false (in linear region)Solutionfalse (in linear region).pdf
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This very short document appears to discuss the linear region of something and states that whatever is being referred to is false within that linear region. No other context or details are provided so only a very high-level summary can be given based on the limited information.
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we can predict that benzene(C6H6) will exhibit the highest enthalpy .pdf
we can predict that benzene(C6H6) will exhibit the highest enthalpy of vaporization (Hvap).
since nitrogen(N2) and xenon(Xe) are gasses they will exhibit lower enthalpy of vaporization
(Hvap).
silicon tetra floride(SiF4) is volatile gas and hence it also exhibit lower enthalpy of vaporization
(Hvap).
bromine and benzene are the liquids and hence they exhibits higher enthalpy of vaporization
(Hvap) values when compared to the other three compounds.
boiling point of benzene is higher than Br2 , hence benzene(C6H6) will exhibit the highest
enthalpy of vaporization (Hvap)when compared to Br2,Xe,SiF4 and N2
Solution
we can predict that benzene(C6H6) will exhibit the highest enthalpy of vaporization (Hvap).
since nitrogen(N2) and xenon(Xe) are gasses they will exhibit lower enthalpy of vaporization
(Hvap).
silicon tetra floride(SiF4) is volatile gas and hence it also exhibit lower enthalpy of vaporization
(Hvap).
bromine and benzene are the liquids and hence they exhibits higher enthalpy of vaporization
(Hvap) values when compared to the other three compounds.
boiling point of benzene is higher than Br2 , hence benzene(C6H6) will exhibit the highest
enthalpy of vaporization (Hvap)when compared to Br2,Xe,SiF4 and N2.
The modulus of elasticity of a material (E) is given byE = Axial S.pdf
The modulus of elasticity of a material (E) is given by
E = Axial Stress/Axial strain
It is the nature of object to deform when an external force is applied
Solution
The modulus of elasticity of a material (E) is given by
E = Axial Stress/Axial strain
It is the nature of object to deform when an external force is applied.
Solution.cpp#include iostreamheader file for input output func.pdf
Solution
.cpp
#include //header file for input output function
using namespace std;//it tells the compiler to link std namespace
int main()
{//main function
int j=4,i=1;//varable initialization
while(i<=4)//loop for number incrementing
{//nested while loop
j=4;
while(j>i)//loop for spaces
{
cout<<\" \";//printing spaces
j--; //decreasing spaces
}
cout<.
Q5Although this question asks about SN1 reactivity, knowledge of a.pdf
Q5
Although this question asks about SN1 reactivity, knowledge of acidity is required to answer the
question. None of the compound actually start out aromatic or anti-aromatic, but if SN1 were to
occur, the carbocation formed would make compound iii planar and thus you have to now
consider aromaticity.
compound iii
-when it loses Cl- and become planar, the molecule has 4n -electrons (anti-aromatic). Forming an
anti-aromatic compound really isn\'t favourable, so going from the original compound iii to this
intermediate is not an easy thing to do. Therefore, it\'s the least reactive toward SN1.
compounds i and ii
-both of these are non-aromatic through the whole reaction, so now it\'s just down to general SN1
reactivities.
-the only difference between the two compounds is that the carbon where the substitution is
going to occur is a normal secondary carbon on compound i, and an allylic carbon on compound
ii. Since allylic carbons can better stabilize positive charges, it will be more reactive toward SN1
than the simple secondary carbon.
Q6
Again with acidity. Phenol itself is going to be less acidic than the other two compounds simply
because the other two have electron-withdrawing groups on the ring that are removing electron
density from the ring and making the compound better able to stabilize a negative charge on the
oxygen (when a proton is lost).
As for comparing the two disubstituted rings, the nitro group in the meta position can stabilize
the resulting phenoxide ion by removing electron density from the ring, but the nitro group in the
para position can further stabilize the negative charge through resonance.
So the most acidic compound would be the para-disubstituted ring.
Q7
Notice that two of the three compounds listed are aromatic. That automatically makes them more
stable than cyclopentadiene. Cyclopentadiene actually is known to dimerize really quickly via
Diels-Alder reaction.
So now to compare furan and pyrrole for stability.
-both compounds have heteroatoms that have lone pairs. These lone pairs are used in the ring
system to make the rings aromatic.
-the difference between the oxygen and nitrogen donating their lone pairs to the ring system is
that the nitrogen has no free lone pairs left, whereas the oxygen still has one reactive lone pair.
-if you put these two in acid, furan will destabilize because the oxygen can pick up a proton from
the acid, with its free lone pair. The nitrogen in pyrrole is not as likely to pick up a proton.
So the most stable compound of the list is pyrrole.
btw, lone pairs in the aromatic system IS the electron delocalization
Solution
Q5
Although this question asks about SN1 reactivity, knowledge of acidity is required to answer the
question. None of the compound actually start out aromatic or anti-aromatic, but if SN1 were to
occur, the carbocation formed would make compound iii planar and thus you have to now
consider aromaticity.
compound iii
-when it loses Cl- and become planar, the molecule ha.
Portal Triad is an area in the liver named after its triangular shap.pdf
Portal Triad is an area in the liver named after its triangular shape. It has three major
components:
Solution
Portal Triad is an area in the liver named after its triangular shape. It has three major
components:.
Please find the answers and explanations belowPart 1The sequen.pdf
Please find the answers and explanations below:
Part 1:
The sequence of the partent strand is: 5’-ACCTGA TCGGACTGGA-3’. It is well known that the
two strands of DNA run anti-parallel and complementarily to each other. Thus, the sequence of
the complimentary strand will be:
3\'-TGGACTAGCCTGACCT-5\'
Part 2: In opposite orientation, the sequence of complementary strand will be:
5\'-TCCAGTCCGATCAGGT-3\'
Part 3:
The mRNA is formed complementarily to the template DNA in the 5\'-3\' direction and that the
thymidine residues are replaced by uracil. So, accordingly, the sequence of the mRNA template
will be:
3\'-UGGACUAGCCUGACCU-5\'
Part 4:
In Griffith\'s experiments, the non-encapsulated rough bacterial non-virulent colonies and
encapsulated smooth bacterial virulent colonies were used to infect mice. The mice was injected
with following preparations and their outcomes were:
1. Rough colony: Suvive
2. Smooth colony: Die
3. Heat killed smooth: Survive
4. Heat killed smooth along with live rough: Die
Thus, the mice died only on two instances, once injected with smooth virulent bacteria and
second when incubated with heat killed smooth virulent and live avirulent bacteria.
Part 5:
What Griffith found: It was very well known at that time that the bacterial capsule is responsible
for preventing lysis of the bacteria in host\'s immune system and thus leading to infection. The
incubation of heat-killed smooth virulent bacteria with rough avirulent bacteria killed the mice.
This made Griffith think that the heat-killed smooth bacteria might have somehow transformed
the non-virulent strain due to transfer of some biochemical information from the heat-killed
bacteria. The exact chemical nature of this \"transforming agent was not identified by Griffith but
it was much supposed to be protein.
Real transforming principle: The real transformation takes place when the genetic information
from one cell is transferred to the other cell where it is incorporated into its DNA and expressed
in the new cell. This does not include transfer of any proteinaceous material from one strain to
the other, but only transfer of nucleic acid takes place.
Part 6:
After Griffith\'s experiment, the trio of Avery, MacLeod and McCarty determined the correct
biochemical identity of the transforming principle. They further extended and verified the
Griffith\'s experiment. In their experimental setup, these investigators isolated following
fractions from the smooth and rough colonies:
1. Proteinaceous enzyme hydrolyzed fragment of smooth, rough and heat-killed smooth bacteria.
2. Crude proteinaceous fraction from all the three sets.
3. DNA from each set of infectants.
4. DNA fragments duly digested by deoxyribonucleodepolymerase.
These fractions were differentially used to infect the mice and they were diagnosed for disease
symptoms. It was found that mice carrying the fraction of set 1, 2 or 4 did not show any
infection. This suggested that protein was not the source of transformation. Im.
Recommended
we can predict that benzene(C6H6) will exhibit the highest enthalpy .pdf
we can predict that benzene(C6H6) will exhibit the highest enthalpy of vaporization (Hvap).
since nitrogen(N2) and xenon(Xe) are gasses they will exhibit lower enthalpy of vaporization
(Hvap).
silicon tetra floride(SiF4) is volatile gas and hence it also exhibit lower enthalpy of vaporization
(Hvap).
bromine and benzene are the liquids and hence they exhibits higher enthalpy of vaporization
(Hvap) values when compared to the other three compounds.
boiling point of benzene is higher than Br2 , hence benzene(C6H6) will exhibit the highest
enthalpy of vaporization (Hvap)when compared to Br2,Xe,SiF4 and N2
Solution
we can predict that benzene(C6H6) will exhibit the highest enthalpy of vaporization (Hvap).
since nitrogen(N2) and xenon(Xe) are gasses they will exhibit lower enthalpy of vaporization
(Hvap).
silicon tetra floride(SiF4) is volatile gas and hence it also exhibit lower enthalpy of vaporization
(Hvap).
bromine and benzene are the liquids and hence they exhibits higher enthalpy of vaporization
(Hvap) values when compared to the other three compounds.
boiling point of benzene is higher than Br2 , hence benzene(C6H6) will exhibit the highest
enthalpy of vaporization (Hvap)when compared to Br2,Xe,SiF4 and N2.
The modulus of elasticity of a material (E) is given byE = Axial S.pdf
The modulus of elasticity of a material (E) is given by
E = Axial Stress/Axial strain
It is the nature of object to deform when an external force is applied
Solution
The modulus of elasticity of a material (E) is given by
E = Axial Stress/Axial strain
It is the nature of object to deform when an external force is applied.
Solution.cpp#include iostreamheader file for input output func.pdf
Solution
.cpp
#include //header file for input output function
using namespace std;//it tells the compiler to link std namespace
int main()
{//main function
int j=4,i=1;//varable initialization
while(i<=4)//loop for number incrementing
{//nested while loop
j=4;
while(j>i)//loop for spaces
{
cout<<\" \";//printing spaces
j--; //decreasing spaces
}
cout<.
Q5Although this question asks about SN1 reactivity, knowledge of a.pdf
Q5
Although this question asks about SN1 reactivity, knowledge of acidity is required to answer the
question. None of the compound actually start out aromatic or anti-aromatic, but if SN1 were to
occur, the carbocation formed would make compound iii planar and thus you have to now
consider aromaticity.
compound iii
-when it loses Cl- and become planar, the molecule has 4n -electrons (anti-aromatic). Forming an
anti-aromatic compound really isn\'t favourable, so going from the original compound iii to this
intermediate is not an easy thing to do. Therefore, it\'s the least reactive toward SN1.
compounds i and ii
-both of these are non-aromatic through the whole reaction, so now it\'s just down to general SN1
reactivities.
-the only difference between the two compounds is that the carbon where the substitution is
going to occur is a normal secondary carbon on compound i, and an allylic carbon on compound
ii. Since allylic carbons can better stabilize positive charges, it will be more reactive toward SN1
than the simple secondary carbon.
Q6
Again with acidity. Phenol itself is going to be less acidic than the other two compounds simply
because the other two have electron-withdrawing groups on the ring that are removing electron
density from the ring and making the compound better able to stabilize a negative charge on the
oxygen (when a proton is lost).
As for comparing the two disubstituted rings, the nitro group in the meta position can stabilize
the resulting phenoxide ion by removing electron density from the ring, but the nitro group in the
para position can further stabilize the negative charge through resonance.
So the most acidic compound would be the para-disubstituted ring.
Q7
Notice that two of the three compounds listed are aromatic. That automatically makes them more
stable than cyclopentadiene. Cyclopentadiene actually is known to dimerize really quickly via
Diels-Alder reaction.
So now to compare furan and pyrrole for stability.
-both compounds have heteroatoms that have lone pairs. These lone pairs are used in the ring
system to make the rings aromatic.
-the difference between the oxygen and nitrogen donating their lone pairs to the ring system is
that the nitrogen has no free lone pairs left, whereas the oxygen still has one reactive lone pair.
-if you put these two in acid, furan will destabilize because the oxygen can pick up a proton from
the acid, with its free lone pair. The nitrogen in pyrrole is not as likely to pick up a proton.
So the most stable compound of the list is pyrrole.
btw, lone pairs in the aromatic system IS the electron delocalization
Solution
Q5
Although this question asks about SN1 reactivity, knowledge of acidity is required to answer the
question. None of the compound actually start out aromatic or anti-aromatic, but if SN1 were to
occur, the carbocation formed would make compound iii planar and thus you have to now
consider aromaticity.
compound iii
-when it loses Cl- and become planar, the molecule ha.
Portal Triad is an area in the liver named after its triangular shap.pdf
Portal Triad is an area in the liver named after its triangular shape. It has three major
components:
Solution
Portal Triad is an area in the liver named after its triangular shape. It has three major
components:.
Please find the answers and explanations belowPart 1The sequen.pdf
Please find the answers and explanations below:
Part 1:
The sequence of the partent strand is: 5’-ACCTGA TCGGACTGGA-3’. It is well known that the
two strands of DNA run anti-parallel and complementarily to each other. Thus, the sequence of
the complimentary strand will be:
3\'-TGGACTAGCCTGACCT-5\'
Part 2: In opposite orientation, the sequence of complementary strand will be:
5\'-TCCAGTCCGATCAGGT-3\'
Part 3:
The mRNA is formed complementarily to the template DNA in the 5\'-3\' direction and that the
thymidine residues are replaced by uracil. So, accordingly, the sequence of the mRNA template
will be:
3\'-UGGACUAGCCUGACCU-5\'
Part 4:
In Griffith\'s experiments, the non-encapsulated rough bacterial non-virulent colonies and
encapsulated smooth bacterial virulent colonies were used to infect mice. The mice was injected
with following preparations and their outcomes were:
1. Rough colony: Suvive
2. Smooth colony: Die
3. Heat killed smooth: Survive
4. Heat killed smooth along with live rough: Die
Thus, the mice died only on two instances, once injected with smooth virulent bacteria and
second when incubated with heat killed smooth virulent and live avirulent bacteria.
Part 5:
What Griffith found: It was very well known at that time that the bacterial capsule is responsible
for preventing lysis of the bacteria in host\'s immune system and thus leading to infection. The
incubation of heat-killed smooth virulent bacteria with rough avirulent bacteria killed the mice.
This made Griffith think that the heat-killed smooth bacteria might have somehow transformed
the non-virulent strain due to transfer of some biochemical information from the heat-killed
bacteria. The exact chemical nature of this \"transforming agent was not identified by Griffith but
it was much supposed to be protein.
Real transforming principle: The real transformation takes place when the genetic information
from one cell is transferred to the other cell where it is incorporated into its DNA and expressed
in the new cell. This does not include transfer of any proteinaceous material from one strain to
the other, but only transfer of nucleic acid takes place.
Part 6:
After Griffith\'s experiment, the trio of Avery, MacLeod and McCarty determined the correct
biochemical identity of the transforming principle. They further extended and verified the
Griffith\'s experiment. In their experimental setup, these investigators isolated following
fractions from the smooth and rough colonies:
1. Proteinaceous enzyme hydrolyzed fragment of smooth, rough and heat-killed smooth bacteria.
2. Crude proteinaceous fraction from all the three sets.
3. DNA from each set of infectants.
4. DNA fragments duly digested by deoxyribonucleodepolymerase.
These fractions were differentially used to infect the mice and they were diagnosed for disease
symptoms. It was found that mice carrying the fraction of set 1, 2 or 4 did not show any
infection. This suggested that protein was not the source of transformation. Im.
Manganese Manganese is a pinkinsh-gray, chemically active elemen.pdf
Manganese
Manganese is a pinkinsh-gray, chemically active element. It is a hard metal and is very brittle. It
is hard to melt, but easily oxidized. Manganese is reactive when pure, and as a powder it will
burn in oxygen, it reacts with water (it rusts like iron) and dissolves in dilute acids.
Manganese compounds exist naturally in the environment as solids in the soils and small
particles in the water. Manganese particles in air are present in dust particles. These usually settle
to earth within a few days.
Humans enhance manganese concentrations in the air by industrial activities and through
burning fossil fuels. Manganese that derives from human sources can also enter surface water,
groundwater and sewage water. Through the application of manganese pesticides, manganese
will enter soils.
For animals manganese is an essential component of over thirty-six enzymes that are used for
the carbohydrate, protein and fat metabolism. With animals that eat too little manganese
interference of normal growth, bone formation and reproduction will occur.
For some animals the lethal dose is quite low, which means they have little chance to survive
even smaller doses of manganese when these exceed the essential dose. Manganese substances
can cause lung, liver and vascular disturbances, declines in blood pressure, failure in
development of animal foetuses and brain damage.
When manganese uptake takes place through the skin it can cause tremors and coordination
failures. Finally, laboratory tests with test animals have shown that severe manganese poisoning
should even be able to cause tumor development with animals.
In plants manganese ions are transported to the leaves after uptake from soils. When too little
manganese can be absorbed from the soil this causes disturbances in plant mechanisms. For
instance disturbance of the division of water to hydrogen and oxygen, in which manganese plays
an important part.
Manganese can cause both toxicity and deficiency symptoms in plants. When the pH of the soil
is low manganese deficiencies are more common.
Highly toxic concentrations of manganese in soils can cause swelling of cell walls, withering of
leafs and brown spots on leaves. Deficiencies can also cause these effects. Between toxic
concentrations and concentrations that cause deficiencies a small area of concentrations for
optimal plant growth can be detected.
- Fatness
- Glucose intolerance
- Blood clotting
- Skin problems
- Lowered cholesterol levels
- Skeleton disorders
- Birth defects
- Changes of hair colour
- Neurological symptoms
Solution
Manganese
Manganese is a pinkinsh-gray, chemically active element. It is a hard metal and is very brittle. It
is hard to melt, but easily oxidized. Manganese is reactive when pure, and as a powder it will
burn in oxygen, it reacts with water (it rusts like iron) and dissolves in dilute acids.
Manganese compounds exist naturally in the environment as solids in the soils and small
particles in the water. Manganese parti.
import java.util.ArrayList; import java.util.Iterator; A.pdf
import java.util.ArrayList;
import java.util.Iterator;
/**
* A PokemonSpecies entry in the Pokedex. Maintains the number of candies associated
* with the Pokemon species as well as the Trainer\'s inventory of Pokemon of this
* species.
*/
public class PokemonSpecies {
private int pokedexNumber;
private String speciesName;
private int candies;
/**
* Maintains the list of Pokemon of this species in the Trainer\'s inventory.
*/
private ArrayList caughtPokemon;
/**
* Constructor suitable for a newly encountered Pokemon species during the course of the
* game and for loading species data from a save file.
*
* @param pokedexNumber the Pokedex Number for the species
* @param speciesName the name of the species
* @param candies the number of candies the player has obtained by catching
* or transferring Pokemon of this species
*/
public PokemonSpecies(int pokedexNumber, String speciesName, int candies) {
this.pokedexNumber = pokedexNumber;
this.speciesName = speciesName;
this.candies = candies;
// construct caughtPokemon
caughtPokemon = new ArrayList();
}
/**
* Getter methods
*/
public Integer getPokedexNumber() {
return pokedexNumber;
}
public String getSpeciesName() {
return speciesName;
}
public int getCandies() {
return candies;
}
/**
* Add a newly caught Pokemon to the player\'s inventory and
* increase the number of candies for this PokemonSpecies
*
* @param pokemon the newly caught Pokemon
*/
public void addNewPokemon(Pokemon pokemon) {
// TODO
caughtPokemon.add(pokemon);
this.candies++;
}
/**
* Helper function to load Pokemon from a save file into the player\'s inventory for this
* Pokemon Species
*
* @param pokemon the pokemon to add to this species
*/
public void loadPokemon(Pokemon pokemon) {
caughtPokemon.add(pokemon);
}
/**
* Find a Pokemon of the given combatPower in the player\'s inventory for this species.
*
* @param cp the combatPower of the Pokemon to find
* @throws PokedexException [Config.POKEMON_NOT_FOUND] if there is no Pokemon
with the
* given combatPower in the player\'s inventory.
* @return the first Pokemon with the provided combatPower
*/
public Pokemon findPokemon(int cp) throws PokedexException {
// TODO
for(int i=0;i 0){
return true;
}
return false;
}
/**
* Increment candies when a new pokemon is caught
*/
private void addNewPokemonCandies() {
this.candies += PokemonGO.NEW_POKEMON_CANDIES;
}
/**
* Increment candies when a pokemon is transferred to the professor
*/
private void addTransferCandies() {
this.candies += PokemonGO.TRANSFER_POKEMON_CANDIES;
}
/**
* Prepare a listing of all the Pokemon of this species that are currently in the
* player\'s inventory.
*
* @return a String of the form
* ...
*/
public String caughtPokemonToString() {
// TODO
return pokedexNumber+\" Name: \"+speciesName+\" Candies\"+candies;
}
/**
* Prepare a String representing this entire PokemonSpecies. This is used to
* save the PokemonSpecies (one part of the Pokedex) to a file to
* save the player\'s game.
*
* @return a String of the form
* [, ,.
Humans first evovled in the African continent. Various sub species a.pdf
Humans first evovled in the African continent. Various sub species and races evolved
indepedently. Some of this populations migrated to europe. The population which migrated to
europe is very less. So, in europe due to the continuous inbreeding, the genetic diversity is less
compared to that of the people who remained in Africa.
Solution
Humans first evovled in the African continent. Various sub species and races evolved
indepedently. Some of this populations migrated to europe. The population which migrated to
europe is very less. So, in europe due to the continuous inbreeding, the genetic diversity is less
compared to that of the people who remained in Africa..
FunctionFunctions in SQL SERVER are reusable. They can accept inpu.pdf
Function
Functions in SQL SERVER are reusable. They can accept input as parameters, perform
calculations and return the output as a value
Solution
Function
Functions in SQL SERVER are reusable. They can accept input as parameters, perform
calculations and return the output as a value.
Financial Crisis is a situation which leads to complete turmoil in a.pdf
Financial Crisis is a situation which leads to complete turmoil in an economy. The consequences
of the turmoil vary depending on whether the economy is an advanced economy or an emerging
market economy. However it should be borne in mind that in a globalized world it is rather
impossible for anyone to become unscathable from a turmoil even if it does not occur in one\'s
own economy. The ripply effect is definitely there howevery small it may be.
While the basic flow of financial crisis is the same in an advanced economy versus an emerging
economy we\'ll drill down on the basics:
1. Stages of Financial Crisis in an advanced economy:
The financial crisis is basically initiated when there is an excess of something and it goes
completely out of control. Consider the 2008 US sub-prime crisis. There were financial products
which were sold to everybody visible. These led to deterioration of the financials of the company
selling them. These companies took on an unsurmountable amount of risk and they even thought
about keeping on betting in the hope that all will be bullish. But as is with every thing. what goes
up must come down. There is a deterioration in the finances of financial institutions. There is an
increase in uncertainty. Asset prices decline massively. The problem of moral hazard comes to
the fore. Economic activity declines. There is again the same moral hazard issue. All the bubbles
of asset price reach their doomsday and there is zero visibility as to how the economy would
recover.
There is complete uncertainty in term of employment. There is large unemployment. People
have no trust in the banking system. All they want if their money back. The US government now
wanted to bail out the enstranged banks by using taxpayers money. FII\'s sell all their
investments in such country. This leads to massive slide in stock markets. People lose trillions of
dollars in their trade. The complete economy is in doldrums. There is nothing that they do. The
entire financial system comes to a screeching halt.
Once the damage has been done it takes years and a lot of Quantitative easing programmes to
propel the economy back on track. This means pumping in excess liquidity to bring banks back
in the system. Bailing out banks. Once economic activity picks up all the rock bottom asset
prices would start picking up. This would take a few years. The economy returns on track and
then the boom period starts again.
Stages of Financial Crisis in an Emerging economy:
While there are no major differences between the financial crisis stages explained for the
Advanced economy and that for the Emerging Economy, there are only a few important points to
note.
The major difference is that a crisis in emerging markets leads to the currency of that country
suffer big time against the US Dollar. This is because it loses its value relative to the dollar. The
country would take a long time to bring back the value of the currency. This would mean
pumping in excess liquidity and.
most of hydroxide salts (inorganic salts ) are in.pdf
most of hydroxide salts (inorganic salts ) are insoluble in water,due formation of
cations
Solution
most of hydroxide salts (inorganic salts ) are insoluble in water,due formation of
cations.
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an impo.pdf
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an important role in regulating
and controlling the progression of the cell through various stages of the cell cycle. They carry out
phosphorylation of other proteins and activate/deactivate them for their role in the cell cycle. But
CDKs are dependent on other proteins called cyclins for their own activation and they do not
function (cause phosphorylation) in the absence of cyclins.
After a CDK-cyclin complex has initiated a phase, the cyclin slowly degrades, inactivating the
CDK and making the cell exit that particular cellular cycle phase. Hence inhibitors and CDK
activating kinases regulate the functioning of CDKs.
For eg: CDK-4 and CDK-6 are present in the G1 phase. These are activated by the CDK-
activating kinase enzyme, which phosphorylates a particular amino acid at T-160 position in the
CDK molecule, leading to its activation. But then, inhibitors like p15and p16, when present,
prevent the binding of CDK-4 and CDK-6 with cyclin D and resultingly inactivate the complex.
This pushes the cell into the next phase.
Cell Cycle Check Points: It is a set of events in the cell cycle which make sure that the cell is in a
healthy condition to move to the next stage of the cell cycle.Basically, the cell checks if it is in
the condition to proceed in the cell cycle or not, like it checks if the DNA replication has been
completed, and if chromosomes have been well separated etc.If any defect is detected, it arrests
the cell in that particular phase and initiates repair or completion.Checkpoints function through
the activities of CDKs and cyclins only. There are 3 known check points: G1 checkpoint, G2
checkpoint and metaphase checkpoint.
For eg: The G2 checkpoint is responsible for making sure that the cell growth in the cell and
protein synthesis is complete for the initiation of mitosis phase. It is situated just before the M-
phase in the cell cycle. CDK1-cyclin B complex is responsible for progression from G2 to the M
phase. As the cell reaches the transition state, CDK1 which is usually inactive, gets activated by
Wee1 and cdc25 proteins\' action. This activated CDK1 then binds to cyclin B and initiates the
cell to enter the M phase. If any abnormality is present, p53 and p21 proteins get activated and
bind to the CDK-cyclin complex, arresting the cell in the G2 phase.
Solution
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an important role in regulating
and controlling the progression of the cell through various stages of the cell cycle. They carry out
phosphorylation of other proteins and activate/deactivate them for their role in the cell cycle. But
CDKs are dependent on other proteins called cyclins for their own activation and they do not
function (cause phosphorylation) in the absence of cyclins.
After a CDK-cyclin complex has initiated a phase, the cyclin slowly degrades, inactivating the
CDK and making the cell exit that particular cellular cycle phase. Hence .
Benefit cost ratio = Incremental cash inflows InvestmentIncremen.pdf
Benefit cost ratio = Incremental cash inflows / Investment
Incremental cash flow = 7 * 200
= 1400
Solution
Benefit cost ratio = Incremental cash inflows / Investment
Incremental cash flow = 7 * 200
= 1400.
A. Packets addressed to a unicast address are delivered to a single .pdf
A. Packets addressed to a unicast address are delivered to a single interface. Packets addressed to
a unicast address are delivered to a single interface.
Solution
A. Packets addressed to a unicast address are delivered to a single interface. Packets addressed to
a unicast address are delivered to a single interface..
a) In terms of software risk,an event is any situation or happening .pdf
a) In terms of software risk,an event is any situation or happening or real/virtual object that
causes risk which is an expectation of loss or a potential problem that may or may not occur in
the future.
a threat according to information security is a possible danger that might exploit a vulnerability
to breach security and therefore cause possible harm.
So,when a threat is in action it becomes an event .( security breach event).
b)Risk management is the process of identifying vulnerabilities and threats to the information
resources used by an organization in achieving business objectives, and deciding what
countermeasures, if any, to take in reducing risk to an acceptable level, based on the value of the
information resource to the organization. Here the information resources are called the assets.
According to Information security,an asset is any data, device, or other component of the
environment that supports information-related activities. Assets generally include hardware,
software and confidential information.Assets should be protected from illicit access, use,
disclosure, alteration, destruction, and/or theft, resulting in loss to the organization.
The goal of information security is to ensure the confidentiality, integrity and availability of
assets from various threats. For example, a hacker might attack a system in order to steal credit
card numbers by exploiting a vulnerability.
If the assests are under risk ,the organization may be driven towards losses in terms of its
business objective ( say information of customers , information regarding customer money and
transactions which affects customer loyalty , damage to infrastructure whether software or
hardware etc).So an asset is not only monetary.
We can broadly classify assets in the following categories:
1. Information assets
Every piece of information about your organization falls in this category. This information has
been collected, classified, organized and stored in various forms.
Example :
Databases: Information about your customers, personnel, production, sales, marketing, finances.
This information is critical for your business. It\'s confidentiality, integrity and availability is of
utmost importance.
Data files: Transactional data giving up-to-date information about each event.
Operational and support procedures: These have been developed over the years and provide
detailed instructions on how to perform various activities.
Archived information: Old information that may be required to be maintained by law.
Continuity plans, fallback arrangements: These would be developed to overcome any disaster
and maintain the continuity of business. Absence of these will lead to ad-hoc decisions in a
crisis.
2. Software assets
These can be divided into two categories:
a) Application software: Application software implements business rules of the organization.
Creation of application software is a time consuming task. Integrity of application software is
very important. Any flaw in t.
In Niemann-Pick disease, the deficiency of a spec.pdf
In Niemann-Pick disease, the deficiency of a specific enzyme results in the
accumulation of sphingomyelin (a product of fat metabolism) or cholesterol. Niemann-Pick
disease has several forms, depending on the severity of the enzyme deficiency, which determines
how much sphingomyelin or cholesterol accumulates. The most severe forms tend to occur in
Jewish people. The milder forms occur in all ethnic groups. Niemann-Pick disease is caused by
a buildup of sphingomyelin or cholesterol in the tissues. This disease causes many neurologic
problems. In the most severe form (type A), children fail to grow normally and have several
neurologic problems. These children usually die by age 3. Children with type B disease develop
fatty growths in the skin, areas of dark pigmentation, and an enlarged liver, spleen, and lymph
nodes. They may be intellectually disabled. Children with type C disease develop symptoms
during childhood, with seizures and neurologic deterioration. Some forms of Niemann-Pick
disease can be diagnosed in the fetus by chorionic villus sampling or amniocentesis. After birth,
the diagnosis can be made by a liver biopsy (removal of a tissue specimen for examination under
a microscope). None of the types of Niemann-Pick disease can be cured, and children tend to die
of infection or progressive dysfunction of the central nervous system. Currently, some therapies
that may slow or halt the progression of symptoms in types B and C are being studied.
Solution
In Niemann-Pick disease, the deficiency of a specific enzyme results in the
accumulation of sphingomyelin (a product of fat metabolism) or cholesterol. Niemann-Pick
disease has several forms, depending on the severity of the enzyme deficiency, which determines
how much sphingomyelin or cholesterol accumulates. The most severe forms tend to occur in
Jewish people. The milder forms occur in all ethnic groups. Niemann-Pick disease is caused by
a buildup of sphingomyelin or cholesterol in the tissues. This disease causes many neurologic
problems. In the most severe form (type A), children fail to grow normally and have several
neurologic problems. These children usually die by age 3. Children with type B disease develop
fatty growths in the skin, areas of dark pigmentation, and an enlarged liver, spleen, and lymph
nodes. They may be intellectually disabled. Children with type C disease develop symptoms
during childhood, with seizures and neurologic deterioration. Some forms of Niemann-Pick
disease can be diagnosed in the fetus by chorionic villus sampling or amniocentesis. After birth,
the diagnosis can be made by a liver biopsy (removal of a tissue specimen for examination under
a microscope). None of the types of Niemann-Pick disease can be cured, and children tend to die
of infection or progressive dysfunction of the central nervous system. Currently, some therapies
that may slow or halt the progression of symptoms in types B and C are being studied..
I cant see the image you have posted plz post it .pdf
I cant see the image you have posted plz post it again plz rate lifesver
Solution
I cant see the image you have posted plz post it again plz rate lifesver.
2.2 x 10-13the question has only 2 significant digits..therfore ro.pdf
2.2 x 10-13
the question has only 2 significant digits..therfore rounding off 2.16 to 2.2 for having two
significant digits...
Solution
2.2 x 10-13
the question has only 2 significant digits..therfore rounding off 2.16 to 2.2 for having two
significant digits....
1. H2SO4 (acid) + Ca(OH)2 (base) = CaSO4 (salt) + 2 H2O (water)2..pdf
1. H2SO4 (acid) + Ca(OH)2 (base) => CaSO4 (salt) + 2 H2O (water)
2. HBr (acid) + NH3 (base) => NH4Br (salt)
3. 2 HCl (acid) + Ba(OH)2 (base) => BaCl2 (salt) + 2 H2O (water)
Solution
1. H2SO4 (acid) + Ca(OH)2 (base) => CaSO4 (salt) + 2 H2O (water)
2. HBr (acid) + NH3 (base) => NH4Br (salt)
3. 2 HCl (acid) + Ba(OH)2 (base) => BaCl2 (salt) + 2 H2O (water).
E belong to period 6 since it has one lone pair a.pdf
E belong to period 6 since it has one lone pair and +4 oxidation state .. : E : -2 is its
anion if you dont place a lone pair then E will belong to 4rth group element so lone pair should
be placed to find its period
Solution
E belong to period 6 since it has one lone pair and +4 oxidation state .. : E : -2 is its
anion if you dont place a lone pair then E will belong to 4rth group element so lone pair should
be placed to find its period.
They conducted their study at six mangrove islands in Florida Bay co.pdf
They conducted their study at six mangrove islands in Florida Bay colonized with terrestrial
arthropods. They conducted a controlled, comparative and corelative study between the fauna
and the seasonal climatic changes. Ant Camponotus floridanus and Oxycopis species,
Brachymirmex spps., Orphaneus, Cirtoxypha confusa, etc. such other in all 24 species were
studied by them. The duration of their research was 250 days. Yes, seasonality was one of the
factors which resulted in the change in species of the ecosystem.
Solution
They conducted their study at six mangrove islands in Florida Bay colonized with terrestrial
arthropods. They conducted a controlled, comparative and corelative study between the fauna
and the seasonal climatic changes. Ant Camponotus floridanus and Oxycopis species,
Brachymirmex spps., Orphaneus, Cirtoxypha confusa, etc. such other in all 24 species were
studied by them. The duration of their research was 250 days. Yes, seasonality was one of the
factors which resulted in the change in species of the ecosystem..
Question 5.3 from the book Introduction to Java Programmin.pdf
/****
* Question 5.3 from the book Introduction to Java Programming 10th edition by Daniel Liang.
* (Conversion from kilograms to pounds) Write a program that displays the following
table (note that 1 kilogram is 2.2 pounds):\\
Kilograms Pounds
1 2.2
3 6.6
...
197 433.4
199 437.8
*/
/************* Test.java****************/
class Test {
public static void main(String args[]){
String head1 = \"Kilograms\"; //header 1 as Kilograms
String head2 = \"Pounds\"; //header 2 as Pounds
//initialization of the variables with 0
int kilograms=0;
float pounds=0;
System.out.printf( \"%-15s %15s %n\", head1, head2);// Just used for pretty printing. %-15s
means 15 chars left-justified & %15s means 15 chars right-justified
//looping for 200 times
for(int i=0;i<200;i++){
kilograms=i;
pounds=(float) (kilograms*2.2); //conversion of kilograms to pounds
System.out.printf( \"%5d %25.1f %n\", kilograms, pounds);
}
}
}
/************* end of program****************/
/**********output*************/
Kilograms Pounds
0 0.0
1 2.2
2 4.4
3 6.6
4 8.8
5 11.0
6 13.2
7 15.4
8 17.6
9 19.8
10 22.0
11 24.2
12 26.4
13 28.6
14 30.8
15 33.0
16 35.2
17 37.4
18 39.6
19 41.8
20 44.0
21 46.2
22 48.4
23 50.6
24 52.8
25 55.0
26 57.2
27 59.4
28 61.6
29 63.8
30 66.0
31 68.2
32 70.4
33 72.6
34 74.8
35 77.0
36 79.2
37 81.4
38 83.6
39 85.8
40 88.0
41 90.2
42 92.4
43 94.6
44 96.8
45 99.0
46 101.2
47 103.4
48 105.6
49 107.8
50 110.0
51 112.2
52 114.4
53 116.6
54 118.8
55 121.0
56 123.2
57 125.4
58 127.6
59 129.8
60 132.0
61 134.2
62 136.4
63 138.6
64 140.8
65 143.0
66 145.2
67 147.4
68 149.6
69 151.8
70 154.0
71 156.2
72 158.4
73 160.6
74 162.8
75 165.0
76 167.2
77 169.4
78 171.6
79 173.8
80 176.0
81 178.2
82 180.4
83 182.6
84 184.8
85 187.0
86 189.2
87 191.4
88 193.6
89 195.8
90 198.0
91 200.2
92 202.4
93 204.6
94 206.8
95 209.0
96 211.2
97 213.4
98 215.6
99 217.8
100 220.0
101 222.2
102 224.4
103 226.6
104 228.8
105 231.0
106 233.2
107 235.4
108 237.6
109 239.8
110 242.0
111 244.2
112 246.4
113 248.6
114 250.8
115 253.0
116 255.2
117 257.4
118 259.6
119 261.8
120 264.0
121 266.2
122 268.4
123 270.6
124 272.8
125 275.0
126 277.2
127 279.4
128 281.6
129 283.8
130 286.0
131 288.2
132 290.4
133 292.6
134 294.8
135 297.0
136 299.2
137 301.4
138 303.6
139 305.8
140 308.0
141 310.2
142 312.4
143 314.6
144 316.8
145 319.0
146 321.2
147 323.4
148 325.6
149 327.8
150 330.0
151 332.2
152 334.4
153 336.6
154 338.8
155 341.0
156 343.2
157 345.4
158 347.6
159 349.8
160 352.0
161 354.2
162 356.4
163 358.6
164 360.8
165 363.0
166 365.2
167 367.4
168 369.6
169 371.8
170 374.0
171 376.2
172 378.4
173 380.6
174 382.8
175 385.0
176 387.2
177 389.4
178 391.6
179 393.8
180 396.0
181 398.2
182 400.4
183 402.6
184 404.8
185 407.0
186 409.2
187 411.4
188 413.6
189 415.8
190 418.0
191 420.2
192 422.4
193 424.6
194 426.8
195 429.0
196 431.2
197 433.4
198 435.6
199 437.8
/************output ends*************/
Thanks a lot. God Bless you
Solution
/****
* Question 5.3 from the book Introduction to Java Programming 10th edit.
By using Ion chromatography we can seperate above.pdf
By using Ion chromatography we can seperate above compounds
Solution
By using Ion chromatography we can seperate above compounds.
Benzyl alcohol has a boiling point too high for t.pdf
Benzyl alcohol has a boiling point too high for this recrystallization. The fluorenol
cannot recrystallize if it is melted and its melting point is much lower than the BP of the solvent.
Solution
Benzyl alcohol has a boiling point too high for this recrystallization. The fluorenol
cannot recrystallize if it is melted and its melting point is much lower than the BP of the solvent..
How to Build a Module in Odoo 17 Using the Scaffold Method
Odoo provides an option for creating a module by using a single line command. By using this command the user can make a whole structure of a module. It is very easy for a beginner to make a module. There is no need to make each file manually. This slide will show how to create a module using the scaffold method.
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Manganese Manganese is a pinkinsh-gray, chemically active elemen.pdf
Manganese
Manganese is a pinkinsh-gray, chemically active element. It is a hard metal and is very brittle. It
is hard to melt, but easily oxidized. Manganese is reactive when pure, and as a powder it will
burn in oxygen, it reacts with water (it rusts like iron) and dissolves in dilute acids.
Manganese compounds exist naturally in the environment as solids in the soils and small
particles in the water. Manganese particles in air are present in dust particles. These usually settle
to earth within a few days.
Humans enhance manganese concentrations in the air by industrial activities and through
burning fossil fuels. Manganese that derives from human sources can also enter surface water,
groundwater and sewage water. Through the application of manganese pesticides, manganese
will enter soils.
For animals manganese is an essential component of over thirty-six enzymes that are used for
the carbohydrate, protein and fat metabolism. With animals that eat too little manganese
interference of normal growth, bone formation and reproduction will occur.
For some animals the lethal dose is quite low, which means they have little chance to survive
even smaller doses of manganese when these exceed the essential dose. Manganese substances
can cause lung, liver and vascular disturbances, declines in blood pressure, failure in
development of animal foetuses and brain damage.
When manganese uptake takes place through the skin it can cause tremors and coordination
failures. Finally, laboratory tests with test animals have shown that severe manganese poisoning
should even be able to cause tumor development with animals.
In plants manganese ions are transported to the leaves after uptake from soils. When too little
manganese can be absorbed from the soil this causes disturbances in plant mechanisms. For
instance disturbance of the division of water to hydrogen and oxygen, in which manganese plays
an important part.
Manganese can cause both toxicity and deficiency symptoms in plants. When the pH of the soil
is low manganese deficiencies are more common.
Highly toxic concentrations of manganese in soils can cause swelling of cell walls, withering of
leafs and brown spots on leaves. Deficiencies can also cause these effects. Between toxic
concentrations and concentrations that cause deficiencies a small area of concentrations for
optimal plant growth can be detected.
- Fatness
- Glucose intolerance
- Blood clotting
- Skin problems
- Lowered cholesterol levels
- Skeleton disorders
- Birth defects
- Changes of hair colour
- Neurological symptoms
Solution
Manganese
Manganese is a pinkinsh-gray, chemically active element. It is a hard metal and is very brittle. It
is hard to melt, but easily oxidized. Manganese is reactive when pure, and as a powder it will
burn in oxygen, it reacts with water (it rusts like iron) and dissolves in dilute acids.
Manganese compounds exist naturally in the environment as solids in the soils and small
particles in the water. Manganese parti.
import java.util.ArrayList; import java.util.Iterator; A.pdf
import java.util.ArrayList;
import java.util.Iterator;
/**
* A PokemonSpecies entry in the Pokedex. Maintains the number of candies associated
* with the Pokemon species as well as the Trainer\'s inventory of Pokemon of this
* species.
*/
public class PokemonSpecies {
private int pokedexNumber;
private String speciesName;
private int candies;
/**
* Maintains the list of Pokemon of this species in the Trainer\'s inventory.
*/
private ArrayList caughtPokemon;
/**
* Constructor suitable for a newly encountered Pokemon species during the course of the
* game and for loading species data from a save file.
*
* @param pokedexNumber the Pokedex Number for the species
* @param speciesName the name of the species
* @param candies the number of candies the player has obtained by catching
* or transferring Pokemon of this species
*/
public PokemonSpecies(int pokedexNumber, String speciesName, int candies) {
this.pokedexNumber = pokedexNumber;
this.speciesName = speciesName;
this.candies = candies;
// construct caughtPokemon
caughtPokemon = new ArrayList();
}
/**
* Getter methods
*/
public Integer getPokedexNumber() {
return pokedexNumber;
}
public String getSpeciesName() {
return speciesName;
}
public int getCandies() {
return candies;
}
/**
* Add a newly caught Pokemon to the player\'s inventory and
* increase the number of candies for this PokemonSpecies
*
* @param pokemon the newly caught Pokemon
*/
public void addNewPokemon(Pokemon pokemon) {
// TODO
caughtPokemon.add(pokemon);
this.candies++;
}
/**
* Helper function to load Pokemon from a save file into the player\'s inventory for this
* Pokemon Species
*
* @param pokemon the pokemon to add to this species
*/
public void loadPokemon(Pokemon pokemon) {
caughtPokemon.add(pokemon);
}
/**
* Find a Pokemon of the given combatPower in the player\'s inventory for this species.
*
* @param cp the combatPower of the Pokemon to find
* @throws PokedexException [Config.POKEMON_NOT_FOUND] if there is no Pokemon
with the
* given combatPower in the player\'s inventory.
* @return the first Pokemon with the provided combatPower
*/
public Pokemon findPokemon(int cp) throws PokedexException {
// TODO
for(int i=0;i 0){
return true;
}
return false;
}
/**
* Increment candies when a new pokemon is caught
*/
private void addNewPokemonCandies() {
this.candies += PokemonGO.NEW_POKEMON_CANDIES;
}
/**
* Increment candies when a pokemon is transferred to the professor
*/
private void addTransferCandies() {
this.candies += PokemonGO.TRANSFER_POKEMON_CANDIES;
}
/**
* Prepare a listing of all the Pokemon of this species that are currently in the
* player\'s inventory.
*
* @return a String of the form
* ...
*/
public String caughtPokemonToString() {
// TODO
return pokedexNumber+\" Name: \"+speciesName+\" Candies\"+candies;
}
/**
* Prepare a String representing this entire PokemonSpecies. This is used to
* save the PokemonSpecies (one part of the Pokedex) to a file to
* save the player\'s game.
*
* @return a String of the form
* [, ,.
Humans first evovled in the African continent. Various sub species a.pdf
Humans first evovled in the African continent. Various sub species and races evolved
indepedently. Some of this populations migrated to europe. The population which migrated to
europe is very less. So, in europe due to the continuous inbreeding, the genetic diversity is less
compared to that of the people who remained in Africa.
Solution
Humans first evovled in the African continent. Various sub species and races evolved
indepedently. Some of this populations migrated to europe. The population which migrated to
europe is very less. So, in europe due to the continuous inbreeding, the genetic diversity is less
compared to that of the people who remained in Africa..
FunctionFunctions in SQL SERVER are reusable. They can accept inpu.pdf
Function
Functions in SQL SERVER are reusable. They can accept input as parameters, perform
calculations and return the output as a value
Solution
Function
Functions in SQL SERVER are reusable. They can accept input as parameters, perform
calculations and return the output as a value.
Financial Crisis is a situation which leads to complete turmoil in a.pdf
Financial Crisis is a situation which leads to complete turmoil in an economy. The consequences
of the turmoil vary depending on whether the economy is an advanced economy or an emerging
market economy. However it should be borne in mind that in a globalized world it is rather
impossible for anyone to become unscathable from a turmoil even if it does not occur in one\'s
own economy. The ripply effect is definitely there howevery small it may be.
While the basic flow of financial crisis is the same in an advanced economy versus an emerging
economy we\'ll drill down on the basics:
1. Stages of Financial Crisis in an advanced economy:
The financial crisis is basically initiated when there is an excess of something and it goes
completely out of control. Consider the 2008 US sub-prime crisis. There were financial products
which were sold to everybody visible. These led to deterioration of the financials of the company
selling them. These companies took on an unsurmountable amount of risk and they even thought
about keeping on betting in the hope that all will be bullish. But as is with every thing. what goes
up must come down. There is a deterioration in the finances of financial institutions. There is an
increase in uncertainty. Asset prices decline massively. The problem of moral hazard comes to
the fore. Economic activity declines. There is again the same moral hazard issue. All the bubbles
of asset price reach their doomsday and there is zero visibility as to how the economy would
recover.
There is complete uncertainty in term of employment. There is large unemployment. People
have no trust in the banking system. All they want if their money back. The US government now
wanted to bail out the enstranged banks by using taxpayers money. FII\'s sell all their
investments in such country. This leads to massive slide in stock markets. People lose trillions of
dollars in their trade. The complete economy is in doldrums. There is nothing that they do. The
entire financial system comes to a screeching halt.
Once the damage has been done it takes years and a lot of Quantitative easing programmes to
propel the economy back on track. This means pumping in excess liquidity to bring banks back
in the system. Bailing out banks. Once economic activity picks up all the rock bottom asset
prices would start picking up. This would take a few years. The economy returns on track and
then the boom period starts again.
Stages of Financial Crisis in an Emerging economy:
While there are no major differences between the financial crisis stages explained for the
Advanced economy and that for the Emerging Economy, there are only a few important points to
note.
The major difference is that a crisis in emerging markets leads to the currency of that country
suffer big time against the US Dollar. This is because it loses its value relative to the dollar. The
country would take a long time to bring back the value of the currency. This would mean
pumping in excess liquidity and.
most of hydroxide salts (inorganic salts ) are in.pdf
most of hydroxide salts (inorganic salts ) are insoluble in water,due formation of
cations
Solution
most of hydroxide salts (inorganic salts ) are insoluble in water,due formation of
cations.
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an impo.pdf
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an important role in regulating
and controlling the progression of the cell through various stages of the cell cycle. They carry out
phosphorylation of other proteins and activate/deactivate them for their role in the cell cycle. But
CDKs are dependent on other proteins called cyclins for their own activation and they do not
function (cause phosphorylation) in the absence of cyclins.
After a CDK-cyclin complex has initiated a phase, the cyclin slowly degrades, inactivating the
CDK and making the cell exit that particular cellular cycle phase. Hence inhibitors and CDK
activating kinases regulate the functioning of CDKs.
For eg: CDK-4 and CDK-6 are present in the G1 phase. These are activated by the CDK-
activating kinase enzyme, which phosphorylates a particular amino acid at T-160 position in the
CDK molecule, leading to its activation. But then, inhibitors like p15and p16, when present,
prevent the binding of CDK-4 and CDK-6 with cyclin D and resultingly inactivate the complex.
This pushes the cell into the next phase.
Cell Cycle Check Points: It is a set of events in the cell cycle which make sure that the cell is in a
healthy condition to move to the next stage of the cell cycle.Basically, the cell checks if it is in
the condition to proceed in the cell cycle or not, like it checks if the DNA replication has been
completed, and if chromosomes have been well separated etc.If any defect is detected, it arrests
the cell in that particular phase and initiates repair or completion.Checkpoints function through
the activities of CDKs and cyclins only. There are 3 known check points: G1 checkpoint, G2
checkpoint and metaphase checkpoint.
For eg: The G2 checkpoint is responsible for making sure that the cell growth in the cell and
protein synthesis is complete for the initiation of mitosis phase. It is situated just before the M-
phase in the cell cycle. CDK1-cyclin B complex is responsible for progression from G2 to the M
phase. As the cell reaches the transition state, CDK1 which is usually inactive, gets activated by
Wee1 and cdc25 proteins\' action. This activated CDK1 then binds to cyclin B and initiates the
cell to enter the M phase. If any abnormality is present, p53 and p21 proteins get activated and
bind to the CDK-cyclin complex, arresting the cell in the G2 phase.
Solution
CDKs (Cyclin-dependent Phosphokinases) are enzymes that play an important role in regulating
and controlling the progression of the cell through various stages of the cell cycle. They carry out
phosphorylation of other proteins and activate/deactivate them for their role in the cell cycle. But
CDKs are dependent on other proteins called cyclins for their own activation and they do not
function (cause phosphorylation) in the absence of cyclins.
After a CDK-cyclin complex has initiated a phase, the cyclin slowly degrades, inactivating the
CDK and making the cell exit that particular cellular cycle phase. Hence .
Benefit cost ratio = Incremental cash inflows InvestmentIncremen.pdf
Benefit cost ratio = Incremental cash inflows / Investment
Incremental cash flow = 7 * 200
= 1400
Solution
Benefit cost ratio = Incremental cash inflows / Investment
Incremental cash flow = 7 * 200
= 1400.
A. Packets addressed to a unicast address are delivered to a single .pdf
A. Packets addressed to a unicast address are delivered to a single interface. Packets addressed to
a unicast address are delivered to a single interface.
Solution
A. Packets addressed to a unicast address are delivered to a single interface. Packets addressed to
a unicast address are delivered to a single interface..
a) In terms of software risk,an event is any situation or happening .pdf
a) In terms of software risk,an event is any situation or happening or real/virtual object that
causes risk which is an expectation of loss or a potential problem that may or may not occur in
the future.
a threat according to information security is a possible danger that might exploit a vulnerability
to breach security and therefore cause possible harm.
So,when a threat is in action it becomes an event .( security breach event).
b)Risk management is the process of identifying vulnerabilities and threats to the information
resources used by an organization in achieving business objectives, and deciding what
countermeasures, if any, to take in reducing risk to an acceptable level, based on the value of the
information resource to the organization. Here the information resources are called the assets.
According to Information security,an asset is any data, device, or other component of the
environment that supports information-related activities. Assets generally include hardware,
software and confidential information.Assets should be protected from illicit access, use,
disclosure, alteration, destruction, and/or theft, resulting in loss to the organization.
The goal of information security is to ensure the confidentiality, integrity and availability of
assets from various threats. For example, a hacker might attack a system in order to steal credit
card numbers by exploiting a vulnerability.
If the assests are under risk ,the organization may be driven towards losses in terms of its
business objective ( say information of customers , information regarding customer money and
transactions which affects customer loyalty , damage to infrastructure whether software or
hardware etc).So an asset is not only monetary.
We can broadly classify assets in the following categories:
1. Information assets
Every piece of information about your organization falls in this category. This information has
been collected, classified, organized and stored in various forms.
Example :
Databases: Information about your customers, personnel, production, sales, marketing, finances.
This information is critical for your business. It\'s confidentiality, integrity and availability is of
utmost importance.
Data files: Transactional data giving up-to-date information about each event.
Operational and support procedures: These have been developed over the years and provide
detailed instructions on how to perform various activities.
Archived information: Old information that may be required to be maintained by law.
Continuity plans, fallback arrangements: These would be developed to overcome any disaster
and maintain the continuity of business. Absence of these will lead to ad-hoc decisions in a
crisis.
2. Software assets
These can be divided into two categories:
a) Application software: Application software implements business rules of the organization.
Creation of application software is a time consuming task. Integrity of application software is
very important. Any flaw in t.
In Niemann-Pick disease, the deficiency of a spec.pdf
In Niemann-Pick disease, the deficiency of a specific enzyme results in the
accumulation of sphingomyelin (a product of fat metabolism) or cholesterol. Niemann-Pick
disease has several forms, depending on the severity of the enzyme deficiency, which determines
how much sphingomyelin or cholesterol accumulates. The most severe forms tend to occur in
Jewish people. The milder forms occur in all ethnic groups. Niemann-Pick disease is caused by
a buildup of sphingomyelin or cholesterol in the tissues. This disease causes many neurologic
problems. In the most severe form (type A), children fail to grow normally and have several
neurologic problems. These children usually die by age 3. Children with type B disease develop
fatty growths in the skin, areas of dark pigmentation, and an enlarged liver, spleen, and lymph
nodes. They may be intellectually disabled. Children with type C disease develop symptoms
during childhood, with seizures and neurologic deterioration. Some forms of Niemann-Pick
disease can be diagnosed in the fetus by chorionic villus sampling or amniocentesis. After birth,
the diagnosis can be made by a liver biopsy (removal of a tissue specimen for examination under
a microscope). None of the types of Niemann-Pick disease can be cured, and children tend to die
of infection or progressive dysfunction of the central nervous system. Currently, some therapies
that may slow or halt the progression of symptoms in types B and C are being studied.
Solution
In Niemann-Pick disease, the deficiency of a specific enzyme results in the
accumulation of sphingomyelin (a product of fat metabolism) or cholesterol. Niemann-Pick
disease has several forms, depending on the severity of the enzyme deficiency, which determines
how much sphingomyelin or cholesterol accumulates. The most severe forms tend to occur in
Jewish people. The milder forms occur in all ethnic groups. Niemann-Pick disease is caused by
a buildup of sphingomyelin or cholesterol in the tissues. This disease causes many neurologic
problems. In the most severe form (type A), children fail to grow normally and have several
neurologic problems. These children usually die by age 3. Children with type B disease develop
fatty growths in the skin, areas of dark pigmentation, and an enlarged liver, spleen, and lymph
nodes. They may be intellectually disabled. Children with type C disease develop symptoms
during childhood, with seizures and neurologic deterioration. Some forms of Niemann-Pick
disease can be diagnosed in the fetus by chorionic villus sampling or amniocentesis. After birth,
the diagnosis can be made by a liver biopsy (removal of a tissue specimen for examination under
a microscope). None of the types of Niemann-Pick disease can be cured, and children tend to die
of infection or progressive dysfunction of the central nervous system. Currently, some therapies
that may slow or halt the progression of symptoms in types B and C are being studied..
I cant see the image you have posted plz post it .pdf
I cant see the image you have posted plz post it again plz rate lifesver
Solution
I cant see the image you have posted plz post it again plz rate lifesver.
2.2 x 10-13the question has only 2 significant digits..therfore ro.pdf
2.2 x 10-13
the question has only 2 significant digits..therfore rounding off 2.16 to 2.2 for having two
significant digits...
Solution
2.2 x 10-13
the question has only 2 significant digits..therfore rounding off 2.16 to 2.2 for having two
significant digits....
1. H2SO4 (acid) + Ca(OH)2 (base) = CaSO4 (salt) + 2 H2O (water)2..pdf
1. H2SO4 (acid) + Ca(OH)2 (base) => CaSO4 (salt) + 2 H2O (water)
2. HBr (acid) + NH3 (base) => NH4Br (salt)
3. 2 HCl (acid) + Ba(OH)2 (base) => BaCl2 (salt) + 2 H2O (water)
Solution
1. H2SO4 (acid) + Ca(OH)2 (base) => CaSO4 (salt) + 2 H2O (water)
2. HBr (acid) + NH3 (base) => NH4Br (salt)
3. 2 HCl (acid) + Ba(OH)2 (base) => BaCl2 (salt) + 2 H2O (water).
E belong to period 6 since it has one lone pair a.pdf
E belong to period 6 since it has one lone pair and +4 oxidation state .. : E : -2 is its
anion if you dont place a lone pair then E will belong to 4rth group element so lone pair should
be placed to find its period
Solution
E belong to period 6 since it has one lone pair and +4 oxidation state .. : E : -2 is its
anion if you dont place a lone pair then E will belong to 4rth group element so lone pair should
be placed to find its period.
They conducted their study at six mangrove islands in Florida Bay co.pdf
They conducted their study at six mangrove islands in Florida Bay colonized with terrestrial
arthropods. They conducted a controlled, comparative and corelative study between the fauna
and the seasonal climatic changes. Ant Camponotus floridanus and Oxycopis species,
Brachymirmex spps., Orphaneus, Cirtoxypha confusa, etc. such other in all 24 species were
studied by them. The duration of their research was 250 days. Yes, seasonality was one of the
factors which resulted in the change in species of the ecosystem.
Solution
They conducted their study at six mangrove islands in Florida Bay colonized with terrestrial
arthropods. They conducted a controlled, comparative and corelative study between the fauna
and the seasonal climatic changes. Ant Camponotus floridanus and Oxycopis species,
Brachymirmex spps., Orphaneus, Cirtoxypha confusa, etc. such other in all 24 species were
studied by them. The duration of their research was 250 days. Yes, seasonality was one of the
factors which resulted in the change in species of the ecosystem..
Question 5.3 from the book Introduction to Java Programmin.pdf
/****
* Question 5.3 from the book Introduction to Java Programming 10th edition by Daniel Liang.
* (Conversion from kilograms to pounds) Write a program that displays the following
table (note that 1 kilogram is 2.2 pounds):\\
Kilograms Pounds
1 2.2
3 6.6
...
197 433.4
199 437.8
*/
/************* Test.java****************/
class Test {
public static void main(String args[]){
String head1 = \"Kilograms\"; //header 1 as Kilograms
String head2 = \"Pounds\"; //header 2 as Pounds
//initialization of the variables with 0
int kilograms=0;
float pounds=0;
System.out.printf( \"%-15s %15s %n\", head1, head2);// Just used for pretty printing. %-15s
means 15 chars left-justified & %15s means 15 chars right-justified
//looping for 200 times
for(int i=0;i<200;i++){
kilograms=i;
pounds=(float) (kilograms*2.2); //conversion of kilograms to pounds
System.out.printf( \"%5d %25.1f %n\", kilograms, pounds);
}
}
}
/************* end of program****************/
/**********output*************/
Kilograms Pounds
0 0.0
1 2.2
2 4.4
3 6.6
4 8.8
5 11.0
6 13.2
7 15.4
8 17.6
9 19.8
10 22.0
11 24.2
12 26.4
13 28.6
14 30.8
15 33.0
16 35.2
17 37.4
18 39.6
19 41.8
20 44.0
21 46.2
22 48.4
23 50.6
24 52.8
25 55.0
26 57.2
27 59.4
28 61.6
29 63.8
30 66.0
31 68.2
32 70.4
33 72.6
34 74.8
35 77.0
36 79.2
37 81.4
38 83.6
39 85.8
40 88.0
41 90.2
42 92.4
43 94.6
44 96.8
45 99.0
46 101.2
47 103.4
48 105.6
49 107.8
50 110.0
51 112.2
52 114.4
53 116.6
54 118.8
55 121.0
56 123.2
57 125.4
58 127.6
59 129.8
60 132.0
61 134.2
62 136.4
63 138.6
64 140.8
65 143.0
66 145.2
67 147.4
68 149.6
69 151.8
70 154.0
71 156.2
72 158.4
73 160.6
74 162.8
75 165.0
76 167.2
77 169.4
78 171.6
79 173.8
80 176.0
81 178.2
82 180.4
83 182.6
84 184.8
85 187.0
86 189.2
87 191.4
88 193.6
89 195.8
90 198.0
91 200.2
92 202.4
93 204.6
94 206.8
95 209.0
96 211.2
97 213.4
98 215.6
99 217.8
100 220.0
101 222.2
102 224.4
103 226.6
104 228.8
105 231.0
106 233.2
107 235.4
108 237.6
109 239.8
110 242.0
111 244.2
112 246.4
113 248.6
114 250.8
115 253.0
116 255.2
117 257.4
118 259.6
119 261.8
120 264.0
121 266.2
122 268.4
123 270.6
124 272.8
125 275.0
126 277.2
127 279.4
128 281.6
129 283.8
130 286.0
131 288.2
132 290.4
133 292.6
134 294.8
135 297.0
136 299.2
137 301.4
138 303.6
139 305.8
140 308.0
141 310.2
142 312.4
143 314.6
144 316.8
145 319.0
146 321.2
147 323.4
148 325.6
149 327.8
150 330.0
151 332.2
152 334.4
153 336.6
154 338.8
155 341.0
156 343.2
157 345.4
158 347.6
159 349.8
160 352.0
161 354.2
162 356.4
163 358.6
164 360.8
165 363.0
166 365.2
167 367.4
168 369.6
169 371.8
170 374.0
171 376.2
172 378.4
173 380.6
174 382.8
175 385.0
176 387.2
177 389.4
178 391.6
179 393.8
180 396.0
181 398.2
182 400.4
183 402.6
184 404.8
185 407.0
186 409.2
187 411.4
188 413.6
189 415.8
190 418.0
191 420.2
192 422.4
193 424.6
194 426.8
195 429.0
196 431.2
197 433.4
198 435.6
199 437.8
/************output ends*************/
Thanks a lot. God Bless you
Solution
/****
* Question 5.3 from the book Introduction to Java Programming 10th edit.
By using Ion chromatography we can seperate above.pdf
By using Ion chromatography we can seperate above compounds
Solution
By using Ion chromatography we can seperate above compounds.
Benzyl alcohol has a boiling point too high for t.pdf
Benzyl alcohol has a boiling point too high for this recrystallization. The fluorenol
cannot recrystallize if it is melted and its melting point is much lower than the BP of the solvent.
Solution
Benzyl alcohol has a boiling point too high for this recrystallization. The fluorenol
cannot recrystallize if it is melted and its melting point is much lower than the BP of the solvent..
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