The java program that reads an input file input.txt an.pdf
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/* * The java program that reads an input file input.txt * and then reads the contens of file. * the program throws file not found exception if file not found. * The program throws DimensionMismatchException if mismatch of dimension. * The program throws NumberFormatException if mismatch of data read. * */ //FormatChecker.java import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class FormatChecker { public static void main(String[] args) { String fileName=\"input.txt\"; //calling checkFormat checkFormat(fileName); } //Method checkFormat that takes string and check for //errors otherwise reads the file and print to console private static void checkFormat(String fileName) { Scanner filescanner=null; try { //thorws FileNotFoundException error if file not found filescanner=new Scanner(new File(fileName)); } catch (FileNotFoundException e) { System.out.println(e.getMessage()); } int rows=0; int cols=0; double[][] arr; String dimensions[]=filescanner.nextLine().split(\" \"); try { //thorws DimensionMismatchException error if mismatch of dimension if(dimensions.length>2) throw new DimensionMismatchException(\"Dimension mismatch\"); } catch (DimensionMismatchException e1) { e1.printStackTrace(); } try { //thorws NumberFormatException error if mismatch of reading values rows=Integer.parseInt(dimensions[0]); cols=Integer.parseInt(dimensions[1]); arr=new double[rows][cols]; System.out.println(\"File contents\"); for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { arr[i][j]=filescanner.nextDouble(); System.out.printf(\"%6.1f\",arr[i][j]); } System.out.println(); } } catch (NumberFormatException e) { System.out.println(e.getMessage()); } } } ------------------------------------------------------------------------ //User defined DimensionMismatchException class //that extends the Exception class //DimensionMismatchException.java public class DimensionMismatchException extends Exception { public DimensionMismatchException(String msg) { super(msg); } } ------------------------------------------------------------------------ input.txt 5 6 2.5 0 1 0 0 0 0 -1 4 0 0 0 0 0 0 0 1.1 0 0 2 0 0 5 0 0 -3.14 0 0 0 0 ------------------------------------------------------------------------ File contents 2.5 0.0 1.0 0.0 0.0 0.0 0.0 -1.0 4.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.1 0.0 0.0 2.0 0.0 0.0 5.0 0.0 0.0 -3.1 0.0 0.0 0.0 0.0 Note : DimensionMismatchException class is included Solution /* * The java program that reads an input file input.txt * and then reads the contens of file. * the program throws file not found exception if file not found. * The program throws DimensionMismatchException if mismatch of dimension. * The program throws NumberFormatException if mismatch of data read. * */ //FormatChecker.java import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class FormatChecker { public static void main(String[] args) { String fileName=\"input.txt\"; //calling check.
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![/*
* The java program that reads an input file input.txt
* and then reads the contens of file.
* the program throws file not found exception if file not found.
* The program throws DimensionMismatchException if mismatch of dimension.
* The program throws NumberFormatException if mismatch of data read.
* */
//FormatChecker.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class FormatChecker {
public static void main(String[] args) {
String fileName="input.txt";
//calling checkFormat
checkFormat(fileName);
}
//Method checkFormat that takes string and check for
//errors otherwise reads the file and print to console
private static void checkFormat(String fileName) {
Scanner filescanner=null;
try {
//thorws FileNotFoundException error if file not found
filescanner=new Scanner(new File(fileName));
} catch (FileNotFoundException e) {
System.out.println(e.getMessage());
}
int rows=0;
int cols=0;
double[][] arr;](https://image.slidesharecdn.com/thejavaprogramthatreadsaninputfileinput-230408100738-606c3cc4/85/The-java-program-that-reads-an-input-file-input-txt-an-pdf-1-320.jpg)
![String dimensions[]=filescanner.nextLine().split(" ");
try
{
//thorws DimensionMismatchException error if mismatch of dimension
if(dimensions.length>2)
throw new DimensionMismatchException("Dimension mismatch");
} catch (DimensionMismatchException e1) {
e1.printStackTrace();
}
try {
//thorws NumberFormatException error if mismatch of reading values
rows=Integer.parseInt(dimensions[0]);
cols=Integer.parseInt(dimensions[1]);
arr=new double[rows][cols];
System.out.println("File contents");
for (int i = 0; i < arr.length; i++)
{
for (int j = 0; j < arr[i].length; j++)
{
arr[i][j]=filescanner.nextDouble();
System.out.printf("%6.1f",arr[i][j]);
}
System.out.println();
}
} catch (NumberFormatException e) {
System.out.println(e.getMessage());
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
2. Write a program which will open an input file and write to an out.pdf
2. Write a program which will open an input file and write to an output file. Use exception
handling (try & Catch to display appropriate error handling).
Solution
herer is code:
import java.io.*;
public class Copytxt{
public static void main (String[] args)throws IOException {
int i;
FileInputStream fin;
FileOutputStream fout;
try {
// open input file
try {
fin = new FileInputStream(\"input.txt\"); // pass the input location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Input File Not Found\");
return;
}
// open output file
try {
fout = new FileOutputStream(\"output.txt\"); // pass the output location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Error Opening Output File\");
return;
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println(\"Usage: CopyFile From To\");
return;
}
// Copy File
try {
byte[] buffer = new byte[1024];
int length;
/*copying the contents from input stream to
* output stream using read and write methods
*/
while ((length = fin.read(buffer)) > 0){
fout.write(buffer, 0, length);
}
}
catch (IOException e) {
System.out.println(\"File Error\");
}
fin.close();
fout.close();
}
}.
Complete the following Java code such that it opens a file named Fruit.docx
Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments.
// complete import statement(s) here
public class FileRead
{
public static void main(String[] args)
{
// complete the code here
}
}
Solution
import java.io.File;
import java.util.Scanner;
/**
* @author
*
*/
public class FileRead {
/**
* @param args
*/
public static void main(String[] args) {
// complete the code here
Scanner scanner = null;
try {
File file = new File(\"FruitList.txt\");
scanner = new Scanner(file);
// checks the file contains data
if (scanner.hasNext()) {
// prints first line
System.out.println(scanner.nextLine());
}
} catch (Exception e) {
// TODO: handle exception
}
}
}
FruitList.txt
Apple
Orange
Papaya
Banana
Jack Fruit
Watermelon
KIWI
Grapes
Mango
Pineapple
OUTPUT:
Apple
.
Lab4
The document provides examples of Java code using try, catch, throw, and exceptions to handle errors and exceptions. Program 36 introduces a try-catch block to handle potential InputMismatchExceptions from user input. Program 37 uses try-catch-finally to handle an ArithmeticException from division by zero and ensure the finally block always executes. Program 38 demonstrates multiple catch blocks to handle different exception types.
PAGE 1Input output for a file tutorialStreams and File IOI.docx
PAGE
1Input output for a file tutorialStreams and File I/O
In this tutorial we study the following concepts:
Text File I/O
Techniques for a file: Class File
Binary File I/O
File Objects and File Name
Note: For question 4 of the midterm you only need to look at the sections 2.2 and 2.3. I do not think you need java class: StringTokenizer. But I just added a small section about it to the end of this tutorial.
So far we learned keyboard/screen I/O. It is time to learn File I/O.
1 An Overview of stream and file I/O
A stream is an object that either outputs data or inputs data. The Java System.out is a stream object that outputs data on the screen.
As our program gets bigger and bigger we may need to enter a lot of data every time we run our program. We also may have a lot of data as the output of the program. It is not practical to enter a sizable input from the keyboard. Therefore, we save the data in a file and let our program to input from this file. Similarly, it is not practical to look at a sizable output. Moreover, we may need to save the output for further study. Therefore, we let our program to output to a file.
We have two kinds of I/O files: Text files and binary files. A text file is readable and understandable by human, but a binary file is not. The size of a text file is bigger than the size of a binary file. We can write arrays without using a loop into a binary file. We can also write objects to a binary file.
2 Text-File I/O
In this section we learn how to input from a text file and how to output to a text file. We first look at output instructions for a text file.
2.1 Text-File Output with PrintWriter class.
To be able to write to a file we need the Java class PrintWriter. This class is in JDK java.io, therefore we need to import it . Another class that we need is : FileOutputStream. This class also is in java.io. A file output stream is an output stream for writing data to a File.
Example 1. The following program to write an integer, a floating point number, a Boolean value and a string into a text file.
import java. io. PrintWriter;
import java. io. FileNotFoundException;
publicclass Main {
publicstaticvoid main( String[] args) {
PrintWriter out = null;
try {
out = new PrintWriter("out.txt");
} catch( FileNotFoundException e) {
System. out. println("Error: opening the file out.txt");
System. exit( 0);
}
out.println(-12);
out.println(25.5);
out.println(true);
out.println("John Doe.");
//Note that we also can write:
out.println(-12+"\n"+ 25.5 + "\n" + true + "\n" + "John Doe.");
out.close();
} }
The content of the file out.txt would be:
-12
25.5
true
John Doe.
-12
25.5
true
John Doe.
Description:
First we need to declare a variable that refers to and object of class PrintWriter. This class has several constructors. One of them needs the name of the output file on the hard drive (or other storages): out = new PrintWriter("out.txt")
This instruction co.
Write a java program that allows the user to input the name of a fil.docx
The document describes a Java program that takes in a file containing positive integers, reads the integers, separates the even and odd numbers, and writes them to separate text files. The program prompts the user to enter the file name and number of integers, then uses loops and conditionals to read each integer, check if it is even or odd, and write it to the corresponding file. On completion, it notifies the user that the files were successfully written.
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
JAVA Q2- Write a program that reads strings from the user and writes t.docx
JAVA
Q2: Write a program that reads strings from the user and writes them to an output file called userStrings.txt. Stop processing when the user enters the string \"DONE\". Do not write the sentinel string (\"DONE\") to the output file. [15 points] Hint: For a complete example of file IO, please see the attached TestData program.
Sample Output:
A string.
Another string.
Yet more text...
DONE
Solution
Answer
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Scanner;
class WriteStringFile {
public static void main(String[] args) {
File file = new File(\"D:/userFile.txt\");
String data;
Scanner input = new Scanner(System.in);
data = input.readLine();
try (FileOutputStream fop = new FileOutputStream(file)) {
// if file doesn\'t exists, then create it
if (!file.exists()) {
file.createNewFile();
}
if (data != \"DONE\") {
// get the content in bytes
byte[] contentInBytes = content.getBytes();
fop.write(contentInBytes);
fop.flush();
fop.close();
} else {
System.out.println(\"User Enter the value Done.. So unable to write into file\");
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
.
ExtraFileIO.pptx
The document discusses file input and output in Java. It covers the File class, opening files for reading using a Scanner, handling exceptions, reading data line-by-line and tokenizing the lines. It also discusses opening files for writing using a PrintWriter and outputting data to files. The key topics are file I/O, exception handling, and using Scanners and PrintWriters to read from and write to files in Java.
Recommended
2. Write a program which will open an input file and write to an out.pdf
2. Write a program which will open an input file and write to an output file. Use exception
handling (try & Catch to display appropriate error handling).
Solution
herer is code:
import java.io.*;
public class Copytxt{
public static void main (String[] args)throws IOException {
int i;
FileInputStream fin;
FileOutputStream fout;
try {
// open input file
try {
fin = new FileInputStream(\"input.txt\"); // pass the input location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Input File Not Found\");
return;
}
// open output file
try {
fout = new FileOutputStream(\"output.txt\"); // pass the output location file here
}
catch (FileNotFoundException e) { // if file not found
System.out.println(\"Error Opening Output File\");
return;
}
}
catch (ArrayIndexOutOfBoundsException e) {
System.out.println(\"Usage: CopyFile From To\");
return;
}
// Copy File
try {
byte[] buffer = new byte[1024];
int length;
/*copying the contents from input stream to
* output stream using read and write methods
*/
while ((length = fin.read(buffer)) > 0){
fout.write(buffer, 0, length);
}
}
catch (IOException e) {
System.out.println(\"File Error\");
}
fin.close();
fout.close();
}
}.
Complete the following Java code such that it opens a file named Fruit.docx
Complete the following Java code such that it opens a file named FruitList.txt, reads the first line from the file, and then prints the first line on console screen. Your Java code should handle possible exception(s). Assume that the file contains the name of a fruit in each line. You don\'t need to provide comments.
// complete import statement(s) here
public class FileRead
{
public static void main(String[] args)
{
// complete the code here
}
}
Solution
import java.io.File;
import java.util.Scanner;
/**
* @author
*
*/
public class FileRead {
/**
* @param args
*/
public static void main(String[] args) {
// complete the code here
Scanner scanner = null;
try {
File file = new File(\"FruitList.txt\");
scanner = new Scanner(file);
// checks the file contains data
if (scanner.hasNext()) {
// prints first line
System.out.println(scanner.nextLine());
}
} catch (Exception e) {
// TODO: handle exception
}
}
}
FruitList.txt
Apple
Orange
Papaya
Banana
Jack Fruit
Watermelon
KIWI
Grapes
Mango
Pineapple
OUTPUT:
Apple
.
Lab4
The document provides examples of Java code using try, catch, throw, and exceptions to handle errors and exceptions. Program 36 introduces a try-catch block to handle potential InputMismatchExceptions from user input. Program 37 uses try-catch-finally to handle an ArithmeticException from division by zero and ensure the finally block always executes. Program 38 demonstrates multiple catch blocks to handle different exception types.
PAGE 1Input output for a file tutorialStreams and File IOI.docx
PAGE
1Input output for a file tutorialStreams and File I/O
In this tutorial we study the following concepts:
Text File I/O
Techniques for a file: Class File
Binary File I/O
File Objects and File Name
Note: For question 4 of the midterm you only need to look at the sections 2.2 and 2.3. I do not think you need java class: StringTokenizer. But I just added a small section about it to the end of this tutorial.
So far we learned keyboard/screen I/O. It is time to learn File I/O.
1 An Overview of stream and file I/O
A stream is an object that either outputs data or inputs data. The Java System.out is a stream object that outputs data on the screen.
As our program gets bigger and bigger we may need to enter a lot of data every time we run our program. We also may have a lot of data as the output of the program. It is not practical to enter a sizable input from the keyboard. Therefore, we save the data in a file and let our program to input from this file. Similarly, it is not practical to look at a sizable output. Moreover, we may need to save the output for further study. Therefore, we let our program to output to a file.
We have two kinds of I/O files: Text files and binary files. A text file is readable and understandable by human, but a binary file is not. The size of a text file is bigger than the size of a binary file. We can write arrays without using a loop into a binary file. We can also write objects to a binary file.
2 Text-File I/O
In this section we learn how to input from a text file and how to output to a text file. We first look at output instructions for a text file.
2.1 Text-File Output with PrintWriter class.
To be able to write to a file we need the Java class PrintWriter. This class is in JDK java.io, therefore we need to import it . Another class that we need is : FileOutputStream. This class also is in java.io. A file output stream is an output stream for writing data to a File.
Example 1. The following program to write an integer, a floating point number, a Boolean value and a string into a text file.
import java. io. PrintWriter;
import java. io. FileNotFoundException;
publicclass Main {
publicstaticvoid main( String[] args) {
PrintWriter out = null;
try {
out = new PrintWriter("out.txt");
} catch( FileNotFoundException e) {
System. out. println("Error: opening the file out.txt");
System. exit( 0);
}
out.println(-12);
out.println(25.5);
out.println(true);
out.println("John Doe.");
//Note that we also can write:
out.println(-12+"\n"+ 25.5 + "\n" + true + "\n" + "John Doe.");
out.close();
} }
The content of the file out.txt would be:
-12
25.5
true
John Doe.
-12
25.5
true
John Doe.
Description:
First we need to declare a variable that refers to and object of class PrintWriter. This class has several constructors. One of them needs the name of the output file on the hard drive (or other storages): out = new PrintWriter("out.txt")
This instruction co.
Write a java program that allows the user to input the name of a fil.docx
The document describes a Java program that takes in a file containing positive integers, reads the integers, separates the even and odd numbers, and writes them to separate text files. The program prompts the user to enter the file name and number of integers, then uses loops and conditionals to read each integer, check if it is even or odd, and write it to the corresponding file. On completion, it notifies the user that the files were successfully written.
Write a java program that allows the user to input the name of a file.docx
Write a java program that allows the user to input the name of a file that contains positive integers (one integer per line) The number of integers in the file The program should find all odd and even numbers and write the odd numbers to a file \"odd.txt\" and write the even numbers to another file \"even.txt\"
Solution
package expertques;
import java.io.File;
import java.io.PrintWriter;
import java.util.Scanner;
public class evenoddwithfile {
public static void main(String[] args) throws Exception {
File in;//file input
File even = new File(\"f://even.txt\");//creates file even
File odd = new File(\"f://odd.txt\");//creates file odd
Scanner s = new Scanner(System.in);//reads input from console or user
System.out.println(\"Enter the file name with path: \");
in = new File(s.nextLine());
System.out.println(\"Enter the number of integers n the file: \");
int n = s.nextInt();
if (in.exists()) {//checks if input file exist or not
Scanner ins = new Scanner(in);//reads input file
PrintWriter pe = new PrintWriter(even);//write to even file
PrintWriter po = new PrintWriter(odd);//writes to odd file
for (int i = 0; i < n; i++) {//loop till the numbers exists
int x = ins.nextInt();//reads from input file
if (x % 2 == 0) {//checks for even or odd
pe.println(x);//if even writes in even file
} else {
po.println(x);//if odd writes in odd file
}
}
pe.close();//closes even file very important else nothing will be written in the file
po.close();//closes odd file very important else nothing will be written in the file
System.out.println(\"File successfully written with odds and evens\");
} else {
System.out.println(\"Error file not found at specified path\");//if file not exist
}
}
}
output
run:
Enter the file name with path:
f://integers.txt
Enter the number of integers n the file:
8
File successfully written with odds and evens
BUILD SUCCESSFUL (total time: 6 seconds)
.
JAVA Q2- Write a program that reads strings from the user and writes t.docx
JAVA
Q2: Write a program that reads strings from the user and writes them to an output file called userStrings.txt. Stop processing when the user enters the string \"DONE\". Do not write the sentinel string (\"DONE\") to the output file. [15 points] Hint: For a complete example of file IO, please see the attached TestData program.
Sample Output:
A string.
Another string.
Yet more text...
DONE
Solution
Answer
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Scanner;
class WriteStringFile {
public static void main(String[] args) {
File file = new File(\"D:/userFile.txt\");
String data;
Scanner input = new Scanner(System.in);
data = input.readLine();
try (FileOutputStream fop = new FileOutputStream(file)) {
// if file doesn\'t exists, then create it
if (!file.exists()) {
file.createNewFile();
}
if (data != \"DONE\") {
// get the content in bytes
byte[] contentInBytes = content.getBytes();
fop.write(contentInBytes);
fop.flush();
fop.close();
} else {
System.out.println(\"User Enter the value Done.. So unable to write into file\");
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
.
ExtraFileIO.pptx
The document discusses file input and output in Java. It covers the File class, opening files for reading using a Scanner, handling exceptions, reading data line-by-line and tokenizing the lines. It also discusses opening files for writing using a PrintWriter and outputting data to files. The key topics are file I/O, exception handling, and using Scanners and PrintWriters to read from and write to files in Java.
Exception handling
Here are solutions to the exercises:
1. WAP to enter a name of the user and show an exception if it does not enter its name:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
try {
System.out.print("Enter your name: ");
String name = sc.nextLine();
if(name.isEmpty()) {
throw new Exception("Name cannot be empty");
}
System.out.println("Name entered: " + name);
} catch (Exception e) {
System.out.println("Exception: " + e.getMessage
Basic input-output-v.1.1
Streams are used for reading and writing data in Java. The Scanner class is used for reading text files by constructing a Scanner from a File object. The PrintStream class is used for writing to text files by specifying the file name and encoding. Exceptions may occur during I/O operations and should be handled using try-catch blocks to prevent program errors.
Java 3 Computer Science.pptx
Exceptions, I/O and Threads Input and Output in Java: The File Class, Standard Streams, Keyboard
Input, File I/O Using Byte Streams, Character Streams, File I/O Using Character Streams -
Buffered Streams, File I/O Using a Buffered Stream, Keyboard Input Using a Buffered Stream,Writing Text Files. Threads: Threads vs. Processes, Creating Threads by Extending Thread,
Creating Threads by Implementing Runnable, Advantages of Using Threads, Daemon Threads,
Thread States, Thread Problems, Synchronization. Exceptions: Exception Handling, The Exception
Hierarchy, throws statement, throw statement, Developing user defined Exception Classes- The
finally Block.
IO and threads Java
This document provides information about input and output in Java. It discusses files, streams, standard streams like System.in and System.out, and different ways of handling keyboard input in Java programs. The File class in Java represents files and directories on the disk. It describes the various File class constructors, methods, and examples of using the File class to work with files like creating, reading, and checking files. Standard streams provide predefined paths for input/output. Streams can be byte-based or character-based. Keyboard input can be handled using command line arguments, the Console class, Scanner class, or InputStreamReader class.
For the following I have finished most of this question but am havin.pdf
For the following I have finished most of this question but am having problem with on method. I
just need the void copyNumbers method filled out. The commented out sections describe what it
needs to do. I have it started. Just need it finished.
package reading_with_exceptions;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Reading_With_Exceptions {
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully read the count integer.
// I recommend -1 for a count value if it is bad to indicate reading ALL
// 4.) Use copyNumbers method described below to complete the job
// 5.) Close Scanner and PrintStream objects
// 6.) Call printToScreen to copy the output file to the screen
void process(String inputFilename) {
int number_to_read = 0;
try {
Scanner input = new Scanner(inputFilename);
String outputFilename = input.next();
PrintStream os = new PrintStream(new FileOutputStream(outputFilename));
if ( input.hasNextInt()) {
number_to_read = input.nextInt();
}else {
number_to_read = -1;
}
copyNumbers(input, os, number_to_read);
input.close();
os.close();
printToScreen(outputFilename);
}catch (FileNotFoundException e) {
System.out.println(\"Cannot find file: \" + e);
return;
}
}
// The following routine is called to complete the job of copying integers to
// the output file:
// scan - a Scanner object to copy integers from
// ps - A PrintStream to write the integers to
// numIntsToRead - number of integers to read. A value of -1 ==> read all integers
void copyNumbers(Scanner scan, PrintStream ps, int numIntsToRead) {
// hasNext() can be used to see if the scan object still has data
// Note that hasNextInt() can be used to see if an integer is present
// nextInt() will read an integer
// next() can be used to skip over bad integers
while (scan.hasNext()) {
if (numIntsToRead < 0) {
//print out a complaint message and then read as many integers as you find.
scan.nextInt();
}
if (!scan.hasNextInt()) {
// print a complaint message and skip over the data
scan.next();
}
if ( scan < numIntsToRead) {
// complain but do not abort
}
}
}
public static void main(String[] args) {
Reading_With_Exceptions rwe = new Reading_With_Exceptions();
for (int i=0; i < args.length; i++) {
System.out.println(\"\ \ =========== Processing \"+ args[i] + \" ==========\ \");
rwe.process(args[i]);
}
}
// For the last step, we Copy the contents of the file to the screen
private void printToScreen(String filename) {
Scanner scan = null;
try {
FileInputStream fis = new FileInputStream(filename);
scan = new Scanner(fis);
while (scan.hasNextLine()) {
System.out.println(scan.nextLine());
}
}
catch (FileNotFoundException e) {
System.out.println(\"printToS.
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Session 23 - JDBC
In this session you will learn:
1. File IO Continued
2. Intro to JDBC (Java Database Connectivity)
CORE JAVA-1
The document discusses various input/output (I/O) concepts in Java including serialization. It begins by explaining that serialization allows Java objects to be written to streams and recreated later. It notes that classes must implement the Serializable interface to be serialized. The ObjectOutputStream class is used to write objects to streams and serialize them. An example is provided that demonstrates serializing an object to a file.
import required package file import java.io.File; The Filed.pdf
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file is not writable\");
}
// main method goes here
public static void main(String[] args) {
// TODO Auto-generated method stub
// object instantiation
FileDetails fd=new FileDetails(\"anyfile.doc\"); // You should give exact path and file name
here
}
}
// Importing required packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// the writestring class
public class WriteString {
// Writestring class
public WriteString(String filename,String text) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Printsteam class that connects file using file output stream
PrintStream ps=new PrintStream(new FileOutputStream(file));
// using println method to write to the file
ps.println(text);
}
// main method to execute the code
public static void main(String[] args) throws FileNotFoundException
{
// the writestring class instantiation
WriteString ws=new WriteString(\"f1.txt\",\"Hello World\"); // You should give exact path
and file name here
}
}
// importing packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// The writints class
public class WriteInts {
// the constructor to instantiate
public WriteInts(String filename,int[] myArr) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Using print stream to write integers
PrintStream ps=new PrintStream(new FileOutputStream(file));
//Looping through array elements to write every element
for(int i=0;i
Solution
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file.
Input output files in java
The document discusses input/output files in Java. It covers the key classes used for reading and writing files in Java, including FileInputStream, FileOutputStream, FileReader, and FileWriter. It also discusses byte streams versus character streams, and provides examples of reading and writing to files in Java using these classes. Standard input/output streams like System.in and System.out are also covered.
Description 1) Create a Lab2 folder for this project2.docx
Description
1) Create a Lab2 folder for this project
2) Use the main driver program (called Writers.java) that I provide below to write files of differing types. You can copy and paste this code, but make sure the spaces variable copies correctly. The copy and paste operation eliminates the spaces between the quotes on some systems.
3) In the writers program, fill in the code for the three classes (Random, Binary, and Text). In each class, you will need a constructor, a write method, and a close method. The constructor opens the file, the write method writes a record, and the close method closes the file.
4) Other than what I just described, don't change the program in any way. The program asks for a file type (random, binary, or text) and the name of the file to create. In a loop it inputs a person's name (string), a person's age (int), and a person's annual salary (double). It writes to a file of the appropriate type. The loop terminates when the user indicates that inputting is complete. The program then asks if another file should be created. If the answer is yes, the whole process starts again. This and all of the java driver programs should be saved in your lab2 folder but not in the cs258 sub-folder.
5) Note: The method signatures for accessing all of the three types of files (binary, random, and text) are on the class web-site. Go to power point slides and click on week two. This will help if you didn't take accurate notes in class.
6) Write a main program to read binary files (BinReader.java). This program only needs to be able to read and display records from a Binary file that was created by the writers program.
7) Write a main program to read random files (RandReader.java). This program only needs to be able to read and display records from a Binary file that was created by the writers program. Make sure that this program reads and displays records in reverse order. DO NOT USE AN ARRAY!!!
8) In your Lab2 folder, create a subfolder within lab2 named cs258. Download Keyboard.java from the class web-site to that folder. Add a new first line of Keyboard.java with the statement, package cs258;. This line will make Keyboard.java part of the cs258 package. The driver program shown below has an import ‘cs258.*;’ statement to access the java files in this package.
9) Modify Keyboard.java. We want to extend this class so it can be extended to allow access to multiple files. The changes follow:
a. Remove all static references. This is necessary so that there will be an input stream variable (in) in each object.
b. Change the private modifier of the in and current_token variables to protected. Change the private modifier to protected in all of the signature lines of the overloaded getNextToken methods.
c. Create a constructor that instantiates the input stream for keyboard input. Remove the instantiation from the original declaration line for the in variable. The constructor doesn't need any parameters.
10)Create a class TextR.
Use Java to program the following.1. Create public java class name.pdf
Use Java to program the following.
1. Create public java class named Benford.
2. It\'s main function should prompt for the name of a data file and then the function iterates
through the all of the elements in the data file and computes the frequency (count and
percentage) of the first number in each entry.
3. Note: Some of the data files have comments that you must filter out.
4. Also note: that blank lines or lines where the number begins or is 0 must also be filtered out.
5. Your output must be formatted as follows.
Solution
Hi Firend, Please find my code.
Please let me know in case of any issue.
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class CountFrequency {
public static void main(String[] args) throws FileNotFoundException {
Scanner sc = new Scanner(System.in);
// taking input file name
System.out.print(\"Enter input file name: \");
String fileName = sc.next();
// opening input file
Scanner inputFile = new Scanner(new File(fileName));
// declaring array to store count of first digit of each entery
int[] frequency = new int[10];
int totalCount = 0; // to maintain total count
int num;
// reading all lines
while(inputFile.hasNextLine()){
// reading current line
String line = inputFile.nextLine();
// if line is not empty
if(line == null || line.isEmpty() || line.trim() == \"\")
continue;
// taking first character of current line
char firstDigit = line.charAt(0);
// if first character is digit and not equal to 0
if(Character.isDigit(firstDigit) && firstDigit != \'0\'){
// converting first character of current line in integer
int d = firstDigit - \'0\';
frequency[d]++;
totalCount++;
}
}
System.out.println(\"Digit\\tCount\\tFrequency\");
for(int i=1; i<=9; i++){
System.out.println(i+\"\\t\"+frequency[i]+\"\\t\"+
((double)frequency[i]/(double)totalCount*100));
}
}
}
/*
Sample run:
##### Entry of input.txt:
453 43
//543
123
0
4ee
875
52
// Output
Enter input file name: input.txt
Digit Count Frequency
1 1 20.0
2 0 0.0
3 0 0.0
4 2 40.0
5 1 20.0
6 0 0.0
7 0 0.0
8 1 20.0
9 0 0.0
*/.
Comments added... import java.io.File; import java.io.FileNotF.pdf
Comments added...
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
/**
*
* @author prmsh
*/
public class SaveMatrix {
public static void main(String args[]) {
//declaring matrix..
String[][] data = new String[4][4];
int row = 0;
// opening and reading file
File file = new File(\"matrix.txt\");
try {
Scanner sc = new Scanner(file);
while (sc.hasNextLine()) {
String line = sc.nextLine();
//splitting each row by spaces
String[] lineArray = line.split(\" \");
//storing into array
for(int i=0; i
Solution
Comments added...
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
/**
*
* @author prmsh
*/
public class SaveMatrix {
public static void main(String args[]) {
//declaring matrix..
String[][] data = new String[4][4];
int row = 0;
// opening and reading file
File file = new File(\"matrix.txt\");
try {
Scanner sc = new Scanner(file);
while (sc.hasNextLine()) {
String line = sc.nextLine();
//splitting each row by spaces
String[] lineArray = line.split(\" \");
//storing into array
for(int i=0; i.
Hi, I need help with a java programming project. specifically practi.pdf
Given 8 distinct integers from the set {1, 2, . . . , 16}, prove that there exists k such that ai aj = k
has at least 3 distinct solutions (ai , aj ) ?
Solution
For any k (unless the K is zero), at least 3 distinct solutions need not be existing.
Let\'s look at the next most favourable case
If k= 2;
We have to consider the case where the number of solutions of ai-aj=2 are minimum since we
have to show that at least 3 distinct solutions exist (which means even in the most unfavourable
case for a chosen k there will be 3 distinct solutions satisfying the equation ai-aj=2)
If k = 2; we start by taking numbers that are not at all 2 units apart from each other;
So we start with 1 and move 3 units successively ahead
1, 4, 7, 10,13, 16; Now we notice that these 6 numbers are of 3k+1 form; remaining numbers
can be any 2 ranomdly selected say 2 and 11; we get 4-2 = 2 and 13-11=2; Hence only 2 distinct
solutions are possible..
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
Understanding java streams
The document discusses Java streams and I/O. It defines streams as abstract representations of input/output devices that are sources or destinations of data. It describes byte and character streams, the core stream classes in java.io, predefined System streams, common stream subclasses, reading/writing files and binary data with byte streams, and reading/writing characters with character streams. It also covers object serialization/deserialization and compressing files with GZIP.
Need help with this java code. fill in lines where needed. Also, not.pdf
Need help with this java code. fill in lines where needed. Also, not sure how to make the text
files and load them into program. Thanks!!
Create a package named \"reading_with_exceptions\". Write a class named:
Reading_With_Exceptions with the following method:
void process(String inputFilename)
Your program will encounter errors, and we want you to gracefully handle them in such a way
that you print out informative information and continue executing.
Your process routine will try to open a file with the name of inputFilename for input. If there is
any problem (i.e. the file doesn\'t exist), then you should catch the exception, give an appropriate
error and then return. Otherwise, your program reads the file for instructions.
Your process routine will read the first line of the file looking for an outputFilename String
followed by an integer. i.e.:
outputFilename number_to_read
Your program will want to write output to a file having the name outputFilename. Your program
will try to read from \"inputFilename\" the number of integers found in \"number_to_read\".
Your process method will copy the integers read from inputFilename and write them to your
output file(i.e. outputFilename). There should contain 10 numbers per line of output in your
output file.
If you encounter bad input, your program should not die with an exception. For example:
If the count of the numbers to be read is bad or < 0 you will print out a complaint message and
then read as many integers as you find.
If any of the other numbers are bad, print a complaint message and skip over the data
If you don\'t have enough input numbers, complain but do not abort
After you have processed inputFilename, I would like your program to then close the output file
and tell the user that the file is created. Then Open up the output file and copy it to the Screen.
For example, if inputFilename contained:
We would expect the output of your program to be (Note that after 23 numbers we stop printing
numbers):
The main program will access the command line to obtain the list of filenames to call your
process routine with.
For those of you who benefit from a Template, your program might look like:
To prove that your program works, I want you to run your program with the following command
line parameters:
file1.txt non-existent-file file2.txt file3.txt
Where non-existent-file does not exist.
file1.txt contains:
file2.txt contains:
file3.txt contains:
Solution
// Reading_With_Exceptions.java
import java.io.File; // required imports for the code
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.Scanner;
public class Reading_With_Exceptions
{ // class that runs the code
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully re.
JDBC
In this core java training session, you will learn Examples of File IO &
Introduction to JDBC. Topics covered in this session are:
• File IO Continued
• Intro to JDBC (Java Database Connectivity)
For more information about this course visit on this link: https://www.mindsmapped.com/courses/software-development/learn-java-fundamentals-hands-on-training-on-core-java-concepts/
Java căn bản - Chapter12
This chapter discusses various methods of file input and output in Java, including low-level file I/O using FileInputStream and FileOutputStream, high-level file I/O using DataInputStream and DataOutputStream to read and write primitive data types, reading and writing text files using PrintWriter, BufferedReader, and Scanner, and object file I/O using ObjectInputStream and ObjectOutputStream to save and load objects. It also covers using JFileChooser to allow users to select files and applying file filters.
1. Copper is above silver in the activity series. Thus Cu metal will.pdf
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq)
Solution
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq).
using recursive method .pdf
/******************* using recursive method **********************/
/**
* 1.2.1 Java program to calculate the Fibonacci Number using recursion
*/
import java.util.Scanner;
public class Fibo {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the
recursive method
scan.close();
}
//method to calculate Fibonacci number recursively
public static long calFibonacci(int index){
if (index == 1)
return 0;
if (index == 2)
return 1;
return calFibonacci(index - 1) + calFibonacci(index - 2);
}
}
/** Outputs
* Enter the value of n 25
The 25. Fibonacci number is 75025
*/
/******************************using iterative
method************************************/
/**
* 1.2.2 Java program to calculate the fibonacci number using iterative method
*/
import java.util.Scanner;
public class Fibo2 {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1)); // Calling the
iterative method to calculate fibonacci number
scan.close();
}
public static long calFibonacci(int index){
int first=0;
int second=1;
for(int i=2;i<=index;i++){
int temp=first;
first=first+second;
second=temp;
}
return first;
}
}
/** Output
*
* Enter the value of n 25
The 25. Fibonacci number is 75025
*
*/
/**************************************************/
The efficient method is the iterative way of calculating the number
Explaination
In recursion method we calculate the the numbers from current index till 0. So for each index we
do calculate the fibonacci number again and again. Hence it takes a lot time to calculate the
answers. Whereas in iterative method we do not rework like recursion. Here we store the
previous two numbers(first and second in above code) and calculate the next one. So its a
efficient way to calculate the number. The time complexity in this will be O(n).
Thanks a lot. Please feel free to ask doubts if you have any. God bless you.
Solution
/******************* using recursive method **********************/
/**
* 1.2.1 Java program to calculate the Fibonacci Number using recursion
*/
import java.util.Scanner;
public class Fibo {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the
recursive method
scan.close();
}
//method to calculate Fibonacci number recursively
public static long calFibonacci(int index){
if (index == 1)
return 0;
if (index == 2)
return 1;
return calFibonacci(index - 1) + calFibonacci(index - 2);
}
}
/** Outputs
* .
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Exception handling
Here are solutions to the exercises:
1. WAP to enter a name of the user and show an exception if it does not enter its name:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
try {
System.out.print("Enter your name: ");
String name = sc.nextLine();
if(name.isEmpty()) {
throw new Exception("Name cannot be empty");
}
System.out.println("Name entered: " + name);
} catch (Exception e) {
System.out.println("Exception: " + e.getMessage
Basic input-output-v.1.1
Streams are used for reading and writing data in Java. The Scanner class is used for reading text files by constructing a Scanner from a File object. The PrintStream class is used for writing to text files by specifying the file name and encoding. Exceptions may occur during I/O operations and should be handled using try-catch blocks to prevent program errors.
Java 3 Computer Science.pptx
Exceptions, I/O and Threads Input and Output in Java: The File Class, Standard Streams, Keyboard
Input, File I/O Using Byte Streams, Character Streams, File I/O Using Character Streams -
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Creating Threads by Implementing Runnable, Advantages of Using Threads, Daemon Threads,
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IO and threads Java
This document provides information about input and output in Java. It discusses files, streams, standard streams like System.in and System.out, and different ways of handling keyboard input in Java programs. The File class in Java represents files and directories on the disk. It describes the various File class constructors, methods, and examples of using the File class to work with files like creating, reading, and checking files. Standard streams provide predefined paths for input/output. Streams can be byte-based or character-based. Keyboard input can be handled using command line arguments, the Console class, Scanner class, or InputStreamReader class.
For the following I have finished most of this question but am havin.pdf
For the following I have finished most of this question but am having problem with on method. I
just need the void copyNumbers method filled out. The commented out sections describe what it
needs to do. I have it started. Just need it finished.
package reading_with_exceptions;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Reading_With_Exceptions {
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully read the count integer.
// I recommend -1 for a count value if it is bad to indicate reading ALL
// 4.) Use copyNumbers method described below to complete the job
// 5.) Close Scanner and PrintStream objects
// 6.) Call printToScreen to copy the output file to the screen
void process(String inputFilename) {
int number_to_read = 0;
try {
Scanner input = new Scanner(inputFilename);
String outputFilename = input.next();
PrintStream os = new PrintStream(new FileOutputStream(outputFilename));
if ( input.hasNextInt()) {
number_to_read = input.nextInt();
}else {
number_to_read = -1;
}
copyNumbers(input, os, number_to_read);
input.close();
os.close();
printToScreen(outputFilename);
}catch (FileNotFoundException e) {
System.out.println(\"Cannot find file: \" + e);
return;
}
}
// The following routine is called to complete the job of copying integers to
// the output file:
// scan - a Scanner object to copy integers from
// ps - A PrintStream to write the integers to
// numIntsToRead - number of integers to read. A value of -1 ==> read all integers
void copyNumbers(Scanner scan, PrintStream ps, int numIntsToRead) {
// hasNext() can be used to see if the scan object still has data
// Note that hasNextInt() can be used to see if an integer is present
// nextInt() will read an integer
// next() can be used to skip over bad integers
while (scan.hasNext()) {
if (numIntsToRead < 0) {
//print out a complaint message and then read as many integers as you find.
scan.nextInt();
}
if (!scan.hasNextInt()) {
// print a complaint message and skip over the data
scan.next();
}
if ( scan < numIntsToRead) {
// complain but do not abort
}
}
}
public static void main(String[] args) {
Reading_With_Exceptions rwe = new Reading_With_Exceptions();
for (int i=0; i < args.length; i++) {
System.out.println(\"\ \ =========== Processing \"+ args[i] + \" ==========\ \");
rwe.process(args[i]);
}
}
// For the last step, we Copy the contents of the file to the screen
private void printToScreen(String filename) {
Scanner scan = null;
try {
FileInputStream fis = new FileInputStream(filename);
scan = new Scanner(fis);
while (scan.hasNextLine()) {
System.out.println(scan.nextLine());
}
}
catch (FileNotFoundException e) {
System.out.println(\"printToS.
Change the code in Writer.java only to get it working. Must contain .pdf
Change the code in Writer.java only to get it working. Must contain methods: logReverse() ,
logMax(), logDuplicates(),
This lab is going to focus on File Output, which you will find is somewhat similar to console
output.
FileMain.java
import java.io.IOException;
import java.util.ArrayList;
import java.util.Scanner;
public class FileMain {
public static void main(String[] args) throws IOException{
Scanner scnr = new Scanner(System.in);
System.out.print("Please enter the name of the file you would like to read: ");
String fileName = scnr.next();
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents(fileName);
System.out.println("Please enter a name for your new file: ");
String newFileName = scnr.next();
Writer fileOut = new Writer(newFileName);
fileOut.logReverse(fileContents);
fileOut.logMax(fileContents);
fileOut.logDuplicates(fileContents);
fileOut.closeWriter();
scnr.close();
}
}
Filetester.java
import java.io.IOException;
import java.util.ArrayList;
public class FileTester {
public static boolean testLogReverse(ArrayList contents) throws IOException {
Writer writer = new Writer("logReverseTest.txt");
writer.logReverse(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Reversed file contents: ");
expected.add("58");
expected.add("12");
expected.add("19");
expected.add("42");
expected.add("12");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logReverseTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogMax(ArrayList contents) throws IOException {
Writer writer = new Writer("logMaxTest.txt");
writer.logMax(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("The largest number in the file is: 58");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logMaxTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static boolean testLogDuplicates(ArrayList contents) throws IOException {
Writer writer = new Writer("logDuplicatesTest.txt");
writer.logDuplicates(contents);
writer.closeWriter();
ArrayList expected = new ArrayList();
expected.add("Duplicates found: true");
expected.add("End of file.");
Reader testReader = new Reader();
ArrayList result = testReader.getFileContents("logDuplicatesTest.txt");
if(expected.equals(result)) return true;
else return false;
}
public static void main(String[] args) throws IOException {
Reader reader = new Reader();
ArrayList fileContents = reader.getFileContents("nums.txt");
System.out.println("logReverse test passed? " + testLogReverse(fileContents));
System.out.println("logMax test passed? " + testLogMax(fileContents));
System.out.println("logDuplicates test passed? " + testLogDuplicates(fileContents));
}
}
Reader.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Sca.
Session 23 - JDBC
In this session you will learn:
1. File IO Continued
2. Intro to JDBC (Java Database Connectivity)
CORE JAVA-1
The document discusses various input/output (I/O) concepts in Java including serialization. It begins by explaining that serialization allows Java objects to be written to streams and recreated later. It notes that classes must implement the Serializable interface to be serialized. The ObjectOutputStream class is used to write objects to streams and serialize them. An example is provided that demonstrates serializing an object to a file.
import required package file import java.io.File; The Filed.pdf
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file is not writable\");
}
// main method goes here
public static void main(String[] args) {
// TODO Auto-generated method stub
// object instantiation
FileDetails fd=new FileDetails(\"anyfile.doc\"); // You should give exact path and file name
here
}
}
// Importing required packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// the writestring class
public class WriteString {
// Writestring class
public WriteString(String filename,String text) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Printsteam class that connects file using file output stream
PrintStream ps=new PrintStream(new FileOutputStream(file));
// using println method to write to the file
ps.println(text);
}
// main method to execute the code
public static void main(String[] args) throws FileNotFoundException
{
// the writestring class instantiation
WriteString ws=new WriteString(\"f1.txt\",\"Hello World\"); // You should give exact path
and file name here
}
}
// importing packages
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
// The writints class
public class WriteInts {
// the constructor to instantiate
public WriteInts(String filename,int[] myArr) throws FileNotFoundException
{
// File object
File file=new File(filename);
// Using print stream to write integers
PrintStream ps=new PrintStream(new FileOutputStream(file));
//Looping through array elements to write every element
for(int i=0;i
Solution
// import required package file
import java.io.File;
// The Filedetails class
public class FileDetails {
// Constructor that performs the action
public FileDetails(String filename)
{
// File object to get details
File file=new File(filename);
// printing obsolute path
System.out.println(\"Absolute path of file:\"+file.getAbsolutePath());
// printing file size in bytes
System.out.println(\"File Size in bytes:\"+file.length());
// Checking if file is readable
if(file.canRead())
System.out.println(\"The file is readable\");
else
System.out.println(\"The file is not readable\");
// checking if file is writable
if(file.canWrite())
System.out.println(\"The file is writable\");
else
System.out.println(\"The file.
Input output files in java
The document discusses input/output files in Java. It covers the key classes used for reading and writing files in Java, including FileInputStream, FileOutputStream, FileReader, and FileWriter. It also discusses byte streams versus character streams, and provides examples of reading and writing to files in Java using these classes. Standard input/output streams like System.in and System.out are also covered.
Description 1) Create a Lab2 folder for this project2.docx
Description
1) Create a Lab2 folder for this project
2) Use the main driver program (called Writers.java) that I provide below to write files of differing types. You can copy and paste this code, but make sure the spaces variable copies correctly. The copy and paste operation eliminates the spaces between the quotes on some systems.
3) In the writers program, fill in the code for the three classes (Random, Binary, and Text). In each class, you will need a constructor, a write method, and a close method. The constructor opens the file, the write method writes a record, and the close method closes the file.
4) Other than what I just described, don't change the program in any way. The program asks for a file type (random, binary, or text) and the name of the file to create. In a loop it inputs a person's name (string), a person's age (int), and a person's annual salary (double). It writes to a file of the appropriate type. The loop terminates when the user indicates that inputting is complete. The program then asks if another file should be created. If the answer is yes, the whole process starts again. This and all of the java driver programs should be saved in your lab2 folder but not in the cs258 sub-folder.
5) Note: The method signatures for accessing all of the three types of files (binary, random, and text) are on the class web-site. Go to power point slides and click on week two. This will help if you didn't take accurate notes in class.
6) Write a main program to read binary files (BinReader.java). This program only needs to be able to read and display records from a Binary file that was created by the writers program.
7) Write a main program to read random files (RandReader.java). This program only needs to be able to read and display records from a Binary file that was created by the writers program. Make sure that this program reads and displays records in reverse order. DO NOT USE AN ARRAY!!!
8) In your Lab2 folder, create a subfolder within lab2 named cs258. Download Keyboard.java from the class web-site to that folder. Add a new first line of Keyboard.java with the statement, package cs258;. This line will make Keyboard.java part of the cs258 package. The driver program shown below has an import ‘cs258.*;’ statement to access the java files in this package.
9) Modify Keyboard.java. We want to extend this class so it can be extended to allow access to multiple files. The changes follow:
a. Remove all static references. This is necessary so that there will be an input stream variable (in) in each object.
b. Change the private modifier of the in and current_token variables to protected. Change the private modifier to protected in all of the signature lines of the overloaded getNextToken methods.
c. Create a constructor that instantiates the input stream for keyboard input. Remove the instantiation from the original declaration line for the in variable. The constructor doesn't need any parameters.
10)Create a class TextR.
Use Java to program the following.1. Create public java class name.pdf
Use Java to program the following.
1. Create public java class named Benford.
2. It\'s main function should prompt for the name of a data file and then the function iterates
through the all of the elements in the data file and computes the frequency (count and
percentage) of the first number in each entry.
3. Note: Some of the data files have comments that you must filter out.
4. Also note: that blank lines or lines where the number begins or is 0 must also be filtered out.
5. Your output must be formatted as follows.
Solution
Hi Firend, Please find my code.
Please let me know in case of any issue.
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class CountFrequency {
public static void main(String[] args) throws FileNotFoundException {
Scanner sc = new Scanner(System.in);
// taking input file name
System.out.print(\"Enter input file name: \");
String fileName = sc.next();
// opening input file
Scanner inputFile = new Scanner(new File(fileName));
// declaring array to store count of first digit of each entery
int[] frequency = new int[10];
int totalCount = 0; // to maintain total count
int num;
// reading all lines
while(inputFile.hasNextLine()){
// reading current line
String line = inputFile.nextLine();
// if line is not empty
if(line == null || line.isEmpty() || line.trim() == \"\")
continue;
// taking first character of current line
char firstDigit = line.charAt(0);
// if first character is digit and not equal to 0
if(Character.isDigit(firstDigit) && firstDigit != \'0\'){
// converting first character of current line in integer
int d = firstDigit - \'0\';
frequency[d]++;
totalCount++;
}
}
System.out.println(\"Digit\\tCount\\tFrequency\");
for(int i=1; i<=9; i++){
System.out.println(i+\"\\t\"+frequency[i]+\"\\t\"+
((double)frequency[i]/(double)totalCount*100));
}
}
}
/*
Sample run:
##### Entry of input.txt:
453 43
//543
123
0
4ee
875
52
// Output
Enter input file name: input.txt
Digit Count Frequency
1 1 20.0
2 0 0.0
3 0 0.0
4 2 40.0
5 1 20.0
6 0 0.0
7 0 0.0
8 1 20.0
9 0 0.0
*/.
Comments added... import java.io.File; import java.io.FileNotF.pdf
Comments added...
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
/**
*
* @author prmsh
*/
public class SaveMatrix {
public static void main(String args[]) {
//declaring matrix..
String[][] data = new String[4][4];
int row = 0;
// opening and reading file
File file = new File(\"matrix.txt\");
try {
Scanner sc = new Scanner(file);
while (sc.hasNextLine()) {
String line = sc.nextLine();
//splitting each row by spaces
String[] lineArray = line.split(\" \");
//storing into array
for(int i=0; i
Solution
Comments added...
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
/**
*
* @author prmsh
*/
public class SaveMatrix {
public static void main(String args[]) {
//declaring matrix..
String[][] data = new String[4][4];
int row = 0;
// opening and reading file
File file = new File(\"matrix.txt\");
try {
Scanner sc = new Scanner(file);
while (sc.hasNextLine()) {
String line = sc.nextLine();
//splitting each row by spaces
String[] lineArray = line.split(\" \");
//storing into array
for(int i=0; i.
Hi, I need help with a java programming project. specifically practi.pdf
Given 8 distinct integers from the set {1, 2, . . . , 16}, prove that there exists k such that ai aj = k
has at least 3 distinct solutions (ai , aj ) ?
Solution
For any k (unless the K is zero), at least 3 distinct solutions need not be existing.
Let\'s look at the next most favourable case
If k= 2;
We have to consider the case where the number of solutions of ai-aj=2 are minimum since we
have to show that at least 3 distinct solutions exist (which means even in the most unfavourable
case for a chosen k there will be 3 distinct solutions satisfying the equation ai-aj=2)
If k = 2; we start by taking numbers that are not at all 2 units apart from each other;
So we start with 1 and move 3 units successively ahead
1, 4, 7, 10,13, 16; Now we notice that these 6 numbers are of 3k+1 form; remaining numbers
can be any 2 ranomdly selected say 2 and 11; we get 4-2 = 2 and 13-11=2; Hence only 2 distinct
solutions are possible..
Please I am trying to get this code to output in -txt file- I need you.pdf
Please I am trying to get this code to output in .txt file:
I need your help:
import java.io.File; // Import the File class
import java.io.FileNotFoundException; // Import this class to handle errors
// Import the Scanner class to read text files
import java.util.*;
import java.io.*;
public class KMeans {
List<double []> clusterCentroids;
Map<Integer,List<Double>> dataMatrix;
List<double[]> data;
Integer numClusters;
public void writeFile(List<Double> value, File filename) {
try {
FileWriter myWriter = new FileWriter(filename);
myWriter.write(value.toString());
myWriter.close();
System.out.println("Successfully wrote to the file.");
} catch (IOException e) {
System.out.println("An error occurred.");
e.printStackTrace();
}
}
public KMeans() {
data = new ArrayList<double []>();
dataMatrix = new LinkedHashMap<>();
}
void readData(String filePath, int n, List<Double> c) {
numClusters = n;
try {
BufferedReader br = new BufferedReader(new FileReader(new File(filePath)));
String line;
int i = 0;
while((line = br.readLine()) != null) {
String [] elem = line.split("\\s+");
int j = 0;
for(String d : elem) {
if(isCentroid(j, c)) {
this.clusterCentroids.get(i)[j] = ((Double.valueOf(d)));
}
//data.get(i)[j] = ((Double.valueOf(d)));
System.out.println(data.get(j)[i]);
}
System.out.println();
i++;
}
br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
private boolean isCentroid(int j, List<Double> c) {
for(int i = 0; i < c.size(); i++) {
if(j == c.get(i)) {
return true;
}
}
return false;
}
public static void main(String [] args) {
Scanner sc = new Scanner(System.in);
List<Double> centroids = new ArrayList<>();
String filePath = ("C:\\Users\\mamdo\\eclipse-
workspace\\K_project\\src\\synthetic_control_data.txt");
int n = 6;
for(int i=0;i<n;i++) {
Random r = new Random();
centroids.add((double)r.nextInt(600)+1);
}
System.out.println("Initial Clusters Centroids : " + centroids);
KMeans km = new KMeans();
//km.readData(filePath,n,centroids);
//km.calc();
}
}
.
The Java Program for the above given isimport java.io.File;impo.pdf
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}
Solution
The Java Program for the above given is:
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
import java.util.NoSuchElementException;
import java.io.PrintWriter;
public class InputPrototype
{
public static void main(String[] args)
throws FileNotFoundException
{
Scanner in = new Scanner(System.in);
System.out.print(\"Input File Name: \");
String inputFileName = in.next();
System.out.print(\"Output File Name: \");
String outputFileName = in.next();
File inputFile = new File(inputFileName);
Scanner input = new Scanner(inputFile);
PrintWriter out = new PrintWriter(outputFileName);
double total= 0;
while (in.hasNextDouble())
{
double value = in.nextDouble();
out.printf(\"%15.2f\ \", value);
total = total + value;
}
out.printf(\"Total: %8.2f\ \", total);
in.close();
out.close();
}
}
}.
Understanding java streams
The document discusses Java streams and I/O. It defines streams as abstract representations of input/output devices that are sources or destinations of data. It describes byte and character streams, the core stream classes in java.io, predefined System streams, common stream subclasses, reading/writing files and binary data with byte streams, and reading/writing characters with character streams. It also covers object serialization/deserialization and compressing files with GZIP.
Need help with this java code. fill in lines where needed. Also, not.pdf
Need help with this java code. fill in lines where needed. Also, not sure how to make the text
files and load them into program. Thanks!!
Create a package named \"reading_with_exceptions\". Write a class named:
Reading_With_Exceptions with the following method:
void process(String inputFilename)
Your program will encounter errors, and we want you to gracefully handle them in such a way
that you print out informative information and continue executing.
Your process routine will try to open a file with the name of inputFilename for input. If there is
any problem (i.e. the file doesn\'t exist), then you should catch the exception, give an appropriate
error and then return. Otherwise, your program reads the file for instructions.
Your process routine will read the first line of the file looking for an outputFilename String
followed by an integer. i.e.:
outputFilename number_to_read
Your program will want to write output to a file having the name outputFilename. Your program
will try to read from \"inputFilename\" the number of integers found in \"number_to_read\".
Your process method will copy the integers read from inputFilename and write them to your
output file(i.e. outputFilename). There should contain 10 numbers per line of output in your
output file.
If you encounter bad input, your program should not die with an exception. For example:
If the count of the numbers to be read is bad or < 0 you will print out a complaint message and
then read as many integers as you find.
If any of the other numbers are bad, print a complaint message and skip over the data
If you don\'t have enough input numbers, complain but do not abort
After you have processed inputFilename, I would like your program to then close the output file
and tell the user that the file is created. Then Open up the output file and copy it to the Screen.
For example, if inputFilename contained:
We would expect the output of your program to be (Note that after 23 numbers we stop printing
numbers):
The main program will access the command line to obtain the list of filenames to call your
process routine with.
For those of you who benefit from a Template, your program might look like:
To prove that your program works, I want you to run your program with the following command
line parameters:
file1.txt non-existent-file file2.txt file3.txt
Where non-existent-file does not exist.
file1.txt contains:
file2.txt contains:
file3.txt contains:
Solution
// Reading_With_Exceptions.java
import java.io.File; // required imports for the code
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.Scanner;
public class Reading_With_Exceptions
{ // class that runs the code
// 1.) Create a Scanner from the inputFilename. Catch exceptions from errors.
// 2.) Read the first String from the file and use it to create a PrintStream
// catching appropriate exceptions
// 3.) Using hasNextInt and nextInt, carefully re.
JDBC
In this core java training session, you will learn Examples of File IO &
Introduction to JDBC. Topics covered in this session are:
• File IO Continued
• Intro to JDBC (Java Database Connectivity)
For more information about this course visit on this link: https://www.mindsmapped.com/courses/software-development/learn-java-fundamentals-hands-on-training-on-core-java-concepts/
Java căn bản - Chapter12
This chapter discusses various methods of file input and output in Java, including low-level file I/O using FileInputStream and FileOutputStream, high-level file I/O using DataInputStream and DataOutputStream to read and write primitive data types, reading and writing text files using PrintWriter, BufferedReader, and Scanner, and object file I/O using ObjectInputStream and ObjectOutputStream to save and load objects. It also covers using JFileChooser to allow users to select files and applying file filters.
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More from vichu19891
1. Copper is above silver in the activity series. Thus Cu metal will.pdf
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq)
Solution
1. Copper is above silver in the activity series. Thus Cu metal will displace Ag+ ions from
solution, forming Cu2+ ions and metallic Ag.
Observation: The reddish brown copper metal dissolves and silver metal precipitates out. The
colorless Ag+ solution turns blue due to Cu2+ ions formed.
2. Molecular equation:
Cu(s) + 2 AgNO3(aq) => 2 Ag(s) + Cu(NO3)2(aq)
3. Complete ionic equation (obtained by expanding soluble ions in molecular equation):
Cu(s) + 2 Ag+(aq) + 2 NO3-(aq) => 2 Ag(s) + Cu2+(aq) + 2 NO3-(aq)
4. Net ionic equation (obtained by cancelling common ions in complete ionic equation):
Cu(s) + 2 Ag+(aq) => 2 Ag(s) + Cu2+(aq).
using recursive method .pdf
/******************* using recursive method **********************/
/**
* 1.2.1 Java program to calculate the Fibonacci Number using recursion
*/
import java.util.Scanner;
public class Fibo {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the
recursive method
scan.close();
}
//method to calculate Fibonacci number recursively
public static long calFibonacci(int index){
if (index == 1)
return 0;
if (index == 2)
return 1;
return calFibonacci(index - 1) + calFibonacci(index - 2);
}
}
/** Outputs
* Enter the value of n 25
The 25. Fibonacci number is 75025
*/
/******************************using iterative
method************************************/
/**
* 1.2.2 Java program to calculate the fibonacci number using iterative method
*/
import java.util.Scanner;
public class Fibo2 {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1)); // Calling the
iterative method to calculate fibonacci number
scan.close();
}
public static long calFibonacci(int index){
int first=0;
int second=1;
for(int i=2;i<=index;i++){
int temp=first;
first=first+second;
second=temp;
}
return first;
}
}
/** Output
*
* Enter the value of n 25
The 25. Fibonacci number is 75025
*
*/
/**************************************************/
The efficient method is the iterative way of calculating the number
Explaination
In recursion method we calculate the the numbers from current index till 0. So for each index we
do calculate the fibonacci number again and again. Hence it takes a lot time to calculate the
answers. Whereas in iterative method we do not rework like recursion. Here we store the
previous two numbers(first and second in above code) and calculate the next one. So its a
efficient way to calculate the number. The time complexity in this will be O(n).
Thanks a lot. Please feel free to ask doubts if you have any. God bless you.
Solution
/******************* using recursive method **********************/
/**
* 1.2.1 Java program to calculate the Fibonacci Number using recursion
*/
import java.util.Scanner;
public class Fibo {
public static void main(String args[]){
Scanner scan= new Scanner(System.in); //Scanner object to read from the user
int n;
System.out.println(\"Enter the value of n\");
n=scan.nextInt();
System.out.println(\"The \"+n+\". Fibonacci number is \"+calFibonacci(n+1));// Calling the
recursive method
scan.close();
}
//method to calculate Fibonacci number recursively
public static long calFibonacci(int index){
if (index == 1)
return 0;
if (index == 2)
return 1;
return calFibonacci(index - 1) + calFibonacci(index - 2);
}
}
/** Outputs
* .
a. Population - families in the state of Florida b. Variable .pdf
a. Population - families in the state of Florida
b. Variable measured - number of children per family
c. Level of measurement - ratio
d. 1.Simple Random Sample
Solution
a. Population - families in the state of Florida
b. Variable measured - number of children per family
c. Level of measurement - ratio
d. 1.Simple Random Sample.
there is no reaction between HNO3 and KCl. S.pdf
There is no reaction observed between HNO3 and KCl in solution. The experiment showed that nitric acid and potassium chloride do not undergo a chemical reaction when combined.
The thickness of non-saturated zone and physico-c.pdf
The thickness of non-saturated zone and physico-chemical conditions are important
parameters to assess the impact of infiltration ponds on water resources with respect to heavy
metals transfer. As changes in physico-chemical parameters of solutions have a strong impact on
the mobility of colloidal phases in sediments and soils, the colloidal facilitated transfer of heavy
metals has to be investigated. Therefore, this study focuses on the characterization of runoff,
surface and interstitial waters in a retention/infiltration pond collecting runoff waters of a bridge
near Nantes. Physico-chemical parameters and chemical analyses were performed on the waters
during about one year. The separation of dissolved and colloidal fractions was carried out by
filtration and ultrafiltration for one sample of surface and interstitial waters. Until now, the
runoff waters were only filtered at 0.45 microm. The comparison of physico-chemical data
shows that the minor variations of runoff water parameters are mitigated in basin and in soils but
strong variations impact the composition of interstitial waters. High concentrations of zinc,
copper and still of lead are measured in runoff. Lead and cadmium seem to be associated to
colloidal and particulate fractions while zinc, copper, nickel and chromium are distributed in all
fractions.
Solution
The thickness of non-saturated zone and physico-chemical conditions are important
parameters to assess the impact of infiltration ponds on water resources with respect to heavy
metals transfer. As changes in physico-chemical parameters of solutions have a strong impact on
the mobility of colloidal phases in sediments and soils, the colloidal facilitated transfer of heavy
metals has to be investigated. Therefore, this study focuses on the characterization of runoff,
surface and interstitial waters in a retention/infiltration pond collecting runoff waters of a bridge
near Nantes. Physico-chemical parameters and chemical analyses were performed on the waters
during about one year. The separation of dissolved and colloidal fractions was carried out by
filtration and ultrafiltration for one sample of surface and interstitial waters. Until now, the
runoff waters were only filtered at 0.45 microm. The comparison of physico-chemical data
shows that the minor variations of runoff water parameters are mitigated in basin and in soils but
strong variations impact the composition of interstitial waters. High concentrations of zinc,
copper and still of lead are measured in runoff. Lead and cadmium seem to be associated to
colloidal and particulate fractions while zinc, copper, nickel and chromium are distributed in all
fractions..
The folding process of proteins is hierarchical, .pdf
The folding process of proteins is hierarchical, with secondary structures forming
before tertiary structures
Solution
The folding process of proteins is hierarchical, with secondary structures forming
before tertiary structures.
Step1 ppt of PbCl2 are soluble in hot water. Ste.pdf
Step1 ppt of PbCl2 are soluble in hot water. Step2 Pb +2 is present in S1 and P1
Step3 Hg and Ag+1 are absent. Step4 Pb+2(aq)+ 2Cl-(aq)---->PbCl2(s)
Solution
Step1 ppt of PbCl2 are soluble in hot water. Step2 Pb +2 is present in S1 and P1
Step3 Hg and Ag+1 are absent. Step4 Pb+2(aq)+ 2Cl-(aq)---->PbCl2(s).
Should take off H from SH group, forming RS-Na+ s.pdf
Should take off H from SH group, forming RS-Na+ salt. note: both S and O are
group 16 elements. However, S is in the third row and O is in the second row. THe atomic size
of S is bigger than that of O, thus S-H bond is weaker than O-H bond. The H in SH is more
acidic than that in OH. the acidity of H: SH > OH > NH > CH
Solution
Should take off H from SH group, forming RS-Na+ salt. note: both S and O are
group 16 elements. However, S is in the third row and O is in the second row. THe atomic size
of S is bigger than that of O, thus S-H bond is weaker than O-H bond. The H in SH is more
acidic than that in OH. the acidity of H: SH > OH > NH > CH.
Rest are okay but B) I think should be vanderwall.pdf
Rest are okay but B) I think should be vanderwall\'s interaction rather than dipole-
dipole. pls ponder over.
Solution
Rest are okay but B) I think should be vanderwall\'s interaction rather than dipole-
dipole. pls ponder over..
pH =4.217 pH = - log(concentration of H+) = -log .pdf
pH =4.217 pH = - log(concentration of H+) = -log (6.06E-05) = 4.217
Solution
pH =4.217 pH = - log(concentration of H+) = -log (6.06E-05) = 4.217.
Liquids may change to a vapor at temperatures bel.pdf
Liquids may change to a vapor at temperatures below their boiling points through
the process of evaporation. Evaporation is a surface phenomenon in which molecules located
near the liquid\'s edge, not contained by enough liquid pressure on that side, escape into the
surroundings as vapor. On the other hand, boiling is a process in which molecules anywhere in
the liquid escape, resulting in the formation of vapor bubbles within the liquid.
Solution
Liquids may change to a vapor at temperatures below their boiling points through
the process of evaporation. Evaporation is a surface phenomenon in which molecules located
near the liquid\'s edge, not contained by enough liquid pressure on that side, escape into the
surroundings as vapor. On the other hand, boiling is a process in which molecules anywhere in
the liquid escape, resulting in the formation of vapor bubbles within the liquid..
intra extra equilibrium potential mEqL mEqL 1.pdf
intra extra equilibrium potential mEq/L mEq/L 12 142 61.77 135 4 -87.97 0.5 *
10^-4 0.75 * 10^-4 120.19 4.5 112 80.36 equlibrium potential = RT/ZF ln(Xo/Xi) =25 mV
ln(Xo/Xi) mEq/L=(mMoles/L) / valency
Solution
intra extra equilibrium potential mEq/L mEq/L 12 142 61.77 135 4 -87.97 0.5 *
10^-4 0.75 * 10^-4 120.19 4.5 112 80.36 equlibrium potential = RT/ZF ln(Xo/Xi) =25 mV
ln(Xo/Xi) mEq/L=(mMoles/L) / valency.
Which of the following forms of DES is considered the most vulnerabl.pdf
Which of the following forms of DES is considered the most vulnerable to attack?
A. CBC
B. ECB
C. CFB
D. OFB
Solution
Which of the following forms of DES is considered the most vulnerable to attack?
A. CBC
B. ECB
C. CFB
D. OFB.
This is actually pretty simple, so Ill help explain. Take a gi.pdf
This is actually pretty simple, so I\'ll help explain.
Take a given hydrogen atom, but we\'ll use an ionic form that has 5 electrons (as you\'ve stated).
Now, for the quantum numbers.
The first one, N, is the electron shell in question. Shells work as providing spaces for electron
density. The first shell, in which N=1, holds two electrons because it only contains one orbital.
N=2 holds two orbitals, which holds four electrons. Combined with N=1, an ion in N=2 has
anywhere between 3 (the minimum of N=1, +1 electron) and 8 electrons (the maximum number
of electrons before entering the third shell. Because the ion in question has 5 electrons, its N
value is 2.
A simple way to calculate the maximum number of electrons in a given atom that occupies a
specific shell is to take that shell number, N, square it and multiply the result by two. That is why
the maximum quantum number N for an atom whose electrons occupy the third shell is 18
(which is (3^2)2).
Onto the next quantum number, which is l. If you understand the order of atomic shells and their
orbitals, this is a simple one.
The first shell is l=0, which is the \"s\" shell of an atom. s shells can only hold one atomic
orbital, which is two electrons. We denote this as \"1s2\". The next shell is 2s, and because we
can fill it, it become 2s2.Because we have 5 electrons, we need to keep going up. The next shell
is l=1, which is the \"p\" shell. That fits our last electron, so your value for the l quantum number
is \"1.\"
Now we\'re at the ml quantum number. These are the numbers we assign to the specific orbitals
in which electrons reside in, within a given shell. We\'re currently in the p shell, which holds 3
orbitals whose names are -1, 0, and +1. Unless you have a picture of the electron shells, we can
only guess that the 5th electron is in any one of these, so the safe bet is to put it into the -1 orbital
(though it can really be in any of them).
Lastly, the ms quantum number. This denotes the spin on the electron. Up spin is +1/2, whilst
down spin is -1/2. Unless you have a picture, I can\'t tell you which way it is spinning, but it\'s a
safe guess to say that it\'s up.
In sum, your quantum numbers as: 2, 1, 0, (1/2)
I hope that helps. (: Feel free to ask any questions.
Solution
This is actually pretty simple, so I\'ll help explain.
Take a given hydrogen atom, but we\'ll use an ionic form that has 5 electrons (as you\'ve stated).
Now, for the quantum numbers.
The first one, N, is the electron shell in question. Shells work as providing spaces for electron
density. The first shell, in which N=1, holds two electrons because it only contains one orbital.
N=2 holds two orbitals, which holds four electrons. Combined with N=1, an ion in N=2 has
anywhere between 3 (the minimum of N=1, +1 electron) and 8 electrons (the maximum number
of electrons before entering the third shell. Because the ion in question has 5 electrons, its N
value is 2.
A simple way to calculate the maximum number of electrons.
There are many test IPv6 networks deployed across the world. For act.pdf
There are many test IPv6 networks deployed across the world. For actual deployment, however,
all the companies need to ensure that the vendors who support companys network have the
requisite IPv6 enhancements.
There are two categories of IPv6 enhancements. The first is the set that supports the packet
forwarding (more commonly referred to as routing) process and the other set comprises
enhancements that support the computing or host infrastructure.
IPv6 enhancements of the first category include larger address formats (the ones that affect the
routing table size and structure), better routing protocols such as Open Shortest First Protocol
(OSPF) and Routing Information Protocol (RIP), and good support for optional extension
headers (which streamline the packet forwarding process) such as the Routing Header. And, the
second category of enhancements comprises enhancements to the Domain Name System (DNS),
the Stateless Auto-configuration (plug and play) process, upgraded Security, and updates to the
Application Programming Interfaces (APIs).
Keeping these requisite enhancements in mind, let us now discuss what kind of support ten of
the premier networking vendors are equipped to provide:
Solution
There are many test IPv6 networks deployed across the world. For actual deployment, however,
all the companies need to ensure that the vendors who support companys network have the
requisite IPv6 enhancements.
There are two categories of IPv6 enhancements. The first is the set that supports the packet
forwarding (more commonly referred to as routing) process and the other set comprises
enhancements that support the computing or host infrastructure.
IPv6 enhancements of the first category include larger address formats (the ones that affect the
routing table size and structure), better routing protocols such as Open Shortest First Protocol
(OSPF) and Routing Information Protocol (RIP), and good support for optional extension
headers (which streamline the packet forwarding process) such as the Routing Header. And, the
second category of enhancements comprises enhancements to the Domain Name System (DNS),
the Stateless Auto-configuration (plug and play) process, upgraded Security, and updates to the
Application Programming Interfaces (APIs).
Keeping these requisite enhancements in mind, let us now discuss what kind of support ten of
the premier networking vendors are equipped to provide:.
The three ways of presenting the changes in the balance of the Compr.pdf
The three ways of presenting the changes in the balance of the Comprehensive Income
(Cumulative) are :
(i) Adding the value to the Stockholders\' Equity Balance.
(ii) Showing the credit balance as a separate item in the Reserves and Surplus section of the
Liabilities side.
(iii) Showing a debit balance in the comprehensive income as an item in the Assets Side of the
Balance Sheet with the heading \"Debit Balance in Profit and Loss Account\".
Solution
The three ways of presenting the changes in the balance of the Comprehensive Income
(Cumulative) are :
(i) Adding the value to the Stockholders\' Equity Balance.
(ii) Showing the credit balance as a separate item in the Reserves and Surplus section of the
Liabilities side.
(iii) Showing a debit balance in the comprehensive income as an item in the Assets Side of the
Balance Sheet with the heading \"Debit Balance in Profit and Loss Account\"..
The RASopathies are a group of genetic syndromes caused by germline .pdf
The RASopathies are a group of genetic syndromes caused by germline mutations in genes that
alter the Ras sub family and Mitogen activated protein kinases that control signal transduction.
Some of these syndromes are neurofibromatosis type 1, Noonan syndrome, Costello syndrome,
cardio-facio-cutaneous syndrome, LEOPARD syndrome and Legius syndrome. RAS opathies
and X-chromosomes are not linked.
Solution
The RASopathies are a group of genetic syndromes caused by germline mutations in genes that
alter the Ras sub family and Mitogen activated protein kinases that control signal transduction.
Some of these syndromes are neurofibromatosis type 1, Noonan syndrome, Costello syndrome,
cardio-facio-cutaneous syndrome, LEOPARD syndrome and Legius syndrome. RAS opathies
and X-chromosomes are not linked..
ThanksSolutionThanks.pdf
This very short document simply contains the word "Thanks" repeated three times. It does not provide much substantive information that can be summarized in 3 sentences or less. The document appears to be acknowledging a solution or response to something but without any other context or details, the intent and meaning cannot be clearly determined from the text alone.
Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p Anti.pdf
Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p * Anti bonding orbital. Hence
O2 molecule is paramagnetic.
Step2 C2^- has 1 unpaired electron; is also paramagnetic.
Solution
Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p * Anti bonding orbital. Hence
O2 molecule is paramagnetic.
Step2 C2^- has 1 unpaired electron; is also paramagnetic..
Quartzite is sandstone that has been converted to a solid quartz roc.pdf
Quartzite is sandstone that has been converted to a solid quartz rock.
It formed when silica is subjected to great heat and pressure. The individual silica particles melt
and glue together to form quartizite.
Solution
Quartzite is sandstone that has been converted to a solid quartz rock.
It formed when silica is subjected to great heat and pressure. The individual silica particles melt
and glue together to form quartizite..
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Step1 ppt of PbCl2 are soluble in hot water. Ste.pdf
Step1 ppt of PbCl2 are soluble in hot water. Ste.pdf
Should take off H from SH group, forming RS-Na+ s.pdf
Should take off H from SH group, forming RS-Na+ s.pdf
Rest are okay but B) I think should be vanderwall.pdf
Rest are okay but B) I think should be vanderwall.pdf
pH =4.217 pH = - log(concentration of H+) = -log .pdf
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Liquids may change to a vapor at temperatures bel.pdf
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Which of the following forms of DES is considered the most vulnerabl.pdf
Which of the following forms of DES is considered the most vulnerabl.pdf
This is actually pretty simple, so Ill help explain. Take a gi.pdf
This is actually pretty simple, so Ill help explain. Take a gi.pdf
There are many test IPv6 networks deployed across the world. For act.pdf
There are many test IPv6 networks deployed across the world. For act.pdf
The three ways of presenting the changes in the balance of the Compr.pdf
The three ways of presenting the changes in the balance of the Compr.pdf
The RASopathies are a group of genetic syndromes caused by germline .pdf
The RASopathies are a group of genetic syndromes caused by germline .pdf
Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p Anti.pdf
Step1 In O2 ; we have 2 unpaired electrons which occupy pi 2p Anti.pdf
Quartzite is sandstone that has been converted to a solid quartz roc.pdf
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- 1. /* * The java program that reads an input file input.txt * and then reads the contens of file. * the program throws file not found exception if file not found. * The program throws DimensionMismatchException if mismatch of dimension. * The program throws NumberFormatException if mismatch of data read. * */ //FormatChecker.java import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class FormatChecker { public static void main(String[] args) { String fileName="input.txt"; //calling checkFormat checkFormat(fileName); } //Method checkFormat that takes string and check for //errors otherwise reads the file and print to console private static void checkFormat(String fileName) { Scanner filescanner=null; try { //thorws FileNotFoundException error if file not found filescanner=new Scanner(new File(fileName)); } catch (FileNotFoundException e) { System.out.println(e.getMessage()); } int rows=0; int cols=0; double[][] arr;
- 2. String dimensions[]=filescanner.nextLine().split(" "); try { //thorws DimensionMismatchException error if mismatch of dimension if(dimensions.length>2) throw new DimensionMismatchException("Dimension mismatch"); } catch (DimensionMismatchException e1) { e1.printStackTrace(); } try { //thorws NumberFormatException error if mismatch of reading values rows=Integer.parseInt(dimensions[0]); cols=Integer.parseInt(dimensions[1]); arr=new double[rows][cols]; System.out.println("File contents"); for (int i = 0; i < arr.length; i++) { for (int j = 0; j < arr[i].length; j++) { arr[i][j]=filescanner.nextDouble(); System.out.printf("%6.1f",arr[i][j]); } System.out.println(); } } catch (NumberFormatException e) { System.out.println(e.getMessage()); }
- 3. } } ------------------------------------------------------------------------ //User defined DimensionMismatchException class //that extends the Exception class //DimensionMismatchException.java public class DimensionMismatchException extends Exception { public DimensionMismatchException(String msg) { super(msg); } } ------------------------------------------------------------------------ input.txt 5 6 2.5 0 1 0 0 0 0 -1 4 0 0 0 0 0 0 0 1.1 0 0 2 0 0 5 0 0 -3.14 0 0 0 0 ------------------------------------------------------------------------ File contents 2.5 0.0 1.0 0.0 0.0 0.0 0.0 -1.0 4.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.1 0.0 0.0 2.0 0.0 0.0 5.0 0.0 0.0 -3.1 0.0 0.0 0.0 0.0 Note : DimensionMismatchException class is included Solution /*
- 4. * The java program that reads an input file input.txt * and then reads the contens of file. * the program throws file not found exception if file not found. * The program throws DimensionMismatchException if mismatch of dimension. * The program throws NumberFormatException if mismatch of data read. * */ //FormatChecker.java import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class FormatChecker { public static void main(String[] args) { String fileName="input.txt"; //calling checkFormat checkFormat(fileName); } //Method checkFormat that takes string and check for //errors otherwise reads the file and print to console private static void checkFormat(String fileName) { Scanner filescanner=null; try { //thorws FileNotFoundException error if file not found filescanner=new Scanner(new File(fileName)); } catch (FileNotFoundException e) { System.out.println(e.getMessage()); } int rows=0; int cols=0; double[][] arr; String dimensions[]=filescanner.nextLine().split(" ");
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- 6. } } ------------------------------------------------------------------------ //User defined DimensionMismatchException class //that extends the Exception class //DimensionMismatchException.java public class DimensionMismatchException extends Exception { public DimensionMismatchException(String msg) { super(msg); } } ------------------------------------------------------------------------ input.txt 5 6 2.5 0 1 0 0 0 0 -1 4 0 0 0 0 0 0 0 1.1 0 0 2 0 0 5 0 0 -3.14 0 0 0 0 ------------------------------------------------------------------------ File contents 2.5 0.0 1.0 0.0 0.0 0.0 0.0 -1.0 4.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.1 0.0 0.0 2.0 0.0 0.0 5.0 0.0 0.0 -3.1 0.0 0.0 0.0 0.0 Note : DimensionMismatchException class is included