INVESTIGACIÓN OPERATIVA I DR. MARLON VILLA
1
UNIVERSIDAD NACIONAL DE CHIMBORAZO
FACULTAD DE CIENCIAS POLÍTICAS Y ADMINISTRATIVAS
CARRERA DE CONTABILIDAD Y AUDITORÍA CPA
INVESTIGACIÓN OPERATIVA I
Dr. Marlón Villa
Deber 08
Nombre: Diana Curicama
Curso: 5to Semestre
Paralelo: “A”
Fecha: 2 de junio 2015
-Tema: Desarrollar 3 ejercicios de Sistema 4x4 por el método de Gauss-Jordán
MÉTODO DE GAUSS-JORDÁN
EJERCICIO 1
5A - 4B + 6C - 2D =-37
-2A + 3B - 4C + 5D= 26
6A - 2B + 3C - 4D = -32
-A + 5B - 8C - 2D = 26
5 - 4 + 6 – 2 = -37
-2 + 3 – 4 + 5= 26
6 – 2 +3 - 4 = -32
-1 +5 – 8 – 2 = 26
2 -8/5 12/5 -4/5 =-74/5
-2 3 -4 5 = 26
0 -14/5 +16/5 -42/5 – 112/5
0 +14/5 -51/5 -8/5 +62/5
-1 +5 -8 -2 = 26
1 -4/5 6/5 -2/5 = -37/5
-6 + 24/5 - 36/5 + 12/5 = 222/5
6 - 2 +3 -4 = -32
INVESTIGACIÓN OPERATIVA I
DIANA CURICAMA, QUINTO SEMESTRE “A”
2
COMPROBACIÓN
5A-4B+6C-2D=-37
5(-3)-4(5)+6(0)-2(1)
=-37
A= -3
B= 5
C= 0
D= 1
1 – 4/5 + 6/5 – 2/5 = -37/5
0 + 7/5 - 8/5 + 21/5= 56/5
0 + 14/5 – 51/5 – 8/5= 62/5
0 + 21/5 – 34/5 – 12/5=93/5
1 + 0 + 2/7 + 2 = -1
0 + 1 – 8/7 + 3 = 8
0 – 0 – 7 - 10 =-10
0 0 - 2 - 15= -15
0 +4/5 -32/35 +12/5 + 32/5
1 -4/5 -6/5 -2/5 - 37/5
0 -21/5 +24/5 -63/5 – 168/5
0 21/5 -34/5 -12/5 + 93/5
1 – 0 + 0 – 78/49 = -69/49
0 + 1 + 0 + 227/49= 472/49
0 + 0 – 1 – 10/7= 10/7
0 + 0 – 0 – 85/7= -85/7
0 +0 2 +20/7 + 20/7
1 0 -2 -15 - 15
1 – 0 + 0 – 0 = -3
0 – 1 + 0 – 0 = 5
0 – 0 + 1 – 0 = 0
0 – 0 + 0 – 1 = 1
0 +0 8/7 +80/49 + 80/49
0 1 -8/7 3 + 8
0 +0 0 -10/7 - 10/7
0 0 1 10/7 10/7
INVESTIGACIÓN OPERATIVA I
DIANA CURICAMA, QUINTO SEMESTRE “A”
3
EJERCICIO 2
2X1 + X2 + 3X3 + 2X4= 3
3X1 + 2X2 -4X3 - X4= 4
4X1 - 3X2 +2X3 +3X4= 2
2X1 +2X2 +2X3 -4X4= 5
1 + 1/2 + 3/2 + 1 =3/2
0 + 1/2 – 17/2- 4=-1/2
0 – 5 – 4 -1 = -4
0 + 1 - 1 -6 = 2
-
2 – 1 + 3 + 2 = 3
3 + 2 - 4 - 1 = 4
4 – 3 + 2 + 3= 2
2 + 2 + 2 -4= 5
3 -3/2 -9/2 -3 = -9/2
3 2 -4 -1 = 4
-4 - 2 - 6 - 4 = -6
4 -3 2 3 = 2
-2 - 1 - 3 - 2 = -3
2 2 2 -4 = 5
0 - 1 17 8 = 1
0 1 -1 -6 = 2
0 0 -16 -656/89 =– 144/89
0 0 16 +2 = 3
0 0 17 697/89 = 153/89
0 0 -17 -8 = -1
0 0 0 -41/89 =5043/42542
0 0 1 41/89 = 9/89
0 0 0 15/89 = -1845/42542
0 1 0 -15/89 = 64/89
0 0 0 -35/89 =4305/42542
1 0 0 35/89 = 88/89
1 + 0 + 10 + 5 = 2
0 + 1 – 17 – 8 =-1
0 + 0 –89 -41 =-9
0 + 0 +16 2 = 3
-
1 + 0 + 0 + 35/89 =88/89
0 + 1 +0 –15/89 =64/89
0 + 0 +1 +41/89 = 9/89
0 + 0 +0 -478/89 =123/89
-
1 + 0 + 0 + 0 =521/478
0 + 1 +0 + 0 =323/478
0 + 0 +1 +0 =105/478
0 + 0 +0 +1=-123/478
INVESTIGACIÓN OPERATIVA I
DIANA CURICAMA, QUINTO SEMESTRE “A”
4
COMPROBACIÓN
2X1 + X2 + 3X3 + 2X4= 3
2(521/478) + (373/478)+3 (105/478) + 2(-123/478)
= 3
EJERCICIO 3
X1= 521/478
X2= 373/478
X3= 105/478
X4= -123/478
3X1 - 2X2 + 4X3 - X4= 4
2X1 + X2 - 3X3 - 2X4= 3
5X1 +2X2 +2X3 +3X4= 5
2X1 -3X2 - X3 + 2X4= 2
1 - 2/3 + 4/3 – 1/3 =4/3
0 +7/3 –17/3- 4/3= 1/3
0 – 16/3 –14/3+ 14/3 =-5/3
0 – 5/3 - 11/3 + 8/3 =-2/3
-
3 – 2 + 4 + -1 = 4
2 + 1 - 3 - 2 = 3
5 + 2 + 2 + 3= 5
2 - 3 - 1 + 2= 2
-2 4/3 -8/3 2/3 = -8/3
2 1 -3 -2 = 3
-5 + 10/2 -20/3 5/3 = -20/3
5 + 2 + 2 + 3 = +5
-2 +4/3 - 8/3 2/3 = -8/3
2 -3 -1 2 = 2
0 - 16/3 272/21 + 64/21 = -16/21
0 16/3 -14/3 +14/3 = -5/3
0 2/3 -34/21 -8/21 = 2/21
0 -2/3 4/3 -1/3 = 4/31 + 0 -2/7 - 5/7 = 10/7
0 + 1 –17/7 –4/7 = 1/7
0 + 0 +58/7 +54/7=-17/7
0 + 0 -54/7 +12/7 =-3/7
-
INVESTIGACIÓN OPERATIVA I
DIANA CURICAMA, QUINTO SEMESTRE “A”
5
COMPROBACIÓN
3X1 - 2X2 + 4X3 - X4= 4
3(52/43) - 2(-5/86)+4 (-1/86) - (-13/43)
= 4
X1= 52/43
X2= -5/86
X3= -1/86
X4= -13/43
0 0 17/7 459/203 =-289/406
0 1 -17/7 -4/7 = 1/7
0 0 0 -27/29 = 351/1247
0 0 1 27/29 = -17/58
0 0 0 -49/29 = 637/1247
0 1 0 49/29 = -33/58
0 0 0 13/29 = -169/1247
1 0 0 -13/29 = 39/29
1 + 0 + 0 - 13/29 =39/29
0 + 1 +0 +49/29 =-33/58
0 + 0 +1 +27/29 = -17/58
0 + 0 +0 +252/29 =-78/29
-
1 + 0 + 0 + 0 =52/43
0 + 1 +0 + 0 =-5/86
0 + 0 +1 +0 =-1/86
0 + 0 +0 +1=-13/43

Método gauss jordan

  • 1.
    INVESTIGACIÓN OPERATIVA IDR. MARLON VILLA 1 UNIVERSIDAD NACIONAL DE CHIMBORAZO FACULTAD DE CIENCIAS POLÍTICAS Y ADMINISTRATIVAS CARRERA DE CONTABILIDAD Y AUDITORÍA CPA INVESTIGACIÓN OPERATIVA I Dr. Marlón Villa Deber 08 Nombre: Diana Curicama Curso: 5to Semestre Paralelo: “A” Fecha: 2 de junio 2015 -Tema: Desarrollar 3 ejercicios de Sistema 4x4 por el método de Gauss-Jordán MÉTODO DE GAUSS-JORDÁN EJERCICIO 1 5A - 4B + 6C - 2D =-37 -2A + 3B - 4C + 5D= 26 6A - 2B + 3C - 4D = -32 -A + 5B - 8C - 2D = 26 5 - 4 + 6 – 2 = -37 -2 + 3 – 4 + 5= 26 6 – 2 +3 - 4 = -32 -1 +5 – 8 – 2 = 26 2 -8/5 12/5 -4/5 =-74/5 -2 3 -4 5 = 26 0 -14/5 +16/5 -42/5 – 112/5 0 +14/5 -51/5 -8/5 +62/5 -1 +5 -8 -2 = 26 1 -4/5 6/5 -2/5 = -37/5 -6 + 24/5 - 36/5 + 12/5 = 222/5 6 - 2 +3 -4 = -32
  • 2.
    INVESTIGACIÓN OPERATIVA I DIANACURICAMA, QUINTO SEMESTRE “A” 2 COMPROBACIÓN 5A-4B+6C-2D=-37 5(-3)-4(5)+6(0)-2(1) =-37 A= -3 B= 5 C= 0 D= 1 1 – 4/5 + 6/5 – 2/5 = -37/5 0 + 7/5 - 8/5 + 21/5= 56/5 0 + 14/5 – 51/5 – 8/5= 62/5 0 + 21/5 – 34/5 – 12/5=93/5 1 + 0 + 2/7 + 2 = -1 0 + 1 – 8/7 + 3 = 8 0 – 0 – 7 - 10 =-10 0 0 - 2 - 15= -15 0 +4/5 -32/35 +12/5 + 32/5 1 -4/5 -6/5 -2/5 - 37/5 0 -21/5 +24/5 -63/5 – 168/5 0 21/5 -34/5 -12/5 + 93/5 1 – 0 + 0 – 78/49 = -69/49 0 + 1 + 0 + 227/49= 472/49 0 + 0 – 1 – 10/7= 10/7 0 + 0 – 0 – 85/7= -85/7 0 +0 2 +20/7 + 20/7 1 0 -2 -15 - 15 1 – 0 + 0 – 0 = -3 0 – 1 + 0 – 0 = 5 0 – 0 + 1 – 0 = 0 0 – 0 + 0 – 1 = 1 0 +0 8/7 +80/49 + 80/49 0 1 -8/7 3 + 8 0 +0 0 -10/7 - 10/7 0 0 1 10/7 10/7
  • 3.
    INVESTIGACIÓN OPERATIVA I DIANACURICAMA, QUINTO SEMESTRE “A” 3 EJERCICIO 2 2X1 + X2 + 3X3 + 2X4= 3 3X1 + 2X2 -4X3 - X4= 4 4X1 - 3X2 +2X3 +3X4= 2 2X1 +2X2 +2X3 -4X4= 5 1 + 1/2 + 3/2 + 1 =3/2 0 + 1/2 – 17/2- 4=-1/2 0 – 5 – 4 -1 = -4 0 + 1 - 1 -6 = 2 - 2 – 1 + 3 + 2 = 3 3 + 2 - 4 - 1 = 4 4 – 3 + 2 + 3= 2 2 + 2 + 2 -4= 5 3 -3/2 -9/2 -3 = -9/2 3 2 -4 -1 = 4 -4 - 2 - 6 - 4 = -6 4 -3 2 3 = 2 -2 - 1 - 3 - 2 = -3 2 2 2 -4 = 5 0 - 1 17 8 = 1 0 1 -1 -6 = 2 0 0 -16 -656/89 =– 144/89 0 0 16 +2 = 3 0 0 17 697/89 = 153/89 0 0 -17 -8 = -1 0 0 0 -41/89 =5043/42542 0 0 1 41/89 = 9/89 0 0 0 15/89 = -1845/42542 0 1 0 -15/89 = 64/89 0 0 0 -35/89 =4305/42542 1 0 0 35/89 = 88/89 1 + 0 + 10 + 5 = 2 0 + 1 – 17 – 8 =-1 0 + 0 –89 -41 =-9 0 + 0 +16 2 = 3 - 1 + 0 + 0 + 35/89 =88/89 0 + 1 +0 –15/89 =64/89 0 + 0 +1 +41/89 = 9/89 0 + 0 +0 -478/89 =123/89 - 1 + 0 + 0 + 0 =521/478 0 + 1 +0 + 0 =323/478 0 + 0 +1 +0 =105/478 0 + 0 +0 +1=-123/478
  • 4.
    INVESTIGACIÓN OPERATIVA I DIANACURICAMA, QUINTO SEMESTRE “A” 4 COMPROBACIÓN 2X1 + X2 + 3X3 + 2X4= 3 2(521/478) + (373/478)+3 (105/478) + 2(-123/478) = 3 EJERCICIO 3 X1= 521/478 X2= 373/478 X3= 105/478 X4= -123/478 3X1 - 2X2 + 4X3 - X4= 4 2X1 + X2 - 3X3 - 2X4= 3 5X1 +2X2 +2X3 +3X4= 5 2X1 -3X2 - X3 + 2X4= 2 1 - 2/3 + 4/3 – 1/3 =4/3 0 +7/3 –17/3- 4/3= 1/3 0 – 16/3 –14/3+ 14/3 =-5/3 0 – 5/3 - 11/3 + 8/3 =-2/3 - 3 – 2 + 4 + -1 = 4 2 + 1 - 3 - 2 = 3 5 + 2 + 2 + 3= 5 2 - 3 - 1 + 2= 2 -2 4/3 -8/3 2/3 = -8/3 2 1 -3 -2 = 3 -5 + 10/2 -20/3 5/3 = -20/3 5 + 2 + 2 + 3 = +5 -2 +4/3 - 8/3 2/3 = -8/3 2 -3 -1 2 = 2 0 - 16/3 272/21 + 64/21 = -16/21 0 16/3 -14/3 +14/3 = -5/3 0 2/3 -34/21 -8/21 = 2/21 0 -2/3 4/3 -1/3 = 4/31 + 0 -2/7 - 5/7 = 10/7 0 + 1 –17/7 –4/7 = 1/7 0 + 0 +58/7 +54/7=-17/7 0 + 0 -54/7 +12/7 =-3/7 -
  • 5.
    INVESTIGACIÓN OPERATIVA I DIANACURICAMA, QUINTO SEMESTRE “A” 5 COMPROBACIÓN 3X1 - 2X2 + 4X3 - X4= 4 3(52/43) - 2(-5/86)+4 (-1/86) - (-13/43) = 4 X1= 52/43 X2= -5/86 X3= -1/86 X4= -13/43 0 0 17/7 459/203 =-289/406 0 1 -17/7 -4/7 = 1/7 0 0 0 -27/29 = 351/1247 0 0 1 27/29 = -17/58 0 0 0 -49/29 = 637/1247 0 1 0 49/29 = -33/58 0 0 0 13/29 = -169/1247 1 0 0 -13/29 = 39/29 1 + 0 + 0 - 13/29 =39/29 0 + 1 +0 +49/29 =-33/58 0 + 0 +1 +27/29 = -17/58 0 + 0 +0 +252/29 =-78/29 - 1 + 0 + 0 + 0 =52/43 0 + 1 +0 + 0 =-5/86 0 + 0 +1 +0 =-1/86 0 + 0 +0 +1=-13/43