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Today’s session will begin shortly
@tescometering
@TESCO_Metering
TESCO -The Eastern Specialty Company
TESCO -The Eastern Specialty Company
TESCO
Tuesdays
Meter Testing
by Form
Prepared by John Williams, TESCO
The Eastern Specialty Company
For TESCO Tuesday
Tuesday, February 8, 2021
11:00 a.m. – 12:00 p.m.
Introduction
Today we are going to review how testing is performed on various
meter forms and why.
We will discuss the following:
• Background on meter testing – Phantom loads, Voltage and Current
Generation
• Self-Contained vs Transformer-Rated meters
• Single Phase vs Series Parallel vs “True” 3 phase testers
• Applications of testers to different meter forms
…but first, let’s learn about polyphase metering and Blondel’s Theorem
3
Three Phase Power
Blondel’s Theorem
The theory of polyphase watthour metering was first set forth on a scientific
basis in 1893 by Andre E. Blondel, engineer and mathematician. His theorem
applies to the measurement of real power in a polyphase system of any
number of wires. The theorem is as follows:
- If energy is supplied to any system of conductors
through N wires, the total power in the system is given
by the algebraic sum of the readings of N wattmeters, so
arranged that each of the N wires contains one current
coil, the corresponding voltage coil being connected
between that wire and some common point. If this
common point is on one of the N wires, the
measurement may be made by the use of N-1
wattmeters.
4
Three Phase Power
Blondel’s Theorem
• Simply – We can measure the power in a
N wire system by measuring the power in
N-1 conductors.
• For example, in a 4-wire, 3-phase system
we need to measure the power in 3
circuits.
5
Three Phase Power
Blondel’s Theorem
• If a meter installation meets Blondel’s
Theorem then we will get accurate power
measurements under all circumstances.
• If a metering system does not meet
Blondel’s Theorem then we will only get
accurate measurements if certain
assumptions are met.
6
Blondel’s Theorem
• Three wires
• Two voltage measurements with
one side common to Line 2
• Current measurements on lines
1 & 3.
This satisfies Blondel’s
Theorem.
7
Blondel’s Theorem
• Four wires
• Two voltage measurements to
neutral
• Current measurements on lines 1 &
3. How about line 2?
This DOES NOT satisfy Blondel’s
Theorem.
8
Blondel’s Theorem
• In the previous example:
– What are the “ASSUMPTIONS”?
– When do we get errors?
• What would the “Right Answer” be?
• What did we measure?
)
cos(
)
cos(
)
cos( c
c
c
b
b
b
a
a
a
sys I
V
I
V
I
V
P θ
θ
θ +
+
=
)]
cos(
)
cos(
[
)]
cos(
)
cos(
[ b
b
c
c
c
b
b
a
a
a
sys I
I
V
I
I
V
P θ
θ
θ
θ −
+
−
=
9
Blondel’s Theorem
• Phase B power would be:
– P = Vb Ib cosθ
• But we aren’t measuring Vb
• What we are measuring is:
– IbVacos(60- θ) + IbVccos(60+ θ)
• cos(α + β) = cos(α)cos(β) - sin(α)sin(β)
• cos(α - β) = cos(α)cos(β) + sin(α)sin(β)
• So
10
Blondel’s Theorem
• Pb = Ib Va cos(60- θ) + Ib Vc cos(60+ θ)
• Applying the trig identity
– IbVa(cos(60)cos(θ) + sin(60)sin(θ))
IbVc (cos(60)cos(θ) - sin(60)sin(θ))
– Ib(Va+Vc)0.5cos(θ) + Ib(Vc-Va) 0.866sin(θ)
• Assuming
– Assume Vb = Va = Vc
– And, they are exactly 120° apart
• Pb = Ib(2Vb)(0.5cosθ) = IbVbcosθ
11
Blondel’s Theorem
• If Va ≠ Vb ≠ Vc then the error is
• %Error =
-Ib{(Va+Vc)/(2Vb) - (Va-Vc) 0.866sin(θ)/(Vbcos(θ))
How big is this in reality? If
Va=117, Vb=120, Vc=119, PF=1 then E=-1.67%
Va=117, Vb=116, Vc=119, PF=.866 then E=-1.67%
12
Blondel’s Theorem
Condition % V % I Phase A Phase B
non-
Blondel
Imb Imb V φvan I φian V φvbn I φibn
% Err
All balanced 0 0 120 0 100 0 120 180 100 180 0.00%
Unbalanced voltages PF=1 18% 0% 108 0 100 0 132 180 100 180 0.00%
Unbalanced current PF=1 0% 18% 120 0 90 0 120 180 110 180 0.00%
Unbalanced V&I PF=1 5% 18% 117 0 90 0 123 180 110 180 -0.25%
Unbalanced V&I PF=1 8% 18% 110 0 90 0 120 180 110 180 -0.43%
Unbalanced V&I PF=1 8% 50% 110 0 50 0 120 180 100 180 -1.43%
Unbalanced V&I PF=1 18% 40% 108 0 75 0 132 180 125 180 -2.44%
Unbalanced voltages
PF≠1 PFa = PFb
18% 0% 108 0 100 30 132 180 100 210 0.00%
Unbalanced current
PF≠1 PFa = PFb
0% 18% 120 0 90 30 120 180 110 210 0.00%
Unbalanced V&I
PF≠1 PFa = PFb
18% 18% 108 0 90 30 132 180 110 210 -0.99%
Unbalanced V&I
PF≠1 PFa = PFb
18% 40% 108 0 75 30 132 180 125 210 -2.44%
Unbalanced voltages
PF≠1 PFa ≠ PFb
18% 0% 108 0 100 60 132 180 100 210 -2.61%
Unbalanced current
PF≠1 PFa ≠ PFb
0% 18% 120 0 90 60 120 180 110 210 0.00%
Unbalanced V&I
PF≠1 PFa ≠ PFb
18% 18% 108 0 90 60 132 180 110 210 -3.46%
Unbalanced V&I
PF≠1 PFa ≠ PFb
18% 40% 108 0 75 60 132 180 125 210 -4.63%
Power Measurements Handbook
13
Phantom Power
• In order to test a revenue grade meter to ANSI C12 specifications,
the test board will have to power each of the voltage and current
elements of the meter at rated test voltage (TV) and rated test
current (TA).
• Let’s take a typical form 1S meter, for instance. It’s TV is 120V and
TA is 10A. Without employing phantom loading, the test board would
have to consume at least 1200W. Using phantom power, the test
board would only consume about 150W
• Phantom Power separates the voltage and the current into two
separate sources; High voltage @ low current and high current @
low voltage.
• From the meter’s point of view, it doesn’t know the difference, but
the test board will consume far less energy over the course of a
year.
14
Phantom Power
• Voltage and Current Generation:
– In most modern meter board equipment, the phantom potential and
current start with a processor that creates a micro-stepped low-level
sine-wave output.
– That output is fed into an amplifier circuit that is the first stage in the
amplification.
– The output of the amplifier is then fed into a step-up transformer that
takes the amplitude to the level that is seen by the meter.
15
Phantom Power
• SeriesParallel Phantom power:
– This term refers to the application of single phase power to polyphase
meters
– The potential is wired in parallel to each voltage coil in the meter
– The current is wired in series through the primaries of the current
transformers.
16
Form 1S – Real Power
17
Form 1S – Phantom Power
18
Form 2S – Real Power
19
Form 2S – Phantom Power
20
Form 3S – Real Power
21
Form 3S – Phantom Power
22
Form 4S – Real Power
23
Form 4S – Phantom Power
24
Form 5S – Real Power
25
Form 5S – Phantom Power
26
Form 6S – Real Power
27
Form 6S – Phantom Power
28
Form 8S – Real Power
29
Form 8S – Phantom Power
30
Form 9S – Real Power
31
Form 9S – Phantom Power
32
Form 12S – Real Power
33
Form 12S – Phantom Power
34
Form 14S – Real Power
35
Form 14S – Phantom Power
36
Form 15S – Real Power
37
Form 15S – Phantom Power
38
Form 16S – Real Power
39
Form 16S – Phantom Power
40
Questions and Discussion
John Williams
john.williams@tescometering.com
TESCO – The Eastern Specialty Company
Bristol, PA
215-228-0500
www.tescometering.com
Thanks for tuning in!
See you at the next session.
Upcoming Session:
Metering Configurations
February 2, 2021 | 11:00 AM Eastern
**TESCO Users Group: July 18-21, 2021**
Presentation Date
Test Switch Operations and Hot Sockets 2/16
Meter Testing in the Field 2/23
Transformer-Rated Testing Using Pickups and Probes 3/2
Traditional Ratio, Burden, Admittance and Demag Testing – Part 1 3/9
Traditional Ratio, Burden, Admittance and Demag Testing – Part 2 3/16
Realizing Your Investment in Technology Through Analytics 3/23
Shop Testing 3/30
Preparing for AMI Deployment 4/6
Communication Equipment 4/13
Sign up: tescometering.com/tesco-tuesdays

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TESCO Tuesday: Metering Testing by Form

  • 1. Today’s session will begin shortly @tescometering @TESCO_Metering TESCO -The Eastern Specialty Company TESCO -The Eastern Specialty Company TESCO Tuesdays
  • 2. Meter Testing by Form Prepared by John Williams, TESCO The Eastern Specialty Company For TESCO Tuesday Tuesday, February 8, 2021 11:00 a.m. – 12:00 p.m.
  • 3. Introduction Today we are going to review how testing is performed on various meter forms and why. We will discuss the following: • Background on meter testing – Phantom loads, Voltage and Current Generation • Self-Contained vs Transformer-Rated meters • Single Phase vs Series Parallel vs “True” 3 phase testers • Applications of testers to different meter forms …but first, let’s learn about polyphase metering and Blondel’s Theorem 3
  • 4. Three Phase Power Blondel’s Theorem The theory of polyphase watthour metering was first set forth on a scientific basis in 1893 by Andre E. Blondel, engineer and mathematician. His theorem applies to the measurement of real power in a polyphase system of any number of wires. The theorem is as follows: - If energy is supplied to any system of conductors through N wires, the total power in the system is given by the algebraic sum of the readings of N wattmeters, so arranged that each of the N wires contains one current coil, the corresponding voltage coil being connected between that wire and some common point. If this common point is on one of the N wires, the measurement may be made by the use of N-1 wattmeters. 4
  • 5. Three Phase Power Blondel’s Theorem • Simply – We can measure the power in a N wire system by measuring the power in N-1 conductors. • For example, in a 4-wire, 3-phase system we need to measure the power in 3 circuits. 5
  • 6. Three Phase Power Blondel’s Theorem • If a meter installation meets Blondel’s Theorem then we will get accurate power measurements under all circumstances. • If a metering system does not meet Blondel’s Theorem then we will only get accurate measurements if certain assumptions are met. 6
  • 7. Blondel’s Theorem • Three wires • Two voltage measurements with one side common to Line 2 • Current measurements on lines 1 & 3. This satisfies Blondel’s Theorem. 7
  • 8. Blondel’s Theorem • Four wires • Two voltage measurements to neutral • Current measurements on lines 1 & 3. How about line 2? This DOES NOT satisfy Blondel’s Theorem. 8
  • 9. Blondel’s Theorem • In the previous example: – What are the “ASSUMPTIONS”? – When do we get errors? • What would the “Right Answer” be? • What did we measure? ) cos( ) cos( ) cos( c c c b b b a a a sys I V I V I V P θ θ θ + + = )] cos( ) cos( [ )] cos( ) cos( [ b b c c c b b a a a sys I I V I I V P θ θ θ θ − + − = 9
  • 10. Blondel’s Theorem • Phase B power would be: – P = Vb Ib cosθ • But we aren’t measuring Vb • What we are measuring is: – IbVacos(60- θ) + IbVccos(60+ θ) • cos(α + β) = cos(α)cos(β) - sin(α)sin(β) • cos(α - β) = cos(α)cos(β) + sin(α)sin(β) • So 10
  • 11. Blondel’s Theorem • Pb = Ib Va cos(60- θ) + Ib Vc cos(60+ θ) • Applying the trig identity – IbVa(cos(60)cos(θ) + sin(60)sin(θ)) IbVc (cos(60)cos(θ) - sin(60)sin(θ)) – Ib(Va+Vc)0.5cos(θ) + Ib(Vc-Va) 0.866sin(θ) • Assuming – Assume Vb = Va = Vc – And, they are exactly 120° apart • Pb = Ib(2Vb)(0.5cosθ) = IbVbcosθ 11
  • 12. Blondel’s Theorem • If Va ≠ Vb ≠ Vc then the error is • %Error = -Ib{(Va+Vc)/(2Vb) - (Va-Vc) 0.866sin(θ)/(Vbcos(θ)) How big is this in reality? If Va=117, Vb=120, Vc=119, PF=1 then E=-1.67% Va=117, Vb=116, Vc=119, PF=.866 then E=-1.67% 12
  • 13. Blondel’s Theorem Condition % V % I Phase A Phase B non- Blondel Imb Imb V φvan I φian V φvbn I φibn % Err All balanced 0 0 120 0 100 0 120 180 100 180 0.00% Unbalanced voltages PF=1 18% 0% 108 0 100 0 132 180 100 180 0.00% Unbalanced current PF=1 0% 18% 120 0 90 0 120 180 110 180 0.00% Unbalanced V&I PF=1 5% 18% 117 0 90 0 123 180 110 180 -0.25% Unbalanced V&I PF=1 8% 18% 110 0 90 0 120 180 110 180 -0.43% Unbalanced V&I PF=1 8% 50% 110 0 50 0 120 180 100 180 -1.43% Unbalanced V&I PF=1 18% 40% 108 0 75 0 132 180 125 180 -2.44% Unbalanced voltages PF≠1 PFa = PFb 18% 0% 108 0 100 30 132 180 100 210 0.00% Unbalanced current PF≠1 PFa = PFb 0% 18% 120 0 90 30 120 180 110 210 0.00% Unbalanced V&I PF≠1 PFa = PFb 18% 18% 108 0 90 30 132 180 110 210 -0.99% Unbalanced V&I PF≠1 PFa = PFb 18% 40% 108 0 75 30 132 180 125 210 -2.44% Unbalanced voltages PF≠1 PFa ≠ PFb 18% 0% 108 0 100 60 132 180 100 210 -2.61% Unbalanced current PF≠1 PFa ≠ PFb 0% 18% 120 0 90 60 120 180 110 210 0.00% Unbalanced V&I PF≠1 PFa ≠ PFb 18% 18% 108 0 90 60 132 180 110 210 -3.46% Unbalanced V&I PF≠1 PFa ≠ PFb 18% 40% 108 0 75 60 132 180 125 210 -4.63% Power Measurements Handbook 13
  • 14. Phantom Power • In order to test a revenue grade meter to ANSI C12 specifications, the test board will have to power each of the voltage and current elements of the meter at rated test voltage (TV) and rated test current (TA). • Let’s take a typical form 1S meter, for instance. It’s TV is 120V and TA is 10A. Without employing phantom loading, the test board would have to consume at least 1200W. Using phantom power, the test board would only consume about 150W • Phantom Power separates the voltage and the current into two separate sources; High voltage @ low current and high current @ low voltage. • From the meter’s point of view, it doesn’t know the difference, but the test board will consume far less energy over the course of a year. 14
  • 15. Phantom Power • Voltage and Current Generation: – In most modern meter board equipment, the phantom potential and current start with a processor that creates a micro-stepped low-level sine-wave output. – That output is fed into an amplifier circuit that is the first stage in the amplification. – The output of the amplifier is then fed into a step-up transformer that takes the amplitude to the level that is seen by the meter. 15
  • 16. Phantom Power • SeriesParallel Phantom power: – This term refers to the application of single phase power to polyphase meters – The potential is wired in parallel to each voltage coil in the meter – The current is wired in series through the primaries of the current transformers. 16
  • 17. Form 1S – Real Power 17
  • 18. Form 1S – Phantom Power 18
  • 19. Form 2S – Real Power 19
  • 20. Form 2S – Phantom Power 20
  • 21. Form 3S – Real Power 21
  • 22. Form 3S – Phantom Power 22
  • 23. Form 4S – Real Power 23
  • 24. Form 4S – Phantom Power 24
  • 25. Form 5S – Real Power 25
  • 26. Form 5S – Phantom Power 26
  • 27. Form 6S – Real Power 27
  • 28. Form 6S – Phantom Power 28
  • 29. Form 8S – Real Power 29
  • 30. Form 8S – Phantom Power 30
  • 31. Form 9S – Real Power 31
  • 32. Form 9S – Phantom Power 32
  • 33. Form 12S – Real Power 33
  • 34. Form 12S – Phantom Power 34
  • 35. Form 14S – Real Power 35
  • 36. Form 14S – Phantom Power 36
  • 37. Form 15S – Real Power 37
  • 38. Form 15S – Phantom Power 38
  • 39. Form 16S – Real Power 39
  • 40. Form 16S – Phantom Power 40
  • 41. Questions and Discussion John Williams john.williams@tescometering.com TESCO – The Eastern Specialty Company Bristol, PA 215-228-0500 www.tescometering.com
  • 42. Thanks for tuning in! See you at the next session. Upcoming Session: Metering Configurations February 2, 2021 | 11:00 AM Eastern **TESCO Users Group: July 18-21, 2021** Presentation Date Test Switch Operations and Hot Sockets 2/16 Meter Testing in the Field 2/23 Transformer-Rated Testing Using Pickups and Probes 3/2 Traditional Ratio, Burden, Admittance and Demag Testing – Part 1 3/9 Traditional Ratio, Burden, Admittance and Demag Testing – Part 2 3/16 Realizing Your Investment in Technology Through Analytics 3/23 Shop Testing 3/30 Preparing for AMI Deployment 4/6 Communication Equipment 4/13 Sign up: tescometering.com/tesco-tuesdays