This document provides information about an online math homework help service called Homework1. It includes: - Contact information for Homework1, including their address, phone number, email, and social media links. - An overview of the services provided, which include math homework help, writing assistance, and teaching students the solutions to help them learn. - Several examples and solutions to common math problems to illustrate the type of homework help offered.

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Math Homework Help Service
Contact Us
Homework1
3422 SW 15 Street
Suite #8924
Deerfield Beach, FL, US 33442
Tel: +1-626-472-1732
Web: https://homework1.com/
Email: info@homework1.com
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2. Homework1
Copyright © 2014-2015 Homework1.com, All rights reserved
About Us:
At Homework1.com we offer authentic and 100% accurate
online math homework help and study assistance to students
from USA, UK, Australia, and Canada. However, we don’t offer
students only math assignment help service to complete their
study project; rather we offer our best effort to teach our
student-clients about the homework we have solved. Our
tutors are not only subject matter experts, they are avid
student-mentors and are ready to walk extra miles to make them understand the
fundamentals of the assignment done, and help them to learn the solution by heart.
We are available online by 24×7 and we can be reached via email, live chat, as well as
by direct phone calls. Our USP is quick turnaround time with stringent quality assurance
about the assignment we undertake. We offer assistance is writing dissertations,
academic and project related essay writing, and in writing and reviewing research
papers. These research papers are done by best subject matter experts available and we
offer 100% plagiarism free content by following proper and prescribed house style.
Looking for quality math homework help ? Before you hire this academic service, you
can first shortlist the reason you are looking for hiring this academic online support. This
is not the fact you can only get to solve complicated math assignment problems, but you
will be able to learn and understand the problem pretty well by some of the most expert
tutors on the most interactive communication platform by hiring this service. In one
word you can be benefited in a multifaceted way provided you can select the best service
provider from the market. We at homework1 not only honor your requirement, we
understand the necessity of doing the assignment by your deadline no matter you have
contacted us the most critical hour. Besides maintaining best quality, we also offer latest
updates in the solution so that you can impress your reviewer. We offer quality Math
Homework Help at most reasonable cost.
Sample of Math Homework Help Illustrations and Solutions:
Illustration 1. Solve for x :
𝑥−1
𝑥−2
+
𝑥−3
𝑥−4
=
10
3
= (x ≠ 2, x ≠ 4)
Solution.
We have :
𝑥−1
𝑥−2
+
𝑥−3
𝑥−4
=
10
3
=
𝑥−1 𝑥−4 𝑥−2 (𝑥−3)
𝑥−2 𝑥−4
=
10
3

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=
𝑥2− 5𝑥+4 + (𝑥2−5𝑥+6)
𝑥2−6𝑥+8
=
10
3
=
2𝑥2− 10𝑥+10
𝑥2−6𝑥+8
=
10
3
= 10 𝑥2
- 10x – 5x + 25 = 0 = 2x (x -5) -5 (x – 5 ) = 0 = 2𝑥2
- 15x + 25 = 0
= 2𝑥2
- 10x – 5x + 25 = 0 = 2x (x – 5) -5 (x-5) = 0
= (x – 5 ) (2x – 5 ) = 0 = Either x – 5 = 0 or 2x -5 = 0 =x = 5 or x =
5
2
Hence, the solution are 5 and
5
2
Illustration 2. Solve the following quadratic equations by factorization method:
(i)
4
𝑥
- 3 =
5
2𝑥+3
; x ≠ 0,
3
2
(ii)
2𝑥
𝑥−3
+
1
2𝑥+3
+
3𝑥+9
𝑥−3 (2𝑥+3)
= 0
Solution.
(i) We have
4
𝑥
- 3 =
5
2𝑥+3
=
4−3𝑥
𝑥
=
5
2𝑥+3
= (4 – 3x) (2x + 3) = 5x = 12 –x - 6𝑥2
= 5x = 6x2 + 6x – 12 = 0 = 𝑥2
+x – 2 = 0
= 𝑥2
+ 2x – x – 2 = 0 = x (x +2) = 0 = (x+2) (x-1) = 0
= x + 2 = 0 or x – 1 = 0 = x = -2 or x = 1
(ii) Clearly, the given equation is valid if x – 3 ≠ 0 i.e., when x ≠-
3
2
, 3

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Now,
2𝑥
𝑥−3
+
1
2𝑥+3
+
3𝑥+9
𝑥−3 (2𝑥+3)
= 0
= 2x (2x + 3) + (x-3) + 3x + 9 = 0 [Multiplying throughout by (x-3) (2x +
3)]
= 4𝑥2
+ 6x +x -3 + 3x + 9 = 0 = 4𝑥2
+ 10x + 6 = 0
= 2x2 + 5x + 3 = 0 = 2𝑥2
+2x + 3x + 3 = 0
= 2x (x + 1) + (3x + 1) = 0 = (2x + 3) (x + 1) = 0 = x + 1 = 0 = x = -1 [∵ 2x + 3 ≠
0]
Hence, x = -1 is the only solution of the given equation.
Illustration 3. The roots of the equation 𝑥2
- 3x + 2 = 0 are
(a) (1,-2) (b) (-1,2) (c) (-1,-2) (d) (-1,-2)
Solution.
x2
- 3x + 2 = 0 = (x – 1) (x – 2 ) = 0 = x = 1,2 = ∴ (d) holds.

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Illustration 4. The non-zero root of 3x - 5𝑥2
= 0 is
(a)
3
5
(b)
5
3
(c)
5
9
(d) (1,2)
Solution.
3x - 5𝑥2
= 0 = x (3 – 5x ) = 0 = x = 0 or x =
3
5
But x ≠ 0 ∴ x =
3
5
∴ (a) holds.
Illustration 5. Which of the following equation has 2 as a root?
(a) 𝑥2
- 4x + 5 = 0 (b) 𝑥2
+ 3x -12 = 0 (c) 2𝑥2
- 7x + 6 = 0 (d) 3𝑥2
- 7x + 6
= 0 (d)3𝑥2
- 6x-2= 0
Solution.
Clearly (c) holds [∵ 2 (2)2
-7 (2) + 6 = 8 – 14 + 6 = 0]
Illustration 6. The root of the quadratic equation 6𝑥2
-x -2 = 0 is :
(a)
1
2
(b)-
1
2
(c) -
2
3
(d) -1.
Solution.
6𝑥2
- x – 2 = 0 = 6𝑥2
– 4x + 3x – 2 = 0 = 2x (3x – 2) + 1 (3x – 2) = 0
= (2x + 1) (3x – 2) = 0 = 2x + 1 = 0 or 3x – 2 = 0

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= 2x = -1 or 3x = 2 = x = −
1
2
or x =
2
3
∴ (b) holds.
Illustration 7. The positive root of 3𝑥2 + 6 = 9 is
(a) 3 (b) 4 (c) 5 (d) 7
Solution.
3𝑥2 + 6 = 9 = 3𝑥2
+ 6 = 81 = 3𝑥2
= 81 – 6 = 75 = 𝑥2
= 25 = x = 5 ∴ (c) holds.
Illustration 8. Which of the following is a solution of the quadratic equation 𝑥2
- 𝑏2
= a
(2x – a) ?
(a) a + b (b) 2b – a (c) ab (d)
𝑎
𝑏
Solution.
We have 𝑥2
- 𝑏2
= a (2x – a) = 2ax - 𝑎2
= (𝑥2
-2ax + 𝑎2
) - 𝑏2
= 0 = (x – 𝑎)2
- 𝑏2
= 0
= (x – a – b) (x –a + b) = 0 = x –a –b = 0 or x – a + b = 0
= x = a + b or x = a –b
Illustration 9. The roots of the equation 𝑥2
+ 5x – (𝛼 + 1 ) (𝛼 + 6) = 0,
where 𝛼 is a constant, are

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(a) 𝛼 + 1, 𝛼 + 6 (b) (𝛼 + 1) 𝛼 + 6 = 0
(c)- (𝛼 + 1), (𝛼 + 6) (d) – (𝛼 + 1), - (𝛼 + 6)
Solution.
The given equation can be written as
𝑥2
+ [(a + 6) – (𝛼 + 1)] x – (𝛼 + 1) 𝛼 + 6 = 0
= x (x +(𝛼 + 6) - ( + 1)(x (𝛼 + 6) =0
= (x + (𝛼 + 6)) (x – (𝛼 + 1)) = 0 = x = -(𝛼 + 6), 𝛼 + 1. ∴ (c) Holds,