The answer is b) water decomposes firstThe standard oxidation pot.pdf
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The answer is: b) water decomposes first The standard oxidation potentials are: 2 F- => F2 + 2 e-, E(oxidation) = -2.87 V 2 H2O => O2 + 4 H+ + 4 e-, E(oxidation) = -1.23 V Since H2O has a less negative oxidation potential, it is oxidized more easily than F-. Thus when a solution of F- ions in H2O is electrolyzed, the H2O will decompose first into O2 and H+, while the F- ions remain unreacted. Solution The answer is: b) water decomposes first The standard oxidation potentials are: 2 F- => F2 + 2 e-, E(oxidation) = -2.87 V 2 H2O => O2 + 4 H+ + 4 e-, E(oxidation) = -1.23 V Since H2O has a less negative oxidation potential, it is oxidized more easily than F-. Thus when a solution of F- ions in H2O is electrolyzed, the H2O will decompose first into O2 and H+, while the F- ions remain unreacted..
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Reset Help By the Brnsted-Lowry definition- acids are proton donors an.docx
Reset Help By the Brønsted-Lowry definition, acids are proton donors and bases are proton acceptors. By the Lewis definition, acids are electron-pair acceptors and bases are electron-pair donors. For bases, the two definitions are equivalent such that all Lewis bases are Brønsted-Lowry bases and vice versa However, it is possible to have a Lewis acid that is not a Brønsted-Lowry acid. This is because Lewis acids include molecules and cations that have a vacant valence orbital, regardless of whether they have a proton to donate Common examples of Lewis acids (that are not Brønsted-Lowry acids) are metal ions, such as Al+and Cu2+. The following is an example ofa Lewis acid-base reaction Lewis acids Lewis bases NH3 donates the electron pair to Cu2+. Therefore NH3 is a Lewis base, and Cu2 is a Lewis acid SubmitPrev Previous Answer
Solution
1. Lewis acids: Lewis acids are the species which accepts electrons.
SO 3 since S has only three electron domains. Hence it accepts electrons.
Fe 2+ is electron deficient. Hence it accepts electrons too.
CO 2 where C accepts electrons since it is bound to two highly electronegative oxygen atoms.
Lewis bases are species that donates electrons.
I - , CO, H - , CH 3 NH 2
2. The order of decreasing pH is:
Ba(OH) 2 > NaOH > N 2 H 4 > HOCl > HCl
Ba(OH) 2 decomposes to give 2 OH - ions. This is why it has higher pH than NaOH which decomposes to give only 1 OH - ion.
Hydrazine N 2 H 4 is basic however lesser than NaOH and Ba(OH) 2
HOCl is a weak acid that partially dissociates to give H + and ClO -
HCl is the strongest acid that completely dissociates into H + and Cl - and hence has the lowest pH.
More the H + ions in solution, lesser the pH.
More the OH - ions in solution, higher the pH.
3. Given,
[ OH - ] = 2.3 x 10 -2 M
We know that at 25 0 C,
[H + ] [OH - ] = Kw = Ionic product of water = 10 -14
Putting the value of [OH - ] in the above equation, we have,
[H + ] x 2.3 x 10 -2 = 10 -14
[H + ] = 10 -14 / (2.3 x 10 -2 )
[H + ] = 0.44 x 10 -12 M
.
When the following equation is balanced properly under acidic conditio.docx
When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? Fe2+ + PbO2 Fe3+ + Pb2+
Water appears in the balanced equation as a (reactant, product, neither) ?
with a coefficient of . (Enter 0 for neither.) ?
How many electrons are transferred in this reaction?
Solution
Balancing of redox equation---
--> break into two half-cell--
O: Fe2+ --> Fe3+
R: PbO2 --> Pb2+
--> Balance atoms other than O and H. Here already balance.
--> Balance O with water and then water with H+--
O: Fe2+ --> Fe3+
R: PbO2 + 4H+ --> Pb2+ + 2H2O
--> Now, Balance charge by e- --
O: Fe2+ --> Fe3+ + e-
R: PbO2 + 4H+ + 2e- --> Pb2+ + 2H2O
--> multiply first equation by 2 and then addup---
2Fe 2+ + PbO 2 + 4H + ? 2Fe 3+ + Pb 2+ + 2H 2 O
--> water appears as a product here with coefficient 2.
--> 2 electrons are transferred in the reaction.
if you have any query comment.
if satisfied please rate it.. thanks..
.
reduction and oxidation reactions.pptx
Presentation On reduction and oxidation reaction..
Course: Chemistry101
Dept. of CSE
The effect of acid deposition is basically the ef.pdf
The effect of acid deposition is basically the effect any acid has on metal. It tends to
corrode it. Corrosion is the electrochemical degradation of a material. That means that as the
metal breaks down, it loses electrons to become a different form. Solid iron (Fe) loses electrons
to become a soluble form, Fe(s) --> Fe2+(in solution) + 2e- These electrons are taken up by
oxygen (O2), which reacts with hydrogen ions (H+) to form water. (1/2) O2 + 2H+ + 2e- -->
H2O The overall reaction is , Fe(s) + (1/2) O2 + 2H+ --> Fe2+ + H2O Normally, the H+ can
come from the acid that forms naturally as CO2 dissolves in water. However, acid rain provides
a lot more H+ & makes it much easier for the reaction to run because there is plenty of
everything needed. Once the iron is in solution it can react further to form iron oxide, which is
also known as rusting.
Solution
The effect of acid deposition is basically the effect any acid has on metal. It tends to
corrode it. Corrosion is the electrochemical degradation of a material. That means that as the
metal breaks down, it loses electrons to become a different form. Solid iron (Fe) loses electrons
to become a soluble form, Fe(s) --> Fe2+(in solution) + 2e- These electrons are taken up by
oxygen (O2), which reacts with hydrogen ions (H+) to form water. (1/2) O2 + 2H+ + 2e- -->
H2O The overall reaction is , Fe(s) + (1/2) O2 + 2H+ --> Fe2+ + H2O Normally, the H+ can
come from the acid that forms naturally as CO2 dissolves in water. However, acid rain provides
a lot more H+ & makes it much easier for the reaction to run because there is plenty of
everything needed. Once the iron is in solution it can react further to form iron oxide, which is
also known as rusting..
Balance the redox reaction by inserting the appropriate coefficients-.docx
Balance the redox reaction by inserting the appropriate coefficients. redox reaction: | Fe3+ + NO + H2O- Fe2+ + H+ + No;
Solution
Fe in Fe+3 has oxidation state of +3
Fe in Fe+2 has oxidation state of +2
So, Fe in Fe+3 is reduced to Fe+2
N in NO2- has oxidation state of +3
N in NO3- has oxidation state of +5
So, N in NO2- is oxidised to NO3-
Reduction half cell:
Fe+3 + 1e- --> Fe+2
Oxidation half cell:
NO2- --> NO3- + 2e-
Balance number of electrons to be same in both half reactions
Reduction half cell:
2 Fe+3 + 2e- --> 2 Fe+2
Oxidation half cell:
NO2- --> NO3- + 2e-
Lets combine both the reactions.
2 Fe+3 + NO2- --> 2 Fe+2 + NO3-
Balance Oxygen by adding water
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3-
Balance Hydrogen by adding H+
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3- + 2 H+
This is balanced chemical equation in acidic medium
Answer:
2 Fe 3+ + NO 2 - + H 2 O —> 2 Fe 2+ + 2 H + + NO 3 -
.
Recommended
Reset Help By the Brnsted-Lowry definition- acids are proton donors an.docx
Reset Help By the Brønsted-Lowry definition, acids are proton donors and bases are proton acceptors. By the Lewis definition, acids are electron-pair acceptors and bases are electron-pair donors. For bases, the two definitions are equivalent such that all Lewis bases are Brønsted-Lowry bases and vice versa However, it is possible to have a Lewis acid that is not a Brønsted-Lowry acid. This is because Lewis acids include molecules and cations that have a vacant valence orbital, regardless of whether they have a proton to donate Common examples of Lewis acids (that are not Brønsted-Lowry acids) are metal ions, such as Al+and Cu2+. The following is an example ofa Lewis acid-base reaction Lewis acids Lewis bases NH3 donates the electron pair to Cu2+. Therefore NH3 is a Lewis base, and Cu2 is a Lewis acid SubmitPrev Previous Answer
Solution
1. Lewis acids: Lewis acids are the species which accepts electrons.
SO 3 since S has only three electron domains. Hence it accepts electrons.
Fe 2+ is electron deficient. Hence it accepts electrons too.
CO 2 where C accepts electrons since it is bound to two highly electronegative oxygen atoms.
Lewis bases are species that donates electrons.
I - , CO, H - , CH 3 NH 2
2. The order of decreasing pH is:
Ba(OH) 2 > NaOH > N 2 H 4 > HOCl > HCl
Ba(OH) 2 decomposes to give 2 OH - ions. This is why it has higher pH than NaOH which decomposes to give only 1 OH - ion.
Hydrazine N 2 H 4 is basic however lesser than NaOH and Ba(OH) 2
HOCl is a weak acid that partially dissociates to give H + and ClO -
HCl is the strongest acid that completely dissociates into H + and Cl - and hence has the lowest pH.
More the H + ions in solution, lesser the pH.
More the OH - ions in solution, higher the pH.
3. Given,
[ OH - ] = 2.3 x 10 -2 M
We know that at 25 0 C,
[H + ] [OH - ] = Kw = Ionic product of water = 10 -14
Putting the value of [OH - ] in the above equation, we have,
[H + ] x 2.3 x 10 -2 = 10 -14
[H + ] = 10 -14 / (2.3 x 10 -2 )
[H + ] = 0.44 x 10 -12 M
.
When the following equation is balanced properly under acidic conditio.docx
When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? Fe2+ + PbO2 Fe3+ + Pb2+
Water appears in the balanced equation as a (reactant, product, neither) ?
with a coefficient of . (Enter 0 for neither.) ?
How many electrons are transferred in this reaction?
Solution
Balancing of redox equation---
--> break into two half-cell--
O: Fe2+ --> Fe3+
R: PbO2 --> Pb2+
--> Balance atoms other than O and H. Here already balance.
--> Balance O with water and then water with H+--
O: Fe2+ --> Fe3+
R: PbO2 + 4H+ --> Pb2+ + 2H2O
--> Now, Balance charge by e- --
O: Fe2+ --> Fe3+ + e-
R: PbO2 + 4H+ + 2e- --> Pb2+ + 2H2O
--> multiply first equation by 2 and then addup---
2Fe 2+ + PbO 2 + 4H + ? 2Fe 3+ + Pb 2+ + 2H 2 O
--> water appears as a product here with coefficient 2.
--> 2 electrons are transferred in the reaction.
if you have any query comment.
if satisfied please rate it.. thanks..
.
reduction and oxidation reactions.pptx
Presentation On reduction and oxidation reaction..
Course: Chemistry101
Dept. of CSE
The effect of acid deposition is basically the ef.pdf
The effect of acid deposition is basically the effect any acid has on metal. It tends to
corrode it. Corrosion is the electrochemical degradation of a material. That means that as the
metal breaks down, it loses electrons to become a different form. Solid iron (Fe) loses electrons
to become a soluble form, Fe(s) --> Fe2+(in solution) + 2e- These electrons are taken up by
oxygen (O2), which reacts with hydrogen ions (H+) to form water. (1/2) O2 + 2H+ + 2e- -->
H2O The overall reaction is , Fe(s) + (1/2) O2 + 2H+ --> Fe2+ + H2O Normally, the H+ can
come from the acid that forms naturally as CO2 dissolves in water. However, acid rain provides
a lot more H+ & makes it much easier for the reaction to run because there is plenty of
everything needed. Once the iron is in solution it can react further to form iron oxide, which is
also known as rusting.
Solution
The effect of acid deposition is basically the effect any acid has on metal. It tends to
corrode it. Corrosion is the electrochemical degradation of a material. That means that as the
metal breaks down, it loses electrons to become a different form. Solid iron (Fe) loses electrons
to become a soluble form, Fe(s) --> Fe2+(in solution) + 2e- These electrons are taken up by
oxygen (O2), which reacts with hydrogen ions (H+) to form water. (1/2) O2 + 2H+ + 2e- -->
H2O The overall reaction is , Fe(s) + (1/2) O2 + 2H+ --> Fe2+ + H2O Normally, the H+ can
come from the acid that forms naturally as CO2 dissolves in water. However, acid rain provides
a lot more H+ & makes it much easier for the reaction to run because there is plenty of
everything needed. Once the iron is in solution it can react further to form iron oxide, which is
also known as rusting..
Balance the redox reaction by inserting the appropriate coefficients-.docx
Balance the redox reaction by inserting the appropriate coefficients. redox reaction: | Fe3+ + NO + H2O- Fe2+ + H+ + No;
Solution
Fe in Fe+3 has oxidation state of +3
Fe in Fe+2 has oxidation state of +2
So, Fe in Fe+3 is reduced to Fe+2
N in NO2- has oxidation state of +3
N in NO3- has oxidation state of +5
So, N in NO2- is oxidised to NO3-
Reduction half cell:
Fe+3 + 1e- --> Fe+2
Oxidation half cell:
NO2- --> NO3- + 2e-
Balance number of electrons to be same in both half reactions
Reduction half cell:
2 Fe+3 + 2e- --> 2 Fe+2
Oxidation half cell:
NO2- --> NO3- + 2e-
Lets combine both the reactions.
2 Fe+3 + NO2- --> 2 Fe+2 + NO3-
Balance Oxygen by adding water
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3-
Balance Hydrogen by adding H+
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3- + 2 H+
This is balanced chemical equation in acidic medium
Answer:
2 Fe 3+ + NO 2 - + H 2 O —> 2 Fe 2+ + 2 H + + NO 3 -
.
1. E) The vapor pressure of a liquid.Increasing attractive intermo.pdf
1. E) The vapor pressure of a liquid.
Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly
to each other. Thus it is more difficult for the molecules to escape into the gas phase and the
vapor pressure decreases.
All the other properties listed should increase in value.
2. A) Ba(OH)2
The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+
and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water
and insoluble BaSO4:
Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l)
The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows
and the bulb dims.
3. D) hydration
Hydration is the process whereby water molecules form dipole-dipole interactions with the solute
ions, releasing energy and causing the salt to fall apart.
4. E)All of these are correct.
All the statements about light, matter and energy are true.
5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your
question but I have put the correct values here for you)
Silicon has electronic configuration 1s2 2s2p6 3s2p2
The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing)
ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to
the nucleus, so the ionization energy shows a large increase.
Solution
1. E) The vapor pressure of a liquid.
Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly
to each other. Thus it is more difficult for the molecules to escape into the gas phase and the
vapor pressure decreases.
All the other properties listed should increase in value.
2. A) Ba(OH)2
The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+
and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water
and insoluble BaSO4:
Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l)
The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows
and the bulb dims.
3. D) hydration
Hydration is the process whereby water molecules form dipole-dipole interactions with the solute
ions, releasing energy and causing the salt to fall apart.
4. E)All of these are correct.
All the statements about light, matter and energy are true.
5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your
question but I have put the correct values here for you)
Silicon has electronic configuration 1s2 2s2p6 3s2p2
The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing)
ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to
the nucleus, so the ionization energy shows a large increase..
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO3.pdf
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3
Solution
FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
tend to dissociate in water, attracted by the partial charges of the molecule.
FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
solution...
H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3.
Oxidation and reduction, Balancing the redox rections
This slide will help the students to learn about the basic concepts of redox reactions and their uses.
Slightly soluble. INsoluble Slightly soluble Solu.pdf
Slightly soluble. INsoluble Slightly soluble Soluble Slightly soluble Soluble
Solution
Slightly soluble. INsoluble Slightly soluble Soluble Slightly soluble Soluble.
O=C-H singlet at about 10 ppm phenyl hydrogens .pdf
O=C-H: singlet at about 10 ppm phenyl hydrogens: doublets at between 7-8 ppm t-
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Solution
O=C-H: singlet at about 10 ppm phenyl hydrogens: doublets at between 7-8 ppm t-
butyl: singlet at between 1-2 ppm.
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1. E) The vapor pressure of a liquid.Increasing attractive intermo.pdf
1. E) The vapor pressure of a liquid.
Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly
to each other. Thus it is more difficult for the molecules to escape into the gas phase and the
vapor pressure decreases.
All the other properties listed should increase in value.
2. A) Ba(OH)2
The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+
and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water
and insoluble BaSO4:
Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l)
The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows
and the bulb dims.
3. D) hydration
Hydration is the process whereby water molecules form dipole-dipole interactions with the solute
ions, releasing energy and causing the salt to fall apart.
4. E)All of these are correct.
All the statements about light, matter and energy are true.
5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your
question but I have put the correct values here for you)
Silicon has electronic configuration 1s2 2s2p6 3s2p2
The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing)
ionization energies. The 5th electron is from the n = 2 shell and is much more strongly bound to
the nucleus, so the ionization energy shows a large increase.
Solution
1. E) The vapor pressure of a liquid.
Increasing attractive intermolecular forces causes molecules in the liquid to bond more strongly
to each other. Thus it is more difficult for the molecules to escape into the gas phase and the
vapor pressure decreases.
All the other properties listed should increase in value.
2. A) Ba(OH)2
The light bulb glows because H2SO4 is an acid and strong electrolyte that ionizes to form H+
and SO42- ions that conduct electricity. Ba(OH)2 is a base that reacts with H2SO4 to form water
and insoluble BaSO4:
Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + H2O(l)
The removal of H+ and SO42-ions decreases the conductivity of the solution, less current flows
and the bulb dims.
3. D) hydration
Hydration is the process whereby water molecules form dipole-dipole interactions with the solute
ions, releasing energy and causing the salt to fall apart.
4. E)All of these are correct.
All the statements about light, matter and energy are true.
5. d) 780 kJ, 1,575 kJ, 3,220 kJ, 4,350 kJ 16,100 kJ (you may have mistyped this in your
question but I have put the correct values here for you)
Silicon has electronic configuration 1s2 2s2p6 3s2p2
The first 4 electrons removed are in the n = 3 shell and have similar (but slowly increasing)
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FeCO3 is an ionic compound, composed of the Fe(II)2+ ion and the CO32- carbonate ion. Ions
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FeCO3 + H2O <---> Fe2+ + CO32- + H2O
Water also dissociates into H+ and OH- at a certain equilibrium rate:
H2O <---> H+ + OH-
Which when combined with an ionic compound is obviously very attractive to the ions in
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H+ + OH- + Fe2+ + CO32- <----> Fe(OH)2 + H2CO3
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FeCO3 + H2O <---> Fe2+ + CO32- + H2O
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An infection is non-cell life forms made up of hereditary material and protein that can attack
living cells. They are viewed as both a living and non living things. In the year 1897, a
researcher named Beijerinck found and begat the term infection. The term infection is gotten
from Latin word-\"infection\" implies harm. Later in the year 1935, a researcher named Wendell
Stanley found that these infections are made out of nucleic acids, protein and lips. The
investigation of infections is called as virology.
Infections are little and they gauged in nanometers. They must be seen with an electron
magnifying lens. They are made out of a center of DNA or RNA encompassed by a protein coat
they can just recreate by tainting living cells. Their size reaches from 20 nanometers to 250
nanometers.
All infections have a capsid or head locale that contains its hereditary material. The capsid is
made of proteins and glycoproteins. Capsid contruction changes enormously among infections,
with most being specific for a specific infection\'s host living being. Some infections, for the
most part of the sort tainting creatures, have a membranous envelope encompassing their capsid.
This permits infections to infiltrate have cells through layer combination. The infection\'s
genetical material rests inside the capsid; that material can be either DNA, RNA, or even now
and again a set number of compounds
qualities of viruses
They are encased in a defensive envelope.
They have spikes, which helps them to join to the host cell.
They are non cell.
They don\'t breathe, don\'t metabolize and don\'t develop yet they do recreate.
They contain a protein coat called the capsid.
They have a nucleic corrosive center containing DNA or RNA.
Ribosomes and catalysts are missing, which are required for digestion system.
They are viewed as both as living and non living things, as infections are idle when they are
available outside of host cells and are dynamic in side of host cells. As they make utilization of
crude materials and proteins of the host cell to imitate and causes a few diseases.
In development, infections are a vital method for flat quality exchange, which increments
hereditary differences. Infections are considered by some to be a living thing, since they convey
hereditary material, replicate, and develop through characteristic choice..
Infections are essential to the investigation of atomic and cell science as they give basic
frameworks that can be utilized to control and research the elements of cells.[235] The study and
utilization of infections have given important data about parts of cell biology.[236] For instance,
infections have been valuable in the investi.
Water will tend to flow in the direction from B to A until equilibri.pdf
Water will tend to flow in the direction from B to A until equilibrium is reached. As we know
AlCl3 is ionic compond where ethyl alcohal has very less ionic character thus water will tend to
flow in direction where it can interact with Al3+ and forms a complex where Al is surrounded by
6 O atoms and Cl by H, Thus stablishing the solution wheras in ethyl alcohal there is very less
ionic character thus water wont prefer itself on side B.
Solution
Water will tend to flow in the direction from B to A until equilibrium is reached. As we know
AlCl3 is ionic compond where ethyl alcohal has very less ionic character thus water will tend to
flow in direction where it can interact with Al3+ and forms a complex where Al is surrounded by
6 O atoms and Cl by H, Thus stablishing the solution wheras in ethyl alcohal there is very less
ionic character thus water wont prefer itself on side B..
To the given post option d is correct answer.The reason is tha.pdf
To the given post option \"d\" is correct answer.
The reason is that added the salt to BaSO4 the solubility get increased .
in the second case ammonia will react with water form ammoniumhydroxide later it dissociated
as ammonium ion and hydroxide ion . So H+ ion concentration will decreased.
Solution
To the given post option \"d\" is correct answer.
The reason is that added the salt to BaSO4 the solubility get increased .
in the second case ammonia will react with water form ammoniumhydroxide later it dissociated
as ammonium ion and hydroxide ion . So H+ ion concentration will decreased..
The von Neumann architecture describes a general framework, or struc.pdf
The von Neumann architecture describes a general framework, or structure, that a computer\'s
hardware,programming, and data should follow. It is an abstract model for computer
architecture: it assumes that execution work by decoding an instruction then getting the operands
and computing the result then also writing the result back to memory and finally it will repeat
these thinsg again and again. So he has given a very simple structure without the actual
implementations. So the whole computer is to two be divided in main 4 parts which actually are
the 4 funtions that a computer will do i.e. it will have to take input so input devices, then it will
do some processing hence the CPU then this result might be stored in Memory or given as output
to Output devices. So by this architeture anyone can understand basic computer.
Solution
The von Neumann architecture describes a general framework, or structure, that a computer\'s
hardware,programming, and data should follow. It is an abstract model for computer
architecture: it assumes that execution work by decoding an instruction then getting the operands
and computing the result then also writing the result back to memory and finally it will repeat
these thinsg again and again. So he has given a very simple structure without the actual
implementations. So the whole computer is to two be divided in main 4 parts which actually are
the 4 funtions that a computer will do i.e. it will have to take input so input devices, then it will
do some processing hence the CPU then this result might be stored in Memory or given as output
to Output devices. So by this architeture anyone can understand basic computer..
The oxide is ionic if there is charge transfer from one atom to anot.pdf
The oxide is ionic if there is charge transfer from one atom to another, i.e. when the
electronegativity difference is large between O and the other element. This is the case for metals
like Mg and Li.
The oxide is molecular if the atoms share electrons equally, i.e. when the electronegativity
difference is small between O and the other element. This is the case for the nonmetals like S, P,
N and Xe.
Solution
The oxide is ionic if there is charge transfer from one atom to another, i.e. when the
electronegativity difference is large between O and the other element. This is the case for metals
like Mg and Li.
The oxide is molecular if the atoms share electrons equally, i.e. when the electronegativity
difference is small between O and the other element. This is the case for the nonmetals like S, P,
N and Xe..
Ques-1 How does silica get into the macrophages what type of coat .pdf
Ques-1: How does silica get into the macrophages? what type of coat do you expect on the
vesicles?
Answer: Silicosis: Alveolar macrophages have associated with presence of \"surface scavanger
receptors-A\" to recognize silica particle and these particles are going to form \"a non-opsonized
coat\" on the surface of macrophages and FCR- mediated uptake. This coat formation is
completely depends on “the negatively changed ligands of silica particles” & it is carried into the
cell via activation of Rac and RhoA GTPases & IP3. This non-opsonized silica uptake into the
cell is going to trigger phagosome formation by the lysosomal vesicles to mediate denaturation
but failure of cell to denaturate it finally result in lysis of phagolysosomal membranes to leak the
internal contents into the cytosplasm
Ques-2:
The silica particles inside the lysosome to from a endolysosome-to-phagosome fusion finally
trigger leakage of internal contents into the cytoplasm of macrophages in alveoli of lung. These
events are followed by activation of mitochondria hyperpolarization signaling pathway finally
result in \"generation of caspase-9 and -3\" as a result apoptosis or cell death even the patient is
not working in the coal mine
Solution
Ques-1: How does silica get into the macrophages? what type of coat do you expect on the
vesicles?
Answer: Silicosis: Alveolar macrophages have associated with presence of \"surface scavanger
receptors-A\" to recognize silica particle and these particles are going to form \"a non-opsonized
coat\" on the surface of macrophages and FCR- mediated uptake. This coat formation is
completely depends on “the negatively changed ligands of silica particles” & it is carried into the
cell via activation of Rac and RhoA GTPases & IP3. This non-opsonized silica uptake into the
cell is going to trigger phagosome formation by the lysosomal vesicles to mediate denaturation
but failure of cell to denaturate it finally result in lysis of phagolysosomal membranes to leak the
internal contents into the cytosplasm
Ques-2:
The silica particles inside the lysosome to from a endolysosome-to-phagosome fusion finally
trigger leakage of internal contents into the cytoplasm of macrophages in alveoli of lung. These
events are followed by activation of mitochondria hyperpolarization signaling pathway finally
result in \"generation of caspase-9 and -3\" as a result apoptosis or cell death even the patient is
not working in the coal mine.
Scenario 1 1) Dec 31st Profit & loss Appropriation reserves Acco.pdf
Scenario 1 :
1) Dec 31st Profit & loss Appropriation/ reserves Account Dr $1 / share
To Proposed Dividend $ 1/ share
2) 20th Jan Proposed dividend Account Dr $ 1/ share
To Bank $ 1/ share
Scenario 2:
1) Dec 31st Profit & loss Appropriation/ reserves Account Dr $5 / share
To Proposed Dividend $ 5/ share
2) 20th Jan Proposed dividend Account Dr $ 5/ share
To Bank $ 5/ share
Notes:
Dividend is the source of income of shareholders when they invest money in shares for gaining
the dividend. On the other hand, when company declares the dividend for shareholder, it will be
the deduction of its net profit. For transferring dividend out of net profit, we make the profit and
loss appropriation account.
Following are the journal entries of dividends
1. When dividend is proposed by company out of net profit.
Profit and Loss Appropriation Account Debit
Proposed Dividend Account Credit
2. When Proposed dividend is paid by Company
Proposed Dividend Account Debit
Bank Account Credit
3. When Dividend is Declared Out of Retained Earning
Retained Earning Account Debit
Dividend Account Credit
4. When Such Dividend is Paid
Dividend Account Debit
Bank Account Credit
Examples :
Let’s assume that the Reliance Corporation, on Dec. 20, 2011, declared a cash dividend of Rs. 2
per share on 4,00,000 shares payable April 1, 2012, to all stockholders of record March 15. The
following journal entries are required:
1. Date of declaration, Dec. 20, 2011
Retained Earning Account Debit 8,00,000
Dividend Payable Account Credit 8,00,000
2. When dividend is paid on Date of payment, April 1, 2012
Dividend Payable Account Debit 8,00,000
Bank Account Credit 8,00,0000
Important : Sometime company may not have sufficient cash, at that time, company may give his
fully paid up new equity shares or other investments. So, we will not credit the bank account but
we will credit the equity share capital or investment.
Solution
Scenario 1 :
1) Dec 31st Profit & loss Appropriation/ reserves Account Dr $1 / share
To Proposed Dividend $ 1/ share
2) 20th Jan Proposed dividend Account Dr $ 1/ share
To Bank $ 1/ share
Scenario 2:
1) Dec 31st Profit & loss Appropriation/ reserves Account Dr $5 / share
To Proposed Dividend $ 5/ share
2) 20th Jan Proposed dividend Account Dr $ 5/ share
To Bank $ 5/ share
Notes:
Dividend is the source of income of shareholders when they invest money in shares for gaining
the dividend. On the other hand, when company declares the dividend for shareholder, it will be
the deduction of its net profit. For transferring dividend out of net profit, we make the profit and
loss appropriation account.
Following are the journal entries of dividends
1. When dividend is proposed by company out of net profit.
Profit and Loss Appropriation Account Debit
Proposed Dividend Account Credit
2. When Proposed dividend is paid by Company
Proposed Dividend Account Debit
Bank Account Credit
3. When Dividend is Declared Out of Retained Earning
Retained Earning Account Debit
Dividend Account Credi.
Please follow the data and description 20)Information richness .pdf
Please follow the data and description :
20)
Information richness :
It can be defined as the amount of detail contained in a piece of textual, graphic, audio, or any
video information. So the answer is OPTION C (Information richness).
21)
E-business and e-commerce are terms that are sometimes used interchangeably, and sometimes
they\'re used to differentiate one vendor\'s product from another. But the terms are different, and
that difference matters to today\'s companies.
So the answer is OPTION A (True).
22)
Operational plans sit at the bottom of the totem pole; they are the plans that are made by
frontline, or low-level, managers. So this can be managed and eleated at this level to make the
enhancements over the course period.
So the answer is OPTION B (False).
23)
WaterFall Model :
The waterfall model is a sequential design process, that are used in the software development
processes, in which the progress is seen as flowing steadily downwards like a waterfall or could
be considered as the stair case with the steps through the phases of conception, initiation,
analysis, design, construction, testing, production/implementation and maintenance.
So the answer is OPTION B (WaterFall Model).
24)
Mid-level management level :
Middle management is the intermediate management of a hierarchical organization that is
subordinate to the executive management and responsible for at least two lower levels of junior
staff. Their main duty is to implement the company strategy in the most efficient way. Their
duties include creating effective working environment, administrating the work process, making
sure it is compliant with organization\'s requirements, leading people and reporting to the highest
level of management.
So the answer is OPTION B (Mid-level management level).
25)
The basic reasons for the growth of decision-making systems include some of the situations like
the large amounts of informations and and this makes the user or the people to make the
decisions more quickly to be in the pace of th information. This also provides us with the ability
to forecast for the future decisions and its making.
So the answer is OPTION C (All Of the Above).
26)
Supply chain management :
The first stage, is the planning, is fairly self-explanatory. Company executives and managers
develop strategies to manage resources for timely product delivery. Metrics should be developed
to monitor progress and compliance. Choosing the suppliers is the next step. Managers are
responsible for developing a system for pricing, delivery and payment. Then there\'s
manufacturing - the third phase. During this step, the manager schedules activities necessary for
production, testing, packaging and preparation for delivery of goods or services to customers.
So the answer is OPTION B (Supply chain management).
27)
The form of reports may be of any form in the detailed version like the spreadsheets,
summarized data and histograms. So the answer is OPTION D (All of the Above).
28)
Gantt .
Mass of water = volume x density= 22.0 x 1.00 = 22.0 gMass of so.pdf
Mass of water = volume x density
= 22.0 x 1.00 = 22.0 g
Mass of solution = mass of water + mass of X
= 22.0 + 2.30 = 24.3 g
Heat released by reaction = heat absorbed by solution
= mass x specific heat x temperature change of solution
= 24.3 x 4.18 x (25.5 - 12.0)
= 1371.249 J
Moles of X = mass/molar mass of X
= 2.30/56.0 = 0.04107 mol
H = -heat released by reaction/moles of X
= -1371.249/0.04107
= -3.34 x 104 J/mol = -33.4 kJ/mol
Note that H is negative as reaction is exothermic and heat is released
Solution
Mass of water = volume x density
= 22.0 x 1.00 = 22.0 g
Mass of solution = mass of water + mass of X
= 22.0 + 2.30 = 24.3 g
Heat released by reaction = heat absorbed by solution
= mass x specific heat x temperature change of solution
= 24.3 x 4.18 x (25.5 - 12.0)
= 1371.249 J
Moles of X = mass/molar mass of X
= 2.30/56.0 = 0.04107 mol
H = -heat released by reaction/moles of X
= -1371.249/0.04107
= -3.34 x 104 J/mol = -33.4 kJ/mol
Note that H is negative as reaction is exothermic and heat is released.
Molar weight of weight of iron= 55.847 gmol heat capcity Ciron=Ci.pdf
Molar weight of weight of iron= 55.847 g/mol
heat capcity Ciron=Ci=25.19j/mol-c
=25.19/55.847 =0.451 j/g-c
heat capacity of water Cw=4.186 j/g-c
14.3 ml of water=14.3 g
Hvapourisation=2.257 j/g
Hv=2.257*14.3=32.27 j
MiCiTi=MwCwTw+Hvapourisatiovn
Tw=100-30=70
1250*0.451*Ti=14.3*4.186*70+32.27
563.75Ti=4222.456
Ti=7.49 Celcius
Solution
Molar weight of weight of iron= 55.847 g/mol
heat capcity Ciron=Ci=25.19j/mol-c
=25.19/55.847 =0.451 j/g-c
heat capacity of water Cw=4.186 j/g-c
14.3 ml of water=14.3 g
Hvapourisation=2.257 j/g
Hv=2.257*14.3=32.27 j
MiCiTi=MwCwTw+Hvapourisatiovn
Tw=100-30=70
1250*0.451*Ti=14.3*4.186*70+32.27
563.75Ti=4222.456
Ti=7.49 Celcius.
Market value of portfolio as at Dec 31,2011 will be =Starting value.pdf
Market value of portfolio as at Dec 31,2011 will be =Starting
value*(1+rate)^period=100000*(1+6%)^7= $ 150,363
Solution
Market value of portfolio as at Dec 31,2011 will be =Starting
value*(1+rate)^period=100000*(1+6%)^7= $ 150,363.
E. 20.0 total mass of 1L solution = 1.0263 x 10.pdf
E. 20.0% total mass of 1L solution = 1.0263 x 1000 = 1026.3 g mass of acetic acid
=60.05 x3.42 = 205.371 g mass % acetic acid = 205.371 x100 /1026.3 =20.01 %
Solution
E. 20.0% total mass of 1L solution = 1.0263 x 1000 = 1026.3 g mass of acetic acid
=60.05 x3.42 = 205.371 g mass % acetic acid = 205.371 x100 /1026.3 =20.01 %.
ISYSIt was founded in the year 1988 by Ian davies,and it is a searc.pdf
ISYS:It was founded in the year 1988 by Ian davies,and it is a search software of australian
based company which competes with google search engine for searching services. ISYS has its
infrastructure and its embedded search applications compete for fast search and transfer.
In 2009 ISYS released much more new applications and a new suite for access of
information.This has the ability to search multiple data sources like Microsoft office, HTML
files, Zip files,necessary email products,SQL based concepts.It is emerging in business
outsourcing.In 2007 it entered the linux market.
In 2012 ISYS was take overed by lexmarx international.It has its searches related to navigation,
relavance ranking,parametric search,multiple query methods.
Solution
ISYS:It was founded in the year 1988 by Ian davies,and it is a search software of australian
based company which competes with google search engine for searching services. ISYS has its
infrastructure and its embedded search applications compete for fast search and transfer.
In 2009 ISYS released much more new applications and a new suite for access of
information.This has the ability to search multiple data sources like Microsoft office, HTML
files, Zip files,necessary email products,SQL based concepts.It is emerging in business
outsourcing.In 2007 it entered the linux market.
In 2012 ISYS was take overed by lexmarx international.It has its searches related to navigation,
relavance ranking,parametric search,multiple query methods..
In this case, Jayne had some other artfull skill which were inherent.pdf
In this case, Jayne had some other artfull skill which were inherent to her but she chose to
become a physician as she was influenced by her parents and siblings. Presence of her parents
and siblings made her choose a profession which she would not have in general against her
inherent personality. This suggests that there was a sort of confusion in her mind regarding her
decision and she might have passed through stage of identity crisis/moratorium in search for her
own identity. Althoug influenced, she found her own one and practised it thenafter.
This feature shows that the status of Jayne was that of identity foreclosure as she was in search
for her identity and followed the cues and influences from others to make up her own.
Solution
In this case, Jayne had some other artfull skill which were inherent to her but she chose to
become a physician as she was influenced by her parents and siblings. Presence of her parents
and siblings made her choose a profession which she would not have in general against her
inherent personality. This suggests that there was a sort of confusion in her mind regarding her
decision and she might have passed through stage of identity crisis/moratorium in search for her
own identity. Althoug influenced, she found her own one and practised it thenafter.
This feature shows that the status of Jayne was that of identity foreclosure as she was in search
for her identity and followed the cues and influences from others to make up her own..
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KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
Palestine last event orientationfvgnh .pptx
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
CACJapan - GROUP Presentation 1- Wk 4.pdf
Macroeconomics- Movie Location
This will be used as part of your Personal Professional Portfolio once graded.
Objective:
Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Protectable subject matters, Protection in biotechnology, Protection of other biological materials, Ownership and period of protection
Synthetic Fiber Construction in lab .pptx
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.Recently uploaded (20)
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
BÀI TẬP BỔ TRỢ TIẾNG ANH GLOBAL SUCCESS LỚP 3 - CẢ NĂM (CÓ FILE NGHE VÀ ĐÁP Á...
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI fund...
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
The answer is b) water decomposes firstThe standard oxidation pot.pdf
- 1. The answer is: b) water decomposes first The standard oxidation potentials are: 2 F- => F2 + 2 e-, E(oxidation) = -2.87 V 2 H2O => O2 + 4 H+ + 4 e-, E(oxidation) = -1.23 V Since H2O has a less negative oxidation potential, it is oxidized more easily than F-. Thus when a solution of F- ions in H2O is electrolyzed, the H2O will decompose first into O2 and H+, while the F- ions remain unreacted. Solution The answer is: b) water decomposes first The standard oxidation potentials are: 2 F- => F2 + 2 e-, E(oxidation) = -2.87 V 2 H2O => O2 + 4 H+ + 4 e-, E(oxidation) = -1.23 V Since H2O has a less negative oxidation potential, it is oxidized more easily than F-. Thus when a solution of F- ions in H2O is electrolyzed, the H2O will decompose first into O2 and H+, while the F- ions remain unreacted.