H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4 Solution H2SO4 ---> 2H+ + SO42- 1 mole of H2SO4 produces 2 moles of H+ ions So [H+ ] = 2* molarity of H2SO4 = 2 * 6M = 12 M HNO3 ---> H+ + NO3- 1 mole of HNO3 produces 1 mole of H+ ion So [H+ ] = 1* Molarity of HNO3 = 1*6M = 6M So there is difference in the [H+ ] ion concentration by taking HNO3 instead of H2SO4.