Organophosphates area. herbicidesb. insecticidesDithiocarbama.pdf
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Organophosphates are: a. herbicides b. insecticides Dithiocarbamates are herbicides? True or False Solution True, because organophosphates are the reasons for many insecticides, herbicides, and nerve agents. Organophosphate pesticides degrade rapidly by hydrolysis on experience of sunlight, air, and soil, although small amounts is usually detected in food and drinking water. Their ability to degrade made them a good looking substitute for the persistent organochloride pesticides.
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Project Communications Management Case StudySeveral issues have a.pdf
Project Communications Management: Case Study
Several issues have arisen on the Recreation and Wellness Intranet Project. The person from the
HR department who was supporting the project left the company, and now the team needs more
support from that group. A member of the user group that supports the project is extremely vocal
and hard to work with, and other users can hardly get a word in at meetings. The project
manager, Tony, is getting weekly status reports from all of his team members, but many of them
do not address obvious challenges that people are facing. The team is having difficulty deciding
how to communicate various project reports and documents and where to store all of the
information being generated. Recall that the team members include you, a programmer/analyst
and aspiring project manager; Patrick, a network specialist; Nancy, a business analyst; and
Bonnie, another programmer/analyst.
Assignment – Project Communications Management: 3 Tasks
1. Prepare a partial communications management plan to address some of the challenges
mentioned in the previous paragraph.
2. Prepare a template and sample of a good weekly progress report that could be used for this
project. Include a list of tips to help team members provide information on these reports.
3. Write a one-page paper describing two suggested approaches to communicating with the hard-
to-work-with user.
Below I have provided the templates that I was given:
Communications Management Plan
Prepared by: Date:
1. Introduction
2. Collection and filing structure for gathering and storing project information
3. Distribution structure (what information goes to whom, when, and how)
4. Format, content, and level of detail of key project information
5. Production schedule and resources for producing key project information
6. Technologies, access methods, and frequency of communications
7. Method for updating the communications management plan
8. Escalation procedures
9. Stakeholder communications analysis
Stakeholders
Document Name
Document Format
Contact Person
Due Date
Comments:
10. Glossary of terms
Status/Progress Report
Project Name:
Team Member Name:
Date:
Reporting Period:
Work completed this reporting period:
Work to complete next reporting period:
What’s going well and why:
What’s not going well and why:
Suggestions/Issues:
Project changes
Stakeholders
Document Name
Document Format
Contact Person
Due Date
Comments:
Solution
1. Communications Management Plan
Prepared by: Joshua (me) Date: 3rd September 2015
This plan gives a detailed outline regarding communication and information exchange on the
Recreation and Wellness Intranet Project.
For collection and filing of information, all data will be stored on the intranet of the company, in
a seperate folder named Recreation and Wellness. Only members of the project and business
managers will have access to the folder.
Distribution structure - there should be a free and transparent flow of information amongst the
project members. .
Priority encoders are much more common than non-priority encoders. W.pdf
Priority encoders are much more common than non-priority encoders. What do you think the
reasons are for that?
Solution
consider an example.
nonpriority encoders are not used to detect interrupts in controllers only Priority encoders are
used to detecting interrupts in microcontrollers. since we have many interrupts and depends on
situation and no. of priorities the controller has to respond. the priority of the interrupts dettected
using priority encoder..
Prove that a reversible adiabatic process cannot also be isothermal f.pdf
Prove that a reversible adiabatic process cannot also be isothermal for T > 0.
Solution
When a system with two independent thermodynamic co-ordinates undergoes a reversible
adiabatic change of state then we can specify one thermodynamic co-ordinate for the final state
but not two , because change in entropy = S2-S1= 0, i.e. S is fixed . Thus a reversible adiabatic
process can\'t be isothermal because such a process will fix both T and S and it is impossible..
Passing arguments by-Value and using return types.#includeiost.pdf
// Passing arguments by-Value and using return types.
#include
using namespace std;
// Constant factor for gravitational acceleration
const double GRAVITATION_CONSTANT = 9.8; // meters/sec^2
// TODO: Declare 3 function prototypes
// - Name: getFallingTime
// Parameters:
// Returns: a double for the amount of time an object falls (to be entered by the user)
// - Name: fallingDistance
// Parameters:
// - 1 double for time in seconds (pass by value)
// Returns: a double for the number of meters the object falls
// - Name: displayResults
// Parameters:
// - 1 double for time (in seconds - pass by value)
// - 1 double for distance (in meters - pass by value)
// Returns:
// ********************************************
int main()
{
// Declare program variables.
double timeInSeconds, distanceInMeters;
// TODO: Call function to get the amount of time the object falls.
// A double value is returned - assign to the correct variable
// TODO: Call function to calculate the distance the object falls,
// given the seconds that it falls
// Pass one argument representing the amount of time the object falls.
// Assign the returned value to the correct variable
// TODO: Call function to print the results.
// Pass the correct two arguments to the function
// Nothing is returned, so do NOT provide a variable assignment
cout << \"End program - \";
return 0;
}
// ********************************************
// TODO: Define getFallingTime()
// Refer to the function prototype above for parameter and return type info
//
// Repeat
// - Prompt the user to enter the seconds the object falls
// - Read the user\'s keyboard response
// Until a value more than 0 is entered
// ********************************************
// TODO: Define fallingDistance()
// Refer to the function prototype above for parameter and return type info
//
// The formula for the distance an object falls due to gravity is:
// d = 1/2 gt^2 (^2 means squared)
// where:
// d = the distance the object falls (in meters)
// g = the gravitational acceleration constant (in meters per second squared)
// t = the amount of time the object falls (in seconds)
// ********************************************
// TODO: Define displayResults()
// Refer to the function prototype above for parameter and return type info
// Output statement to format results as shown in Sample Output
// using values passed to parameters.
/* Sample Output
Sample Run #1:
=====================
Enter seconds the object falls: 0
Enter seconds the object falls: 5.75
In 5.75 seconds, the object falls 162.006 meters.
End program - Press any key to continue . . .
Sample Run #2:
=====================
Enter seconds the object falls: -10
Enter seconds the object falls: -1
Enter seconds the object falls: 0.75
In 0.75 seconds, the object falls 2.75625 meters.
End program - Press any key to continue . . .
*/
Solution
#include
using namespace std;
// Constant factor for gravitational acceleration
const double GRAVITATION_CONSTANT = 9.8; // meters/sec^2
/.
Match the functions with the plots. The following pictures are image.pdf
Match the functions with the plots. The following pictures are images of the region U = {z = x +
i y: pi/6 lessthanorequalto x lessthanorequalto pi/3, pi/6 lessthanorequalto y lessthanorequalto
pi/3}. Match the plot with the corresponding function. (Notice that the plots have different
scales.)
Solution
Function Plot tan (z) D sin (z) C cos (z) B Log (z) A.
July 4 Paid utilities expense of $370 Cash Accounts Payable Service .pdf
July 4: Paid utilities expense of $370 Cash Accounts Payable Service Revenue u 2 14,000
Accounts Receivable Notes Payable Utilities Expense Office Supplies Common Stock 14,000
Jul. 2 Equipment Dividends
Solution
Cash
July 2
$14000
$370
July 4
July 12
$7100
$200
July 19
$840
July 21
$1600
July 27
Accounts Payable
July 27
$1600
$1600
July 5
Service Revenue
$2900
July 10
Accounts Receivable
July 10
$2900
Notes Payable
$7100
July 12
Utilities Expense
July 4
$370
Office Supplies
July 21
$840
Common Stock
$14000
July 2
Equipment
July 5
$1600
Dividends
July 19
$200
Cash
July 2
$14000
$370
July 4
July 12
$7100
$200
July 19
$840
July 21
$1600
July 27.
Income statements and balance sheets follow for The New York Times C.pdf
Income statements and balance sheets follow for The New York Times Company. Refer to these
financial statements to answer the requirements.
The New York Times Company
Consolidated Statements of Income
Fiscal year ended
(in thousands)
Dec. 29, 2016
Dec. 30, 2015
Revenues
Circulation
$ 880,543
$ 851,790
Advertising
580,732
638,709
Other
94,067
88,716
Total revenues
1,555,342
1,579,215
Production costs
Wages and benefits
363,051
354,516
Raw materials
72,325
77,176
Other
192,728
186,120
Total production costs
628,104
617,812
Selling, general and administrative costs
721,083
713,837
Depreciation and amortization
61,723
61,597
Total operating costs
1,410,910
1,393,246
Restructuring charge
14,804
0
Multiemployer pension plan withdrawal expense
6,730
9,055
Pension settlement charges
21,294
40,329
Early termination charge
0
0
Operating profit
101,604
136,585
Loss from joint ventures
(36,273)
(783)
Interest expense, net
34,805
39,050
Income from continuing operations before income taxes
30,526
96,752
Income tax expense/(benefit)
4,421
33,910
Income from continuing operations
26,105
62,842
Loss from discontinued operations, net of income taxes
(2,273)
0
Net income
23,832
62,842
Net loss attributable to the noncontrolling interest
5,236
404
Net income attributable to The New York Times Company common stockholders
$29,068
$63,246
Continued next page
The New York Times Company
Consolidated Balance Sheets
As of
(in thousands)
Dec. 29, 2016
Dec. 30, 2015
Cash and cash equivalents
$ 100,692
$ 105,776
Short-term investments
449,535
507,639
Accounts receivable, net
197,355
207,180
Prepaid assets
15,948
19,430
Other current assets
32,648
22,507
Total current assets
796,178
862,532
Long-term marketable securities
187,299
291,136
Investments in joint ventures
15,614
22,815
Property plant and equipment, net
596,743
632,439
Goodwill
134,517
109,085
Deferred income taxes
301,342
309,142
Miscellaneous assets
153,702
190,541
Total assets
$2,185,395
$2,417,690
Accounts payable
$ 104,463
$ 96,082
Accrued payroll and other related liabilities
96,463
98,256
Unexpired subscriptions
66,686
60,184
Current portion of long-term debt
0
188,377
Accrued expenses and other
131,125
120,686
Total current liabilities
398,737
563,585
Long-term debt and capital lease obligations
246,978
242,851
Pension benefits obligation
558,790
627,697
Postretirement benefits obligation
57,999
62,879
Other
78,647
92,223
Total other liabilities
942,414
1,025,650
Stockholders’ equity
Common stock of $0.10 par value
Class A common stock
16,921
16,826
Class B convertible stock
82
82
Additional paid-in capital
149,928
146,348
Retained earnings
1,331,911
1,328,744
Common stock held in treasury, at cost
(171,211)
(156,155)
Accumulated other comprehensive loss, net of tax
(479,816)
(509,094)
Total New York Times Company stockholders’ equity
847,815
826,751
Noncontrolling interest
(3,571)
1,704
Total stockholders’ equity
844,244
828,455
Total liabilities and stockholders’ equity
$2,185,395.
$2,185,395
d. Compu.
How do contemporary economic geographers view the economy From a ge.pdf
How do contemporary economic geographers view the economy? From a geographers point of
view,
Solution
The geographers view the distribution of economic resources as the means of economic activity.
Industrial locations today are dependent on the geographical distribution of resources whether
natural or man-made. Though these resources, which impact the economy are highly unequally
distributed. Their point is that the whole of economy is dependent of the geographical
distribution of resources and ease of use and doing business in the geographical location.
The geographers view also consists of service based sectors in the economy such as those
commercial spaces where people uses internet and technology. The geographers view is to
change the conventional economy into a digital economy, where there are robust and dynamic
technological changes. Geographers are interested in the impact of the economic processes on
the geographic structure. For example impact of economic processes on spatial structures..
Recommended
Project Communications Management Case StudySeveral issues have a.pdf
Project Communications Management: Case Study
Several issues have arisen on the Recreation and Wellness Intranet Project. The person from the
HR department who was supporting the project left the company, and now the team needs more
support from that group. A member of the user group that supports the project is extremely vocal
and hard to work with, and other users can hardly get a word in at meetings. The project
manager, Tony, is getting weekly status reports from all of his team members, but many of them
do not address obvious challenges that people are facing. The team is having difficulty deciding
how to communicate various project reports and documents and where to store all of the
information being generated. Recall that the team members include you, a programmer/analyst
and aspiring project manager; Patrick, a network specialist; Nancy, a business analyst; and
Bonnie, another programmer/analyst.
Assignment – Project Communications Management: 3 Tasks
1. Prepare a partial communications management plan to address some of the challenges
mentioned in the previous paragraph.
2. Prepare a template and sample of a good weekly progress report that could be used for this
project. Include a list of tips to help team members provide information on these reports.
3. Write a one-page paper describing two suggested approaches to communicating with the hard-
to-work-with user.
Below I have provided the templates that I was given:
Communications Management Plan
Prepared by: Date:
1. Introduction
2. Collection and filing structure for gathering and storing project information
3. Distribution structure (what information goes to whom, when, and how)
4. Format, content, and level of detail of key project information
5. Production schedule and resources for producing key project information
6. Technologies, access methods, and frequency of communications
7. Method for updating the communications management plan
8. Escalation procedures
9. Stakeholder communications analysis
Stakeholders
Document Name
Document Format
Contact Person
Due Date
Comments:
10. Glossary of terms
Status/Progress Report
Project Name:
Team Member Name:
Date:
Reporting Period:
Work completed this reporting period:
Work to complete next reporting period:
What’s going well and why:
What’s not going well and why:
Suggestions/Issues:
Project changes
Stakeholders
Document Name
Document Format
Contact Person
Due Date
Comments:
Solution
1. Communications Management Plan
Prepared by: Joshua (me) Date: 3rd September 2015
This plan gives a detailed outline regarding communication and information exchange on the
Recreation and Wellness Intranet Project.
For collection and filing of information, all data will be stored on the intranet of the company, in
a seperate folder named Recreation and Wellness. Only members of the project and business
managers will have access to the folder.
Distribution structure - there should be a free and transparent flow of information amongst the
project members. .
Priority encoders are much more common than non-priority encoders. W.pdf
Priority encoders are much more common than non-priority encoders. What do you think the
reasons are for that?
Solution
consider an example.
nonpriority encoders are not used to detect interrupts in controllers only Priority encoders are
used to detecting interrupts in microcontrollers. since we have many interrupts and depends on
situation and no. of priorities the controller has to respond. the priority of the interrupts dettected
using priority encoder..
Prove that a reversible adiabatic process cannot also be isothermal f.pdf
Prove that a reversible adiabatic process cannot also be isothermal for T > 0.
Solution
When a system with two independent thermodynamic co-ordinates undergoes a reversible
adiabatic change of state then we can specify one thermodynamic co-ordinate for the final state
but not two , because change in entropy = S2-S1= 0, i.e. S is fixed . Thus a reversible adiabatic
process can\'t be isothermal because such a process will fix both T and S and it is impossible..
Passing arguments by-Value and using return types.#includeiost.pdf
// Passing arguments by-Value and using return types.
#include
using namespace std;
// Constant factor for gravitational acceleration
const double GRAVITATION_CONSTANT = 9.8; // meters/sec^2
// TODO: Declare 3 function prototypes
// - Name: getFallingTime
// Parameters:
// Returns: a double for the amount of time an object falls (to be entered by the user)
// - Name: fallingDistance
// Parameters:
// - 1 double for time in seconds (pass by value)
// Returns: a double for the number of meters the object falls
// - Name: displayResults
// Parameters:
// - 1 double for time (in seconds - pass by value)
// - 1 double for distance (in meters - pass by value)
// Returns:
// ********************************************
int main()
{
// Declare program variables.
double timeInSeconds, distanceInMeters;
// TODO: Call function to get the amount of time the object falls.
// A double value is returned - assign to the correct variable
// TODO: Call function to calculate the distance the object falls,
// given the seconds that it falls
// Pass one argument representing the amount of time the object falls.
// Assign the returned value to the correct variable
// TODO: Call function to print the results.
// Pass the correct two arguments to the function
// Nothing is returned, so do NOT provide a variable assignment
cout << \"End program - \";
return 0;
}
// ********************************************
// TODO: Define getFallingTime()
// Refer to the function prototype above for parameter and return type info
//
// Repeat
// - Prompt the user to enter the seconds the object falls
// - Read the user\'s keyboard response
// Until a value more than 0 is entered
// ********************************************
// TODO: Define fallingDistance()
// Refer to the function prototype above for parameter and return type info
//
// The formula for the distance an object falls due to gravity is:
// d = 1/2 gt^2 (^2 means squared)
// where:
// d = the distance the object falls (in meters)
// g = the gravitational acceleration constant (in meters per second squared)
// t = the amount of time the object falls (in seconds)
// ********************************************
// TODO: Define displayResults()
// Refer to the function prototype above for parameter and return type info
// Output statement to format results as shown in Sample Output
// using values passed to parameters.
/* Sample Output
Sample Run #1:
=====================
Enter seconds the object falls: 0
Enter seconds the object falls: 5.75
In 5.75 seconds, the object falls 162.006 meters.
End program - Press any key to continue . . .
Sample Run #2:
=====================
Enter seconds the object falls: -10
Enter seconds the object falls: -1
Enter seconds the object falls: 0.75
In 0.75 seconds, the object falls 2.75625 meters.
End program - Press any key to continue . . .
*/
Solution
#include
using namespace std;
// Constant factor for gravitational acceleration
const double GRAVITATION_CONSTANT = 9.8; // meters/sec^2
/.
Match the functions with the plots. The following pictures are image.pdf
Match the functions with the plots. The following pictures are images of the region U = {z = x +
i y: pi/6 lessthanorequalto x lessthanorequalto pi/3, pi/6 lessthanorequalto y lessthanorequalto
pi/3}. Match the plot with the corresponding function. (Notice that the plots have different
scales.)
Solution
Function Plot tan (z) D sin (z) C cos (z) B Log (z) A.
July 4 Paid utilities expense of $370 Cash Accounts Payable Service .pdf
July 4: Paid utilities expense of $370 Cash Accounts Payable Service Revenue u 2 14,000
Accounts Receivable Notes Payable Utilities Expense Office Supplies Common Stock 14,000
Jul. 2 Equipment Dividends
Solution
Cash
July 2
$14000
$370
July 4
July 12
$7100
$200
July 19
$840
July 21
$1600
July 27
Accounts Payable
July 27
$1600
$1600
July 5
Service Revenue
$2900
July 10
Accounts Receivable
July 10
$2900
Notes Payable
$7100
July 12
Utilities Expense
July 4
$370
Office Supplies
July 21
$840
Common Stock
$14000
July 2
Equipment
July 5
$1600
Dividends
July 19
$200
Cash
July 2
$14000
$370
July 4
July 12
$7100
$200
July 19
$840
July 21
$1600
July 27.
Income statements and balance sheets follow for The New York Times C.pdf
Income statements and balance sheets follow for The New York Times Company. Refer to these
financial statements to answer the requirements.
The New York Times Company
Consolidated Statements of Income
Fiscal year ended
(in thousands)
Dec. 29, 2016
Dec. 30, 2015
Revenues
Circulation
$ 880,543
$ 851,790
Advertising
580,732
638,709
Other
94,067
88,716
Total revenues
1,555,342
1,579,215
Production costs
Wages and benefits
363,051
354,516
Raw materials
72,325
77,176
Other
192,728
186,120
Total production costs
628,104
617,812
Selling, general and administrative costs
721,083
713,837
Depreciation and amortization
61,723
61,597
Total operating costs
1,410,910
1,393,246
Restructuring charge
14,804
0
Multiemployer pension plan withdrawal expense
6,730
9,055
Pension settlement charges
21,294
40,329
Early termination charge
0
0
Operating profit
101,604
136,585
Loss from joint ventures
(36,273)
(783)
Interest expense, net
34,805
39,050
Income from continuing operations before income taxes
30,526
96,752
Income tax expense/(benefit)
4,421
33,910
Income from continuing operations
26,105
62,842
Loss from discontinued operations, net of income taxes
(2,273)
0
Net income
23,832
62,842
Net loss attributable to the noncontrolling interest
5,236
404
Net income attributable to The New York Times Company common stockholders
$29,068
$63,246
Continued next page
The New York Times Company
Consolidated Balance Sheets
As of
(in thousands)
Dec. 29, 2016
Dec. 30, 2015
Cash and cash equivalents
$ 100,692
$ 105,776
Short-term investments
449,535
507,639
Accounts receivable, net
197,355
207,180
Prepaid assets
15,948
19,430
Other current assets
32,648
22,507
Total current assets
796,178
862,532
Long-term marketable securities
187,299
291,136
Investments in joint ventures
15,614
22,815
Property plant and equipment, net
596,743
632,439
Goodwill
134,517
109,085
Deferred income taxes
301,342
309,142
Miscellaneous assets
153,702
190,541
Total assets
$2,185,395
$2,417,690
Accounts payable
$ 104,463
$ 96,082
Accrued payroll and other related liabilities
96,463
98,256
Unexpired subscriptions
66,686
60,184
Current portion of long-term debt
0
188,377
Accrued expenses and other
131,125
120,686
Total current liabilities
398,737
563,585
Long-term debt and capital lease obligations
246,978
242,851
Pension benefits obligation
558,790
627,697
Postretirement benefits obligation
57,999
62,879
Other
78,647
92,223
Total other liabilities
942,414
1,025,650
Stockholders’ equity
Common stock of $0.10 par value
Class A common stock
16,921
16,826
Class B convertible stock
82
82
Additional paid-in capital
149,928
146,348
Retained earnings
1,331,911
1,328,744
Common stock held in treasury, at cost
(171,211)
(156,155)
Accumulated other comprehensive loss, net of tax
(479,816)
(509,094)
Total New York Times Company stockholders’ equity
847,815
826,751
Noncontrolling interest
(3,571)
1,704
Total stockholders’ equity
844,244
828,455
Total liabilities and stockholders’ equity
$2,185,395.
$2,185,395
d. Compu.
How do contemporary economic geographers view the economy From a ge.pdf
How do contemporary economic geographers view the economy? From a geographers point of
view,
Solution
The geographers view the distribution of economic resources as the means of economic activity.
Industrial locations today are dependent on the geographical distribution of resources whether
natural or man-made. Though these resources, which impact the economy are highly unequally
distributed. Their point is that the whole of economy is dependent of the geographical
distribution of resources and ease of use and doing business in the geographical location.
The geographers view also consists of service based sectors in the economy such as those
commercial spaces where people uses internet and technology. The geographers view is to
change the conventional economy into a digital economy, where there are robust and dynamic
technological changes. Geographers are interested in the impact of the economic processes on
the geographic structure. For example impact of economic processes on spatial structures..
I am solving Rational Inequalities and I am a little confused about .pdf
I am solving Rational Inequalities and I am a little confused about when I am supposed to change
the direction of the inequality sign. Is it when I divide by a negative number? If so, a negative
numerator? a negative denominator or both?
Solution
If we want to change direction of inequlity sign then we mulitply or divide by a negative number.
If we divide then either divide numerator or denominator ( any one) with negative sign..
How would your plates appear if you incubated agar when they were co.pdf
How would your plates appear if you incubated agar when they were contaminated? What about
if they weren\'t?
Solution
Ans. Incubating a contaminated plate shows microbial growth. Incubation of a sterile plate (no
contamination, no inoculation) shows no microbial growth.
In case of an inoculated plate- the contaminated plate (contaminated with microbes other than
those present in inoculum) show much rapid and outgrowth of many undesirable colonies. When
not contaminated, the same inoculated plate shows less number of colonies and clearly separated
(most often) colonies.
Sometimes it’s preferred to incubate inoculated plates as a control. The control plate serves the
following purpose-
I. Since this plate is not inoculated, there shall be no microbial growth on the plate after
incubation period. If so, absence of microbial growth on plate indicates that the all steps, from
media preparation to inoculation chamber, follows aseptic techniques and are reliable and
reproducible.
II. If an uninoculated plate show microbial growth, contamination has occurred at one or more
steps. Moreover, the cultural techniques adopted need to be recalibrated thoroughly..
Hormones are distributed throughout the body in blood and other body.pdf
Hormones are distributed throughout the body in blood and other body fluids. Why don’t all
tissues/cells
respond to all hormones?
Solution
The “endocrine glands” are ductless glands, which release the hormones into the blood and are
transported to a site distant from its origin where it produces its action. It is known as endocrine
signalling. Though the endocrine hormones travel throughout the blood, only specific tissues
respond to each hormone because hormones bind to specific receptors to produce physiological
effects. For example, the insulin released by pancreas binds to the insulin receptor. The
luteinizing hormone (LH) and follicle-stimulating hormone (FSH) acts on receptors prominent in
ovaries and uterus..
Explain the internet infrastructure stack. SolutionInternet inf.pdf
Explain the internet infrastructure stack.
Solution
Internet infrastructure includes all the hardware and software that helps in the functioning of the
internet ecosystem. In simpler words, all hardware and software that helps a web page appear on
a browser can be defined as internet infrastructure.
It includes:.
Each hormone is known to have a specific target tissue. For each of t.pdf
Each hormone is known to have a specific target tissue. For each of the following hormones, list
its target tissue and describe its specific action. thyroxine estrogen thyroid stimulating hormone
(TSH) insulin follicle stimulating hormone (FSH) What is the role of the hypothalamus in the
production of thyroxine and TsH? How does thyrotropin releasing hormone (TRH travel from
the hypothalamus to the pituitary gland? It travels through the bleed sream
Solution
2.
Hormone
Specific target tissue
Function
Thyroxine
All through the body especially liver and kidneys
Increases the basal metabolic rate and promotes growth as well as development
Estrogen
Female reproductive system
Helps in sexual growth and development and helps in good functioning of the female
reproductive system
TSH
Thyroid gland
Stimulates the thyroid hormone secretion
Insulin
Throughout the body
Helps in regulating levels of blood glucose levels; facilitates the body cells to intake glucose;
helps in increasing glycogem storage
FSH
Sex gland
Stimulates the maturation of female eggs and also production of sperms
3. when T3 and T4 levels are low in the blood, the hypothalamus senses it and secretes TRH
(thyrotropin releasing hormone) which in turn triggers the pituitary to release TSH (thyroid
stimulating hormone) which stimulates the thyroid gland to release thyroxine.
Hormone
Specific target tissue
Function
Thyroxine
All through the body especially liver and kidneys
Increases the basal metabolic rate and promotes growth as well as development
Estrogen
Female reproductive system
Helps in sexual growth and development and helps in good functioning of the female
reproductive system
TSH
Thyroid gland
Stimulates the thyroid hormone secretion
Insulin
Throughout the body
Helps in regulating levels of blood glucose levels; facilitates the body cells to intake glucose;
helps in increasing glycogem storage
FSH
Sex gland
Stimulates the maturation of female eggs and also production of sperms.
Describe the differences in the appearance of the sterile tube of Try.pdf
Describe the differences in the appearance of the sterile tube of Tryptic soy broth and the one in
which microorganisms are growing. Do the same for the slants.
Solution
Uninoculated or sterile Tryptic soy broth appears light amber and clear with no precipitates. If
microorganisms are growing in the broth, then it appears turbid with visible precipitates or
flocculates. Trypticase soy broth is an enrichment medium. It cannot be used for growing
fastidious organisms.
Sterile slants appear clear without any visible colonies. Whereas if microbes are growing, then
the colonies of the microbes can be seen on the slant..
As we entered the 21st century, the Human Genome Project, a massive .pdf
As we entered the 21st century, the Human Genome Project, a massive collaborative effort by
scientists all over the world, reached the first stage of completion; we now have the complete
sequence of human DNA. What is the value of this information?
Solution
Human Genome Project (HGP) is one of the biggest genome projects completed. In this project,
the whole human genome is sequenced to identify all the genes. From the data interpreted till
now, it was concluded that humans share some set of genes with all other species.
Also, humans contain certain unique set of genes that are necessary for intellectual functioning
and the other unique characteristic of humans. However, sharing the genome with the all other
species indicates that all living organisms arose from a common ancestor.
The major goals of Human Genome Project are,
The data provided by the human genome project directs the scientists to identify the genes
associated with several of the diseases. Identifying the disease-causing genes and their
inheritance would be useful in designing treatment for these diseases..
ActiveX is used by which of the following technologiesA. JavaB..pdf
ActiveX is used by which of the following technologies?
A. Java
B. CORBA
C. EJB
D. DCOM
Solution
D. The Distributed Object Component Model (DCOM) allows applications to be divided into
pieces and objects to be run remotely over the network. Potential vulnerabilities exist because of
the way ActiveX is integrated with DCOM. Answer A is incorrect answer B is incorrect because
CORBA is a set of standards that addresses the need for interoperability between hardware and
software. Answer C is incorrect because Enterprise JavaBeans (EJB) is designed for enterprise
networks.
CBE 20. The following information is from financial statements (in mi.pdf
CBE 20. The following information is from financial statements (in millions of dollars Total
assets 150S Net financial assets 90 financial obligations 15S common equity 75S What was the
value of the operating assets? A. 45 B. 60 C. 75 D. 135 21.At the end of the fiscal year ending
June 30, 2003, Microsot equity of $64.9 billion on its balance sheet, with $4 assets (in the form
of cash equivalents and short term investmentancial debt. For fiscal year 2004, the firm reported
S7.4 billio of which $1.1 billion was after-tax earnings on the financial assets. This month
Microsoft is distributing $34 billion of financial assets to shareholders in the of a special
dividend. 9.0 billion invested in and no financing n in comprehensive income, form a. Calculate
Microsoft\'s return on common equity (ROCE) for 2004. Holding all else constant what would
Microsoft\'s ROCE be S34 billion? after the payout of b.
Solution
PART-1).
Below is a simple Role Play Game (RPG) Simulator program.importjav.pdf
Below is a simple Role Play Game (RPG) Simulator program.
importjava.util.Random;
// Student, Programmer
publicclassRPGSimulator {
publicstaticvoidmain(Stringargs[])throwsInterruptedException
{
Randomrand1=newRandom();
Randomrand2=newRandom();
Stringmission1=\"Capture the Castle\";
Stringmission2=\"Enter the Hidden City\";
Stringmission3=\"Rescue the Princess\";
Stringmission4=\"Traverse the Forest\";
Stringmission5=\"Locate the Tunnel Entrance\";
Stringplayer1=\"\",player2=\"\";
charletter=\'\\0\',role=\'\\0\';
// initial health and treasures for the two players
intnumber= 0,mission= 0,health1= 100,health2= 100;
inttreasure1= 100,treasure2= 100,encounter= 0;
// define your role
role= (char)(rand1.nextInt(26) +\'a\');
if(role>=\'a\'&&role<=\'m\')
{
player1=\"protagonist\";
player2=\"opponent\";
}
else
{
player1=\"opponent\";
player2=\"protagonist\";
}
System.out.println(\"you are the \"+player1);
// define your mission
number=rand2.nextInt(5) + 1;
System.out.print(\"your mission is: \");
switch(number)
{
case1: System.out.println(mission1);mission= 1;break;
case2: System.out.println(mission2);mission= 2;break;
case3: System.out.println(mission3);mission= 3;break;
case4: System.out.println(mission4);mission= 4;break;
case5: System.out.println(mission5);mission= 5;break;
}
System.out.println(\"\");
// let the game simulation commence (limit the # of encounters)
for(encounter= 1;encounter<= 20;encounter++)
{
letter= (char)(rand1.nextInt(3) +\'a\');
number=rand2.nextInt(10) + 1;
// randomly encounter the enemy
if(letter==\'a\'||letter==\'b\')
//if(mission == 1 || mission == 2 || mission == 3)
{
health1-= 10;
health2+= 15;
treasure1+= 10;
treasure2-= 10;
//Thread.sleep(5000);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//encounter++;
}
elseif(letter==\'c\'||letter==\'d\')
{
health1+= 20;
health2-= 30;
treasure1+= 40;
treasure2-= 20;
//Thread.sleep(500);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//break;
}
else
{
health1+= 30;
health2-= 20;
treasure1-= 30;
treasure2+= 20;
//Thread.sleep(500);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//break;
}
health1-= 5;
health2-= 5;
treasure1-= 5;
treasure2-= 5;
if(health1<= 0 ||health2<= 0 ||treasure1<= 0 ||treasure2<= 0)
{
//System.out.print(\"encounter: \" + encounter + \" action status: \");
break;
}
}
System.out.println(\"simulation has ended\ \");
System.out.println(\"results:\ \".
A swim bladder allows a fish to Regulate its water content in sea wa.pdf
A swim bladder allows a fish to Regulate its water content in sea water. Regulate its salt
content in sea water. Regulate its salt content in fresh water. Control its buoyancy. Tolerate
changes in water pressure. Monotremes are classified as mammals because they Are carnivores.
Give birth to live young rather than lay eggs. Have mammary glands. Are omnivores. Are
endoderms. In plants which of the following are produced by meiosis? Haploid sporophytes.
Diploid gametes. Haploid gametes. Haploid spores. Diploid spores. Which of the following is
a feature that sets primates apart from all other mammals? Placental embryonic development.
Opposable thumb. Ability to produce milk. Naked faces. Hairy bodies. Fertilization in the
earthworm is accomplished by the use of the Nephridium. Clitellium. Flame cells. Tracheal
system Typhosole. Humans and apes are presently classified in the same category as all of the
following levels except Class. Genus. Kingdo
Solution
question
Answer
explanation
16
d. controls its buoyancy
The swim bladder or air bladder: it is an inner gas-filled organ that adds to the capacity of
numerous hard fish (yet not cartilaginous fish to control their lightness, and in this way to remain
at their ebb and flow water profundity without wasting vitality in swimming.
17
c.have mammary glands
It is an organ situated in the bosoms of females that is in charge of lactation, or the creation of
drain. Both guys and females have glandular tissue inside the bosoms; be that as it may, in
females the glandular tissue starts to create after adolescence in light of estrogen discharge
18
d. haploid spores
Spores are normally haploid and unicellular and are delivered by meiosis in the sporangium of a
diploid sporophyte
19
B, opposable thumb
Primates : they are with completely opposable thumbs incorporate the Great primates (people,
chimpanzees, gorillas, and orangutans) and Old World monkeys
20
B . clitellum
clitellum: it is a thickened glandular and non-portioned area of the body divider close to the head
in worms and bloodsuckers, that secretes a viscid sac in which the eggs are stored. It is available
around 2 cm (0.79 in) behind the foremost end of the body (around the fourteenth, fifteenth and
sixteenth sections)
21
B .genus
question
Answer
explanation
16
d. controls its buoyancy
The swim bladder or air bladder: it is an inner gas-filled organ that adds to the capacity of
numerous hard fish (yet not cartilaginous fish to control their lightness, and in this way to
remain at their ebb and flow water profundity without wasting vitality in swimming.
17
c.have mammary glands
It is an organ situated in the bosoms of females that is in charge of lactation, or the creation of
drain. Both guys and females have glandular tissue inside the bosoms; be that as it may, in
females the glandular tissue starts to create after adolescence in light of estrogen discharge
18
d. haploid spores
Spores are normally haploid and unicellular and are delivered by meios.
12. You want to extract dsDNA from live tissue. Which of the followi.pdf
12. You want to extract dsDNA from live tissue. Which of the following is an option, not a
necessity?
A. SDS
B. RNase A
C. S1 nuclease
D. Exonucleases
Solution
Option B. RNase A. It is used to denature RNA and extract DNA in pure form.
S1 nuclease is used to extract single stranded DNA or RNA.
SDS is absolutely necessary for DNA extraction, so it is not an option but a necessity..
1. Given that mitochondria are the “powerhouse” of the cell, how can.pdf
1. Given that mitochondria are the “powerhouse” of the cell, how can Giardia survive and thrive
with reduced mitochondria? Be specific during the explanation.
2. Explain how the light detector and eyespot aid Euglena in meeting its nutritional
requirements. Be specific.
3. Paramecium has both a macronucleus and a micronucleus. What is the function of each of
these structures? Which one is involved in reproduction? What are the different methods of
reproduction that Paramecium can use?
4. The geometric appearance of diatoms is due to what structural compound? What are some of
the commercial applications for diatoms?
5. Describe how radiolarians use their threadlike pseudopodia to “feed.”
Solution
1.Giardia survives by eating anaerobic bacteria in these rich anoxic environments.They thrive in
anaerobic environments such as marine or freshwater sediments,salt,marshes,rumen,and
intestinal tracts of metazoa;some are parasitic.Giardia makes all of its ATP in the cytosol with
the help of simple anaerobic pathways.Several enzymes of Giardia’s ATP-generating machinery
contain Fe–S clusters,which are ubiquitous cofactors in the electron-transfer reactions involved
in ATP production.They are essential for the parasite’s survival.Eukaryotes that lack
mitochondria oxidize pyruvate with the O2-sensitive enzyme pyruvate:ferredoxin oxidoreductase
(PFO).Like PDH,PFO yields CO2 and acetyl-CoA,but the electrons that are removed from
pyruvate are not transferred to NAD+ as in the PDH reaction,but rather to ferredoxin.The
resulting acetyl-CoA is further converted into a mixture of ethanol and acetate.
2.Euglena have an eyespot at the anterior end that detects light which helps the euglena find
bright areas to gather sunlight to make their food.The euglena\'s eyespot is not an eye,but it can
react to changes in the brightness of a light source.The eyespot is important because it helps the
euglena move toward light,the source of energy for photosynthesis.The intensity of visible light
determines the area towards which Euglenas swim,which always is towards the source of
light,i.e.towards the place where the light is more intense.Euglena can also gain nutrients by
absorbing them across their cell membrane,hence they become heterotrophic when light is not
available,and they cannot photosynthesize.
3..
Write a C++ program 1. Study the function process_text() in file.pdf
Write a C++ program
1. Study the function process_text() in file \"text_processing.cpp\". What do the string member
functions find(), substr(), c_str() do?
//text_processing.cpp
#include \"util.h\"
#include \"text_processing.h\"
#include
using namespace std;
int process_text( fstream &ifs, fstream &ofs, char target[] )
{
string replace_str( \"XXX\" ); //hard-coded string for replacement
int tlen = strlen( target ); //string length of target
int max_len = 200; //maximum length of a line
char s[max_len+1];
clear_screen(); //clear the screen
while ( !ifs.eof() ) {
int i2, i1 = 0, len=0;
ifs.getline( s, max_len ); //get one line from file
string str( s ); //construct a string object
i2 = str.find ( target, i1 ); //find target
len = i2 - i1;
if ( i2 > -1 && len > 0 ){ //if target found
print_text( str.substr( i1, i2 ).c_str() ); //print up to target
ofs << str.substr( i1, i2 );
}
while ( i2 > -1 ) {
print_text_inverse ( target ); //highlight target
ofs << replace_str;
i1 = i2 + tlen; //new search position
i2 = str.find ( target, i1 ); //find next target
len = i2 - i1;
if ( i2 > -1 && len > 0 ){ //found target
print_text( str.substr( i1, len ).c_str() ); //print up to target
ofs << str.substr( i1, len );
}
}
len = str.length() - i1;
if ( len > 0 ) { //print the remainder
print_text( str.substr( i1, len ).c_str() );
ofs << str.substr( i1, len );
}
ofs << endl;
getnstr( s, 1 ); //prompt for
} //while ( !ifs.eof() )
restore_screen(); //restore the old screen
return 1;
}
//text_processing.h
#ifndef TEXT_PROCESSING_H
#define TEXT_PROCESSING_H
#include
#include
using namespace std;
int process_text( fstream &ifs, fstream &ofs, char target[] );
#endif
//util.h
#ifndef UTIL_H
#define UTIL_H
#include
#include
#include
#include
#include
using namespace std;
void usage ( char program_name[] );
void clear_screen();
void print_text( const char *s );
void print_text_inverse( const char *s );
void get_input_text( char *s, int max_len );
void restore_screen();
#endif
//util.cpp
#include \"util.h\"
void usage ( char program_name[] )
{
cout << \"Usage: \" << program_name << \" infile outfile search_string\" << endl;
return;
}
/*
The following are some curses functions. You can find
the details by the command \"man ncurses\". But its use
can be transparent to you.
*/
void clear_screen()
{
initscr();
scrollok ( stdscr, true ); //allow window to scroll
}
void print_text ( const char *s )
{
printw(\"%s\", s );
refresh();
}
void print_text_inverse( const char *s )
{
attron( A_REVERSE );
printw(\"%s\", s );
attroff( A_REVERSE );
refresh();
}
void get_input_text( char *s, int max_len )
{
getnstr( s, max_len );
}
void restore_screen()
{
endwin();
}
//str_main.cpp
#include \"util.h\"
#include \"text_processing.h\"
#include
using namespace std;
/*
Note that grace_open() must be defined in same file
as main(), otherwise the destructor of fstream will
automatically close the opened file as it finds that
its out of scope upon exiting the function.
*/
int grace_open( char *s, fst.
Which of the following is an example of a population, as defined by .pdf
Which of the following is an example of a population, as defined by a biologist?All of the grass
species in Manhattan, Kansas
Solution
Population is defined as group of all members of same species present in an geographical area in
a given time. Among the given options, option D represent a population of coyotes present in
Konza Prairie. Options A, B and C includes all species of grass, snakes and moth+ butterflies in
an area respectively. Since these options incldue more than one species, they are incorrect.
Option D is the correct answer..
Which of the following are characteristics or examples of sponges (.pdf
Which of the following are characteristics or examples of sponges? (Select all that apply.)
Solution
Answer:
Since no options are given, general characteristics of sponges and their examples are mentioned
below:
Characteristics:
Sponges are the common name for the phylum porifera.
1. They are mostly marine and asymmetric animals.
2. They have cellular level of organization.
3. Water enters through minute pores (ostia) in the body wall into a central cavity, spongocoel,
from where it goes out through the osculum.
4. Choanocytes (collar cells) line the spongocoel and the canal.
5. Digestion is intracellular.
6. Spicules or spongin fibres form the skeleton in sponges.
7. They are hermaphrodite, that is the sexes are not separate
8. They reproduce asexually by fragmentation and sexually by formation of gametes.
9. Fertilization is internal
10. Development is indirect with a larval stage distinct from the adults.
Examples: Sycon (Scypha), Spongilla (Fresh water sponge), Euspongia (Bath sponge),
Demonspongiae, Glass sponges, Calcareous aponges..
When does the Signal Transduction step occur during cell communicatio.pdf
When does the Signal Transduction step occur during cell communication (or cell signaling)?
After the cellular response. Before both the receptor is activated and the cellular response
occurs. Before the receptor is activated but after the ligand binds. Signal Transduction is not a
part of cell communication. After receptor activation but before the cellular response. A
chemical reaction that has positive free energy (delta G > 0) is correctly described as
endothermic. exothermic. endergonic. enthalpic. spontaneous
Solution
Q40. E. after receptor activation but before the cellular response .... signalling is always the
intermediate step between cause and effect
Q41.C. Endergonic ... endergoinic reaction require a positive input of energy so deltaG will be
positive.
What is the main difference between a CUT feature and a HOLE feature .pdf
What is the main difference between a CUT feature and a HOLE feature in Autodesk Inventor?
Solution
Answer:-
1. HOLE feature will create only a circular hole in a part whereas CUT can be make any closed
shape that can be either geometric and non-geometric profiles.
2. Even we can make a circular Hole using CUT feature but if use HOLE feature that will give
better control over the part feature.
3. For CUT, Need to make 2D sketch to use this option. For HOLE, 2D sketch is not required,
simply diameter and depth values are enough..
1. Prices are an important tool because theyOffer an information .pdf
1. Prices are an important tool because they:
Offer an information generating, gathering and transmitting process.
Provide information that no single person or entity can know on his/her own.
C.Call up widely dispersed information into one measurable form.
All of the above.
2.All else being equal, as the price of a good rises:
A.Consumers purchase less of that good
B.Consumers purchase more of that good
C.All of the above
3.Government price controls do the following:
A.Cause resources to be allocated to their most efficient use
B.Eliminate the need for competition.
Cause surpluses and shortages
All of the aboveA.
Offer an information generating, gathering and transmitting process.B.
Provide information that no single person or entity can know on his/her own.
C.Call up widely dispersed information into one measurable form.D.
All of the above.
Solution
1A
2B
3A.
What might those purkinje cells have evolved to be very good at, base.pdf
What might those purkinje cells have evolved to be very good at, based on their cellular
structure? What types of cells do they receive input from? How many cells (kinds and numbers
communicate with a purkinje cell?
Solution
Purkinje cells, are inhibitory projection neurons.They have active dendrites, generating electrical
impulses. They have two-dimensional layers through which parallel fibers arise which includes
climbing fibers originating from the inferior olivary nucleus in the medulla. It forms the sole
output of all motor coordination in the cerebellar cortex..
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk from the OECD’s Centre for Educational Research and Innovation presents at the Ask an Expert Webinar: How can education support child empowerment?
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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Explain the internet infrastructure stack. SolutionInternet inf.pdf
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Each hormone is known to have a specific target tissue. For each of t.pdf
Each hormone is known to have a specific target tissue. For each of the following hormones, list
its target tissue and describe its specific action. thyroxine estrogen thyroid stimulating hormone
(TSH) insulin follicle stimulating hormone (FSH) What is the role of the hypothalamus in the
production of thyroxine and TsH? How does thyrotropin releasing hormone (TRH travel from
the hypothalamus to the pituitary gland? It travels through the bleed sream
Solution
2.
Hormone
Specific target tissue
Function
Thyroxine
All through the body especially liver and kidneys
Increases the basal metabolic rate and promotes growth as well as development
Estrogen
Female reproductive system
Helps in sexual growth and development and helps in good functioning of the female
reproductive system
TSH
Thyroid gland
Stimulates the thyroid hormone secretion
Insulin
Throughout the body
Helps in regulating levels of blood glucose levels; facilitates the body cells to intake glucose;
helps in increasing glycogem storage
FSH
Sex gland
Stimulates the maturation of female eggs and also production of sperms
3. when T3 and T4 levels are low in the blood, the hypothalamus senses it and secretes TRH
(thyrotropin releasing hormone) which in turn triggers the pituitary to release TSH (thyroid
stimulating hormone) which stimulates the thyroid gland to release thyroxine.
Hormone
Specific target tissue
Function
Thyroxine
All through the body especially liver and kidneys
Increases the basal metabolic rate and promotes growth as well as development
Estrogen
Female reproductive system
Helps in sexual growth and development and helps in good functioning of the female
reproductive system
TSH
Thyroid gland
Stimulates the thyroid hormone secretion
Insulin
Throughout the body
Helps in regulating levels of blood glucose levels; facilitates the body cells to intake glucose;
helps in increasing glycogem storage
FSH
Sex gland
Stimulates the maturation of female eggs and also production of sperms.
Describe the differences in the appearance of the sterile tube of Try.pdf
Describe the differences in the appearance of the sterile tube of Tryptic soy broth and the one in
which microorganisms are growing. Do the same for the slants.
Solution
Uninoculated or sterile Tryptic soy broth appears light amber and clear with no precipitates. If
microorganisms are growing in the broth, then it appears turbid with visible precipitates or
flocculates. Trypticase soy broth is an enrichment medium. It cannot be used for growing
fastidious organisms.
Sterile slants appear clear without any visible colonies. Whereas if microbes are growing, then
the colonies of the microbes can be seen on the slant..
As we entered the 21st century, the Human Genome Project, a massive .pdf
As we entered the 21st century, the Human Genome Project, a massive collaborative effort by
scientists all over the world, reached the first stage of completion; we now have the complete
sequence of human DNA. What is the value of this information?
Solution
Human Genome Project (HGP) is one of the biggest genome projects completed. In this project,
the whole human genome is sequenced to identify all the genes. From the data interpreted till
now, it was concluded that humans share some set of genes with all other species.
Also, humans contain certain unique set of genes that are necessary for intellectual functioning
and the other unique characteristic of humans. However, sharing the genome with the all other
species indicates that all living organisms arose from a common ancestor.
The major goals of Human Genome Project are,
The data provided by the human genome project directs the scientists to identify the genes
associated with several of the diseases. Identifying the disease-causing genes and their
inheritance would be useful in designing treatment for these diseases..
ActiveX is used by which of the following technologiesA. JavaB..pdf
ActiveX is used by which of the following technologies?
A. Java
B. CORBA
C. EJB
D. DCOM
Solution
D. The Distributed Object Component Model (DCOM) allows applications to be divided into
pieces and objects to be run remotely over the network. Potential vulnerabilities exist because of
the way ActiveX is integrated with DCOM. Answer A is incorrect answer B is incorrect because
CORBA is a set of standards that addresses the need for interoperability between hardware and
software. Answer C is incorrect because Enterprise JavaBeans (EJB) is designed for enterprise
networks.
CBE 20. The following information is from financial statements (in mi.pdf
CBE 20. The following information is from financial statements (in millions of dollars Total
assets 150S Net financial assets 90 financial obligations 15S common equity 75S What was the
value of the operating assets? A. 45 B. 60 C. 75 D. 135 21.At the end of the fiscal year ending
June 30, 2003, Microsot equity of $64.9 billion on its balance sheet, with $4 assets (in the form
of cash equivalents and short term investmentancial debt. For fiscal year 2004, the firm reported
S7.4 billio of which $1.1 billion was after-tax earnings on the financial assets. This month
Microsoft is distributing $34 billion of financial assets to shareholders in the of a special
dividend. 9.0 billion invested in and no financing n in comprehensive income, form a. Calculate
Microsoft\'s return on common equity (ROCE) for 2004. Holding all else constant what would
Microsoft\'s ROCE be S34 billion? after the payout of b.
Solution
PART-1).
Below is a simple Role Play Game (RPG) Simulator program.importjav.pdf
Below is a simple Role Play Game (RPG) Simulator program.
importjava.util.Random;
// Student, Programmer
publicclassRPGSimulator {
publicstaticvoidmain(Stringargs[])throwsInterruptedException
{
Randomrand1=newRandom();
Randomrand2=newRandom();
Stringmission1=\"Capture the Castle\";
Stringmission2=\"Enter the Hidden City\";
Stringmission3=\"Rescue the Princess\";
Stringmission4=\"Traverse the Forest\";
Stringmission5=\"Locate the Tunnel Entrance\";
Stringplayer1=\"\",player2=\"\";
charletter=\'\\0\',role=\'\\0\';
// initial health and treasures for the two players
intnumber= 0,mission= 0,health1= 100,health2= 100;
inttreasure1= 100,treasure2= 100,encounter= 0;
// define your role
role= (char)(rand1.nextInt(26) +\'a\');
if(role>=\'a\'&&role<=\'m\')
{
player1=\"protagonist\";
player2=\"opponent\";
}
else
{
player1=\"opponent\";
player2=\"protagonist\";
}
System.out.println(\"you are the \"+player1);
// define your mission
number=rand2.nextInt(5) + 1;
System.out.print(\"your mission is: \");
switch(number)
{
case1: System.out.println(mission1);mission= 1;break;
case2: System.out.println(mission2);mission= 2;break;
case3: System.out.println(mission3);mission= 3;break;
case4: System.out.println(mission4);mission= 4;break;
case5: System.out.println(mission5);mission= 5;break;
}
System.out.println(\"\");
// let the game simulation commence (limit the # of encounters)
for(encounter= 1;encounter<= 20;encounter++)
{
letter= (char)(rand1.nextInt(3) +\'a\');
number=rand2.nextInt(10) + 1;
// randomly encounter the enemy
if(letter==\'a\'||letter==\'b\')
//if(mission == 1 || mission == 2 || mission == 3)
{
health1-= 10;
health2+= 15;
treasure1+= 10;
treasure2-= 10;
//Thread.sleep(5000);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//encounter++;
}
elseif(letter==\'c\'||letter==\'d\')
{
health1+= 20;
health2-= 30;
treasure1+= 40;
treasure2-= 20;
//Thread.sleep(500);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//break;
}
else
{
health1+= 30;
health2-= 20;
treasure1-= 30;
treasure2+= 20;
//Thread.sleep(500);
System.out.print(\"battle: \"+encounter);
System.out.println(\"\\t\"+\"health\"+\"\\t\"+\"treasure\");
System.out.println(player1+\"\\t\"+health1+\"\\t\"+treasure1);
System.out.println(player2+\"\\t\"+health2+\"\\t\"+treasure2);
System.out.println(\"\");
//break;
}
health1-= 5;
health2-= 5;
treasure1-= 5;
treasure2-= 5;
if(health1<= 0 ||health2<= 0 ||treasure1<= 0 ||treasure2<= 0)
{
//System.out.print(\"encounter: \" + encounter + \" action status: \");
break;
}
}
System.out.println(\"simulation has ended\ \");
System.out.println(\"results:\ \".
A swim bladder allows a fish to Regulate its water content in sea wa.pdf
A swim bladder allows a fish to Regulate its water content in sea water. Regulate its salt
content in sea water. Regulate its salt content in fresh water. Control its buoyancy. Tolerate
changes in water pressure. Monotremes are classified as mammals because they Are carnivores.
Give birth to live young rather than lay eggs. Have mammary glands. Are omnivores. Are
endoderms. In plants which of the following are produced by meiosis? Haploid sporophytes.
Diploid gametes. Haploid gametes. Haploid spores. Diploid spores. Which of the following is
a feature that sets primates apart from all other mammals? Placental embryonic development.
Opposable thumb. Ability to produce milk. Naked faces. Hairy bodies. Fertilization in the
earthworm is accomplished by the use of the Nephridium. Clitellium. Flame cells. Tracheal
system Typhosole. Humans and apes are presently classified in the same category as all of the
following levels except Class. Genus. Kingdo
Solution
question
Answer
explanation
16
d. controls its buoyancy
The swim bladder or air bladder: it is an inner gas-filled organ that adds to the capacity of
numerous hard fish (yet not cartilaginous fish to control their lightness, and in this way to remain
at their ebb and flow water profundity without wasting vitality in swimming.
17
c.have mammary glands
It is an organ situated in the bosoms of females that is in charge of lactation, or the creation of
drain. Both guys and females have glandular tissue inside the bosoms; be that as it may, in
females the glandular tissue starts to create after adolescence in light of estrogen discharge
18
d. haploid spores
Spores are normally haploid and unicellular and are delivered by meiosis in the sporangium of a
diploid sporophyte
19
B, opposable thumb
Primates : they are with completely opposable thumbs incorporate the Great primates (people,
chimpanzees, gorillas, and orangutans) and Old World monkeys
20
B . clitellum
clitellum: it is a thickened glandular and non-portioned area of the body divider close to the head
in worms and bloodsuckers, that secretes a viscid sac in which the eggs are stored. It is available
around 2 cm (0.79 in) behind the foremost end of the body (around the fourteenth, fifteenth and
sixteenth sections)
21
B .genus
question
Answer
explanation
16
d. controls its buoyancy
The swim bladder or air bladder: it is an inner gas-filled organ that adds to the capacity of
numerous hard fish (yet not cartilaginous fish to control their lightness, and in this way to
remain at their ebb and flow water profundity without wasting vitality in swimming.
17
c.have mammary glands
It is an organ situated in the bosoms of females that is in charge of lactation, or the creation of
drain. Both guys and females have glandular tissue inside the bosoms; be that as it may, in
females the glandular tissue starts to create after adolescence in light of estrogen discharge
18
d. haploid spores
Spores are normally haploid and unicellular and are delivered by meios.
12. You want to extract dsDNA from live tissue. Which of the followi.pdf
12. You want to extract dsDNA from live tissue. Which of the following is an option, not a
necessity?
A. SDS
B. RNase A
C. S1 nuclease
D. Exonucleases
Solution
Option B. RNase A. It is used to denature RNA and extract DNA in pure form.
S1 nuclease is used to extract single stranded DNA or RNA.
SDS is absolutely necessary for DNA extraction, so it is not an option but a necessity..
1. Given that mitochondria are the “powerhouse” of the cell, how can.pdf
1. Given that mitochondria are the “powerhouse” of the cell, how can Giardia survive and thrive
with reduced mitochondria? Be specific during the explanation.
2. Explain how the light detector and eyespot aid Euglena in meeting its nutritional
requirements. Be specific.
3. Paramecium has both a macronucleus and a micronucleus. What is the function of each of
these structures? Which one is involved in reproduction? What are the different methods of
reproduction that Paramecium can use?
4. The geometric appearance of diatoms is due to what structural compound? What are some of
the commercial applications for diatoms?
5. Describe how radiolarians use their threadlike pseudopodia to “feed.”
Solution
1.Giardia survives by eating anaerobic bacteria in these rich anoxic environments.They thrive in
anaerobic environments such as marine or freshwater sediments,salt,marshes,rumen,and
intestinal tracts of metazoa;some are parasitic.Giardia makes all of its ATP in the cytosol with
the help of simple anaerobic pathways.Several enzymes of Giardia’s ATP-generating machinery
contain Fe–S clusters,which are ubiquitous cofactors in the electron-transfer reactions involved
in ATP production.They are essential for the parasite’s survival.Eukaryotes that lack
mitochondria oxidize pyruvate with the O2-sensitive enzyme pyruvate:ferredoxin oxidoreductase
(PFO).Like PDH,PFO yields CO2 and acetyl-CoA,but the electrons that are removed from
pyruvate are not transferred to NAD+ as in the PDH reaction,but rather to ferredoxin.The
resulting acetyl-CoA is further converted into a mixture of ethanol and acetate.
2.Euglena have an eyespot at the anterior end that detects light which helps the euglena find
bright areas to gather sunlight to make their food.The euglena\'s eyespot is not an eye,but it can
react to changes in the brightness of a light source.The eyespot is important because it helps the
euglena move toward light,the source of energy for photosynthesis.The intensity of visible light
determines the area towards which Euglenas swim,which always is towards the source of
light,i.e.towards the place where the light is more intense.Euglena can also gain nutrients by
absorbing them across their cell membrane,hence they become heterotrophic when light is not
available,and they cannot photosynthesize.
3..
Write a C++ program 1. Study the function process_text() in file.pdf
Write a C++ program
1. Study the function process_text() in file \"text_processing.cpp\". What do the string member
functions find(), substr(), c_str() do?
//text_processing.cpp
#include \"util.h\"
#include \"text_processing.h\"
#include
using namespace std;
int process_text( fstream &ifs, fstream &ofs, char target[] )
{
string replace_str( \"XXX\" ); //hard-coded string for replacement
int tlen = strlen( target ); //string length of target
int max_len = 200; //maximum length of a line
char s[max_len+1];
clear_screen(); //clear the screen
while ( !ifs.eof() ) {
int i2, i1 = 0, len=0;
ifs.getline( s, max_len ); //get one line from file
string str( s ); //construct a string object
i2 = str.find ( target, i1 ); //find target
len = i2 - i1;
if ( i2 > -1 && len > 0 ){ //if target found
print_text( str.substr( i1, i2 ).c_str() ); //print up to target
ofs << str.substr( i1, i2 );
}
while ( i2 > -1 ) {
print_text_inverse ( target ); //highlight target
ofs << replace_str;
i1 = i2 + tlen; //new search position
i2 = str.find ( target, i1 ); //find next target
len = i2 - i1;
if ( i2 > -1 && len > 0 ){ //found target
print_text( str.substr( i1, len ).c_str() ); //print up to target
ofs << str.substr( i1, len );
}
}
len = str.length() - i1;
if ( len > 0 ) { //print the remainder
print_text( str.substr( i1, len ).c_str() );
ofs << str.substr( i1, len );
}
ofs << endl;
getnstr( s, 1 ); //prompt for
} //while ( !ifs.eof() )
restore_screen(); //restore the old screen
return 1;
}
//text_processing.h
#ifndef TEXT_PROCESSING_H
#define TEXT_PROCESSING_H
#include
#include
using namespace std;
int process_text( fstream &ifs, fstream &ofs, char target[] );
#endif
//util.h
#ifndef UTIL_H
#define UTIL_H
#include
#include
#include
#include
#include
using namespace std;
void usage ( char program_name[] );
void clear_screen();
void print_text( const char *s );
void print_text_inverse( const char *s );
void get_input_text( char *s, int max_len );
void restore_screen();
#endif
//util.cpp
#include \"util.h\"
void usage ( char program_name[] )
{
cout << \"Usage: \" << program_name << \" infile outfile search_string\" << endl;
return;
}
/*
The following are some curses functions. You can find
the details by the command \"man ncurses\". But its use
can be transparent to you.
*/
void clear_screen()
{
initscr();
scrollok ( stdscr, true ); //allow window to scroll
}
void print_text ( const char *s )
{
printw(\"%s\", s );
refresh();
}
void print_text_inverse( const char *s )
{
attron( A_REVERSE );
printw(\"%s\", s );
attroff( A_REVERSE );
refresh();
}
void get_input_text( char *s, int max_len )
{
getnstr( s, max_len );
}
void restore_screen()
{
endwin();
}
//str_main.cpp
#include \"util.h\"
#include \"text_processing.h\"
#include
using namespace std;
/*
Note that grace_open() must be defined in same file
as main(), otherwise the destructor of fstream will
automatically close the opened file as it finds that
its out of scope upon exiting the function.
*/
int grace_open( char *s, fst.
Which of the following is an example of a population, as defined by .pdf
Which of the following is an example of a population, as defined by a biologist?All of the grass
species in Manhattan, Kansas
Solution
Population is defined as group of all members of same species present in an geographical area in
a given time. Among the given options, option D represent a population of coyotes present in
Konza Prairie. Options A, B and C includes all species of grass, snakes and moth+ butterflies in
an area respectively. Since these options incldue more than one species, they are incorrect.
Option D is the correct answer..
Which of the following are characteristics or examples of sponges (.pdf
Which of the following are characteristics or examples of sponges? (Select all that apply.)
Solution
Answer:
Since no options are given, general characteristics of sponges and their examples are mentioned
below:
Characteristics:
Sponges are the common name for the phylum porifera.
1. They are mostly marine and asymmetric animals.
2. They have cellular level of organization.
3. Water enters through minute pores (ostia) in the body wall into a central cavity, spongocoel,
from where it goes out through the osculum.
4. Choanocytes (collar cells) line the spongocoel and the canal.
5. Digestion is intracellular.
6. Spicules or spongin fibres form the skeleton in sponges.
7. They are hermaphrodite, that is the sexes are not separate
8. They reproduce asexually by fragmentation and sexually by formation of gametes.
9. Fertilization is internal
10. Development is indirect with a larval stage distinct from the adults.
Examples: Sycon (Scypha), Spongilla (Fresh water sponge), Euspongia (Bath sponge),
Demonspongiae, Glass sponges, Calcareous aponges..
When does the Signal Transduction step occur during cell communicatio.pdf
When does the Signal Transduction step occur during cell communication (or cell signaling)?
After the cellular response. Before both the receptor is activated and the cellular response
occurs. Before the receptor is activated but after the ligand binds. Signal Transduction is not a
part of cell communication. After receptor activation but before the cellular response. A
chemical reaction that has positive free energy (delta G > 0) is correctly described as
endothermic. exothermic. endergonic. enthalpic. spontaneous
Solution
Q40. E. after receptor activation but before the cellular response .... signalling is always the
intermediate step between cause and effect
Q41.C. Endergonic ... endergoinic reaction require a positive input of energy so deltaG will be
positive.
What is the main difference between a CUT feature and a HOLE feature .pdf
What is the main difference between a CUT feature and a HOLE feature in Autodesk Inventor?
Solution
Answer:-
1. HOLE feature will create only a circular hole in a part whereas CUT can be make any closed
shape that can be either geometric and non-geometric profiles.
2. Even we can make a circular Hole using CUT feature but if use HOLE feature that will give
better control over the part feature.
3. For CUT, Need to make 2D sketch to use this option. For HOLE, 2D sketch is not required,
simply diameter and depth values are enough..
1. Prices are an important tool because theyOffer an information .pdf
1. Prices are an important tool because they:
Offer an information generating, gathering and transmitting process.
Provide information that no single person or entity can know on his/her own.
C.Call up widely dispersed information into one measurable form.
All of the above.
2.All else being equal, as the price of a good rises:
A.Consumers purchase less of that good
B.Consumers purchase more of that good
C.All of the above
3.Government price controls do the following:
A.Cause resources to be allocated to their most efficient use
B.Eliminate the need for competition.
Cause surpluses and shortages
All of the aboveA.
Offer an information generating, gathering and transmitting process.B.
Provide information that no single person or entity can know on his/her own.
C.Call up widely dispersed information into one measurable form.D.
All of the above.
Solution
1A
2B
3A.
What might those purkinje cells have evolved to be very good at, base.pdf
What might those purkinje cells have evolved to be very good at, based on their cellular
structure? What types of cells do they receive input from? How many cells (kinds and numbers
communicate with a purkinje cell?
Solution
Purkinje cells, are inhibitory projection neurons.They have active dendrites, generating electrical
impulses. They have two-dimensional layers through which parallel fibers arise which includes
climbing fibers originating from the inferior olivary nucleus in the medulla. It forms the sole
output of all motor coordination in the cerebellar cortex..
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Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
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