iodine binds to the primary stain and forms a large crystal violet-iodine complex that becomes
trapped in the cell wall.
Iodine is used to fix the specimen to the glass slide in case the fixing stepA.
Iodine will wash the primary stain from the cell wall of the bacteria.B.
Iodine will stain any organisms that lose the primary stain after rinsing with alcohol.C.
Iodine binds to the primary stain and forms a large crystal violet-iodine complex that becomes
trapped in the cell wall.D.
Iodine is used to fix the specimen to the glass slide in case the fixing step
Solution
C). Iodine binds to the primary stain and forms a large crystal violet-iodine complex that
becomes trapped in the cell wall.
The components of Gram staining are listed below:
1). Crystal violet – It is a positively charged dye, These positively charged and coloured ions
bind to the negatively charged cell membrane of the bacteria and imparts colour to the bacterial
cell wall.
2). Iodine is the stabilizing mordant. The mordant allows the fixation of primary stain (crystal
violet) with the test sample.
3). Ethanol removes the excess stain
4). Safranin is the counter stain, which is applied to stain the cells which loss the purple stain..
In the days before refrigeration, a common practice to preserve me.pdf
In the days before refrigeration, a common practice to preserve meat was to add a lot of salt to
the meat. Why was this a relatively effective technique?
In the days before refrigeration, a common practice to preserve meat was to add a lot of salt to
the meat. Why was this a relatively effective technique?
Solution
Answer:
Using a salt was one way to preserve meat without electricity. Salt creates hypertonic conditions
causing exocytosis of water from bacterial cells, the cells lose water until they reach a state
where they cannot grow. Thus addition of salt inhibits the growth of microorganisms..
In a typical organization, databases and communications technology a.pdf
In a typical organization, databases and communications technology are linked. Databases are
rarely accessed from the same computer system in which they are housed. It is important to
understand the relationship between databases and communications technology within the
organization.
In this assignment, research and summarize how databases are accessed by employees in an
organization. The questions that the assignment paper should answer include, but are not limited
to:
Solution
Successful knowledge management programs often begin by addressing a critical business
problem facing the company. However, many firms fail to align their knowledge efforts with
their most pressing business issues. When this occurs, significant time and effort is spent on
projects that have minimal impact, while key needs are not addressed or are completely
overlooked.
It is the hierarchical system that gives direction to and imposes restrictions upon the flow of
communications. Management decisions and directions flow from higher to lower levels in the
organization.Responses and reports from the lower level managers flow upward in the
organization. Managers also spend time communicating with their peers. Therefore, we see from
the outset that communications must function effectively in a lateral direction, as well as
downward and upward.
The Internet expands the horizon of every utterance or expressive act to a potentially planetary
level. This makes it impossible to imagine a purely local context or public for anything that
anyone creates today. It also de-centres the idea of the global from any privileged location. No
place is any more or less the centre of the world than any other anymore. As people who once
sensed that they inhabited the intellectual margins of the contemporary world simply because of
the nature of geo-political arrangements, we know that nothing can be quite as debilitating as the
constant production of proof of one\'s significance. The Internet has changed this one fact
comprehensively. The significance, worth or import of one\'s statements is no longer
automatically tied to the physical facts of one\'s location along a still unequal geo-political map.
we use web-based database requests on a daily basis. We are constantly visiting web pages,
clicking on links and using the menu to navigate us through our activity on that page. Using
middleware, the web server passes a request on to a database query and the information is stored
and passed along to the database server. The database server then uses this information to direct
the page to where it was intended to go. CGI Script is another way information is passed along.
They use instructions via a programming language and accept and return the websites data to the
user. Active server pages are yet another example of scripts used commonly on websites. They
are very similar to CGI Scripts, yet they are exclusive because they almost always use VBS
script or Java script. PHP Hypertext processor is a .
in JAVA Jagged Array recall that in Java 2D arrays are jagged in t.pdf
in JAVA: Jagged Array: recall that in Java 2D arrays are jagged in the sense that each row can
have a different length. Write a program that takes an integer 2D array as input and returns the
mean of it values.
Solution
public Double getMean(Integer[][] input) {
// Your code goes here
Double mean = 0.0;
int total = 0;
int count = 0;
for(int i=0; i.
If the elasticity of ethyl alcohol and water are 1.0610^9 Pa and 2.1.pdf
If the elasticity of ethyl alcohol and water are 1.06*10^9 Pa and 2.15*10^9 Pa respectively,
determine which substance is easier to compress
Solution
Ethyl alcohol is easy to compress .since the bulk modulus elasticity of Ethyl alcohol is less as
compare to water . Lower bulk modulus means easy to compress ..
Hi there! Im having trouble answering these tow questions could yo.pdf
Hi there! I\'m having trouble answering these tow questions could you please help me? Thank
you. (two pages of the article are attached below for reference)
1. How does the estimate of the coefficent o relatedness (r) fit with the \"brothers\" hyothesis
(what coesfficientss of relatedness between males would we expect)? r = (0.42 plus or minus
0.07)
2. There is a possibility of half-brothers (r=0.25). For maternal half-brothers (same mother,
different father), what is the chance they share an autozygous allele via a male parent? A female
parent? (don\'t overthink this!) letters to nature kinship facilitates indirect fitness benefit for lo
ranked males male (Tab This value is an underestimate to the extent that high because female
visitation often increases at larger leks, thereby relatedness makes more difficult to assign
paternity to males in ght settle at one lek. her than coalitions (see Methods explaining why a
male ma 3-14. No cmpil rical study has yet quantified this kin-selected hypothesis is that the
benefit due to differ another An al benefi ive to alternative benefits such as low freq uencies of
dividual quality of dominan her than the hel males ra ngs or future inheritance of d ded by the f
this were true, one eir subordinate partner(s mat ominant positions provi Wild turkeys the few
uld predict a diffe rence in the distributions eagris gallopavo) are a reproductive species o birds
to forma male display partnerships within larger display success between dominant and solitary
males, and that there aggregations. Male turkeys fo rm coalitions of two to fo uld be difference
betwe en the success of presumed ur same e or no aged males that court females and defend
those females against high-quality males that successfully reproduce, whether they are in a ary
males. A previous observational study ominant member of a coal other groups and so on or
display as a sol tary individual found that only one male in each coalition mates. The authors of
Contrary to these predictions, both dominants and solitary males that study believed that coal ons
were composed of brothers show bimodal distributions of reproductive success, with n sibling
nestmates thereby providing the relatedness necessary o dominant males and n ary males not
reproducing at all. 10 so accrue indirect fitness benefits. Although this work was published When
only the presumably high-quality males that reproduce are ong before molecular techniques were
available to measure related used to calculate the average fitness of dominant and solitary males,
ness and reproductive success directly and has been questioned on the dominant males father
significantly more offspring (49) than do other grounds, the story remains a well-cited example
of kin solitary males (13) (Mann-Whitney U 4 for 0.5, P 0.026, n both groups), and the benefit
Bincreases to 9.0 offspring per male Selection Here I show that kin-selected indirect fitness
benefits do in fact rather than decreases (Table Thus kin selec.
Recommended
On this image, please label all marked structures Definedescribe t.pdf
On this image, please label all marked structures: Define/describe the following vocabulary
words pertaining to your Senses optic disc rightarrow Accommodation rightarrow Olfactory
Glomeruli rightarrow Photoreceptor Rods rightarrow Bone Deafness rightarrow Visual Acuity
rightarrow
Solution
1. Marked structures should be labeled as follows;
Left side marks (from top to bottom):
(a) Optic nerve
(b) Retina
(c) Choroid
(d) Sclera
Right side marks (from top to bottom)
(a) Lens
(b) Cornea
(c) Iris
(d) Ciliary body
2. Definitions of terminologies given;
(a) Optic Disc: Optic disc is the point of exit of ganglion cell axons from the eye. It is a blind
spot in the eye, as there are no rods and cone cells present on it. These ganglion cell axonsafter
leaving the eye form the optic nerve. Therefore, optic disc is also known as optic nerve head.
(b) Accomodation: Accomodation is considered as the reflex action of eye, i.e, the way one can
focus on nearby or distant object, thereby changing optical power frequently to maintain the
clear image of the object. In this manner, the shape of lens and and pupil size changes frequently.
(c) Olfactory glomeruli: Olfactory glomeruli is the point at which the information from the axons
of olfactory receptor neurons is received; the synapses are formed between the terminal end of
olfactory nerve with dendrites of mitral, tufted cells and periglomerular. It is a structure located
in the olfactory bulb in the mammalian central nervous system. Olfactory glomeruli are sperical
in shape.
(d) Photoreceptor rods: Phtotoreceptor rods are the cells in the retina of the eye that help in clear
sight in dim light. They are located towards the outer edges of the retina. They are present in
millions, and are more sensitive than cone cells.
(e) Bone deafness: Sond waves are conducted from outer ear, tympanic membrane to inner ear
through middle ear ossicles. In case of problems that lead blocking of conduction of sound waves
from outer to inner ear, leads to conductive hearing loss, also known as bone deafness. In such
cases, passage of sound across the ear drum and the inner ear is blocked.
(f) Visual Acuity: It refers to the \'clarity of vision\', which depends on both optical and neural
factors, such as focal capacity of retina, clarity of lens, interpretative functioning of the brain..
Meniere’s disease - named for its discoverer, the nineteenth-century.pdf
Meniere’s disease - named for its discoverer, the nineteenth-century French physical Prosper
Meniere - is associated with a build-up of fluid in the inner ear and is also known as
endolymphatic hydrops. Symptoms of Meniere’s disease include episodic attacks of vertigo,
nausea, and tinnitus, accompanied by hearing loss and a feeling of fullness in the ears. Vertigo is
a false sensation of spinning movement that patients often describe as dizziness.
Question 1: In which part of the brain is sensory information about equilibrium processed? Are
there any accessory areas that aid in equilibrium sensation and processing? Which of the special
senses organs play a role in regulating equilibrium?
Solution
Answer:
Brain stem is composed of midbrain and hind brain. Hind brain and fore brain is connected by
midbrain.The hind part of the brain composed of myelencephalon and metencephalon.Pons and
cerebellum are the special structures present in the metencephalon, which assist in equilibrium
and coordination and pass sensory information..
Iodine serves as a mordant in the Gram stain procedure. What is the .pdf
Iodine serves as a mordant in the Gram stain procedure. What is the best explanation of iodine\'s
role in the Gram stain?
Iodine will wash the primary stain from the cell wall of the bacteria.
Iodine will stain any organisms that lose the primary stain after rinsing with alcohol.
Iodine binds to the primary stain and forms a large crystal violet-iodine complex that becomes
trapped in the cell wall.
Iodine is used to fix the specimen to the glass slide in case the fixing stepA.
Iodine will wash the primary stain from the cell wall of the bacteria.B.
Iodine will stain any organisms that lose the primary stain after rinsing with alcohol.C.
Iodine binds to the primary stain and forms a large crystal violet-iodine complex that becomes
trapped in the cell wall.D.
Iodine is used to fix the specimen to the glass slide in case the fixing step
Solution
C). Iodine binds to the primary stain and forms a large crystal violet-iodine complex that
becomes trapped in the cell wall.
The components of Gram staining are listed below:
1). Crystal violet – It is a positively charged dye, These positively charged and coloured ions
bind to the negatively charged cell membrane of the bacteria and imparts colour to the bacterial
cell wall.
2). Iodine is the stabilizing mordant. The mordant allows the fixation of primary stain (crystal
violet) with the test sample.
3). Ethanol removes the excess stain
4). Safranin is the counter stain, which is applied to stain the cells which loss the purple stain..
In the days before refrigeration, a common practice to preserve me.pdf
In the days before refrigeration, a common practice to preserve meat was to add a lot of salt to
the meat. Why was this a relatively effective technique?
In the days before refrigeration, a common practice to preserve meat was to add a lot of salt to
the meat. Why was this a relatively effective technique?
Solution
Answer:
Using a salt was one way to preserve meat without electricity. Salt creates hypertonic conditions
causing exocytosis of water from bacterial cells, the cells lose water until they reach a state
where they cannot grow. Thus addition of salt inhibits the growth of microorganisms..
In a typical organization, databases and communications technology a.pdf
In a typical organization, databases and communications technology are linked. Databases are
rarely accessed from the same computer system in which they are housed. It is important to
understand the relationship between databases and communications technology within the
organization.
In this assignment, research and summarize how databases are accessed by employees in an
organization. The questions that the assignment paper should answer include, but are not limited
to:
Solution
Successful knowledge management programs often begin by addressing a critical business
problem facing the company. However, many firms fail to align their knowledge efforts with
their most pressing business issues. When this occurs, significant time and effort is spent on
projects that have minimal impact, while key needs are not addressed or are completely
overlooked.
It is the hierarchical system that gives direction to and imposes restrictions upon the flow of
communications. Management decisions and directions flow from higher to lower levels in the
organization.Responses and reports from the lower level managers flow upward in the
organization. Managers also spend time communicating with their peers. Therefore, we see from
the outset that communications must function effectively in a lateral direction, as well as
downward and upward.
The Internet expands the horizon of every utterance or expressive act to a potentially planetary
level. This makes it impossible to imagine a purely local context or public for anything that
anyone creates today. It also de-centres the idea of the global from any privileged location. No
place is any more or less the centre of the world than any other anymore. As people who once
sensed that they inhabited the intellectual margins of the contemporary world simply because of
the nature of geo-political arrangements, we know that nothing can be quite as debilitating as the
constant production of proof of one\'s significance. The Internet has changed this one fact
comprehensively. The significance, worth or import of one\'s statements is no longer
automatically tied to the physical facts of one\'s location along a still unequal geo-political map.
we use web-based database requests on a daily basis. We are constantly visiting web pages,
clicking on links and using the menu to navigate us through our activity on that page. Using
middleware, the web server passes a request on to a database query and the information is stored
and passed along to the database server. The database server then uses this information to direct
the page to where it was intended to go. CGI Script is another way information is passed along.
They use instructions via a programming language and accept and return the websites data to the
user. Active server pages are yet another example of scripts used commonly on websites. They
are very similar to CGI Scripts, yet they are exclusive because they almost always use VBS
script or Java script. PHP Hypertext processor is a .
in JAVA Jagged Array recall that in Java 2D arrays are jagged in t.pdf
in JAVA: Jagged Array: recall that in Java 2D arrays are jagged in the sense that each row can
have a different length. Write a program that takes an integer 2D array as input and returns the
mean of it values.
Solution
public Double getMean(Integer[][] input) {
// Your code goes here
Double mean = 0.0;
int total = 0;
int count = 0;
for(int i=0; i.
If the elasticity of ethyl alcohol and water are 1.0610^9 Pa and 2.1.pdf
If the elasticity of ethyl alcohol and water are 1.06*10^9 Pa and 2.15*10^9 Pa respectively,
determine which substance is easier to compress
Solution
Ethyl alcohol is easy to compress .since the bulk modulus elasticity of Ethyl alcohol is less as
compare to water . Lower bulk modulus means easy to compress ..
Hi there! Im having trouble answering these tow questions could yo.pdf
Hi there! I\'m having trouble answering these tow questions could you please help me? Thank
you. (two pages of the article are attached below for reference)
1. How does the estimate of the coefficent o relatedness (r) fit with the \"brothers\" hyothesis
(what coesfficientss of relatedness between males would we expect)? r = (0.42 plus or minus
0.07)
2. There is a possibility of half-brothers (r=0.25). For maternal half-brothers (same mother,
different father), what is the chance they share an autozygous allele via a male parent? A female
parent? (don\'t overthink this!) letters to nature kinship facilitates indirect fitness benefit for lo
ranked males male (Tab This value is an underestimate to the extent that high because female
visitation often increases at larger leks, thereby relatedness makes more difficult to assign
paternity to males in ght settle at one lek. her than coalitions (see Methods explaining why a
male ma 3-14. No cmpil rical study has yet quantified this kin-selected hypothesis is that the
benefit due to differ another An al benefi ive to alternative benefits such as low freq uencies of
dividual quality of dominan her than the hel males ra ngs or future inheritance of d ded by the f
this were true, one eir subordinate partner(s mat ominant positions provi Wild turkeys the few
uld predict a diffe rence in the distributions eagris gallopavo) are a reproductive species o birds
to forma male display partnerships within larger display success between dominant and solitary
males, and that there aggregations. Male turkeys fo rm coalitions of two to fo uld be difference
betwe en the success of presumed ur same e or no aged males that court females and defend
those females against high-quality males that successfully reproduce, whether they are in a ary
males. A previous observational study ominant member of a coal other groups and so on or
display as a sol tary individual found that only one male in each coalition mates. The authors of
Contrary to these predictions, both dominants and solitary males that study believed that coal ons
were composed of brothers show bimodal distributions of reproductive success, with n sibling
nestmates thereby providing the relatedness necessary o dominant males and n ary males not
reproducing at all. 10 so accrue indirect fitness benefits. Although this work was published When
only the presumably high-quality males that reproduce are ong before molecular techniques were
available to measure related used to calculate the average fitness of dominant and solitary males,
ness and reproductive success directly and has been questioned on the dominant males father
significantly more offspring (49) than do other grounds, the story remains a well-cited example
of kin solitary males (13) (Mann-Whitney U 4 for 0.5, P 0.026, n both groups), and the benefit
Bincreases to 9.0 offspring per male Selection Here I show that kin-selected indirect fitness
benefits do in fact rather than decreases (Table Thus kin selec.
For graph to the right Amplitude Midline Period Equation using.pdf
For graph to the right Amplitude: Midline: Period: Equation using sine: Equation using
cosine:
Solution
a) amplitude =|(1-(-7))|/2 =4
b) mid line y=[1+(-7)]/2
y=-3
c)period =3-(-1)=4
d)equation using sine :
vertical shift D=-3
period =2/B=4 =>B=/2
y =4sin((/2)x) -3
d)equation using cosine
vertical shift D=-3
period =2/B=4 =>B=/2
phase shift =-C/B=1 =>C=-B=>C =-/2
y =4cos((/2)x-(/2)) -3.
Explain what exactly is going on with this picture. SolutionIn.pdf
Explain what exactly is going on with this picture.
Solution
In this picture
Clearly shows
Prime numbers
And they are indicated circles
without any inner lines
Remaining composite numbers
Are indicated how many
Factors are indicated
in the circle
And also tables (multiplicative )
Are shown in the below circles.
Do you agree that rich countries have systematically impoverished lo.pdf
Do you agree that rich countries have systematically impoverished low-income countries,
making poor nations dependent on rich ones? Why or why not?
Solution
Yes. Here we explains the idea of dependency to understand the above informations.
Dependency theory
The dependency theory explains that global poverty atleast partially be attributed the fact that the
low income countries have been exploited by the higher income countries. According to
dependency theorist, After the world capitalism, the rich countries are always impoverished low
income countries and their people. We know that the economic growth is key to economic
development. When economic development is happend the income and standered of living of the
peoples are increased.
When the low income countries are trapped the dependency on the richer nations then they have
loss their entire economic control..
Differentiate between physical and chemical methods used to control m.pdf
Differentiate between physical and chemical methods used to control microbial growth; and
give 5 examples of each (Chapter 7). Describe pre-translational control through an inducible
operon, a repressible operon, positive regulation and epigenetic control and describe post-
transcriptional control (Chapter 8). Describe the three mechanisms whereby genes are
transferred from one bacterium to another (Chapter 8). Describe a typical genetic modification
procedure (Chapter 9). Identify 8 different pharmaceutical products of rDNA produced by E.
coli (Chapter 9) Identify 5 different pharmaceutical products of rDNA produced by S. cerevisiae
(yeast) (Chapter 9). Identify 7 different pharmaceutical products of rDNA produced by
mammalian cell culture (Chapter 9).
Solution
Q.NO I
Methods used to manage the growth of microbial growth could be placed into two broad
categories, physical and chemical. Physical methods either exclude microbes, or reduce their
numbers in a remedy, or at first glance of a fomite Examples for physical methods: heat, drying
or desiccation, filtration and radiation. Chemical methods involve the application of specific
chemical agents which inhibit growth or kill microbes on fomites or the outer lining of skin. The
choice of a suitable technique is essential, since many physical and chemical agents can cause
damage to the cells and tissues of the individual along with the microbe. Examples : detergents,
solvents, oxidizing agents and heavy metals.
Q.No III
Positive transcriptional control requires an activator protein to stimulate transcription at the
operon. In negative control, a repressor protein inhibits or turns off transcription at the operon.
An inducible operon normally is not transcribed. It needs an inducer molecule to stimulate
transcription either by inactivating a repressor protein in a negative inducible operon or by
stimulating the activator protein in a confident inducible operon. Transcription normally occurs
in a repressible operon. In a repressible operon, transcription is turned off either by the repressor
becoming active in a negative repressible operon or by the activator becoming inactive in a
confident repressible operon.
Q.No IV
Genetic transfer is the mechanism by which DNA is transferred from a donar to a recipient. Once
donar DNA is inside the recipient, crossing over can occur. The result is just a recombinant cell
that\'s a genome different from either the donar or the recipient. In bacteria genetic transfer can
happen three ways:
Transformation - horizontal gene transfer\' \', where exogenous genetic material passes from
bacterium to another.
Transduction - DNA is transferred from one bacterium to another with a virus. Additionally it
refers to the method whereby foreign DNA is introduced into another cell using a viral vector.
Conjugation - is the transfer of genetic material between bacterial cells by direct cell-to-cell
contact or with a bridge-like connection between two cells. It is just a mecha.
Describe the complexities stemming from U. S.-based companies operat.pdf
Describe the complexities stemming from U. S.-based companies operating in an international
environment.
Solution
Answer:
we can discuss the main complexities stemming from U. S.-based companies operating in an
international environment.
Company has risk associated to settle its accounts in different currency from the U. S. dollars.
Such company have complexities for translation of the financial statements prepared with foreign
currency.
Every country has different accounting standered so these company has to face the differences in
particular nation\'s accounting standards.
Such U. S.-based companies operating in an international environment may have complexities
for.
An elevator starts with five passengers and stops on eight floors. I.pdf
An elevator starts with five passengers and stops on eight floors. If each passenger is equally
likely
to get off on any floor, what is the probability that no two passengers will get off on the same
floor?
Solution
Note that
P(no two passengers are same) = P(all are unique)
There are 8P5 = 6720 ways for them to get off at distinct floors.
Also, there are 8^5 = 32768 ways for them to get off.
Thus,
P(all unique) = 6720/32768
= 0.205078125 [ANSWER].
Write a recursive function to print portion of a linked list in r.pdf
Write a recursive function to print portion of a linked list in reverse order. The portion is to be
printed between node P and Q.
Solution
Hi, I wrote function in C++.
// function to print linked list in reverse order from node P to node Q
// lets assume that structure of Node is:
struct Node{
Node *next;
int data;
};
void printRecursive(Ndoe *p, Node *q){
// if list is empty
if(p == NULL)
return;
// base case, if we have only one node
if(p == q){
cout<data<next);
// print p\'s data
cout<data<.
Why does salt dissolve in waterThe positive charges of sodium (Na.pdf
Why does salt dissolve in water?
The positive charges of sodium (Na) and the negative charges of chloride (Cl) interact with water
molecules
The NaCl molecules form covalent bonds with the surrounding water molecules
The water molecules are attracted to the nonpolar bonds of the sodium and chloride ions
The ionic bond between the sodium ion and chloride ion is strong
None of the above
Why does salt dissolve in water?A.
The positive charges of sodium (Na) and the negative charges of chloride (Cl) interact with
water moleculesB.
The NaCl molecules form covalent bonds with the surrounding water moleculesC.
The water molecules are attracted to the nonpolar bonds of the sodium and chloride ionsD.
The ionic bond between the sodium ion and chloride ion is strongE.
None of the above
Solution
Answer from the above options is A PART
When we try to dissolve an ionic compound by stirring it in water, the positive poles of the water
molecules are attracted to the anions, while the negative poles of other water molecules are
attracted to the cations, so the polar water molecules \"pull\" the ions out of a crystal. As a result
of these interactions, the ionic bonds eventually break and ions are released into the water. When
the salt is dissolved, every ion is surrounded by water molecules, creating a kind of concentric
shells of polar water molecules centered around the ions. (They also look like petals of a daisy).
This process is called \"hydration.\"
The hydration of its ions causes a salt crystal to break apart (dissolve) in the water. Therefore,
when table salt (NaCl) is dissolved, two hydrated ions appear in the water: a positively cation
Na+ and a negative charged anion Cl-. Each is surrounded with a shell of closely attracted water
molecules that prevent the ions from reconciling into a crystal again.
These watery shells prevent the ions from getting together again into a solid. Hydrated ions
jostles around the solution, dispersing evenly in the solution and causing the particles to
disappear from view as they are spreading within the solution. The hydrated ions are so small
that we cannot see them even with a strong microscope. and therefore we see the process as a
disappearance of particles from view as the dissolving progresses.
Different ions can attract different number of water molecules into the \"watery shell\" because
they can have different strength (density) of their charge. The density of the charge depends on
the ratio of charge to surface area of an ion; the larger the ratio, the larger the hydration number
will be..
Which of the terms below is most appropriate for describing the natu.pdf
Which of the terms below is most appropriate for describing the nature of the transfer function?
Voltage gain
Transadmittance
Transimpedancea.
Voltage gainb.
Transadmittancec.
Transimpedanced.
Current gain
Solution
Ans) C Transinmpedance
because transfer function represents Vo(s)/Ii(s) = Z(Impedance) so it is a Transimpedance
Transfer function.
What was the type of donor cell if the recipient genotype changes bu.pdf
What was the type of donor cell if the recipient genotype changes but it does not become a
donor?a) Fb) F+c) Hfrd) F
Solution
Answer:
c). Hfr
F+ is the donor that donate genotype ans stay the same as F+, but the recipient cell also bocomes
F+. If Hfr is the donor, but the recipient cell does nto become Hfr cell (donor).
What is evolution What is it when we say the theory of evolution.pdf
What is evolution? What is it when we say the theory of evolution? What does the theory of
evolution say about the diversity of life on earth?
What is evolution? What is it when we say the theory of evolution? What does the theory of
evolution say about the diversity of life on earth?
Solution
Evolution is defined as the process by which different kinds of living organisms are believed to
have developed from earlier forms during the history of the earth. Biological evolution refers to
cumulative changes that occur in a population over time.
Theory of evolution: The theory of evolution proposed by Charles Darwin, entails the evolution
by natural selection of life on earth. It states that new generations are born with different
inheritable traits, and that the traits superior for the survival will be passed on to new generation.
This means that given enough time an organism can change and evolve to create a new speices.
Using the theory of evolution, scientists predicted the ancestors of modern life forms,
paleontologists found fossils that backed up the initial predictions..
What are the possible types of interfund transfers What are th.pdf
What are the possible types of interfund transfers?
What are the possible types of interfund transfers?
Solution
An interfund transfer moves the money already in your account among the TSP investment
funds.
The two major categories of interfund transfers are as follows:
1. Residual equity transfers.
2. Operating transfers.
Using sampling and Sampling DistributionsA financial institution s.pdf
Using sampling and Sampling Distributions
A financial institution sells several kinds of investment products - a stock fund, a bond fund, and
a tax-deferred annuity. The company is examining whether customer satisfaction depends on the
type of investment product purchased. To do this, 100 clients are randomly selected from the
population of clients who have purchased shares in exactly one of the funds. The company
records the fund type purchased by these clients and asks each sampled client to rate his/her level
of satisfaction with the fund as either high, medium, or low. Analyze this data and summarize
your results.
FundType
SRating
BOND
HIGH
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
LOW
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
BOND
HIGH
BOND
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
LOW
BOND
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
TAXDEF
HIGH
TAXDEF
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
FundType
SRating
BOND
HIGH
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
LOW
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
BOND
HIGH
BOND
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
LOW
BOND
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
TAXDEF
HIGH
TAXDEF
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
Solution
HIGH MED LOW TOTAL
BOND 15 12 3 30
STOCK 24 3 3 30
TAX 1 24 15 40
NOW IN BOND
50% OF PPL RATE HIGH, 40% AS MEDIUM AND 10% AS LOW
IN STOCK
80% 0F PPL RATED AS HIGH, 10% LOW 10% MEDIUM
IN TAXDEF
60% PF PPL RATED AS MEDIUM,27.5% P.
Can someone explain 9 and 10 My teacher did one problem like this a.pdf
Can someone explain 9 and 10? My teacher did one problem like this and it made no sense when
she tried to explain because she\'s a foreign teacher. Therefore, I honestly have. I idea how I\'m
supposed to go about answering these questions. 4, cos 8. tan (105°) Given information about the
angles, use sum or difference identities to find the trigonometric function value of the
combination of the angles IL. 9. IfsinAs--where A is in quadrant IV, and cos B=-where B is in
quadrant 1, find the exact value of sin(A + B). 10. If cos A where A is in quadrant I, and cos B
where B is in quadrant II, 11. If sin A =-1 where A is in quadrant III, and sin B = 3 where B is in
quadrant II, 12. If tan A =-12 where A is in quadrant ll, and tan B-where B is in quadrant l. find
the exact value of sin(A -B). find the exact value of cos(A + B). find the exact value of tan(A
+B). 13. If secAs v 50 where A is in quadrant I, and csc B =--where B is in quadrant V17 III,
find the exact value of tan(A - B). 14. If sin A-13 where A is in quadrant IV, and cos B = s where
Bis in quadrant 1, sin A=-- find the exact value of sin(A - B), cos (A -B), and the quadrant of
angle (A - B).
Solution
9) sinA = -5/6 where A is in QIV and cosB = 4/5 where B is in QI
cosA = sqrt( 1 - sin^2A) = sqrt( 1 - 25/36) = sqrt(11)/6 (cos is +ve in QIV)
sinB = sqrt( 1 - cos^2B) = sqrt( 1 - 16/25) = 3/5 (sin is +ve in Q I)
sin(A +B) = sinAcosB + cosAsinB
plug all the values
= (-5/6)(4/5) + (sqrt(11)/6)(3/5)
= [3sqrt11 - 20]/30
10) cosA =2/3 where A is in QI ; cosB = -1/4 where B is in QIII
sinA = sqrt( 1 - cos^2A) = sqrt( 1 -4/9) = sqrt(5)/3 ; ( sin is +ve in QI)
cosB = -1/4 ; sinB = sqrt( 1 - cos^B) = - sqrt(1 - 1/16) = - sqrt(15)/4 (sin is -ve in QIII)
sin(A - B) = sinAcosB + cosAsinB
= ( sqrt(5)/3)(-1/4) + (2/3)(-sqrt(15)/4)
= [ -sqrt(5) -2sqrt(15) ]/12.
tier 2 railroad retirement benefits are treated as social security. .pdf
tier 2 railroad retirement benefits are treated as social security. true or false
Solution
False
Tier 2 railroad benifits are not treated like social security.Tier 2 benifits are treated like private
pension
The Non social security equivalent benifit portion of tier I, tier II benefits, vested dual benefits,
and supplemental annuities are all treated like private pensions for Federal income tax purposes.
This is because social security benefits based on age and service are not payable before age 62,
social security disability benefit entitlement requires total disability, and the Social Security
Tier 2 benifits primarily include those in which early retirement benefits are payable to retired
employees and spouses between ages 60 and 62, disability benefits, and other categories of
unique RRB entitlements, the entire annuity may be treated like a private pension.
Tier 1 Railroad Retirement benefits that are designated as Social Security Equivalent Benefits,
listed on Form RRB-1099, sent by the government to recipients, is taxed like Social Security.
Other Tier 1 benefits and all Tier 2 benefits are treated as pension income under tax law..
9. What type of enzymes are called the ‘scalpels of molecular biolog.pdf
9. What type of enzymes are called the ‘scalpels of molecular biology’? (10 points)
Solution
Answer:- Restriction endunuleases are called molecular scalpels or molecular scissors or knives
because they cut the DNA at the specific restriction sites where any gene of intrest can be
inserted. They are backbone of recombinant DNA technology..
3. We learn a lot of information from model organisms. Frequently, t.pdf
3. We learn a lot of information from model organisms. Frequently, these model organisms have
a particular “specialty” – a particular field within biology for which the organism has provided a
lot of information. Name 2 model organisms and tell what the “specialty” of each is.
Solution
Model organism is a species or strain that has been widely studied, because of easy maintenance,
easy breeding in the lab and possess experimental advantages.
E. coli is Gram - ve prokaryotic model organism
Drosophila melanogaster is, model organisms for Animal genetics
Saccharomysis cereveciae or yeast is a model organism for Eukaryotes
Arabidopsis is model organisms for plant studies
All these model organisms possess simple morphology, less genome size, less breading time,
mostly related to higher organisms etc.
2. Division of the cytoplasm is called 3. Do each of the following de.pdf
2. Division of the cytoplasm is called 3. Do each of the following descriptions characterize
mitosis, meiosis, or both mitosis and meiosis? a. Produces haploid gametes b. Results in
formation of four daughter cells. c. Crossing over of chromosomes occurs. d. Is preceded by
interphase. e. Produces diploid cells.
Solution
2) cytokinesis..
3) (a) meosis which is also called a reductional division produces a haploid gamets..
(b) meosis results in formation of 4 daughters cells
(c) meosis where crossing over takes place at pachytene stage.
(d) meosis and mitosis both occurs after inter phase..
(e) mitosis produce 2 daughters cells which are diploid..
1. How is the recipient cell different from before the two cells mat.pdf
1. How is the recipient cell different from before the two cells mated? Phenotypically as well as
genetically.
2. What do F+ cells do?
3. What are all properties of a recipient cell (which receives the F plasmid)?
Solution
1. Recipient cell (F- cell) is different after it mates with the F+ cell. Conjugation/mating is
equivalent to sex (however no new individuals are produced in this case) in that it combines
genetic material from two different individuals into a single genome.It occurs through F pili
which originate from cell membrane and project outward beyond the cell wall. Thus, like sexual
reproduction conjugation produces new genetic combinations. The pilus is essential for
recognition of recipient cell. The sex plasmid passes from the donor F+ to the recipient F– cell
through the conjugation tube, and seperates after the event is over and now called as
exconjugates. F- cell after matinh with F+ cell, now becomes F+ and can act as donor during
next conjugation event.
After conjugation event, recipient cell now contains the F factor. Genetic changes takes place in
the recipient cell. Once inside the F cell, the linear single-stranded DNA molecule acts as a
polymerization template and is converted into a DNA double helix. This linear donor fragment is
termed as the exogenote, and the resident F chromosome is termed as the endogenote. Crossover
events take place which integrate a part of the donor genome into the recipient. It is in this way
that recombination takes place.
2. F+ cells are the bacterial cells which possess F factor as a plasmid independent of the bacterial
genome. The F cell plasmid contains F factor as the only DNA and no DNA from the bacterial
genome. Mating or conjugation of an F+ cell with an F cell, result in two F+ cells, both of which
are capable of transmitting the plasmid to other F cells by conjugation. Thus F+ bacterial cells
act as donor. The F+ cells also contain surface exclusion proteins; TraS and TraT on the bacterial
surface. These proteins have the capability to prevent secondary mating events involving
plasmids belonging to the same incompatibility group. Thus, each F+ bacterium can host only a
single plasmid type of any given incompatibility group.
3. Properties of Recipient cells (receiving the F plasmid)
Recipients are basically F bacteria that do not contain F factor (F plasmid), and are considered as
female. The F-plasmid is a class of conjugative plasmids that control sexual functions of bacteria
with a fertility inhibition (Fin) system. In this system, FinO, which is a trans-acting factor and
Fin P, an antisense RNAs, combine to repress the expression of the activator gene TraJ. TraJ is a
transcription factor that upregulates the tra operon, which contains the genes required for
conjugation and plasmid transfer. The F- plasmid can exist in two alternative states, viz. it can
either remain free in the cell or it can be integrated into the E. coli chromosome.called as
episomes. The F-plasmid also carr.
1 of 2 CS140 Joes Automotive performs the following routine mainten.pdf
1 of 2 CS140 Joe\'s Automotive performs the following routine maintenance services: Oil
change-$26.00 Lube job-$18.00 Radiator flush-$30.00 . Transmission flush-$80.00 Inspection-
$15.00 Muffler replacement-$100.00 Tire rotation-$20.00 Joe also performs other nonroutine
services and charges for parts and labor ($20 per hour). Create an application that displays the
total for a customer\'s visit to Joe\'s. The form should resemble the one shown in Figure below:
and Lube Rushes Mac Parts and Labor Inspection ($15 00) Pats Replace Mier ($10000) labors
Tre Rotation ($2000) Summary Service and Labor Parts Tax (on parts) Total Fees Calculate
Clear Et
Solution
Form1.cs
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace JoesAutomotive
{
public partial class frmAutomotive : Form
{
public frmAutomotive()
{
InitializeComponent();
}
private void btnExit_Click(object sender, EventArgs e)
{
this.Close();
}
private void btnClear_Click(object sender, EventArgs e)
{
//call methods to clear all inputs on form
ClearOilLube(); // Clear OilLube group
ClearFlushes(); // Clear Flushes group
ClearMisc(); // Clear Misc group
ClearOther(); // Clear Other Fees group
ClearFees(); //Clear Summary group
}
public void ClearCheckBoxAndTextBoxControls(Control parent)
{
//Loops there all the controls within a groupbox revewing each control
foreach (Control control in parent.Controls)
{
//Checkbox controls are reset
if (control is CheckBox)
{
((CheckBox)control).Checked = false;
}
//Textbox controls are cleared of any text
else if (control is TextBox)
{
((TextBox)control).Text = \"\";
}
}
}
private void ClearOilLube()
{
ClearCheckBoxAndTextBoxControls(grpbxOil_Lube);
}
private void ClearFlushes()
{
ClearCheckBoxAndTextBoxControls(grpbxFlushes);
}
private void ClearMisc()
{
ClearCheckBoxAndTextBoxControls(grpbxMisc);
}
private void ClearOther()
{
ClearCheckBoxAndTextBoxControls(grpbxParts_Labor);
}
private void ClearFees()
{
lblParts.Text = \"\";
lblService_Labor.Text = \"\";
lblTax.Text = \"\";
lblTotalFees.Text = \"\";
}
private void btnCalculateTotal_Click(object sender, EventArgs e)
{
//Check to make sure the textboxes are valid
if (CheckTextBoxes())
{
double otherCharges = OtherCharges(); // Calls method to calculate Other Group
Charges
double oilLubeCharges = OilLubeCharges(); // Calls method to calculate Oil and Lube
Group Charges
double flushCharges = FlushCharges(); // Calls method to caclulate Flush Group
Charges
double miscCharges = MiscCharges(); // Calls method to calculate Misc Group
Charges
double taxCharges = TaxCharges(); // Call method to calculate Tax
double laborCharges = LaborCharges(); // Call Method for Labor Charges
//Assign Total Service and Labor Charges to Lable
lblService_Labor.Text = TotalCharges(oilLubeCharges, flushCharges, miscCharges,
laborCharges);
//Assign Total Fees to Lable
lblTotalFees.Text = TotalCh.
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
More Related Content
More from libowskymcinnisell69
For graph to the right Amplitude Midline Period Equation using.pdf
For graph to the right Amplitude: Midline: Period: Equation using sine: Equation using
cosine:
Solution
a) amplitude =|(1-(-7))|/2 =4
b) mid line y=[1+(-7)]/2
y=-3
c)period =3-(-1)=4
d)equation using sine :
vertical shift D=-3
period =2/B=4 =>B=/2
y =4sin((/2)x) -3
d)equation using cosine
vertical shift D=-3
period =2/B=4 =>B=/2
phase shift =-C/B=1 =>C=-B=>C =-/2
y =4cos((/2)x-(/2)) -3.
Explain what exactly is going on with this picture. SolutionIn.pdf
Explain what exactly is going on with this picture.
Solution
In this picture
Clearly shows
Prime numbers
And they are indicated circles
without any inner lines
Remaining composite numbers
Are indicated how many
Factors are indicated
in the circle
And also tables (multiplicative )
Are shown in the below circles.
Do you agree that rich countries have systematically impoverished lo.pdf
Do you agree that rich countries have systematically impoverished low-income countries,
making poor nations dependent on rich ones? Why or why not?
Solution
Yes. Here we explains the idea of dependency to understand the above informations.
Dependency theory
The dependency theory explains that global poverty atleast partially be attributed the fact that the
low income countries have been exploited by the higher income countries. According to
dependency theorist, After the world capitalism, the rich countries are always impoverished low
income countries and their people. We know that the economic growth is key to economic
development. When economic development is happend the income and standered of living of the
peoples are increased.
When the low income countries are trapped the dependency on the richer nations then they have
loss their entire economic control..
Differentiate between physical and chemical methods used to control m.pdf
Differentiate between physical and chemical methods used to control microbial growth; and
give 5 examples of each (Chapter 7). Describe pre-translational control through an inducible
operon, a repressible operon, positive regulation and epigenetic control and describe post-
transcriptional control (Chapter 8). Describe the three mechanisms whereby genes are
transferred from one bacterium to another (Chapter 8). Describe a typical genetic modification
procedure (Chapter 9). Identify 8 different pharmaceutical products of rDNA produced by E.
coli (Chapter 9) Identify 5 different pharmaceutical products of rDNA produced by S. cerevisiae
(yeast) (Chapter 9). Identify 7 different pharmaceutical products of rDNA produced by
mammalian cell culture (Chapter 9).
Solution
Q.NO I
Methods used to manage the growth of microbial growth could be placed into two broad
categories, physical and chemical. Physical methods either exclude microbes, or reduce their
numbers in a remedy, or at first glance of a fomite Examples for physical methods: heat, drying
or desiccation, filtration and radiation. Chemical methods involve the application of specific
chemical agents which inhibit growth or kill microbes on fomites or the outer lining of skin. The
choice of a suitable technique is essential, since many physical and chemical agents can cause
damage to the cells and tissues of the individual along with the microbe. Examples : detergents,
solvents, oxidizing agents and heavy metals.
Q.No III
Positive transcriptional control requires an activator protein to stimulate transcription at the
operon. In negative control, a repressor protein inhibits or turns off transcription at the operon.
An inducible operon normally is not transcribed. It needs an inducer molecule to stimulate
transcription either by inactivating a repressor protein in a negative inducible operon or by
stimulating the activator protein in a confident inducible operon. Transcription normally occurs
in a repressible operon. In a repressible operon, transcription is turned off either by the repressor
becoming active in a negative repressible operon or by the activator becoming inactive in a
confident repressible operon.
Q.No IV
Genetic transfer is the mechanism by which DNA is transferred from a donar to a recipient. Once
donar DNA is inside the recipient, crossing over can occur. The result is just a recombinant cell
that\'s a genome different from either the donar or the recipient. In bacteria genetic transfer can
happen three ways:
Transformation - horizontal gene transfer\' \', where exogenous genetic material passes from
bacterium to another.
Transduction - DNA is transferred from one bacterium to another with a virus. Additionally it
refers to the method whereby foreign DNA is introduced into another cell using a viral vector.
Conjugation - is the transfer of genetic material between bacterial cells by direct cell-to-cell
contact or with a bridge-like connection between two cells. It is just a mecha.
Describe the complexities stemming from U. S.-based companies operat.pdf
Describe the complexities stemming from U. S.-based companies operating in an international
environment.
Solution
Answer:
we can discuss the main complexities stemming from U. S.-based companies operating in an
international environment.
Company has risk associated to settle its accounts in different currency from the U. S. dollars.
Such company have complexities for translation of the financial statements prepared with foreign
currency.
Every country has different accounting standered so these company has to face the differences in
particular nation\'s accounting standards.
Such U. S.-based companies operating in an international environment may have complexities
for.
An elevator starts with five passengers and stops on eight floors. I.pdf
An elevator starts with five passengers and stops on eight floors. If each passenger is equally
likely
to get off on any floor, what is the probability that no two passengers will get off on the same
floor?
Solution
Note that
P(no two passengers are same) = P(all are unique)
There are 8P5 = 6720 ways for them to get off at distinct floors.
Also, there are 8^5 = 32768 ways for them to get off.
Thus,
P(all unique) = 6720/32768
= 0.205078125 [ANSWER].
Write a recursive function to print portion of a linked list in r.pdf
Write a recursive function to print portion of a linked list in reverse order. The portion is to be
printed between node P and Q.
Solution
Hi, I wrote function in C++.
// function to print linked list in reverse order from node P to node Q
// lets assume that structure of Node is:
struct Node{
Node *next;
int data;
};
void printRecursive(Ndoe *p, Node *q){
// if list is empty
if(p == NULL)
return;
// base case, if we have only one node
if(p == q){
cout<data<next);
// print p\'s data
cout<data<.
Why does salt dissolve in waterThe positive charges of sodium (Na.pdf
Why does salt dissolve in water?
The positive charges of sodium (Na) and the negative charges of chloride (Cl) interact with water
molecules
The NaCl molecules form covalent bonds with the surrounding water molecules
The water molecules are attracted to the nonpolar bonds of the sodium and chloride ions
The ionic bond between the sodium ion and chloride ion is strong
None of the above
Why does salt dissolve in water?A.
The positive charges of sodium (Na) and the negative charges of chloride (Cl) interact with
water moleculesB.
The NaCl molecules form covalent bonds with the surrounding water moleculesC.
The water molecules are attracted to the nonpolar bonds of the sodium and chloride ionsD.
The ionic bond between the sodium ion and chloride ion is strongE.
None of the above
Solution
Answer from the above options is A PART
When we try to dissolve an ionic compound by stirring it in water, the positive poles of the water
molecules are attracted to the anions, while the negative poles of other water molecules are
attracted to the cations, so the polar water molecules \"pull\" the ions out of a crystal. As a result
of these interactions, the ionic bonds eventually break and ions are released into the water. When
the salt is dissolved, every ion is surrounded by water molecules, creating a kind of concentric
shells of polar water molecules centered around the ions. (They also look like petals of a daisy).
This process is called \"hydration.\"
The hydration of its ions causes a salt crystal to break apart (dissolve) in the water. Therefore,
when table salt (NaCl) is dissolved, two hydrated ions appear in the water: a positively cation
Na+ and a negative charged anion Cl-. Each is surrounded with a shell of closely attracted water
molecules that prevent the ions from reconciling into a crystal again.
These watery shells prevent the ions from getting together again into a solid. Hydrated ions
jostles around the solution, dispersing evenly in the solution and causing the particles to
disappear from view as they are spreading within the solution. The hydrated ions are so small
that we cannot see them even with a strong microscope. and therefore we see the process as a
disappearance of particles from view as the dissolving progresses.
Different ions can attract different number of water molecules into the \"watery shell\" because
they can have different strength (density) of their charge. The density of the charge depends on
the ratio of charge to surface area of an ion; the larger the ratio, the larger the hydration number
will be..
Which of the terms below is most appropriate for describing the natu.pdf
Which of the terms below is most appropriate for describing the nature of the transfer function?
Voltage gain
Transadmittance
Transimpedancea.
Voltage gainb.
Transadmittancec.
Transimpedanced.
Current gain
Solution
Ans) C Transinmpedance
because transfer function represents Vo(s)/Ii(s) = Z(Impedance) so it is a Transimpedance
Transfer function.
What was the type of donor cell if the recipient genotype changes bu.pdf
What was the type of donor cell if the recipient genotype changes but it does not become a
donor?a) Fb) F+c) Hfrd) F
Solution
Answer:
c). Hfr
F+ is the donor that donate genotype ans stay the same as F+, but the recipient cell also bocomes
F+. If Hfr is the donor, but the recipient cell does nto become Hfr cell (donor).
What is evolution What is it when we say the theory of evolution.pdf
What is evolution? What is it when we say the theory of evolution? What does the theory of
evolution say about the diversity of life on earth?
What is evolution? What is it when we say the theory of evolution? What does the theory of
evolution say about the diversity of life on earth?
Solution
Evolution is defined as the process by which different kinds of living organisms are believed to
have developed from earlier forms during the history of the earth. Biological evolution refers to
cumulative changes that occur in a population over time.
Theory of evolution: The theory of evolution proposed by Charles Darwin, entails the evolution
by natural selection of life on earth. It states that new generations are born with different
inheritable traits, and that the traits superior for the survival will be passed on to new generation.
This means that given enough time an organism can change and evolve to create a new speices.
Using the theory of evolution, scientists predicted the ancestors of modern life forms,
paleontologists found fossils that backed up the initial predictions..
What are the possible types of interfund transfers What are th.pdf
What are the possible types of interfund transfers?
What are the possible types of interfund transfers?
Solution
An interfund transfer moves the money already in your account among the TSP investment
funds.
The two major categories of interfund transfers are as follows:
1. Residual equity transfers.
2. Operating transfers.
Using sampling and Sampling DistributionsA financial institution s.pdf
Using sampling and Sampling Distributions
A financial institution sells several kinds of investment products - a stock fund, a bond fund, and
a tax-deferred annuity. The company is examining whether customer satisfaction depends on the
type of investment product purchased. To do this, 100 clients are randomly selected from the
population of clients who have purchased shares in exactly one of the funds. The company
records the fund type purchased by these clients and asks each sampled client to rate his/her level
of satisfaction with the fund as either high, medium, or low. Analyze this data and summarize
your results.
FundType
SRating
BOND
HIGH
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
LOW
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
BOND
HIGH
BOND
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
LOW
BOND
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
TAXDEF
HIGH
TAXDEF
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
FundType
SRating
BOND
HIGH
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
LOW
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
BOND
HIGH
BOND
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
HIGH
TAXDEF
MED
STOCK
LOW
BOND
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
LOW
TAXDEF
LOW
STOCK
MED
BOND
LOW
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
MED
BOND
HIGH
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
TAXDEF
LOW
BOND
MED
STOCK
HIGH
STOCK
HIGH
BOND
MED
TAXDEF
MED
BOND
HIGH
STOCK
MED
STOCK
HIGH
BOND
MED
TAXDEF
MED
TAXDEF
LOW
STOCK
HIGH
TAXDEF
MED
BOND
HIGH
TAXDEF
HIGH
TAXDEF
LOW
TAXDEF
LOW
STOCK
HIGH
BOND
HIGH
BOND
MED
STOCK
HIGH
TAXDEF
MED
TAXDEF
MED
Solution
HIGH MED LOW TOTAL
BOND 15 12 3 30
STOCK 24 3 3 30
TAX 1 24 15 40
NOW IN BOND
50% OF PPL RATE HIGH, 40% AS MEDIUM AND 10% AS LOW
IN STOCK
80% 0F PPL RATED AS HIGH, 10% LOW 10% MEDIUM
IN TAXDEF
60% PF PPL RATED AS MEDIUM,27.5% P.
Can someone explain 9 and 10 My teacher did one problem like this a.pdf
Can someone explain 9 and 10? My teacher did one problem like this and it made no sense when
she tried to explain because she\'s a foreign teacher. Therefore, I honestly have. I idea how I\'m
supposed to go about answering these questions. 4, cos 8. tan (105°) Given information about the
angles, use sum or difference identities to find the trigonometric function value of the
combination of the angles IL. 9. IfsinAs--where A is in quadrant IV, and cos B=-where B is in
quadrant 1, find the exact value of sin(A + B). 10. If cos A where A is in quadrant I, and cos B
where B is in quadrant II, 11. If sin A =-1 where A is in quadrant III, and sin B = 3 where B is in
quadrant II, 12. If tan A =-12 where A is in quadrant ll, and tan B-where B is in quadrant l. find
the exact value of sin(A -B). find the exact value of cos(A + B). find the exact value of tan(A
+B). 13. If secAs v 50 where A is in quadrant I, and csc B =--where B is in quadrant V17 III,
find the exact value of tan(A - B). 14. If sin A-13 where A is in quadrant IV, and cos B = s where
Bis in quadrant 1, sin A=-- find the exact value of sin(A - B), cos (A -B), and the quadrant of
angle (A - B).
Solution
9) sinA = -5/6 where A is in QIV and cosB = 4/5 where B is in QI
cosA = sqrt( 1 - sin^2A) = sqrt( 1 - 25/36) = sqrt(11)/6 (cos is +ve in QIV)
sinB = sqrt( 1 - cos^2B) = sqrt( 1 - 16/25) = 3/5 (sin is +ve in Q I)
sin(A +B) = sinAcosB + cosAsinB
plug all the values
= (-5/6)(4/5) + (sqrt(11)/6)(3/5)
= [3sqrt11 - 20]/30
10) cosA =2/3 where A is in QI ; cosB = -1/4 where B is in QIII
sinA = sqrt( 1 - cos^2A) = sqrt( 1 -4/9) = sqrt(5)/3 ; ( sin is +ve in QI)
cosB = -1/4 ; sinB = sqrt( 1 - cos^B) = - sqrt(1 - 1/16) = - sqrt(15)/4 (sin is -ve in QIII)
sin(A - B) = sinAcosB + cosAsinB
= ( sqrt(5)/3)(-1/4) + (2/3)(-sqrt(15)/4)
= [ -sqrt(5) -2sqrt(15) ]/12.
tier 2 railroad retirement benefits are treated as social security. .pdf
tier 2 railroad retirement benefits are treated as social security. true or false
Solution
False
Tier 2 railroad benifits are not treated like social security.Tier 2 benifits are treated like private
pension
The Non social security equivalent benifit portion of tier I, tier II benefits, vested dual benefits,
and supplemental annuities are all treated like private pensions for Federal income tax purposes.
This is because social security benefits based on age and service are not payable before age 62,
social security disability benefit entitlement requires total disability, and the Social Security
Tier 2 benifits primarily include those in which early retirement benefits are payable to retired
employees and spouses between ages 60 and 62, disability benefits, and other categories of
unique RRB entitlements, the entire annuity may be treated like a private pension.
Tier 1 Railroad Retirement benefits that are designated as Social Security Equivalent Benefits,
listed on Form RRB-1099, sent by the government to recipients, is taxed like Social Security.
Other Tier 1 benefits and all Tier 2 benefits are treated as pension income under tax law..
9. What type of enzymes are called the ‘scalpels of molecular biolog.pdf
9. What type of enzymes are called the ‘scalpels of molecular biology’? (10 points)
Solution
Answer:- Restriction endunuleases are called molecular scalpels or molecular scissors or knives
because they cut the DNA at the specific restriction sites where any gene of intrest can be
inserted. They are backbone of recombinant DNA technology..
3. We learn a lot of information from model organisms. Frequently, t.pdf
3. We learn a lot of information from model organisms. Frequently, these model organisms have
a particular “specialty” – a particular field within biology for which the organism has provided a
lot of information. Name 2 model organisms and tell what the “specialty” of each is.
Solution
Model organism is a species or strain that has been widely studied, because of easy maintenance,
easy breeding in the lab and possess experimental advantages.
E. coli is Gram - ve prokaryotic model organism
Drosophila melanogaster is, model organisms for Animal genetics
Saccharomysis cereveciae or yeast is a model organism for Eukaryotes
Arabidopsis is model organisms for plant studies
All these model organisms possess simple morphology, less genome size, less breading time,
mostly related to higher organisms etc.
2. Division of the cytoplasm is called 3. Do each of the following de.pdf
2. Division of the cytoplasm is called 3. Do each of the following descriptions characterize
mitosis, meiosis, or both mitosis and meiosis? a. Produces haploid gametes b. Results in
formation of four daughter cells. c. Crossing over of chromosomes occurs. d. Is preceded by
interphase. e. Produces diploid cells.
Solution
2) cytokinesis..
3) (a) meosis which is also called a reductional division produces a haploid gamets..
(b) meosis results in formation of 4 daughters cells
(c) meosis where crossing over takes place at pachytene stage.
(d) meosis and mitosis both occurs after inter phase..
(e) mitosis produce 2 daughters cells which are diploid..
1. How is the recipient cell different from before the two cells mat.pdf
1. How is the recipient cell different from before the two cells mated? Phenotypically as well as
genetically.
2. What do F+ cells do?
3. What are all properties of a recipient cell (which receives the F plasmid)?
Solution
1. Recipient cell (F- cell) is different after it mates with the F+ cell. Conjugation/mating is
equivalent to sex (however no new individuals are produced in this case) in that it combines
genetic material from two different individuals into a single genome.It occurs through F pili
which originate from cell membrane and project outward beyond the cell wall. Thus, like sexual
reproduction conjugation produces new genetic combinations. The pilus is essential for
recognition of recipient cell. The sex plasmid passes from the donor F+ to the recipient F– cell
through the conjugation tube, and seperates after the event is over and now called as
exconjugates. F- cell after matinh with F+ cell, now becomes F+ and can act as donor during
next conjugation event.
After conjugation event, recipient cell now contains the F factor. Genetic changes takes place in
the recipient cell. Once inside the F cell, the linear single-stranded DNA molecule acts as a
polymerization template and is converted into a DNA double helix. This linear donor fragment is
termed as the exogenote, and the resident F chromosome is termed as the endogenote. Crossover
events take place which integrate a part of the donor genome into the recipient. It is in this way
that recombination takes place.
2. F+ cells are the bacterial cells which possess F factor as a plasmid independent of the bacterial
genome. The F cell plasmid contains F factor as the only DNA and no DNA from the bacterial
genome. Mating or conjugation of an F+ cell with an F cell, result in two F+ cells, both of which
are capable of transmitting the plasmid to other F cells by conjugation. Thus F+ bacterial cells
act as donor. The F+ cells also contain surface exclusion proteins; TraS and TraT on the bacterial
surface. These proteins have the capability to prevent secondary mating events involving
plasmids belonging to the same incompatibility group. Thus, each F+ bacterium can host only a
single plasmid type of any given incompatibility group.
3. Properties of Recipient cells (receiving the F plasmid)
Recipients are basically F bacteria that do not contain F factor (F plasmid), and are considered as
female. The F-plasmid is a class of conjugative plasmids that control sexual functions of bacteria
with a fertility inhibition (Fin) system. In this system, FinO, which is a trans-acting factor and
Fin P, an antisense RNAs, combine to repress the expression of the activator gene TraJ. TraJ is a
transcription factor that upregulates the tra operon, which contains the genes required for
conjugation and plasmid transfer. The F- plasmid can exist in two alternative states, viz. it can
either remain free in the cell or it can be integrated into the E. coli chromosome.called as
episomes. The F-plasmid also carr.
1 of 2 CS140 Joes Automotive performs the following routine mainten.pdf
1 of 2 CS140 Joe\'s Automotive performs the following routine maintenance services: Oil
change-$26.00 Lube job-$18.00 Radiator flush-$30.00 . Transmission flush-$80.00 Inspection-
$15.00 Muffler replacement-$100.00 Tire rotation-$20.00 Joe also performs other nonroutine
services and charges for parts and labor ($20 per hour). Create an application that displays the
total for a customer\'s visit to Joe\'s. The form should resemble the one shown in Figure below:
and Lube Rushes Mac Parts and Labor Inspection ($15 00) Pats Replace Mier ($10000) labors
Tre Rotation ($2000) Summary Service and Labor Parts Tax (on parts) Total Fees Calculate
Clear Et
Solution
Form1.cs
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace JoesAutomotive
{
public partial class frmAutomotive : Form
{
public frmAutomotive()
{
InitializeComponent();
}
private void btnExit_Click(object sender, EventArgs e)
{
this.Close();
}
private void btnClear_Click(object sender, EventArgs e)
{
//call methods to clear all inputs on form
ClearOilLube(); // Clear OilLube group
ClearFlushes(); // Clear Flushes group
ClearMisc(); // Clear Misc group
ClearOther(); // Clear Other Fees group
ClearFees(); //Clear Summary group
}
public void ClearCheckBoxAndTextBoxControls(Control parent)
{
//Loops there all the controls within a groupbox revewing each control
foreach (Control control in parent.Controls)
{
//Checkbox controls are reset
if (control is CheckBox)
{
((CheckBox)control).Checked = false;
}
//Textbox controls are cleared of any text
else if (control is TextBox)
{
((TextBox)control).Text = \"\";
}
}
}
private void ClearOilLube()
{
ClearCheckBoxAndTextBoxControls(grpbxOil_Lube);
}
private void ClearFlushes()
{
ClearCheckBoxAndTextBoxControls(grpbxFlushes);
}
private void ClearMisc()
{
ClearCheckBoxAndTextBoxControls(grpbxMisc);
}
private void ClearOther()
{
ClearCheckBoxAndTextBoxControls(grpbxParts_Labor);
}
private void ClearFees()
{
lblParts.Text = \"\";
lblService_Labor.Text = \"\";
lblTax.Text = \"\";
lblTotalFees.Text = \"\";
}
private void btnCalculateTotal_Click(object sender, EventArgs e)
{
//Check to make sure the textboxes are valid
if (CheckTextBoxes())
{
double otherCharges = OtherCharges(); // Calls method to calculate Other Group
Charges
double oilLubeCharges = OilLubeCharges(); // Calls method to calculate Oil and Lube
Group Charges
double flushCharges = FlushCharges(); // Calls method to caclulate Flush Group
Charges
double miscCharges = MiscCharges(); // Calls method to calculate Misc Group
Charges
double taxCharges = TaxCharges(); // Call method to calculate Tax
double laborCharges = LaborCharges(); // Call Method for Labor Charges
//Assign Total Service and Labor Charges to Lable
lblService_Labor.Text = TotalCharges(oilLubeCharges, flushCharges, miscCharges,
laborCharges);
//Assign Total Fees to Lable
lblTotalFees.Text = TotalCh.
More from libowskymcinnisell69 (20)
For graph to the right Amplitude Midline Period Equation using.pdf
For graph to the right Amplitude Midline Period Equation using.pdf
Explain what exactly is going on with this picture. SolutionIn.pdf
Explain what exactly is going on with this picture. SolutionIn.pdf
Do you agree that rich countries have systematically impoverished lo.pdf
Do you agree that rich countries have systematically impoverished lo.pdf
Differentiate between physical and chemical methods used to control m.pdf
Differentiate between physical and chemical methods used to control m.pdf
Describe the complexities stemming from U. S.-based companies operat.pdf
Describe the complexities stemming from U. S.-based companies operat.pdf
An elevator starts with five passengers and stops on eight floors. I.pdf
An elevator starts with five passengers and stops on eight floors. I.pdf
Write a recursive function to print portion of a linked list in r.pdf
Write a recursive function to print portion of a linked list in r.pdf
Why does salt dissolve in waterThe positive charges of sodium (Na.pdf
Why does salt dissolve in waterThe positive charges of sodium (Na.pdf
Which of the terms below is most appropriate for describing the natu.pdf
Which of the terms below is most appropriate for describing the natu.pdf
What was the type of donor cell if the recipient genotype changes bu.pdf
What was the type of donor cell if the recipient genotype changes bu.pdf
What is evolution What is it when we say the theory of evolution.pdf
What is evolution What is it when we say the theory of evolution.pdf
What are the possible types of interfund transfers What are th.pdf
What are the possible types of interfund transfers What are th.pdf
Using sampling and Sampling DistributionsA financial institution s.pdf
Using sampling and Sampling DistributionsA financial institution s.pdf
Can someone explain 9 and 10 My teacher did one problem like this a.pdf
Can someone explain 9 and 10 My teacher did one problem like this a.pdf
tier 2 railroad retirement benefits are treated as social security. .pdf
tier 2 railroad retirement benefits are treated as social security. .pdf
9. What type of enzymes are called the ‘scalpels of molecular biolog.pdf
9. What type of enzymes are called the ‘scalpels of molecular biolog.pdf
3. We learn a lot of information from model organisms. Frequently, t.pdf
3. We learn a lot of information from model organisms. Frequently, t.pdf
2. Division of the cytoplasm is called 3. Do each of the following de.pdf
2. Division of the cytoplasm is called 3. Do each of the following de.pdf
1. How is the recipient cell different from before the two cells mat.pdf
1. How is the recipient cell different from before the two cells mat.pdf
1 of 2 CS140 Joes Automotive performs the following routine mainten.pdf
1 of 2 CS140 Joes Automotive performs the following routine mainten.pdf
Recently uploaded
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)Academy of Science of South Africa
A workshop hosted by the South African Journal of Science aimed at postgraduate students and early career researchers with little or no experience in writing and publishing journal articles.Biological Screening of Herbal Drugs in detailed.
Biological screening of herbal drugs: Introduction and Need for
Phyto-Pharmacological Screening, New Strategies for evaluating
Natural Products, In vitro evaluation techniques for Antioxidants, Antimicrobial and Anticancer drugs. In vivo evaluation techniques
for Anti-inflammatory, Antiulcer, Anticancer, Wound healing, Antidiabetic, Hepatoprotective, Cardio protective, Diuretics and
Antifertility, Toxicity studies as per OECD guidelines
Unit 2- Research Aptitude (UGC NET Paper I).pdf
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
special B.ed 2nd year old paper_20240531.pdf
Instagram:-
https://instagram.com/special_education_needs_01?igshid=YmMyMTA2M2Y=
WhatsApp:-
https://chat.whatsapp.com/JVakNIYlSV94x7bwunO3Dc
YouTube:-
https://youtube.com/@special_education_needs
Teligram :- https://t.me/special_education_needs
Slide Shere :-
https://www.slideshare.net/shabnambano20?utm_campaign=profiletracking&utm_medium=sssite&utm_source=ssslideview
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH ANSWERS.
Introduction to AI for Nonprofits with Tapp Network
Dive into the world of AI! Experts Jon Hill and Tareq Monaur will guide you through AI's role in enhancing nonprofit websites and basic marketing strategies, making it easy to understand and apply.
The Challenger.pdf DNHS Official Publication
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
Model Attribute Check Company Auto Property
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Thesis Statement for students diagnonsed withADHD.ppt
Presentation required for the master in Education.
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...Dr. Vinod Kumar Kanvaria
Exploiting Artificial Intelligence for Empowering Researchers and Faculty,
International FDP on Fundamentals of Research in Social Sciences
at Integral University, Lucknow, 06.06.2024
By Dr. Vinod Kumar KanvariaRecently uploaded (20)
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
South African Journal of Science: Writing with integrity workshop (2024)
South African Journal of Science: Writing with integrity workshop (2024)
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk - How can education support child empowerment.pptx
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
Introduction to AI for Nonprofits with Tapp Network
Introduction to AI for Nonprofits with Tapp Network
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Exploiting Artificial Intelligence for Empowering Researchers and Faculty, In...
Why might a transposon screen for genes required for virulence in a .pdf
- 1. Why might a transposon screen for genes required for virulence in a bacterium NOT identify a particular gene required for virulence in humans? Solution There is lack of transposons specific to vertebrates. Hence, the usage of transposons in vertebrates has been limited. Transposons present and compatible inside vertebrate genomes are inactive or "junk" DNA.