Network Solving

Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω

Redraw circuit , replace 2 parrellel resistors with one: Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 1/Rt = 2/15 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω

Redraw circuit , replace 2 parrellel resistors with one: 1/Rt = 1/R2 + 1/R3 1/Rt = 1/12 + 1/20 1/Rt = 2/15 Rt = 7.5 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5 Ω

Replace 2 resistors in series, for one: 10 Ω + 7.5Ω = 17.5 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

R total = 17.5Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω I total = 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 80V R1 10 Ω 7.5Ω 80V 17.5Ω

R total = 17.5Ω I total = Vt/ Rt = 80V/ 17.5Ω I total = 4.57A DRAW THIS ON YOUR CIRCUITS Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 80V R1 10 Ω 7.5Ω 4.57A 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 80V 17.5Ω 4.57A

Work out Voltdrops: VR1 = R1x I VR1 = 10 Ω x 4.57A VR1 = 45.7 V DRAW RESULT ON THE CIRCUIT V 7.5Ω = 7.5Ωx 4.57A = 34.275V DRAW RESULT ON THE CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A DRAW RESULTS ON CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

WORK OUT BRANCH CURRENTS IR2 = VR2/ R2 = 34.275V/12 Ω = 2.85A IR3 = VR3/ R3 = 34.275V/20 Ω = 1.71A DRAW RESULTS ON CIRCUIT Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A 80V R1 10 Ω 7.5Ω 4.57A 45.7 V 34.275V 80V 17.5Ω 4.57A

Now that you have all the branch currents you can work out anything required: Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W PR3 = I x V Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Now that you have all the branch currents you can work out anything required: Power: PR1 = I x V = 4.57A x 45.7 V = 208.85W PR2 = I x V = 2.85A x 34.275V = 97.68W PR3 = I x V = 1.71A x 34.275V = 58.61W Solve the Network: 80V R1 10 Ω R2 12 Ω R3 20 Ω 4.57A 45.7 V 34.275V 1.71A 2.85A

Network Solving

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