PYTHON- Write a function findMaxDiff() that takes a two-dimensional li.docx

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PYTHON: Write a function findMaxDiff() that takes a two-dimensional list of positive integers as a parameter. It prints the index of the row with the maximum difference between elements as well as the value of the maximum difference in that row. The maximum difference between elements in a row is defined to be the difference between the largest and smallest elements in the row. The function must not modify the list passed as a parameter. You may assume that each sublist in the parameter has at least one item in it. If there are multiple sublists that all achieve the maximum difference, the first sublist should be reported as the one with the maximum difference. T Solution def findMaxDiff(lst): \"Input:list(int); Output: (int, int)\" answer = [] index = max(range(len(lst)), key=lambda i: sum(lst[i])) holder = enumerate(max(x) - min(x) for x in lst) return max(x[::-1] for x in holder) return index .

PYTHON: Write a function findMaxDiff() that takes a two-dimensional list of positive integers
as a parameter. It prints the index of the row with the maximum difference between elements as
well as the value of the maximum difference in that row. The maximum difference between
elements in a row is defined to be the difference between the largest and smallest elements in the
row. The function must not modify the list passed as a parameter. You may assume that each
sublist in the parameter has at least one item in it. If there are multiple sublists that all achieve
the maximum difference, the first sublist should be reported as the one with the maximum
difference. T
Solution
def findMaxDiff(lst):
"Input:list(int); Output: (int, int)"
answer = []
index = max(range(len(lst)), key=lambda i: sum(lst[i]))
holder = enumerate(max(x) - min(x) for x in lst)
return max(x[::-1] for x in holder)
return index

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30. Higher speed image receptors generally produce images with a)Â Â Â Â Â Â Â Â Â Â Â Â Â Better resolution b)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased noise c)Â Â Â Â Â Â Â Â Â Â Â Â Â Higher contrast d)Â Â Â Â Â Â Â Â Â Â Â Â Â Increased density e)Â Â Â Â Â Â Â Â Â Â Â Â Wide latitude Solution Option B is correct Higher speed image receptors generally produce images with increased noise as it have to recieve images at higher speeds .

30- Higher speed image receptors generally produce images with a) Bet.docx

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Problem 3 Given 5.81 g of C11H22011, calculate the following: moles of C11H22011 0.0176 mol You are correct Your receipt no. is Previous Tries 4 4 number of oxygen atoms in C11H22011 1oxygen atoms Submit Answr Incorrect. Tries 1/5 Previous Tries mass of carbon atoms in C11H22011 Submit Answer Incorrect. Tries 1/5 Previous Tries Solution Given that 5.81 g of C11H22O11 Molar mass of C11H22O11= 330.286 g/mol Numbe rof mole s= amount in g/ molar mass =5.81g / 330.286 g/mol =0.0176 mole C11H22O11 1 mole of C11H22O11 contains =11 mole O And 1 mole = 6.022*10^23 atoms So 1 mole C11H22O11=6.6242 *10^24 atoms O There are 11 mole C Mass of C = number of mole s* molar mass =11*12.01 = 132.11 g C .

Problem 3 Given 5-81 g of C11H22011- calculate the following- moles of.docx

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QUESTION 11 Another name for the spread in a Eurocurrency loan is the _______. drawdown term LIBOR rate Margin 5 points QUESTION 12 Leading and lagging strategies have several advantages EXCEPT no formal note of indebtedness is needed governments are less like to interfere with payments on intercompany accounts interest must be charged on all intercompany accounts intercompany accounts up to six months are interest free Solution 11- Margin 12- no formal note of indebtedness is needed. .

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QUESTION 1 The following complex is yellow in color What color of light does this complex absorb? O yellow O green ?blue QUESTION 2 The following complex is yellow in color: Is this complex likely to be low spin or high spin? O low spin ?high spin QUESTION 3 The following complex is yellow in color How many unpaired electrons does this complex poss0s8? Solution 1. Any substance gives the color complementary to the color which it absorbs . The complementary color of yellow is violet .Hence it absorbs violet colour of light and appears yellow in colour. 2. Fe is in +3 oxidation state and 3d^5 configuration and thus high spin complex due presence of 5 unpaired e-s .Secondly as it shows colour so it is high spin as color is a property of inspired e-s . 3. 5 unpaired e-s as calculated in 2 question. .

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Propane (molar mass 44.11 g/mol) boils at -42.1Â°C. Ethanol has almost the same molar mass (46.07 g/mol), but boils at 78.5Â°C. Which of the following BEST explains the reason for the large discrepancy in boiling point? A. Â Â Propane is ionic and, therefore, has a lower boiling point. B. Â Â Ethanol is ionic and, therefore, has a higher boiling point. C. Â Â Both compounds only exhibit van der Waals forces. D. Â Â Both compounds are polar. Ethanol is more polar than Propane. E. Â Â Ethanol exhibits hydrogen bonding. F. Â Â Propane exhibits hydrogen bonding. Solution ethanol is having high boiling point than propane because in ethanol, the -OH group can form intermolecular hydrogen bonding. so there is association of molecules which it leads to greater boiling point. whereas in case of propane, no such hydrogen bonding is possible. .

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QUESTION 1 1 points S Saved What is the concentration of H2S in a saturated solution of H2S? Not enough information in the lab manual to decide. Smaller than 1.0 x 10-8 1.0 M O Greater than 6 M 1.3 M 0.10 M QUESTION 2 4 points Save Answer Match each type of ion to the method used to separate it Silver ions A. Precipitated by adding HCl. B. Precipitated using H2S in a very acidic sol C. Precipitated using H2S in a slightly basic solution. D. Precipitated by adding ammonium carbonate. E. Precipitated by adding sodium sulfide in a weakly basic uion Copper (1) ions Zinc ions Calcium ions solution. Solution Ans 1 : 0.10 M The concentration of H2S in a saturated solution of H2S is 0.10 M. The solubility of H2S is 0.00016 g / 100 g So the concentration = number of moles / volume of solution in L which comes approximately 0.10 M .

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