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Map of
molarity
Mole
mass
solids/liquids
formula for mole calculation
n= mass/ molar.mass
n=m/mol.m
m=n*mol.mass
particles
n=no pf particlas/avagadros numb
no of particles=n*avagadros numb
gases
n=vol(dm3)/22.4 dm3.mol-1
n=vol(dm3) at stp/molar vol
Practice problem 1.1
Calculate the molecular masses (in amu) of the following compounds:
SO2
Caffeine (C8H10N4O2)
Atomic
mass
of
C=12,
s=32,
N=14,
H=1,
O=16
Solution:
SO2
32+2(16) =64 amu
Caffeine (C8H10N4O2)
8(12) +10(1) +4(14) +2(16) = 194 amu.
Practice problem 1.1
Calculate the number of moles in 5.68 g of iron.
Atomic
mass of
iron
Fe=55.8
Solution:
No of moles=n=? Mass of Fe=5.68 g
As we know that n= mass/ molar. Mass so by putting
values in the formula
n=5.68 g /55.8 g.mol -1 , n= 0.1 mol.

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mole map

  • 1. Map of molarity Mole mass solids/liquids formula for mole calculation n= mass/ molar.mass n=m/mol.m m=n*mol.mass particles n=no pf particlas/avagadros numb no of particles=n*avagadros numb gases n=vol(dm3)/22.4 dm3.mol-1 n=vol(dm3) at stp/molar vol
  • 2. Practice problem 1.1 Calculate the molecular masses (in amu) of the following compounds: SO2 Caffeine (C8H10N4O2) Atomic mass of C=12, s=32, N=14, H=1, O=16 Solution: SO2 32+2(16) =64 amu Caffeine (C8H10N4O2) 8(12) +10(1) +4(14) +2(16) = 194 amu.
  • 3. Practice problem 1.1 Calculate the number of moles in 5.68 g of iron. Atomic mass of iron Fe=55.8 Solution: No of moles=n=? Mass of Fe=5.68 g As we know that n= mass/ molar. Mass so by putting values in the formula n=5.68 g /55.8 g.mol -1 , n= 0.1 mol.