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MATEMATICA
PRODUCTOS NOTABLES
A) Binomio al cuadrado
PRIMERO
(โˆš3 x + 2)
2
= (โˆš3 x)
2
+ 2(โˆš3 x)(2) + 22
(โˆš3 x + 2)
2
= โˆš3
2
x2
+ 4โˆš3 x + 4
(โˆš3 x + 2)
2
= โˆš3
2
x2
+ 4โˆš3 x + 4
SEGUNDO
(5x + 3y2
z4)2
= (5x)2
+ 2(5x)(3y2
z4) + (3y2
z4)2
(5x + 3y2
z4)2
= 25x2
+ 30xy2
z4
+ 9y4
z8
B) Cuadrado de la diferencia de dos cantidades
PRIMERO
(x ๐‘Ž+1
โˆ’ x ๐‘Ž+2
)2
= (x ๐‘Ž+1
)2
โˆ’ 2(x ๐‘Ž+1
)(x ๐‘Ž+2
)+ (x ๐‘Ž+2
)2
(x ๐‘Ž+1
โˆ’ x ๐‘Ž+2
)2
= x2๐‘Ž+2
โˆ’ 2x2๐‘Ž+3
+ x2๐‘Ž+4
SEGUNDO
(4m2
โˆ’ 3n5
)2
= (4m2
)2
โˆ’ 2(4m2
)(3n5
)+ (3n5
)2
(4m2
โˆ’ 3n5
)2
= 16๐‘š4
โˆ’ 24๐‘š2
๐‘›5
+ 9๐‘›10
C) Cubo de una suma
PRIMERO
(8๐‘ฅ3
+ 27๐‘ฆ6
) = (2x + 3y2
)(4๐‘ฅ2
โˆ’ 6๐‘ฅ๐‘ฆ2
+ 9๐‘ฆ4
)
SEGUNDO
(512 + 27๐‘ฅ9
) = (8 + 3๐‘ฅ3
)(64 โˆ’ 24๐‘ฅ3
+ 9๐‘ฅ6
D) Cubo de una diferencia
PRIMERO
(273
โˆ’ ๐‘ฆ3
) = (3x โˆ’ y)(9๐‘ฅ2
+ 3๐‘ฅ๐‘ฆ + ๐‘ฆ2
SEGUNDO
(๐‘ฅ3
โˆ’ 23
) = (x โˆ’ 2)(๐‘ฅ2
+ 2๐‘ฅ + 22
)
(๐‘ฅ3
โˆ’ 23
) = (x โˆ’ 2)(๐‘ฅ2
+ 2๐‘ฅ + 4)
E) Producto de la suma por la diferencia de dos cantidades
PRIMERO
(๐‘ฅ2
โˆ’ 2x)(๐‘ฅ2
+ 2x) = (๐‘ฅ2
)2
โˆ’ (2๐‘ฅ )2
SEGUNDO
(๐‘ฅ2
โˆ’ 4)(๐‘ฅ2
+ 4) = (๐‘ฅ2
)2
โˆ’ 42
COCIENTES NOTABLES
PRIMERO
๐‘ฅ2
โˆ’ 1
๐‘ฅ + 1
=
๐‘ฅ2
โˆ’ 12
๐‘ฅ + 1
= ๐‘ฅ โˆ’ 1
SEGUNDO
(๐‘ฅ + 1)2
โˆ’ 4๐‘ฆ2
๐‘ฅ + 1 โˆ’ 2๐‘ฆ
=
(๐‘ฅ + 1)2
โˆ’ (2๐‘ฆ)2
( ๐‘ฅ + 1) โˆ’ 2๐‘ฆ
= ( ๐‘ฅ + 1) + 2๐‘ฆ
TERCERO
๐‘ฅ3
+ 8
๐‘ฅ + 2
=
๐‘ฅ3
+ 23
๐‘ฅ + 2
= ๐‘ฅ2
โˆ’ 2๐‘ฅ + 22
= ๐‘ฅ2
โˆ’ 2๐‘ฅ + 4
CUARTO
125 โˆ’ 64๐‘ฅ6
5 โˆ’ 4๐‘ฅ2
=
53
โˆ’ (4๐‘ฅ2
)3
5 โˆ’ (4๐‘ฅ2)
= 25 + 20๐‘ฅ2
+ 16๐‘ฅ2
DERIVADAS
A) DERIVADAS DE UNA FUNCION POTENCIAL
PRIMERO
๐‘“( ๐‘ฅ) = (3๐‘ฅ2
+ 2)3
(2๐‘ฅ2
+ 3๐‘ฅ + 1)
๐‘“( ๐‘ฅ) = 3(3๐‘ฅ2
+ 2)2
. 6๐‘ฅ(2๐‘ฅ2
+ 3๐‘ฅ + 1) + (3๐‘ฅ2
+ 2)3
(4๐‘ฅ + 3)
๐‘“( ๐‘ฅ) = 18๐‘ฅ(3๐‘ฅ2
+ 2)2 (2๐‘ฅ2
+ 3๐‘ฅ + 1) + (3๐‘ฅ2
+ 2)3
(4๐‘ฅ + 3)
๐‘“( ๐‘ฅ) = (3๐‘ฅ2
+ 2)2[18๐‘ฅ(2๐‘ฅ2
+ 3๐‘ฅ + 1) + (3๐‘ฅ2
+ 2)(4๐‘ฅ + 3)]
๐‘“( ๐‘ฅ) = (3๐‘ฅ2
+ 2)2
(36๐‘ฅ3
+ 54๐‘ฅ2
+ 18๐‘ฅ + 12๐‘ฅ3
+ 9๐‘ฅ2
+ 8๐‘ฅ + 6)
๐’‡( ๐’™) = (๐Ÿ‘๐’™ ๐Ÿ
+ ๐Ÿ) ๐Ÿ
(๐Ÿ’๐Ÿ–๐’™ ๐Ÿ‘
+ ๐Ÿ”๐Ÿ‘๐’™ ๐Ÿ
+ ๐Ÿ๐Ÿ”๐’™ + ๐Ÿ”)
SEGUNDO
๐‘“( ๐‘ฅ) = (6๐‘ฅ2
+ ๐‘ฅ)2
(๐‘ฅ5
+ ๐‘ฅ6
)4
๐‘“(๐‘ฅ) = 2(6๐‘ฅ2
+ ๐‘ฅ)(12๐‘ฅ + 1)(๐‘ฅ5
+ ๐‘ฅ6
)4
+ (6๐‘ฅ2
+ ๐‘ฅ)2
4(๐‘ฅ5
+ ๐‘ฅ6
)3
(5๐‘ฅ4
+ 6๐‘ฅ5
)
๐‘“(๐‘ฅ) = 2(6๐‘ฅ2
+ ๐‘ฅ) (๐‘ฅ5
+ ๐‘ฅ6
)3[(12๐‘ฅ + 1)( ๐‘ฅ5
+ ๐‘ฅ6) + 2(6๐‘ฅ2
+ ๐‘ฅ)(5๐‘ฅ4
+ 6๐‘ฅ5
)]
๐‘“(๐‘ฅ) = 2(6๐‘ฅ2
+ ๐‘ฅ) (๐‘ฅ5
+ ๐‘ฅ6
)3[12๐‘ฅ6
+ 12๐‘ฅ7
+ ๐‘ฅ5
+ ๐‘ฅ6
+ 2(30๐‘ฅ6
+ 36๐‘ฅ7
+ 5๐‘ฅ5
+ 6๐‘ฅ6
)]
๐‘“(๐‘ฅ) = 2(6๐‘ฅ2
+ ๐‘ฅ) (๐‘ฅ5
+ ๐‘ฅ6
)3[12๐‘ฅ6
+ 12๐‘ฅ7
+ ๐‘ฅ5
+ ๐‘ฅ6
+ 60๐‘ฅ6
+ 72๐‘ฅ7
+ 10๐‘ฅ5
+ 12๐‘ฅ6]
๐’‡( ๐’™) = ๐Ÿ(๐Ÿ”๐’™ ๐Ÿ
+ ๐’™) (๐’™ ๐Ÿ“
+ ๐’™ ๐Ÿ”
) ๐Ÿ‘
(๐Ÿ–๐Ÿ’๐’™ ๐Ÿ•
+ ๐Ÿ–๐Ÿ“๐’™ ๐Ÿ”
+ ๐Ÿ๐Ÿ๐’™ ๐Ÿ“
)
TERCERO
๐‘“( ๐‘ฅ) =
(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
๐‘ฅ2 + 6
=
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)(10๐‘ฅ + 7)( ๐‘ฅ2
+ 6) โˆ’ (5๐‘ฅ2
+ 7๐‘ฅ + 2)2
2๐‘ฅ
(๐‘ฅ2 + 6)2
๐‘“( ๐‘ฅ) =
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
๐‘ฅ2 + 6
=
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)(10๐‘ฅ + 7)( ๐‘ฅ2
+ 6) โˆ’ 2๐‘ฅ(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
(๐‘ฅ2 + 6)2
๐‘“( ๐‘ฅ) =
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
๐‘ฅ2 + 6
=
[(10๐‘ฅ + 7)( ๐‘ฅ2
+ 6) โˆ’ ๐‘ฅ(5๐‘ฅ2
+ 7๐‘ฅ + 2)]
(๐‘ฅ2 + 6)2
๐‘“( ๐‘ฅ) =
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
๐‘ฅ2 + 6
=
[10๐‘ฅ3
+ 60๐‘ฅ + 7๐‘ฅ2
+ 42 โˆ’ 5๐‘ฅ3
โˆ’ 7๐‘ฅ2
โˆ’ 2๐‘ฅ]
(๐‘ฅ2 + 6)2
๐‘“( ๐‘ฅ) =
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)2
๐‘ฅ2 + 6
=
2(5๐‘ฅ2
+ 7๐‘ฅ + 2)2[5๐‘ฅ3
+ 58๐‘ฅ + 42]
(๐‘ฅ2 + 6)2
B) DERIVADAS DE UNA FUNCION LOGARITMICA
PRIMERO
๐‘“( ๐‘ฅ) = ( ๐‘ฅ3
+ ๐‘ฅ2
+ ๐‘ฅ + 5) ๐‘™๐‘›(5๐‘ฅ2
โˆ’ 7) =
๐‘“( ๐‘ฅ) = (3๐‘ฅ2
+ 2๐‘ฅ + 1) ๐‘™๐‘›(5๐‘ฅ2
โˆ’ 7) + ( ๐‘ฅ3
+ ๐‘ฅ2
+ ๐‘ฅ + 5).
10๐‘ฅ
5๐‘ฅ2 โˆ’ 7
=
๐’‡( ๐’™) = ( ๐Ÿ‘๐’™ ๐Ÿ
+ ๐Ÿ๐’™ + ๐Ÿ) ๐’๐’( ๐Ÿ“๐’™ ๐Ÿ
โˆ’ ๐Ÿ•) +
๐Ÿ๐ŸŽ๐’™( ๐’™ ๐Ÿ‘
+ ๐’™ ๐Ÿ
+ ๐’™ + ๐Ÿ“)
๐Ÿ“๐’™ ๐Ÿ โˆ’ ๐Ÿ•
SEGUNDO
๐‘“( ๐‘ฅ) = ๐ฟ๐‘›( ๐‘ฅ7
+ 7๐‘ฅ3
+ 3๐‘ฅ + 1) ๐‘™๐‘›(4๐‘ฅ2
โˆ’ 3๐‘ฅ โˆ’ 1) =
๐‘“( ๐‘ฅ) = ๐ฟ๐‘›(7๐‘ฅ6
+ 21๐‘ฅ2
+ 3) ๐‘™๐‘›(4๐‘ฅ2
โˆ’ 3๐‘ฅ โˆ’ 1) + ( ๐‘ฅ7
+ 7๐‘ฅ3
+ 3๐‘ฅ + 1).
8๐‘ฅ โˆ’ 3
4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1
๐‘“( ๐‘ฅ) = (7๐‘ฅ6
+ 21๐‘ฅ2
+ 3)ln(4๐‘ฅ2
โˆ’ 3๐‘ฅ โˆ’ 1) +
(๐‘ฅ7
+ 7๐‘ฅ3
+ 3๐‘ฅ + 1)(8๐‘ฅ โˆ’ 3)
4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1
TERCERO
๐‘“( ๐‘ฅ) = ๐ฟ๐‘› (
1
โˆš(1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2)23
) =
๐‘“( ๐‘ฅ) = ๐ฟ๐‘› (
1
(1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2)
2
3
) =
๐‘“( ๐‘ฅ) = ๐ฟ๐‘› = (1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2
)โˆ’
2
3 = โˆ’
2
3
ln(1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2
)
๐‘“( ๐‘ฅ) = โˆ’
2
3
.
2 โˆ’ 10๐‘ฅ
1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2
=
โˆ’๐Ÿ(๐Ÿ โˆ’ ๐Ÿ๐ŸŽ๐’™)
๐Ÿ‘(๐Ÿ โˆ’ ๐Ÿ๐’™ โˆ’ ๐Ÿ“๐’™ ๐Ÿ)
C) DERIVADAS DE UNA FUNCION EXPONENCIAL
PRIMERO
๐‘“( ๐‘ฅ) = (4๐‘ฅ2
+ 3)5
3(๐‘ฅ+2)
๐‘“( ๐‘ฅ) = 5(4๐‘ฅ2
+ 3)4
8๐‘ฅ3( ๐‘ฅ+2)
+ (4๐‘ฅ2
+ 3)5
3( ๐‘ฅ+2)
ln(3)
๐‘“( ๐‘ฅ) = 40๐‘ฅ(4๐‘ฅ2
+ 3)4
3( ๐‘ฅ+2)
+ (4๐‘ฅ2
+ 3)5
3( ๐‘ฅ+2)
ln(3)
๐‘“( ๐‘ฅ) = (4๐‘ฅ2
+ 3)4 [40๐‘ฅ + (4๐‘ฅ2
+ 3) ๐‘™๐‘›n(3)]3( ๐‘ฅ+2)
SEGUNDO
๐‘“( ๐‘ฅ) = (๐‘ฅ5
+ 4๐‘ฅ + 1)3
2(๐‘ฅ3
+5)
๐‘“( ๐‘ฅ) = 3(๐‘ฅ5
+4๐‘ฅ + 1)2(5๐‘ฅ4
+ 4)2(๐‘ฅ3
+5)
+ (๐‘ฅ5
+ 4๐‘ฅ + 1)3
2(๐‘ฅ3
+5)
3๐‘ฅ2
ln(2)
๐‘“( ๐‘ฅ) = 3(๐‘ฅ5
+4๐‘ฅ + 1)2(5๐‘ฅ4
+ 4)2(๐‘ฅ3
+5)
+ 3๐‘ฅ2
(๐‘ฅ5
+4๐‘ฅ + 1)3
2(๐‘ฅ3
+5)
ln(2)
๐‘“( ๐‘ฅ) = 3(๐‘ฅ5
+4๐‘ฅ + 1)2[(5๐‘ฅ4
+ 4)+๐‘ฅ2
(๐‘ฅ5
+ 4๐‘ฅ + 1)ln(2)]2(๐‘ฅ3+5)
TERCERO
๐‘“( ๐‘ฅ) = (๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)2
7(5๐‘ฅโˆ’3)
๐‘“( ๐‘ฅ) = 2( ๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)(2๐‘ฅ โˆ’ 1)7(5๐‘ฅโˆ’3)
+ (๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)2
7(5๐‘ฅโˆ’3)
5ln(7)
๐‘“( ๐‘ฅ) = 2( ๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)(2๐‘ฅ โˆ’ 1)7(5๐‘ฅโˆ’3)
+ 5(๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)2
7(5๐‘ฅโˆ’3)
ln(7)
๐‘“( ๐‘ฅ) = ( ๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)[2(2๐‘ฅ โˆ’ 1) + 5(๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3)ln(7)]7(5๐‘ฅโˆ’3)
D) Derivada de la funciรณn trigonomรฉtrica de Seno
PRIMERO
๐‘“( ๐‘ฅ) = ( ๐‘ฅ2
+ 7๐‘ฅ + 2) ๐‘ ๐‘’๐‘›(5๐‘ฅ3
+ ๐‘ฅ2
+ 2)3
๐‘“( ๐‘ฅ) = (2๐‘ฅ + 7) ๐‘ ๐‘’๐‘›(5๐‘ฅ3
+ ๐‘ฅ2
+ 2)3
+ ( ๐‘ฅ2
+ 7๐‘ฅ + 2)(15๐‘ฅ2
+ 2๐‘ฅ)3(5๐‘ฅ3
+ ๐‘ฅ2
+ 23
)
๐‘“( ๐‘ฅ) = (2๐‘ฅ + 7) ๐‘ ๐‘’๐‘›(5๐‘ฅ3
+ ๐‘ฅ2
+ 2)3
+ 3(๐‘ฅ2
+ 7๐‘ฅ + 2)( 15๐‘ฅ2
2๐‘ฅ) (5๐‘ฅ3
+ ๐‘ฅ2
+ 2)2
๐‘๐‘œ๐‘ 5๐‘ฅ3
+ ๐‘ฅ2
+ 2)3
SEGUNDO
๐‘“( ๐‘ฅ) = (3๐‘ฅ4
+ 3๐‘ฅ2
+ ๐‘ฅ โˆ’ 2) ๐‘ ๐‘’๐‘›(3๐‘ฅ2
โˆ’ ๐‘ฅ + 4)5
๐‘“( ๐‘ฅ) = (12๐‘ฅ3
+ 6๐‘ฅ + 1) ๐‘ ๐‘’๐‘›(3๐‘ฅ2
โˆ’ ๐‘ฅ + 4)5
+ (3๐‘ฅ4
+ 3๐‘ฅ2
+ ๐‘ฅ โˆ’ 2)5(3๐‘ฅ2
โˆ’ ๐‘ฅ
+ 4)4(6๐‘ฅ โˆ’ 1) ๐‘๐‘œ๐‘ (3๐‘ฅ2
โˆ’ ๐‘ฅ + 4)5
๐‘“( ๐‘ฅ) = (12๐‘ฅ3
+ 6๐‘ฅ + 1) ๐‘ ๐‘’๐‘›(3๐‘ฅ2
โˆ’ ๐‘ฅ + 4)5
+ 5(3๐‘ฅ4
+ 3๐‘ฅ2
+ ๐‘ฅ โˆ’ 2)(3๐‘ฅ2
โˆ’ ๐‘ฅ
+ 4)4(6๐‘ฅ โˆ’ 1) ๐‘๐‘œ๐‘ (3๐‘ฅ2
โˆ’ ๐‘ฅ + 4)5
LIMITES
PRIMERO
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
๐‘ฅ3
= (๐‘™๐‘–๐‘š ๐‘ฅ)3
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
๐‘ฅ3
= (3)3
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
๐‘ฅ3
= ๐Ÿ
SEGUNDO
๐‘™๐‘–๐‘š
๐‘ฅโ†’2
3๐‘ฅ = ๐‘™๐‘–๐‘š
๐‘ฅโ†’2
3๐‘ฅ
๐‘™๐‘–๐‘š
๐‘ฅโ†’2
3๐‘ฅ = 3(2) = ๐Ÿ”
TERCERO
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ โˆ’ 1) ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(2๐‘ฅ โˆ’ 3)
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = ( ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
6๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
1)( ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
2๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
3)
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (6 ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
1)(2 ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
3)
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (6(2)+ 1)(2 โˆ’ 3)
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’2
(6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (13)(1)= 13
CUARTO
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
(4๐‘ฅ โˆ’ 5)2 = (๐‘™๐‘–๐‘š
๐‘ฅโ†’3
4๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’3
5)2
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
(4๐‘ฅ โˆ’ 5)2 = (4 ๐‘™๐‘–๐‘š
๐‘ฅโ†’3
๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’3
5)2
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
(4๐‘ฅ โˆ’ 5)2
= (4(3) โˆ’ 5)2
๐‘™๐‘–๐‘š
๐‘ฅโ†’3
(4๐‘ฅ โˆ’ 5)2
= 72
= ๐Ÿ’๐Ÿ—
QUINTO
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ3
โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
3๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = ( ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ)3
โˆ’ 3 ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = (โˆ’1) โˆ’ 3(โˆ’1) + 2 = ๐Ÿ’
SEXTO
lim
๐‘‹โ†’3
โˆš๐‘ฅ + 13 = โˆšlim
๐‘‹โ†’3
( ๐‘ฅ + 13)
lim
๐‘‹โ†’3
โˆš๐‘ฅ + 13 = lim
๐‘‹โ†’3
โˆšlim
๐‘‹โ†’3
๐‘ฅ + lim
๐‘‹โ†’3
13
lim
๐‘‹โ†’3
โˆš๐‘ฅ + 13 = โˆš3 + 13 = โˆš16 = ๐Ÿ’
SEPTIMO
lim
๐‘‹โ†’7
โˆš ๐‘ฅ + 2
2๐‘ฅ โˆ’ 10
=
lim
๐‘‹โ†’7
โˆš ๐‘ฅ + 2
lim
๐‘‹โ†’7
(2๐‘ฅ โˆ’ 10)
lim
๐‘‹โ†’7
โˆš ๐‘ฅ + 2
2๐‘ฅ โˆ’ 10
=
โˆšlim
๐‘‹โ†’7
๐‘ฅ + lim
๐‘‹โ†’7
2
2 lim
๐‘‹โ†’7
๐‘ฅ โˆ’ lim
๐‘‹โ†’7
10)
lim
๐‘‹โ†’7
โˆš ๐‘ฅ + 2
2๐‘ฅ โˆ’ 10
=
โˆš7 + 2
2(7) โˆ’ 10
lim
๐‘‹โ†’7
โˆš ๐‘ฅ + 2
2๐‘ฅ โˆ’ 10
=
โˆš9
14 โˆ’ 10
=
๐Ÿ‘
๐Ÿ’
OCTAVO
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
๐‘ฅ
=
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
lim
๐‘‹โ†’4
๐‘ฅ
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
๐‘ฅ
=
โˆšlim
๐‘‹โ†’4
(๐‘ฅ2 + 9)
lim
๐‘‹โ†’4
๐‘ฅ
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
๐‘ฅ
=
โˆšlim
๐‘‹โ†’4
๐‘ฅ2 + lim
๐‘‹โ†’4
9
lim
๐‘‹โ†’4
๐‘ฅ
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
๐‘ฅ
=
โˆš(lim
๐‘‹โ†’4
๐‘ฅ)2 + 9
4
lim
๐‘‹โ†’4
โˆš๐‘ฅ2 + 9
๐‘ฅ
=
โˆš 42 + 9
4
=
๐Ÿ“
๐Ÿ’
NOVENO
๐‘™๐‘–๐‘š
๐‘ฅโ†’2
(3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š
๐‘ฅโ†’2
3๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’2
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’2
(3๐‘ฅ + 2) = 3 ๐‘™๐‘–๐‘š
๐‘ฅโ†’2
๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’2
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’2
(3๐‘ฅ + 2) = 3(2) + 2 = ๐Ÿ–
DECIMO
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ3
โˆ’ ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
3๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = ( ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ)3
โˆ’ 3 ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
๐‘ฅ + ๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
2
๐‘™๐‘–๐‘š
๐‘ฅโ†’โˆ’1
(๐‘ฅ3
โˆ’ 3๐‘ฅ + 2) = (โˆ’1)3
โˆ’ 3(โˆ’1)+ 2 = ๐Ÿ’

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guia informatica Guanajuato modulo 22 nuples
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Matematica

  • 1. MATEMATICA PRODUCTOS NOTABLES A) Binomio al cuadrado PRIMERO (โˆš3 x + 2) 2 = (โˆš3 x) 2 + 2(โˆš3 x)(2) + 22 (โˆš3 x + 2) 2 = โˆš3 2 x2 + 4โˆš3 x + 4 (โˆš3 x + 2) 2 = โˆš3 2 x2 + 4โˆš3 x + 4 SEGUNDO (5x + 3y2 z4)2 = (5x)2 + 2(5x)(3y2 z4) + (3y2 z4)2 (5x + 3y2 z4)2 = 25x2 + 30xy2 z4 + 9y4 z8 B) Cuadrado de la diferencia de dos cantidades PRIMERO (x ๐‘Ž+1 โˆ’ x ๐‘Ž+2 )2 = (x ๐‘Ž+1 )2 โˆ’ 2(x ๐‘Ž+1 )(x ๐‘Ž+2 )+ (x ๐‘Ž+2 )2 (x ๐‘Ž+1 โˆ’ x ๐‘Ž+2 )2 = x2๐‘Ž+2 โˆ’ 2x2๐‘Ž+3 + x2๐‘Ž+4 SEGUNDO (4m2 โˆ’ 3n5 )2 = (4m2 )2 โˆ’ 2(4m2 )(3n5 )+ (3n5 )2 (4m2 โˆ’ 3n5 )2 = 16๐‘š4 โˆ’ 24๐‘š2 ๐‘›5 + 9๐‘›10 C) Cubo de una suma PRIMERO (8๐‘ฅ3 + 27๐‘ฆ6 ) = (2x + 3y2 )(4๐‘ฅ2 โˆ’ 6๐‘ฅ๐‘ฆ2 + 9๐‘ฆ4 ) SEGUNDO (512 + 27๐‘ฅ9 ) = (8 + 3๐‘ฅ3 )(64 โˆ’ 24๐‘ฅ3 + 9๐‘ฅ6
  • 2. D) Cubo de una diferencia PRIMERO (273 โˆ’ ๐‘ฆ3 ) = (3x โˆ’ y)(9๐‘ฅ2 + 3๐‘ฅ๐‘ฆ + ๐‘ฆ2 SEGUNDO (๐‘ฅ3 โˆ’ 23 ) = (x โˆ’ 2)(๐‘ฅ2 + 2๐‘ฅ + 22 ) (๐‘ฅ3 โˆ’ 23 ) = (x โˆ’ 2)(๐‘ฅ2 + 2๐‘ฅ + 4) E) Producto de la suma por la diferencia de dos cantidades PRIMERO (๐‘ฅ2 โˆ’ 2x)(๐‘ฅ2 + 2x) = (๐‘ฅ2 )2 โˆ’ (2๐‘ฅ )2 SEGUNDO (๐‘ฅ2 โˆ’ 4)(๐‘ฅ2 + 4) = (๐‘ฅ2 )2 โˆ’ 42 COCIENTES NOTABLES PRIMERO ๐‘ฅ2 โˆ’ 1 ๐‘ฅ + 1 = ๐‘ฅ2 โˆ’ 12 ๐‘ฅ + 1 = ๐‘ฅ โˆ’ 1 SEGUNDO (๐‘ฅ + 1)2 โˆ’ 4๐‘ฆ2 ๐‘ฅ + 1 โˆ’ 2๐‘ฆ = (๐‘ฅ + 1)2 โˆ’ (2๐‘ฆ)2 ( ๐‘ฅ + 1) โˆ’ 2๐‘ฆ = ( ๐‘ฅ + 1) + 2๐‘ฆ TERCERO ๐‘ฅ3 + 8 ๐‘ฅ + 2 = ๐‘ฅ3 + 23 ๐‘ฅ + 2 = ๐‘ฅ2 โˆ’ 2๐‘ฅ + 22 = ๐‘ฅ2 โˆ’ 2๐‘ฅ + 4 CUARTO 125 โˆ’ 64๐‘ฅ6 5 โˆ’ 4๐‘ฅ2 = 53 โˆ’ (4๐‘ฅ2 )3 5 โˆ’ (4๐‘ฅ2) = 25 + 20๐‘ฅ2 + 16๐‘ฅ2
  • 3. DERIVADAS A) DERIVADAS DE UNA FUNCION POTENCIAL PRIMERO ๐‘“( ๐‘ฅ) = (3๐‘ฅ2 + 2)3 (2๐‘ฅ2 + 3๐‘ฅ + 1) ๐‘“( ๐‘ฅ) = 3(3๐‘ฅ2 + 2)2 . 6๐‘ฅ(2๐‘ฅ2 + 3๐‘ฅ + 1) + (3๐‘ฅ2 + 2)3 (4๐‘ฅ + 3) ๐‘“( ๐‘ฅ) = 18๐‘ฅ(3๐‘ฅ2 + 2)2 (2๐‘ฅ2 + 3๐‘ฅ + 1) + (3๐‘ฅ2 + 2)3 (4๐‘ฅ + 3) ๐‘“( ๐‘ฅ) = (3๐‘ฅ2 + 2)2[18๐‘ฅ(2๐‘ฅ2 + 3๐‘ฅ + 1) + (3๐‘ฅ2 + 2)(4๐‘ฅ + 3)] ๐‘“( ๐‘ฅ) = (3๐‘ฅ2 + 2)2 (36๐‘ฅ3 + 54๐‘ฅ2 + 18๐‘ฅ + 12๐‘ฅ3 + 9๐‘ฅ2 + 8๐‘ฅ + 6) ๐’‡( ๐’™) = (๐Ÿ‘๐’™ ๐Ÿ + ๐Ÿ) ๐Ÿ (๐Ÿ’๐Ÿ–๐’™ ๐Ÿ‘ + ๐Ÿ”๐Ÿ‘๐’™ ๐Ÿ + ๐Ÿ๐Ÿ”๐’™ + ๐Ÿ”) SEGUNDO ๐‘“( ๐‘ฅ) = (6๐‘ฅ2 + ๐‘ฅ)2 (๐‘ฅ5 + ๐‘ฅ6 )4 ๐‘“(๐‘ฅ) = 2(6๐‘ฅ2 + ๐‘ฅ)(12๐‘ฅ + 1)(๐‘ฅ5 + ๐‘ฅ6 )4 + (6๐‘ฅ2 + ๐‘ฅ)2 4(๐‘ฅ5 + ๐‘ฅ6 )3 (5๐‘ฅ4 + 6๐‘ฅ5 ) ๐‘“(๐‘ฅ) = 2(6๐‘ฅ2 + ๐‘ฅ) (๐‘ฅ5 + ๐‘ฅ6 )3[(12๐‘ฅ + 1)( ๐‘ฅ5 + ๐‘ฅ6) + 2(6๐‘ฅ2 + ๐‘ฅ)(5๐‘ฅ4 + 6๐‘ฅ5 )] ๐‘“(๐‘ฅ) = 2(6๐‘ฅ2 + ๐‘ฅ) (๐‘ฅ5 + ๐‘ฅ6 )3[12๐‘ฅ6 + 12๐‘ฅ7 + ๐‘ฅ5 + ๐‘ฅ6 + 2(30๐‘ฅ6 + 36๐‘ฅ7 + 5๐‘ฅ5 + 6๐‘ฅ6 )] ๐‘“(๐‘ฅ) = 2(6๐‘ฅ2 + ๐‘ฅ) (๐‘ฅ5 + ๐‘ฅ6 )3[12๐‘ฅ6 + 12๐‘ฅ7 + ๐‘ฅ5 + ๐‘ฅ6 + 60๐‘ฅ6 + 72๐‘ฅ7 + 10๐‘ฅ5 + 12๐‘ฅ6] ๐’‡( ๐’™) = ๐Ÿ(๐Ÿ”๐’™ ๐Ÿ + ๐’™) (๐’™ ๐Ÿ“ + ๐’™ ๐Ÿ” ) ๐Ÿ‘ (๐Ÿ–๐Ÿ’๐’™ ๐Ÿ• + ๐Ÿ–๐Ÿ“๐’™ ๐Ÿ” + ๐Ÿ๐Ÿ๐’™ ๐Ÿ“ ) TERCERO ๐‘“( ๐‘ฅ) = (5๐‘ฅ2 + 7๐‘ฅ + 2)2 ๐‘ฅ2 + 6 = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)(10๐‘ฅ + 7)( ๐‘ฅ2 + 6) โˆ’ (5๐‘ฅ2 + 7๐‘ฅ + 2)2 2๐‘ฅ (๐‘ฅ2 + 6)2 ๐‘“( ๐‘ฅ) = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)2 ๐‘ฅ2 + 6 = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)(10๐‘ฅ + 7)( ๐‘ฅ2 + 6) โˆ’ 2๐‘ฅ(5๐‘ฅ2 + 7๐‘ฅ + 2)2 (๐‘ฅ2 + 6)2 ๐‘“( ๐‘ฅ) = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)2 ๐‘ฅ2 + 6 = [(10๐‘ฅ + 7)( ๐‘ฅ2 + 6) โˆ’ ๐‘ฅ(5๐‘ฅ2 + 7๐‘ฅ + 2)] (๐‘ฅ2 + 6)2 ๐‘“( ๐‘ฅ) = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)2 ๐‘ฅ2 + 6 = [10๐‘ฅ3 + 60๐‘ฅ + 7๐‘ฅ2 + 42 โˆ’ 5๐‘ฅ3 โˆ’ 7๐‘ฅ2 โˆ’ 2๐‘ฅ] (๐‘ฅ2 + 6)2 ๐‘“( ๐‘ฅ) = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)2 ๐‘ฅ2 + 6 = 2(5๐‘ฅ2 + 7๐‘ฅ + 2)2[5๐‘ฅ3 + 58๐‘ฅ + 42] (๐‘ฅ2 + 6)2
  • 4. B) DERIVADAS DE UNA FUNCION LOGARITMICA PRIMERO ๐‘“( ๐‘ฅ) = ( ๐‘ฅ3 + ๐‘ฅ2 + ๐‘ฅ + 5) ๐‘™๐‘›(5๐‘ฅ2 โˆ’ 7) = ๐‘“( ๐‘ฅ) = (3๐‘ฅ2 + 2๐‘ฅ + 1) ๐‘™๐‘›(5๐‘ฅ2 โˆ’ 7) + ( ๐‘ฅ3 + ๐‘ฅ2 + ๐‘ฅ + 5). 10๐‘ฅ 5๐‘ฅ2 โˆ’ 7 = ๐’‡( ๐’™) = ( ๐Ÿ‘๐’™ ๐Ÿ + ๐Ÿ๐’™ + ๐Ÿ) ๐’๐’( ๐Ÿ“๐’™ ๐Ÿ โˆ’ ๐Ÿ•) + ๐Ÿ๐ŸŽ๐’™( ๐’™ ๐Ÿ‘ + ๐’™ ๐Ÿ + ๐’™ + ๐Ÿ“) ๐Ÿ“๐’™ ๐Ÿ โˆ’ ๐Ÿ• SEGUNDO ๐‘“( ๐‘ฅ) = ๐ฟ๐‘›( ๐‘ฅ7 + 7๐‘ฅ3 + 3๐‘ฅ + 1) ๐‘™๐‘›(4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1) = ๐‘“( ๐‘ฅ) = ๐ฟ๐‘›(7๐‘ฅ6 + 21๐‘ฅ2 + 3) ๐‘™๐‘›(4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1) + ( ๐‘ฅ7 + 7๐‘ฅ3 + 3๐‘ฅ + 1). 8๐‘ฅ โˆ’ 3 4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1 ๐‘“( ๐‘ฅ) = (7๐‘ฅ6 + 21๐‘ฅ2 + 3)ln(4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1) + (๐‘ฅ7 + 7๐‘ฅ3 + 3๐‘ฅ + 1)(8๐‘ฅ โˆ’ 3) 4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 1 TERCERO ๐‘“( ๐‘ฅ) = ๐ฟ๐‘› ( 1 โˆš(1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2)23 ) = ๐‘“( ๐‘ฅ) = ๐ฟ๐‘› ( 1 (1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2) 2 3 ) = ๐‘“( ๐‘ฅ) = ๐ฟ๐‘› = (1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2 )โˆ’ 2 3 = โˆ’ 2 3 ln(1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2 ) ๐‘“( ๐‘ฅ) = โˆ’ 2 3 . 2 โˆ’ 10๐‘ฅ 1 + 2๐‘ฅ โˆ’ 5๐‘ฅ2 = โˆ’๐Ÿ(๐Ÿ โˆ’ ๐Ÿ๐ŸŽ๐’™) ๐Ÿ‘(๐Ÿ โˆ’ ๐Ÿ๐’™ โˆ’ ๐Ÿ“๐’™ ๐Ÿ) C) DERIVADAS DE UNA FUNCION EXPONENCIAL PRIMERO ๐‘“( ๐‘ฅ) = (4๐‘ฅ2 + 3)5 3(๐‘ฅ+2) ๐‘“( ๐‘ฅ) = 5(4๐‘ฅ2 + 3)4 8๐‘ฅ3( ๐‘ฅ+2) + (4๐‘ฅ2 + 3)5 3( ๐‘ฅ+2) ln(3) ๐‘“( ๐‘ฅ) = 40๐‘ฅ(4๐‘ฅ2 + 3)4 3( ๐‘ฅ+2) + (4๐‘ฅ2 + 3)5 3( ๐‘ฅ+2) ln(3) ๐‘“( ๐‘ฅ) = (4๐‘ฅ2 + 3)4 [40๐‘ฅ + (4๐‘ฅ2 + 3) ๐‘™๐‘›n(3)]3( ๐‘ฅ+2)
  • 5. SEGUNDO ๐‘“( ๐‘ฅ) = (๐‘ฅ5 + 4๐‘ฅ + 1)3 2(๐‘ฅ3 +5) ๐‘“( ๐‘ฅ) = 3(๐‘ฅ5 +4๐‘ฅ + 1)2(5๐‘ฅ4 + 4)2(๐‘ฅ3 +5) + (๐‘ฅ5 + 4๐‘ฅ + 1)3 2(๐‘ฅ3 +5) 3๐‘ฅ2 ln(2) ๐‘“( ๐‘ฅ) = 3(๐‘ฅ5 +4๐‘ฅ + 1)2(5๐‘ฅ4 + 4)2(๐‘ฅ3 +5) + 3๐‘ฅ2 (๐‘ฅ5 +4๐‘ฅ + 1)3 2(๐‘ฅ3 +5) ln(2) ๐‘“( ๐‘ฅ) = 3(๐‘ฅ5 +4๐‘ฅ + 1)2[(5๐‘ฅ4 + 4)+๐‘ฅ2 (๐‘ฅ5 + 4๐‘ฅ + 1)ln(2)]2(๐‘ฅ3+5) TERCERO ๐‘“( ๐‘ฅ) = (๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)2 7(5๐‘ฅโˆ’3) ๐‘“( ๐‘ฅ) = 2( ๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)(2๐‘ฅ โˆ’ 1)7(5๐‘ฅโˆ’3) + (๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)2 7(5๐‘ฅโˆ’3) 5ln(7) ๐‘“( ๐‘ฅ) = 2( ๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)(2๐‘ฅ โˆ’ 1)7(5๐‘ฅโˆ’3) + 5(๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)2 7(5๐‘ฅโˆ’3) ln(7) ๐‘“( ๐‘ฅ) = ( ๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)[2(2๐‘ฅ โˆ’ 1) + 5(๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3)ln(7)]7(5๐‘ฅโˆ’3) D) Derivada de la funciรณn trigonomรฉtrica de Seno PRIMERO ๐‘“( ๐‘ฅ) = ( ๐‘ฅ2 + 7๐‘ฅ + 2) ๐‘ ๐‘’๐‘›(5๐‘ฅ3 + ๐‘ฅ2 + 2)3 ๐‘“( ๐‘ฅ) = (2๐‘ฅ + 7) ๐‘ ๐‘’๐‘›(5๐‘ฅ3 + ๐‘ฅ2 + 2)3 + ( ๐‘ฅ2 + 7๐‘ฅ + 2)(15๐‘ฅ2 + 2๐‘ฅ)3(5๐‘ฅ3 + ๐‘ฅ2 + 23 ) ๐‘“( ๐‘ฅ) = (2๐‘ฅ + 7) ๐‘ ๐‘’๐‘›(5๐‘ฅ3 + ๐‘ฅ2 + 2)3 + 3(๐‘ฅ2 + 7๐‘ฅ + 2)( 15๐‘ฅ2 2๐‘ฅ) (5๐‘ฅ3 + ๐‘ฅ2 + 2)2 ๐‘๐‘œ๐‘ 5๐‘ฅ3 + ๐‘ฅ2 + 2)3 SEGUNDO ๐‘“( ๐‘ฅ) = (3๐‘ฅ4 + 3๐‘ฅ2 + ๐‘ฅ โˆ’ 2) ๐‘ ๐‘’๐‘›(3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)5 ๐‘“( ๐‘ฅ) = (12๐‘ฅ3 + 6๐‘ฅ + 1) ๐‘ ๐‘’๐‘›(3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)5 + (3๐‘ฅ4 + 3๐‘ฅ2 + ๐‘ฅ โˆ’ 2)5(3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)4(6๐‘ฅ โˆ’ 1) ๐‘๐‘œ๐‘ (3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)5 ๐‘“( ๐‘ฅ) = (12๐‘ฅ3 + 6๐‘ฅ + 1) ๐‘ ๐‘’๐‘›(3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)5 + 5(3๐‘ฅ4 + 3๐‘ฅ2 + ๐‘ฅ โˆ’ 2)(3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)4(6๐‘ฅ โˆ’ 1) ๐‘๐‘œ๐‘ (3๐‘ฅ2 โˆ’ ๐‘ฅ + 4)5 LIMITES PRIMERO ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 ๐‘ฅ3 = (๐‘™๐‘–๐‘š ๐‘ฅ)3 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 ๐‘ฅ3 = (3)3 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 ๐‘ฅ3 = ๐Ÿ
  • 6. SEGUNDO ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 3๐‘ฅ = ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 3๐‘ฅ ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 3๐‘ฅ = 3(2) = ๐Ÿ” TERCERO ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ โˆ’ 1) ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (2๐‘ฅ โˆ’ 3) ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = ( ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 6๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 1)( ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 2๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 3) ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (6 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 ๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 1)(2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 ๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 3) ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (6(2)+ 1)(2 โˆ’ 3) ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’2 (6๐‘ฅ + 1)(2๐‘ฅ โˆ’ 3) = (13)(1)= 13 CUARTO ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 (4๐‘ฅ โˆ’ 5)2 = (๐‘™๐‘–๐‘š ๐‘ฅโ†’3 4๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 5)2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 (4๐‘ฅ โˆ’ 5)2 = (4 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 ๐‘ฅ โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 5)2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 (4๐‘ฅ โˆ’ 5)2 = (4(3) โˆ’ 5)2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’3 (4๐‘ฅ โˆ’ 5)2 = 72 = ๐Ÿ’๐Ÿ— QUINTO ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ3 โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 3๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = ( ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ)3 โˆ’ 3 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = (โˆ’1) โˆ’ 3(โˆ’1) + 2 = ๐Ÿ’
  • 7. SEXTO lim ๐‘‹โ†’3 โˆš๐‘ฅ + 13 = โˆšlim ๐‘‹โ†’3 ( ๐‘ฅ + 13) lim ๐‘‹โ†’3 โˆš๐‘ฅ + 13 = lim ๐‘‹โ†’3 โˆšlim ๐‘‹โ†’3 ๐‘ฅ + lim ๐‘‹โ†’3 13 lim ๐‘‹โ†’3 โˆš๐‘ฅ + 13 = โˆš3 + 13 = โˆš16 = ๐Ÿ’ SEPTIMO lim ๐‘‹โ†’7 โˆš ๐‘ฅ + 2 2๐‘ฅ โˆ’ 10 = lim ๐‘‹โ†’7 โˆš ๐‘ฅ + 2 lim ๐‘‹โ†’7 (2๐‘ฅ โˆ’ 10) lim ๐‘‹โ†’7 โˆš ๐‘ฅ + 2 2๐‘ฅ โˆ’ 10 = โˆšlim ๐‘‹โ†’7 ๐‘ฅ + lim ๐‘‹โ†’7 2 2 lim ๐‘‹โ†’7 ๐‘ฅ โˆ’ lim ๐‘‹โ†’7 10) lim ๐‘‹โ†’7 โˆš ๐‘ฅ + 2 2๐‘ฅ โˆ’ 10 = โˆš7 + 2 2(7) โˆ’ 10 lim ๐‘‹โ†’7 โˆš ๐‘ฅ + 2 2๐‘ฅ โˆ’ 10 = โˆš9 14 โˆ’ 10 = ๐Ÿ‘ ๐Ÿ’ OCTAVO lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 ๐‘ฅ = lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 lim ๐‘‹โ†’4 ๐‘ฅ lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 ๐‘ฅ = โˆšlim ๐‘‹โ†’4 (๐‘ฅ2 + 9) lim ๐‘‹โ†’4 ๐‘ฅ lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 ๐‘ฅ = โˆšlim ๐‘‹โ†’4 ๐‘ฅ2 + lim ๐‘‹โ†’4 9 lim ๐‘‹โ†’4 ๐‘ฅ lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 ๐‘ฅ = โˆš(lim ๐‘‹โ†’4 ๐‘ฅ)2 + 9 4 lim ๐‘‹โ†’4 โˆš๐‘ฅ2 + 9 ๐‘ฅ = โˆš 42 + 9 4 = ๐Ÿ“ ๐Ÿ’
  • 8. NOVENO ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 (3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 3๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 (3๐‘ฅ + 2) = 3 ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 ๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’2 (3๐‘ฅ + 2) = 3(2) + 2 = ๐Ÿ– DECIMO ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ3 โˆ’ ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 3๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = ( ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ)3 โˆ’ 3 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 ๐‘ฅ + ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 2 ๐‘™๐‘–๐‘š ๐‘ฅโ†’โˆ’1 (๐‘ฅ3 โˆ’ 3๐‘ฅ + 2) = (โˆ’1)3 โˆ’ 3(โˆ’1)+ 2 = ๐Ÿ’