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S.M.E.D (Single minute Exchange of day)
                          Metal structure calculation



CALCULO DE LA VIGA DEL APOYA- MOLDES

Two hypothesis.
   1.   We suppose the load will be leant just on one beams.
   2.   We suppose the load distributed equally on each .


   First :

   The heaviest mould weighs 3200kg , We suppose a distributed load
   3200Kg/540mm =6Kg/mm

                                  6Kg/mm




         R1                                         R2




We use a square hollow beam:

R1 + R 2 = 6 • 540
6 • 540 • 270 = 540 R1
R1 = 1620 Kg
R 2 = 1620 Kg

Maximum moment


                         4200kg




               1176000




                                    Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                               Metal structure calculation




Q = −6 x + 1620
Mf = −3x 2 + 1620 x

x = 270mm
Mf max = −3 • 2702 + 1670 • 270
Mf max = 218700 Kg • mm

Square hollow beam




Steel A-42

                                               218000 Kg • m  L 
σ adm = 260 Kg           2               260 =              • 
                    mm                            L
                                                         4
                                                             2
          M f max                                  
σ adm =             •x                             12 
              Ix                         L = 18mm


          .


Square de 40.2               L=40mm (length) y e=2mm (thickness)




                                                 M f max                         M f max ( Kg • mm )
W = 3.40cm3 = 3400mm3                  σ adm =             260 Kg        2   =
                                                   W                mm               3400mm3


Mf max = 884000 Kg • mm            Mf max > 218000( Kg • mm )                    Cumple




                                    Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                             Metal structure calculation


 Second hypothesis :


                            2Kg/mm




           R1                                      R2




          R1 + R 2 = 2 • 540
          2 • 540 • 270 = 540 R1
          R1 = 1080 Kg
          R 2 = 1080 Kg



 Maximum moment
         2Kg/mm




R1




 Q = −2 x + 540
 Mf = − x 2 + 540 x


     x = 270mm
 Mf max = ( − 1) • 2702 + 540 • 270
 Mf max = 72900 Kg • mm




                                   Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                             Metal structure calculation




                                                   72900 Kg • m  L 
σ adm = 260 Kg           2                   260 =             • 
                    mm                                L
                                                             4
                                                                2
          M f max                                      
σ adm =             •x                                 12 
            Ix                               L = 12mm


          12mm de lado, the standard which fits best according to the regulation NBE
EA-95


          L= 40mm;           e = 2mm




                                                 M f max                         M f max ( Kg • mm )
W = 3.40cm3 = 3400mm3                  σ adm =             260 Kg        2   =
                                                   W                mm               3400mm3
Mf max = 884000 Kg • mm                Mf max > 72900( Kg • mm ) Cumple




CALCULATION OF THE LIFT




Calculation of the total load lean on the lift

Ct = Cd + Ces

Cd = depots loaded; Ces = weight metallic structure.

ρac= 7850 Kg / m 3 (Steel density).


                                   Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                         Metal structure calculation



ρpp = 1kg / m3       (Polypropylene density)

Measurement of the depots:
   •   ∅235mm x 835
   •   ∅235mm x 605

Cálculation of the depot´s load


   M                                                π • 0.2352
ρ=               M = ρ • V : M = 7851 • 0.850 •                = 284 Kg   Deposito1
   V                                                     4
   M                                  π • 0.2352
ρ=               M = 7851 • 0.605 •              = 206 Kg                 Deposito 2
   V                                       4


Calculation of the metallic structure load

M = ρ • V Ves = L • as = 3.555 • 0.060 2 = 0.012798mm 3 Volumen de la estructura metálica
M = 7850 • 0.012798 = 100 Kg
Ct = Cd + Ces Ct = 490 + 100 = 590
Suponiendo que los deposito esta n llenos

                                           590 kg
                        Seccion A-A




                      E:1/5




                               Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                           Metal structure calculation


section A-A




                   Q=590Kg




                   Mf=590*50Kgmm




                                                             :
   •     Sheer stress.
   •     Bending moment.


Sheer stress
                    a     a
               590 •  •a•
   Q • Me           2     2 ≤ 26• 0.5
τ≥        ;                                  a = 12mm      (sec ción maciza )
    b•I               a 4
                   a•
                      12
Momento flector

     Mf           590 • 50 • 3 a
σ≥       y : 26 =             • ;    a = 30mm
      I               a4       2                    Con un coeficiente de seguridad N=3
                      12
Estándar profile according to the regulations is 40.2




       Mf          590 • 50 • 3
σ≥        y : 26 ≥              • 20    do not meet the minimum security conditions
        I            66000



                                 Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                           Metal structure calculation


profile 60.2
     Mf          590 • 50 • 3
σ≥      y : 26 ≥              • 30
      I            248000                    meet all the specifications



   (*)Meeting all the specifications according to the regulations NBE-EA95.




Calculation metal sheet nº7

                                   550 Kg.




                        59mm




   Sección B-B



Section B-B

                      550 Kg
 550*59

                               b


                  a
Sheer stress

                    b        b
               550 • • 20 •
   Q • Me           2        2 ≤ 26• 0.5
τ≥        ;                                         b = 5mm
    b•I             20 • b 4
                 b•
                      12




                                   Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                                Metal structure calculation




      Bending moment


            Mf          550 • 59 • 3 b
      σ≥       y : 26 ≥             •         b = 10.5mm
             I            20 • b 4    2
                            12
      The metal sheet has 11mm of thickness


      Calculation metal sheet nº8



                            550 Kg
       30

                                     a

Sección C-C
                  60

      section C-C


                            550 Kg
        550*54
                                     b


                        a

      Bending moment


            Mf          550 • 54 • 3 b
      σ ≥      y : 26 ≥             •          b = 8mm        N=3
             I            40 • b 4    2
                            12

      The thickness is of 8mm.

      Screw calculation for piece 9


                                         Proyecto fin de carrera
S.M.E.D (Single minute Exchange of day)
                          Metal structure calculation




      N            225(*) • 3                     De diámetro
σ=          26 ≥              D = 2mm
      A             D •π •8



Sheer screw calculation


      Q             225(*) • 3
τ =         13 ≥                 D = 8mm
      A             π •D2                  Cogemos el mayor, necesitamos un tornillo de
                        4
métrica 8




                                 Proyecto fin de carrera

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Metal Structure Calculations

  • 1. S.M.E.D (Single minute Exchange of day) Metal structure calculation CALCULO DE LA VIGA DEL APOYA- MOLDES Two hypothesis. 1. We suppose the load will be leant just on one beams. 2. We suppose the load distributed equally on each . First : The heaviest mould weighs 3200kg , We suppose a distributed load 3200Kg/540mm =6Kg/mm 6Kg/mm R1 R2 We use a square hollow beam: R1 + R 2 = 6 • 540 6 • 540 • 270 = 540 R1 R1 = 1620 Kg R 2 = 1620 Kg Maximum moment 4200kg 1176000 Proyecto fin de carrera
  • 2. S.M.E.D (Single minute Exchange of day) Metal structure calculation Q = −6 x + 1620 Mf = −3x 2 + 1620 x x = 270mm Mf max = −3 • 2702 + 1670 • 270 Mf max = 218700 Kg • mm Square hollow beam Steel A-42 218000 Kg • m  L  σ adm = 260 Kg 2 260 = •  mm L 4 2 M f max   σ adm = •x  12  Ix L = 18mm . Square de 40.2 L=40mm (length) y e=2mm (thickness) M f max M f max ( Kg • mm ) W = 3.40cm3 = 3400mm3 σ adm = 260 Kg 2 = W mm 3400mm3 Mf max = 884000 Kg • mm Mf max > 218000( Kg • mm ) Cumple Proyecto fin de carrera
  • 3. S.M.E.D (Single minute Exchange of day) Metal structure calculation Second hypothesis : 2Kg/mm R1 R2 R1 + R 2 = 2 • 540 2 • 540 • 270 = 540 R1 R1 = 1080 Kg R 2 = 1080 Kg Maximum moment 2Kg/mm R1 Q = −2 x + 540 Mf = − x 2 + 540 x x = 270mm Mf max = ( − 1) • 2702 + 540 • 270 Mf max = 72900 Kg • mm Proyecto fin de carrera
  • 4. S.M.E.D (Single minute Exchange of day) Metal structure calculation 72900 Kg • m  L  σ adm = 260 Kg 2 260 = •  mm L 4 2 M f max   σ adm = •x  12  Ix L = 12mm 12mm de lado, the standard which fits best according to the regulation NBE EA-95 L= 40mm; e = 2mm M f max M f max ( Kg • mm ) W = 3.40cm3 = 3400mm3 σ adm = 260 Kg 2 = W mm 3400mm3 Mf max = 884000 Kg • mm Mf max > 72900( Kg • mm ) Cumple CALCULATION OF THE LIFT Calculation of the total load lean on the lift Ct = Cd + Ces Cd = depots loaded; Ces = weight metallic structure. ρac= 7850 Kg / m 3 (Steel density). Proyecto fin de carrera
  • 5. S.M.E.D (Single minute Exchange of day) Metal structure calculation ρpp = 1kg / m3 (Polypropylene density) Measurement of the depots: • ∅235mm x 835 • ∅235mm x 605 Cálculation of the depot´s load M π • 0.2352 ρ= M = ρ • V : M = 7851 • 0.850 • = 284 Kg Deposito1 V 4 M π • 0.2352 ρ= M = 7851 • 0.605 • = 206 Kg Deposito 2 V 4 Calculation of the metallic structure load M = ρ • V Ves = L • as = 3.555 • 0.060 2 = 0.012798mm 3 Volumen de la estructura metálica M = 7850 • 0.012798 = 100 Kg Ct = Cd + Ces Ct = 490 + 100 = 590 Suponiendo que los deposito esta n llenos 590 kg Seccion A-A E:1/5 Proyecto fin de carrera
  • 6. S.M.E.D (Single minute Exchange of day) Metal structure calculation section A-A Q=590Kg Mf=590*50Kgmm : • Sheer stress. • Bending moment. Sheer stress a a 590 • •a• Q • Me 2 2 ≤ 26• 0.5 τ≥ ; a = 12mm (sec ción maciza ) b•I a 4 a• 12 Momento flector Mf 590 • 50 • 3 a σ≥ y : 26 = • ; a = 30mm I a4 2 Con un coeficiente de seguridad N=3 12 Estándar profile according to the regulations is 40.2 Mf 590 • 50 • 3 σ≥ y : 26 ≥ • 20 do not meet the minimum security conditions I 66000 Proyecto fin de carrera
  • 7. S.M.E.D (Single minute Exchange of day) Metal structure calculation profile 60.2 Mf 590 • 50 • 3 σ≥ y : 26 ≥ • 30 I 248000 meet all the specifications (*)Meeting all the specifications according to the regulations NBE-EA95. Calculation metal sheet nº7 550 Kg. 59mm Sección B-B Section B-B 550 Kg 550*59 b a Sheer stress b b 550 • • 20 • Q • Me 2 2 ≤ 26• 0.5 τ≥ ; b = 5mm b•I 20 • b 4 b• 12 Proyecto fin de carrera
  • 8. S.M.E.D (Single minute Exchange of day) Metal structure calculation Bending moment Mf 550 • 59 • 3 b σ≥ y : 26 ≥ • b = 10.5mm I 20 • b 4 2 12 The metal sheet has 11mm of thickness Calculation metal sheet nº8 550 Kg 30 a Sección C-C 60 section C-C 550 Kg 550*54 b a Bending moment Mf 550 • 54 • 3 b σ ≥ y : 26 ≥ • b = 8mm N=3 I 40 • b 4 2 12 The thickness is of 8mm. Screw calculation for piece 9 Proyecto fin de carrera
  • 9. S.M.E.D (Single minute Exchange of day) Metal structure calculation N 225(*) • 3 De diámetro σ= 26 ≥ D = 2mm A D •π •8 Sheer screw calculation Q 225(*) • 3 τ = 13 ≥ D = 8mm A π •D2 Cogemos el mayor, necesitamos un tornillo de 4 métrica 8 Proyecto fin de carrera