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The experiment of the series
resonant circuit
s1210196 Yoichi Saito
Abstract
Based on the basic knowledge, I’ll
understand the series resonant
circuit with an inductor, a capacitor
and a resister, and learn it by
experimenting.
What is resonance?
Resonance is to transmit energy among
three elements: inductor, capacitor,
resister.
Circuit diagram
Explanation of the words
• OSC: The device that receives the
electrical signals from the circuit.
• FG: The device that outputs the
electrical signals into the circuit.
• V0: The whole voltage in the circuit.
• VR: The voltage of the resistance.
The rate of the expanding the voltage
• This parameter is expressed as Q.
• The value of Q can be calculated by the
formula as follows:
• Q = f0/(2Δf)
• f0 is the frequency.
• Δf is the amount of change of the
frequency.
The measurement of the series
resonant circuit:
what should I measure?
Purpose
Measurement
1. Make sure the value of L and C.
2. Calculate the resonance frequency.
3. Use two resistances that the value of Q
is 10 and 100.
4. Calculate the values of 2Δf and Q by
using the L, C and R.
Next>>
Measurement
5. Using the FG and OSC, make the table
and calculate the value of 2Δf and Q.
Theoretical values(Q = 100)
• R = 10Ω
• C = 10000pF
• L = 10mH
• f0 = 1/2π√LC = 16kHz
• 2Δf = 0.08kHz
Theoretical values(Q = 10)
• R = 100Ω
• C = 10000pF
• L = 10mH
• f0 = 1/2π√LC = 16kHz
• 2Δf = 0.8kHz
Result Q = 100
f0 Voltage1 Voltage2 phase V1*5/V2 normalized value
15.7 2.44 0.6 0° 1.23 1
16 3.08 0.54 45°delay 0.88 0.72
16.5 4.12 0.4 65°delay 0.49 0.4
17 4.64 0.3 70°delay 0.32 0.26
17.5 4.84 0.25 78°delay 0.29 0.24
18 5 0.2 78°delay 0.2 0.16
15.5 2.64 0.56 26°lead 1.06 0.86
15 4.04 0.42 66°lead 0.52 0.42
14.5 4.64 0.3 79°lead 0.32 0.26
14 4.92 0.24 87°lead 0.24 0.2
Result Q = 10
f0 Voltage1 Voltage2 phase V1*5/V2 normalized value
15.7 3.92 2.96 0° 3.78 1
16 4 2.96 15°delay 3.7 0.98
16.5 4.24 2.64 34°delay 3.11 0.82
17 4.56 2.32 45°delay 2.54 0.67
17.5 4.8 2 50°delay 2.88 0.55
18 4.88 1.76 60°delay 1.8 0.48
15.5 3.92 2.96 14°lead 3.78 1
15 4.16 2.84 40°lead 3.17 0.84
14.5 4.64 2.24 55°lead 2.41 0.64
14 4.88 1.84 65°lead 1.89 0.5
Result
• Q = 100 (Theoretical value)
・ Q = 26.2 (Measured value)
・2Δf = 0.6kHz (Measured value)
• Q = 10 (Theoretical value)
・ Q = 7.9 (Measured value)
・2Δf = 2kHz (Measured value)
Consideration and Conclusion
• There is a difference between the theoretical
value and measured value of f0 and Q because
the parameter of L and C has an error(About
f0, slide 11 & 12).
• The value of Q and is calculated by the
formula as follows:
Q = √LC/CR
Next>>
Consideration and Conclusion
In fact, an inductor has resistance(r).
Therefore, exact formula is as follows:
Q = L/(R + r)√LC
It is clear that the theoretical value and
the measured value about f0 and Q.

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The experiment of the series resonant circuit

  • 1. The experiment of the series resonant circuit s1210196 Yoichi Saito
  • 2. Abstract Based on the basic knowledge, I’ll understand the series resonant circuit with an inductor, a capacitor and a resister, and learn it by experimenting.
  • 3. What is resonance? Resonance is to transmit energy among three elements: inductor, capacitor, resister.
  • 5. Explanation of the words • OSC: The device that receives the electrical signals from the circuit. • FG: The device that outputs the electrical signals into the circuit. • V0: The whole voltage in the circuit. • VR: The voltage of the resistance.
  • 6. The rate of the expanding the voltage • This parameter is expressed as Q. • The value of Q can be calculated by the formula as follows: • Q = f0/(2Δf) • f0 is the frequency. • Δf is the amount of change of the frequency.
  • 7. The measurement of the series resonant circuit: what should I measure? Purpose
  • 8. Measurement 1. Make sure the value of L and C. 2. Calculate the resonance frequency. 3. Use two resistances that the value of Q is 10 and 100. 4. Calculate the values of 2Δf and Q by using the L, C and R. Next>>
  • 9. Measurement 5. Using the FG and OSC, make the table and calculate the value of 2Δf and Q.
  • 10. Theoretical values(Q = 100) • R = 10Ω • C = 10000pF • L = 10mH • f0 = 1/2π√LC = 16kHz • 2Δf = 0.08kHz
  • 11. Theoretical values(Q = 10) • R = 100Ω • C = 10000pF • L = 10mH • f0 = 1/2π√LC = 16kHz • 2Δf = 0.8kHz
  • 12. Result Q = 100 f0 Voltage1 Voltage2 phase V1*5/V2 normalized value 15.7 2.44 0.6 0° 1.23 1 16 3.08 0.54 45°delay 0.88 0.72 16.5 4.12 0.4 65°delay 0.49 0.4 17 4.64 0.3 70°delay 0.32 0.26 17.5 4.84 0.25 78°delay 0.29 0.24 18 5 0.2 78°delay 0.2 0.16 15.5 2.64 0.56 26°lead 1.06 0.86 15 4.04 0.42 66°lead 0.52 0.42 14.5 4.64 0.3 79°lead 0.32 0.26 14 4.92 0.24 87°lead 0.24 0.2
  • 13. Result Q = 10 f0 Voltage1 Voltage2 phase V1*5/V2 normalized value 15.7 3.92 2.96 0° 3.78 1 16 4 2.96 15°delay 3.7 0.98 16.5 4.24 2.64 34°delay 3.11 0.82 17 4.56 2.32 45°delay 2.54 0.67 17.5 4.8 2 50°delay 2.88 0.55 18 4.88 1.76 60°delay 1.8 0.48 15.5 3.92 2.96 14°lead 3.78 1 15 4.16 2.84 40°lead 3.17 0.84 14.5 4.64 2.24 55°lead 2.41 0.64 14 4.88 1.84 65°lead 1.89 0.5
  • 14. Result • Q = 100 (Theoretical value) ・ Q = 26.2 (Measured value) ・2Δf = 0.6kHz (Measured value) • Q = 10 (Theoretical value) ・ Q = 7.9 (Measured value) ・2Δf = 2kHz (Measured value)
  • 15. Consideration and Conclusion • There is a difference between the theoretical value and measured value of f0 and Q because the parameter of L and C has an error(About f0, slide 11 & 12). • The value of Q and is calculated by the formula as follows: Q = √LC/CR Next>>
  • 16. Consideration and Conclusion In fact, an inductor has resistance(r). Therefore, exact formula is as follows: Q = L/(R + r)√LC It is clear that the theoretical value and the measured value about f0 and Q.