Submit Search
Upload
synthesis .pdf
•
0 likes
•
3 views
A
akkhan101
Follow
synthesis Solution synthesis.
Read less
Read more
Education
Report
Share
Report
Share
1 of 1
Download now
Download to read offline
Recommended
1.C explanation; Cloud consumers that use cloud-based IT resources can generally lease them with a pay-for-use model. With this model, cloud consumers pay a usage fee for only the amount of the IT resource actually used, resulting in directly proportional costs. This gives an organization access to IT resources without having to purchase its own, resulting in reduced investment requirements 2.B explanation The availability of an IT resource is the probability that it will be accessible. The probability value is generally expressed with a percentage representing the amount of time that the IT resource is accessible during a given period. The percentage is calculated as follows: 1. Divide the amount of hours the IT resource was unavailable (within a measured period) by the total amount of hours within the measured period. 2. Multiply the value by 100. 3. Deduct the value from 100 3.D explanation; Horizontal scaling refers to the allocation or releasing of resources of the same type. The horizontal allocation of resources is referred to as scaling out and the horizontal releasing of resources is referred to as scaling in. Horizontal scaling is a common form of scaling within cloud environments 4.C explanation; Cloud-based IT resources that are used by a cloud consumer reside outside of the cloud consumer’s organizational boundary. To use the IT resources, the cloud consumer will generally need to trust them. As a result, the cloud consumer’s trust boundary is expanded beyond its organizational boundary to encompass the cloud. 5.C explanation; An organization will often have existing IT resources that are already paid for and operational. The prior investment that has been made in these on-premise IT resources is referred to as sunk costs. When comparing cloud-based IT resources to on-premise IT resources with sunk costs, the up-front costs for on-premise IT resources is significantly lower. It can therefore be more difficult to justify the leasing of cloud- based IT resources as an alternative 6.D explanation the fact that trust boundaries overlap can lead to opportunities for an attacker to attack IT resources shared by multiple cloud consumers 7.D explanation all r correct 8.B explanation Cloud A provides Cloud Service A as part of a failover system that encompasses a redundant implementation of Cloud Service A on Cloud B. If Cloud Service A on Cloud A fails, then Cloud Service A on Cloud B is automatically provisioned transparently to Cloud Service Consumer A. Each cloud has a specific level of reliability and availability that it guarantees for Cloud Service A. By spanning the failover system across both clouds, the overall reliability and availability will be higher than the maximum reliability and availability of either cloud 9.C explanation Different physical and virtual IT resources are dynamically assigned and reassigned according to cloud consumer demand, typically followed by execution through statistical multiplexing. Resource poolin.
1.Cexplanation; Cloud consumers that use cloud-based IT resources .pdf
1.Cexplanation; Cloud consumers that use cloud-based IT resources .pdf
akkhan101
1) WBC count is high and this level indicates that the person has leucocytosis. This may be due to some infections or stress etc. 2)the pH level is alkalotic and this is caused by the respiratory alkalosis. As the pH is less than the normal level. Solution 1) WBC count is high and this level indicates that the person has leucocytosis. This may be due to some infections or stress etc. 2)the pH level is alkalotic and this is caused by the respiratory alkalosis. As the pH is less than the normal level..
1) WBC count is high and this level indicates that the person has le.pdf
1) WBC count is high and this level indicates that the person has le.pdf
akkhan101
What are the four steps of a process involving a heterogeneous catalyst? Stage 1:Diffusion of Reactant(s) to the Surface The rate at which reactants will diffuse to the surface will be influenced by their bulk concentration and by the thickness of the boundary layer. Stage 2:Adsorption of reactants Bonds are formed as the reactant(s) are adsorbed onto the surface of the catalyst. The ability for an atom or molecule to stick to the surface is known, brilliantly, as the Sticking Co-efficient. This is just the ratio or percentage of molecules that end up sticking on the surface. Stage 3:Reaction Bonds form between the atoms and molecules on the surface Stage 4:Desorption of products Bonds are broken as the product(s) desorb from the surface. Stage 5:Diffusion of Product(s) away from the Surface The products are then desorbed from the surface of the catalyst. Solution What are the four steps of a process involving a heterogeneous catalyst? Stage 1:Diffusion of Reactant(s) to the Surface The rate at which reactants will diffuse to the surface will be influenced by their bulk concentration and by the thickness of the boundary layer. Stage 2:Adsorption of reactants Bonds are formed as the reactant(s) are adsorbed onto the surface of the catalyst. The ability for an atom or molecule to stick to the surface is known, brilliantly, as the Sticking Co-efficient. This is just the ratio or percentage of molecules that end up sticking on the surface. Stage 3:Reaction Bonds form between the atoms and molecules on the surface Stage 4:Desorption of products Bonds are broken as the product(s) desorb from the surface. Stage 5:Diffusion of Product(s) away from the Surface The products are then desorbed from the surface of the catalyst..
What are the four steps of a process involving a heterogeneous catal.pdf
What are the four steps of a process involving a heterogeneous catal.pdf
akkhan101
The given function is:- Strictly increasing from 2 to infinity Hence, Strictly increasing:- (2,inf)Option 2 Strictly decreasing :- (-inf , 2) Option 4 Hence, Option- 2,4 are correct. Solution The given function is:- Strictly increasing from 2 to infinity Hence, Strictly increasing:- (2,inf)Option 2 Strictly decreasing :- (-inf , 2) Option 4 Hence, Option- 2,4 are correct..
The given function is-Strictly increasing from 2 to infinityHen.pdf
The given function is-Strictly increasing from 2 to infinityHen.pdf
akkhan101
OrderTest.java public class OrderTest { /** * Get an array of specified size and pass it to Order.order(). * Report the results. */ public static void main(String[] args) { if (args.length != 1) {//1 System.out.println(\"Usage: java OrderTest sizeOfArray\ \" + \"\\tor\ \\tjava OrderTest arrayFile\"); System.exit(1); } // create or read the int[] int size = 0; int[] array = new int[0];//5 try { size = Integer.parseInt(args[0]); array = ArrayOfInts.randomizedArray(size); } catch (NumberFormatException nfe) {//8 try { array = ArrayOfInts.arrayFromFile(args[0]); size = array.length; } catch (Exception e) { System.err.println(\"unable to read array from \" + args[0]); System.exit(1);//14 } } System.out.println(\"before:\");//15 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]);//1 } int myNum = Order.order(array); //this is the call we want to measure System.out.println(\"\ after:\");//18 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]); } System.out.println(myNum); } } ArrayOfInts.java import java.io.BufferedWriter; import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.InputMismatchException; import java.util.Scanner; public class ArrayOfInts { /** * Returns an array of consecutive ints from 1 to size. */ public static int[] orderedArray(int size) { int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = i+1; } return a; } /** * Returns a randomized array containing ints from 1 to size. */ public static int[] randomizedArray(int size) { ArrayList aL = new ArrayList(); for (int i = 0; i < size; i++) { aL.add(i+1); } Collections.shuffle(aL); int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = aL.get(i); } return a; } /** * Writes an int[] to a plain-text file with ints separated by spaces. * Useful for creating input files for repeatable tests. */ public static void arrayToFile(int[] array, String outfile) { try { FileWriter fw = new FileWriter(outfile); BufferedWriter bw = new BufferedWriter(fw); PrintWriter outFile = new PrintWriter(bw); for (int i : array) { outFile.print(i + \" \"); } outFile.close(); } catch (IOException e) { System.err.println(\"Could not write to \" + outfile + \"\ \" + e); } } /** * Read ints from a file and return them in an int[] */ public static int[] arrayFromFile(String infile) throws FileNotFoundException, InputMismatchException { Scanner scan = new Scanner(new File(infile)); ArrayList aL = new ArrayList(); while (scan.hasNext()) { aL.add(scan.nextInt()); } scan.close(); int[] a = new int[aL.size()]; for (int i = 0; i < a.length; i++) { a[i] = aL.get(i); } return a; } } Order.java public class Order { /** * Take an int[] and reorganize it so they are in ascending order. */ public static int order(int[] array) .
OrderTest.javapublic class OrderTest { Get an arra.pdf
OrderTest.javapublic class OrderTest { Get an arra.pdf
akkhan101
In the span of several decades, the Kingdom Protista has been disassembled because sequence analyses have revealed new genetic (and therefore evolutionary) relationships among these eukaryotes. Moreover, protists that exhibit similar morphological features may have evolved analogous structures because of similar selective pressures—rather than because of recent common ancestry. This phenomenon, called convergent evolution, is one reason why protist classification is so challenging. The emerging classification scheme groups the entire domain Eukaryota into six “supergroups” that contain all of the protists as well as animals, plants, and fungi that evolved from a common ancestor. The supergroups are believed to be monophyletic, meaning that all organisms within each supergroup are believed to have evolved from a single common ancestor, and thus all members are most closely related to each other than to organisms outside that group. There is still evidence lacking for the monophyly of some groups. Many of the protist species classified into the supergroup Excavata are asymmetrical, single- celled organisms with a feeding groove “excavated” from one side. This supergroup includes heterotrophic predators, photosynthetic species, and parasites. Its subgroups are the diplomonads, parabasalids, and euglenozoans. Diplomonads Among the Excavata are the diplomonads, which include the intestinal parasite, Giardia lamblia. Until recently, these protists were believed to lack mitochondria. Mitochondrial remnant organelles, called mitosomes, have since been identified in diplomonads, but these mitosomes are essentially nonfunctional. Diplomonads exist in anaerobic environments and use alternative pathways, such as glycolysis, to generate energy. Each diplomonad cell has two identical nuclei and uses several flagella for locomotion. Parabasalids A second Excavata subgroup, the parabasalids, also exhibits semi-functional mitochondria. In parabasalids, these structures function anaerobically and are called hydrogenosomes because they produce hydrogen gas as a byproduct. Parabasalids move with flagella and membrane rippling. Trichomonas vaginalis, a parabasalid that causes a sexually transmitted disease in humans. Euglenozoans Euglenozoans includes parasites, heterotrophs, autotrophs, and mixotrophs, ranging in size from 10 to 500 µm. Euglenoids move through their aquatic habitats using two long flagella that guide them toward light sources sensed by a primitive ocular organ called an eyespot. The familiar genus, Euglena, encompasses some mixotrophic species that display a photosynthetic capability only when light is present. In the dark, the chloroplasts of Euglena shrink up and temporarily cease functioning, and the cells instead take up organic nutrients from their environment. The human parasite, Trypanosoma brucei, belongs to a different subgroup of Euglenozoa, the kinetoplastids. The kinetoplastid subgroup is named after the kinetoplast, a DNA mass carri.
In the span of several decades, the Kingdom Protista has been disass.pdf
In the span of several decades, the Kingdom Protista has been disass.pdf
akkhan101
Information privacy : It refers to the collection of data and dissemination of the data. It includes following issues those are 1. Data collection 2. Extract data from affected subjects 3. Controlled disclosureI Option A is correct choice. Solution Information privacy : It refers to the collection of data and dissemination of the data. It includes following issues those are 1. Data collection 2. Extract data from affected subjects 3. Controlled disclosureI Option A is correct choice..
Information privacy It refers to the collection of data and disse.pdf
Information privacy It refers to the collection of data and disse.pdf
akkhan101
H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4 Solution H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4.
H2SO4 --- 2H+ + SO42-1 mole of H2SO4 produces 2 moles of H+ ions.pdf
H2SO4 --- 2H+ + SO42-1 mole of H2SO4 produces 2 moles of H+ ions.pdf
akkhan101
Recommended
1.C explanation; Cloud consumers that use cloud-based IT resources can generally lease them with a pay-for-use model. With this model, cloud consumers pay a usage fee for only the amount of the IT resource actually used, resulting in directly proportional costs. This gives an organization access to IT resources without having to purchase its own, resulting in reduced investment requirements 2.B explanation The availability of an IT resource is the probability that it will be accessible. The probability value is generally expressed with a percentage representing the amount of time that the IT resource is accessible during a given period. The percentage is calculated as follows: 1. Divide the amount of hours the IT resource was unavailable (within a measured period) by the total amount of hours within the measured period. 2. Multiply the value by 100. 3. Deduct the value from 100 3.D explanation; Horizontal scaling refers to the allocation or releasing of resources of the same type. The horizontal allocation of resources is referred to as scaling out and the horizontal releasing of resources is referred to as scaling in. Horizontal scaling is a common form of scaling within cloud environments 4.C explanation; Cloud-based IT resources that are used by a cloud consumer reside outside of the cloud consumer’s organizational boundary. To use the IT resources, the cloud consumer will generally need to trust them. As a result, the cloud consumer’s trust boundary is expanded beyond its organizational boundary to encompass the cloud. 5.C explanation; An organization will often have existing IT resources that are already paid for and operational. The prior investment that has been made in these on-premise IT resources is referred to as sunk costs. When comparing cloud-based IT resources to on-premise IT resources with sunk costs, the up-front costs for on-premise IT resources is significantly lower. It can therefore be more difficult to justify the leasing of cloud- based IT resources as an alternative 6.D explanation the fact that trust boundaries overlap can lead to opportunities for an attacker to attack IT resources shared by multiple cloud consumers 7.D explanation all r correct 8.B explanation Cloud A provides Cloud Service A as part of a failover system that encompasses a redundant implementation of Cloud Service A on Cloud B. If Cloud Service A on Cloud A fails, then Cloud Service A on Cloud B is automatically provisioned transparently to Cloud Service Consumer A. Each cloud has a specific level of reliability and availability that it guarantees for Cloud Service A. By spanning the failover system across both clouds, the overall reliability and availability will be higher than the maximum reliability and availability of either cloud 9.C explanation Different physical and virtual IT resources are dynamically assigned and reassigned according to cloud consumer demand, typically followed by execution through statistical multiplexing. Resource poolin.
1.Cexplanation; Cloud consumers that use cloud-based IT resources .pdf
1.Cexplanation; Cloud consumers that use cloud-based IT resources .pdf
akkhan101
1) WBC count is high and this level indicates that the person has leucocytosis. This may be due to some infections or stress etc. 2)the pH level is alkalotic and this is caused by the respiratory alkalosis. As the pH is less than the normal level. Solution 1) WBC count is high and this level indicates that the person has leucocytosis. This may be due to some infections or stress etc. 2)the pH level is alkalotic and this is caused by the respiratory alkalosis. As the pH is less than the normal level..
1) WBC count is high and this level indicates that the person has le.pdf
1) WBC count is high and this level indicates that the person has le.pdf
akkhan101
What are the four steps of a process involving a heterogeneous catalyst? Stage 1:Diffusion of Reactant(s) to the Surface The rate at which reactants will diffuse to the surface will be influenced by their bulk concentration and by the thickness of the boundary layer. Stage 2:Adsorption of reactants Bonds are formed as the reactant(s) are adsorbed onto the surface of the catalyst. The ability for an atom or molecule to stick to the surface is known, brilliantly, as the Sticking Co-efficient. This is just the ratio or percentage of molecules that end up sticking on the surface. Stage 3:Reaction Bonds form between the atoms and molecules on the surface Stage 4:Desorption of products Bonds are broken as the product(s) desorb from the surface. Stage 5:Diffusion of Product(s) away from the Surface The products are then desorbed from the surface of the catalyst. Solution What are the four steps of a process involving a heterogeneous catalyst? Stage 1:Diffusion of Reactant(s) to the Surface The rate at which reactants will diffuse to the surface will be influenced by their bulk concentration and by the thickness of the boundary layer. Stage 2:Adsorption of reactants Bonds are formed as the reactant(s) are adsorbed onto the surface of the catalyst. The ability for an atom or molecule to stick to the surface is known, brilliantly, as the Sticking Co-efficient. This is just the ratio or percentage of molecules that end up sticking on the surface. Stage 3:Reaction Bonds form between the atoms and molecules on the surface Stage 4:Desorption of products Bonds are broken as the product(s) desorb from the surface. Stage 5:Diffusion of Product(s) away from the Surface The products are then desorbed from the surface of the catalyst..
What are the four steps of a process involving a heterogeneous catal.pdf
What are the four steps of a process involving a heterogeneous catal.pdf
akkhan101
The given function is:- Strictly increasing from 2 to infinity Hence, Strictly increasing:- (2,inf)Option 2 Strictly decreasing :- (-inf , 2) Option 4 Hence, Option- 2,4 are correct. Solution The given function is:- Strictly increasing from 2 to infinity Hence, Strictly increasing:- (2,inf)Option 2 Strictly decreasing :- (-inf , 2) Option 4 Hence, Option- 2,4 are correct..
The given function is-Strictly increasing from 2 to infinityHen.pdf
The given function is-Strictly increasing from 2 to infinityHen.pdf
akkhan101
OrderTest.java public class OrderTest { /** * Get an array of specified size and pass it to Order.order(). * Report the results. */ public static void main(String[] args) { if (args.length != 1) {//1 System.out.println(\"Usage: java OrderTest sizeOfArray\ \" + \"\\tor\ \\tjava OrderTest arrayFile\"); System.exit(1); } // create or read the int[] int size = 0; int[] array = new int[0];//5 try { size = Integer.parseInt(args[0]); array = ArrayOfInts.randomizedArray(size); } catch (NumberFormatException nfe) {//8 try { array = ArrayOfInts.arrayFromFile(args[0]); size = array.length; } catch (Exception e) { System.err.println(\"unable to read array from \" + args[0]); System.exit(1);//14 } } System.out.println(\"before:\");//15 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]);//1 } int myNum = Order.order(array); //this is the call we want to measure System.out.println(\"\ after:\");//18 for (int i = 0; i < array.length; i++) {//2 n System.out.printf(((i+1) % 10 > 0) ? \" %d\" : \" %d\ \", array[i]); } System.out.println(myNum); } } ArrayOfInts.java import java.io.BufferedWriter; import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.InputMismatchException; import java.util.Scanner; public class ArrayOfInts { /** * Returns an array of consecutive ints from 1 to size. */ public static int[] orderedArray(int size) { int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = i+1; } return a; } /** * Returns a randomized array containing ints from 1 to size. */ public static int[] randomizedArray(int size) { ArrayList aL = new ArrayList(); for (int i = 0; i < size; i++) { aL.add(i+1); } Collections.shuffle(aL); int[] a = new int[size]; for (int i = 0; i < size; i++) { a[i] = aL.get(i); } return a; } /** * Writes an int[] to a plain-text file with ints separated by spaces. * Useful for creating input files for repeatable tests. */ public static void arrayToFile(int[] array, String outfile) { try { FileWriter fw = new FileWriter(outfile); BufferedWriter bw = new BufferedWriter(fw); PrintWriter outFile = new PrintWriter(bw); for (int i : array) { outFile.print(i + \" \"); } outFile.close(); } catch (IOException e) { System.err.println(\"Could not write to \" + outfile + \"\ \" + e); } } /** * Read ints from a file and return them in an int[] */ public static int[] arrayFromFile(String infile) throws FileNotFoundException, InputMismatchException { Scanner scan = new Scanner(new File(infile)); ArrayList aL = new ArrayList(); while (scan.hasNext()) { aL.add(scan.nextInt()); } scan.close(); int[] a = new int[aL.size()]; for (int i = 0; i < a.length; i++) { a[i] = aL.get(i); } return a; } } Order.java public class Order { /** * Take an int[] and reorganize it so they are in ascending order. */ public static int order(int[] array) .
OrderTest.javapublic class OrderTest { Get an arra.pdf
OrderTest.javapublic class OrderTest { Get an arra.pdf
akkhan101
In the span of several decades, the Kingdom Protista has been disassembled because sequence analyses have revealed new genetic (and therefore evolutionary) relationships among these eukaryotes. Moreover, protists that exhibit similar morphological features may have evolved analogous structures because of similar selective pressures—rather than because of recent common ancestry. This phenomenon, called convergent evolution, is one reason why protist classification is so challenging. The emerging classification scheme groups the entire domain Eukaryota into six “supergroups” that contain all of the protists as well as animals, plants, and fungi that evolved from a common ancestor. The supergroups are believed to be monophyletic, meaning that all organisms within each supergroup are believed to have evolved from a single common ancestor, and thus all members are most closely related to each other than to organisms outside that group. There is still evidence lacking for the monophyly of some groups. Many of the protist species classified into the supergroup Excavata are asymmetrical, single- celled organisms with a feeding groove “excavated” from one side. This supergroup includes heterotrophic predators, photosynthetic species, and parasites. Its subgroups are the diplomonads, parabasalids, and euglenozoans. Diplomonads Among the Excavata are the diplomonads, which include the intestinal parasite, Giardia lamblia. Until recently, these protists were believed to lack mitochondria. Mitochondrial remnant organelles, called mitosomes, have since been identified in diplomonads, but these mitosomes are essentially nonfunctional. Diplomonads exist in anaerobic environments and use alternative pathways, such as glycolysis, to generate energy. Each diplomonad cell has two identical nuclei and uses several flagella for locomotion. Parabasalids A second Excavata subgroup, the parabasalids, also exhibits semi-functional mitochondria. In parabasalids, these structures function anaerobically and are called hydrogenosomes because they produce hydrogen gas as a byproduct. Parabasalids move with flagella and membrane rippling. Trichomonas vaginalis, a parabasalid that causes a sexually transmitted disease in humans. Euglenozoans Euglenozoans includes parasites, heterotrophs, autotrophs, and mixotrophs, ranging in size from 10 to 500 µm. Euglenoids move through their aquatic habitats using two long flagella that guide them toward light sources sensed by a primitive ocular organ called an eyespot. The familiar genus, Euglena, encompasses some mixotrophic species that display a photosynthetic capability only when light is present. In the dark, the chloroplasts of Euglena shrink up and temporarily cease functioning, and the cells instead take up organic nutrients from their environment. The human parasite, Trypanosoma brucei, belongs to a different subgroup of Euglenozoa, the kinetoplastids. The kinetoplastid subgroup is named after the kinetoplast, a DNA mass carri.
In the span of several decades, the Kingdom Protista has been disass.pdf
In the span of several decades, the Kingdom Protista has been disass.pdf
akkhan101
Information privacy : It refers to the collection of data and dissemination of the data. It includes following issues those are 1. Data collection 2. Extract data from affected subjects 3. Controlled disclosureI Option A is correct choice. Solution Information privacy : It refers to the collection of data and dissemination of the data. It includes following issues those are 1. Data collection 2. Extract data from affected subjects 3. Controlled disclosureI Option A is correct choice..
Information privacy It refers to the collection of data and disse.pdf
Information privacy It refers to the collection of data and disse.pdf
akkhan101
H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4 Solution H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4.
H2SO4 --- 2H+ + SO42-1 mole of H2SO4 produces 2 moles of H+ ions.pdf
H2SO4 --- 2H+ + SO42-1 mole of H2SO4 produces 2 moles of H+ ions.pdf
akkhan101
Gene editing of somatic cells There are grave concerns regarding the ethical and safety implications of this research. There is also fear of the negative impact it could have on important work involving the use of genome- editing techniques in somatic (non-reproductive) cells. Genome-editing technologies may offer a powerful approach to treat many human diseases, including HIV/AIDS, haemophilia, sickle-cell anaemia and several forms of cancer genome editing in human embryos using current technologies could have unpredictable effects on future generations. This makes it dangerous and ethically unacceptable. Such research could be exploited for non-therapeutic modifications. We are concerned that a public outcry about such an ethical breach could hinder a promising area of therapeutic development, namely making genetic changes that cannot be inherited. prospect of manipulating the genome of human embryos has raised debates and discussions amongst scientists, regulators, and the public. It is a crucial conversation that we need to participate in as we have done for other scientific advancements in the past from embryonic stem cells research to ‘in vitro’ fertilization and, recently in the UK, mitochondrial replacement. Gene editing of somatic cells is currently in clinical development for a variety of conditions. The editing of genomes in human somatic cells certainly raises ethical questions, but is distinct from germline gene modification, in that changes in the gene(s) do not persist beyond a single generation. As to human germline editing, the EGE is of the view that there should be a moratorium on gene editing of human embryos or gametes which would result in the modification of the human genome. Solution Gene editing of somatic cells There are grave concerns regarding the ethical and safety implications of this research. There is also fear of the negative impact it could have on important work involving the use of genome- editing techniques in somatic (non-reproductive) cells. Genome-editing technologies may offer a powerful approach to treat many human diseases, including HIV/AIDS, haemophilia, sickle-cell anaemia and several forms of cancer genome editing in human embryos using current technologies could have unpredictable effects on future generations. This makes it dangerous and ethically unacceptable. Such research could be exploited for non-therapeutic modifications. We are concerned that a public outcry about such an ethical breach could hinder a promising area of therapeutic development, namely making genetic changes that cannot be inherited. prospect of manipulating the genome of human embryos has raised debates and discussions amongst scientists, regulators, and the public. It is a crucial conversation that we need to participate in as we have done for other scientific advancements in the past from embryonic stem cells research to ‘in vitro’ fertilization and, recently in the UK, mitochondrial replacement. Gene editing of somatic.
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
akkhan101
Four parts of compare and contrast Solution Four parts of compare and contrast.
Four parts of compare and contrastSolutionFour parts of compar.pdf
Four parts of compare and contrastSolutionFour parts of compar.pdf
akkhan101
Each Restriction enzymes has a unique restriction site and therefore in a GFP-HindIII clone no restriction patterns will be observed with EcoRI digestion until and unless one has prior knowledge of all restriction sites present on the clone. Solution Each Restriction enzymes has a unique restriction site and therefore in a GFP-HindIII clone no restriction patterns will be observed with EcoRI digestion until and unless one has prior knowledge of all restriction sites present on the clone..
Each Restriction enzymes has a unique restriction site and therefore.pdf
Each Restriction enzymes has a unique restriction site and therefore.pdf
akkhan101
correct Solution correct.
correctSolutioncorrect.pdf
correctSolutioncorrect.pdf
akkhan101
Code of main class: public class LBmain { public static void main(String[]args) { LinkedStack list = new LinkedStack<>(); System.out.println(\"Let\'s make a List!\"); System.out.println(\"Push 3 times.\"); System.out.println(\"Check the size.\"); System.out.println(\"Peek the top element.\"); System.out.println(\"Pop three times.\"); System.out.println (\"The size now should be zero!\" + \"\ \"); list.Push(1); list.Push(2); list.Push(3); System.out.println(list.toString()); list.Size(); list.Peek(); list.Pop(); list.Pop(); list.Pop(); list.Size(); } public class LinkedStack implements Stack { private int count; private LinearNode top; //----------------------------------------------------------------- // Creates an empty stack using the default capacity. //----------------------------------------------------------------- public LinkedStack() { count = 0; top = null; } @Override public boolean IsEmpty() { if(top == null) { System.out.println(\"Stack is empty\"); } return top == null; } @Override public void Push(T element) { LinearNode current = new LinearNode<>(element); current.setNext(top); top = current; count++;} @Override public T Pop() { T result; System.out.println(\"Lets pop the top element!\"); if (count == 0) { System.out.println(\"Pop operation failed. \"+ \"The stack is empty.\"); } result = top.getElement(); top = top.getNext(); count--; System.out.println(\"The element that we have poped is :\" + result); return result; } Override public String toString() { String result = \"\ \"; LinearNode current = top; while (current != null) { result += current.getElement() + \"\ \"; current = current.getNext(); } return result + \"\"; } @Override public T Peek() { System.out.println(\"Lets peek the top element!\"); if(count == 0) { System.out.println(\"Peek failed stack is empty\"); } System.out.println(\"The element that we have peeked is: \" + top.getElement()); return top.getElement(); } @Override public int Size() { System.out.println(\"The size of the list now is: \" + count); return count; } } main.Peek(); main.Pop(); main.Pop(); main.Size(); main.toString(); } } @Override public void Push(T element) { LinearNode current = new LinearNode<>(element); current.setNext(top); top = current; count++; } } public class LinearNode { private LinearNode next; //se guarda la referencia del Nodo private T element; //Lista vacia public LinearNode() { next = null; element = null; } //----------------------------------------------------------------- // Creates a node storing the specified element. //----------------------------------------------------------------- public LinearNode (T elem) { next = null; element = elem; } //----------------------------------------------------------------- // Returns the node that follows this one. //----------------------------------------------------------------- public LinearNode getNext() { return next; } //----------------------------------------------------------------- // Sets the node that follows this one. .
Code of main classpublic class LBmain { public static void m.pdf
Code of main classpublic class LBmain { public static void m.pdf
akkhan101
Bibliography: Hall, J. E. (2015). Guyton and Hall textbook of medical physiology. Elsevier Health Sciences. De Luca Jr, L. A., Menani, J. V., & Johnson, A. K. (2014). Circumventricular Organs: Integrators of Circulating Signals Controlling Hydration, Energy Balance, and Immune Function--Neurobiology of Body Fluid Homeostasis: Transduction and Integration. Sherwood, L. (2015). Human physiology: from cells to systems. Cengage learning. Homeostatic Regulation of the Vascular System | Anatomy and Physiology II. (2016). Courses.lumenlearning.com. Retrieved 25 November 2016, from https://courses.lumenlearning.com/ap2/chapter/homeostatic-regulation-of-the-vascular-system De Luca Jr, L. A., Menani, J. V., & Johnson, A. K. (2014). Preoptic–Periventricular Integrative Mechanisms Involved in Behavior, Fluid–Electrolyte Balance, and Pressor Responses-- Neurobiology of Body Fluid Homeostasis: Transduction and Integration. Keeping in mind the end goal to keep up homeostasis in the cardiovascular framework and give sufficient blood to the tissues, blood stream must be diverted constantly to the tissues as they turn out to be more dynamic. Undeniably, the cardiovascular framework takes part in asset assignment, in light of the fact that there is insufficient blood stream to disseminate blood similarly to all tissues at the same time. For instance, when an individual is working out, more blood will be coordinated to skeletal muscles, the heart, and the lungs. Taking after a dinner, more blood is coordinated to the stomach related framework. Just the mind gets a pretty much steady supply of blood whether you are dynamic, resting, considering, or occupied with some other activity.The sensory system assumes a basic part in the direction of vascular homeostasis. The essential administrative destinations incorporate the cardiovascular focuses in the mind that control both heart and vascular capacities. Also, more summed up neural reactions from the limbic framework and the autonomic sensory system are variables. The Cardiovascular Centers in the Brain Neurological control of circulatory strain and stream relies on upon the cardiovascular focuses situated in the medulla oblongata. This group of neurons reacts to changes in pulse and in addition blood convergences of oxygen, carbon dioxide, and hydrogen particles. The cardiovascular focus contains three particular combined segments: The cardioaccelerator focuses empower cardiovascular capacity by controlling heart rate and stroke volume by means of thoughtful incitement from the cardiovascular quickening agent nerve. The cardioinhibitor focuses moderate cardiovascular capacity by diminishing heart rate and stroke volume through parasympathetic incitement from the vagus nerve. The vasomotor focuses control vessel tone or withdrawal of the smooth muscle in the tunica media. Changes in width influence fringe resistance, weight, and stream, which influence cardiovascular yield. The lion\'s share of these neurons demonst.
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
akkhan101
LiOH is a strong base so we assume it dissociates completely. So there will be 8.82 x 10^-3 M of OH- pOH = -log[OH-] = -log(8.82 x 10^-3) = 2.05 pH = 14 - pOH = 14 - 2.05 = 11.95 Solution LiOH is a strong base so we assume it dissociates completely. So there will be 8.82 x 10^-3 M of OH- pOH = -log[OH-] = -log(8.82 x 10^-3) = 2.05 pH = 14 - pOH = 14 - 2.05 = 11.95.
LiOH is a strong base so we assume it dissociates.pdf
LiOH is a strong base so we assume it dissociates.pdf
akkhan101
With Sp3d hybridization, a seesaw or linear shape is possible. The seesaw shape occurs when the molecule has the form AB4E, where A is the central atom, B represents the atoms attached to the central atom and E is a nonbonding pair of electrons attached to the central atom. Linear is in the form AB2E3. So A is the central atom and should be by itself and the only choice that fits that criteria is answer A (BrFs) Solution With Sp3d hybridization, a seesaw or linear shape is possible. The seesaw shape occurs when the molecule has the form AB4E, where A is the central atom, B represents the atoms attached to the central atom and E is a nonbonding pair of electrons attached to the central atom. Linear is in the form AB2E3. So A is the central atom and should be by itself and the only choice that fits that criteria is answer A (BrFs).
With Sp3d hybridization, a seesaw or linear shape.pdf
With Sp3d hybridization, a seesaw or linear shape.pdf
akkhan101
Two-photon transition probability Solution Two-photon transition probability.
Two-photon transition probability .pdf
Two-photon transition probability .pdf
akkhan101
this is because Nitrogen has a lone pair and and the Carbon with chlorine is electrophilic in nature and therefore, the lone pair attracted towards that lone pair. Solution this is because Nitrogen has a lone pair and and the Carbon with chlorine is electrophilic in nature and therefore, the lone pair attracted towards that lone pair..
this is because Nitrogen has a lone pair and and .pdf
this is because Nitrogen has a lone pair and and .pdf
akkhan101
There is no easy way to remember the ionization levels on periodic table. Elements in a certain group share similar properties. That could be one way to predict the ionization levels but its not 100% accurate at all times. Solution There is no easy way to remember the ionization levels on periodic table. Elements in a certain group share similar properties. That could be one way to predict the ionization levels but its not 100% accurate at all times..
There is no easy way to remember the ionization l.pdf
There is no easy way to remember the ionization l.pdf
akkhan101
My opinion is to carry out in the complete absence of water. Solution My opinion is to carry out in the complete absence of water..
My opinion is to carry out in the complete absenc.pdf
My opinion is to carry out in the complete absenc.pdf
akkhan101
cant say anything about no. of molecules, unless we know how many moles are present. (A) not enough info Solution cant say anything about no. of molecules, unless we know how many moles are present. (A) not enough info.
cant say anything about no. of molecules, unless .pdf
cant say anything about no. of molecules, unless .pdf
akkhan101
C-O (carbonlyl) peaks occur usually around 1500-1700. I Cant clearly see the picture but I would say you have at least 1-2 Carbonly groups, since there are 2 peaks that occur past 1500. Solution C-O (carbonlyl) peaks occur usually around 1500-1700. I Cant clearly see the picture but I would say you have at least 1-2 Carbonly groups, since there are 2 peaks that occur past 1500..
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
akkhan101
Boiling points and solubility of alcohols are high because there are hydrogen bonds Solution Boiling points and solubility of alcohols are high because there are hydrogen bonds.
Boiling points and solubility of alcohols are hig.pdf
Boiling points and solubility of alcohols are hig.pdf
akkhan101
C. Bromobenzene undergoes addition reactions rather than substitution reactions. Solution C. Bromobenzene undergoes addition reactions rather than substitution reactions..
C. Bromobenzene undergoes addition reactions rath.pdf
C. Bromobenzene undergoes addition reactions rath.pdf
akkhan101
Answer: Measels (aka rubeola) and rubella (aka German Measels) are both caused by enveloped single stranded RNA viruses and develop skin rash. Rubella (aka German Measels) disease is only lasts for 3 days whereas \"rubeola\" always lasts for 7 days. Rubella (aka German Measels) is mainly result in light red or spotted for 3 days finally result in swelling of lymph nodes and joint swelling. Rubeola also known as regular measles and the resultant skin rashes are going to generate reddish-brown rash but the symptoms are \"running nose and pyrexia\". Solution Answer: Measels (aka rubeola) and rubella (aka German Measels) are both caused by enveloped single stranded RNA viruses and develop skin rash. Rubella (aka German Measels) disease is only lasts for 3 days whereas \"rubeola\" always lasts for 7 days. Rubella (aka German Measels) is mainly result in light red or spotted for 3 days finally result in swelling of lymph nodes and joint swelling. Rubeola also known as regular measles and the resultant skin rashes are going to generate reddish-brown rash but the symptoms are \"running nose and pyrexia\"..
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
akkhan101
Answer : It very much essential and plays very miportant role in the regulation of the cell cycle, differentiation, growth and cell senescence, all of which are critical to normal development. A class of human genetic syndromes has emerged that are caused by germline mutations in genes which encode components of the Ras/mitogen activated protein kinase (MAPK) pathway. This pathway plays an essential role in the control of the cell cycle and differentiation, therefore its dysregulation has profound developmental consequences. These “RASopathies” exhibit unique phenotypic features, however, many share characteristic overlapping features including craniofacial dysmorphology, cardiac, cutaneous malformations, musculoskeletal and ocular abnormalities, varying degrees of neurocognitive impairment and in some syndromes, an increased risk of developing cancer.Yes it act as second messenger for the ccell cycyle to go on. This RASopathy plays a very important role in the developement of T cells Solution Answer : It very much essential and plays very miportant role in the regulation of the cell cycle, differentiation, growth and cell senescence, all of which are critical to normal development. A class of human genetic syndromes has emerged that are caused by germline mutations in genes which encode components of the Ras/mitogen activated protein kinase (MAPK) pathway. This pathway plays an essential role in the control of the cell cycle and differentiation, therefore its dysregulation has profound developmental consequences. These “RASopathies” exhibit unique phenotypic features, however, many share characteristic overlapping features including craniofacial dysmorphology, cardiac, cutaneous malformations, musculoskeletal and ocular abnormalities, varying degrees of neurocognitive impairment and in some syndromes, an increased risk of developing cancer.Yes it act as second messenger for the ccell cycyle to go on. This RASopathy plays a very important role in the developement of T cells.
Answer It very much essential and plays very miportant role in th.pdf
Answer It very much essential and plays very miportant role in th.pdf
akkhan101
As entropy increases as we move from solid to liquid to gas, so S is clearly negative for B, D and E. In case of no change in the state, the entropy increases with the number of particles, so S is negative for C and positive only for A. Solution As entropy increases as we move from solid to liquid to gas, so S is clearly negative for B, D and E. In case of no change in the state, the entropy increases with the number of particles, so S is negative for C and positive only for A..
As entropy increases as we move from solid to liquid to gas, so S is.pdf
As entropy increases as we move from solid to liquid to gas, so S is.pdf
akkhan101
Advantages of peer to peer networks Reasons why using a server would benefit a home network Solution Advantages of peer to peer networks Reasons why using a server would benefit a home network.
Advantages of peer to peer networksReasons why using a server woul.pdf
Advantages of peer to peer networksReasons why using a server woul.pdf
akkhan101
The first step to enter the process...
PART A. Introduction to Costumer Service
PART A. Introduction to Costumer Service
PedroFerreira53928
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Thiyagu K
More Related Content
More from akkhan101
Gene editing of somatic cells There are grave concerns regarding the ethical and safety implications of this research. There is also fear of the negative impact it could have on important work involving the use of genome- editing techniques in somatic (non-reproductive) cells. Genome-editing technologies may offer a powerful approach to treat many human diseases, including HIV/AIDS, haemophilia, sickle-cell anaemia and several forms of cancer genome editing in human embryos using current technologies could have unpredictable effects on future generations. This makes it dangerous and ethically unacceptable. Such research could be exploited for non-therapeutic modifications. We are concerned that a public outcry about such an ethical breach could hinder a promising area of therapeutic development, namely making genetic changes that cannot be inherited. prospect of manipulating the genome of human embryos has raised debates and discussions amongst scientists, regulators, and the public. It is a crucial conversation that we need to participate in as we have done for other scientific advancements in the past from embryonic stem cells research to ‘in vitro’ fertilization and, recently in the UK, mitochondrial replacement. Gene editing of somatic cells is currently in clinical development for a variety of conditions. The editing of genomes in human somatic cells certainly raises ethical questions, but is distinct from germline gene modification, in that changes in the gene(s) do not persist beyond a single generation. As to human germline editing, the EGE is of the view that there should be a moratorium on gene editing of human embryos or gametes which would result in the modification of the human genome. Solution Gene editing of somatic cells There are grave concerns regarding the ethical and safety implications of this research. There is also fear of the negative impact it could have on important work involving the use of genome- editing techniques in somatic (non-reproductive) cells. Genome-editing technologies may offer a powerful approach to treat many human diseases, including HIV/AIDS, haemophilia, sickle-cell anaemia and several forms of cancer genome editing in human embryos using current technologies could have unpredictable effects on future generations. This makes it dangerous and ethically unacceptable. Such research could be exploited for non-therapeutic modifications. We are concerned that a public outcry about such an ethical breach could hinder a promising area of therapeutic development, namely making genetic changes that cannot be inherited. prospect of manipulating the genome of human embryos has raised debates and discussions amongst scientists, regulators, and the public. It is a crucial conversation that we need to participate in as we have done for other scientific advancements in the past from embryonic stem cells research to ‘in vitro’ fertilization and, recently in the UK, mitochondrial replacement. Gene editing of somatic.
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
akkhan101
Four parts of compare and contrast Solution Four parts of compare and contrast.
Four parts of compare and contrastSolutionFour parts of compar.pdf
Four parts of compare and contrastSolutionFour parts of compar.pdf
akkhan101
Each Restriction enzymes has a unique restriction site and therefore in a GFP-HindIII clone no restriction patterns will be observed with EcoRI digestion until and unless one has prior knowledge of all restriction sites present on the clone. Solution Each Restriction enzymes has a unique restriction site and therefore in a GFP-HindIII clone no restriction patterns will be observed with EcoRI digestion until and unless one has prior knowledge of all restriction sites present on the clone..
Each Restriction enzymes has a unique restriction site and therefore.pdf
Each Restriction enzymes has a unique restriction site and therefore.pdf
akkhan101
correct Solution correct.
correctSolutioncorrect.pdf
correctSolutioncorrect.pdf
akkhan101
Code of main class: public class LBmain { public static void main(String[]args) { LinkedStack list = new LinkedStack<>(); System.out.println(\"Let\'s make a List!\"); System.out.println(\"Push 3 times.\"); System.out.println(\"Check the size.\"); System.out.println(\"Peek the top element.\"); System.out.println(\"Pop three times.\"); System.out.println (\"The size now should be zero!\" + \"\ \"); list.Push(1); list.Push(2); list.Push(3); System.out.println(list.toString()); list.Size(); list.Peek(); list.Pop(); list.Pop(); list.Pop(); list.Size(); } public class LinkedStack implements Stack { private int count; private LinearNode top; //----------------------------------------------------------------- // Creates an empty stack using the default capacity. //----------------------------------------------------------------- public LinkedStack() { count = 0; top = null; } @Override public boolean IsEmpty() { if(top == null) { System.out.println(\"Stack is empty\"); } return top == null; } @Override public void Push(T element) { LinearNode current = new LinearNode<>(element); current.setNext(top); top = current; count++;} @Override public T Pop() { T result; System.out.println(\"Lets pop the top element!\"); if (count == 0) { System.out.println(\"Pop operation failed. \"+ \"The stack is empty.\"); } result = top.getElement(); top = top.getNext(); count--; System.out.println(\"The element that we have poped is :\" + result); return result; } Override public String toString() { String result = \"\ \"; LinearNode current = top; while (current != null) { result += current.getElement() + \"\ \"; current = current.getNext(); } return result + \"\"; } @Override public T Peek() { System.out.println(\"Lets peek the top element!\"); if(count == 0) { System.out.println(\"Peek failed stack is empty\"); } System.out.println(\"The element that we have peeked is: \" + top.getElement()); return top.getElement(); } @Override public int Size() { System.out.println(\"The size of the list now is: \" + count); return count; } } main.Peek(); main.Pop(); main.Pop(); main.Size(); main.toString(); } } @Override public void Push(T element) { LinearNode current = new LinearNode<>(element); current.setNext(top); top = current; count++; } } public class LinearNode { private LinearNode next; //se guarda la referencia del Nodo private T element; //Lista vacia public LinearNode() { next = null; element = null; } //----------------------------------------------------------------- // Creates a node storing the specified element. //----------------------------------------------------------------- public LinearNode (T elem) { next = null; element = elem; } //----------------------------------------------------------------- // Returns the node that follows this one. //----------------------------------------------------------------- public LinearNode getNext() { return next; } //----------------------------------------------------------------- // Sets the node that follows this one. .
Code of main classpublic class LBmain { public static void m.pdf
Code of main classpublic class LBmain { public static void m.pdf
akkhan101
Bibliography: Hall, J. E. (2015). Guyton and Hall textbook of medical physiology. Elsevier Health Sciences. De Luca Jr, L. A., Menani, J. V., & Johnson, A. K. (2014). Circumventricular Organs: Integrators of Circulating Signals Controlling Hydration, Energy Balance, and Immune Function--Neurobiology of Body Fluid Homeostasis: Transduction and Integration. Sherwood, L. (2015). Human physiology: from cells to systems. Cengage learning. Homeostatic Regulation of the Vascular System | Anatomy and Physiology II. (2016). Courses.lumenlearning.com. Retrieved 25 November 2016, from https://courses.lumenlearning.com/ap2/chapter/homeostatic-regulation-of-the-vascular-system De Luca Jr, L. A., Menani, J. V., & Johnson, A. K. (2014). Preoptic–Periventricular Integrative Mechanisms Involved in Behavior, Fluid–Electrolyte Balance, and Pressor Responses-- Neurobiology of Body Fluid Homeostasis: Transduction and Integration. Keeping in mind the end goal to keep up homeostasis in the cardiovascular framework and give sufficient blood to the tissues, blood stream must be diverted constantly to the tissues as they turn out to be more dynamic. Undeniably, the cardiovascular framework takes part in asset assignment, in light of the fact that there is insufficient blood stream to disseminate blood similarly to all tissues at the same time. For instance, when an individual is working out, more blood will be coordinated to skeletal muscles, the heart, and the lungs. Taking after a dinner, more blood is coordinated to the stomach related framework. Just the mind gets a pretty much steady supply of blood whether you are dynamic, resting, considering, or occupied with some other activity.The sensory system assumes a basic part in the direction of vascular homeostasis. The essential administrative destinations incorporate the cardiovascular focuses in the mind that control both heart and vascular capacities. Also, more summed up neural reactions from the limbic framework and the autonomic sensory system are variables. The Cardiovascular Centers in the Brain Neurological control of circulatory strain and stream relies on upon the cardiovascular focuses situated in the medulla oblongata. This group of neurons reacts to changes in pulse and in addition blood convergences of oxygen, carbon dioxide, and hydrogen particles. The cardiovascular focus contains three particular combined segments: The cardioaccelerator focuses empower cardiovascular capacity by controlling heart rate and stroke volume by means of thoughtful incitement from the cardiovascular quickening agent nerve. The cardioinhibitor focuses moderate cardiovascular capacity by diminishing heart rate and stroke volume through parasympathetic incitement from the vagus nerve. The vasomotor focuses control vessel tone or withdrawal of the smooth muscle in the tunica media. Changes in width influence fringe resistance, weight, and stream, which influence cardiovascular yield. The lion\'s share of these neurons demonst.
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
akkhan101
LiOH is a strong base so we assume it dissociates completely. So there will be 8.82 x 10^-3 M of OH- pOH = -log[OH-] = -log(8.82 x 10^-3) = 2.05 pH = 14 - pOH = 14 - 2.05 = 11.95 Solution LiOH is a strong base so we assume it dissociates completely. So there will be 8.82 x 10^-3 M of OH- pOH = -log[OH-] = -log(8.82 x 10^-3) = 2.05 pH = 14 - pOH = 14 - 2.05 = 11.95.
LiOH is a strong base so we assume it dissociates.pdf
LiOH is a strong base so we assume it dissociates.pdf
akkhan101
With Sp3d hybridization, a seesaw or linear shape is possible. The seesaw shape occurs when the molecule has the form AB4E, where A is the central atom, B represents the atoms attached to the central atom and E is a nonbonding pair of electrons attached to the central atom. Linear is in the form AB2E3. So A is the central atom and should be by itself and the only choice that fits that criteria is answer A (BrFs) Solution With Sp3d hybridization, a seesaw or linear shape is possible. The seesaw shape occurs when the molecule has the form AB4E, where A is the central atom, B represents the atoms attached to the central atom and E is a nonbonding pair of electrons attached to the central atom. Linear is in the form AB2E3. So A is the central atom and should be by itself and the only choice that fits that criteria is answer A (BrFs).
With Sp3d hybridization, a seesaw or linear shape.pdf
With Sp3d hybridization, a seesaw or linear shape.pdf
akkhan101
Two-photon transition probability Solution Two-photon transition probability.
Two-photon transition probability .pdf
Two-photon transition probability .pdf
akkhan101
this is because Nitrogen has a lone pair and and the Carbon with chlorine is electrophilic in nature and therefore, the lone pair attracted towards that lone pair. Solution this is because Nitrogen has a lone pair and and the Carbon with chlorine is electrophilic in nature and therefore, the lone pair attracted towards that lone pair..
this is because Nitrogen has a lone pair and and .pdf
this is because Nitrogen has a lone pair and and .pdf
akkhan101
There is no easy way to remember the ionization levels on periodic table. Elements in a certain group share similar properties. That could be one way to predict the ionization levels but its not 100% accurate at all times. Solution There is no easy way to remember the ionization levels on periodic table. Elements in a certain group share similar properties. That could be one way to predict the ionization levels but its not 100% accurate at all times..
There is no easy way to remember the ionization l.pdf
There is no easy way to remember the ionization l.pdf
akkhan101
My opinion is to carry out in the complete absence of water. Solution My opinion is to carry out in the complete absence of water..
My opinion is to carry out in the complete absenc.pdf
My opinion is to carry out in the complete absenc.pdf
akkhan101
cant say anything about no. of molecules, unless we know how many moles are present. (A) not enough info Solution cant say anything about no. of molecules, unless we know how many moles are present. (A) not enough info.
cant say anything about no. of molecules, unless .pdf
cant say anything about no. of molecules, unless .pdf
akkhan101
C-O (carbonlyl) peaks occur usually around 1500-1700. I Cant clearly see the picture but I would say you have at least 1-2 Carbonly groups, since there are 2 peaks that occur past 1500. Solution C-O (carbonlyl) peaks occur usually around 1500-1700. I Cant clearly see the picture but I would say you have at least 1-2 Carbonly groups, since there are 2 peaks that occur past 1500..
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
akkhan101
Boiling points and solubility of alcohols are high because there are hydrogen bonds Solution Boiling points and solubility of alcohols are high because there are hydrogen bonds.
Boiling points and solubility of alcohols are hig.pdf
Boiling points and solubility of alcohols are hig.pdf
akkhan101
C. Bromobenzene undergoes addition reactions rather than substitution reactions. Solution C. Bromobenzene undergoes addition reactions rather than substitution reactions..
C. Bromobenzene undergoes addition reactions rath.pdf
C. Bromobenzene undergoes addition reactions rath.pdf
akkhan101
Answer: Measels (aka rubeola) and rubella (aka German Measels) are both caused by enveloped single stranded RNA viruses and develop skin rash. Rubella (aka German Measels) disease is only lasts for 3 days whereas \"rubeola\" always lasts for 7 days. Rubella (aka German Measels) is mainly result in light red or spotted for 3 days finally result in swelling of lymph nodes and joint swelling. Rubeola also known as regular measles and the resultant skin rashes are going to generate reddish-brown rash but the symptoms are \"running nose and pyrexia\". Solution Answer: Measels (aka rubeola) and rubella (aka German Measels) are both caused by enveloped single stranded RNA viruses and develop skin rash. Rubella (aka German Measels) disease is only lasts for 3 days whereas \"rubeola\" always lasts for 7 days. Rubella (aka German Measels) is mainly result in light red or spotted for 3 days finally result in swelling of lymph nodes and joint swelling. Rubeola also known as regular measles and the resultant skin rashes are going to generate reddish-brown rash but the symptoms are \"running nose and pyrexia\"..
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
akkhan101
Answer : It very much essential and plays very miportant role in the regulation of the cell cycle, differentiation, growth and cell senescence, all of which are critical to normal development. A class of human genetic syndromes has emerged that are caused by germline mutations in genes which encode components of the Ras/mitogen activated protein kinase (MAPK) pathway. This pathway plays an essential role in the control of the cell cycle and differentiation, therefore its dysregulation has profound developmental consequences. These “RASopathies” exhibit unique phenotypic features, however, many share characteristic overlapping features including craniofacial dysmorphology, cardiac, cutaneous malformations, musculoskeletal and ocular abnormalities, varying degrees of neurocognitive impairment and in some syndromes, an increased risk of developing cancer.Yes it act as second messenger for the ccell cycyle to go on. This RASopathy plays a very important role in the developement of T cells Solution Answer : It very much essential and plays very miportant role in the regulation of the cell cycle, differentiation, growth and cell senescence, all of which are critical to normal development. A class of human genetic syndromes has emerged that are caused by germline mutations in genes which encode components of the Ras/mitogen activated protein kinase (MAPK) pathway. This pathway plays an essential role in the control of the cell cycle and differentiation, therefore its dysregulation has profound developmental consequences. These “RASopathies” exhibit unique phenotypic features, however, many share characteristic overlapping features including craniofacial dysmorphology, cardiac, cutaneous malformations, musculoskeletal and ocular abnormalities, varying degrees of neurocognitive impairment and in some syndromes, an increased risk of developing cancer.Yes it act as second messenger for the ccell cycyle to go on. This RASopathy plays a very important role in the developement of T cells.
Answer It very much essential and plays very miportant role in th.pdf
Answer It very much essential and plays very miportant role in th.pdf
akkhan101
As entropy increases as we move from solid to liquid to gas, so S is clearly negative for B, D and E. In case of no change in the state, the entropy increases with the number of particles, so S is negative for C and positive only for A. Solution As entropy increases as we move from solid to liquid to gas, so S is clearly negative for B, D and E. In case of no change in the state, the entropy increases with the number of particles, so S is negative for C and positive only for A..
As entropy increases as we move from solid to liquid to gas, so S is.pdf
As entropy increases as we move from solid to liquid to gas, so S is.pdf
akkhan101
Advantages of peer to peer networks Reasons why using a server would benefit a home network Solution Advantages of peer to peer networks Reasons why using a server would benefit a home network.
Advantages of peer to peer networksReasons why using a server woul.pdf
Advantages of peer to peer networksReasons why using a server woul.pdf
akkhan101
More from akkhan101
(20)
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
Gene editing of somatic cellsThere are grave concerns regarding th.pdf
Four parts of compare and contrastSolutionFour parts of compar.pdf
Four parts of compare and contrastSolutionFour parts of compar.pdf
Each Restriction enzymes has a unique restriction site and therefore.pdf
Each Restriction enzymes has a unique restriction site and therefore.pdf
correctSolutioncorrect.pdf
correctSolutioncorrect.pdf
Code of main classpublic class LBmain { public static void m.pdf
Code of main classpublic class LBmain { public static void m.pdf
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
BibliographyHall, J. E. (2015). Guyton and Hall textbook of medic.pdf
LiOH is a strong base so we assume it dissociates.pdf
LiOH is a strong base so we assume it dissociates.pdf
With Sp3d hybridization, a seesaw or linear shape.pdf
With Sp3d hybridization, a seesaw or linear shape.pdf
Two-photon transition probability .pdf
Two-photon transition probability .pdf
this is because Nitrogen has a lone pair and and .pdf
this is because Nitrogen has a lone pair and and .pdf
There is no easy way to remember the ionization l.pdf
There is no easy way to remember the ionization l.pdf
My opinion is to carry out in the complete absenc.pdf
My opinion is to carry out in the complete absenc.pdf
cant say anything about no. of molecules, unless .pdf
cant say anything about no. of molecules, unless .pdf
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
C-O (carbonlyl) peaks occur usually around 1500-1.pdf
Boiling points and solubility of alcohols are hig.pdf
Boiling points and solubility of alcohols are hig.pdf
C. Bromobenzene undergoes addition reactions rath.pdf
C. Bromobenzene undergoes addition reactions rath.pdf
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
AnswerMeasels (aka rubeola) and rubella (aka German Measels) are .pdf
Answer It very much essential and plays very miportant role in th.pdf
Answer It very much essential and plays very miportant role in th.pdf
As entropy increases as we move from solid to liquid to gas, so S is.pdf
As entropy increases as we move from solid to liquid to gas, so S is.pdf
Advantages of peer to peer networksReasons why using a server woul.pdf
Advantages of peer to peer networksReasons why using a server woul.pdf
Recently uploaded
The first step to enter the process...
PART A. Introduction to Costumer Service
PART A. Introduction to Costumer Service
PedroFerreira53928
This slide describes the research aptitude of unit 2 in the UGC NET paper I.
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Thiyagu K
The map views are useful for providing a geographical representation of data. They allow users to visualize and analyze the data in a more intuitive manner.
How to Create Map Views in the Odoo 17 ERP
How to Create Map Views in the Odoo 17 ERP
Celine George
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
Jheel Barad
Child centred education is an educational approach that priorities the interest, needs and abilities of the child in the learning process.
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
JosvitaDsouza2
UNA PRESENTACION IMPECABLE DE PHRASAL VERBS
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
MIRIAMSALINAS13
plant breeding method
plant breeding methods in asexually or clonally propagated crops
plant breeding methods in asexually or clonally propagated crops
parmarsneha2
for studentd in cabridge board
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
AzmatAli747758
If you want to make , ppt, dissertation/research, project or any document edit service DM me on what's app 8434381558 E-mail sachingone220@gmail.com I will take charge depend upon how much pages u want
Extraction Of Natural Dye From Beetroot (Beta Vulgaris) And Preparation Of He...
Extraction Of Natural Dye From Beetroot (Beta Vulgaris) And Preparation Of He...
SachinKumar945617
Let us know about Maruti Suzuki, a successful Joint venture in India.
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
bennyroshan06
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
DeeptiGupta154
Geographical themes connected with Taylor Swift's ERAS tour - coming to the UK in June 2024
The geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideas
GeoBlogs
A presentation about a famous track athlete
Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345
beazzy04
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
Synthetic Fiber Construction in lab .pptx
Synthetic Fiber Construction in lab .pptx
Pavel ( NSTU)
Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity Green house effect & Hydrological cycle Types of Ecosystem (1) Natural Ecosystem (2) Artificial Ecosystem component of ecosystem Biotic Components Abiotic Components Producers Consumers Decomposers Functions of Ecosystem Types of Biodiversity Genetic Biodiversity Species Biodiversity Ecological Biodiversity Importance of Biodiversity Hydrological Cycle Green House Effect
Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...
Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...
Denish Jangid
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024. He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
Introduction to Quality Improvement Essentials
Introduction to Quality Improvement Essentials
Excellence Foundation for South Sudan
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
Palestine last event orientationfvgnh .pptx
Palestine last event orientationfvgnh .pptx
RaedMohamed3
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
Thiyagu K
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension. For more information, visit-www.vavaclasses.com
Sectors of the Indian Economy - Class 10 Study Notes pdf
Sectors of the Indian Economy - Class 10 Study Notes pdf
Vivekanand Anglo Vedic Academy
Bills have a main role in point of sale procedure. It will help to track sales, handling payments and giving receipts to customers. Bill splitting also has an important role in POS. For example, If some friends come together for dinner and if they want to divide the bill then it is possible by POS bill splitting. This slide will show how to split bills in odoo 17 POS.
How to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS Module
Celine George
Recently uploaded
(20)
PART A. Introduction to Costumer Service
PART A. Introduction to Costumer Service
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdf
How to Create Map Views in the Odoo 17 ERP
How to Create Map Views in the Odoo 17 ERP
Instructions for Submissions thorugh G- Classroom.pptx
Instructions for Submissions thorugh G- Classroom.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
1.4 modern child centered education - mahatma gandhi-2.pptx
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
plant breeding methods in asexually or clonally propagated crops
plant breeding methods in asexually or clonally propagated crops
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Extraction Of Natural Dye From Beetroot (Beta Vulgaris) And Preparation Of He...
Extraction Of Natural Dye From Beetroot (Beta Vulgaris) And Preparation Of He...
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
MARUTI SUZUKI- A Successful Joint Venture in India.pptx
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
The geography of Taylor Swift - some ideas
The geography of Taylor Swift - some ideas
Sha'Carri Richardson Presentation 202345
Sha'Carri Richardson Presentation 202345
Synthetic Fiber Construction in lab .pptx
Synthetic Fiber Construction in lab .pptx
Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...
Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...
Introduction to Quality Improvement Essentials
Introduction to Quality Improvement Essentials
Palestine last event orientationfvgnh .pptx
Palestine last event orientationfvgnh .pptx
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
Sectors of the Indian Economy - Class 10 Study Notes pdf
Sectors of the Indian Economy - Class 10 Study Notes pdf
How to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS Module
synthesis .pdf
1.
synthesis Solution synthesis
Download now