soal uas fuzzy.2

1. 1. Matriks A minimum encoding
M1= At
1. B1 =
0
1
0
(0 1 0) =
0 0 0
0 1 0
0 0 0
M2= At
2. B2 =
0
0
1
(0 0 1) =
0 0 0
0 0 0
0 0 1
M3= At
3. B3 =
0,3
0.8
0.9
(0.3 0.8 0.9) =
0.3 0.3 0.3
0.3 0.8 0.8
0.3 0.8 0.9
M4= At
4. B4 =
0,3
0.8
0.9
(0.3 0.8 0.9) =
0.3 0.3 0.3
0.3 0.8 0.8
0.3 0.8 0.9
2. Matriks B menggunakan max-min composition
Mencari derajat keanggotaan
µsepi = 23-12/23-3 = 11/20= 0.55
µsedang =1
µpadat= 12-3/20= 9/20 = 0.45
Menentukan nilai B menggunakan correlation max min
B1= (0.55 1 0.45)
0 0 0
0 1 0
0 0 0
= (0 1 0)
B2= (0.55 1 0.45)
0 0 0
0 0 0
0 0 1
= (0 0 0.45)
B3= (0.55 1 0.45)
0.3 0.3 0.3
0.3 0.8 0.8
0.3 0.8 0.9
= (0.3 0.8 0.45)

2. B4= (0.55 1 0.45)
0.3 0.3 0.3
0.3 0.8 0.8
0.3 0.8 0.9
= (0.3 0.8 0.45)
3. Menghitung lama akan menyala jika jumlah kendaraan 12
b1= max (0,0,0.3,0,3) = 0.3
b2 = max(1,0,0.8,0.8) = 1
b3 = max(0,0.45,0.45,0.45)= 0.45
Jadi hasil yang didapat menunjukan pada urutan ke 2 nilai terbesar y = 15 detik
B*
=( 0.3*5 + 1*15+0.45*50)/(0.3+1+0.45) = 39/1.75 = 22.285
Jadi, lampu akan menyala selama 22.285 detik