The mole is a unit of measurement for the amount .pdf
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The mole is a unit of measurement for the amount of substance or chemical amount. It is one of the base units in the International System of Units, and has the unit symbol mol. n ionic compound is a chemical compound in which ions are held together in a lattice structure by ionic bonds. Usually, the positively charged portion consists of metal cations and the negatively charged portion is an anion or polyatomic ion. Ions in ionic compounds are held together by the electrostatic force between oppositely charged bodies. Ionic compounds have a high melting and boiling point, and they are hard and very brittle. Solution The mole is a unit of measurement for the amount of substance or chemical amount. It is one of the base units in the International System of Units, and has the unit symbol mol. n ionic compound is a chemical compound in which ions are held together in a lattice structure by ionic bonds. Usually, the positively charged portion consists of metal cations and the negatively charged portion is an anion or polyatomic ion. Ions in ionic compounds are held together by the electrostatic force between oppositely charged bodies. Ionic compounds have a high melting and boiling point, and they are hard and very brittle..
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yep in water which is higly polar will dissolve ionic NaCl but not nonpolar steric
acid yes.
When thinking of E or Z, the first thing that com.pdf
When thinking of E or Z, the first thing that comes to mind is the double bond of
the alkene. From there, you look at the atom attach to the double bond of the alkene. There are 4
atoms: 1) Carbon (top left) : bonded to 1 carbon and 2 hydrogen 2) Carbon (bottom left) : bonded
to 2 Oxygen [treat double bond here as two bonds] and 1 Hydrogen 3) Carbon (top right) :
bonded to 2 carbon and 1 hydrogen 4) Hydrogen (bottom right) : bonded to nothing. On each
side of the double bond, rank the priority (with respect to molecular mass) Bottom left >> Top
left Top right >> bottom right since the two groups are trans each other, this is an E isomer
Solution
When thinking of E or Z, the first thing that comes to mind is the double bond of
the alkene. From there, you look at the atom attach to the double bond of the alkene. There are 4
atoms: 1) Carbon (top left) : bonded to 1 carbon and 2 hydrogen 2) Carbon (bottom left) : bonded
to 2 Oxygen [treat double bond here as two bonds] and 1 Hydrogen 3) Carbon (top right) :
bonded to 2 carbon and 1 hydrogen 4) Hydrogen (bottom right) : bonded to nothing. On each
side of the double bond, rank the priority (with respect to molecular mass) Bottom left >> Top
left Top right >> bottom right since the two groups are trans each other, this is an E isomer.
Since it contains oxygen double bonded to a carbo.pdf
Since it contains oxygen double bonded to a carbon atom , it may beCaboxylic acid
or carbonyl compound. So the characteristic IRabsorption band is aroud 1700 cm -1
Solution
Since it contains oxygen double bonded to a carbon atom , it may beCaboxylic acid
or carbonyl compound. So the characteristic IRabsorption band is aroud 1700 cm -1.
salicylic acid alcohol (R-OH) and carboxylic aci.pdf
salicylic acid: alcohol (R-OH) and carboxylic acid (R-COOH) acetylsalicylic acid
(aspirin): carboxylic acid and ester (R-COOR)
Solution
salicylic acid: alcohol (R-OH) and carboxylic acid (R-COOH) acetylsalicylic acid
(aspirin): carboxylic acid and ester (R-COOR).
no it doesnot .pdf
This very short document does not seem to provide any clear information that can be summarized in 3 sentences or less. It contains the phrase "no it doesnot" repeated but no other context or details.
It would be Ruthenium (II) Sulfide Ruthenium is .pdf
It would be Ruthenium (II) Sulfide Ruthenium is a transition metal, meaning that it
can have multiple oxidation numbers. Sulfur always takes the charge of -2, so from that we see
that there is a 1 to 1 relation between Ru and S in the empirical formula, so that means that
Ruthenium has the opposite charge, +2.
Solution
It would be Ruthenium (II) Sulfide Ruthenium is a transition metal, meaning that it
can have multiple oxidation numbers. Sulfur always takes the charge of -2, so from that we see
that there is a 1 to 1 relation between Ru and S in the empirical formula, so that means that
Ruthenium has the opposite charge, +2..
ketones do not give tollens test.. hence no react.pdf
ketones do not give tollens test.. hence no reaction
Solution
ketones do not give tollens test.. hence no reaction.
for IONIC the metal name followed by nonmetal io.pdf
for IONIC: the metal name followed by nonmetal ion (-ide) for ex: NaCl is Sodium
Chloride or MgS is Magnesium Sulfide
Solution
for IONIC: the metal name followed by nonmetal ion (-ide) for ex: NaCl is Sodium
Chloride or MgS is Magnesium Sulfide.
pH = 4-log2.4 = 3.62 pOH 14 - pH = 14-3.62 = 10.3.pdf
pH = 4-log2.4 = 3.62 pOH 14 - pH = 14-3.62 = 10.38 concentration of OH- = 10^(-
14) / (2.4*10^(-4)) = 4.167* 10^(-11)
Solution
pH = 4-log2.4 = 3.62 pOH 14 - pH = 14-3.62 = 10.38 concentration of OH- = 10^(-
14) / (2.4*10^(-4)) = 4.167* 10^(-11).
This suggest that dissociation of FeCl3 is 100 .pdf
This suggest that dissociation of FeCl3 is 100 % to form 4 ions (1Fe+3Cl). Other
dissociation also may be possible like FeCl3---->(FeCl2) + Cl- FeCl3---->(FeCl)2+ + 2Cl- so
number of ions is averaged considering dissociation constants which is 3.4
Solution
This suggest that dissociation of FeCl3 is 100 % to form 4 ions (1Fe+3Cl). Other
dissociation also may be possible like FeCl3---->(FeCl2) + Cl- FeCl3---->(FeCl)2+ + 2Cl- so
number of ions is averaged considering dissociation constants which is 3.4.
Total probability of dot received P = (37)(78).pdf
Total probability of dot received P = (3/7)*(7/8)+(4/7)*(1/8)=0.4464 probability
that dot sentP1 = 3/7=0.4285 so P(dot sent | dot received).= P1/P=0.4285/.4464=0.96
Solution
Total probability of dot received P = (3/7)*(7/8)+(4/7)*(1/8)=0.4464 probability
that dot sentP1 = 3/7=0.4285 so P(dot sent | dot received).= P1/P=0.4285/.4464=0.96.
Environmental contaminants of recent concern are .pdf
Environmental contaminants of recent concern are pharmaceuticals, estrogens and
other endocrine disrupting chemicals (EDC) such as degradation products of surfactants, algal
and cyanobacterial toxins, disinfection by-products (DBPs) and metalloids. In addition,
pesticides (especially their transformation products), microorganisms, and humic substances
(HS), in their function as vehicles for contaminants and as precursors for by-products in water
treatment, traditionally play an important role. The present status of the application of LC-MS
techniques for these water constituents are discussed and examples of application are given.
Solid-phase extraction with various non-selective materials in combination with liquid
chromatography (LC) on reversed-phase columns have been the most widely used methods for
sample preconcentration and separation for different compound classes like pesticides,
pharmaceuticals or estrogens. Electrospray ionization (ESI) and atmospheric pressure ionization
(APCI) are the most frequently used ionization techniques for polar and ionic compounds, as
well as for less polar non-ionic ones. The facilities of LC-MS have been successfully
demonstrated for different compound classes. Polar compounds from pharmaceuticals used as
betablockers, iodinated X-ray contrast media, or estrogens have been determined without
derivatization down to ultratrace concentrations. LC-MS can be viewed as a prerequisite for the
determination of algal and cyanobacterial toxins and the homologues and oligomers of
alkylphenol ethoxylates and their metabolites. Tandem mass spectrometric techniques and the
use of diagnostic ions reveal their usefulness for compound-class specific screening and
unknown identification, and are also valid for the analysis of pesticides and especially for their
transformation products.
Solution
Environmental contaminants of recent concern are pharmaceuticals, estrogens and
other endocrine disrupting chemicals (EDC) such as degradation products of surfactants, algal
and cyanobacterial toxins, disinfection by-products (DBPs) and metalloids. In addition,
pesticides (especially their transformation products), microorganisms, and humic substances
(HS), in their function as vehicles for contaminants and as precursors for by-products in water
treatment, traditionally play an important role. The present status of the application of LC-MS
techniques for these water constituents are discussed and examples of application are given.
Solid-phase extraction with various non-selective materials in combination with liquid
chromatography (LC) on reversed-phase columns have been the most widely used methods for
sample preconcentration and separation for different compound classes like pesticides,
pharmaceuticals or estrogens. Electrospray ionization (ESI) and atmospheric pressure ionization
(APCI) are the most frequently used ionization techniques for polar and ionic compounds, as
well as for less polar non-ionic ones. The facilities of .
C-H polar covalent bond Solution .pdf
The document discusses C-H polar covalent bonds. C-H bonds have some ionic character due to the difference in electronegativity between carbon and hydrogen. Hydrogen is more electronegative so it pulls the electrons in the bond slightly toward itself, giving the bond some polar character though it remains primarily covalent.
To insert an element at given position in arrayInsert(stack s1, s.pdf
To insert an element at given position in array:
Insert(stack s1, stack s2, int value, int pos)
//Inserts a value into the array at specified position.
//Assume s1 is a stack which holds the values, and s2 is an empty stack.
while(!s1.empty()) //Till the stack is empty.
s2.push(s1.pop()) //Pop element from s1, and push it in s2.
//By now, all elements are placed in reverse order from s1 to s2.
for i = 1 to pos - 1 //Till the pos-1
s1.push(s2.pop()) //Remove elements from s2, and push them to s1.
s1.push(value) //Now push your element in specified position pos.
while(!s2.empty()) //Push all the remaining elements in s2 to s1.
s1.push(s2.pop())
To delete an element at given position in array:
Delete(stack s1, stack s2, int pos)
//Deletes a value into the array at specified position.
//Assume s1 is a stack which holds the values, and s2 is an empty stack.
while(!s1.empty()) //Till the stack is empty.
s2.push(s1.pop()) //Pop element from s1, and push it in s2.
//By now, all elements are placed in reverse order from s1 to s2.
for i = 1 to pos - 1 //Till the pos-1
s1.push(s2.pop()) //Remove elements from s2, and push them to s1.
s1.pop(value) //Now pop your element in specified position pos.
while(!s2.empty()) //Push all the remaining elements in s2 to s1.
s1.push(s2.pop())
To delete a given element in array:
DeleteVal(stack s1, stack s2, int value)
//Deletes a value from the array.
//Assume s1 is a stack which holds the values, and s2 is an empty stack.
while(!s1.empty()) //Till the stack is empty.
s2.push(s1.pop()) //Pop element from s1, and push it in s2.
//By now, all elements are placed in reverse order from s1 to s2.
ele = s2.peek();
while(ele != value || !s2.empty()) //Till you found the element to be deleted.
s1.push(s2.pop()) //Remove elements from s2, and push them to s1.
ele = s2.peek()
s2.pop(value) //If element is found, delete it.
while(!s2.empty()) //Push all the remaining elements in s2 to s1.
s1.push(s2.pop())
If you have any queries with this, just get back to me.
Solution
To insert an element at given position in array:
Insert(stack s1, stack s2, int value, int pos)
//Inserts a value into the array at specified position.
//Assume s1 is a stack which holds the values, and s2 is an empty stack.
while(!s1.empty()) //Till the stack is empty.
s2.push(s1.pop()) //Pop element from s1, and push it in s2.
//By now, all elements are placed in reverse order from s1 to s2.
for i = 1 to pos - 1 //Till the pos-1
s1.push(s2.pop()) //Remove elements from s2, and push them to s1.
s1.push(value) //Now push your element in specified position pos.
while(!s2.empty()) //Push all the remaining elements in s2 to s1.
s1.push(s2.pop())
To delete an element at given position in array:
Delete(stack s1, stack s2, int pos)
//Deletes a value into the array at specified position.
//Assume s1 is a stack which holds the values, and s2 is an empty stack.
while(!s1.empty()) //Till the stack is empty.
s2.push(s1.pop()) //Pop element from s1, and push it in s2.
//By .
Their physical properties are so dofferent just because theintermole.pdf
Their physical properties are so dofferent just because theintermolecular or interatomic forces are
so different.
Solution
Their physical properties are so dofferent just because theintermolecular or interatomic forces are
so different..
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- 1. The mole is a unit of measurement for the amount of substance or chemical amount. It is one of the base units in the International System of Units, and has the unit symbol mol. n ionic compound is a chemical compound in which ions are held together in a lattice structure by ionic bonds. Usually, the positively charged portion consists of metal cations and the negatively charged portion is an anion or polyatomic ion. Ions in ionic compounds are held together by the electrostatic force between oppositely charged bodies. Ionic compounds have a high melting and boiling point, and they are hard and very brittle. Solution The mole is a unit of measurement for the amount of substance or chemical amount. It is one of the base units in the International System of Units, and has the unit symbol mol. n ionic compound is a chemical compound in which ions are held together in a lattice structure by ionic bonds. Usually, the positively charged portion consists of metal cations and the negatively charged portion is an anion or polyatomic ion. Ions in ionic compounds are held together by the electrostatic force between oppositely charged bodies. Ionic compounds have a high melting and boiling point, and they are hard and very brittle.