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17.1 Species diversity
Need calculators 
Learning outcomes
Students should be able to understand the following:
 Diversity may relate to the number of species present in a community.
 An index of diversity describes the relationship between the number of
species and the number of individuals in a community.
 Calculation of an index of diversity from the formula
d = N (N – 1)
Σ n (n – 1)
where N = total number of organisms of all species
and n = total number of organisms of each species
Candidates should be able to
 calculate the index of diversity from suitable data
Definitions
Biodiversity – the general term used to describe variety
in the living world. It has 3 components:
 Species diversity – the number of different species
and the abundance of each species within a
community.
 Genetic diversity – the variety of genes possessed by
individuals that make up any one species.
 Ecosystem diversity – the range of different habitats
within a particular area.
Species diversity
 The higher the species diversity of plants and trees in
an area, the higher the species diversity of insects ,
animals and birds. Why?
 This is because there are more habitats and a larger
more varied food source.
 Species diversity can be measured using the ‘index of
diversity’ – it takes into account different population
sizes.
Index of diversity (d)
d = N ( N – 1 )
n ( n – 1 )
N = total number of organisms of all species
n = total number of one species
The higher the number the more diverse the area is.
If all the individuals are of the same species (i.e. no
diversity) the index is 1.
Index of diversity (d)
 If we want to calculate the index of diversity for two
habitats we must first calculate the n( n – 1 ) for each
species in each habitat.
Species found
Numbers found in
habitat X
Numbers found in
habitat Y
A 10 3
B 10 5
C 10 2
D 10 36
E 10 4
No of species 5 5
No of individuals 50 50
d = N( N – 1 )
n( n – 1 )
Index of diversity (d)
Species
found
Numbers found
in habitat X n(n-1)
Numbers found
in habitat Y n(n-1)
A 10 10(9) = 90 3 3(2) = 6
B 10 10(9) = 90 5 5(4) = 20
C 10 10(9) = 90 2 2(1) = 2
D 10 10(9) = 90 36 36(35) = 1260
E 10 10(9) = 90 4 4(3) = 12
n(n-1) 450 n(n-1) 1300
We can now calculate the species diversity for each habitat:
Habitat X d = 50(49) = 2450 = 5.44
450 450
Habitat Y d = 50(49) = 2450 = 1.88
1300 1300
d = N( N – 1 )
n( n – 1 )
Index of diversity (d) - Task
P227 Answer the summary questions
1. What is meant by species diversity?
2. Calculate the index of diversity, show your working.
3. Explain why it is more useful to calculate a species diversity index
than just record the number of species present.
species numbers in salt marsh
Salicornia maritima 24
Halimione portulacoides 20
Festuca rubra 7
Aster tripolium 3
Limonium humile 3
Suaeda maritima 1
Index of diversity (d) - Task
1. The number of different species and the proportion of each species
within a given area/community.
2.
d = 58(57) = 3306 = 3.35
986 986
3. It measures both the number of species and the number of
individuals. It therefore takes account of species that are only present
in small numbers.
species numbers in salt marsh n(n-1)
Salicornia maritima 24 24(23) = 552
Halimione portulacoides 20 20(19) = 380
Festuca rubra 7 7(6) = 42
Aster tripolium 3 3(2) = 6
Limonium humile 3 3(2) = 6
Suaeda maritima 1 1(0) = 0
n(n-1) 986
Biodiversity
Biodiversity reflects how well an ecosystem functions.
The higher the species diversity the more stable the
ecosystem and the less it is affected by climate change.
E.g. A community with a high species diversity is more
likely to have at least one species able to tolerate a
change in climate conditions (drought) .
Biodiversity
In extreme environments the species diversity is
normally low as only a few species will have the
necessary adaptations to survive.
 Here to ecosystem is unstable and dominated by
climatic factors rather than by the organisms within
the community.
Biodiversity
In less harsh environments the species diversity is
normally high.
 Here the ecosystem is stable and dominated by living
organisms rather than the climate.
Learning outcomes
Students should be able to understand the following:
 Diversity may relate to the number of species present in a community.
 An index of diversity describes the relationship between the number of
species and the number of individuals in a community.
 Calculation of an index of diversity from the formula
d = N (N – 1)
Σ n (n – 1)
where N = total number of organisms of all species
and n = total number of organisms of each species
Candidates should be able to
 calculate the index of diversity from suitable data

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SPECIES DIVERSITY FOR HIGH SCHOOL STUDENTS

  • 1. 17.1 Species diversity Need calculators 
  • 2. Learning outcomes Students should be able to understand the following:  Diversity may relate to the number of species present in a community.  An index of diversity describes the relationship between the number of species and the number of individuals in a community.  Calculation of an index of diversity from the formula d = N (N – 1) Σ n (n – 1) where N = total number of organisms of all species and n = total number of organisms of each species Candidates should be able to  calculate the index of diversity from suitable data
  • 3. Definitions Biodiversity – the general term used to describe variety in the living world. It has 3 components:  Species diversity – the number of different species and the abundance of each species within a community.  Genetic diversity – the variety of genes possessed by individuals that make up any one species.  Ecosystem diversity – the range of different habitats within a particular area.
  • 4. Species diversity  The higher the species diversity of plants and trees in an area, the higher the species diversity of insects , animals and birds. Why?  This is because there are more habitats and a larger more varied food source.  Species diversity can be measured using the ‘index of diversity’ – it takes into account different population sizes.
  • 5. Index of diversity (d) d = N ( N – 1 ) n ( n – 1 ) N = total number of organisms of all species n = total number of one species The higher the number the more diverse the area is. If all the individuals are of the same species (i.e. no diversity) the index is 1.
  • 6. Index of diversity (d)  If we want to calculate the index of diversity for two habitats we must first calculate the n( n – 1 ) for each species in each habitat. Species found Numbers found in habitat X Numbers found in habitat Y A 10 3 B 10 5 C 10 2 D 10 36 E 10 4 No of species 5 5 No of individuals 50 50 d = N( N – 1 ) n( n – 1 )
  • 7. Index of diversity (d) Species found Numbers found in habitat X n(n-1) Numbers found in habitat Y n(n-1) A 10 10(9) = 90 3 3(2) = 6 B 10 10(9) = 90 5 5(4) = 20 C 10 10(9) = 90 2 2(1) = 2 D 10 10(9) = 90 36 36(35) = 1260 E 10 10(9) = 90 4 4(3) = 12 n(n-1) 450 n(n-1) 1300 We can now calculate the species diversity for each habitat: Habitat X d = 50(49) = 2450 = 5.44 450 450 Habitat Y d = 50(49) = 2450 = 1.88 1300 1300 d = N( N – 1 ) n( n – 1 )
  • 8. Index of diversity (d) - Task P227 Answer the summary questions 1. What is meant by species diversity? 2. Calculate the index of diversity, show your working. 3. Explain why it is more useful to calculate a species diversity index than just record the number of species present. species numbers in salt marsh Salicornia maritima 24 Halimione portulacoides 20 Festuca rubra 7 Aster tripolium 3 Limonium humile 3 Suaeda maritima 1
  • 9. Index of diversity (d) - Task 1. The number of different species and the proportion of each species within a given area/community. 2. d = 58(57) = 3306 = 3.35 986 986 3. It measures both the number of species and the number of individuals. It therefore takes account of species that are only present in small numbers. species numbers in salt marsh n(n-1) Salicornia maritima 24 24(23) = 552 Halimione portulacoides 20 20(19) = 380 Festuca rubra 7 7(6) = 42 Aster tripolium 3 3(2) = 6 Limonium humile 3 3(2) = 6 Suaeda maritima 1 1(0) = 0 n(n-1) 986
  • 10. Biodiversity Biodiversity reflects how well an ecosystem functions. The higher the species diversity the more stable the ecosystem and the less it is affected by climate change. E.g. A community with a high species diversity is more likely to have at least one species able to tolerate a change in climate conditions (drought) .
  • 11. Biodiversity In extreme environments the species diversity is normally low as only a few species will have the necessary adaptations to survive.  Here to ecosystem is unstable and dominated by climatic factors rather than by the organisms within the community.
  • 12. Biodiversity In less harsh environments the species diversity is normally high.  Here the ecosystem is stable and dominated by living organisms rather than the climate.
  • 13. Learning outcomes Students should be able to understand the following:  Diversity may relate to the number of species present in a community.  An index of diversity describes the relationship between the number of species and the number of individuals in a community.  Calculation of an index of diversity from the formula d = N (N – 1) Σ n (n – 1) where N = total number of organisms of all species and n = total number of organisms of each species Candidates should be able to  calculate the index of diversity from suitable data