RainfallTest.javaimport java.util.Arrays; import java.util.Scann.pdf
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RainfallTest.java import java.util.Arrays; import java.util.Scanner; public class RainFallDetails { static String month[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\", \"July\", \"August\", \"September\",\"October\",\"November\",\"December\"}; public static void main(String[] args) { int months[] = new int[12]; Scanner scan = new Scanner(System.in); for(int i=0; i months[i]){ min = months[i]; minIndex = i; } } System.out.println(\"The minimum rainfall is :\"+min); System.out.println(\"The minimum rainfall month is :\"+month[minIndex]); } } Output: Enter Rainfall for the month 1: 33 Enter Rainfall for the month 2: 22 Enter Rainfall for the month 3: 11 Enter Rainfall for the month 4: 44 Enter Rainfall for the month 5: 55 Enter Rainfall for the month 6: 66 Enter Rainfall for the month 7: 77 Enter Rainfall for the month 8: 88 Enter Rainfall for the month 9: 99 Enter Rainfall for the month 10: 12 Enter Rainfall for the month 11: 14 Enter Rainfall for the month 12: 15 Entered rainfall details [33, 22, 11, 44, 55, 66, 77, 88, 99, 12, 14, 15] January: 33 Fabruary: 22 March: 11 April: 44 May: 55 June: 66 July: 77 August: 88 September: 99 October: 12 November: 14 December: 15 The total rainfall is :536 The average rainfall is :44.666666666666664 The maximum rainfall is :99 The maximum rainfall month is :September The minimum rainfall is :11 The minimum rainfall month is :March Solution RainfallTest.java import java.util.Arrays; import java.util.Scanner; public class RainFallDetails { static String month[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\", \"July\", \"August\", \"September\",\"October\",\"November\",\"December\"}; public static void main(String[] args) { int months[] = new int[12]; Scanner scan = new Scanner(System.in); for(int i=0; i months[i]){ min = months[i]; minIndex = i; } } System.out.println(\"The minimum rainfall is :\"+min); System.out.println(\"The minimum rainfall month is :\"+month[minIndex]); } } Output: Enter Rainfall for the month 1: 33 Enter Rainfall for the month 2: 22 Enter Rainfall for the month 3: 11 Enter Rainfall for the month 4: 44 Enter Rainfall for the month 5: 55 Enter Rainfall for the month 6: 66 Enter Rainfall for the month 7: 77 Enter Rainfall for the month 8: 88 Enter Rainfall for the month 9: 99 Enter Rainfall for the month 10: 12 Enter Rainfall for the month 11: 14 Enter Rainfall for the month 12: 15 Entered rainfall details [33, 22, 11, 44, 55, 66, 77, 88, 99, 12, 14, 15] January: 33 Fabruary: 22 March: 11 April: 44 May: 55 June: 66 July: 77 August: 88 September: 99 October: 12 November: 14 December: 15 The total rainfall is :536 The average rainfall is :44.666666666666664 The maximum rainfall is :99 The maximum rainfall month is :September The minimum rainfall is :11 The minimum rainfall month is :March.
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![RainfallTest.java
import java.util.Arrays;
import java.util.Scanner;
public class RainFallDetails {
static String month[] = {"January", "Fabruary", "March", "April", "May", "June",
"July", "August", "September","October","November","December"};
public static void main(String[] args) {
int months[] = new int[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println("The minimum rainfall is :"+min);
System.out.println("The minimum rainfall month is :"+month[minIndex]);
}
}
Output:
Enter Rainfall for the month 1:
33
Enter Rainfall for the month 2:
22
Enter Rainfall for the month 3:
11
Enter Rainfall for the month 4:
44
Enter Rainfall for the month 5:
55
Enter Rainfall for the month 6:
66](https://image.slidesharecdn.com/rainfalltest-230409040752-1b970b9c/85/RainfallTest-javaimport-java-util-Arrays-import-java-util-Scann-pdf-1-320.jpg)
![Enter Rainfall for the month 7:
77
Enter Rainfall for the month 8:
88
Enter Rainfall for the month 9:
99
Enter Rainfall for the month 10:
12
Enter Rainfall for the month 11:
14
Enter Rainfall for the month 12:
15
Entered rainfall details [33, 22, 11, 44, 55, 66, 77, 88, 99, 12, 14, 15]
January: 33
Fabruary: 22
March: 11
April: 44
May: 55
June: 66
July: 77
August: 88
September: 99
October: 12
November: 14
December: 15
The total rainfall is :536
The average rainfall is :44.666666666666664
The maximum rainfall is :99
The maximum rainfall month is :September
The minimum rainfall is :11
The minimum rainfall month is :March
Solution
RainfallTest.java
import java.util.Arrays;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
RainFall.java public class RainFall { private double months.pdf
RainFall.java
public class RainFall {
private double months[];
String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public RainFall(double d[]){
months = d;
}
public void displayTotalRainFall(){
double total = 0;
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println(\"The minimum rainfall is :\"+min);
System.out.println(\"The minimum rainfall month is :\"+monthStr[minIndex]);
}
}
RainFallTest.java
import java.util.Scanner;
public class RainFallTest {
static String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public static void main(String[] args) {
double month[] = new double[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i
Solution
RainFall.java
public class RainFall {
private double months[];
String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public RainFall(double d[]){
months = d;
}
public void displayTotalRainFall(){
double total = 0;
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println(\"The minimum rainfall is :\"+min);
System.out.println(\"The minimum rainfall month is :\"+monthStr[minIndex]);
}
}
RainFallTest.java
import java.util.Scanner;
public class RainFallTest {
static String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public static void main(String[] args) {
double month[] = new double[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i.
import java.util.Scanner; public class Rainfall {Scanner s=new.pdf
import java.util.Scanner;
public class Rainfall
{
Scanner s=new Scanner(System.in);
private double months[] = new double[12];
Rainfall(double months[])
{
this.months=months;
}
public void setRainfall()
{
System.out.println(\"enter rainfalll for each month \");
for(int i=0;i<12;i++)
{
inner:
System.out.println(\"Month \"+(i+1)+\" rainfall :\");
months[i]=s.nextDouble();
if(months[i]<0.0)
{
System.out.println(\"invalid value .... please enter again\");
continue inner;
}
else continue;
}
}
public void getRainfall()
{
for(int i=0;i<12;i++)
{
System.out.println(\"Month \"+(i+1)+\" rainfall :\"+
months[i]);
}
}
public double totalYearRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total;
}
public double averageMonthlyRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total/12;
}
public int monthLeastRainfall()
{
double min=0.0;
int month;
for(int i=0;i<12;i++)
{
if(month[i]max)
{
max=month[i];
month=i+1;
}
}
return month;
}
}
public class TestRainfall
{
public static void main(String args[])
{
Rainfall r = new Rainfall();
r.setRainfall();
r.getRainfall();
r.totalYearRainfall();
r.averageMonthlyRainfall();
r.monthLeastRainfall();
r.monthMostRainfall();
}
}
Solution
import java.util.Scanner;
public class Rainfall
{
Scanner s=new Scanner(System.in);
private double months[] = new double[12];
Rainfall(double months[])
{
this.months=months;
}
public void setRainfall()
{
System.out.println(\"enter rainfalll for each month \");
for(int i=0;i<12;i++)
{
inner:
System.out.println(\"Month \"+(i+1)+\" rainfall :\");
months[i]=s.nextDouble();
if(months[i]<0.0)
{
System.out.println(\"invalid value .... please enter again\");
continue inner;
}
else continue;
}
}
public void getRainfall()
{
for(int i=0;i<12;i++)
{
System.out.println(\"Month \"+(i+1)+\" rainfall :\"+
months[i]);
}
}
public double totalYearRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total;
}
public double averageMonthlyRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total/12;
}
public int monthLeastRainfall()
{
double min=0.0;
int month;
for(int i=0;i<12;i++)
{
if(month[i]max)
{
max=month[i];
month=i+1;
}
}
return month;
}
}
public class TestRainfall
{
public static void main(String args[])
{
Rainfall r = new Rainfall();
r.setRainfall();
r.getRainfall();
r.totalYearRainfall();
r.averageMonthlyRainfall();
r.monthLeastRainfall();
r.monthMostRainfall();
}
}.
Oot practical
The document contains 10 Java programs to solve common mathematical and logical problems:
1) A program to calculate the factorial of a number.
2) A program to add two matrices.
3) A program to calculate the sum of two numbers.
4) A program to reverse a number.
5) A program to check if a number is an Armstrong number.
6) A program to find the largest of three numbers.
7) A program to output the current date and time.
8) A program to check if a string is a palindrome.
9) A program to print prime numbers up to a given limit.
10) A program to swap two numbers.
import java.util.Scanner; import java.text.; public class Ave.pdf
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j
Solution
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j.
Java Language.....pdf
It\'s theoretically possible that naturally occurring (contaminating) bacteria that happen to be
ampicillin resistant could be yielding the colonies observed. Describe a NEGATIVE CONTROL
experiment that could be run in parallel to test for this possibility?
Solution
In this case for making negative control one must take bacteria present in its natural condition
where no transfer of ampicillin resistant gene has been done. As and when this condition is
maintained where bacteria lacks ampicillin resistant gene, then by applying ampicillin from
outside during plating of bacteria the population density seems to decrease. This clearly shows
lack of ampicillin resistivity hence NEGATIVE CONTROL experiment gets completed..
Write a Java ProgramSolutionAnswer- Code- import java-io--- import jav.docx
This Java program allows a user to input employee data including name, type of employee (hourly or salaried), hourly rate, hours worked, and regular pay. It then calculates the income for hourly employees based on hours worked and overtime pay, and calculates income for salaried employees based on regular pay and hourly rate. The program outputs the employee name and calculated income.
Lab101.pptx
The document contains 12 code examples for Java programs that perform various tasks like greeting a user, calculating triangle area, printing even numbers, generating Fibonacci sequences, calculating factorials, determining if a number is even/odd, comparing two numbers, determining if a number is positive/negative, generating a multiplication table, and reversing a string. Each code example demonstrates the use of basic Java concepts like variables, conditionals, loops, methods, and classes to solve common programming problems.
import java.text.SimpleDateFormat; import java.util.Calendar; import.pdf
import java.text.SimpleDateFormat; import java.util.Calendar; import
java.util.GregorianCalendar; import java.util.Scanner; class Main { private static Scanner
input; public static void main(String args[]) { SimpleDateFormat sdf = new
SimpleDateFormat(\"yyyy MMM dd HH:mm:ss\"); System.out.println(\"when to begin
taking the medication (Year,month,day of month,hour, minute\"); input = new
Scanner(System.in); String begin = input.nextLine(); String[] parts = begin.split(\",\");
Calendar calendar = new
GregorianCalendar(Integer.parseInt(parts[0]),Integer.parseInt(parts[1])-
1,Integer.parseInt(parts[2]),Integer.parseInt(parts[3]),Integer.parseInt(parts[4]),00);
System.out.println(sdf.format(calendar.getTime())); System.out.println(\"when to end\");
String end = input.nextLine(); String[] parts2 = end.split(\",\"); Calendar calendar2 =
new GregorianCalendar(Integer.parseInt(parts2[0]),Integer.parseInt(parts2[1])-
1,Integer.parseInt(parts2[2]),Integer.parseInt(parts2[3]),Integer.parseInt(parts2[4]),00);
System.out.println(sdf.format(calendar2.getTime())); System.out.println(\"proper
dosage\"); String dosage = input.nextLine(); System.out.println(\"frequency (hours
between medication)\"); int frequence = input.nextInt();
calendar.add(Calendar.HOUR_OF_DAY,+ frequence); System.out.println(\"The second
scheduled medication is: \" + sdf.format(calendar.getTime())); } }
Solution
import java.text.SimpleDateFormat; import java.util.Calendar; import
java.util.GregorianCalendar; import java.util.Scanner; class Main { private static Scanner
input; public static void main(String args[]) { SimpleDateFormat sdf = new
SimpleDateFormat(\"yyyy MMM dd HH:mm:ss\"); System.out.println(\"when to begin
taking the medication (Year,month,day of month,hour, minute\"); input = new
Scanner(System.in); String begin = input.nextLine(); String[] parts = begin.split(\",\");
Calendar calendar = new
GregorianCalendar(Integer.parseInt(parts[0]),Integer.parseInt(parts[1])-
1,Integer.parseInt(parts[2]),Integer.parseInt(parts[3]),Integer.parseInt(parts[4]),00);
System.out.println(sdf.format(calendar.getTime())); System.out.println(\"when to end\");
String end = input.nextLine(); String[] parts2 = end.split(\",\"); Calendar calendar2 =
new GregorianCalendar(Integer.parseInt(parts2[0]),Integer.parseInt(parts2[1])-
1,Integer.parseInt(parts2[2]),Integer.parseInt(parts2[3]),Integer.parseInt(parts2[4]),00);
System.out.println(sdf.format(calendar2.getTime())); System.out.println(\"proper
dosage\"); String dosage = input.nextLine(); System.out.println(\"frequency (hours
between medication)\"); int frequence = input.nextInt();
calendar.add(Calendar.HOUR_OF_DAY,+ frequence); System.out.println(\"The second
scheduled medication is: \" + sdf.format(calendar.getTime())); } }.
Recommended
RainFall.java public class RainFall { private double months.pdf
RainFall.java
public class RainFall {
private double months[];
String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public RainFall(double d[]){
months = d;
}
public void displayTotalRainFall(){
double total = 0;
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println(\"The minimum rainfall is :\"+min);
System.out.println(\"The minimum rainfall month is :\"+monthStr[minIndex]);
}
}
RainFallTest.java
import java.util.Scanner;
public class RainFallTest {
static String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public static void main(String[] args) {
double month[] = new double[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i
Solution
RainFall.java
public class RainFall {
private double months[];
String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public RainFall(double d[]){
months = d;
}
public void displayTotalRainFall(){
double total = 0;
for(int i=0; i months[i]){
min = months[i];
minIndex = i;
}
}
System.out.println(\"The minimum rainfall is :\"+min);
System.out.println(\"The minimum rainfall month is :\"+monthStr[minIndex]);
}
}
RainFallTest.java
import java.util.Scanner;
public class RainFallTest {
static String monthStr[] = {\"January\", \"Fabruary\", \"March\", \"April\", \"May\", \"June\",
\"July\", \"August\", \"September\",\"October\",\"November\",\"December\"};
public static void main(String[] args) {
double month[] = new double[12];
Scanner scan = new Scanner(System.in);
for(int i=0; i.
import java.util.Scanner; public class Rainfall {Scanner s=new.pdf
import java.util.Scanner;
public class Rainfall
{
Scanner s=new Scanner(System.in);
private double months[] = new double[12];
Rainfall(double months[])
{
this.months=months;
}
public void setRainfall()
{
System.out.println(\"enter rainfalll for each month \");
for(int i=0;i<12;i++)
{
inner:
System.out.println(\"Month \"+(i+1)+\" rainfall :\");
months[i]=s.nextDouble();
if(months[i]<0.0)
{
System.out.println(\"invalid value .... please enter again\");
continue inner;
}
else continue;
}
}
public void getRainfall()
{
for(int i=0;i<12;i++)
{
System.out.println(\"Month \"+(i+1)+\" rainfall :\"+
months[i]);
}
}
public double totalYearRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total;
}
public double averageMonthlyRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total/12;
}
public int monthLeastRainfall()
{
double min=0.0;
int month;
for(int i=0;i<12;i++)
{
if(month[i]max)
{
max=month[i];
month=i+1;
}
}
return month;
}
}
public class TestRainfall
{
public static void main(String args[])
{
Rainfall r = new Rainfall();
r.setRainfall();
r.getRainfall();
r.totalYearRainfall();
r.averageMonthlyRainfall();
r.monthLeastRainfall();
r.monthMostRainfall();
}
}
Solution
import java.util.Scanner;
public class Rainfall
{
Scanner s=new Scanner(System.in);
private double months[] = new double[12];
Rainfall(double months[])
{
this.months=months;
}
public void setRainfall()
{
System.out.println(\"enter rainfalll for each month \");
for(int i=0;i<12;i++)
{
inner:
System.out.println(\"Month \"+(i+1)+\" rainfall :\");
months[i]=s.nextDouble();
if(months[i]<0.0)
{
System.out.println(\"invalid value .... please enter again\");
continue inner;
}
else continue;
}
}
public void getRainfall()
{
for(int i=0;i<12;i++)
{
System.out.println(\"Month \"+(i+1)+\" rainfall :\"+
months[i]);
}
}
public double totalYearRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total;
}
public double averageMonthlyRainfall()
{
double total=0.0;
for(int i=0;i<12;i++)
{
total=total+months[i];
}
return total/12;
}
public int monthLeastRainfall()
{
double min=0.0;
int month;
for(int i=0;i<12;i++)
{
if(month[i]max)
{
max=month[i];
month=i+1;
}
}
return month;
}
}
public class TestRainfall
{
public static void main(String args[])
{
Rainfall r = new Rainfall();
r.setRainfall();
r.getRainfall();
r.totalYearRainfall();
r.averageMonthlyRainfall();
r.monthLeastRainfall();
r.monthMostRainfall();
}
}.
Oot practical
The document contains 10 Java programs to solve common mathematical and logical problems:
1) A program to calculate the factorial of a number.
2) A program to add two matrices.
3) A program to calculate the sum of two numbers.
4) A program to reverse a number.
5) A program to check if a number is an Armstrong number.
6) A program to find the largest of three numbers.
7) A program to output the current date and time.
8) A program to check if a string is a palindrome.
9) A program to print prime numbers up to a given limit.
10) A program to swap two numbers.
import java.util.Scanner; import java.text.; public class Ave.pdf
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j
Solution
import java.util.Scanner;
import java.text.*;
public class AverageRainfall {
public static void main(String[] args) {
int years; // Variable to hold the amount of years
final int MONTHS = 12; // Constant to hold the amount of months in a year
int totalMonths = 0; // Months accumulator variable
double monthlyRain; // Holds the amount of rain in inches for each month
double totalRainfall = 0; // Holds the total rainfall
NumberFormat df = DecimalFormat.getInstance(); // Decimal formating
df.setMaximumFractionDigits(2);
// Create Scanner object
Scanner input = new Scanner(System.in);
// Prompt user for the number of years
System.out.println(\"Enter the number of years: \");
years = input.nextInt();
System.out.println(\"Enter the rainfall amount for each month \");
// Construct for-loop for each year
for(int i=0; i < years; i++){
for(int j=1; j.
Java Language.....pdf
It\'s theoretically possible that naturally occurring (contaminating) bacteria that happen to be
ampicillin resistant could be yielding the colonies observed. Describe a NEGATIVE CONTROL
experiment that could be run in parallel to test for this possibility?
Solution
In this case for making negative control one must take bacteria present in its natural condition
where no transfer of ampicillin resistant gene has been done. As and when this condition is
maintained where bacteria lacks ampicillin resistant gene, then by applying ampicillin from
outside during plating of bacteria the population density seems to decrease. This clearly shows
lack of ampicillin resistivity hence NEGATIVE CONTROL experiment gets completed..
Write a Java ProgramSolutionAnswer- Code- import java-io--- import jav.docx
This Java program allows a user to input employee data including name, type of employee (hourly or salaried), hourly rate, hours worked, and regular pay. It then calculates the income for hourly employees based on hours worked and overtime pay, and calculates income for salaried employees based on regular pay and hourly rate. The program outputs the employee name and calculated income.
Lab101.pptx
The document contains 12 code examples for Java programs that perform various tasks like greeting a user, calculating triangle area, printing even numbers, generating Fibonacci sequences, calculating factorials, determining if a number is even/odd, comparing two numbers, determining if a number is positive/negative, generating a multiplication table, and reversing a string. Each code example demonstrates the use of basic Java concepts like variables, conditionals, loops, methods, and classes to solve common programming problems.
import java.text.SimpleDateFormat; import java.util.Calendar; import.pdf
import java.text.SimpleDateFormat; import java.util.Calendar; import
java.util.GregorianCalendar; import java.util.Scanner; class Main { private static Scanner
input; public static void main(String args[]) { SimpleDateFormat sdf = new
SimpleDateFormat(\"yyyy MMM dd HH:mm:ss\"); System.out.println(\"when to begin
taking the medication (Year,month,day of month,hour, minute\"); input = new
Scanner(System.in); String begin = input.nextLine(); String[] parts = begin.split(\",\");
Calendar calendar = new
GregorianCalendar(Integer.parseInt(parts[0]),Integer.parseInt(parts[1])-
1,Integer.parseInt(parts[2]),Integer.parseInt(parts[3]),Integer.parseInt(parts[4]),00);
System.out.println(sdf.format(calendar.getTime())); System.out.println(\"when to end\");
String end = input.nextLine(); String[] parts2 = end.split(\",\"); Calendar calendar2 =
new GregorianCalendar(Integer.parseInt(parts2[0]),Integer.parseInt(parts2[1])-
1,Integer.parseInt(parts2[2]),Integer.parseInt(parts2[3]),Integer.parseInt(parts2[4]),00);
System.out.println(sdf.format(calendar2.getTime())); System.out.println(\"proper
dosage\"); String dosage = input.nextLine(); System.out.println(\"frequency (hours
between medication)\"); int frequence = input.nextInt();
calendar.add(Calendar.HOUR_OF_DAY,+ frequence); System.out.println(\"The second
scheduled medication is: \" + sdf.format(calendar.getTime())); } }
Solution
import java.text.SimpleDateFormat; import java.util.Calendar; import
java.util.GregorianCalendar; import java.util.Scanner; class Main { private static Scanner
input; public static void main(String args[]) { SimpleDateFormat sdf = new
SimpleDateFormat(\"yyyy MMM dd HH:mm:ss\"); System.out.println(\"when to begin
taking the medication (Year,month,day of month,hour, minute\"); input = new
Scanner(System.in); String begin = input.nextLine(); String[] parts = begin.split(\",\");
Calendar calendar = new
GregorianCalendar(Integer.parseInt(parts[0]),Integer.parseInt(parts[1])-
1,Integer.parseInt(parts[2]),Integer.parseInt(parts[3]),Integer.parseInt(parts[4]),00);
System.out.println(sdf.format(calendar.getTime())); System.out.println(\"when to end\");
String end = input.nextLine(); String[] parts2 = end.split(\",\"); Calendar calendar2 =
new GregorianCalendar(Integer.parseInt(parts2[0]),Integer.parseInt(parts2[1])-
1,Integer.parseInt(parts2[2]),Integer.parseInt(parts2[3]),Integer.parseInt(parts2[4]),00);
System.out.println(sdf.format(calendar2.getTime())); System.out.println(\"proper
dosage\"); String dosage = input.nextLine(); System.out.println(\"frequency (hours
between medication)\"); int frequence = input.nextInt();
calendar.add(Calendar.HOUR_OF_DAY,+ frequence); System.out.println(\"The second
scheduled medication is: \" + sdf.format(calendar.getTime())); } }.
Write a program that uses nested loops to collect data and calculate .docx
The program uses nested loops to collect rainfall data over a specified number of years. The outer loop iterates once for each year entered by the user. The inner loop iterates 12 times, once for each month, prompting the user to enter the rainfall for that month. After all iterations, the program displays the total number of months, total rainfall, and average monthly rainfall. Input validation is included to reject years less than 1 or negative rainfall amounts.
DS LAB RECORD.docx
The document contains Java code examples for implementing various data structures and algorithms using arrays. It includes programs for linear search, binary search, stack, queue, and converting an infix expression to postfix notation. For linear search, both recursive and non-recursive functions are provided. Similarly, for binary search and converting infix to postfix, both recursive and non-recursive approaches are demonstrated. The programs have main methods that accept user input and demonstrate the functionality of each implementation through sample outputs.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44
Solution
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44.
programming for Calculator in java
The document describes a Java program that creates a basic four function calculator. The program prompts the user to enter two numbers and select an operator of addition, subtraction, multiplication, or division. It then uses nested if statements to perform the selected arithmetic operation on the numbers and output the result.
Lab01.pptx
The document contains instructions for 14 programming exercises involving basic Java concepts like user input, arithmetic operations, loops, strings, and prime number identification. The exercises cover printing greetings, calculating triangle areas, generating even numbers, Fibonacci sequences, factorials, and determining parity, in addition to other foundational programming tasks. Students are guided to write Java code to prompt for input, perform calculations, and output results for each problem.
WINSEM2020-21_STS3105_SS_VL2020210500169_Reference_Material_I_15-Feb-2021_L6-...
The document contains sample code snippets for 7 questions related to arrays in Java. For each question, it provides the problem statement, sample input, sample output, and the Java code to solve the problem. The problems include searching for an element in an array, finding the number of occurrences of an element, finding the largest element, finding pairs with a given sum, rotating an array, finding the unique element, and checking if an array is a palindrome. It also includes 2 multiple choice questions to predict the output of code snippets.
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...Nithin Kumar,VVCE, Mysuru
VTU Fourth Semester Design and Analysis of Algorithms Laboratory Manual As per CBCS Scheme by Nithin Kumar, VVCE, Mysurujava program assigment -2
This document contains code written by Ankit Gupta for an assignment. It includes 6 Java programs: 1) A program to calculate the sum of first n numbers using a for loop. 2) A program to find the maximum of n numbers using a do-while loop. 3) A program to find all Armstrong numbers between 0 and 999. 4) A program to correct common typing errors. 5) A program to solve a problem related to the gangster Dawood Abrahim. 6) Additional Java programs and problems solved by Ankit Gupta.
An input file A1-txt is given which contains a list of integer values-.docx
An input file A1.txt is given which contains a list of integer values. Write a program that reads
all the values from A1.txt and save them into an array. Prompt the user for an integer number and
count the frequency of that number within that array.
Sample input:
51 27 44 50 99 74 58 28 62 84 45 75 71 97 71
Enter the number you want to search: 71
Sample Output:
71 appeared 2 times
Solution
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
public class CountFrequency {
public static void main(String[] args) throws NumberFormatException, IOException{
Scanner scanner;
Scanner sc;
int [] tall = new int[20];
try {
scanner = new Scanner(new File(\"A1.txt\"));
sc = new Scanner(System.in);
int i = 0;
tall = new int [20];
while(scanner.hasNextInt())
{
tall[i++] = scanner.nextInt();
}
i=0;
System.out.println(\"Enter the number you want to search:\");
int searchnumber= sc.nextInt();
int count=0;
for(i=0;i<15;i++){
if(tall[i]==searchnumber){
count++;
i++;
}else
i++;
}
System.out.println(searchnumber+\" appeared \"+count+\" times.\");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
.
WAP to add two given matrices in Java
The document contains code to add two matrices of given size. It takes the number of rows and columns as input to create two matrices of that size. It then takes elements of both matrices as input and stores them. It iterates through both matrices to add the elements and stores the result in a third sum matrix. Finally, it prints the sum matrix.
CountPositiveNumbersInArray.javapackage org.students;import java.pdf
CountPositiveNumbersInArray.java
package org.students;
import java.util.Scanner;
public class CountPositiveNumbersInArray {
public static void main(String[] args) throws Exception {
int array[] = null;
//Declaring variables
int count_positive_nos;
//Scanner object is used to Get the values entered by the user.
Scanner sc = new Scanner(System.in);
//Getting the Array Size from the user.
System.out.print(\"\ Enter no of elements you want to store in Array :\");
int number = sc.nextInt();
//Creating an array with that size
array = new int[number];
//Populating the array with user enterd values.
for (int i = 0; i < number; i++) {
System.out.print(\"\ Enter the element \" + (i + 1) + \" :\");
array[i] = sc.nextInt();
}
//Calling the method by passing the array as argument.
count_positive_nos = countPositive(array);
//Displaying the no of positive numbers in the array
System.out.println(\"The number of Positive Numbers in the array :\"+ count_positive_nos);
}
/*
* This method checks and count number of positive numbers in the array
* @Params, array of integer type
* @return array
*/
private static int countPositive(int[] array)
{
//Declaring local variable
int count = 0;
try
{
if (array == null)
{
throw new NullPointerException();
}
else
{
for (int i = 0; i < array.length; i++)
{
if (array[i] > 0)
{
count++;
}
}
}
}
catch (Exception e)
{
System.out.println(\"Exception :\"+e);
}
return count;
}
}
_______________________________________________________________
Output:
Enter no of elements you want to store in Array :4
Enter the element 1 :-4
Enter the element 2 :0
Enter the element 3 :2
Enter the element 4 :2
The number of Positive Numbers in the array :2
____________________________________________________________________
Solution
CountPositiveNumbersInArray.java
package org.students;
import java.util.Scanner;
public class CountPositiveNumbersInArray {
public static void main(String[] args) throws Exception {
int array[] = null;
//Declaring variables
int count_positive_nos;
//Scanner object is used to Get the values entered by the user.
Scanner sc = new Scanner(System.in);
//Getting the Array Size from the user.
System.out.print(\"\ Enter no of elements you want to store in Array :\");
int number = sc.nextInt();
//Creating an array with that size
array = new int[number];
//Populating the array with user enterd values.
for (int i = 0; i < number; i++) {
System.out.print(\"\ Enter the element \" + (i + 1) + \" :\");
array[i] = sc.nextInt();
}
//Calling the method by passing the array as argument.
count_positive_nos = countPositive(array);
//Displaying the no of positive numbers in the array
System.out.println(\"The number of Positive Numbers in the array :\"+ count_positive_nos);
}
/*
* This method checks and count number of positive numbers in the array
* @Params, array of integer type
* @return array
*/
private static int countPositive(int[] array)
{
//Declaring local variable
int count = 0;
try
{
if (array == null)
{
throw new NullPointerException(.
5. The normal route of transmission of Paramyxo virus is droplets or.pdf
5. The normal route of transmission of Paramyxo virus is droplets or air-borne particles.
6. Teenage and adults at the age 20 - 30 are more likely to develop complications than children
and old age people, with mumps infection
7. Most of the times, the symptoms of mumps are so mild that they go unnoticed. The parotid
swelling that occurs with mumps is commonly mistaken as throat infection.
8. Urethritis: categorized as either gonococcal urethritis or non-gonococcal. Gonococcal
urethritis is caused by Neisseria gonorrheeae. Non-gonococcal urethritis is due to Mycoplasma
genitalium and Ureaplasma,Trichomonas, Herpes simplex virus.
sore throat: Streptococcus pyogenes, Corynebacterium diphtheriae, Mycoplasma pneumoniae
Diarrhea: Vibrio cholera, E. coli, Campylobacter
Solution
5. The normal route of transmission of Paramyxo virus is droplets or air-borne particles.
6. Teenage and adults at the age 20 - 30 are more likely to develop complications than children
and old age people, with mumps infection
7. Most of the times, the symptoms of mumps are so mild that they go unnoticed. The parotid
swelling that occurs with mumps is commonly mistaken as throat infection.
8. Urethritis: categorized as either gonococcal urethritis or non-gonococcal. Gonococcal
urethritis is caused by Neisseria gonorrheeae. Non-gonococcal urethritis is due to Mycoplasma
genitalium and Ureaplasma,Trichomonas, Herpes simplex virus.
sore throat: Streptococcus pyogenes, Corynebacterium diphtheriae, Mycoplasma pneumoniae
Diarrhea: Vibrio cholera, E. coli, Campylobacter.
35Solution35.pdf
The document provides a solution to the problem "35". However, it does not contain any further context, details, or explanation about the problem being solved or nature of the solution. The document simply states the number "35" twice without any other words.
1. C. Mycorrhiza can transport sugars between different plants.Thi.pdf
1. C. Mycorrhiza can transport sugars between different plants.
This mutualistic association provides the fungus with relatively constant and direct access to
carbohydrates, such as glucose and sucrose. The carbohydrates are translocated from their source
(usually leaves) to root tissue and on to the plant\'s fungal partners. In return, the plant gains the
benefits of the mycelium\'s higher absorptive capacity for water and mineral nutrients due to the
large surface area of fungal hyphae.
2.A. Subsidiary cells lose turgor
Subsidiary cells loose water to nearby guard cells and become flaccid. Thus they loose Turgor
and guard cells gain Turgor .
A. Chelated iron.
Wheat.
Wheat has the highest harvest index of 0.55 .
Solution
1. C. Mycorrhiza can transport sugars between different plants.
This mutualistic association provides the fungus with relatively constant and direct access to
carbohydrates, such as glucose and sucrose. The carbohydrates are translocated from their source
(usually leaves) to root tissue and on to the plant\'s fungal partners. In return, the plant gains the
benefits of the mycelium\'s higher absorptive capacity for water and mineral nutrients due to the
large surface area of fungal hyphae.
2.A. Subsidiary cells lose turgor
Subsidiary cells loose water to nearby guard cells and become flaccid. Thus they loose Turgor
and guard cells gain Turgor .
A. Chelated iron.
Wheat.
Wheat has the highest harvest index of 0.55 ..
1.Petals They are the part of flower that appear conspicuously, o.pdf
1.
Petals: They are the part of flower that appear conspicuously, often coloured or variegated. They
attract pollinating insects to the flower
Sepals: The outer part of a flower that enclose a developing bud
Stamen: It is the male reproductive organ of flower that produced pollen. It is usually thing and
slender filament with a stamen
Anther: It is the part of the stamen where pollen is actually produced
Calyx: The leaf like structures that are present at the base of a flower and protect the flower
during development. The calyx is made of individual units called sepals.
Corolla: The collective unit of petals that are arranged in a specific pattern around the center of a
flower is called corolla.
Receptacle: It is a thickened region or a base upon which the flowers and its associated organs
grow. Receptacles form edible part of the fruit.
Peduncle: It is a stem structure that supports inflorescence. In simple terms, it is the stalk of the
flower.
Pedicel: The stem or stalk that attaches each flower to the inflorescence.
Pistil: It is a swollen part of the flower which produces the ovule. It is centrally located in the
flower and bear structures like stalk, style, potential seeds, ovary, etc.
Filament: It is a stalk that connects to the anther, and together with anther, it forms the stamen.
Ovary: It is the enlarged basal region of the pistil where ovules are produced. Carpel: The
innermost part of a flower which is surrounded by male reproductive structures. It is a seed
bearing structure (ovary or egg is present within this).
Solution
1.
Petals: They are the part of flower that appear conspicuously, often coloured or variegated. They
attract pollinating insects to the flower
Sepals: The outer part of a flower that enclose a developing bud
Stamen: It is the male reproductive organ of flower that produced pollen. It is usually thing and
slender filament with a stamen
Anther: It is the part of the stamen where pollen is actually produced
Calyx: The leaf like structures that are present at the base of a flower and protect the flower
during development. The calyx is made of individual units called sepals.
Corolla: The collective unit of petals that are arranged in a specific pattern around the center of a
flower is called corolla.
Receptacle: It is a thickened region or a base upon which the flowers and its associated organs
grow. Receptacles form edible part of the fruit.
Peduncle: It is a stem structure that supports inflorescence. In simple terms, it is the stalk of the
flower.
Pedicel: The stem or stalk that attaches each flower to the inflorescence.
Pistil: It is a swollen part of the flower which produces the ovule. It is centrally located in the
flower and bear structures like stalk, style, potential seeds, ovary, etc.
Filament: It is a stalk that connects to the anther, and together with anther, it forms the stamen.
Ovary: It is the enlarged basal region of the pistil where ovules are produced. Carpel: The
innermost part of a flower which .
A type I error, also known as an error of the first kind, occurs wh.pdf
A type I error, also known as an error of the first kind, occurs when the null hypothesis (H0) is
true, but is rejected. It is asserting something that is absent, a false hit. A type I error may be
compared with a so-called false positive (a result that indicates that a given condition is present
when it actually is not present) in tests where a single condition is tested for. Type I errors are
philosophically a focus of skepticism and Occam\'s razor. A Type I error occurs when we believe
a falsehood.[4] In terms of folk tales, an investigator may be \"crying wolf\" without a wolf in
sight (raising a false alarm) (H0: no wolf).
The rate of the type I error is called the size of the test and denoted by the Greek letter ? (alpha).
It usually equals the significance level of a test. In the case of a simple null hypothesis ? is the
probability of a type I error. If the null hypothesis is composite, ? is the maximum (supremum)
of the possible probabilities of a type I error.
A false positive error, or in short false positive, commonly called a \"false alarm\", is a result
that indicates a given condition has been fulfilled, when it actually has not been fulfilled. I.e.
erroneously a positive effect has been assumed. In the case of \"crying wolf\"
Solution
A type I error, also known as an error of the first kind, occurs when the null hypothesis (H0) is
true, but is rejected. It is asserting something that is absent, a false hit. A type I error may be
compared with a so-called false positive (a result that indicates that a given condition is present
when it actually is not present) in tests where a single condition is tested for. Type I errors are
philosophically a focus of skepticism and Occam\'s razor. A Type I error occurs when we believe
a falsehood.[4] In terms of folk tales, an investigator may be \"crying wolf\" without a wolf in
sight (raising a false alarm) (H0: no wolf).
The rate of the type I error is called the size of the test and denoted by the Greek letter ? (alpha).
It usually equals the significance level of a test. In the case of a simple null hypothesis ? is the
probability of a type I error. If the null hypothesis is composite, ? is the maximum (supremum)
of the possible probabilities of a type I error.
A false positive error, or in short false positive, commonly called a \"false alarm\", is a result
that indicates a given condition has been fulfilled, when it actually has not been fulfilled. I.e.
erroneously a positive effect has been assumed. In the case of \"crying wolf\".
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold.pdf
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold the organisms together.
Q3. there will be less oxygen available for the aquatic life due to microbial activity Q4. Oxygen
minimum zone Q5. Piezophiles.
Solution
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold the organisms together.
Q3. there will be less oxygen available for the aquatic life due to microbial activity Q4. Oxygen
minimum zone Q5. Piezophiles..
D orbitals are only available to atoms in rows 3-7. D orbitals only.pdf
D orbitals are only available to atoms in rows 3-7. D orbitals only exist for electrons with
primary quantum number (n) = 3 or greater. That is, there is no such thing as a 2d orbital. Thus
elements such as B, C, O, N, etc do not have available d orbitals, but the atoms immediately
below them: Al, Si, S, P, etc. do. Among atoms of a given element, there is no such thing as
having d orbitals available or not - that is, all S atoms have d orbitals available. However,
depending on the environment surrounding the atom, it may or may not be energetically
favorable to use the d orbitals for bonding. But whether or not they\'re used, they\'re always
there, and you can always consider them to be available.
Solution
D orbitals are only available to atoms in rows 3-7. D orbitals only exist for electrons with
primary quantum number (n) = 3 or greater. That is, there is no such thing as a 2d orbital. Thus
elements such as B, C, O, N, etc do not have available d orbitals, but the atoms immediately
below them: Al, Si, S, P, etc. do. Among atoms of a given element, there is no such thing as
having d orbitals available or not - that is, all S atoms have d orbitals available. However,
depending on the environment surrounding the atom, it may or may not be energetically
favorable to use the d orbitals for bonding. But whether or not they\'re used, they\'re always
there, and you can always consider them to be available..
Zeff - dec going down, inc going across IE - inc .pdf
Zeff - dec going down, inc going across IE - inc going up, inc going across EA - inc
going up, inc going acroos n - inc going down, same across For a graphic representation see:
http://upload.wikimedia.org/wikipedia/commons/f/fe/Periodic_trends.svg
Solution
Zeff - dec going down, inc going across IE - inc going up, inc going across EA - inc
going up, inc going acroos n - inc going down, same across For a graphic representation see:
http://upload.wikimedia.org/wikipedia/commons/f/fe/Periodic_trends.svg.
There are diastereomers. note Diastereomers (som.pdf
There are diastereomers. note: Diastereomers (sometimes called diastereoisomers)
are stereoisomers that are not enantiomers. Diastereomerism occurs when two or more
stereoisomers of a compound have different configurations at one or more (but not all) of the
equivalent (related) stereocenters and are not mirror images of each other.
Solution
There are diastereomers. note: Diastereomers (sometimes called diastereoisomers)
are stereoisomers that are not enantiomers. Diastereomerism occurs when two or more
stereoisomers of a compound have different configurations at one or more (but not all) of the
equivalent (related) stereocenters and are not mirror images of each other..
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Write a program that uses nested loops to collect data and calculate .docx
The program uses nested loops to collect rainfall data over a specified number of years. The outer loop iterates once for each year entered by the user. The inner loop iterates 12 times, once for each month, prompting the user to enter the rainfall for that month. After all iterations, the program displays the total number of months, total rainfall, and average monthly rainfall. Input validation is included to reject years less than 1 or negative rainfall amounts.
DS LAB RECORD.docx
The document contains Java code examples for implementing various data structures and algorithms using arrays. It includes programs for linear search, binary search, stack, queue, and converting an infix expression to postfix notation. For linear search, both recursive and non-recursive functions are provided. Similarly, for binary search and converting infix to postfix, both recursive and non-recursive approaches are demonstrated. The programs have main methods that accept user input and demonstrate the functionality of each implementation through sample outputs.
import java.util.;public class Program{public static void.pdf
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println(x);
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Why does It print out the last set of X\'s twice? I am doing basic Java so please try to explain
using the most basic codes.
Solution
Hi,
I have modified the code. it is working as expected now. Highlighted the code changes below.
Issue here is with you have written this statement twice System.out.println(x); which causes the
issue.
Program.java
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String x=\"X\";
int amount;
System.out.println(\"Enter amount\");
amount=input.nextInt();
System.out.println(\"Amount is: \"+amount);
for(int i=1; i<=amount; i++)
{
System.out.println();
for(int j=1; j<=i; j++)
{
System.out.print(x);
}
}
}
}
Output:
Enter amount
10
Amount is: 10
X
XX
XXX
XXXX
XXXXX
XXXXXX
XXXXXXX
XXXXXXXX
XXXXXXXXX
XXXXXXXXXX.
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44
Solution
Factors.java
import java.io.*;
import java.util.Scanner;
class Factors
{
public static void main(String args[])
{
int a,i;
Scanner in = new Scanner(System.in);
System.out.println(\"Enter an integer\");
a = in.nextInt();
System.out.println(\"You entered integer \"+a);
System.out.print(\"\ \");
System.out.print(\"The factors are : \");
for(i=1;i<=a/2;i++)
{
if(a%i==0)
System.out.print(i+\",\");
}
System.out.print(a);
}
}
Output:
Enter an integer
44
You entered integer 44
The factors are : 1,2,4,11,22,44.
programming for Calculator in java
The document describes a Java program that creates a basic four function calculator. The program prompts the user to enter two numbers and select an operator of addition, subtraction, multiplication, or division. It then uses nested if statements to perform the selected arithmetic operation on the numbers and output the result.
Lab01.pptx
The document contains instructions for 14 programming exercises involving basic Java concepts like user input, arithmetic operations, loops, strings, and prime number identification. The exercises cover printing greetings, calculating triangle areas, generating even numbers, Fibonacci sequences, factorials, and determining parity, in addition to other foundational programming tasks. Students are guided to write Java code to prompt for input, perform calculations, and output results for each problem.
WINSEM2020-21_STS3105_SS_VL2020210500169_Reference_Material_I_15-Feb-2021_L6-...
The document contains sample code snippets for 7 questions related to arrays in Java. For each question, it provides the problem statement, sample input, sample output, and the Java code to solve the problem. The problems include searching for an element in an array, finding the number of occurrences of an element, finding the largest element, finding pairs with a given sum, rotating an array, finding the unique element, and checking if an array is a palindrome. It also includes 2 multiple choice questions to predict the output of code snippets.
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...Nithin Kumar,VVCE, Mysuru
VTU Fourth Semester Design and Analysis of Algorithms Laboratory Manual As per CBCS Scheme by Nithin Kumar, VVCE, Mysurujava program assigment -2
This document contains code written by Ankit Gupta for an assignment. It includes 6 Java programs: 1) A program to calculate the sum of first n numbers using a for loop. 2) A program to find the maximum of n numbers using a do-while loop. 3) A program to find all Armstrong numbers between 0 and 999. 4) A program to correct common typing errors. 5) A program to solve a problem related to the gangster Dawood Abrahim. 6) Additional Java programs and problems solved by Ankit Gupta.
An input file A1-txt is given which contains a list of integer values-.docx
An input file A1.txt is given which contains a list of integer values. Write a program that reads
all the values from A1.txt and save them into an array. Prompt the user for an integer number and
count the frequency of that number within that array.
Sample input:
51 27 44 50 99 74 58 28 62 84 45 75 71 97 71
Enter the number you want to search: 71
Sample Output:
71 appeared 2 times
Solution
import java.io.File;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Scanner;
public class CountFrequency {
public static void main(String[] args) throws NumberFormatException, IOException{
Scanner scanner;
Scanner sc;
int [] tall = new int[20];
try {
scanner = new Scanner(new File(\"A1.txt\"));
sc = new Scanner(System.in);
int i = 0;
tall = new int [20];
while(scanner.hasNextInt())
{
tall[i++] = scanner.nextInt();
}
i=0;
System.out.println(\"Enter the number you want to search:\");
int searchnumber= sc.nextInt();
int count=0;
for(i=0;i<15;i++){
if(tall[i]==searchnumber){
count++;
i++;
}else
i++;
}
System.out.println(searchnumber+\" appeared \"+count+\" times.\");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
.
WAP to add two given matrices in Java
The document contains code to add two matrices of given size. It takes the number of rows and columns as input to create two matrices of that size. It then takes elements of both matrices as input and stores them. It iterates through both matrices to add the elements and stores the result in a third sum matrix. Finally, it prints the sum matrix.
CountPositiveNumbersInArray.javapackage org.students;import java.pdf
CountPositiveNumbersInArray.java
package org.students;
import java.util.Scanner;
public class CountPositiveNumbersInArray {
public static void main(String[] args) throws Exception {
int array[] = null;
//Declaring variables
int count_positive_nos;
//Scanner object is used to Get the values entered by the user.
Scanner sc = new Scanner(System.in);
//Getting the Array Size from the user.
System.out.print(\"\ Enter no of elements you want to store in Array :\");
int number = sc.nextInt();
//Creating an array with that size
array = new int[number];
//Populating the array with user enterd values.
for (int i = 0; i < number; i++) {
System.out.print(\"\ Enter the element \" + (i + 1) + \" :\");
array[i] = sc.nextInt();
}
//Calling the method by passing the array as argument.
count_positive_nos = countPositive(array);
//Displaying the no of positive numbers in the array
System.out.println(\"The number of Positive Numbers in the array :\"+ count_positive_nos);
}
/*
* This method checks and count number of positive numbers in the array
* @Params, array of integer type
* @return array
*/
private static int countPositive(int[] array)
{
//Declaring local variable
int count = 0;
try
{
if (array == null)
{
throw new NullPointerException();
}
else
{
for (int i = 0; i < array.length; i++)
{
if (array[i] > 0)
{
count++;
}
}
}
}
catch (Exception e)
{
System.out.println(\"Exception :\"+e);
}
return count;
}
}
_______________________________________________________________
Output:
Enter no of elements you want to store in Array :4
Enter the element 1 :-4
Enter the element 2 :0
Enter the element 3 :2
Enter the element 4 :2
The number of Positive Numbers in the array :2
____________________________________________________________________
Solution
CountPositiveNumbersInArray.java
package org.students;
import java.util.Scanner;
public class CountPositiveNumbersInArray {
public static void main(String[] args) throws Exception {
int array[] = null;
//Declaring variables
int count_positive_nos;
//Scanner object is used to Get the values entered by the user.
Scanner sc = new Scanner(System.in);
//Getting the Array Size from the user.
System.out.print(\"\ Enter no of elements you want to store in Array :\");
int number = sc.nextInt();
//Creating an array with that size
array = new int[number];
//Populating the array with user enterd values.
for (int i = 0; i < number; i++) {
System.out.print(\"\ Enter the element \" + (i + 1) + \" :\");
array[i] = sc.nextInt();
}
//Calling the method by passing the array as argument.
count_positive_nos = countPositive(array);
//Displaying the no of positive numbers in the array
System.out.println(\"The number of Positive Numbers in the array :\"+ count_positive_nos);
}
/*
* This method checks and count number of positive numbers in the array
* @Params, array of integer type
* @return array
*/
private static int countPositive(int[] array)
{
//Declaring local variable
int count = 0;
try
{
if (array == null)
{
throw new NullPointerException(.
Similar to RainfallTest.javaimport java.util.Arrays; import java.util.Scann.pdf (12)
Write a program that uses nested loops to collect data and calculate .docx
Write a program that uses nested loops to collect data and calculate .docx
import java.util.;public class Program{public static void.pdf
import java.util.;public class Program{public static void.pdf
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
Factors.javaimport java.io.; import java.util.Scanner; class .pdf
WINSEM2020-21_STS3105_SS_VL2020210500169_Reference_Material_I_15-Feb-2021_L6-...
WINSEM2020-21_STS3105_SS_VL2020210500169_Reference_Material_I_15-Feb-2021_L6-...
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...
VTU Design and Analysis of Algorithms(DAA) Lab Manual by Nithin, VVCE, Mysuru...
An input file A1-txt is given which contains a list of integer values-.docx
An input file A1-txt is given which contains a list of integer values-.docx
CountPositiveNumbersInArray.javapackage org.students;import java.pdf
CountPositiveNumbersInArray.javapackage org.students;import java.pdf
More from anithacells
5. The normal route of transmission of Paramyxo virus is droplets or.pdf
5. The normal route of transmission of Paramyxo virus is droplets or air-borne particles.
6. Teenage and adults at the age 20 - 30 are more likely to develop complications than children
and old age people, with mumps infection
7. Most of the times, the symptoms of mumps are so mild that they go unnoticed. The parotid
swelling that occurs with mumps is commonly mistaken as throat infection.
8. Urethritis: categorized as either gonococcal urethritis or non-gonococcal. Gonococcal
urethritis is caused by Neisseria gonorrheeae. Non-gonococcal urethritis is due to Mycoplasma
genitalium and Ureaplasma,Trichomonas, Herpes simplex virus.
sore throat: Streptococcus pyogenes, Corynebacterium diphtheriae, Mycoplasma pneumoniae
Diarrhea: Vibrio cholera, E. coli, Campylobacter
Solution
5. The normal route of transmission of Paramyxo virus is droplets or air-borne particles.
6. Teenage and adults at the age 20 - 30 are more likely to develop complications than children
and old age people, with mumps infection
7. Most of the times, the symptoms of mumps are so mild that they go unnoticed. The parotid
swelling that occurs with mumps is commonly mistaken as throat infection.
8. Urethritis: categorized as either gonococcal urethritis or non-gonococcal. Gonococcal
urethritis is caused by Neisseria gonorrheeae. Non-gonococcal urethritis is due to Mycoplasma
genitalium and Ureaplasma,Trichomonas, Herpes simplex virus.
sore throat: Streptococcus pyogenes, Corynebacterium diphtheriae, Mycoplasma pneumoniae
Diarrhea: Vibrio cholera, E. coli, Campylobacter.
35Solution35.pdf
The document provides a solution to the problem "35". However, it does not contain any further context, details, or explanation about the problem being solved or nature of the solution. The document simply states the number "35" twice without any other words.
1. C. Mycorrhiza can transport sugars between different plants.Thi.pdf
1. C. Mycorrhiza can transport sugars between different plants.
This mutualistic association provides the fungus with relatively constant and direct access to
carbohydrates, such as glucose and sucrose. The carbohydrates are translocated from their source
(usually leaves) to root tissue and on to the plant\'s fungal partners. In return, the plant gains the
benefits of the mycelium\'s higher absorptive capacity for water and mineral nutrients due to the
large surface area of fungal hyphae.
2.A. Subsidiary cells lose turgor
Subsidiary cells loose water to nearby guard cells and become flaccid. Thus they loose Turgor
and guard cells gain Turgor .
A. Chelated iron.
Wheat.
Wheat has the highest harvest index of 0.55 .
Solution
1. C. Mycorrhiza can transport sugars between different plants.
This mutualistic association provides the fungus with relatively constant and direct access to
carbohydrates, such as glucose and sucrose. The carbohydrates are translocated from their source
(usually leaves) to root tissue and on to the plant\'s fungal partners. In return, the plant gains the
benefits of the mycelium\'s higher absorptive capacity for water and mineral nutrients due to the
large surface area of fungal hyphae.
2.A. Subsidiary cells lose turgor
Subsidiary cells loose water to nearby guard cells and become flaccid. Thus they loose Turgor
and guard cells gain Turgor .
A. Chelated iron.
Wheat.
Wheat has the highest harvest index of 0.55 ..
1.Petals They are the part of flower that appear conspicuously, o.pdf
1.
Petals: They are the part of flower that appear conspicuously, often coloured or variegated. They
attract pollinating insects to the flower
Sepals: The outer part of a flower that enclose a developing bud
Stamen: It is the male reproductive organ of flower that produced pollen. It is usually thing and
slender filament with a stamen
Anther: It is the part of the stamen where pollen is actually produced
Calyx: The leaf like structures that are present at the base of a flower and protect the flower
during development. The calyx is made of individual units called sepals.
Corolla: The collective unit of petals that are arranged in a specific pattern around the center of a
flower is called corolla.
Receptacle: It is a thickened region or a base upon which the flowers and its associated organs
grow. Receptacles form edible part of the fruit.
Peduncle: It is a stem structure that supports inflorescence. In simple terms, it is the stalk of the
flower.
Pedicel: The stem or stalk that attaches each flower to the inflorescence.
Pistil: It is a swollen part of the flower which produces the ovule. It is centrally located in the
flower and bear structures like stalk, style, potential seeds, ovary, etc.
Filament: It is a stalk that connects to the anther, and together with anther, it forms the stamen.
Ovary: It is the enlarged basal region of the pistil where ovules are produced. Carpel: The
innermost part of a flower which is surrounded by male reproductive structures. It is a seed
bearing structure (ovary or egg is present within this).
Solution
1.
Petals: They are the part of flower that appear conspicuously, often coloured or variegated. They
attract pollinating insects to the flower
Sepals: The outer part of a flower that enclose a developing bud
Stamen: It is the male reproductive organ of flower that produced pollen. It is usually thing and
slender filament with a stamen
Anther: It is the part of the stamen where pollen is actually produced
Calyx: The leaf like structures that are present at the base of a flower and protect the flower
during development. The calyx is made of individual units called sepals.
Corolla: The collective unit of petals that are arranged in a specific pattern around the center of a
flower is called corolla.
Receptacle: It is a thickened region or a base upon which the flowers and its associated organs
grow. Receptacles form edible part of the fruit.
Peduncle: It is a stem structure that supports inflorescence. In simple terms, it is the stalk of the
flower.
Pedicel: The stem or stalk that attaches each flower to the inflorescence.
Pistil: It is a swollen part of the flower which produces the ovule. It is centrally located in the
flower and bear structures like stalk, style, potential seeds, ovary, etc.
Filament: It is a stalk that connects to the anther, and together with anther, it forms the stamen.
Ovary: It is the enlarged basal region of the pistil where ovules are produced. Carpel: The
innermost part of a flower which .
A type I error, also known as an error of the first kind, occurs wh.pdf
A type I error, also known as an error of the first kind, occurs when the null hypothesis (H0) is
true, but is rejected. It is asserting something that is absent, a false hit. A type I error may be
compared with a so-called false positive (a result that indicates that a given condition is present
when it actually is not present) in tests where a single condition is tested for. Type I errors are
philosophically a focus of skepticism and Occam\'s razor. A Type I error occurs when we believe
a falsehood.[4] In terms of folk tales, an investigator may be \"crying wolf\" without a wolf in
sight (raising a false alarm) (H0: no wolf).
The rate of the type I error is called the size of the test and denoted by the Greek letter ? (alpha).
It usually equals the significance level of a test. In the case of a simple null hypothesis ? is the
probability of a type I error. If the null hypothesis is composite, ? is the maximum (supremum)
of the possible probabilities of a type I error.
A false positive error, or in short false positive, commonly called a \"false alarm\", is a result
that indicates a given condition has been fulfilled, when it actually has not been fulfilled. I.e.
erroneously a positive effect has been assumed. In the case of \"crying wolf\"
Solution
A type I error, also known as an error of the first kind, occurs when the null hypothesis (H0) is
true, but is rejected. It is asserting something that is absent, a false hit. A type I error may be
compared with a so-called false positive (a result that indicates that a given condition is present
when it actually is not present) in tests where a single condition is tested for. Type I errors are
philosophically a focus of skepticism and Occam\'s razor. A Type I error occurs when we believe
a falsehood.[4] In terms of folk tales, an investigator may be \"crying wolf\" without a wolf in
sight (raising a false alarm) (H0: no wolf).
The rate of the type I error is called the size of the test and denoted by the Greek letter ? (alpha).
It usually equals the significance level of a test. In the case of a simple null hypothesis ? is the
probability of a type I error. If the null hypothesis is composite, ? is the maximum (supremum)
of the possible probabilities of a type I error.
A false positive error, or in short false positive, commonly called a \"false alarm\", is a result
that indicates a given condition has been fulfilled, when it actually has not been fulfilled. I.e.
erroneously a positive effect has been assumed. In the case of \"crying wolf\".
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold.pdf
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold the organisms together.
Q3. there will be less oxygen available for the aquatic life due to microbial activity Q4. Oxygen
minimum zone Q5. Piezophiles.
Solution
Q1. Fundamental niche Q2. Presence of a cellulose matrix to hold the organisms together.
Q3. there will be less oxygen available for the aquatic life due to microbial activity Q4. Oxygen
minimum zone Q5. Piezophiles..
D orbitals are only available to atoms in rows 3-7. D orbitals only.pdf
D orbitals are only available to atoms in rows 3-7. D orbitals only exist for electrons with
primary quantum number (n) = 3 or greater. That is, there is no such thing as a 2d orbital. Thus
elements such as B, C, O, N, etc do not have available d orbitals, but the atoms immediately
below them: Al, Si, S, P, etc. do. Among atoms of a given element, there is no such thing as
having d orbitals available or not - that is, all S atoms have d orbitals available. However,
depending on the environment surrounding the atom, it may or may not be energetically
favorable to use the d orbitals for bonding. But whether or not they\'re used, they\'re always
there, and you can always consider them to be available.
Solution
D orbitals are only available to atoms in rows 3-7. D orbitals only exist for electrons with
primary quantum number (n) = 3 or greater. That is, there is no such thing as a 2d orbital. Thus
elements such as B, C, O, N, etc do not have available d orbitals, but the atoms immediately
below them: Al, Si, S, P, etc. do. Among atoms of a given element, there is no such thing as
having d orbitals available or not - that is, all S atoms have d orbitals available. However,
depending on the environment surrounding the atom, it may or may not be energetically
favorable to use the d orbitals for bonding. But whether or not they\'re used, they\'re always
there, and you can always consider them to be available..
Zeff - dec going down, inc going across IE - inc .pdf
Zeff - dec going down, inc going across IE - inc going up, inc going across EA - inc
going up, inc going acroos n - inc going down, same across For a graphic representation see:
http://upload.wikimedia.org/wikipedia/commons/f/fe/Periodic_trends.svg
Solution
Zeff - dec going down, inc going across IE - inc going up, inc going across EA - inc
going up, inc going acroos n - inc going down, same across For a graphic representation see:
http://upload.wikimedia.org/wikipedia/commons/f/fe/Periodic_trends.svg.
There are diastereomers. note Diastereomers (som.pdf
There are diastereomers. note: Diastereomers (sometimes called diastereoisomers)
are stereoisomers that are not enantiomers. Diastereomerism occurs when two or more
stereoisomers of a compound have different configurations at one or more (but not all) of the
equivalent (related) stereocenters and are not mirror images of each other.
Solution
There are diastereomers. note: Diastereomers (sometimes called diastereoisomers)
are stereoisomers that are not enantiomers. Diastereomerism occurs when two or more
stereoisomers of a compound have different configurations at one or more (but not all) of the
equivalent (related) stereocenters and are not mirror images of each other..
oxidesNa2O,MgO peroxidesK2O2,H2O2 superoxidesC.pdf
This document lists different types of chemical compounds including oxides like sodium oxide and magnesium oxide, peroxides such as potassium peroxide and hydrogen peroxide, and superoxides such as cesium superoxide.
Nuclear Fusion and please rate me Helpful atleast.pdf
Nuclear Fusion and please rate me Helpful atleast
Solution
Nuclear Fusion and please rate me Helpful atleast.
K2S potassium sulfide. This is an ordinary ionic.pdf
K2S: potassium sulfide. This is an ordinary ionic compound, and K only has one
oxidation state (+1) CoSO4: Cobalt(II) sulfate. The SO4(2-) anion is the sulfate anion. Since Co
has multiple oxidation states, we must specify (II) here. (NH(4))(3)PO(4): ammonium
phosphate. The (NH4)+ cation is the ammonium cation, and PO4(3-) is the phosphate ion.
Otherwise, this is just an ordinary ionic compound.\\ I think there is a typo in the last compound.
Ca(ClO)4 does not exist, but Ca(ClO4)2 and Ca(ClO)2 do. I\'ll name both - if neither is what you
need, let me know. Ca(ClO4)2: calcium perchlorate. Again, ClO4(-) is the perchlorate anion.
Calcium only has one oxidation state (+2, so we do not need to specify (II). Ca(ClO)2: calcium
hypochlorite. Here, ClO- is the hypochlorite anion, otherwise see above.
Solution
K2S: potassium sulfide. This is an ordinary ionic compound, and K only has one
oxidation state (+1) CoSO4: Cobalt(II) sulfate. The SO4(2-) anion is the sulfate anion. Since Co
has multiple oxidation states, we must specify (II) here. (NH(4))(3)PO(4): ammonium
phosphate. The (NH4)+ cation is the ammonium cation, and PO4(3-) is the phosphate ion.
Otherwise, this is just an ordinary ionic compound.\\ I think there is a typo in the last compound.
Ca(ClO)4 does not exist, but Ca(ClO4)2 and Ca(ClO)2 do. I\'ll name both - if neither is what you
need, let me know. Ca(ClO4)2: calcium perchlorate. Again, ClO4(-) is the perchlorate anion.
Calcium only has one oxidation state (+2, so we do not need to specify (II). Ca(ClO)2: calcium
hypochlorite. Here, ClO- is the hypochlorite anion, otherwise see above..
I believe you are missing the delocalized double .pdf
I believe you are missing the delocalized double bonds that make it toluene but the
answer should be E
Solution
I believe you are missing the delocalized double bonds that make it toluene but the
answer should be E.
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Florenone is polar compound and Flourene is nonpolar aromatic compound , So,
when we do column chromotography, Florenone will dissolve in eluent due to its polar nature so
,it is mobile phase and Flourene is stationary phase...
Solution
Florenone is polar compound and Flourene is nonpolar aromatic compound , So,
when we do column chromotography, Florenone will dissolve in eluent due to its polar nature so
,it is mobile phase and Flourene is stationary phase....
Equivalent Lewis structures are called resonance .pdf
Equivalent Lewis structures are called resonance structures. In this C) only
electrons can be moved
Solution
Equivalent Lewis structures are called resonance structures. In this C) only
electrons can be moved.
• Students who earn less than a “C” in an upper-division business or.pdf
• Students who earn less than a “C” in an upper-division business or accounting course are
eligible to repeat it only once and only if/when a seat becomes available. • No more than three
upper-division business and/or accounting courses are allowed to be repeated. Failure to comply
with either of these requirements will result in the student being dropped from the accounting
program and switched to another major. Students must earn a grade of “C” or higher in each
business and accounting course in order to graduate with a BS degree in Accountancy.
WITHDRAWAL FROM CLASS The last day to withdraw from this class without any approval
is Friday, February 6 (the end of the third week). To withdraw during the fourth week of
instruction, students must have a serious and compelling reason that is approved by the instructor
and department chair of this class. Requests for withdrawal after the fourth week are rarely
approved and only in cases where the student can provide written proof (to the department chair
and associate dean) of extraordinary circumstances that have arisen from events beyond the
student’s control. Furthermore, there must be no viable alternative to the requested withdrawal,
such as repeating the course. The following situations ARE NOT considered extraordinary
circumstances and WILL NOT be approved to justify a withdrawal after the end of the fourth
week of instruction: failing the class or receiving less-than-desired grade; waiting for the
instructor to give a permission number; failing to take action to add or drop a class, assuming
incorrectly that the instructor will do it for the student; failing to make payment of registration
and/or waiting for financial aid; the need to work because of financial considerations or
opportunities; encountering a situation that should have been anticipated, such as the need to
have transportation, the need to pay for ordinary living expenses, the need for child care;
aspirations of either the student or his/her family in regard to GPA, the dean\'s list, graduate
school, scholarships, etc.; dissatisfaction with class material, instructor, instructional method, or
class intensity; lack of motivation, change in academic interests, or change of major;
participation in extracurricular activities; or academic overload and inability to keep up in all
classes. The following situations are typically the only ones that would meet the standard of
extraordinary circumstances for which there is no viable alternative and would justify a
withdrawal after the fourth week of instruction: medical documentation that the academic
schedule is detrimental to the student\'s physical or mental health; activation for compulsory
military duty; relocation out of the immediate area. POLICY ON ACADEMIC DISHONESTY
Academic dishonesty, which includes cheating, fabrication, falsification, materially misleading
omissions, facilitation of academic dishonesty, and plagiarism, is a serious academic offense.
Please carefully review.
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Solution
Benzene differs from water because it is nonpolar meaning that there is no overall
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- 2. Enter Rainfall for the month 7: 77 Enter Rainfall for the month 8: 88 Enter Rainfall for the month 9: 99 Enter Rainfall for the month 10: 12 Enter Rainfall for the month 11: 14 Enter Rainfall for the month 12: 15 Entered rainfall details [33, 22, 11, 44, 55, 66, 77, 88, 99, 12, 14, 15] January: 33 Fabruary: 22 March: 11 April: 44 May: 55 June: 66 July: 77 August: 88 September: 99 October: 12 November: 14 December: 15 The total rainfall is :536 The average rainfall is :44.666666666666664 The maximum rainfall is :99 The maximum rainfall month is :September The minimum rainfall is :11 The minimum rainfall month is :March Solution RainfallTest.java import java.util.Arrays;
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