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GRADE 11 MATH
GRADE 10 MATH
PREVIEW:
THIS VIDEO ILLUSTRATES HOW TO CALCULATE EQUATION OF A LINE .
THE SLOPE INTERCEPT FORM AND THE TWO POINT FORM ARE
ILLUSTRATED.
PROBLEMS INVOLVING EQUATION OF THE MEDIAN AND ALTITUDE OF A
TRIANGLE ARE ALSO EXPLAINED.
SO WATCH THIS ENTIRE VIDEO WITH ME!
Equation of a line passing through 2 points
Find the equation of a line passing through (-1,1) and parallel to the line joining
(2,3) and (4, -1)
y-1 =-2 ( x+ 1)
y -1 = -2x -2
y = -2x -1
Question 2
Find the equation of the straight line joining the points (2,3) and (4, 1)
y -3 = -1 ( x-2)
y -3 = - x + 2
y + x = 5
Question 3
Find the equation of the line through (2 , - 5) and making an intercept of -3 on the y axis
y + 3 = - 1 ( x)
y + x + 3 = 0
The line passes through ( 0 , -3 )
Question 4
If the points (1 , 4), (3, -2 ) and (p , -5 ) lie on a straight line, find p
y – 4 = - 3 x + 3
y = - 3 x + 7
3 p =12
p = 4
-5 = - 3p + 7
If A (10,4), B (-4,9) , C(-2,-1) are the vertices of triangle ABC,find the
equation of the
Median through A
Altitude through B
A(10,4)
B(-4,9) (-3,4)
D
If AD is the median
Slope of AD =0
Equation of median is y =4
To find equation of the altitude through B, we first calculate
= Slope of AC
= Slope of BD
5 y – 45 = - 12x – 48
5y + 12x + 3 = 0
Question 6
Write the coordinates of the circumcentre of the circle whose vertices are (0,0), (6,0) (0,8)
For a right angled triangle the circumcenter is
The midpoint of the hypotenuse
Circumcenter is
(3,4)
Question 7
If
Are perpendicular to each other find. k
4x +3y – 60 =0
3y = -4x +60
From 1 and 2
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HOW TO CALCULATE EQUATION OF A LINE(2018)

  • 2. PREVIEW: THIS VIDEO ILLUSTRATES HOW TO CALCULATE EQUATION OF A LINE . THE SLOPE INTERCEPT FORM AND THE TWO POINT FORM ARE ILLUSTRATED. PROBLEMS INVOLVING EQUATION OF THE MEDIAN AND ALTITUDE OF A TRIANGLE ARE ALSO EXPLAINED. SO WATCH THIS ENTIRE VIDEO WITH ME!
  • 3. Equation of a line passing through 2 points Find the equation of a line passing through (-1,1) and parallel to the line joining (2,3) and (4, -1)
  • 4. y-1 =-2 ( x+ 1) y -1 = -2x -2 y = -2x -1 Question 2 Find the equation of the straight line joining the points (2,3) and (4, 1) y -3 = -1 ( x-2) y -3 = - x + 2 y + x = 5
  • 5. Question 3 Find the equation of the line through (2 , - 5) and making an intercept of -3 on the y axis y + 3 = - 1 ( x) y + x + 3 = 0 The line passes through ( 0 , -3 )
  • 6. Question 4 If the points (1 , 4), (3, -2 ) and (p , -5 ) lie on a straight line, find p y – 4 = - 3 x + 3 y = - 3 x + 7 3 p =12 p = 4 -5 = - 3p + 7
  • 7. If A (10,4), B (-4,9) , C(-2,-1) are the vertices of triangle ABC,find the equation of the Median through A Altitude through B A(10,4) B(-4,9) (-3,4) D
  • 8. If AD is the median Slope of AD =0 Equation of median is y =4 To find equation of the altitude through B, we first calculate = Slope of AC = Slope of BD 5 y – 45 = - 12x – 48 5y + 12x + 3 = 0
  • 9. Question 6 Write the coordinates of the circumcentre of the circle whose vertices are (0,0), (6,0) (0,8) For a right angled triangle the circumcenter is The midpoint of the hypotenuse Circumcenter is (3,4)
  • 10. Question 7 If Are perpendicular to each other find. k 4x +3y – 60 =0 3y = -4x +60
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