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TTEERRMMOOQQUUÍÍMMIICCAA 
CCEEMM SSeettoorr LLeessttee 
CCllaarriiccee PPiinnhheeiirroo AAnnddrraaddee VViiaannaa 
AAnnáálliissee ddee ttrrooccaass ddee eenneerrggiiaa nnaa ffoorrmmaa ddee ccaalloorr nnaass 
rreeaaççõõeess qquuíímmiiccaass ee nnaass mmuuddaannççaass ddee eessttaaddoo ffííssiiccoo ddaa 
mmaattéérriiaa..
UUmm ppoouuccoo ddee hhiissttóórriiaa…… 
SSéécc..XXIIXX-- SSaaddii CCaarrnnoott ((11779966--1188322)):: 
ccaalloorr ccoonnssiiddeerraaddoo uumm fflluuííddoo((ccaallóórriiccoo)),, 
ttrraabbaallhhoo==fflluuxxoo ccaallóórriiccoo .. 
JJaammeess JJoouullee ::ccaalloorr ee ttrraabbaallhhoo ((ffoorrmmaass ddee 
eenneerrggiiaa eeqquuiivvaalleenntteess)) ccaappaazzeess ddee mmuuddaarr aa eenneerrggiiaa ddee 
uumm ssiisstteemmaa
CCaalloorr 
TTrraannssffeerrêênncciiaa ddee eenneerrggiiaa ttéérrmmiiccaa eennttrree ccoorrppooss qquuee 
ppoossssuueemm tteemmppeerraattuurraass ddiissttiinnttaass
CCaalloorr sseennssíívveell XX CCaalloorr llaatteennttee 
DDeetteerrmmiinnaaççããoo ddee qquuaannttiiddaaddee ddee eenneerrggiiaa ::UUssoo ddee uumm 
ccaalloorríímmeettrroo,, ppoorr eexxeemmpplloo ::
11 ccaalloorriiaa == qquuaannttiiddaaddee nneecceessssáárriiaa ppaarraa 
eelleevvaarr eemm 11 °°CC aa tteemmppeerraattuurraa ddee 11,,00 ggrraammaa 
ddee áágguuaa.. 
EExxeemmpplloo :: CCoonnssiiddeerraannddoo aa qquueeiimmaa ddee 11,,00 gg ddee 
aaççúúccaarr((CC1122HH2222OO1111)) eemm uumm ccaalloorríímmeettrroo qquuee ccoonntteennhhaa 11000000 
gg ddee áágguuaa aa uummaa tteemmppeerraattuurraa iinniicciiaall ddee 2200 °°CC,, sseennddoo qquuee 
aappóóss aa rreeaaççããoo ,, aa tteemmppeerraattuurraa ffiinnaall ddaa áágguuaa sseejjaa 2244 °°CC.. 
DDeetteerrmmiinnee oo vvaalloorr eennéérrggiiccoo ddoo aaççúúccaarr eemm KKJJ((kkiilloo jjoouullee)) 
..CCoonnssiiddeerree oo ccaalloorr eessppeecciiffiiccoo ddaa áágguuaa sseejjaa 11 ccaall//gg°°CC.. 
11 ccaall 44,,1188 JJ oouu 11KKccaall 44,,1188kkJJ 
QQ== mm xx cc xx ΔΔTT
OOccoorrrree ccoomm aa lliibbeerraaççããoo ddee ccaalloorr 
FFQQ:: CCHH44((gg))++ 22 OO22 ((gg))CCOO22((gg)) ++22HH22OO((vv))++ 888899,,55kkJJ 
FFFF:: HH22OO ((ll)) HH22OO((ss)) ++ 77,,3 kkJJ
OOccoorrrree ccoomm aabbssoorrççããoo ddee ccaalloorr 
FFQQ:: FFee22OO3((ss))++ 3CC((ss))++449911,,55 kkJJ 22 FFee((ss))++ 3 CCOO22((gg)) 
FFFF:: HH22OO((ll)) ++4444kkJJ HH22OO ((vv))
AATTEENNÇÇÃÃOO!! AA QQUUAANNTTIIDDAADDEE DDEE CCAALLOORR 
LLIIBBEERRAADDOO OOUU AABBSSOORRVVIIDDOO ÉÉ SSEEMMPPRREE 
PPRROOPPOORRCCIIOONNAALL ÀÀ QQUUAANNTTIIDDAADDEE DDAASS 
SSUUBBSSTTÂÂNNCCIIAASS EENNVVOOLLVVIIDDAASS..
EExxeemmpplloo :: 
AA ccoommbbuussttããoo ccoommpplleettaa ddee 11 mmooll ddee mmeettaannoo lliibbeerraa 773300 kkJJ 
ccoomm ffoorrmmaaççããoo ddee ggááss ccaarrbbôônniiccoo ee áágguuaa lliiqquuiiddaa .. 
((AA))EEssccrreevvaa aa eeqquuaaççããoo tteerrmmooqquuíímmiiccaa ddaa ccoommbbuussttããoo ddee 11 mmooll 
ddee mmeettaannoo 
((BB))CCaallccuullee aa mmaassssaa ddee mmeettaannoo nneecceessssáárriiaa ppaarraa pprroodduuzziirr 33880000 
kkJJ ddee ccaalloorr
EExxeemmpplloo :: 
AA ccoommbbuussttããoo ccoommpplleettaa ddee 11 mmooll ddee mmeettaannoo lliibbeerraa 773300 kkJJ ccoomm ffoorrmmaaççããoo 
ddee ggááss ccaarrbbôônniiccoo ee áágguuaa lliiqquuiiddaa .. 
((AA))EEssccrreevvaa aa eeqquuaaççããoo tteerrmmooqquuíímmiiccaa ddaa ccoommbbuussttããoo ddee 11 mmooll ddee mmeettaannoo 
CCHH44((ll))++ 22 OO22((gg))  CCOO22((gg)) ++ 22 HH22OO((ll)) ΔΔHH==--773300kkJJ 
((BB))CCaallccuullee aa mmaassssaa ddee mmeettaannoo nneecceessssáárriiaa ppaarraa pprroodduuzziirr 33880000 kkJJ ddee ccaalloorr 
1166 ((gg)) -------- 773300 KKJJ 
yy((gg)) ------------------ 33880000 KKJJ 
yy== 
MMMM==1166 gg//mmooll
Energia liberada qquuee eessttaavvaa ccoonnttiiddaa nnooss 
rreeaaggeenntteess 
SSee ooccoorrrree qquueeiimmaa((ccoommbbuussttããoo)) ,, oo 
rreeaaggeennttee eessttáá rreeaaggiinnddoo ccoomm oo ooxxiiggêênniioo 
ΔΔHH==HHpp((pprroodduuttooss))--HHrr((rreeaaggeenntteess)) 
ΔΔHH<<00 EExxoottéérrmmiiccaa ΔΔHH>>00 EEnnddoottéérrmmiiccaa
Quantidade necessária ddee ccaalloorr ppaarraa pprroovvooccaarr aa ffuussããoo ddee 
11 mmooll ddee uummaa ssuubbssttâânncciiaa ,, àà pprreessssããoo ccoonnssttaannttee == CCAALLOORR
Estado aammbbiieennttee== EEssttaaddoo ppaaddrrããoo== 
ffoorrmmaa ppuurraa ddee uummaa ssuubbssttâânncciiaa aa 2255 °°CC 
((229988kk)) ee 11 aattmm.. 
TTooddaa ssuubbssttâânncciiaa ssiimmpplleess,, nnoo eessttaaddoo 
ppaaddrrããoo ee nnaa ffoorrmmaa aalloottrróóppiiccaa mmaaiiss 
eessttáávveell ((++ccoommuumm)) tteemm eennttaallppiiaa iigguuaall 
aa ZZEERROO ((HH°°== 00))  HH22,, NN22,, FF22,, FFee,, AAll ,, 
HHgg,, CC ,, OO..
CCaalloorr lliibbeerraaddoo oouu aabbssoorrvviiddoo nnaa ffoorrmmaa ddee 11 
mmooll ddee uummaa ssuubbssttâânncciiaa aa ppaarrttiirr ddee 
ssuubbssttâânncciiaass ssiimmpplleess nnoo eessttaaddoo ppaaddrrããoo 
VVáárriiaass ssuubbssttâânncciiaass  11 ssuubbssttâânncciiaa 
CC((ggrraaffiittee))++ OO22((gg))  CCOO22((gg))
Energia liberado ou aabbssoorrvviiddaa nnaa ccoommbbuussttããoo ddee 11 mmooll ddee uummaa 
ssuubbssttâânncciiaa nnoo eessttaaddoo ppaaddrrããoo 
XX((gg)) ++ OO22((gg))  CCOO22((gg)) ++ HH22OO((ll))
EExxeemmpplloo 
ΔH (kJ/mol) 
ácido -160 
CO2 -394 
H2O -286 
*Calcule a entalpia de 
combustão completa 
padrão do ácido pent-3- 
enoico :
EExxeemmpplloo 
ΔH (kJ/mol) 
ácido -160 
CO2 -394 
H2O -286 
*Calcule a entalpia de 
combustão completa 
padrão do ácido pent-3- 
enoico : 
ΔH=Hp-Hr 
5(-394) + 4(-286)-(- 
160) = -2954kJ
Energia lliibbeerraaddaa oouu aabbssoorrvviiddaa ppaarraa QQUUEEBBRRAARR 11 mmooll ddee lliiggaaççõõeess nnoo EESSTTAADDOO 
GGAASSOOSSOO.. 
CCHH44((gg)) ++ 22 OO22 ((gg))  CCOO22((gg)) ++ 22 HH22OO((gg))
ΔΔHH == EEaa--EEll 
Ligaçao Energia da ligação 
H--H 436 
O--H 463 
C--C 348
ΔΔHH == EEaa--EEll 
ΔΔHH==22664422--33445522==--881100 kkJJ//mmooll 
Ligaçao Energia da ligação 
H--H 436 
O--H 463 
C--C 348
r Numa reeaaççããoo qquuíímmiiccaa oo ΔΔHH éé sseemmpprree oo 
mmeessmmoo ,, qquueerr eellaa ooccoorrrraa eemm uummaa eettaappaa oouu 
eemm vváárriiaass eettaappaass.. OO ΔΔHH ddeeppeennddee aappeennaass 
ddooss eessttaaddooss iinniicciiaall ee ffiinnaall .. 
ΔΔHH== ΣΣ ΔΔHH 
AA ppaarrttiirr ddee eeqquuaaççõõeess ““ffiillhhaass”” ccoonnsseegguuiimmooss iiddeennttiiffiiccaarr aa 
vvaarriiaaççããoo ddee eennttaallppiiaa ddaa eeqquuaaççããoo ““mmããee””
EExxeemmpplliiffiiccaannddoo...... 
EQUACOES ΔH 
(1) 2C(grafite)+ 2 O2(g)2 CO2(g) -788 kJ 
(2) 3H2(g)+3/2 O2(g)3H2O(l) -858 kJ 
(3) 2CO2(g)+3H2O(l)1 C2H6O(l) 
+3O2(g) 
+1368 kJ 
GLOBAL: ? ?
EExxeemmpplliiffiiccaannddoo...... 
EQUACOES ΔH 
(1) 2C(grafite)+ 2 O2(g)2 CO2(g) -788 kJ 
(2) 3H2(g)+3/2 O2(g)3H2O(l) -858 kJ 
(3) 2CO2(g)+3H2O(l)1 C2H6O(l) 
+3O2(g) 
+1368 kJ 
(G) 2C(garfite)+3H2(g)+1/2 
O2(g)1C2H6O(l) 
-278
W WE know Termoquímica
RReeffeerreenncciiaass 
BBiibblliiooggrrááffiiccaass 
UUssbbeerrccoo && SSaallvvaaddoorr,, ssaarraaiivvaa;;QQuuíímmiiccaa ((vvoolluummee 22--ffííssiiccoo-- 
qquuíímmiiccaa));;uunniiddaaddee 33;;ccaappiittuulloo 88 aaoo 1111.. 
IImmaaggeennss :: ggooooggllee

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Termoquímica - Setor Leste

  • 1. TTEERRMMOOQQUUÍÍMMIICCAA CCEEMM SSeettoorr LLeessttee CCllaarriiccee PPiinnhheeiirroo AAnnddrraaddee VViiaannaa AAnnáálliissee ddee ttrrooccaass ddee eenneerrggiiaa nnaa ffoorrmmaa ddee ccaalloorr nnaass rreeaaççõõeess qquuíímmiiccaass ee nnaass mmuuddaannççaass ddee eessttaaddoo ffííssiiccoo ddaa mmaattéérriiaa..
  • 2. UUmm ppoouuccoo ddee hhiissttóórriiaa…… SSéécc..XXIIXX-- SSaaddii CCaarrnnoott ((11779966--1188322)):: ccaalloorr ccoonnssiiddeerraaddoo uumm fflluuííddoo((ccaallóórriiccoo)),, ttrraabbaallhhoo==fflluuxxoo ccaallóórriiccoo .. JJaammeess JJoouullee ::ccaalloorr ee ttrraabbaallhhoo ((ffoorrmmaass ddee eenneerrggiiaa eeqquuiivvaalleenntteess)) ccaappaazzeess ddee mmuuddaarr aa eenneerrggiiaa ddee uumm ssiisstteemmaa
  • 3. CCaalloorr TTrraannssffeerrêênncciiaa ddee eenneerrggiiaa ttéérrmmiiccaa eennttrree ccoorrppooss qquuee ppoossssuueemm tteemmppeerraattuurraass ddiissttiinnttaass
  • 4. CCaalloorr sseennssíívveell XX CCaalloorr llaatteennttee DDeetteerrmmiinnaaççããoo ddee qquuaannttiiddaaddee ddee eenneerrggiiaa ::UUssoo ddee uumm ccaalloorríímmeettrroo,, ppoorr eexxeemmpplloo ::
  • 5. 11 ccaalloorriiaa == qquuaannttiiddaaddee nneecceessssáárriiaa ppaarraa eelleevvaarr eemm 11 °°CC aa tteemmppeerraattuurraa ddee 11,,00 ggrraammaa ddee áágguuaa.. EExxeemmpplloo :: CCoonnssiiddeerraannddoo aa qquueeiimmaa ddee 11,,00 gg ddee aaççúúccaarr((CC1122HH2222OO1111)) eemm uumm ccaalloorríímmeettrroo qquuee ccoonntteennhhaa 11000000 gg ddee áágguuaa aa uummaa tteemmppeerraattuurraa iinniicciiaall ddee 2200 °°CC,, sseennddoo qquuee aappóóss aa rreeaaççããoo ,, aa tteemmppeerraattuurraa ffiinnaall ddaa áágguuaa sseejjaa 2244 °°CC.. DDeetteerrmmiinnee oo vvaalloorr eennéérrggiiccoo ddoo aaççúúccaarr eemm KKJJ((kkiilloo jjoouullee)) ..CCoonnssiiddeerree oo ccaalloorr eessppeecciiffiiccoo ddaa áágguuaa sseejjaa 11 ccaall//gg°°CC.. 11 ccaall 44,,1188 JJ oouu 11KKccaall 44,,1188kkJJ QQ== mm xx cc xx ΔΔTT
  • 6. OOccoorrrree ccoomm aa lliibbeerraaççããoo ddee ccaalloorr FFQQ:: CCHH44((gg))++ 22 OO22 ((gg))CCOO22((gg)) ++22HH22OO((vv))++ 888899,,55kkJJ FFFF:: HH22OO ((ll)) HH22OO((ss)) ++ 77,,3 kkJJ
  • 7. OOccoorrrree ccoomm aabbssoorrççããoo ddee ccaalloorr FFQQ:: FFee22OO3((ss))++ 3CC((ss))++449911,,55 kkJJ 22 FFee((ss))++ 3 CCOO22((gg)) FFFF:: HH22OO((ll)) ++4444kkJJ HH22OO ((vv))
  • 8. AATTEENNÇÇÃÃOO!! AA QQUUAANNTTIIDDAADDEE DDEE CCAALLOORR LLIIBBEERRAADDOO OOUU AABBSSOORRVVIIDDOO ÉÉ SSEEMMPPRREE PPRROOPPOORRCCIIOONNAALL ÀÀ QQUUAANNTTIIDDAADDEE DDAASS SSUUBBSSTTÂÂNNCCIIAASS EENNVVOOLLVVIIDDAASS..
  • 9. EExxeemmpplloo :: AA ccoommbbuussttããoo ccoommpplleettaa ddee 11 mmooll ddee mmeettaannoo lliibbeerraa 773300 kkJJ ccoomm ffoorrmmaaççããoo ddee ggááss ccaarrbbôônniiccoo ee áágguuaa lliiqquuiiddaa .. ((AA))EEssccrreevvaa aa eeqquuaaççããoo tteerrmmooqquuíímmiiccaa ddaa ccoommbbuussttããoo ddee 11 mmooll ddee mmeettaannoo ((BB))CCaallccuullee aa mmaassssaa ddee mmeettaannoo nneecceessssáárriiaa ppaarraa pprroodduuzziirr 33880000 kkJJ ddee ccaalloorr
  • 10. EExxeemmpplloo :: AA ccoommbbuussttããoo ccoommpplleettaa ddee 11 mmooll ddee mmeettaannoo lliibbeerraa 773300 kkJJ ccoomm ffoorrmmaaççããoo ddee ggááss ccaarrbbôônniiccoo ee áágguuaa lliiqquuiiddaa .. ((AA))EEssccrreevvaa aa eeqquuaaççããoo tteerrmmooqquuíímmiiccaa ddaa ccoommbbuussttããoo ddee 11 mmooll ddee mmeettaannoo CCHH44((ll))++ 22 OO22((gg))  CCOO22((gg)) ++ 22 HH22OO((ll)) ΔΔHH==--773300kkJJ ((BB))CCaallccuullee aa mmaassssaa ddee mmeettaannoo nneecceessssáárriiaa ppaarraa pprroodduuzziirr 33880000 kkJJ ddee ccaalloorr 1166 ((gg)) -------- 773300 KKJJ yy((gg)) ------------------ 33880000 KKJJ yy== MMMM==1166 gg//mmooll
  • 11. Energia liberada qquuee eessttaavvaa ccoonnttiiddaa nnooss rreeaaggeenntteess SSee ooccoorrrree qquueeiimmaa((ccoommbbuussttããoo)) ,, oo rreeaaggeennttee eessttáá rreeaaggiinnddoo ccoomm oo ooxxiiggêênniioo ΔΔHH==HHpp((pprroodduuttooss))--HHrr((rreeaaggeenntteess)) ΔΔHH<<00 EExxoottéérrmmiiccaa ΔΔHH>>00 EEnnddoottéérrmmiiccaa
  • 12. Quantidade necessária ddee ccaalloorr ppaarraa pprroovvooccaarr aa ffuussããoo ddee 11 mmooll ddee uummaa ssuubbssttâânncciiaa ,, àà pprreessssããoo ccoonnssttaannttee == CCAALLOORR
  • 13. Estado aammbbiieennttee== EEssttaaddoo ppaaddrrããoo== ffoorrmmaa ppuurraa ddee uummaa ssuubbssttâânncciiaa aa 2255 °°CC ((229988kk)) ee 11 aattmm.. TTooddaa ssuubbssttâânncciiaa ssiimmpplleess,, nnoo eessttaaddoo ppaaddrrããoo ee nnaa ffoorrmmaa aalloottrróóppiiccaa mmaaiiss eessttáávveell ((++ccoommuumm)) tteemm eennttaallppiiaa iigguuaall aa ZZEERROO ((HH°°== 00))  HH22,, NN22,, FF22,, FFee,, AAll ,, HHgg,, CC ,, OO..
  • 14. CCaalloorr lliibbeerraaddoo oouu aabbssoorrvviiddoo nnaa ffoorrmmaa ddee 11 mmooll ddee uummaa ssuubbssttâânncciiaa aa ppaarrttiirr ddee ssuubbssttâânncciiaass ssiimmpplleess nnoo eessttaaddoo ppaaddrrããoo VVáárriiaass ssuubbssttâânncciiaass  11 ssuubbssttâânncciiaa CC((ggrraaffiittee))++ OO22((gg))  CCOO22((gg))
  • 15. Energia liberado ou aabbssoorrvviiddaa nnaa ccoommbbuussttããoo ddee 11 mmooll ddee uummaa ssuubbssttâânncciiaa nnoo eessttaaddoo ppaaddrrããoo XX((gg)) ++ OO22((gg))  CCOO22((gg)) ++ HH22OO((ll))
  • 16. EExxeemmpplloo ΔH (kJ/mol) ácido -160 CO2 -394 H2O -286 *Calcule a entalpia de combustão completa padrão do ácido pent-3- enoico :
  • 17. EExxeemmpplloo ΔH (kJ/mol) ácido -160 CO2 -394 H2O -286 *Calcule a entalpia de combustão completa padrão do ácido pent-3- enoico : ΔH=Hp-Hr 5(-394) + 4(-286)-(- 160) = -2954kJ
  • 18. Energia lliibbeerraaddaa oouu aabbssoorrvviiddaa ppaarraa QQUUEEBBRRAARR 11 mmooll ddee lliiggaaççõõeess nnoo EESSTTAADDOO GGAASSOOSSOO.. CCHH44((gg)) ++ 22 OO22 ((gg))  CCOO22((gg)) ++ 22 HH22OO((gg))
  • 19. ΔΔHH == EEaa--EEll Ligaçao Energia da ligação H--H 436 O--H 463 C--C 348
  • 20. ΔΔHH == EEaa--EEll ΔΔHH==22664422--33445522==--881100 kkJJ//mmooll Ligaçao Energia da ligação H--H 436 O--H 463 C--C 348
  • 21.
  • 22. r Numa reeaaççããoo qquuíímmiiccaa oo ΔΔHH éé sseemmpprree oo mmeessmmoo ,, qquueerr eellaa ooccoorrrraa eemm uummaa eettaappaa oouu eemm vváárriiaass eettaappaass.. OO ΔΔHH ddeeppeennddee aappeennaass ddooss eessttaaddooss iinniicciiaall ee ffiinnaall .. ΔΔHH== ΣΣ ΔΔHH AA ppaarrttiirr ddee eeqquuaaççõõeess ““ffiillhhaass”” ccoonnsseegguuiimmooss iiddeennttiiffiiccaarr aa vvaarriiaaççããoo ddee eennttaallppiiaa ddaa eeqquuaaççããoo ““mmããee””
  • 23. EExxeemmpplliiffiiccaannddoo...... EQUACOES ΔH (1) 2C(grafite)+ 2 O2(g)2 CO2(g) -788 kJ (2) 3H2(g)+3/2 O2(g)3H2O(l) -858 kJ (3) 2CO2(g)+3H2O(l)1 C2H6O(l) +3O2(g) +1368 kJ GLOBAL: ? ?
  • 24. EExxeemmpplliiffiiccaannddoo...... EQUACOES ΔH (1) 2C(grafite)+ 2 O2(g)2 CO2(g) -788 kJ (2) 3H2(g)+3/2 O2(g)3H2O(l) -858 kJ (3) 2CO2(g)+3H2O(l)1 C2H6O(l) +3O2(g) +1368 kJ (G) 2C(garfite)+3H2(g)+1/2 O2(g)1C2H6O(l) -278
  • 25. W WE know Termoquímica
  • 26. RReeffeerreenncciiaass BBiibblliiooggrrááffiiccaass UUssbbeerrccoo && SSaallvvaaddoorr,, ssaarraaiivvaa;;QQuuíímmiiccaa ((vvoolluummee 22--ffííssiiccoo-- qquuíímmiiccaa));;uunniiddaaddee 33;;ccaappiittuulloo 88 aaoo 1111.. IImmaaggeennss :: ggooooggllee