ook at the mean- median- mode- and standard deviation and describe how.docx
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ook at the mean, median, mode, and standard deviation and describe how these measures of central tendency indicates whether the distribution of women are normal or skewed. How does the mean, median, and mode scores indicate if the distribution is normal or skewed? Mean 19.93 Median 20 Mode 19 Standard Deviation 4.30 Kurtosis 0.03 Skewness -0.46 Minimum 11 Maximum 27 .
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PARTICIPANTS PROFILE ANSWER ABOVE MENTIONED QUESTIONS BY TAKING CARE.docx
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ANSWER ABOVE MENTIONED QUESTIONS BY TAKING CAREGIVERS OF ADULTS IN LONG TERM FACILITY AS AUDIENCE
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Part3- Offline traffic monitoring In this part will use a PCAP file to.docx
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Provide a thoughtful and meaningful approach to posts and ensure quality contributions:
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Partners Johnny and Daniel each have capital balances of $95-000- Migu.docx
Partners Johnny and Daniel each have capital balances of $95 , 000 . Miguel invests $110 , 000 for a 1/3 interest in the partnership. How much of Miguel's investment is credited to his capital account? $300 , 000 $100 , 000 $95 , 000 $110 , 000 Millie and David have capital accounts totalling $100 , 000 and $150 , 000 respectively in a partnership at the beginning of the year. Regarding the division of net income (losses), the partnership agreement states that each partner earns 10% interest on their capital account balance and gives salary allowances of $25 , 000 to Millie and $10 , 000 to David, with the remaining income (loss) being shared equally. How much of a net income of $80 , 000 will be allocated to Millie? $45 , 000 $40 , 000 $25 , 000 $35 , 000 Elliot makes $10 per hour. He worked 42 hours last week. According to FLSA, how much should his gross pay be? $420 $630 $400 $430
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package edu-ser222-m03_02- --- - A binary search tree based impleme.docx
package edu.ser222.m03_02;
/**
* A binary search tree based implementation of a symbol table.
*
* Completion time: (your completion time)
*
* @author (your name), Sedgewick, Acuna
* @version (version)
*/
import java.util.Collections;
import java.util.LinkedList;
import java.util.NoSuchElementException;
import java.util.Queue;
public class CompletedBST<Key extends Comparable<Key>, Value> implements BST<Key, Value> {
private Node<Key, Value> root;
@Override
public int size() {
return size(root);
}
private int size(Node x) {
if (x == null)
return 0;
else
return x.N;
}
@Override
public Value get(Key key) {
Node<Key, Value> iter = root;
while(iter != null) {
int cmp = key.compareTo(iter.key);
if (cmp < 0)
iter = iter.left;
else if (cmp > 0)
iter = iter.right;
else
return iter.val;
}
return null;
}
private Value get(Node<Key, Value> x, Key key) {
// Return value associated with key in the subtree rooted at x;
// return null if key not present in subtree rooted at x.
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
@Override
public void put(Key key, Value val) {
root = put(root, key, val);
}
private Node put(Node<Key, Value> x, Key key, Value val) {
if (x == null)
return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0)
x.left = put(x.left, key, val);
else if (cmp > 0)
x.right = put(x.right, key, val);
else
x.val = val;
x.N = size(x.left) + size(x.right) + 1;
return x;
}
@Override
public Key min() {
if(root == null)
throw new NoSuchElementException();
return min(root).key;
}
private Node<Key, Value> min(Node x) {
if (x.left == null)
return x;
return min(x.left);
}
@Override
public Key max() {
if(root == null)
throw new NoSuchElementException();
return max(root).key;
}
private Node<Key, Value> max(Node x) {
if (x.right == null) return x;
return max(x.right);
}
@Override
public Key floor(Key key) {
if(root == null)
throw new NoSuchElementException();
Node<Key, Value> x = floor(root, key);
if (x == null)
return null;
return x.key;
}
private Node<Key, Value> floor(Node<Key, Value> x, Key key) {
if (x == null)
return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) return floor(x.left, key);
Node<Key, Value> t = floor(x.right, key);
if (t != null) return t;
else return x;
}
@Override
public Key select(int k) {
return select(root, k).key;
}
private Node<Key, Value> select(Node x, int k) {
if (x == null) return null;
int t = size(x.left);
if (t > k) return select(x.left, k);
else if (t < k) return select(x.right, k-t-1);
else return x;
}
@Override
public int rank(Key key) {
return rank(key, root);
}
private int rank(Key key, Node<Key, Value> x) {
// Return number of keys less than x.key in the subtree rooted at x.
if (x == null) return 0;
int cmp = key.compareTo(x.key);
if (cmp < 0) return rank(key, x.left);
else if (cmp > 0) return 1 + size(x.left) + rank(key, x.right);
else return size(x.left);
}
@O.
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.
package edu-ser222-m03_02- --- - A binary search tree based impleme.docx
package edu.ser222.m03_02;
/**
* A binary search tree based implementation of a symbol table.
*
* Completion time: (your completion time)
*
* @author (your name), Sedgewick, Acuna
* @version (version)
*/
import java.util.Collections;
import java.util.LinkedList;
import java.util.NoSuchElementException;
import java.util.Queue;
public class CompletedBST<Key extends Comparable<Key>, Value> implements BST<Key, Value> {
private Node<Key, Value> root;
@Override
public int size() {
return size(root);
}
private int size(Node x) {
if (x == null)
return 0;
else
return x.N;
}
@Override
public Value get(Key key) {
Node<Key, Value> iter = root;
while(iter != null) {
int cmp = key.compareTo(iter.key);
if (cmp < 0)
iter = iter.left;
else if (cmp > 0)
iter = iter.right;
else
return iter.val;
}
return null;
}
private Value get(Node<Key, Value> x, Key key) {
// Return value associated with key in the subtree rooted at x;
// return null if key not present in subtree rooted at x.
if (x == null) return null;
int cmp = key.compareTo(x.key);
if (cmp < 0) return get(x.left, key);
else if (cmp > 0) return get(x.right, key);
else return x.val;
}
@Override
public void put(Key key, Value val) {
root = put(root, key, val);
}
private Node put(Node<Key, Value> x, Key key, Value val) {
if (x == null)
return new Node(key, val, 1);
int cmp = key.compareTo(x.key);
if (cmp < 0)
x.left = put(x.left, key, val);
else if (cmp > 0)
x.right = put(x.right, key, val);
else
x.val = val;
x.N = size(x.left) + size(x.right) + 1;
return x;
}
@Override
public Key min() {
if(root == null)
throw new NoSuchElementException();
return min(root).key;
}
private Node<Key, Value> min(Node x) {
if (x.left == null)
return x;
return min(x.left);
}
@Override
public Key max() {
if(root == null)
throw new NoSuchElementException();
return max(root).key;
}
private Node<Key, Value> max(Node x) {
if (x.right == null) return x;
return max(x.right);
}
@Override
public Key floor(Key key) {
if(root == null)
throw new NoSuchElementException();
Node<Key, Value> x = floor(root, key);
if (x == null)
return null;
return x.key;
}
private Node<Key, Value> floor(Node<Key, Value> x, Key key) {
if (x == null)
return null;
int cmp = key.compareTo(x.key);
if (cmp == 0) return x;
if (cmp < 0) return floor(x.left, key);
Node<Key, Value> t = floor(x.right, key);
if (t != null) return t;
else return x;
}
@Override
public Key select(int k) {
return select(root, k).key;
}
private Node<Key, Value> select(Node x, int k) {
if (x == null) return null;
int t = size(x.left);
if (t > k) return select(x.left, k);
else if (t < k) return select(x.right, k-t-1);
else return x;
}
@Override
public int rank(Key key) {
return rank(key, root);
}
private int rank(Key key, Node<Key, Value> x) {
// Return number of keys less than x.key in the subtree rooted at x.
if (x == null) return 0;
int cmp = key.compareTo(x.key);
if (cmp < 0) return rank(key, x.left);
else if (cmp > 0) return 1 + size(x.left) + rank(key, x.right);
else return size(x.left);
}
@O.
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Over 1 million Americans make a living working for advertising and pub.docx
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JButton
ActionListener
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Once you have all the structures working as intended- it is time to co.docx
Once you have all the structures working as intended, it is time to compare the
performances of the 2. Use runBenchmark() to start.
a. First, generate an increasing number (N) of random integers (1000, 5000, 10000,
50000, 75000, 100000, 500000 or as far as your computing power will let you)
i. Time and print how long it takes to insert the random integers into an initially
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You can get a random list using the java class Random, located in
java.util.Random. To test the speed of the insertion algorithm, you should use
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the algorithm runs and subtract the two times. (Instant.now() is an alternative
way of recording the time.)
ii. Time and print how long it takes to insert the same random integers into an
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iii. If T(N) is the time function, how does the growth of TBST(N) compare with the
growth of TAVL(N)?
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b. Second, generate a list of k random integers. k is also some large value.
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integers. It does not matter whether the search succeeds.
ii. Time how long it takes to search your N-node AVL trees for the same k random
integers.
iii. Compare the growth rates of these two search time-functions with a graph the
same way you did in part a.
public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
/**
* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
* @return
*/
private int countLeafNodes(BinaryNode<AnyType> root) {
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public class BinarySearchTree<AnyType extends Comparable<? super AnyType>> {
protected BinaryNode<AnyType> root;
public BinarySearchTree() {
root = null;
}
/**
* Insert into the tree; duplicates are ignored.
*
* @param x the item to insert.
* @param root
* @return
*/
protected BinaryNode<AnyType> insert(AnyType x, BinaryNode<AnyType> root) {
// If the root is null, we've reached an empty leaf node, so we create a new node
// with the value x and return it
if (root == null) {
return new BinaryNode<>(x, null, null);
}
// Compare the value of x to the value stored in the root node
int compareResult = x.compareTo(root.element);
// If x is less than the value stored in the root node, we insert it into the left subtree
if (compareResult < 0) {
root.left = insert(x, root.left);
}
// If x is greater than the value stored in the root node, we insert it into the right subtree
else if (compareResult > 0) {
root.right = insert(x, root.right);
}
// If x is equal to the value stored in the root node, we ignore it since the tree does not allow duplicates
return root;
}
/**
* Counts the number of leaf nodes in this tree.
*
* @param t The root of the tree.
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Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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