Suppose you are eating at cafeteria with two friends. You have agreed to the following rule to decide who will pay the bill. Each person will toss a coin. The person who gets a result that is different from the other two will pay the bill. If all the three tosses yield the same result the bill will be shared by all. Find the probability that
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I am Christopher, T.I am a Mathematics Assignment Expert at eduassignmenthelp.com. I hold a PhD. in Mathematics, University of Alberta, Canada. I have been helping students with their Assignments for the past 7 years. I solve assignments related to Mathematics.
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Week 3 Homework (HW3) LANE C5 AND ILLOWSKY C3 AND C4OVERVIEW O.docxcockekeshia
Week 3 Homework (HW3) LANE C5 AND ILLOWSKY C3 AND C4
OVERVIEW OF THIS WEEK’S VERY IMPORTANT CONCEPTS
The important concepts this week are the ADDITION RULE, MULTIPLICATION RULE, PERMUTATIONS, COMBINATIONS AND THE BINOMIAL DISTRIBUTION PROBABILITIES. It’s a lot of new vocabulary and some math. LOT’S OF THIS IS ON THE FINAL EXAM !!
ALWAYS REMEMBER THAT THE HIGHEST PROBABILITY IS 100% OR 1.00 (A SURE THING). IF YOU GET AN ANSWER GREATER THAN 1.00, IT IS WRONG. ALWAYS DO A REALITY CHECK ON YOUR CALCULATED NUMBERS. (THE LOWEST PROBABILITY IS OF COURSE ZERO.) IN PROBABILITY, HOWEVER, LIKE MOST THINGS IS THERE IS NO “SURE THING” IN LIFE (EXCEPT DEATH AND TAXES AS THEY SAY) AND NO “IMPOSSIBILITY” ( YOU COULD WIN THE LOTTERY !!).
LET’S START WITH THE “RULES”:
Always keep in mind that as with relative frequencies all the options MUST add up to 100% or 1.00. None of this works if we leave out an option or possibility.
SUBTRACTION RULE: The probability that event A will NOT occur is equal to 1 minus the probability that event A WILL occur. Not P(A) = 1 - P(A) ( This assumes that there is only ONE option: “A”)
MULTIPLICATION RULE: The probability that Events A and B both occur is equal to the probability that Event A occurs TIMES the probability that Event B occurs, given that A has occurred. THESE EVENTS MUST BE INDEPENDENT, “B” CAN’T DEPEND ON “A” OCCURRING. P(A ∩ B) = P(A) * P(B|A) (The “∩” means “and” and the “∪” means “or” and the “|” means “given that” as in B|A means the probability of B given that A has already occurred AND they are not related – they are “independent”.)
ADDITION RULE: The probability that Event A or Event B occurs is equal to the probability that Event A occurs PLUS (NOT TIMES) the probability that Event B occurs MINUS the probability that both Events A and B occur (DON’T FORGET THIS LAST SUBTRACTION). P(A ∪ B) = P(A) + P(B) - P(A ∩ B) where the P(A ∩ B) means that since we can’t use both the pen and pencil, it’s another option (e.g., write in blood) or could be zero.
AND, since P(A ∩ B) = P( A ) * P( B|A ), the Addition Rule can also be expressed as P(A ∪ B) = P(A) + P(B) - P(A)P( B|A )
An example of the addition rule could be that you take a pen and a pencil to fill out a job application. The probability that you will use the pen (A) is 60%, the pencil (B) is 30% and that you will use both (P(A ∩ B) )is 10% . Note that these probabilities MUST equal 100% ). This also means that the probability that you will use NO writing instrument is 0%, which would be the Subtraction Rule.
Solution
: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), so 0.60 + 0.30 – 0.10 = 0.80 = 80% chance you will use a pen or a pencil (not both and not neither). The P(A ∩ B) means that we since we cannot use BOTH the pen and pencil it means we use neither, hence it’s the 10% chance of this option. Now, if we HAD to use a pen OR pencil then those would add up to the 100% and P(A ∩ B) would be zero.
A second example: .
I am Josh U. I am a Probability Assignment Expert at statisticsassignmenthelp.com. I hold a Masters in Statistics from St. Edward’s University, USA.
I have been helping students with their homework for the past 5 years. I solve assignments related to Probability. Visit statisticsassignmenthelp.com or email info@statisticsassignmenthelp.com.
You can also call on +1 678 648 4277 for any assistance with Probability Assignments.
I am Christopher, T.I am a Mathematics Assignment Expert at eduassignmenthelp.com. I hold a PhD. in Mathematics, University of Alberta, Canada. I have been helping students with their Assignments for the past 7 years. I solve assignments related to Mathematics.
Visit eduassignmenthelp.com or email info@eduassignmenthelp.com . You can also call on +1 678 648 4277 for any assistance with Mathematics Assignments.
Week 3 Homework (HW3) LANE C5 AND ILLOWSKY C3 AND C4OVERVIEW O.docxcockekeshia
Week 3 Homework (HW3) LANE C5 AND ILLOWSKY C3 AND C4
OVERVIEW OF THIS WEEK’S VERY IMPORTANT CONCEPTS
The important concepts this week are the ADDITION RULE, MULTIPLICATION RULE, PERMUTATIONS, COMBINATIONS AND THE BINOMIAL DISTRIBUTION PROBABILITIES. It’s a lot of new vocabulary and some math. LOT’S OF THIS IS ON THE FINAL EXAM !!
ALWAYS REMEMBER THAT THE HIGHEST PROBABILITY IS 100% OR 1.00 (A SURE THING). IF YOU GET AN ANSWER GREATER THAN 1.00, IT IS WRONG. ALWAYS DO A REALITY CHECK ON YOUR CALCULATED NUMBERS. (THE LOWEST PROBABILITY IS OF COURSE ZERO.) IN PROBABILITY, HOWEVER, LIKE MOST THINGS IS THERE IS NO “SURE THING” IN LIFE (EXCEPT DEATH AND TAXES AS THEY SAY) AND NO “IMPOSSIBILITY” ( YOU COULD WIN THE LOTTERY !!).
LET’S START WITH THE “RULES”:
Always keep in mind that as with relative frequencies all the options MUST add up to 100% or 1.00. None of this works if we leave out an option or possibility.
SUBTRACTION RULE: The probability that event A will NOT occur is equal to 1 minus the probability that event A WILL occur. Not P(A) = 1 - P(A) ( This assumes that there is only ONE option: “A”)
MULTIPLICATION RULE: The probability that Events A and B both occur is equal to the probability that Event A occurs TIMES the probability that Event B occurs, given that A has occurred. THESE EVENTS MUST BE INDEPENDENT, “B” CAN’T DEPEND ON “A” OCCURRING. P(A ∩ B) = P(A) * P(B|A) (The “∩” means “and” and the “∪” means “or” and the “|” means “given that” as in B|A means the probability of B given that A has already occurred AND they are not related – they are “independent”.)
ADDITION RULE: The probability that Event A or Event B occurs is equal to the probability that Event A occurs PLUS (NOT TIMES) the probability that Event B occurs MINUS the probability that both Events A and B occur (DON’T FORGET THIS LAST SUBTRACTION). P(A ∪ B) = P(A) + P(B) - P(A ∩ B) where the P(A ∩ B) means that since we can’t use both the pen and pencil, it’s another option (e.g., write in blood) or could be zero.
AND, since P(A ∩ B) = P( A ) * P( B|A ), the Addition Rule can also be expressed as P(A ∪ B) = P(A) + P(B) - P(A)P( B|A )
An example of the addition rule could be that you take a pen and a pencil to fill out a job application. The probability that you will use the pen (A) is 60%, the pencil (B) is 30% and that you will use both (P(A ∩ B) )is 10% . Note that these probabilities MUST equal 100% ). This also means that the probability that you will use NO writing instrument is 0%, which would be the Subtraction Rule.
Solution
: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), so 0.60 + 0.30 – 0.10 = 0.80 = 80% chance you will use a pen or a pencil (not both and not neither). The P(A ∩ B) means that we since we cannot use BOTH the pen and pencil it means we use neither, hence it’s the 10% chance of this option. Now, if we HAD to use a pen OR pencil then those would add up to the 100% and P(A ∩ B) would be zero.
A second example: .
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Suppose you are eating at cafeteria with two friends.docx
1. Suppose you are eating at cafeteria with two friends. You have
agreed to the following rule to decide who will pay the bill.
Each person will toss a coin. The person who gets a result that is
different from the other two will pay the bill. If all the three
tosses yield the same result the bill will be shared by all. Find
the probability that
(a) Only you have to pay
(b) All three will share.
Solution
𝑺 = {𝑯𝑯𝑯, 𝑯𝑯𝑻, 𝑯𝑻𝑯, 𝑯𝑻𝑻, 𝑻𝑯𝑯, 𝑻𝑯𝑻, 𝑻𝑻𝑯, 𝑻𝑻𝑻}
𝒏(𝑺) = 𝟖
(a) Probability of each person to pay the bill is
𝟏
𝟑
.
Let A be the event that any one’s result is different
from others.
𝑨 = {𝑯𝑯𝑻, 𝑯𝑻𝑯, 𝑯𝑻𝑻, 𝑻𝑯𝑯, 𝑻𝑯𝑻, 𝑻𝑻𝑯}
𝒏(𝑨) = 𝟔
2. 𝑷(𝑨) =
𝒏(𝑨)
𝒏(𝑺)
=
𝟔
𝟖
𝑵𝒐𝒘 𝒕𝒉𝒆 𝒑𝒓𝒐𝒃𝒂𝒃𝒊𝒍𝒊𝒕𝒚 𝒕𝒉𝒂𝒕 𝒐𝒏𝒍𝒚 𝒚𝒐𝒖 𝒉𝒂𝒗𝒆 𝒕𝒐 𝒑𝒂𝒚 𝒕𝒉𝒆 𝒃𝒊𝒍𝒍
= 𝑷(𝑨) ×
𝟏
𝟑
=
𝟔
𝟖
×
𝟏
𝟑
= 𝟎. 𝟐𝟓 = 𝟐𝟓%
There is 25% chance, that only you will pay the bill.
(b) Let B be the event that all three will share the bill.
If all the three tosses yield the same result the bill will
be shared by all.
𝑩 = {𝑯𝑯𝑯, 𝑻𝑻𝑻}
𝒏(𝑩) = 𝟐
𝑷(𝑩) =
𝒏(𝑩)
𝒏(𝑺)
=
𝟐
𝟖
= 𝟎. 𝟐𝟓 = 𝟐𝟓%
There is 25% chance, that bill will be shared by all.