P13 017
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The document describes a pulley system with 4 cables where the tension doubles at each pulley. Cable 1 has a tension of F supporting a block with mass m. The tensions double so that the top cable has a tension of 8F. Calculating the total tension supporting the block yields F=8.96N. Therefore, the tension in the top cable is 8*8.96N = 71.7N.
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Lo2 rosalie ho
1) There are three simple pendulums with identical masses, string lengths, and angles of displacement. The period is the same for all three pendulums, while the tension increases with mass.
2) When the string length is halved for pendulum B and quadrupled for C, the period increases from B to A to C, while the tension and angular frequency rankings remain unchanged.
3) Pendulum A experiences the greatest drag force when it is perpendicular to gravity and therefore moving the fastest.
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P13 062
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P13 059
A balance has arms of length 1 and 2, and masses m1 and m2. The equations for torque equilibrium when the balance is balanced are m1*1=m2*2 and m1=m2*2. Dividing the equations and solving for the unknown mass gives the result that m = √(m1*m2).
P13 058
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P13 057
The document analyzes the forces at a knot holding a 5 kg mass at a 30 degree angle. It represents the static friction force and weight of the 5 kg mass as the sides of a right triangle. It finds that the static friction force equals the weight of the 5 kg mass multiplied by the tangent of 30 degrees. For the static friction force to be at its maximum, it must equal the coefficient of static friction multiplied by the weight of the 10 kg object. Equating these expressions allows one to calculate that the coefficient of static friction equals 0.29.
P13 056
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P13 053
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P13 050
The document describes calculating the forces acting on a beam attached to a hinge by a cable and balanced force. It finds that the cable exerts 88N of tension to balance the 50N force on the beam and no net torque. It then calculates the x and y components of the hinge force as 30N rightward and 97N upward to balance all the forces acting on the beam.
P13 048
This document describes calculating torques and forces on a beam hinged at one end. It finds that for a 12m beam with a 400N tension and angles of 40 and 50 degrees, the weight on the beam is 671N. Equilibrium equations show the horizontal hinge force is 400N of tension and the vertical force is approximately 670N of weight.
P13 047
1) The document describes calculating the torque on a ladder leaning against a wall and finding the horizontal force needed to keep it from sliding.
2) Key values given include the applied force F, the weight W, and moment arms used to calculate torque.
3) The torque equation is set to zero and rearranged to solve for the horizontal ground force Fgx for different values of F and W.
P13 046
This document describes the tensions in two strings (T and T') that are supporting a weight (W). It provides the force equilibrium equations relating the horizontal and vertical forces of T, T', and W. Solving these simultaneous equations yields that T = 15 N and T' = 29 N.
P13 045
The force exerted on the beam is 7900 N. To find the required cross-sectional area, the formula F/A = Su/6 is used, giving an area of 9.5 x 10-4 m2. Taking the square root of this area gives the thickness of 0.031 m.
P13 044
A steel cable supporting a 670 kg load experiences an elastic stretch proportional to its free length. For a cable length of 12m, the calculated stretch is 0.0008m. For a longer cable length of 350m, the calculated stretch increases to 0.023m due to the cable's increased free length.
P13 043
The document calculates the strain, stress, and Young's modulus of a rope used for rock climbing. It determines that the strain is 1.9 × 10−3 based on the rope's stretched length. The stress is calculated to be 1.3 × 107 N/m2 by relating the force of a 95 kg climber to the rope's cross-sectional area. Finally, it divides the stress by the strain to determine the rope's Young's modulus is 6.9 × 109 N/m2.
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The document summarizes the calculation of:
1) The volume of sand contained within a cylinder and cone of given dimensions is 6.78 cubic meters.
2) The weight of the sand is calculated to be 1.20 × 105 Newtons based on the volume and density.
3) An equation for stress as a function of radius is derived, with stress proportional to 13r + 40000 pascals.
4) The force on the cylinder is integrated and calculated to be 1.04 × 105 Newtons.
5) The fractional reduction in calculated force compared to measured weight is 13%.
P13 041
The document describes the equations used to determine the angle and tension required to move a log just before it begins to slide. It provides three equations setting the horizontal and vertical forces equal to the maximum static friction and torque, which are solved simultaneously to find the angle is 51 degrees when the coefficient of static friction is 0.8. The tension is then calculated to be 0.64 times the weight of the log.
P13 040
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P13 039
1) The forces exerted by wires A (FA) and B (FB) on a log are related by the stretching of the wires based on their original lengths (LA and LB), cross-sectional areas, and Young's modulus.
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P13 038
The brick compresses the two cylinders equally by an amount Δ. This means the force exerted by each cylinder is proportional to its cross-sectional area and elastic modulus. The ratio of the forces is 4:1. Combining this with the equation that the total force equals the weight gives the individual forces as 4W/5 and W/5. Computing torques about the center of mass confirms the 4:1 ratio of the distances of the forces from the center.
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【业务选择办理准则】
一、工作未确定，回国需先给父母、亲戚朋友看下文凭的情况，办理一份就读学校的毕业证【微信：A575476】文凭即可
二、回国进私企、外企、自己做生意的情况，这些单位是不查询毕业证真伪的，而且国内没有渠道去查询国外文凭的真假，也不需要提供真实教育部认证。鉴于此，办理一份毕业证【微信：A575476】即可
三、进国企，银行，事业单位，考公务员等等，这些单位是必需要提供真实教育部认证的，办理教育部认证所需资料众多且烦琐，所有材料您都必须提供原件，我们凭借丰富的经验，快捷的绿色通道帮您快速整合材料，让您少走弯路。
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
→ 【关于价格问题（保证一手价格）
我们所定的价格是非常合理的，而且我们现在做得单子大多数都是代理和回头客户介绍的所以一般现在有新的单子 我给客户的都是第一手的代理价格，因为我想坦诚对待大家 不想跟大家在价格方面浪费时间
对于老客户或者被老客户介绍过来的朋友，我们都会适当给一些优惠。
选择实体注册公司办理，更放心，更安全！我们的承诺：可来公司面谈，可签订合同，会陪同客户一起到教育部认证窗口递交认证材料，客户在教育部官方认证查询网站查询到认证通过结果后付款，不成功不收费！
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