This document contains 26 multiple choice questions about Java programming concepts like keywords, variables, data types, operators, control flow etc. Each question is followed by 4-5 answer options and an explanation of the correct answer. The questions test knowledge of basic Java syntax, semantics and language features.

1. JAVA Quiz

2. 1. Which one of these lists contains
only Java programming language
keywords?
 A class, if, void, long, Int, continue
 B goto, instanceof, native, finally, default, throws
 C try, virtual, throw, final, volatile, transient
 D strictfp, constant, super, implements, do
 E byte, break, assert, switch, include

3.  Answer: B
 Explanation:
 All the words in option B are among the 49 Java
keywords. Although goto reserved as a keyword in
Java, goto is not used and has no function.
 Option A is wrong because the keyword for the
primitive int starts with a lowercase i.
 Option C is wrong because "virtual" is a keyword in
C++, but not Java.
 Option D is wrong because "constant" is not a
keyword. Constants in Java are
marked static and final.
 Option E is wrong because "include" is a keyword in
C, but not in Java.

4. 2. A _________ is a basic unit of
storage in Java.
 A. Identifier
 B. Variable
 C. Constant
 D. Memory

5.  Answer : B
 Explanation
A variable is the basic unit of storage in java.
All the constants of any of the data types are
stored in a variable.

6. 3. What is the default data type
of a decimal number in Java?
 A. int
 B. float
 C. double
 D. long

7. Answer : C

8. 4. What would be the output of the
following program?
class AutoConv2
{
public static void main(String args[])
{
int i=257;
byte b=(byte)i;
System.out.println("b= "+b);
}
}
 A. b= 1
 B. b= -128
 C. Compilation Error
 D. None of the Above

9.  Answer : A
 Explanation
If the value that is being assigned (Let it be N)
is larger than the range of the target integer
type , the value that is actually assigned is
 N%(Range ofTarget Datatype)
 In the Above Question
 The value assigned to "b" is 257 % 256 = 1.

10. 5. What would be the output of the
following program?
class Scope1
{
public static void main(String args[])
{
int i=10;
System.out.println(i);
if (i==10)
{
int i=20;
System.out.println(i);
}
System.out.println(i);
}
}
 A. 10 20 10
 B. 10 20 20
 C. 10 10 10
 D. Compilation Error

11.  Answer : D
 Explanation
Be careful! In Java you can not define the
same variabe twice.

12. 6. What would be the output of the
following program?
class Scope2
{
public static void main(String args[])
{
int i=10;
System.out.println("i="+i);
if (i==10)
{
int j=20;
i=20;
System.out.println("i="+i+" , j="+ j);
}
System.out.println("i="+i+" , j="+ j);
}
}

13.  A. i=10
i=20, j=20
i=20, j=20
 B. i=10
i=10,j=20
 C. Compilation Error
 D. None of the Above

14.  Answer : C
 Explanation
The variable j is local to the "if" block and
hence is not visible outside it.
 Hence when we try to use it later while
printing, the compiler reports that it is unable
to find the symbol j.

15. 7. What would be the output of the following program?
class Scope3
{
public static void main(String args[])
{
for (int i=1;i<=3 ;i++ )
{
int y=1;
System.out.println("i="+i+" y="+y);
y++;
}
}
} A. i=1 y=1
i=2 y=2
i=3 y=3
 B. i=1 y=1
i=2 y=1
i=3 y=1
 C. i=1 y=1
i=1 y=1
i=1 y=1
 D.Compilation Error

16.  Answer : B
 Explanation
The declaration of variable y is inside the for
loop and is executed every time the control
enters the loop thus, re-initializing it to 1
everytime.
 So,Y remains 1 across all the 3 iterations.
 A variable declared inside a block is lost
every time the control goes out of the
scope thus the y declared here is created
afresh and discarded at the end of every
iteration.

17. 8. Which will legally declare,
construct, and initialize an
array?
 A int [] myList = {"1", "2", "3"};
 B int [] myList = (5, 8, 2);
 C int myList [] [] = {4,9,7,0};
 D int myList [] = {4, 3, 7};

18.  Answer: D
 Explanation:
 The only legal array declaration and assignment
statement is Option D
 Option A is wrong because it initializes an int
array with String literals.
 Option B is wrong because it use something
other than curly braces for the initialization.
 Option C is wrong because it provides initial
values for only one dimension, although the
declared array is a two-dimensional array.

19. 9. Which is a reserved word in the Java
programming language?
 A method
 B native
 C subclasses
 D reference
 E array

20.  Answer: B
 Explanation:
 The word "native" is a valid keyword, used to
modify a method declaration.
 Option A, D and E are not keywords. Option C
is wrong because the keyword for subclassing
in Java is extends, not 'subclasses'.

21. 10. Which is a valid keyword in java?
 A interface
 B string
 C Float
 D unsigned

22.  Answer: A
 Explanation:
 interface is a valid keyword.
 Option B is wrong because although "String"
is a class type in Java, "string" is not a
keyword.
 Option C is wrong because "Float" is a class
type.The keyword for the Java primitive
is float.
 Option D is wrong because "unsigned" is a
keyword in C/C++ but not in Java.

23. 11. Which one is a valid declaration of
a boolean?
 A boolean b1 = 0;
 B boolean b2 = 'false';
 C boolean b3 = false;
 D boolean b4 = Boolean.false();
 E boolean b5 = no;

24.  Answer: C
 Explanation:
 A boolean can only be assigned the
literal true or false.

25. 12. What is the output of the following program?
class Operators1
{
public static void main(String[] args)
{
int a=10, b=0;
if( a > 10 && a/b == 10)
System.out.println("Inside the If Condition!");
System.out.println("Outside the If Condition!");
}
}
 A. Inside the If Condtion!
Outside the If Condition!
 B. Outside the If Condition!
 C. RunTime Error
 D. CompileTime Error

26.  Answer : B
 Explanation
Here a>10 is False and so "a/b == 10" is never
executed. So no error occurs.
This happens due to short circuiting of relational
operators.
In case of && ( Logical AND operator)
exp1 && exp2
Here if exp1 is False then exp2 is not evaluated as
the compiler already knows that even if the exp2 is
True the result will still be False i.e.
False &&True = False.
So it does not waste time on evaluating the second
expression exp2.

27. 13. What is the output of the following program?
class ModulusOperators1
{
public static void main(String[] args)
{
float f=7.5f;
System.out.println("7.5 % 2 ="+ f%2);
}
}
 A. 1
 B. Compilation Error: Modulus operator can not be applied
on Floating Point Numbers
 C. 1.5
 D. None of the Above

28.  Answer : C
 Explanation
Java supports modulus operators on
Floating Point Numbers too.This is opposite
to C Language where you can not apply
Modulus operator on Floating Point
Numbers.

29. 14. What is the output of the following program?
class Operators1
{
public static void main(String[] args)
{
int i=0;
System.out.println("i--="+i--+" , --i="+ --i);
}
}
 A. i-- = 0, --i=-2
 B. i-- = -1, --i= -1
 C. i-- = -1, --i =-2
 D. None of the Above

30.  Answer : A
 Explanation
Since, in the case of post decrement, the
decremented value becomes available only in
the next use, the first i-- prints the current
value i.e. 0 and the value of i becomes -1,
when --i is encountered later the current
value of i was -1 and it is decremented again
and i becomes -2 Hence -2 is printed.

31. 15. What is the output of the following program?
class ModulusOperators1
{
public static void main(String[] args)
{
System.out.println("-8%3="+ -8%3);
System.out.println("10%-3="+ 10%-3);
System.out.println("-7%-3="+ -7%-3);
}
}
 A. 2 -1 -1
 B. -2 -1 1
 C. -2 1 -1
 D. -2 1 1

32.  Answer : C
 Explanation
The sign of remainder is always same as the
sign of the dividend in Java.

33. 16. What is the output of the following program?
class Operators1
{
public static void main(String[] args)
{
int i=5,j;
j=i++ + ++i;
System.out.println("i="+i);
System.out.println("j="+j);
}
}
 A. i=5
j=10
 B. i=6
j=12
 C. i=7
j=12
 D. i=7
j=11

34.  Answer : C
 Explanation
Since, i is incremented twice in the
statement, i =7
 j= 12 = 5 + 7

35. 17. What is the output of thefollowing program?
class Operators1
{
public static void main(String[] args)
{
double x=6;
int y=5,z=2;
x= y++ + ++x/z;
System.out.println(x);
}
}
 A. 9
 B. 8
 C. 8.5
 D. None of the Above

36.  Answer : C
 Explanation
++ has higher precedence than division. So,
++x is executed first and then division is
performed.
 x= 5+ 7/2 = 5 + 3.5= 8.5

37. 18. What is the output of the following program?
class Operators1
{
public static void main(String[] args)
{
int x =5;
x *= 2 +5;
System.out.println(x);
}
}
 A.15
 B.35
 C.Compilation Error
 D.None of the Above

38.  Answer : B
 Explanation
x*=2+5
 => x=x*(2+5)
 => x=5 * (7)
 x=35

39. 19. What is the output of the following program?
class IfExample
{
public static void main(String[] args)
{
int var1=10;
if (var1 < 10);
System.out.println("Inside If Condition");
else if (var1==10)
{
System.out.println("Inside Else If Condition");
}
else
System.out.println("Inside Else Condition");
}
}
 A. Inside Else If Condition
 B. Inside If Condition
Inside Else If Condition
 C. Compilation Error
 D. None of the Above

40.  Answer : C
 ExplanationNotice the semi-colon at the end
of "if condition"!This ends the "empty if
block" . Since the print statement is placed
after it, it causes the "else if" wo be without
an "if".
 Note: "else if" should immediately follow
either an "if" or an "else if".

41. 20. What is the output of the following program?
class SwitchControl
{
public static void main(String[] args)
{
int i=10;
switch(i)
{
case 5 : System.out.println("Case 5!");
case 10 : System.out.println("Case 10!");
case 20 : System.out.println("Case 20!");
default : System.out.println("Default Case!");
break;
}
}
}

42.  A.Case 10!
 B.Case 5!
Case 10!
Case 20!
Default Case!
 C.Case 10!
Case 20!
Default Case!
 D.Compilation Error

43.  Answer : C
 Explanation
This is called switch Fall-Through. All the
cases after the matching case are executed in
sequence until a break is found or the end of
switch block is encountered.

44. 21. What is the output of the following program?
class IfExample
{
public static void main(String[] args)
{
int var1=10;
if (var1 = 20)
{
System.out.println("Inside If Condition");
System.out.println("var1= "+var1);
}
}
}
 A.Inside If Condition
var1= 20
 B.Inside If Condition
var1= 10
 C.Compilation Error
 D.Runtime Error

45.  Answer : C
 Explanation
var1=20 evaluates to 20 which is an integer
value , but the condition has to be a boolean
value. So, we get Compilation Error.

46. 22. What is the output of the following program?
public class ForLoop
{
public static void main(String[] args)
{
int i=0;
for(;i<4;)
{
System.out.println("i="+i);
}
}
}
 A.Compilation Error
 B.RunTime Error
 C.Infinite Loop
 D.None of the Above

47.  Answer : C
 Explanation
If you eliminate the iteration part from the for
loop, do not forget to manually increment the
counter variable inside the body.

48. 23. What is the output of the following program?
public class ForLoop
{
public static void main(String[] args)
{
int i=0;
for(;i<4;)
{
i++;
System.out.print("i="+i+” “);
}
}
}
 A. i=0 i=1 i=2 i=3
 B. i=1 i=2 i=3 i=4
 C.Compilation Error
 D.None of the Above

49.  Answer : B
 ExplanationIf the condition is true, then i is
first incremented and then printed, So in the
first iteration when i=0, i is incremented and
i=1 is printed.
 So,
 i=1 i=2 i=3 i=4

50. 24. What is the output of the following program?
class BreakClass
{
public static void main(String[] args)
{
for(int i=0;i<5;i++)
{
if(i==2)
{
break;
}
System.out.print("i="+i+” “);
}
}
}
 A. i=0 i=1
 B. i=0 i=1 i=2 i=3 i=4
 C. i=0 i=1 i=3 i=4
 D.None of the Above.

51.  Answer : A
 Explanation
As soon as a break is encountered the loop is
terminated.

52. 25. What is the output of the following program?
public class InfiniteLoop
{
public static void main(String[] args)
{
while(1)
System.out.println("Inside Infinite Loop");
}
}
 A. Results in an Infinite Loop
 B. Compilation Error
 C. Inside Infinite Loop
 D. None of the above

53.  Answer : B
 Explanation
The condition can only be a boolean
expression.

54. 26. What is the output of the following program?
class BreakClass
{
public static void main(String[] args)
{
for(int i=0;i<2;i++)
{
for(int j=0;j<2;j++)
{
if (j==1)
break;
System.out.println("i="+i+", j="+j);
}
}
}
}

55.  A. i=0, j=0
i=0, j=1
i=1, j=0
i=1, j=1
 B. i=0, j=0
i=1, j=0
 C. i=0, j=0
 D. None of the Above

56.  Answer : B
 Explanation
The break inside the inner loop only
interrupts the inner loop.

57. 27. What is the output of the following program?
public class ForLoop
{
public static void main(String[] args)
{
for(int i=0;i<2;i++)
{
inner: for(int j=0;j<3;j++)
{
if (j==2)
break outer;
System.out.println("i="+i+", j="+j);
}
System.out.println("Outside the inner loop");
}
outer: System.out.println("Outside the outer loop");
}
}

58.  A. i=0, j=0
i=0, j=1
i=0, j=2
i=1, j=0
i=1, j=1
i=1, j=2
 B. i=0, j=0
i=0, j=1
Outside the outer loop
 C. Compilation Error
 D. None of the Above

59.  Answer : C
 Explanation
A break can only be used with an enclosing label

60. 28. What is the output of the following program?
public class ForLoop
{
public static void main(String[] args)
{
for(int i=0;i<5;)
{
if (i==2)
continue;
System.out.print("i="+i+” “);
i++;
}
}
}
 A. i=0 i=1 i=2 i=3 i=4
 B. i=0 i=1 i=3 i=4
 C.Compilation Error
 D.None of the Above

61.  Answer : D
 Explanation
 Infinite Loop!The continue will skip the i++
inside the body of the loop and thus the value of
i will always remain 2 !

62. 29. What is the output of the following program?
public class ForLoop
{
public static void main(String[] args)
{
outer: for(int i=0;i<5;i++)
{
inner: for(int j=0;j<5;j++)
{
if (j==2)
break outer;
System.out.println("i="+i+", j="+j);
}
System.out.println("Outside the inner loop");
}
System.out.println("Outside the outer loop");
}
}

63.  A. i=0, j=0
i=0, j=1
Outside the inner loop
Outside the outer loop
 B. i=0, j=0
i=0, j=1
Outside the outer loop
 C. Compilation Error
 D. None of the Above

64.  Answer : B
 Explanation
This is a form of goto in Java using the break
statement.
When break is used with a label, the control
comes out of the block identified by the label.

65. 30.What is the output of the following program?
class ByteSize
{
public static void main(String[] args)
{
byte b=127;
System.out.println(b+1);
}
}
 A.128
 B.-127
 C.Compilation Error
 D.None of the Above

66.  Answer is : A
 Explanation
The answer is 128 add 1 to b's value i.e. 127 +
1 = 128.

67. 31.What is the output of following code?
Class Loop
{
public static void main(String arg[])
{
int b=0;
do
{
int a=2;
b++;
System.out.print(a++);
}while(b!=3);
}
}
 A. 222
 B. 234
 C. 345
 D. Compilation error

68.  Answer :A
 Explanation:
Variable a is declared every time the loop is
run.

69. 32. What is the output of the following program?
Class Loop
{
public static void main(String arg[])
{
int i=0;
for(;i<4;i++)
{
System.out.print(i<2+” “);
}
}
}
 A. 0 1
 B. true true false false
 C. Compilation error
 D. None of these

70. Answer : B
Explanation:
This program will compare the value of i and
return true or false accordingly.

71. 33. What is the output of the following program?
Class Loop
{
public static void main(String arg[])
{
for(int a=0,int b=0;a+b<5;a++,b++)
{
System.out.print(a^b+” “); //Ex-or
}
}
}
 A. 0 0 0
 B. 1 1 1
 C. 1 0 1
 D. Compilation error

72.  Answer :A

73. 34. What is the width and range of int in java?
 A. 32 bits | -2,147,483,648 to 2,147,483,647
 B. 32 bits | 0 to 4294967296
 C. 16 bits | -32768 to 32767
 D. Compiler Dependent

74.  Answer : A
 Explanation
Remember, All integers in java are
signed, Java does not support unsigned int ,
unsigned short , unsigned byte
The rang can by found by the following
Formula : -2^(n-1) to 2^(n-1) -1

75. 35. What would be the output of the following
program?
class CharRange
{
public static void main(String[] args)
{
char ch=88;
System.out.println(ch+" = " +(int)ch);
ch=ch+1;
System.out.println(ch+" = " +(int)ch);
}
}
 A.X=88
Y=99
 B.X=88
X=88
 C.Compiler Error
 D.None of the Above

76.  Answer : C
 Explanation
We can not write ch= ch+1; as addition
operator expects int type as its operands.
We can instead write:
ch++;

77. 36. What would be the output of the following program?
class OctalPrgm
{
public static void main(String[] args)
{
int i=08;
System.out.println(i+1);
}
}
 A.9
 B.09
 C.00
 D.Compilation Error

78.  Answer : D
 Explanation
The range of an octal number is from 0 to 7.

79. 37. What would be the output of the following program?
class OctalPrgm
{
public static void main(String[] args)
{
int i=07;
System.out.println(++i);
i=i+1;
System.out.println(++i);
}
}
 A. 00
01
 B. 8
9
 C. 8
10
 D. Compilation Error

80.  Answer : C
 Explanation
i=07 since the decimal value of octal 07 is 7 , 7
is assigned to i and thus the value 8 and 10 is
printed.
8
10

81. Thanks