Independent Assortment Two genes Dumb d and Anxious a .pdf
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Independent Assortment Two genes, Dumb (d) and Anxious (a), are recessive genes routinely found in offspring. Previous research has determined that they reside on different chromosomes. F1 male and female are mated and their F2 offspring are scored for dumbness and anxiety. Complete the Punnett square for the F2. Show the Phenotype, Genotype, and expected ratio for the F2 below or to the side of the Punnett square. a. What % of the F2 offspring would you expect that are dumb but not anxious? b. What % of the F2 offspring would you expect that are anxious but not dumb? c. What % of the F2 offspring would you expect that are dumb and anxious? d. If your goal is to not have offspring that are dumb or anxious, what % of the F 2 could be mated in the F3 ?.
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Insert a function in cell D11 to display the ltem name based.pdf
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#include <stdlib.h>
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int drawnnumber(int bingocard[5][5], int called[3]);
void completedrowcolumn(int bingocard[5][5], int win);
int main(void)
{
//array of bingo numbers
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int col = 5;
int bingocard[row][col];
int called[3];
int counter = 0;
int callednumber[75];
char yn[1];
int win = 0;
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called[3] = PickNumber(called, callednumber, counter);
for(int i = 0; i < 75; i++)
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callednumber[i] = 0;
}
callednumber[counter] = called[1];
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while(counter < 75)
{
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int PickNumber(int called[3], int callednumber[75], int counter);
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/************************************************************/
template<typename T>
struct ListNode
{
ListNode () : data ()
{
}
ListNode (const T& v) : data (v)
{
}
ListNode (const T& v, ListNode* n, ListNode* p) : data (v), next (n), prev (p)
{
}
// unhooks the range [begin,end] from a linked list
// NOTE: will lose reference to begin and end if you
// are not keeping track of it!
//
// - does not create any new nodes
// - does not destroy any existing nodes
// - begin is start of range to remove
// - end is inclusive end of range to remove
//
// [5]
static void
unhook_range (ListNode* begin, ListNode* end)
{
// TODO
}
// inserts the range [first,last] before this
// NOTE: does not create any new nodes, does not destroy any existing nodes
//
// [5]
void
hook_range (ListNode* first, ListNode* last)
{
// TODO
}
// insert first before this
void
hook (ListNode* first)
{
hook_range (first, first);
}
// unhooks current node from linked list
void
unhook ()
{
ListNode::unhook_range (this, this);
}
T data;
ListNode* next{nullptr};
ListNode* prev{nullptr};
};
Please complete the implementation of the missing part marked TODO.
// node insertion/removal [5] static Node:: unhook_range (Node* first, Node* last) [3] When first ==
last (single element) [2] When first != last [5] Node: :hook_range (Node* first, Node* last) [3] When
first != last [2] When first == last (single element).
In your opinion What would drive your decisions If you wer.pdf
In your opinion?
What would drive your decisions?
If you were deciding to invest in a company how would you use their financial statements in your
decision making process? What specific information would you review? What would you be trying
to determine?
What criteria would you use to decide whether or not to make the investment?
In addition to the financial statements what other information would you need to make your
decision or what other information would be helpful?
If you were ranking the financial statement in importance how would you rank them and why?.
Income statement for 2016 Sales are expected to increase by .pdf
Income statement for 2016
Sales are expected to increase by 10% in 2017, while costs including depreciation are expected to
reach 60% of sales. Interest expenses and the average tax rate are expected to stay constant
(in $) 2016
Sales 360,000
Costs (incl. depr.) 252,000
EBIT 108,000
Interest 25,000
Taxes (28%) 23,240
Net income 59,760.
Indicate in the figure below the location of the Stratosphe.pdf
Indicate in the figure below the location of the: Stratosphere, Tropopause, Troposphere, Boundary
layer, Surface layer
Please use locations that are appropriate for this sounding, do not use values from the USSA. You
only need to do this for the daytime sounding. You can provide the answers to this question either
in a table or by (somehow) importing the image in your document and annotating it.
Geopotential height asl (km) Altitude asl (km).
Independent ttest Dependentpaired ttest Oneway ANOVA Two.pdf
Independent t-test
Dependent/paired t-test
One-way ANOVA
Two-way ANOVA
Repeated Measures ANOVA
ANCOVA
A researcher was interested in the effects of journal therapy on depression. Sixty individuals
diagnosed with severe depression were randomly assigned to three different treatment groups (20
individuals in each group). The first group received journal therapy (writing about their feelings for
an hour each day for three weeks) and regular counseling, the second group received only journal
therapy, and the third group received only regular counseling. All sixty individuals were given a
depression scale before (baseline) and after treatment. Assume the assumptions of the parametric
method were satisfied. Do depression scores after the intervention differ among the three groups,
controlling for or removing the effect of the baseline depression score?.
incubation limes that rimake up the middle 97 Cick the icon.pdf
incubation limes that rimake up the middle 97% Cick the icon to view a table of areas under the
normal curve. The incubation times that make up the middle 97% are 10 days. (Round to the
nearest whole number ass needed. Use ascending order.).
ind the area of the shaded region The graph to the right de.pdf
ind the area of the shaded region. The graph to the right depicts 1Q scores of adults, and those
scores are normally listributed with a mean of 100 and a slandard deviation of 15 . The atea of the
shaded region is (fround to four decimal placos as mooded).
increase in the demand for loanable funds could be best expl.pdf
increase in the demand for loanable funds could be best explained by which of the following? (A)
There is a decrease in investment spending. (B) There is an increase in the government's budget
surplus. (C) Firms are optimistic about the future performance of the country's economy. (D)
Domestic investors seek higher returns by investing in foreign financial assets. (E) The economy is
facing political instability..
Increase the proportion of aduits who get recommended eviden.pdf
Increase the proportion of aduits who get recommended evidence-based preventive healthcare
(AHS-08) Increase the number of community organizations that provide prevention services
(ECBP-D07) Reduce the proportion of people who can't get prescription medicines when they
need them (AHS-06) Increase the proportion of people with a usual primary care provider (AHS-
07) Increase the proportion of people with prescription drug insurance (AHS-03)For each
healthcare access and quality-related objective, identify if the objective is a core, research, or
developmental objective..
In your team research how you can improve communications in.pdf
In your team, research how you can improve communications in global teams. Provide the results
of your research in a not-to-exceed two-page double-spaced paper. Include in your discussion, as
a minimum: (a) How managing communications in agile is different? (b) What are the best
practices for improving communication in global teams?.
increase by 3 per year thereafter If Tolo has 21 million .pdf
increase by 3% per year thereafter. If Tolo has 2.1 million shares outstanding and an equity cost of
capital of 11.1%, what is its price per share today? The stock price will be $ (Round to the nearest
cent.).
include ltstdiohgt include ltstringhgt define M.pdf
#include <stdio.h>
#include <string.h>
#define MAX_USERS 100
struct user {
char username[20];
char password[20];
char codeword[20];
};
int num_users = 0;
struct user users[MAX_USERS];
int find_user_index(char *username) {
for (int i = 0; i < num_users; i++) {
if (strcmp(users[i].username, username) == 0) {
return i;
}
}
return -1;
}
void add_user() {
if (num_users == MAX_USERS) {
printf("Error: maximum number of users reachedn");
return;
}
struct user u;
printf("Enter username: ");
scanf("%s", u.username);
printf("Enter password: ");
scanf("%s", u.password);
printf("Enter codeword: ");
scanf("%s", u.codeword);
users[num_users++] = u;
}
void edit_user() {
char username[20];
printf("Enter username to edit: ");
scanf("%s", username);
int i = find_user_index(username);
if (i == -1) {
printf("Error: user not foundn");
return;
}
struct user u = users[i];
printf("Enter new password (or press enter to keep current password): ");
scanf("%s", u.password);
printf("Enter new codeword (or press enter to keep current codeword): ");
scanf("%s", u.codeword);
users[i] = u;
}
void display_users() {
printf("%-20s %-20s %-20sn", "Username", "Password", "Codeword");
for (int i = 0; i < num_users; i++) {
printf("%-20s %-20s %-20sn", users[i].username, users[i].password, users[i].codeword);
}
}
void remove_user() {
char username[20];
printf("Enter username to remove: ");
scanf("%s", username);
int i = find_user_index(username);
if (i == -1) {
printf("Error: user not foundn");
return;
}
for (int j = i; j < num_users - 1; j++) {
users[j] = users[j + 1];
}
num_users--;
}
int main() {
int choice;
while (1) {
printf("n");
printf("1. Add usern");
printf("2. Edit usern");
printf("3. Display usersn");
printf("4. Remove usern");
printf("5. Exitn");
printf("Enter choice: ");
scanf("%d", &choice);
switch (choice) {
case 1:
add_user();
break;
case 2:
edit_user();
break;
case 3:
display_users();
break;
case 4:
remove_user();
break;
case 5:
return 0;
default:
printf("Error: invalid choicen");
}
}
}
Based on the code above, provide the necessary comments in the code..
include ltiostreamgt include ltfstreamgt in.pdf
#include <iostream>
#include <fstream>
#include <sstream>
#include <vector>
#include <string>
using namespace std;
/* A binary tree node has data,pointer to left child and apointer to right child */
struct Node
{
int data;
Node* left, * right;
};
/*Function for creating a new Node structure */
Node* newNode(int data)
{
Node* node = new Node;
//Node* node = (Node*)malloc(sizeof(Node)); //will also work.
node->data = data;
node->left = node->right = NULL;
return (node);
}
// Function to insert nodes in level order. This function takes an array-based treerepresentation as
inputand
// convert it into a linked list-based tree representationNode* insertLevelOrder(vector<int>
tree_vec,
//tree_vec: array implementation,
create node for position i.
int i, int n)
{
Node* root = nullptr;
// Base case for recursion
if (i < n)
{
root = newNode(tree_vec[i]);
// insert left child
root->left = insertLevelOrder(tree_vec,
2 * i + 1, n);
// insert right child
root->right = insertLevelOrder(tree_vec,
2 * i + 2, n);
}
return root;
}
// Example code for InOrder traversal
void inOrder(Node * root)
{
if (root != NULL)
{
inOrder(root->left);
cout << root->data << " ";
inOrder(root->right);
}
}
int main()
{
vector<int> tree_vec;
string file_name;
int temp_data;
cout << "Please input the file name of a complete binary tree:";
cin >> file_name;
ifstream tree_file(file_name, ios::in);
if (tree_file.fail())
{
cout << "Fail to open the tree file.";
return 0;
}
while (!tree_file.fail() && !tree_file.eof())
{
tree_file >> temp_data;
tree_vec.push_back(temp_data);
}
/*Transform the array-based tree into linked-list in level-order.*/
Node* root = insertLevelOrder(tree_vec, 0, tree_vec.size());
/*Task 1, to be implemented*/
cout << "The Preorder Traversal result is: " << endl;
/*Example implementation*/
cout << "The Inorder Traversal result is: " << endl;
inOrder(root);
/*Task 2, to be implemented*/
cout << "The Postorder Traversal result is: " << endl;
/*Task 3, to be implemented*/
cout << "The number of leaf nodes is: " << endl;
return 0;
}
please help me to finish the code with the task using c++
#include <iostream>
#include <fstream>
#include <sstream>
#include <vector>
#include <string>
using namespace std;
/* A binary tree node has data,pointer to left child and apointer to right child */
struct Node
{
int data;
Node* left, * right;
};
/*Function for creating a new Node structure */
Node* newNode(int data)
{
Node* node = new Node;
//Node* node = (Node*)malloc(sizeof(Node)); //will also work.
node->data = data;
node->left = node->right = NULL;
return (node);
}
// Function to insert nodes in level order. This function takes an array-based treerepresentation as
inputand
// convert it into a linked list-based tree representationNode* insertLevelOrder(vector<int>
tree_vec,
//tree_vec: array implementation,
create node for position i.
int i, int n)
{
Node* root = nullptr;
// Base case for recursion
if (i < n)
{
root = newNode(tree_vec[i]);
// insert left child
root->left = inse.
include ltstdiohgtinclude ltstdlibhgtinclude l.pdf
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void FillBingoCard(int bingocard[5][5]);
void PrintCard(int bingocard[5][5], int called[3], char yn[1]);
int PickNumber(int called[3], int callednumber[75], int counter);
int drawnnumber(int bingocard[5][5], int called[3]);
void completedrowcolumn(int bingocard[5][5], int win);
int main(void)
{
//array of bingo numbers
int row = 5;
int col = 5;
int bingocard[row][col];
int called[3];
int counter = 0;
int callednumber[75];
char yn[1];
int win = 0;
//fill bingocard
void FillBingoCard(int bingocard[5][5])
{
int i, j, k;
int temp;
srand(time(NULL));
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
temp = rand() % 15 + 1 + j * 15;
for (k = 0; k < j; k++)
{
if (temp == bingocard[i][k])
{
j--;
break;
}
}
bingocard[i][j] = temp;
}
}
bingocard[2][2] = -1;
}
void PrintCard(int bingocard[5][5], int called[3], char yn[1])
{
int i, j;
printf(" B I N G On");
for (i = 0; i < 5; i++)
{
printf("----------------------n");
for (j = 0; j < 5; j++)
{
if (bingocard[i][j] == -1)
{
printf("| X ");
}
else if (called[0] == 'B' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'I' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'N' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'G' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'O' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else
{
printf("| %2d", bingocard[i][j]);
}
}
printf("|n");
}
printf("----------------------n");
printf("Have you got number %c%d? (Y/N) ", called[0], called[1]);
scanf(" %c", yn);
}
int PickNumber(int called[3], int callednumber[75], int counter)
{
int temp;
srand(time(NULL));
do
{
temp = rand() % 75 + 1;
} while (callednumber[temp - 1] != 0);
callednumber[temp - 1] = 1;
called[1] = temp;
if (temp <= 15)
{
called[0] = 'B';
}
else if (temp <= 30)
{
called[0] = 'I';
}
else if (temp <= 45)
{
called[0] = 'N';
}
else if (temp <= 60)
{
called[0] = 'G';
}
else
{
called[0] = 'O';
}
return *called;
}
int drawnnumber(int bingocard[5][5], int called[3])
{
int row, col;
int found = 0;
for (row = 0; row < 5; row++)
{
for (col = 0; col < 5; col++)
{
if (bingocard[row][col] == called[1])
{
bingocard[row][col] = -1;
found = 1;
}
}
}
if (found == 1)
{
return 1;
}
else
{
return 0;
}
}
{
int row, col;
// check for completed rows
for (row = 0; row < 5; row++)
{
int count = 0;
for (col = 0; col < 5; col++)
{
if (bingocard[row][col] == -1)
{
count++;
}
}
if (count == 5)
{
printf("nBINGO! You completed row %d.", row + 1);
win = 1;
}
}
// check for completed columns
for (col = 0; col < 5; col++)
{
int count = 0;
for (row = 0; row < 5; row++)
{
if (bingocard[row][col] == -1)
{
count++;
}
}
if (count == 5)
{
printf("nBINGO! You completed column %d.", col + 1);
win = 1;
}
}
}
void completedrowcolumn(int bingocard[5][5], int win)
{
int row, col, diag, count;
// ch.
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/************************************************************/
template<typename T>
struct ListNode
{
ListNode () : data ()
{
}
ListNode (const T& v) : data (v)
{
}
ListNode (const T& v, ListNode* n, ListNode* p) : data (v), next (n), prev (p)
{
}
// unhooks the range [begin,end] from a linked list
// NOTE: will lose reference to begin and end if you
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//
// - does not create any new nodes
// - does not destroy any existing nodes
// - begin is start of range to remove
// - end is inclusive end of range to remove
//
// [5]
static void
unhook_range (ListNode* begin, ListNode* end)
{
// TODO
}
// inserts the range [first,last] before this
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//
// [5]
void
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// TODO
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hook_range (first, first);
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unhook ()
{
ListNode::unhook_range (this, this);
}
T data;
ListNode* next{nullptr};
ListNode* prev{nullptr};
};
Please complete the implementation of the missing part marked TODO.
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include ltstdiohgt include ltstringhgt define M.pdf
#include <stdio.h>
#include <string.h>
#define MAX_USERS 100
struct user {
char username[20];
char password[20];
char codeword[20];
};
int num_users = 0;
struct user users[MAX_USERS];
int find_user_index(char *username) {
for (int i = 0; i < num_users; i++) {
if (strcmp(users[i].username, username) == 0) {
return i;
}
}
return -1;
}
void add_user() {
if (num_users == MAX_USERS) {
printf("Error: maximum number of users reachedn");
return;
}
struct user u;
printf("Enter username: ");
scanf("%s", u.username);
printf("Enter password: ");
scanf("%s", u.password);
printf("Enter codeword: ");
scanf("%s", u.codeword);
users[num_users++] = u;
}
void edit_user() {
char username[20];
printf("Enter username to edit: ");
scanf("%s", username);
int i = find_user_index(username);
if (i == -1) {
printf("Error: user not foundn");
return;
}
struct user u = users[i];
printf("Enter new password (or press enter to keep current password): ");
scanf("%s", u.password);
printf("Enter new codeword (or press enter to keep current codeword): ");
scanf("%s", u.codeword);
users[i] = u;
}
void display_users() {
printf("%-20s %-20s %-20sn", "Username", "Password", "Codeword");
for (int i = 0; i < num_users; i++) {
printf("%-20s %-20s %-20sn", users[i].username, users[i].password, users[i].codeword);
}
}
void remove_user() {
char username[20];
printf("Enter username to remove: ");
scanf("%s", username);
int i = find_user_index(username);
if (i == -1) {
printf("Error: user not foundn");
return;
}
for (int j = i; j < num_users - 1; j++) {
users[j] = users[j + 1];
}
num_users--;
}
int main() {
int choice;
while (1) {
printf("n");
printf("1. Add usern");
printf("2. Edit usern");
printf("3. Display usersn");
printf("4. Remove usern");
printf("5. Exitn");
printf("Enter choice: ");
scanf("%d", &choice);
switch (choice) {
case 1:
add_user();
break;
case 2:
edit_user();
break;
case 3:
display_users();
break;
case 4:
remove_user();
break;
case 5:
return 0;
default:
printf("Error: invalid choicen");
}
}
}
Based on the code above, provide the necessary comments in the code..
include ltiostreamgt include ltfstreamgt in.pdf
#include <iostream>
#include <fstream>
#include <sstream>
#include <vector>
#include <string>
using namespace std;
/* A binary tree node has data,pointer to left child and apointer to right child */
struct Node
{
int data;
Node* left, * right;
};
/*Function for creating a new Node structure */
Node* newNode(int data)
{
Node* node = new Node;
//Node* node = (Node*)malloc(sizeof(Node)); //will also work.
node->data = data;
node->left = node->right = NULL;
return (node);
}
// Function to insert nodes in level order. This function takes an array-based treerepresentation as
inputand
// convert it into a linked list-based tree representationNode* insertLevelOrder(vector<int>
tree_vec,
//tree_vec: array implementation,
create node for position i.
int i, int n)
{
Node* root = nullptr;
// Base case for recursion
if (i < n)
{
root = newNode(tree_vec[i]);
// insert left child
root->left = insertLevelOrder(tree_vec,
2 * i + 1, n);
// insert right child
root->right = insertLevelOrder(tree_vec,
2 * i + 2, n);
}
return root;
}
// Example code for InOrder traversal
void inOrder(Node * root)
{
if (root != NULL)
{
inOrder(root->left);
cout << root->data << " ";
inOrder(root->right);
}
}
int main()
{
vector<int> tree_vec;
string file_name;
int temp_data;
cout << "Please input the file name of a complete binary tree:";
cin >> file_name;
ifstream tree_file(file_name, ios::in);
if (tree_file.fail())
{
cout << "Fail to open the tree file.";
return 0;
}
while (!tree_file.fail() && !tree_file.eof())
{
tree_file >> temp_data;
tree_vec.push_back(temp_data);
}
/*Transform the array-based tree into linked-list in level-order.*/
Node* root = insertLevelOrder(tree_vec, 0, tree_vec.size());
/*Task 1, to be implemented*/
cout << "The Preorder Traversal result is: " << endl;
/*Example implementation*/
cout << "The Inorder Traversal result is: " << endl;
inOrder(root);
/*Task 2, to be implemented*/
cout << "The Postorder Traversal result is: " << endl;
/*Task 3, to be implemented*/
cout << "The number of leaf nodes is: " << endl;
return 0;
}
please help me to finish the code with the task using c++
#include <iostream>
#include <fstream>
#include <sstream>
#include <vector>
#include <string>
using namespace std;
/* A binary tree node has data,pointer to left child and apointer to right child */
struct Node
{
int data;
Node* left, * right;
};
/*Function for creating a new Node structure */
Node* newNode(int data)
{
Node* node = new Node;
//Node* node = (Node*)malloc(sizeof(Node)); //will also work.
node->data = data;
node->left = node->right = NULL;
return (node);
}
// Function to insert nodes in level order. This function takes an array-based treerepresentation as
inputand
// convert it into a linked list-based tree representationNode* insertLevelOrder(vector<int>
tree_vec,
//tree_vec: array implementation,
create node for position i.
int i, int n)
{
Node* root = nullptr;
// Base case for recursion
if (i < n)
{
root = newNode(tree_vec[i]);
// insert left child
root->left = inse.
include ltstdiohgtinclude ltstdlibhgtinclude l.pdf
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
void FillBingoCard(int bingocard[5][5]);
void PrintCard(int bingocard[5][5], int called[3], char yn[1]);
int PickNumber(int called[3], int callednumber[75], int counter);
int drawnnumber(int bingocard[5][5], int called[3]);
void completedrowcolumn(int bingocard[5][5], int win);
int main(void)
{
//array of bingo numbers
int row = 5;
int col = 5;
int bingocard[row][col];
int called[3];
int counter = 0;
int callednumber[75];
char yn[1];
int win = 0;
//fill bingocard
void FillBingoCard(int bingocard[5][5])
{
int i, j, k;
int temp;
srand(time(NULL));
for (i = 0; i < 5; i++)
{
for (j = 0; j < 5; j++)
{
temp = rand() % 15 + 1 + j * 15;
for (k = 0; k < j; k++)
{
if (temp == bingocard[i][k])
{
j--;
break;
}
}
bingocard[i][j] = temp;
}
}
bingocard[2][2] = -1;
}
void PrintCard(int bingocard[5][5], int called[3], char yn[1])
{
int i, j;
printf(" B I N G On");
for (i = 0; i < 5; i++)
{
printf("----------------------n");
for (j = 0; j < 5; j++)
{
if (bingocard[i][j] == -1)
{
printf("| X ");
}
else if (called[0] == 'B' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'I' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'N' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'G' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else if (called[0] == 'O' && called[1] == bingocard[i][j])
{
printf("| %2d", bingocard[i][j]);
}
else
{
printf("| %2d", bingocard[i][j]);
}
}
printf("|n");
}
printf("----------------------n");
printf("Have you got number %c%d? (Y/N) ", called[0], called[1]);
scanf(" %c", yn);
}
int PickNumber(int called[3], int callednumber[75], int counter)
{
int temp;
srand(time(NULL));
do
{
temp = rand() % 75 + 1;
} while (callednumber[temp - 1] != 0);
callednumber[temp - 1] = 1;
called[1] = temp;
if (temp <= 15)
{
called[0] = 'B';
}
else if (temp <= 30)
{
called[0] = 'I';
}
else if (temp <= 45)
{
called[0] = 'N';
}
else if (temp <= 60)
{
called[0] = 'G';
}
else
{
called[0] = 'O';
}
return *called;
}
int drawnnumber(int bingocard[5][5], int called[3])
{
int row, col;
int found = 0;
for (row = 0; row < 5; row++)
{
for (col = 0; col < 5; col++)
{
if (bingocard[row][col] == called[1])
{
bingocard[row][col] = -1;
found = 1;
}
}
}
if (found == 1)
{
return 1;
}
else
{
return 0;
}
}
{
int row, col;
// check for completed rows
for (row = 0; row < 5; row++)
{
int count = 0;
for (col = 0; col < 5; col++)
{
if (bingocard[row][col] == -1)
{
count++;
}
}
if (count == 5)
{
printf("nBINGO! You completed row %d.", row + 1);
win = 1;
}
}
// check for completed columns
for (col = 0; col < 5; col++)
{
int count = 0;
for (row = 0; row < 5; row++)
{
if (bingocard[row][col] == -1)
{
count++;
}
}
if (count == 5)
{
printf("nBINGO! You completed column %d.", col + 1);
win = 1;
}
}
}
void completedrowcolumn(int bingocard[5][5], int win)
{
int row, col, diag, count;
// ch.
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