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Aggregating Data
Using Group Functions
Objectives
• After completing this lesson, you should
be able to do the following:
– Identify the available group functions
– Describe the use of group functions
– Group data using the GROUP BY clause
– Include or exclude grouped rows by using
the HAVING clause
What Are Group Functions?
• Group functions operate on sets of rows to give
one result per group.
EMP
“maximum
salary in
the EMP table”
DEPTNO SAL
--------- ---------
10 2450
10 5000
10 1300
20 800
20 1100
20 3000
20 3000
20 2975
30 1600
30 2850
30 1250
30 950
30 1500
30 1250
MAX(SAL)
---------
5000
Types of Group Functions
– AVG
– COUNT
– MAX
– MIN
– SUM
Using Group Functions
SELECT [column,] group_function(column)
FROM table
[WHERE condition]
[GROUP BY column]
[ORDER BY column];
Using AVG and SUM Functions
AVG(SAL) MAX(SAL) MIN(SAL) SUM(SAL)
-------- --------- --------- ---------
1400 1600 1250 5600
• You can use AVG and SUM for numeric data.
SQL> SELECT AVG(sal), MAX(sal),
2 MIN(sal), SUM(sal)
3 FROM emp
4 WHERE job LIKE 'SALES%';
Using MIN and MAX Functions
• You can use MIN and MAX for any
datatype.
SQL> SELECT MIN(hiredate), MAX(hiredate)
2 FROM emp;
MIN(HIRED MAX(HIRED
--------- ---------
17-DEC-80 12-JAN-83
Using the COUNT Function
COUNT(*)
---------
6
SQL> SELECT COUNT(*)
2 FROM emp
3 WHERE deptno = 30;
• COUNT(*) returns the number of rows in a
table.
Using the COUNT Function
• COUNT(expr) returns the number of
nonnull rows.
SQL> SELECT COUNT(comm)
2 FROM emp
3 WHERE deptno = 30;
COUNT(COMM)
-----------
4
Group Functions and Null
Values
• Group functions ignore null values in the
column.
SQL> SELECT AVG(comm)
2 FROM emp;
AVG(COMM)
---------
550
Using the NVL Function
with Group Functions
• The NVL function forces group functions to
include null values.
SQL> SELECT AVG(NVL(comm,0))
2 FROM emp;
AVG(NVL(COMM,0))
----------------
157.14286
Creating Groups of Data
EMP
“average
salary
in EMP
table
for each
department”
2916.6667
2175
1566.6667
DEPTNO SAL
--------- ---------
10 2450
10 5000
10 1300
20 800
20 1100
20 3000
20 3000
20 2975
30 1600
30 2850
30 1250
30 950
30 1500
30 1250
DEPTNO AVG(SAL)
------- ---------
10 2916.6667
20 2175
30 1566.6667
Creating Groups of Data:
GROUP BY Clause
SELECT column, group_function(column)
FROM table
[WHERE condition]
[GROUP BY group_by_expression]
[ORDER BY column];
• Divide rows in a table into smaller groups
by using the GROUP BY clause.
Using the GROUP BY Clause
• All columns in the SELECT list that are
not in group functions must be in the
GROUP BY clause.
SQL> SELECT deptno, AVG(sal)
2 FROM emp
3 GROUP BY deptno;
DEPTNO AVG(SAL)
--------- ---------
10 2916.6667
20 2175
30 1566.6667
Using the GROUP BY Clause
• The GROUP BY column does not have to
be in the SELECT list.
SQL> SELECT AVG(sal)
2 FROM emp
3 GROUP BY deptno;
AVG(SAL)
---------
2916.6667
2175
1566.6667
Grouping by More
Than One Column
EMP
“sum salaries in
the EMP table
for each job,
grouped by
department”
DEPTNO JOB SAL
--------- --------- ---------
10 MANAGER 2450
10 PRESIDENT 5000
10 CLERK 1300
20 CLERK 800
20 CLERK 1100
20 ANALYST 3000
20 ANALYST 3000
20 MANAGER 2975
30 SALESMAN 1600
30 MANAGER 2850
30 SALESMAN 1250
30 CLERK 950
30 SALESMAN 1500
30 SALESMAN 1250
JOB SUM(SAL)
--------- ---------
CLERK 1300
MANAGER 2450
PRESIDENT 5000
ANALYST 6000
CLERK 1900
MANAGER 2975
CLERK 950
MANAGER 2850
SALESMAN 5600
DEPTNO
--------
10
10
10
20
20
20
30
30
30
Using the GROUP BY Clause
on Multiple Columns
SQL> SELECT deptno, job, sum(sal)
2 FROM emp
3 GROUP BY deptno, job;
DEPTNO JOB SUM(SAL)
--------- --------- ---------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
20 ANALYST 6000
20 CLERK 1900
...
9 rows selected.
Illegal Queries
Using Group Functions
• Any column or expression in the SELECT
list that is not an aggregate function must
be in the GROUP BY clause.
SQL> SELECT deptno, COUNT(ename)
2 FROM emp;
SELECT deptno, COUNT(ename)
*
ERROR at line 1:
ORA-00937: not a single-group group function
Illegal Queries
Using Group Functions
– You cannot use the WHERE clause to restrict groups.
– You use the HAVING clause to restrict groups.
SQL> SELECT deptno, AVG(sal)
2 FROM emp
3 WHERE AVG(sal) > 2000
4 GROUP BY deptno;
WHERE AVG(sal) > 2000
*
ERROR at line 3:
ORA-00934: group function is not allowed here
Excluding Group Results
“maximum
salary
per department
greater than
$2900”
EMP
5000
3000
2850
DEPTNO SAL
--------- ---------
10 2450
10 5000
10 1300
20 800
20 1100
20 3000
20 3000
20 2975
30 1600
30 2850
30 1250
30 950
30 1500
30 1250
DEPTNO MAX(SAL)
--------- ---------
10 5000
20 3000
Excluding Group Results:
HAVING Clause
• Use the HAVING clause to restrict groups
• Rows are grouped.
• The group function is applied.
• Groups matching the HAVING clause are
displayed.
SELECT column, group_function
FROM table
[WHERE condition]
[GROUP BY group_by_expression]
[HAVING group_condition]
[ORDER BY column];
Using the HAVING Clause
SQL> SELECT deptno, max(sal)
2 FROM emp
3 GROUP BY deptno
4 HAVING max(sal)>2900;
DEPTNO MAX(SAL)
--------- ---------
10 5000
20 3000
Using the HAVING Clause
SQL> SELECT job, SUM(sal) PAYROLL
2 FROM emp
3 WHERE job NOT LIKE 'SALES%'
4 GROUP BY job
5 HAVING SUM(sal)>5000
6 ORDER BY SUM(sal);
JOB PAYROLL
--------- ---------
ANALYST 6000
MANAGER 8275
Nesting Group Functions
SQL> SELECT max(avg(sal))
2 FROM emp
3 GROUP BY deptno;
MAX(AVG(SAL))
-------------
2916.6667
• Display the maximum average salary.
Summary
SELECT column, group_function(column)
FROM table
[WHERE condition]
[GROUP BY group_by_expression]
[HAVING group_condition]
[ORDER BY column];
• Order of evaluation of the clauses:
– WHERE clause
– GROUP BY clause
– HAVING clause
Practice Overview
– Showing different queries that use group functions
– Grouping by rows to achieve more than one result
– Excluding groups by using the HAVING clause

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SQL5.ppt

  • 2. Objectives • After completing this lesson, you should be able to do the following: – Identify the available group functions – Describe the use of group functions – Group data using the GROUP BY clause – Include or exclude grouped rows by using the HAVING clause
  • 3. What Are Group Functions? • Group functions operate on sets of rows to give one result per group. EMP “maximum salary in the EMP table” DEPTNO SAL --------- --------- 10 2450 10 5000 10 1300 20 800 20 1100 20 3000 20 3000 20 2975 30 1600 30 2850 30 1250 30 950 30 1500 30 1250 MAX(SAL) --------- 5000
  • 4. Types of Group Functions – AVG – COUNT – MAX – MIN – SUM
  • 5. Using Group Functions SELECT [column,] group_function(column) FROM table [WHERE condition] [GROUP BY column] [ORDER BY column];
  • 6. Using AVG and SUM Functions AVG(SAL) MAX(SAL) MIN(SAL) SUM(SAL) -------- --------- --------- --------- 1400 1600 1250 5600 • You can use AVG and SUM for numeric data. SQL> SELECT AVG(sal), MAX(sal), 2 MIN(sal), SUM(sal) 3 FROM emp 4 WHERE job LIKE 'SALES%';
  • 7. Using MIN and MAX Functions • You can use MIN and MAX for any datatype. SQL> SELECT MIN(hiredate), MAX(hiredate) 2 FROM emp; MIN(HIRED MAX(HIRED --------- --------- 17-DEC-80 12-JAN-83
  • 8. Using the COUNT Function COUNT(*) --------- 6 SQL> SELECT COUNT(*) 2 FROM emp 3 WHERE deptno = 30; • COUNT(*) returns the number of rows in a table.
  • 9. Using the COUNT Function • COUNT(expr) returns the number of nonnull rows. SQL> SELECT COUNT(comm) 2 FROM emp 3 WHERE deptno = 30; COUNT(COMM) ----------- 4
  • 10. Group Functions and Null Values • Group functions ignore null values in the column. SQL> SELECT AVG(comm) 2 FROM emp; AVG(COMM) --------- 550
  • 11. Using the NVL Function with Group Functions • The NVL function forces group functions to include null values. SQL> SELECT AVG(NVL(comm,0)) 2 FROM emp; AVG(NVL(COMM,0)) ---------------- 157.14286
  • 12. Creating Groups of Data EMP “average salary in EMP table for each department” 2916.6667 2175 1566.6667 DEPTNO SAL --------- --------- 10 2450 10 5000 10 1300 20 800 20 1100 20 3000 20 3000 20 2975 30 1600 30 2850 30 1250 30 950 30 1500 30 1250 DEPTNO AVG(SAL) ------- --------- 10 2916.6667 20 2175 30 1566.6667
  • 13. Creating Groups of Data: GROUP BY Clause SELECT column, group_function(column) FROM table [WHERE condition] [GROUP BY group_by_expression] [ORDER BY column]; • Divide rows in a table into smaller groups by using the GROUP BY clause.
  • 14. Using the GROUP BY Clause • All columns in the SELECT list that are not in group functions must be in the GROUP BY clause. SQL> SELECT deptno, AVG(sal) 2 FROM emp 3 GROUP BY deptno; DEPTNO AVG(SAL) --------- --------- 10 2916.6667 20 2175 30 1566.6667
  • 15. Using the GROUP BY Clause • The GROUP BY column does not have to be in the SELECT list. SQL> SELECT AVG(sal) 2 FROM emp 3 GROUP BY deptno; AVG(SAL) --------- 2916.6667 2175 1566.6667
  • 16. Grouping by More Than One Column EMP “sum salaries in the EMP table for each job, grouped by department” DEPTNO JOB SAL --------- --------- --------- 10 MANAGER 2450 10 PRESIDENT 5000 10 CLERK 1300 20 CLERK 800 20 CLERK 1100 20 ANALYST 3000 20 ANALYST 3000 20 MANAGER 2975 30 SALESMAN 1600 30 MANAGER 2850 30 SALESMAN 1250 30 CLERK 950 30 SALESMAN 1500 30 SALESMAN 1250 JOB SUM(SAL) --------- --------- CLERK 1300 MANAGER 2450 PRESIDENT 5000 ANALYST 6000 CLERK 1900 MANAGER 2975 CLERK 950 MANAGER 2850 SALESMAN 5600 DEPTNO -------- 10 10 10 20 20 20 30 30 30
  • 17. Using the GROUP BY Clause on Multiple Columns SQL> SELECT deptno, job, sum(sal) 2 FROM emp 3 GROUP BY deptno, job; DEPTNO JOB SUM(SAL) --------- --------- --------- 10 CLERK 1300 10 MANAGER 2450 10 PRESIDENT 5000 20 ANALYST 6000 20 CLERK 1900 ... 9 rows selected.
  • 18. Illegal Queries Using Group Functions • Any column or expression in the SELECT list that is not an aggregate function must be in the GROUP BY clause. SQL> SELECT deptno, COUNT(ename) 2 FROM emp; SELECT deptno, COUNT(ename) * ERROR at line 1: ORA-00937: not a single-group group function
  • 19. Illegal Queries Using Group Functions – You cannot use the WHERE clause to restrict groups. – You use the HAVING clause to restrict groups. SQL> SELECT deptno, AVG(sal) 2 FROM emp 3 WHERE AVG(sal) > 2000 4 GROUP BY deptno; WHERE AVG(sal) > 2000 * ERROR at line 3: ORA-00934: group function is not allowed here
  • 20. Excluding Group Results “maximum salary per department greater than $2900” EMP 5000 3000 2850 DEPTNO SAL --------- --------- 10 2450 10 5000 10 1300 20 800 20 1100 20 3000 20 3000 20 2975 30 1600 30 2850 30 1250 30 950 30 1500 30 1250 DEPTNO MAX(SAL) --------- --------- 10 5000 20 3000
  • 21. Excluding Group Results: HAVING Clause • Use the HAVING clause to restrict groups • Rows are grouped. • The group function is applied. • Groups matching the HAVING clause are displayed. SELECT column, group_function FROM table [WHERE condition] [GROUP BY group_by_expression] [HAVING group_condition] [ORDER BY column];
  • 22. Using the HAVING Clause SQL> SELECT deptno, max(sal) 2 FROM emp 3 GROUP BY deptno 4 HAVING max(sal)>2900; DEPTNO MAX(SAL) --------- --------- 10 5000 20 3000
  • 23. Using the HAVING Clause SQL> SELECT job, SUM(sal) PAYROLL 2 FROM emp 3 WHERE job NOT LIKE 'SALES%' 4 GROUP BY job 5 HAVING SUM(sal)>5000 6 ORDER BY SUM(sal); JOB PAYROLL --------- --------- ANALYST 6000 MANAGER 8275
  • 24. Nesting Group Functions SQL> SELECT max(avg(sal)) 2 FROM emp 3 GROUP BY deptno; MAX(AVG(SAL)) ------------- 2916.6667 • Display the maximum average salary.
  • 25. Summary SELECT column, group_function(column) FROM table [WHERE condition] [GROUP BY group_by_expression] [HAVING group_condition] [ORDER BY column]; • Order of evaluation of the clauses: – WHERE clause – GROUP BY clause – HAVING clause
  • 26. Practice Overview – Showing different queries that use group functions – Grouping by rows to achieve more than one result – Excluding groups by using the HAVING clause