Option #1- Creating a GUI Bank Balance Application Create a simple Gr.docx
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Option #1: Creating a GUI Bank Balance Application Create a simple Graphical User Interface (GUI) Bank Balance application. The application must obtain the BankAccount balance from a user, and then display that balance within a JPanel when the user selects a button. The program should allow for the user to deposit and withdraw funds from their account using a simple interface. The remaining balance in the account should be displayed before exiting the program. Ensure that your application includes the following components: JPanel JButton ActionListener Submit screenshots of your program's execution and output. Include all appropriate source code in a zip file. .
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package edu-ser222-m03_02- --- - A binary search tree based impleme.docx
package edu.ser222.m03_02;
/**
* A binary search tree based implementation of a symbol table.
*
* Completion time: (your completion time)
*
* @author (your name), Sedgewick, Acuna
* @version (version)
*/
import java.util.Collections;
import java.util.LinkedList;
import java.util.NoSuchElementException;
import java.util.Queue;
public class CompletedBST<Key extends Comparable<Key>, Value> implements BST<Key, Value> {
private Node<Key, Value> root;
@Override
public int size() {
return size(root);
}
private int size(Node x) {
if (x == null)
return 0;
else
return x.N;
}
@Override
public Value get(Key key) {
Node<Key, Value> iter = root;
while(iter != null) {
int cmp = key.compareTo(iter.key);
if (cmp < 0)
iter = iter.left;
else if (cmp > 0)
iter = iter.right;
else
return iter.val;
}
return null;
}
private Value get(Node<Key, Value> x, Key key) {
// Return value associated with key in the subtree rooted at x;
// return null if key not present in subtree rooted at x.
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
@Override
public void put(Key key, Value val) {
root = put(root, key, val);
}
private Node put(Node<Key, Value> x, Key key, Value val) {
if (x == null)
return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0)
x.left = put(x.left, key, val);
else if (cmp > 0)
x.right = put(x.right, key, val);
else
x.val = val;
x.N = size(x.left) + size(x.right) + 1;
return x;
}
@Override
public Key min() {
if(root == null)
throw new NoSuchElementException();
return min(root).key;
}
private Node<Key, Value> min(Node x) {
if (x.left == null)
return x;
return min(x.left);
}
@Override
public Key max() {
if(root == null)
throw new NoSuchElementException();
return max(root).key;
}
private Node<Key, Value> max(Node x) {
if (x.right == null) return x;
return max(x.right);
}
@Override
public Key floor(Key key) {
if(root == null)
throw new NoSuchElementException();
Node<Key, Value> x = floor(root, key);
if (x == null)
return null;
return x.key;
}
private Node<Key, Value> floor(Node<Key, Value> x, Key key) {
if (x == null)
return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) return floor(x.left, key);
Node<Key, Value> t = floor(x.right, key);
if (t != null) return t;
else return x;
}
@Override
public Key select(int k) {
return select(root, k).key;
}
private Node<Key, Value> select(Node x, int k) {
if (x == null) return null;
int t = size(x.left);
if (t > k) return select(x.left, k);
else if (t < k) return select(x.right, k-t-1);
else return x;
}
@Override
public int rank(Key key) {
return rank(key, root);
}
private int rank(Key key, Node<Key, Value> x) {
// Return number of keys less than x.key in the subtree rooted at x.
if (x == null) return 0;
int cmp = key.compareTo(x.key);
if (cmp < 0) return rank(key, x.left);
else if (cmp > 0) return 1 + size(x.left) + rank(key, x.right);
else return size(x.left);
}
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.
package edu-ser222-m03_02- --- - A binary search tree based impleme.docx
package edu.ser222.m03_02;
/**
* A binary search tree based implementation of a symbol table.
*
* Completion time: (your completion time)
*
* @author (your name), Sedgewick, Acuna
* @version (version)
*/
import java.util.Collections;
import java.util.LinkedList;
import java.util.NoSuchElementException;
import java.util.Queue;
public class CompletedBST<Key extends Comparable<Key>, Value> implements BST<Key, Value> {
private Node<Key, Value> root;
@Override
public int size() {
return size(root);
}
private int size(Node x) {
if (x == null)
return 0;
else
return x.N;
}
@Override
public Value get(Key key) {
Node<Key, Value> iter = root;
while(iter != null) {
int cmp = key.compareTo(iter.key);
if (cmp < 0)
iter = iter.left;
else if (cmp > 0)
iter = iter.right;
else
return iter.val;
}
return null;
}
private Value get(Node<Key, Value> x, Key key) {
// Return value associated with key in the subtree rooted at x;
// return null if key not present in subtree rooted at x.
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
@Override
public void put(Key key, Value val) {
root = put(root, key, val);
}
private Node put(Node<Key, Value> x, Key key, Value val) {
if (x == null)
return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0)
x.left = put(x.left, key, val);
else if (cmp > 0)
x.right = put(x.right, key, val);
else
x.val = val;
x.N = size(x.left) + size(x.right) + 1;
return x;
}
@Override
public Key min() {
if(root == null)
throw new NoSuchElementException();
return min(root).key;
}
private Node<Key, Value> min(Node x) {
if (x.left == null)
return x;
return min(x.left);
}
@Override
public Key max() {
if(root == null)
throw new NoSuchElementException();
return max(root).key;
}
private Node<Key, Value> max(Node x) {
if (x.right == null) return x;
return max(x.right);
}
@Override
public Key floor(Key key) {
if(root == null)
throw new NoSuchElementException();
Node<Key, Value> x = floor(root, key);
if (x == null)
return null;
return x.key;
}
private Node<Key, Value> floor(Node<Key, Value> x, Key key) {
if (x == null)
return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) return floor(x.left, key);
Node<Key, Value> t = floor(x.right, key);
if (t != null) return t;
else return x;
}
@Override
public Key select(int k) {
return select(root, k).key;
}
private Node<Key, Value> select(Node x, int k) {
if (x == null) return null;
int t = size(x.left);
if (t > k) return select(x.left, k);
else if (t < k) return select(x.right, k-t-1);
else return x;
}
@Override
public int rank(Key key) {
return rank(key, root);
}
private int rank(Key key, Node<Key, Value> x) {
// Return number of keys less than x.key in the subtree rooted at x.
if (x == null) return 0;
int cmp = key.compareTo(x.key);
if (cmp < 0) return rank(key, x.left);
else if (cmp > 0) return 1 + size(x.left) + rank(key, x.right);
else return size(x.left);
}
@O.
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ook at the mean- median- mode- and standard deviation and describe how.docx
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Median 20
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Standard Deviation 4.30
Kurtosis 0.03
Skewness -0.46
Minimum 11
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a. First, generate an increasing number (N) of random integers (1000, 5000, 10000,
50000, 75000, 100000, 500000 or as far as your computing power will let you)
i. Time and print how long it takes to insert the random integers into an initially
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You can get a random list using the java class Random, located in
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current time (in milliseconds). Call System.currentTimeMillis() before and after
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way of recording the time.)
ii. Time and print how long it takes to insert the same random integers into an
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iii. If T(N) is the time function, how does the growth of TBST(N) compare with the
growth of TAVL(N)?
Plot a simple graph to of time against N for the two types of BSTs to visualize
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iii. Compare the growth rates of these two search time-functions with a graph the
same way you did in part a.
public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
/**
* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
* @return
*/
private int countLeafNodes(BinaryNode<AnyType> root) {
// If the root is null, it means the tree is empty, so we return 0
if (root == null) {
return 0;
}
// If the root has no children, it means it is a leaf node, so we return 1
if (root.left == .
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On its December 31-2020 balance sheet- Blossom Company appropriately r.docx
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Kurtosis 0.03
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Minimum 11
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public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
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* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
* @return
*/
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if (root == null) {
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• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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