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MATHEMATICS
DIGITAL TEXT BOOK
CLASSIX
submittedby,
AKHILA.V.V
B.Ed. Mathematics
18014376002Chapter 1
POLYGONS
A triangle hasthree sidesthree angles;aquadrilateral hasfour.
A Pentagonisa figure of five sidesandfive angles;six sides andsix anglesfromahexagon.
There are othernameslike this:a figure of sevensidesandanglesiscalledaheptagon;andof eight
sidesand,an octagon.There isa commonname forall these together:Polygons.
Sumof the angles
We knowthatthe sumof the anglesof a trianlesis1800 andthat the sum of the anglesof a
quadriateral is3600.
To compute the sum of the anglesof a pentagon.SplititintoPOLYGONS
Sumof the angles
Exteriorangles
Regularpolygons
2: PAIRSOFEQUATIONS
Algebraicdescription
Unificationquadriateral andtriangle.
Sumof the anglesof the pentagon
= sumof the anglesof the quadriateral
+ sumof the anglesof the triangle
= 3600+1800
= 5400
Generallyspeaking,we candivide anypolygon intopreviouspolygon(meaningone sideless)anda
triangle;andso itssumof angleswill be 1800 more thanthe sumof the anglesof the previousone.
Thus we have a sheme forcomputingthe sumof the anglesof polygon:
Triangle1800
Quadriateral 1800 +1800 = 2x1800
Pentagon 1800 +(2x1800) = 3x1800Hexagon 1800 +(3x1800) = 4x1800
................... .............................................
................... .............................................
................... .............................................
F The sumof the anglesof an sidedpolygonis(n-2) x 1800
Can youfindthe answersto these questions?
. The sum of the anglesof polygonis21600. What is the sum of the anglesof polygonwithone
more side?Whatabout a polygonwithone side less?
. What isthe sumof the anglesof polygonwith102 sides?
Exteriorangles
Look at thisfigure: Regularpolygons
Polygons,withequal anglesandlengthof side alsoequal are calledregularpolygons.
The figure belowshowaregular pentagonanda regularhexagon: Prove that the linesADandBD
divide ÐCDEintothe equal parts.
Since ÐCDE is angle of a regularpentagon,itisequal to1080,as seenearlies.
So,what isit that we wantto prove?
We needonlyshowthateachof ÐEDA, ÐADB andÐBDC is360.
How dowe findÐEDA?
It isan angle of DAED.What all thingsdo we know aboutthistriangle?
We haveÐAED= 1800
sinceitisangle of a regularpentagon.
So,
ÐEDA + ÐEAD = 1800 - 1080 = 720
Also,inthistriangle AE= ED (why?)
So,
ÐEDA = ÐEAD
We are earlierthatthe sum of these equal anglesi 720 So,each mustbe 300. Thus
ÐEDA = 360
Usingthe same argumentinDABCD,we get
ÐCDB = 360
(Try it)
Nowif we use the fact that
ÐEDA + ÐADB + ÐCDB = ÐEDC = 1080 andthat
ÐEDA = 300 = ÐCDB
We can easilyget
ÐADB = 360
Here are some problemsforyou:
. How muchis eachangle of a 12- sidesregularpolygon?
How muchis eachof itsextentangle?
. In the figure belowABCDEFisregularhexagon. Chapter2
PAIRSOF EQUATIONS
Let’sstart with a problemwhichyoucanddo in yourhead:
. The booksof the sameprice anda penfor five rupeeswere boughtforthirtyfive rupees.Whatis
the price of one book?
Look at thisproblem:
. Four chairsof the same price and a table for3150 rupeeswere boughtfor4950 rupees.Whatis
the price of a chair?
Here alsowe can mentallyworkoutthe steps;butforthe actual computationwe needpenand
paper,right?
Price of four chairs= 4950 - 3150 = Rs. 1800
Price of one chair = 1800 = Rs. 450
4
Algebraicdescription
Suppose we are toldthis:
The perimeterof a rectangle is20 centimetres.
Usingthis factalone,can we findthe lengthandbreath?
If we denote the lengthbyx andthe breadthby y, then
2 (x+y) = 20
and simplifythis,we get
x+y = 10
From this,we cannotfindthe lengthandbreadth.
Nowsuppose we knowone more factabout the lengthandbreadth:
Lengthe isI centimetre more thanbreadth.
Thisalsowe can write inalgebra,usingourearliernotation:
x = y+1
Nowcan we findlengthandbreadth?Forthat we must findthe numbersx andy such that boththe
equations
x + y = 10
x = y + 1
are true
By the secondequation,the numberx andy +1 are the same;andby the firstequation,the sumof the
numbersx andyis 10. So,the sum of the numbersy+1 and y is10.
That is
(y+ 1) + y = 10
From this,we get
2y + 1 = 10
and so
y = 10-1 = 4.5
2
Thus the breadthis4.5 centimetres.
What baoutthe length?
Since x + y = 10, we find
x = 10 - y = 10 - 4.5 = 5.5
so,the lengthis 5.5 centimetres
Nowtry these problems.
. Th numberof girlsin a classis 4 more thanthe numberof boys.Onaday whenonly8 boyswere
absent,the numberof girlswere double the numberof boys.How manygirlsand boysare there inthe
class?
. Th price of a table anda chair togetheris2500 rupees.The price of 3 tablesand4 chairsof this
kindis8000 rupees.Whatis the price of each.
Unification
Look at thisbroble:
The price od 2 pensand 3 note booksis 29 rupees;for2 pensand 5 note books,itis43. What is
the price of each?
Denotingthe price of a penby x and the price of a note bookby,ye,we can the givenpiecesof
informationtofromthe equations
2x + 3y = 29
2x + 5y = 43
Nowthese are to be combinedtoa single equationwithonlyone letter. So,subtracting29from 43 is
the same subtracting2x + 3y from2x+5y)
That is
(2x+ 5y) - (2x + 3y) = 43- 29,
Simplyfyingthis,we get
2y =14
fromwhichwe get
y = 7
Now, fromthe firstequation,we canfind
2x=29- 3y = 29 - (3x7) 8
and thisgives
x = 4
Nowtry these problemonyourown:
. Some autotrikshawsandbikesare parkedin a place.
These are 19 in all.The total numberof wheelsis45.
How manyof eachvehicle are there?
. Four timesanumberaddedto thrice anothernumbergives43.Twice the secondnumber,
substractedfromthrice the firstgives11. What are the numbers?

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DIGITAL TEXT BOOK

  • 1. MATHEMATICS DIGITAL TEXT BOOK CLASSIX submittedby, AKHILA.V.V B.Ed. Mathematics 18014376002Chapter 1 POLYGONS A triangle hasthree sidesthree angles;aquadrilateral hasfour. A Pentagonisa figure of five sidesandfive angles;six sides andsix anglesfromahexagon.
  • 2. There are othernameslike this:a figure of sevensidesandanglesiscalledaheptagon;andof eight sidesand,an octagon.There isa commonname forall these together:Polygons. Sumof the angles We knowthatthe sumof the anglesof a trianlesis1800 andthat the sum of the anglesof a quadriateral is3600. To compute the sum of the anglesof a pentagon.SplititintoPOLYGONS Sumof the angles Exteriorangles Regularpolygons 2: PAIRSOFEQUATIONS Algebraicdescription Unificationquadriateral andtriangle.
  • 3. Sumof the anglesof the pentagon = sumof the anglesof the quadriateral + sumof the anglesof the triangle = 3600+1800 = 5400 Generallyspeaking,we candivide anypolygon intopreviouspolygon(meaningone sideless)anda triangle;andso itssumof angleswill be 1800 more thanthe sumof the anglesof the previousone. Thus we have a sheme forcomputingthe sumof the anglesof polygon: Triangle1800 Quadriateral 1800 +1800 = 2x1800 Pentagon 1800 +(2x1800) = 3x1800Hexagon 1800 +(3x1800) = 4x1800 ................... ............................................. ................... ............................................. ................... ............................................. F The sumof the anglesof an sidedpolygonis(n-2) x 1800 Can youfindthe answersto these questions? . The sum of the anglesof polygonis21600. What is the sum of the anglesof polygonwithone more side?Whatabout a polygonwithone side less? . What isthe sumof the anglesof polygonwith102 sides? Exteriorangles Look at thisfigure: Regularpolygons Polygons,withequal anglesandlengthof side alsoequal are calledregularpolygons. The figure belowshowaregular pentagonanda regularhexagon: Prove that the linesADandBD divide ÐCDEintothe equal parts. Since ÐCDE is angle of a regularpentagon,itisequal to1080,as seenearlies.
  • 4. So,what isit that we wantto prove? We needonlyshowthateachof ÐEDA, ÐADB andÐBDC is360. How dowe findÐEDA? It isan angle of DAED.What all thingsdo we know aboutthistriangle? We haveÐAED= 1800 sinceitisangle of a regularpentagon. So, ÐEDA + ÐEAD = 1800 - 1080 = 720 Also,inthistriangle AE= ED (why?) So, ÐEDA = ÐEAD We are earlierthatthe sum of these equal anglesi 720 So,each mustbe 300. Thus ÐEDA = 360 Usingthe same argumentinDABCD,we get ÐCDB = 360 (Try it) Nowif we use the fact that ÐEDA + ÐADB + ÐCDB = ÐEDC = 1080 andthat ÐEDA = 300 = ÐCDB We can easilyget ÐADB = 360 Here are some problemsforyou: . How muchis eachangle of a 12- sidesregularpolygon? How muchis eachof itsextentangle? . In the figure belowABCDEFisregularhexagon. Chapter2
  • 5. PAIRSOF EQUATIONS Let’sstart with a problemwhichyoucanddo in yourhead: . The booksof the sameprice anda penfor five rupeeswere boughtforthirtyfive rupees.Whatis the price of one book? Look at thisproblem: . Four chairsof the same price and a table for3150 rupeeswere boughtfor4950 rupees.Whatis the price of a chair? Here alsowe can mentallyworkoutthe steps;butforthe actual computationwe needpenand paper,right? Price of four chairs= 4950 - 3150 = Rs. 1800 Price of one chair = 1800 = Rs. 450 4 Algebraicdescription Suppose we are toldthis: The perimeterof a rectangle is20 centimetres. Usingthis factalone,can we findthe lengthandbreath? If we denote the lengthbyx andthe breadthby y, then 2 (x+y) = 20 and simplifythis,we get x+y = 10 From this,we cannotfindthe lengthandbreadth. Nowsuppose we knowone more factabout the lengthandbreadth: Lengthe isI centimetre more thanbreadth. Thisalsowe can write inalgebra,usingourearliernotation: x = y+1
  • 6. Nowcan we findlengthandbreadth?Forthat we must findthe numbersx andy such that boththe equations x + y = 10 x = y + 1 are true By the secondequation,the numberx andy +1 are the same;andby the firstequation,the sumof the numbersx andyis 10. So,the sum of the numbersy+1 and y is10. That is (y+ 1) + y = 10 From this,we get 2y + 1 = 10 and so y = 10-1 = 4.5 2 Thus the breadthis4.5 centimetres. What baoutthe length? Since x + y = 10, we find x = 10 - y = 10 - 4.5 = 5.5 so,the lengthis 5.5 centimetres Nowtry these problems. . Th numberof girlsin a classis 4 more thanthe numberof boys.Onaday whenonly8 boyswere absent,the numberof girlswere double the numberof boys.How manygirlsand boysare there inthe class? . Th price of a table anda chair togetheris2500 rupees.The price of 3 tablesand4 chairsof this kindis8000 rupees.Whatis the price of each. Unification
  • 7. Look at thisbroble: The price od 2 pensand 3 note booksis 29 rupees;for2 pensand 5 note books,itis43. What is the price of each? Denotingthe price of a penby x and the price of a note bookby,ye,we can the givenpiecesof informationtofromthe equations 2x + 3y = 29 2x + 5y = 43 Nowthese are to be combinedtoa single equationwithonlyone letter. So,subtracting29from 43 is the same subtracting2x + 3y from2x+5y) That is (2x+ 5y) - (2x + 3y) = 43- 29, Simplyfyingthis,we get 2y =14 fromwhichwe get y = 7 Now, fromthe firstequation,we canfind 2x=29- 3y = 29 - (3x7) 8 and thisgives x = 4 Nowtry these problemonyourown: . Some autotrikshawsandbikesare parkedin a place. These are 19 in all.The total numberof wheelsis45. How manyof eachvehicle are there? . Four timesanumberaddedto thrice anothernumbergives43.Twice the secondnumber, substractedfromthrice the firstgives11. What are the numbers?