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International Journal of Trend in Scientific Research and Development (IJTSRD)
Volume 4 Issue 6, September-October 2020
@ IJTSRD | Unique Paper ID – IJTSRD33600
Generalized Derivations
Associate Professor in Mathematics
ABSTRACT
Let NP be a zero symmetric prime near ring with multiplicative centre Z.
Let f: NP → NP be a generalized derivation de
f ≠ 0 generalized derivation on NP for which (a) f(NP)
∀x,y∈ NP ” Also if NP is 2-torsion free then NP is commutative ring, from
which Herstein [2] Theorem comes out as a corollary.
KEYWORDS: Prime near rings, Generalized Derivation, Commutative ring, 2
Torsion free.
1. INTRODUCTION
In this paper NP will denote a zero-symmetric near
with multiplicative centre Z. A generalized derivation on
NP is defined to be an additive endomorphism satisfying
f(xy) = f(x)y + xD(y) ∀x,y∈ N
where D is the ordinary derivation defined on NP.
For x,y∈ NP, the symbol [x,y] will denote the commutator
xy−yx, while the symbol (x,y) will denote the additive
group commutator x+y−x−y.
The generalized derivation f will be called
[x,f(x)] = 0 ∀ x ∈ NP. Finally, NP will be called prime if a,b
N and aNb = {0} implies that a = 0 or b = 0.
(Note that this definition implies the usual definition of
prime near-ring. It does not seem to be known whether
the twodefinition are equivalent.)
We have proved (1) If f ≠ 0 generalized derivation on
prime near ring N for which
A. f(NP) ⊆ Z
B. [f(x),f(y)] = 0 ∀x,y∈ NP
Also if NP is 2-torsion free then NP is commutative ring,
from which Herstein [2] Theorem comes out as a
corollary.
2. Preliminary results
We begin with three quite general and useful lemmas to
proving Theorems in Prime near Rings.
International Journal of Trend in Scientific Research and Development (IJTSRD)
October 2020 Available Online: www.ijtsrd.com
33600 | Volume – 4 | Issue – 6 | September
Generalized Derivations in Prime near Rings
Dr. K. L. Kaushik
n Mathematics, Aggarwal College, Ballabgarh, Faridabad, Haryana
Let NP be a zero symmetric prime near ring with multiplicative centre Z.
→ NP be a generalized derivation defined on NP. We prove that “If
0 generalized derivation on NP for which (a) f(NP) ⊆ Z (b) [f(x),f(y)] = 0
orsion free then NP is commutative ring, from
which Herstein [2] Theorem comes out as a corollary.
Prime near rings, Generalized Derivation, Commutative ring, 2-
How to cite this paper
"Generalized Derivations in Prime near
Rings" Published in
International
Journal of Trend in
Scientific Research
and Development
(ijtsrd), ISSN: 2456
6470, Volume
Issue-6, October
2020, pp.1283
www.ijtsrd.com/papers
Copyright © 20
International Journal of Trend in
Scientific Research and Development
Journal. This is an Open Access article
distributed under
the terms of the
Creative Commons
Attribution License (
(http://creativecommons.org/licenses/by/4.0)
symmetric near-ring
with multiplicative centre Z. A generalized derivation on
fined to be an additive endomorphism satisfying
fined on NP.
NP, the symbol [x,y] will denote the commutator
−yx, while the symbol (x,y) will denote the additive-
The generalized derivation f will be called commuting if
NP. Finally, NP will be called prime if a,b∈
N and aNb = {0} implies that a = 0 or b = 0.
finition implies the usual definition of
ring. It does not seem to be known whether
≠ 0 generalized derivation on
torsion free then NP is commutative ring,
from which Herstein [2] Theorem comes out as a
We begin with three quite general and useful lemmas to
Lemma 3.1 Let f be an arbitrary generalized derivation on
the near-ring N. Then N satis
Distributive Law:
(f(a)b + aD(b))c = f(a)bc + aD(b)c
Lemma 3.2 If f be a generalized derivation on N and
suppose that u ∈ N is not a zero divisor. then (u,x) is
constant for every x ∈ N.
Lemma 3.3 Let N have no non
admits a generalized
derivation f. Then (N,+) is abelian.
3. Prime near-rings:
We have taken NP be the prime near
Lemma 4.1 Let NP be a Prime near
then z is not zero divisor (ii) If Z contains a non
element z for which z + z ∈ Z then (NP,+) is abelian.
Proof
A. If z ∈ Z −{0} and zx = 0. Then zNPx = 0. Hence x = 0.
B. Let z ∈ Z−{0}be an element such that z+z
x,y∈ NP. Since z + z is distributive
⇒ (x + y)(z + z) = x(z + z) + y(z + z)
= xz + xz + yz + yz
= (x + x + y + y)z
On the other hand
(x + y)(z + z) = (x + y)z + (x + y)z
= xz + yz + xz + yz
= (x + y + x + y)z
International Journal of Trend in Scientific Research and Development (IJTSRD)
www.ijtsrd.com e-ISSN: 2456 – 6470
6 | September-October 2020 Page 1283
n Prime near Rings
Faridabad, Haryana, India
How to cite this paper: Dr. K. L. Kaushik
"Generalized Derivations in Prime near
Rings" Published in
International
Journal of Trend in
Scientific Research
and Development
(ijtsrd), ISSN: 2456-
6470, Volume-4 |
6, October
2020, pp.1283-1284, URL:
www.ijtsrd.com/papers/ijtsrd33600.pdf
Copyright © 2020 by author(s) and
International Journal of Trend in
Scientific Research and Development
Journal. This is an Open Access article
distributed under
the terms of the
Creative Commons
Attribution License (CC BY 4.0)
(http://creativecommons.org/licenses/by/4.0)
Let f be an arbitrary generalized derivation on
Then N satisfies the following Partial
(a)b + aD(b))c = f(a)bc + aD(b)c ∀a,b,c∈ NP
If f be a generalized derivation on N and
N is not a zero divisor. then (u,x) is
Let N have no non-zero divisors of zero if N
erivation f. Then (N,+) is abelian.
We have taken NP be the prime near-ring.
1 Let NP be a Prime near-ring (i) If z ∈ Z −{0}
then z is not zero divisor (ii) If Z contains a non-zero
Z then (NP,+) is abelian.
−{0} and zx = 0. Then zNPx = 0. Hence x = 0.
−{0}be an element such that z+z∈ Z and let
NP. Since z + z is distributive
(x + y)(z + z) = x(z + z) + y(z + z)
(x + y)(z + z) = (x + y)z + (x + y)z
IJTSRD33600
International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470
@ IJTSRD | Unique Paper ID – IJTSRD33600 | Volume – 4 | Issue – 6 | September-October 2020 Page 1284
Then x + x + y + y = x + y + x + y.
Hence x + y = y + x
Hence (NP,+) is abelian.
Lemma 4.2 Let NP be a Prime near-ring
A. Let f be a non-zero generalized derivation on NP. Then
xf(NP) = {0} ⇒ x = 0, and
f(NP)x = {0} implies x = 0.
B. If NP is 2-torsion free and f is a generalized derivation
on NP s.t. f2 = 0 then f = 0
Proof (i) Let xf(NP) = {0} and let r,s be arbitrary elements
of NP. Then
xf(rs) = 0 ⇒ x(f(r)s + rD(s)) = 0
⇒xf(r)s =0 + xrD(s) = 0
⇒xrD(s) = 0
Then xND(NP) = {0} Since D(NP) ≠ 0 ⇒ x = 0
A similar argument works if f(NP)x = {0} (Since Lemma 3.1
gives distributivity to carry it through).
Let x, y ∈ NP we have
0 = f2(xy)
⇒ 0 = f (f(x)y + xD(y))
= f (f(x))y + f(x)D(y) + f(x)D(y) + xD(D(y))
= f2(x)y + f(x)D(y) + f(x)D(y) + xD2(y)
⇒ 0 = 2f(x)D(y)
⇒ f(x)D(y) = 0
since NP is 2 torsion-free ⇒ f(x)D(NP) = {0} for each x ∈ N
and (i) gives f = 0.
Theorem 4.3 Let NP be a Prime near-ring. Let f be a non
zero generalized derivation for which f(NP) ⊆ Z, then
(NP,+) is abelian. Moreover, if NP is 2-torsion-free then NP
is a commutative ring.
Proof Let v be an arbitrary constant, and let x be a non
constant. Then
f(xv) = f(x)v + xD(v)
= f(x)v ∈ Z
Since f(x) ∈ Z −{0}, it follows easily that v ∈ Z. Since v + v is
constant for all constants v, it follows from Lemma 2.1(ii)
that (NP,+) is abelian, provided that there exists a non-
zero constant. Let NP is 2-torsion free near-ring. To prove
that NP is commutative.
By Lemma 3.1
(f(a)b + aD(b))c = f(x)bc+aD(b)c ∀a,b,c∈ N and using the
fact that f(ab) ∈ Z, we get
cf(a)b + caD(b) = f(a)bc + aD(b)c
Since (NP,+) is abelian and f(NP) ⊆ Z. This equation
rearrange to yield f(a)[b,c] = D(b)[c,a], ∀a,b,c∈ NP Now
suppose that NP is not commutative we choose b,c∈ NP
with [b,c] ≠ 0 and letting a = f(x), we get
f2(x)[b,c] = 0 ∀ x ∈ NP;
⇒ we conclude that
f2(x) = 0 ∀ x ∈ NP By Lemma 4.2(ii) f = 0 which is a
contradiction ∵ f 6= 0. Hence our supposition is wrong. So
NP is commutative.
Theorem 4.4 Let NP be a Prime near-ring admitting a non
zero generalized derivation f such that [f(x),f(y)] = 0 ∀x,y∈
NP. Then (NP,+) is abelian and if NP is 2-torsion free as
well. Then NP is a commutative ring.
Proof By Lemma 4.1(ii), if z and z + z commute
elementwise with f(NP). Then z f(v) = 0 for all additive
commutators v. Thus putting z = f(x), we get
f(x)f(v) = 0 ∀ x ∈ NP
⇒ f(c) = 0
(By Lemma 4.2(i)) Since wv is also an additive
commutator for any w ∈ NP, we have
f(wv) = 0 ⇒ f(w)v = 0
By Lemma 3.3
v = 0.
Hence (NP,+) is an abelian. Assume now that NP is 2-
torsion free. By partial distributive law
f(f(x)y)f(z) = (f(f(x)y + f(x)D(y))f(z) ∀x,y,z∈ NP
= f2(f(x))y f(z) + f(x)D(y)f(z)
⇒ f2(f(x))yf(z) = −f(f(x)y)f(z)−f(x)D(y)f(z)
= f(z)(f(f(x)y−f(x)D(y))
= f(z)(f(f(x)y)
= f(z)f2(x)y
= f2(x)f(z)y
⇒ f2(x)(yf(z)−f(z)y) = 0 ∀x,y,z∈ NP
Replacing y by yt we get
f2(x)(ytf(z)−f(z)yt) = 0
⇒ f2(x)ytf(z) = f2(x)f(z)yt
= f2(x)yf(z)t∀x,y,z,t∈ NP
⇒ f2(x)NP [t,f(z)] = {0} ∀x,t,z∈ NP
⇒ either f2 = 0 or f(NP) ⊆ Z (∵ NP is Prime)
If f2 = 0 ⇒ By Lemma 4.2 (ii) f = 0
which is a contradiction. (∵ f ≠0)
⇒ f2 6= 0
⇒ f(NP) ⊆ Z.
By Theorem 4.3, NP is a commutative ring.
Hence proved.
Corollary 4.4.1 Replacing f by D we get Herstein [2]
Theorem
Conclusion
In this paper we proved that “If f ≠ 0 generalized
derivation on NP for which (a) f(NP) ⊆ Z (b) [f(x),f(y)] = 0
∀x,y∈ NP ” and we also showed that if NP is 2-torsion free
then NP is commutative ring, from which Herstein [2]
Theorem comes out as a corollary.
References
[1] Havala, B. Generalized derivation in rings,
Communication in algebra 26(4),1147-1166 (1998)
[2] I. N. Herstein, A note on derivations, Canad. Math.
Bull. 21 (1978).
[3] G. Pilz, Near-rings, 2nd edition, North-Holland,
Amsterdam, 1983.
[4] E. C. Posner, Derivations in Prime rings, Proc. Amer.
Math. Soc. 8 (1957)1093-1100.

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Generalized Derivations

  • 1. International Journal of Trend in Scientific Research and Development (IJTSRD) Volume 4 Issue 6, September-October 2020 @ IJTSRD | Unique Paper ID – IJTSRD33600 Generalized Derivations Associate Professor in Mathematics ABSTRACT Let NP be a zero symmetric prime near ring with multiplicative centre Z. Let f: NP → NP be a generalized derivation de f ≠ 0 generalized derivation on NP for which (a) f(NP) ∀x,y∈ NP ” Also if NP is 2-torsion free then NP is commutative ring, from which Herstein [2] Theorem comes out as a corollary. KEYWORDS: Prime near rings, Generalized Derivation, Commutative ring, 2 Torsion free. 1. INTRODUCTION In this paper NP will denote a zero-symmetric near with multiplicative centre Z. A generalized derivation on NP is defined to be an additive endomorphism satisfying f(xy) = f(x)y + xD(y) ∀x,y∈ N where D is the ordinary derivation defined on NP. For x,y∈ NP, the symbol [x,y] will denote the commutator xy−yx, while the symbol (x,y) will denote the additive group commutator x+y−x−y. The generalized derivation f will be called [x,f(x)] = 0 ∀ x ∈ NP. Finally, NP will be called prime if a,b N and aNb = {0} implies that a = 0 or b = 0. (Note that this definition implies the usual definition of prime near-ring. It does not seem to be known whether the twodefinition are equivalent.) We have proved (1) If f ≠ 0 generalized derivation on prime near ring N for which A. f(NP) ⊆ Z B. [f(x),f(y)] = 0 ∀x,y∈ NP Also if NP is 2-torsion free then NP is commutative ring, from which Herstein [2] Theorem comes out as a corollary. 2. Preliminary results We begin with three quite general and useful lemmas to proving Theorems in Prime near Rings. International Journal of Trend in Scientific Research and Development (IJTSRD) October 2020 Available Online: www.ijtsrd.com 33600 | Volume – 4 | Issue – 6 | September Generalized Derivations in Prime near Rings Dr. K. L. Kaushik n Mathematics, Aggarwal College, Ballabgarh, Faridabad, Haryana Let NP be a zero symmetric prime near ring with multiplicative centre Z. → NP be a generalized derivation defined on NP. We prove that “If 0 generalized derivation on NP for which (a) f(NP) ⊆ Z (b) [f(x),f(y)] = 0 orsion free then NP is commutative ring, from which Herstein [2] Theorem comes out as a corollary. Prime near rings, Generalized Derivation, Commutative ring, 2- How to cite this paper "Generalized Derivations in Prime near Rings" Published in International Journal of Trend in Scientific Research and Development (ijtsrd), ISSN: 2456 6470, Volume Issue-6, October 2020, pp.1283 www.ijtsrd.com/papers Copyright © 20 International Journal of Trend in Scientific Research and Development Journal. This is an Open Access article distributed under the terms of the Creative Commons Attribution License ( (http://creativecommons.org/licenses/by/4.0) symmetric near-ring with multiplicative centre Z. A generalized derivation on fined to be an additive endomorphism satisfying fined on NP. NP, the symbol [x,y] will denote the commutator −yx, while the symbol (x,y) will denote the additive- The generalized derivation f will be called commuting if NP. Finally, NP will be called prime if a,b∈ N and aNb = {0} implies that a = 0 or b = 0. finition implies the usual definition of ring. It does not seem to be known whether ≠ 0 generalized derivation on torsion free then NP is commutative ring, from which Herstein [2] Theorem comes out as a We begin with three quite general and useful lemmas to Lemma 3.1 Let f be an arbitrary generalized derivation on the near-ring N. Then N satis Distributive Law: (f(a)b + aD(b))c = f(a)bc + aD(b)c Lemma 3.2 If f be a generalized derivation on N and suppose that u ∈ N is not a zero divisor. then (u,x) is constant for every x ∈ N. Lemma 3.3 Let N have no non admits a generalized derivation f. Then (N,+) is abelian. 3. Prime near-rings: We have taken NP be the prime near Lemma 4.1 Let NP be a Prime near then z is not zero divisor (ii) If Z contains a non element z for which z + z ∈ Z then (NP,+) is abelian. Proof A. If z ∈ Z −{0} and zx = 0. Then zNPx = 0. Hence x = 0. B. Let z ∈ Z−{0}be an element such that z+z x,y∈ NP. Since z + z is distributive ⇒ (x + y)(z + z) = x(z + z) + y(z + z) = xz + xz + yz + yz = (x + x + y + y)z On the other hand (x + y)(z + z) = (x + y)z + (x + y)z = xz + yz + xz + yz = (x + y + x + y)z International Journal of Trend in Scientific Research and Development (IJTSRD) www.ijtsrd.com e-ISSN: 2456 – 6470 6 | September-October 2020 Page 1283 n Prime near Rings Faridabad, Haryana, India How to cite this paper: Dr. K. L. Kaushik "Generalized Derivations in Prime near Rings" Published in International Journal of Trend in Scientific Research and Development (ijtsrd), ISSN: 2456- 6470, Volume-4 | 6, October 2020, pp.1283-1284, URL: www.ijtsrd.com/papers/ijtsrd33600.pdf Copyright © 2020 by author(s) and International Journal of Trend in Scientific Research and Development Journal. This is an Open Access article distributed under the terms of the Creative Commons Attribution License (CC BY 4.0) (http://creativecommons.org/licenses/by/4.0) Let f be an arbitrary generalized derivation on Then N satisfies the following Partial (a)b + aD(b))c = f(a)bc + aD(b)c ∀a,b,c∈ NP If f be a generalized derivation on N and N is not a zero divisor. then (u,x) is Let N have no non-zero divisors of zero if N erivation f. Then (N,+) is abelian. We have taken NP be the prime near-ring. 1 Let NP be a Prime near-ring (i) If z ∈ Z −{0} then z is not zero divisor (ii) If Z contains a non-zero Z then (NP,+) is abelian. −{0} and zx = 0. Then zNPx = 0. Hence x = 0. −{0}be an element such that z+z∈ Z and let NP. Since z + z is distributive (x + y)(z + z) = x(z + z) + y(z + z) (x + y)(z + z) = (x + y)z + (x + y)z IJTSRD33600
  • 2. International Journal of Trend in Scientific Research and Development (IJTSRD) @ www.ijtsrd.com eISSN: 2456-6470 @ IJTSRD | Unique Paper ID – IJTSRD33600 | Volume – 4 | Issue – 6 | September-October 2020 Page 1284 Then x + x + y + y = x + y + x + y. Hence x + y = y + x Hence (NP,+) is abelian. Lemma 4.2 Let NP be a Prime near-ring A. Let f be a non-zero generalized derivation on NP. Then xf(NP) = {0} ⇒ x = 0, and f(NP)x = {0} implies x = 0. B. If NP is 2-torsion free and f is a generalized derivation on NP s.t. f2 = 0 then f = 0 Proof (i) Let xf(NP) = {0} and let r,s be arbitrary elements of NP. Then xf(rs) = 0 ⇒ x(f(r)s + rD(s)) = 0 ⇒xf(r)s =0 + xrD(s) = 0 ⇒xrD(s) = 0 Then xND(NP) = {0} Since D(NP) ≠ 0 ⇒ x = 0 A similar argument works if f(NP)x = {0} (Since Lemma 3.1 gives distributivity to carry it through). Let x, y ∈ NP we have 0 = f2(xy) ⇒ 0 = f (f(x)y + xD(y)) = f (f(x))y + f(x)D(y) + f(x)D(y) + xD(D(y)) = f2(x)y + f(x)D(y) + f(x)D(y) + xD2(y) ⇒ 0 = 2f(x)D(y) ⇒ f(x)D(y) = 0 since NP is 2 torsion-free ⇒ f(x)D(NP) = {0} for each x ∈ N and (i) gives f = 0. Theorem 4.3 Let NP be a Prime near-ring. Let f be a non zero generalized derivation for which f(NP) ⊆ Z, then (NP,+) is abelian. Moreover, if NP is 2-torsion-free then NP is a commutative ring. Proof Let v be an arbitrary constant, and let x be a non constant. Then f(xv) = f(x)v + xD(v) = f(x)v ∈ Z Since f(x) ∈ Z −{0}, it follows easily that v ∈ Z. Since v + v is constant for all constants v, it follows from Lemma 2.1(ii) that (NP,+) is abelian, provided that there exists a non- zero constant. Let NP is 2-torsion free near-ring. To prove that NP is commutative. By Lemma 3.1 (f(a)b + aD(b))c = f(x)bc+aD(b)c ∀a,b,c∈ N and using the fact that f(ab) ∈ Z, we get cf(a)b + caD(b) = f(a)bc + aD(b)c Since (NP,+) is abelian and f(NP) ⊆ Z. This equation rearrange to yield f(a)[b,c] = D(b)[c,a], ∀a,b,c∈ NP Now suppose that NP is not commutative we choose b,c∈ NP with [b,c] ≠ 0 and letting a = f(x), we get f2(x)[b,c] = 0 ∀ x ∈ NP; ⇒ we conclude that f2(x) = 0 ∀ x ∈ NP By Lemma 4.2(ii) f = 0 which is a contradiction ∵ f 6= 0. Hence our supposition is wrong. So NP is commutative. Theorem 4.4 Let NP be a Prime near-ring admitting a non zero generalized derivation f such that [f(x),f(y)] = 0 ∀x,y∈ NP. Then (NP,+) is abelian and if NP is 2-torsion free as well. Then NP is a commutative ring. Proof By Lemma 4.1(ii), if z and z + z commute elementwise with f(NP). Then z f(v) = 0 for all additive commutators v. Thus putting z = f(x), we get f(x)f(v) = 0 ∀ x ∈ NP ⇒ f(c) = 0 (By Lemma 4.2(i)) Since wv is also an additive commutator for any w ∈ NP, we have f(wv) = 0 ⇒ f(w)v = 0 By Lemma 3.3 v = 0. Hence (NP,+) is an abelian. Assume now that NP is 2- torsion free. By partial distributive law f(f(x)y)f(z) = (f(f(x)y + f(x)D(y))f(z) ∀x,y,z∈ NP = f2(f(x))y f(z) + f(x)D(y)f(z) ⇒ f2(f(x))yf(z) = −f(f(x)y)f(z)−f(x)D(y)f(z) = f(z)(f(f(x)y−f(x)D(y)) = f(z)(f(f(x)y) = f(z)f2(x)y = f2(x)f(z)y ⇒ f2(x)(yf(z)−f(z)y) = 0 ∀x,y,z∈ NP Replacing y by yt we get f2(x)(ytf(z)−f(z)yt) = 0 ⇒ f2(x)ytf(z) = f2(x)f(z)yt = f2(x)yf(z)t∀x,y,z,t∈ NP ⇒ f2(x)NP [t,f(z)] = {0} ∀x,t,z∈ NP ⇒ either f2 = 0 or f(NP) ⊆ Z (∵ NP is Prime) If f2 = 0 ⇒ By Lemma 4.2 (ii) f = 0 which is a contradiction. (∵ f ≠0) ⇒ f2 6= 0 ⇒ f(NP) ⊆ Z. By Theorem 4.3, NP is a commutative ring. Hence proved. Corollary 4.4.1 Replacing f by D we get Herstein [2] Theorem Conclusion In this paper we proved that “If f ≠ 0 generalized derivation on NP for which (a) f(NP) ⊆ Z (b) [f(x),f(y)] = 0 ∀x,y∈ NP ” and we also showed that if NP is 2-torsion free then NP is commutative ring, from which Herstein [2] Theorem comes out as a corollary. References [1] Havala, B. Generalized derivation in rings, Communication in algebra 26(4),1147-1166 (1998) [2] I. N. Herstein, A note on derivations, Canad. Math. Bull. 21 (1978). [3] G. Pilz, Near-rings, 2nd edition, North-Holland, Amsterdam, 1983. [4] E. C. Posner, Derivations in Prime rings, Proc. Amer. Math. Soc. 8 (1957)1093-1100.