Quantitative Analysis for Management
Fourteenth Edition
Chapter 3
Decision Analysis
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Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Learning Objectives (1 of 2)
After completing this chapter, students will be able to:
3.1 List the steps of the decision-making process.
3.2 Describe the types of decision-making environments.
3.3 Make decisions under uncertainty.
3.4 Use probability values to make decisions under risk.
3.5 Use computers to solve basic decision-making
problems.
3.6 Develop accurate and useful decision trees.
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Learning Objectives (2 of 2)
3.7 Revise probability estimates using Bayesian analysis.
3.8 Understand the importance and use of utility theory in
decision making.
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Introduction
Decision theory is an analytic and systematic approach
to the study of decision making
What is involved in making a good decision?
A good decision is one that is based on logic, considers all
available data and possible alternatives, and applies a
quantitative approach
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The Six Steps in Decision Making
1. Clearly define the problem at hand
2. List the possible alternatives
3. Identify the possible outcomes or states of nature
4. List the payoff (typically profit) of each combination of
alternatives and outcomes
5. Select one of the mathematical decision theory models
6. Apply the model and make your decision
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Thompson Lumber Company (1 of 2)
• Step 1 – Define the problem
– Consider manufacturing and marketing new product
• Step 2 – List alternatives
– Large plant, small plant, do nothing
• Step 3 – Identify possible outcomes, states of nature
– Market is favorable or unfavorable
• Step 4 – List the payoffs
– Identify conditional values for each alternative
• Step 5 – Select the decision model
– Depends on environment & risk uncertainty
• Step 6 – Apply the model to the data
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Thompson Lumber Company (2 of 2)
Table 3.1 Decision Table with Conditional Values for
Thompson Lumber
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($)
Construct a large plant 200,000 negative180,000
Construct a small plant 100,000 negative 20,000
Do nothing 0 0
180, 000

20, 000

Note: It is important to include all alternatives, including “do nothing.”
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Types of Decision-Making Environments
• Decision making under certainty
– The decision maker knows with certainty the
consequences of every alternative or decision choice
• Decision making under uncertainty
– The decision maker does not know the probabilities of
the various outcomes
• Decision making under risk
– The decision maker knows the probabilities of the
various outcomes
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Decision Making Under Uncertainty
• Criteria for making decisions under uncertainty
1. Maximax (optimistic)
2. Maximin (pessimistic)
3. Criterion of realism (Hurwicz)
4. Equally likely (Laplace)
5. Minimax regret
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Optimistic = Maximax
• Used to find the alternative that maximizes the maximum
payoff—maximax criterion
1. Locate the maximum payoff for each alternative
2. Select the alternative with the maximum number
Table 3.2 Thompson’s Maximax Decision
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market
($)
Maximum in a Row
($)
Construct a large plant 200,000
negative180,000 A text,Maximax points to200,000insideacircle.
Construct a small plant 100,000 negative20,000
100,000
Do nothing 0 0 0
180, 000

20, 000

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Pessimistic = Maximin
• Used to find the alternative that maximizes the minimum
payoff—maximin criterion
1. Locate the minimum payoff for each alternative
2. Select the alternative with the maximum number
Table 3.3 Thompson’s Maximin Decision
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($) Maximum in a Row ($)
Construct a large plant 200,000 negative180,000 negative180,000
Construct a small plant 100,000 negative20,000 negative20,000
Do nothing 0 0
Atext,Maximax points to0 insideacircle.
180, 000
 180, 000

20, 000
 20, 000

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Criterion of Realism (Hurwicz Criterion) (1 of 2)
• Often called weighted average
– Compromise between optimism and pessimism
– Select a coefficient of
realism
, with 0 1
 
 
1
  is perfectly optimistic
0
  is perfectly pessimistic
– Compute the weighted averages for each alternative
– Select the alternative with the highest value
Weighted average (best payoff) (1 )(worst payoff)
 
  
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Criterion of Realism (Hurwicz Criterion) (2 of 2)
For the large plant alternative using 0.8
 
   ( )(
0.8 200,000 1 0.8 1 )
80,000 124,000
   
For the small plant alternative using 0.8
 
  
0.8 100,000 1 0.8 20,000 76,000
( )( )
   
Table 3.4 Thompson’s Criterion of Realism Decision
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($)
Criterion of Realism
or Weighted Average
left parenthesisalphaequals0.8right parenthesisleft parenthesisdollars right parenthesis
Construct a large plant 200,000
negative180,000 Atext, realism, points to124,000insideacircle.
Construct a small plant 100,000 negative20,000
76,000
Do nothing 0 0 0
( 0.8) ($)


180, 000

20, 000

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Equally Likely (Laplace Criterion)
• Considers all the payoffs for each alternative
– Find the average payoff for each alternative
– Select the alternative with the highest average
Table 3.5 Thompson’s Equally Likely Decision
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market
($) Row Average ($)
Construct a large plant 200,000 negative180,000
10,000
Construct a small plant 100,000
negative20,000 Atext,equally likely, points to40,000insidea circle.
Do nothing 0 0 0
180, 000

20, 000

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Minimax Regret (1 of 3)
• Based on opportunity loss or regret
– The difference between the optimal profit and actual payoff
for a decision
Step 1—Create an opportunity loss table by determining
the opportunity loss from not choosing the best alternative
Step 2—Calculate opportunity loss by subtracting each
payoff in the column from the best payoff in the column
Step 3—Find the maximum opportunity loss for each
alternative, and pick the alternative with the minimum
number
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Minimax Regret (2 of 3)
Table 3.6 Determining Opportunity Losses for Thompson Lumber
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($)
200,000 minus 200,000 0minus left parenthesis negative180,000rightparenthesis
200,000 minus 100,000 0minus left parenthesis negative20,000right parenthesis
200,000 minus 0 0minus 0
200,000 200,000
 0 ( 180,000)
 
200,000 100,000
 0 ( 20,000)
 
200,000 0
 0 0

Table 3.7 Opportunity Loss Table for Thompson Lumber
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($)
Construct a large plant 0 180,000
Construct a small plant 100,000 20,000
Do nothing 200,000 0
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Minimax Regret (3 of 3)
Table 3.8 Thompson’s Minimax Decision Using Opportunity Loss
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($) Maximum in a Row ($)
Construct a large plant 0 180,000 180,000
Construct a small plant 100,000 20,000
Atext, minimax, points to100,000 insideacircle.
Do nothing 200,000 0 200,000
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Decision Making Under Risk (1 of 2)
• When there are several possible states of nature and the
probabilities associated with each possible state are known
– Most popular method—choose the alternative with the highest
expected monetary value (EMV)
EMV(alternative) ( )
i i
X P X

where
i
X  payoff for the alternative in state of nature i
( )
i
P X  probability of achieving payoff i
X (i.e., probability of
state of nature i)
 summation symbol
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Decision Making Under Risk (2 of 2)
• Expanding the equation
 
 
 
 
 
EMV alternative payoff of first state of nature
probability of first state of nature
payoff of second state of nature
probability of second state of nature
… payoff of last state of natur
(
e
)
i 



 
probability of last state of na
( )
ture

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EMV for Thompson Lumber
Each market outcome has a probability of occurrence of
0.50 Which alternative would give the highest EMV?
Table 3.9 Decision Table with Probabilities and EMVs for
Thompson Lumber
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($) EMV ($)
Construct a large plant 200,000 negative180,000
10,000
Construct a small plant 100,000
negative20,000 A text,best EM V, points to40,000 insideacircle.
Do nothing 0 0 0
Probabilities 0.50 0.50
Blank
180, 000

20, 000

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Expected Value of Perfect Information
(EVPI) (1 of 6)
• EVPI places an upper bound on what you should pay for
additional information
• EVwPI is the long-run average return if we have perfect
information before a decision is made
EVwPI best payoff in state of nature
probability of state of nat
(
u
)
( )
re
i
i

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Expected Value of Perfect Information (E
VPI) (2 of 6)
• Expanded EVwPI becomes
 
 
 
 
EVwPI best payoff for first state of nature
probability of first state of nature
best payoff for second state of nature
probability of second state of nature
… best payoff for last state of




   
 
nature
probability of last state of nature

And
EVPI EVwPI Best EMV
 
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Expected Value of Perfect Information
(EVPI) (3 of 6)
• Scientific Marketing, Inc. offers analysis that will provide
certainty about market conditions (favorable)
• Additional information will cost $65,000
• Should Thompson Lumber purchase the information?
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Expected Value of Perfect Information
(EVPI) (4 of 6)
Table 3.10 Decision Table with Perfect Information
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($) EMV ($)
Construct a large plant 200,000 negative180,000
10,000
Construct a small plant 100,000 negative20,000 40,000
Do nothing 0 0 0
With perfect
information
200,000 0
Atext E Vw P I, points to100,000 insideacircle.
Probabilities 0.50 0.50
Blank
180, 000

20, 000

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Expected Value of Perfect Information
(EVPI) (5 of 6)
• The maximum EMV without additional information is
$40,000
– Therefore
EVPI EVwPI Maximum EMV
$100,000 $40,000
$60,000
 
 

So, the maximum Thompson should pay for the additional
information is $60,000
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Expected Value of Perfect Information
(EVPI) (6 of 6)
• The maximum EMV without additional information is
$40,000
– Therefore
Thompson should not pay $65,000 for this information
EVPI EVwPI Maximum EMV
$100,000 $40,000
$60,000
 
 

So the maximum Thompson should pay for the additional
information is $60,000
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Expected Opportunity Loss (1 of 2)
• Expected opportunity loss (EOL) is the cost of not picking
the best solution
– Construct an opportunity loss table
– For each alternative, multiply the opportunity loss by
the probability of that loss for each possible outcome
and add these together
– Minimum EOL will always result in the same decision
as maximum EMV
– Minimum EOL will always equal EVPI
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Expected Opportunity Loss (2 of 2)
       
       
       
EOL large plant 0.50 $0 0.50 $180,000 $90,000
EOL small plant 0.50 $100,000 0.50 $20,000 $60,000
EOL do nothing 0.50 $200,000 0.50 $0 $100,000
  
  
  
Table 3.11 EOL Table for Thompson Lumber
Alternative
State of Nature
Favorable Market ($)
State of Nature
Unfavorable Market ($) EOL ($)
Construct a large plant 0 180,000 90,000
Construct a small plant 100,000 20,000
Atext, best EO L,points to60,000insidea circle.
Do nothing 200,000 0 100,0
0
Probabilities 0.50 0.50
Blank
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Sensitivity Analysis (1 of 3)
Define P = probability of a favorable market
 
 
 
EMV large plant $200,000 $180,000 1
$200,000 $180,000 $180,000
$380,000 $180,000
EMV small plant $100,000 $20,000 1
$100,000 $20,000 $20,000
$120,000 $20,000
EMV do no
)( )
)( )
thing
P P
P P
P
P P
P P
P
  
  
 
  
  
 
 $0 0 1
0
(
$
)
P P
 

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Sensitivity Analysis (2 of 3)
Figure 3.1 Sensitivity Analysis
Best Alternative Range of P Values
Do nothing Less than 0.167
Construct a small plant 0.167–0.615
Construct a large plant Greater than 0.615
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Sensitivity Analysis (3 of 3)
Point 1: 
EMV do nothing EMV small p
( ) ( lant)
 
0 $120,000 $20,000
P  
20,000
0.167
120,000
P
Point 2: 
EMV small plant EMV large p
( ) ( lant)
$120,000 $20,000 $380,000 $180,000
P P
  
160,000
0.615
260,000
P  
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A Minimization Example (1 of 4)
Three-year lease for a copy machine—which cost is lowest?
Table 3.12 Payoff Table with Monthly Copy Costs for Business Analytics
Department
Blank
10,000 Copies per Month
($)
20,000 Copies per Month
($)
30,000 Copies per Month
($)
Machine A 950 1,050 1,150
Machine B 850 1,100 1,350
Machine C 700 1,000 1,300
Table 3.13 Best and Worst Payoffs (Costs) for Business Analytics Department
Blank
10,000
Copies per
Month ($)
20,000 Copies
per Month ($)
30,000
Copies per
Month ($)
Best Payoff
(Minimum) ($)
Worst Payoff
(Maximum) ($)
Machine A 950 1,050 1,150 950 1,150
Machine B 850 1,100 1,350 850 1,350
Machine C 700 1,000 1,300 700 1,300
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A Minimization Example (2 of 4)
1. Determine the best alternative using Hurwicz criteria
with 70% coefficient.
2. Determine the best alternative using the equally likely
criteria.
3. Determine the best alternative using the EMV criterion
using P(10,000) 0.4, P(20,000) 0.3, P(30,000) 0.3
  
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A Minimization Example (3 of 4)
Table 3.14 Expected Monetary Values and Expected Values with
Perfect Information for Business Analytics Department
Blank
10,000 Copies per
Month ($)
20,000 Copies per
Month ($)
30,000 Copies per
Month ($)
EMV ($)
Machine A 950 1,050 1,150 1,040
Machine B 850 1,100 1,350 1,075
Machine C 700 1,000 1,300 970
With perfect
information
700 1,000 1,150 925
Probability 0.4 0.3 0.3
Blank


  
EVwPI $925
Best EMV without perfect information $970
EVPI 970 925 $45
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A Minimization Example (4 of 4)
Table 3.15 Opportunity Loss Table for Business Analytics
Department
Blank
10,000
Copies per
Month ($)
20,000
Copies per
Month ($)
30,000
Copies per
Month ($)
Maximum ($) EOL ($)
Machine A 250 50 0 250 115
Machine B 150 100 200 200 150
Machine C 0 0 150 150 45
Probability 0.4 0.3 0.3
Blank Blank
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Using Software (1 of 2)
Program 3.1A QM for Windows Input for Thompson
Lumber Example
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Using Software (2 of 2)
Program 3.1B QM for Windows Output Screen for Thompson Lumber
Example
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Using Excel (1 of 4)
Program 3.2A Excel QM Results for Thompson Lumber Example
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Using Excel (2 of 4)
Program 3.2B Key Formulas in Excel QM for Thompson Lumber
Example
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Decision Trees
Any problem presented in a decision table can be graphically represented in a
decision tree
• Most beneficial with a sequence of decisions
• All decision trees contain decision points/nodes and state-of-nature
points/nodes
• At decision nodes (the squares), one of several alternatives may be chosen
• At state-of-nature nodes (the circles), one state of nature will occur
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Five Steps of Decision Tree Analysis
1. Define the problem
2. Structure or draw the decision tree
3. Assign probabilities to the states of nature
4. Estimate payoffs for each possible combination of
alternatives and states of nature
5. Solve the problem by computing expected monetary
values (EMVs) for each state of nature node
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Thompson’s Decision Tree (1 of 2)
Figure 3.2 Thompson Lumber Decision Tree
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Thompson’s Decision Tree (2 of 2)
Figure 3.3 Completed and Solved Decision Tree for
Thompson Lumber
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Thompson’s Complex Decision Tree (1 of 5)
Figure 3.4
Larger Decision
Tree with
Payoffs and
Probabilities for
Thompson
Lumber
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Thompson’s Complex Decision Tree (2 of 5)
1. Given favorable survey results
 
    
   
EMV node 2 EMV large plant positive survey
0.78 $190,000 0.22 $190,000
$106,400
EMV node 3 EMV small
( ) |
( )
|
plant positive survey

  


    
0.78 $90,000 0.22 $30,000
$63,600
EMV for no plant $10,000
( )
  


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Thompson’s Complex Decision Tree (3 of 5)
2. Given negative survey results
   
    
   
    
EMV node 4 EMV large plant negative survey
0.27 $190,000 0.73 $190,000
$87,400
EMV node 5 EMV small plant negative survey
0.27 $90,000 0.73 $30,000
$2,400
EMV for no
|
( )
|
( )
plant $10,000

  


  


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Thompson’s Complex Decision Tree (4 of 5)
The best choice is to seek marketing information
3. Expected value of the market survey
     
EMV node1 EMV conduct survey
0.45 $106,400 0.55 $2,400
$47,880 $1,320
( ) ( )
$49,200

 
  
4. Expected value no market survey
   
    
   
    
EMV node 6 EMV large plant
0.50 $200,000 0.50 $180,000
$10,000
EMV node 7 EMV small plant
0.50 $100,000 0.50 $20,000
$40,000
EMV for no plant $
( )
(
0
)

  


  


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Thompson’s Complex Decision Tree (5 of 5)
Figure 3.5
Thompson’s
Decision Tree
with EMVs
Shown
What is the
value of doing
the survey?
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Efficiency of Sample Information
Market survey is only 32% as efficient as perfect information
• Possibly many types of sample information available
• Different sources can be evaluated
EVSI
Efficiency of sample information 100%
EVPI

• For Thompson
19,200
Efficiency of sample information 100% 32%
60,000
 
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Sensitivity Analysis (1 of 2)
• How sensitive are the decisions to changes in the
probabilities?
• How sensitive is our decision to the probability of a
favorable survey result?
• If the probability of a favorable result (p = .45) were to
change, would we make the same decision?
• How much could it change before we would make a
different decision?
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Sensitivity Analysis (2 of 2)
If p < 0.36, do not conduct the survey
If p > 0.36, conduct the survey
p = probability of a favorable survey result
(1 )
p
  probability of a negative survey result
     
EMV node1 $106,400 $2,400 1
$104,000
( )
$2,400
p p
p
  
 
We are indifferent when the EMV of node 1 is the same as the EMV of not
conducting the survey
$104,000 $2,400 $40,000
$104,000 $37,600
$37,600 $104,000 0.36
p
p
p
 

  
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Bayesian Analysis
• Many ways of getting probability data
– Management’s experience and intuition
– Historical data
– Computed from other data using Bayes’ theorem
• Bayes’ theorem incorporates initial estimates and
information about the accuracy of the sources
• Allows the revision of initial estimates based on new
information
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Calculating Revised Probabilities (1 of 5)
• Four conditional probabilities for Thompson Lumber
 
 
 
 
 
 
 
favorable market FM survey results positive 0.78
unfavorable market UM survey results positive 0.22
favorable market FM survey results negative 0.27
unfavorable market UM surve
|
|
y resul
|
s
| t
P
P
P
P



 
negative 0.73

• Prior probabilities
 
 
FM 0.50
UM 0.50
P
P


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Calculating Revised Probabilities (2 of 5)
Table 3.16 Market Survey Reliability in Predicting States of
Nature
Result of Survey
State of Nature
Favorable Market (FM)
State of Nature
Unfavorable Market (UM)
Positive (predicts
favorable market
for product)
Pleftparenthesis survey positivepipeF M right parenthesis equals 0.70 Pleftparenthesis survey positivepipeU M right parenthesis equals 0.20
Negative (predicts
unfavorable
market for
product)
Pleftparenthesis survey negative pipeF M rightparenthesis equals 0.30 Pleftparenthesis survey negative pipeU M right parenthesis equals 0.80
(survey positive | FM) 0.70
P  (survey positive | UM) 0.20
P 
(survey negative | FM) 0.30
P  (survey negative | UM) 0.80
P 
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Calculating Revised Probabilities (3 of 5)
• Calculating posterior probabilities
( ) ( )
( )
( ) ( ) ( ) ( )
P B | A P A
P A | B
P B | A P A P B | A P A


 
  
where
A, B = any two events
A  complement of A
A = favorable market
B = positive survey
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Calculating Revised Probabilities (4 of 5)
Table 3.17 Probability Revisions Given a Positive Survey
State
of
Nature
Conditional Probability
Pleft parenthesis Survey positivepipeState ofNatureright parenthesis
Prior Probability Posterior
Probability
Joint
Probability
Posterior Probability
P left parenthesis State of Nature pipe Survey positive right parenthesis
FM 0.70 Times 0.50
= 0.35 Start fraction0.35over 0.45 endfractionequals 0.78
UM 0.20 Times 0.50
= 0.10 Start fraction0.10over 0.45 endfractionequals 0.22
Blank Blank
Pleftparenthesis survey results positiveright parenthesis
= 0.45 1.00
(Survey Positive |
State of Nature)
P (State of Nature |
Survey Positive)
P
0.50
 0.35/0.45 0.78

0.50
 0.10/0.45 0.22

(survey results positive)
P
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Calculating Revised Probabilities (5 of 5)
Table 3.18 Probability Revisions Given a Negative Survey
State
of
Nature
Conditional
Probability
P left parenthesis Survey negative pipe State of Nature right parenthesis
Prior Probability Posterior
Probability
Joint
Probability
Posterior Probability
P left parenthesis State of Nature pipe Survey negative right parenthesis
FM 0.30 Times 0.50
= 0.15 Start fraction0.15over 0.55 endfractionequals 0.27
UM 0.80 Times 0.50
= 0.40 Start fraction0.40over 0.55 endfractionequals 0.73
Blank Blank
Pleftparenthesis survey results negativeright parenthesis
= 0.55 1.00
(Survey Negative |
State of Nature)
P (State of Nature |
Survey Negative)
P
0.50
 0.15/0.55 0.27

0.50
 0.40/0.55 0.73

(survey results negative)
P
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Using Excel (3 of 4)
Program 3.3A Results of Bayes’ Calculations in Excel 2016
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Using Excel (4 of 4)
Program 3.3B Formulas Used for Bayes’ Calculations
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Potential Problems Using Survey Results
• We can not always get the necessary data for analysis
• Survey results may be based on cases where an action
was taken
• Conditional probability information may not be as
accurate as we would like
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Utility Theory (1 of 3)
• Monetary value is not always a true indicator of the
overall value of the result of a decision
• The overall value of a decision is called utility
• Economists assume that rational people make decisions
to maximize their utility
• Utility assessment assigns the worst outcome a utility of
0 and the best outcome a utility of 1
• A standard gamble is used to determine utility values
• When you are indifferent, your utility values are equal
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Utility Theory (2 of 3)
Figure 3.6 Your Decision Tree for the Lottery Ticket
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Utility Theory (3 of 3)
Figure 3.7 Standard Gamble for a Utility Assessment
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Investment Example (1 of 2)
• Construct a utility curve revealing preference for money
between $0 and $10,000
• A utility curve plots the utility value versus the monetary value
– An investment in a bank will result in $5,000
– An investment in real estate will result in $0 or $10,000
– Unless there is an 80% chance of getting $10,000 from the
real estate deal, prefer to have her money in the bank
– If p = 0.80, Jane is indifferent between the bank or the real
estate investment
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Investment Example (2 of 2)
Figure 3.8 Utility of $5,000
What are the utility values for $3,000 and for $7,000?
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Utility Curve
Figure 3.9 Utility Curve for Jane Dickson
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Preferences for Risk
Figure 3.10 Preferences for Risk Risk Avoider
• Avoids high losses
• Less utility from greater risk
Risk Seeker
• Utility curve increases faster
than payoff
• More utility from greater risk
Risk Indifferent
• Linear utility
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Utility as a Decision-Making Criteria (1 of 3)
Mark Simkin’s thumbtack game
Lands Point Up Lands Point Down
Mark wins $10,000 Mark loses $10,000
Figure 3.11 Decision Facing Mark Simkin
Should Mark play the game is P(point up) 0.45?

Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Utility as a Decision-Making Criteria (2 of 3)
Step 1 – Define Mark’s utilities
$10,000 0.05
$0
( )
( )
(
0.15
$10,000) 0.30
U
U
U
 


Figure 3.12 Utility Curve
for Mark Simkin
Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
Utility as a Decision-Making Criteria (3 of 3)
Step 2 – Replace monetary values with utility values
    
alternative1:play the game 0.45 0.30 0.55 0.05
0.135 0.027 0.162
(alternative 2 : don’t play the game) 0.
(
1
( ) )
5
E
E
 
  

Figure 3.13 Using Expected Utilities in Decision Making
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Copyright
This work is protected by United States copyright laws and is
provided solely for the use of instructors in teaching their
courses and assessing student learning. Dissemination or sale of
any part of this work (including on the World Wide Web) will
destroy the integrity of the work and is not permitted. The work
and materials from it should never be made available to students
except by instructors using the accompanying text in their
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Decision science Analytical hierarchy process

  • 1.
    Quantitative Analysis forManagement Fourteenth Edition Chapter 3 Decision Analysis Copyright © 2024, 2018, 2015 Pearson Education, Inc. All Rights Reserved
  • 2.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Learning Objectives (1 of 2) After completing this chapter, students will be able to: 3.1 List the steps of the decision-making process. 3.2 Describe the types of decision-making environments. 3.3 Make decisions under uncertainty. 3.4 Use probability values to make decisions under risk. 3.5 Use computers to solve basic decision-making problems. 3.6 Develop accurate and useful decision trees.
  • 3.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Learning Objectives (2 of 2) 3.7 Revise probability estimates using Bayesian analysis. 3.8 Understand the importance and use of utility theory in decision making.
  • 4.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Introduction Decision theory is an analytic and systematic approach to the study of decision making What is involved in making a good decision? A good decision is one that is based on logic, considers all available data and possible alternatives, and applies a quantitative approach
  • 5.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved The Six Steps in Decision Making 1. Clearly define the problem at hand 2. List the possible alternatives 3. Identify the possible outcomes or states of nature 4. List the payoff (typically profit) of each combination of alternatives and outcomes 5. Select one of the mathematical decision theory models 6. Apply the model and make your decision
  • 6.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson Lumber Company (1 of 2) • Step 1 – Define the problem – Consider manufacturing and marketing new product • Step 2 – List alternatives – Large plant, small plant, do nothing • Step 3 – Identify possible outcomes, states of nature – Market is favorable or unfavorable • Step 4 – List the payoffs – Identify conditional values for each alternative • Step 5 – Select the decision model – Depends on environment & risk uncertainty • Step 6 – Apply the model to the data
  • 7.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson Lumber Company (2 of 2) Table 3.1 Decision Table with Conditional Values for Thompson Lumber Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Construct a large plant 200,000 negative180,000 Construct a small plant 100,000 negative 20,000 Do nothing 0 0 180, 000  20, 000  Note: It is important to include all alternatives, including “do nothing.”
  • 8.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Types of Decision-Making Environments • Decision making under certainty – The decision maker knows with certainty the consequences of every alternative or decision choice • Decision making under uncertainty – The decision maker does not know the probabilities of the various outcomes • Decision making under risk – The decision maker knows the probabilities of the various outcomes
  • 9.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Decision Making Under Uncertainty • Criteria for making decisions under uncertainty 1. Maximax (optimistic) 2. Maximin (pessimistic) 3. Criterion of realism (Hurwicz) 4. Equally likely (Laplace) 5. Minimax regret
  • 10.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Optimistic = Maximax • Used to find the alternative that maximizes the maximum payoff—maximax criterion 1. Locate the maximum payoff for each alternative 2. Select the alternative with the maximum number Table 3.2 Thompson’s Maximax Decision Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Maximum in a Row ($) Construct a large plant 200,000 negative180,000 A text,Maximax points to200,000insideacircle. Construct a small plant 100,000 negative20,000 100,000 Do nothing 0 0 0 180, 000  20, 000 
  • 11.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Pessimistic = Maximin • Used to find the alternative that maximizes the minimum payoff—maximin criterion 1. Locate the minimum payoff for each alternative 2. Select the alternative with the maximum number Table 3.3 Thompson’s Maximin Decision Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Maximum in a Row ($) Construct a large plant 200,000 negative180,000 negative180,000 Construct a small plant 100,000 negative20,000 negative20,000 Do nothing 0 0 Atext,Maximax points to0 insideacircle. 180, 000  180, 000  20, 000  20, 000 
  • 12.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Criterion of Realism (Hurwicz Criterion) (1 of 2) • Often called weighted average – Compromise between optimism and pessimism – Select a coefficient of realism , with 0 1     1   is perfectly optimistic 0   is perfectly pessimistic – Compute the weighted averages for each alternative – Select the alternative with the highest value Weighted average (best payoff) (1 )(worst payoff)     
  • 13.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Criterion of Realism (Hurwicz Criterion) (2 of 2) For the large plant alternative using 0.8      ( )( 0.8 200,000 1 0.8 1 ) 80,000 124,000     For the small plant alternative using 0.8      0.8 100,000 1 0.8 20,000 76,000 ( )( )     Table 3.4 Thompson’s Criterion of Realism Decision Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Criterion of Realism or Weighted Average left parenthesisalphaequals0.8right parenthesisleft parenthesisdollars right parenthesis Construct a large plant 200,000 negative180,000 Atext, realism, points to124,000insideacircle. Construct a small plant 100,000 negative20,000 76,000 Do nothing 0 0 0 ( 0.8) ($)   180, 000  20, 000 
  • 14.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Equally Likely (Laplace Criterion) • Considers all the payoffs for each alternative – Find the average payoff for each alternative – Select the alternative with the highest average Table 3.5 Thompson’s Equally Likely Decision Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Row Average ($) Construct a large plant 200,000 negative180,000 10,000 Construct a small plant 100,000 negative20,000 Atext,equally likely, points to40,000insidea circle. Do nothing 0 0 0 180, 000  20, 000 
  • 15.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Minimax Regret (1 of 3) • Based on opportunity loss or regret – The difference between the optimal profit and actual payoff for a decision Step 1—Create an opportunity loss table by determining the opportunity loss from not choosing the best alternative Step 2—Calculate opportunity loss by subtracting each payoff in the column from the best payoff in the column Step 3—Find the maximum opportunity loss for each alternative, and pick the alternative with the minimum number
  • 16.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Minimax Regret (2 of 3) Table 3.6 Determining Opportunity Losses for Thompson Lumber State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) 200,000 minus 200,000 0minus left parenthesis negative180,000rightparenthesis 200,000 minus 100,000 0minus left parenthesis negative20,000right parenthesis 200,000 minus 0 0minus 0 200,000 200,000  0 ( 180,000)   200,000 100,000  0 ( 20,000)   200,000 0  0 0  Table 3.7 Opportunity Loss Table for Thompson Lumber Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Construct a large plant 0 180,000 Construct a small plant 100,000 20,000 Do nothing 200,000 0
  • 17.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Minimax Regret (3 of 3) Table 3.8 Thompson’s Minimax Decision Using Opportunity Loss Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) Maximum in a Row ($) Construct a large plant 0 180,000 180,000 Construct a small plant 100,000 20,000 Atext, minimax, points to100,000 insideacircle. Do nothing 200,000 0 200,000
  • 18.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Decision Making Under Risk (1 of 2) • When there are several possible states of nature and the probabilities associated with each possible state are known – Most popular method—choose the alternative with the highest expected monetary value (EMV) EMV(alternative) ( ) i i X P X  where i X  payoff for the alternative in state of nature i ( ) i P X  probability of achieving payoff i X (i.e., probability of state of nature i)  summation symbol
  • 19.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Decision Making Under Risk (2 of 2) • Expanding the equation           EMV alternative payoff of first state of nature probability of first state of nature payoff of second state of nature probability of second state of nature … payoff of last state of natur ( e ) i       probability of last state of na ( ) ture 
  • 20.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved EMV for Thompson Lumber Each market outcome has a probability of occurrence of 0.50 Which alternative would give the highest EMV? Table 3.9 Decision Table with Probabilities and EMVs for Thompson Lumber Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) EMV ($) Construct a large plant 200,000 negative180,000 10,000 Construct a small plant 100,000 negative20,000 A text,best EM V, points to40,000 insideacircle. Do nothing 0 0 0 Probabilities 0.50 0.50 Blank 180, 000  20, 000 
  • 21.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (EVPI) (1 of 6) • EVPI places an upper bound on what you should pay for additional information • EVwPI is the long-run average return if we have perfect information before a decision is made EVwPI best payoff in state of nature probability of state of nat ( u ) ( ) re i i 
  • 22.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (E VPI) (2 of 6) • Expanded EVwPI becomes         EVwPI best payoff for first state of nature probability of first state of nature best payoff for second state of nature probability of second state of nature … best payoff for last state of           nature probability of last state of nature  And EVPI EVwPI Best EMV  
  • 23.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (EVPI) (3 of 6) • Scientific Marketing, Inc. offers analysis that will provide certainty about market conditions (favorable) • Additional information will cost $65,000 • Should Thompson Lumber purchase the information?
  • 24.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (EVPI) (4 of 6) Table 3.10 Decision Table with Perfect Information Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) EMV ($) Construct a large plant 200,000 negative180,000 10,000 Construct a small plant 100,000 negative20,000 40,000 Do nothing 0 0 0 With perfect information 200,000 0 Atext E Vw P I, points to100,000 insideacircle. Probabilities 0.50 0.50 Blank 180, 000  20, 000 
  • 25.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (EVPI) (5 of 6) • The maximum EMV without additional information is $40,000 – Therefore EVPI EVwPI Maximum EMV $100,000 $40,000 $60,000      So, the maximum Thompson should pay for the additional information is $60,000
  • 26.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Value of Perfect Information (EVPI) (6 of 6) • The maximum EMV without additional information is $40,000 – Therefore Thompson should not pay $65,000 for this information EVPI EVwPI Maximum EMV $100,000 $40,000 $60,000      So the maximum Thompson should pay for the additional information is $60,000
  • 27.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Opportunity Loss (1 of 2) • Expected opportunity loss (EOL) is the cost of not picking the best solution – Construct an opportunity loss table – For each alternative, multiply the opportunity loss by the probability of that loss for each possible outcome and add these together – Minimum EOL will always result in the same decision as maximum EMV – Minimum EOL will always equal EVPI
  • 28.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Expected Opportunity Loss (2 of 2)                         EOL large plant 0.50 $0 0.50 $180,000 $90,000 EOL small plant 0.50 $100,000 0.50 $20,000 $60,000 EOL do nothing 0.50 $200,000 0.50 $0 $100,000          Table 3.11 EOL Table for Thompson Lumber Alternative State of Nature Favorable Market ($) State of Nature Unfavorable Market ($) EOL ($) Construct a large plant 0 180,000 90,000 Construct a small plant 100,000 20,000 Atext, best EO L,points to60,000insidea circle. Do nothing 200,000 0 100,0 0 Probabilities 0.50 0.50 Blank
  • 29.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Sensitivity Analysis (1 of 3) Define P = probability of a favorable market       EMV large plant $200,000 $180,000 1 $200,000 $180,000 $180,000 $380,000 $180,000 EMV small plant $100,000 $20,000 1 $100,000 $20,000 $20,000 $120,000 $20,000 EMV do no )( ) )( ) thing P P P P P P P P P P                  $0 0 1 0 ( $ ) P P   
  • 30.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Sensitivity Analysis (2 of 3) Figure 3.1 Sensitivity Analysis Best Alternative Range of P Values Do nothing Less than 0.167 Construct a small plant 0.167–0.615 Construct a large plant Greater than 0.615
  • 31.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Sensitivity Analysis (3 of 3) Point 1:  EMV do nothing EMV small p ( ) ( lant)   0 $120,000 $20,000 P   20,000 0.167 120,000 P Point 2:  EMV small plant EMV large p ( ) ( lant) $120,000 $20,000 $380,000 $180,000 P P    160,000 0.615 260,000 P  
  • 32.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved A Minimization Example (1 of 4) Three-year lease for a copy machine—which cost is lowest? Table 3.12 Payoff Table with Monthly Copy Costs for Business Analytics Department Blank 10,000 Copies per Month ($) 20,000 Copies per Month ($) 30,000 Copies per Month ($) Machine A 950 1,050 1,150 Machine B 850 1,100 1,350 Machine C 700 1,000 1,300 Table 3.13 Best and Worst Payoffs (Costs) for Business Analytics Department Blank 10,000 Copies per Month ($) 20,000 Copies per Month ($) 30,000 Copies per Month ($) Best Payoff (Minimum) ($) Worst Payoff (Maximum) ($) Machine A 950 1,050 1,150 950 1,150 Machine B 850 1,100 1,350 850 1,350 Machine C 700 1,000 1,300 700 1,300
  • 33.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved A Minimization Example (2 of 4) 1. Determine the best alternative using Hurwicz criteria with 70% coefficient. 2. Determine the best alternative using the equally likely criteria. 3. Determine the best alternative using the EMV criterion using P(10,000) 0.4, P(20,000) 0.3, P(30,000) 0.3   
  • 34.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved A Minimization Example (3 of 4) Table 3.14 Expected Monetary Values and Expected Values with Perfect Information for Business Analytics Department Blank 10,000 Copies per Month ($) 20,000 Copies per Month ($) 30,000 Copies per Month ($) EMV ($) Machine A 950 1,050 1,150 1,040 Machine B 850 1,100 1,350 1,075 Machine C 700 1,000 1,300 970 With perfect information 700 1,000 1,150 925 Probability 0.4 0.3 0.3 Blank      EVwPI $925 Best EMV without perfect information $970 EVPI 970 925 $45
  • 35.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved A Minimization Example (4 of 4) Table 3.15 Opportunity Loss Table for Business Analytics Department Blank 10,000 Copies per Month ($) 20,000 Copies per Month ($) 30,000 Copies per Month ($) Maximum ($) EOL ($) Machine A 250 50 0 250 115 Machine B 150 100 200 200 150 Machine C 0 0 150 150 45 Probability 0.4 0.3 0.3 Blank Blank
  • 36.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Software (1 of 2) Program 3.1A QM for Windows Input for Thompson Lumber Example
  • 37.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Software (2 of 2) Program 3.1B QM for Windows Output Screen for Thompson Lumber Example
  • 38.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Excel (1 of 4) Program 3.2A Excel QM Results for Thompson Lumber Example
  • 39.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Excel (2 of 4) Program 3.2B Key Formulas in Excel QM for Thompson Lumber Example
  • 40.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Decision Trees Any problem presented in a decision table can be graphically represented in a decision tree • Most beneficial with a sequence of decisions • All decision trees contain decision points/nodes and state-of-nature points/nodes • At decision nodes (the squares), one of several alternatives may be chosen • At state-of-nature nodes (the circles), one state of nature will occur
  • 41.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Five Steps of Decision Tree Analysis 1. Define the problem 2. Structure or draw the decision tree 3. Assign probabilities to the states of nature 4. Estimate payoffs for each possible combination of alternatives and states of nature 5. Solve the problem by computing expected monetary values (EMVs) for each state of nature node
  • 42.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Decision Tree (1 of 2) Figure 3.2 Thompson Lumber Decision Tree
  • 43.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Decision Tree (2 of 2) Figure 3.3 Completed and Solved Decision Tree for Thompson Lumber
  • 44.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Complex Decision Tree (1 of 5) Figure 3.4 Larger Decision Tree with Payoffs and Probabilities for Thompson Lumber
  • 45.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Complex Decision Tree (2 of 5) 1. Given favorable survey results            EMV node 2 EMV large plant positive survey 0.78 $190,000 0.22 $190,000 $106,400 EMV node 3 EMV small ( ) | ( ) | plant positive survey            0.78 $90,000 0.22 $30,000 $63,600 EMV for no plant $10,000 ( )     
  • 46.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Complex Decision Tree (3 of 5) 2. Given negative survey results                   EMV node 4 EMV large plant negative survey 0.27 $190,000 0.73 $190,000 $87,400 EMV node 5 EMV small plant negative survey 0.27 $90,000 0.73 $30,000 $2,400 EMV for no | ( ) | ( ) plant $10,000           
  • 47.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Complex Decision Tree (4 of 5) The best choice is to seek marketing information 3. Expected value of the market survey       EMV node1 EMV conduct survey 0.45 $106,400 0.55 $2,400 $47,880 $1,320 ( ) ( ) $49,200       4. Expected value no market survey                   EMV node 6 EMV large plant 0.50 $200,000 0.50 $180,000 $10,000 EMV node 7 EMV small plant 0.50 $100,000 0.50 $20,000 $40,000 EMV for no plant $ ( ) ( 0 )           
  • 48.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Thompson’s Complex Decision Tree (5 of 5) Figure 3.5 Thompson’s Decision Tree with EMVs Shown What is the value of doing the survey?
  • 49.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Efficiency of Sample Information Market survey is only 32% as efficient as perfect information • Possibly many types of sample information available • Different sources can be evaluated EVSI Efficiency of sample information 100% EVPI  • For Thompson 19,200 Efficiency of sample information 100% 32% 60,000  
  • 50.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Sensitivity Analysis (1 of 2) • How sensitive are the decisions to changes in the probabilities? • How sensitive is our decision to the probability of a favorable survey result? • If the probability of a favorable result (p = .45) were to change, would we make the same decision? • How much could it change before we would make a different decision?
  • 51.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Sensitivity Analysis (2 of 2) If p < 0.36, do not conduct the survey If p > 0.36, conduct the survey p = probability of a favorable survey result (1 ) p   probability of a negative survey result       EMV node1 $106,400 $2,400 1 $104,000 ( ) $2,400 p p p      We are indifferent when the EMV of node 1 is the same as the EMV of not conducting the survey $104,000 $2,400 $40,000 $104,000 $37,600 $37,600 $104,000 0.36 p p p      
  • 52.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Bayesian Analysis • Many ways of getting probability data – Management’s experience and intuition – Historical data – Computed from other data using Bayes’ theorem • Bayes’ theorem incorporates initial estimates and information about the accuracy of the sources • Allows the revision of initial estimates based on new information
  • 53.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Calculating Revised Probabilities (1 of 5) • Four conditional probabilities for Thompson Lumber               favorable market FM survey results positive 0.78 unfavorable market UM survey results positive 0.22 favorable market FM survey results negative 0.27 unfavorable market UM surve | | y resul | s | t P P P P      negative 0.73  • Prior probabilities     FM 0.50 UM 0.50 P P  
  • 54.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Calculating Revised Probabilities (2 of 5) Table 3.16 Market Survey Reliability in Predicting States of Nature Result of Survey State of Nature Favorable Market (FM) State of Nature Unfavorable Market (UM) Positive (predicts favorable market for product) Pleftparenthesis survey positivepipeF M right parenthesis equals 0.70 Pleftparenthesis survey positivepipeU M right parenthesis equals 0.20 Negative (predicts unfavorable market for product) Pleftparenthesis survey negative pipeF M rightparenthesis equals 0.30 Pleftparenthesis survey negative pipeU M right parenthesis equals 0.80 (survey positive | FM) 0.70 P  (survey positive | UM) 0.20 P  (survey negative | FM) 0.30 P  (survey negative | UM) 0.80 P 
  • 55.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Calculating Revised Probabilities (3 of 5) • Calculating posterior probabilities ( ) ( ) ( ) ( ) ( ) ( ) ( ) P B | A P A P A | B P B | A P A P B | A P A        where A, B = any two events A  complement of A A = favorable market B = positive survey
  • 56.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Calculating Revised Probabilities (4 of 5) Table 3.17 Probability Revisions Given a Positive Survey State of Nature Conditional Probability Pleft parenthesis Survey positivepipeState ofNatureright parenthesis Prior Probability Posterior Probability Joint Probability Posterior Probability P left parenthesis State of Nature pipe Survey positive right parenthesis FM 0.70 Times 0.50 = 0.35 Start fraction0.35over 0.45 endfractionequals 0.78 UM 0.20 Times 0.50 = 0.10 Start fraction0.10over 0.45 endfractionequals 0.22 Blank Blank Pleftparenthesis survey results positiveright parenthesis = 0.45 1.00 (Survey Positive | State of Nature) P (State of Nature | Survey Positive) P 0.50  0.35/0.45 0.78  0.50  0.10/0.45 0.22  (survey results positive) P
  • 57.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Calculating Revised Probabilities (5 of 5) Table 3.18 Probability Revisions Given a Negative Survey State of Nature Conditional Probability P left parenthesis Survey negative pipe State of Nature right parenthesis Prior Probability Posterior Probability Joint Probability Posterior Probability P left parenthesis State of Nature pipe Survey negative right parenthesis FM 0.30 Times 0.50 = 0.15 Start fraction0.15over 0.55 endfractionequals 0.27 UM 0.80 Times 0.50 = 0.40 Start fraction0.40over 0.55 endfractionequals 0.73 Blank Blank Pleftparenthesis survey results negativeright parenthesis = 0.55 1.00 (Survey Negative | State of Nature) P (State of Nature | Survey Negative) P 0.50  0.15/0.55 0.27  0.50  0.40/0.55 0.73  (survey results negative) P
  • 58.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Excel (3 of 4) Program 3.3A Results of Bayes’ Calculations in Excel 2016
  • 59.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Using Excel (4 of 4) Program 3.3B Formulas Used for Bayes’ Calculations
  • 60.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Potential Problems Using Survey Results • We can not always get the necessary data for analysis • Survey results may be based on cases where an action was taken • Conditional probability information may not be as accurate as we would like
  • 61.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility Theory (1 of 3) • Monetary value is not always a true indicator of the overall value of the result of a decision • The overall value of a decision is called utility • Economists assume that rational people make decisions to maximize their utility • Utility assessment assigns the worst outcome a utility of 0 and the best outcome a utility of 1 • A standard gamble is used to determine utility values • When you are indifferent, your utility values are equal
  • 62.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility Theory (2 of 3) Figure 3.6 Your Decision Tree for the Lottery Ticket
  • 63.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility Theory (3 of 3) Figure 3.7 Standard Gamble for a Utility Assessment
  • 64.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Investment Example (1 of 2) • Construct a utility curve revealing preference for money between $0 and $10,000 • A utility curve plots the utility value versus the monetary value – An investment in a bank will result in $5,000 – An investment in real estate will result in $0 or $10,000 – Unless there is an 80% chance of getting $10,000 from the real estate deal, prefer to have her money in the bank – If p = 0.80, Jane is indifferent between the bank or the real estate investment
  • 65.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Investment Example (2 of 2) Figure 3.8 Utility of $5,000 What are the utility values for $3,000 and for $7,000?
  • 66.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility Curve Figure 3.9 Utility Curve for Jane Dickson
  • 67.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Preferences for Risk Figure 3.10 Preferences for Risk Risk Avoider • Avoids high losses • Less utility from greater risk Risk Seeker • Utility curve increases faster than payoff • More utility from greater risk Risk Indifferent • Linear utility
  • 68.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility as a Decision-Making Criteria (1 of 3) Mark Simkin’s thumbtack game Lands Point Up Lands Point Down Mark wins $10,000 Mark loses $10,000 Figure 3.11 Decision Facing Mark Simkin Should Mark play the game is P(point up) 0.45? 
  • 69.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility as a Decision-Making Criteria (2 of 3) Step 1 – Define Mark’s utilities $10,000 0.05 $0 ( ) ( ) ( 0.15 $10,000) 0.30 U U U     Figure 3.12 Utility Curve for Mark Simkin
  • 70.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Utility as a Decision-Making Criteria (3 of 3) Step 2 – Replace monetary values with utility values      alternative1:play the game 0.45 0.30 0.55 0.05 0.135 0.027 0.162 (alternative 2 : don’t play the game) 0. ( 1 ( ) ) 5 E E       Figure 3.13 Using Expected Utilities in Decision Making
  • 71.
    Copyright © 2024,2018, 2015 Pearson Education, Inc. All Rights Reserved Copyright This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permitted. The work and materials from it should never be made available to students except by instructors using the accompanying text in their classes. All recipients of this work are expected to abide by these restrictions and to honor the intended pedagogical purposes and the needs of other instructors who rely on these materials.

Editor's Notes

  • #1 If this PowerPoint presentation contains mathematical equations, you may need to check that your computer has the following installed: 1) MathType Plugin 2) Math Player (free versions available) 3) NVDA Reader (free versions available)
  • #19 Long Description: E M V, left parenthesis, alternative i, right parenthesis, equals, left parenthesis, payoff of first state of nature, right parenthesis, times, left parenthesis, probability of first state of nature, right parenthesis, plus, left parenthesis, payoff of second state of nature, right parenthesis, times, left parenthesis, probability of second state of nature, right parenthesis, plus, ellipsis, plus, left parenthesis, payoff of last state of nature, right parenthesis, times, left parenthesis, probability of last state of nature, right parenthesis.
  • #20 EMV (large plant) = $200,000×0.5+-$180,000×0.5=$10,000 EMV (small plant) = $100,000×0.5+-$20,000×0.5=$40,000 EMV (do nothing) = $0×0.5+$0×0.5=$0
  • #28 Long description: E O L, left parenthesis, large plant, right parenthesis, equals, left parenthesis, 0.50, right parenthesis, times, left parenthesis, 0 dollar, right parenthesis, plus, left parenthesis, 0.50, right parenthesis times left parenthesis, 180,000 dollars, right parenthesis, equals 90,000 dollars. E O L, left parenthesis, small plant, right parenthesis, equals, left parenthesis, 0.50, right parenthesis, times, left parenthesis, 100,000 dollars, right parenthesis, plus, left parenthesis, 0.50, right parenthesis, times, left parenthesis, 20,000 dollars, right parenthesis, equals 60,000 dollars. E O L, left parenthesis, do nothing, right parenthesis, equals, left parenthesis, 0.50, right parenthesis, times, left parenthesis, 200,000 dollars, right parenthesis, plus, left parenthesis, 0.50, right parenthesis, times, left parenthesis, 0 dollar, right parenthesis, equals 100,000 dollars.
  • #29 Long Description: E M V, left parenthesis, large plant, right parenthesis, equals, 200,000 dollars P minus 180,000 dollars, right parenthesis, times, left parenthesis, 1 minus P, right parenthesis, equals 200,000 dollars P minus 180,000 dollars plus 180,000 dollars P equals 380,000 dollars P minus 180,000 dollars. E M V, left parenthesis, small plant, right parenthesis equals 100,000 dollars P minus 20,000 dollars, right parenthesis, times, left parenthesis, 1 minus P, right parenthesis, equals 100,000 dollars P minus 20,000 dollars plus 20,000 dollars P equals 120,000 dollars P minus 20,000 dollars. E M V, left parenthesis, do nothing, right parenthesis, equals 0 dollar P plus 0, times, left parenthesis, 1 minus P, right parenthesis, equals 0 dollar.
  • #30 Long Description: The graph’s y axis is labeled E M V Value and is scaled in units of one hundred thousand dollars from negative two hundred thousand dollars to positive three hundred thousand dollars. The X axis, labeled Value of P, originates from the zero point on the y axis and has three data points labeled 0.167, 0.615, and 1. The x axis represents an E M V, do nothing. There is a line that originates from the negative two hundred thousand dollar point of the y axis and ascends up and to the right, crossing the x axis right before the data point of 0.61. It ends on the far right of the x axis, parallel to the positive two hundred thousand dollar point of the y axis. It is marked as E M V, large plant. A second line originates just under the zero point of the y axis, it ascends up and to the right, crossing the x axis exactly at the 0.167 mark. This intersection is labeled Point One. This same line continues ascending and intersects the first line at the 0.615 data mark, this intersection is labeled Point Two. It ends on the far right of the x axis, parallel to the positive one hundred thousand dollar point of the y axis. It is marked as E M V, small plant.
  • #33 Hurwicz criterion with 70% coefficient Machine A = 0.7×950+0.3×1150=1010 Machine B = 0.7×850+0.3×1350=1000 Machine C = 0.7×700+0.3×1300=880 → Choose C Equally likely criterion Machine A = (950+1050+1150)/3 = 1050 Machine B = (850+1100+1350)/3 = 1100 Machine C = (700+1000+1300)/3 = 1000 → Choose C EMV criterion Machine A = 950×0.4+1050×0.3+1150×0.3 = 1040 Machine B = 850×0.4+1100×0.3+1350×0.3 = 1075 Machine C = 700×0.4+1000×0.3+1300×0.3 = 970 → Choose C
  • #36 Long Description: A tip box gives instructions to enter data into table and type the row and column names. The words Thompson Lumber appear on the upper right row of the Excel screen. There are three columns of five cells each underneath Thompson Lumber. The input in the first column, descending, is as follows, First cell is blank Probabilities Large Plant Small Plant Do Nothing The input in the second column, descending, is as follows, Favorable market 0.5 200,000 100,000 Zero The input in the third column, descending, is as follows, Unfavorable market 0.5 Negative 180000 Negative 20000 Zero
  • #37 Long Description: The pop up window is labeled Decision Table Results. There are a minus sign, square, and x on the upper right corner of the pop up. The output is in the form of a table titled Thompson Lumber Solutions. The table contains seven columns of seven rows each. The data in column one, descending, is as follows, The first cell is blank Probabilities Large Plant Small Plant Do Nothing The data in column two, descending, is as follows, Favorable Market 0.5 200,000 100,000 Zero The sixth cell is blank The seventh cell is blank The data in column three, descending, is as follows, Unfavorable Market 0.5 Negative 180000 Negative 20000 Zero Maximum The seventh cell is blank The data in column four, descending, is as follows, E M V The second cell is blank 10000 40000 Zero 40000 Best E V The data in column five, descending, is as follows, Row Min The second cell is blank Negative 180000 Negative 20000 Zero Zero Maximin The data in column six, descending, is as follows, Row Max The second cell is blank 200000 100000 Zero 200000 Maximax The data in column seven, descending, is as follows, Hurwicz The second cell is blank 86000 64000 Zero 860000 Best Hurwicz Underneath the table, the following text appears, The maximum expected monetary value is 40000 given by Small Plant. The maximin is zero given by Do Nothing. The maximax is 200000 given by Large Plant.
  • #38 Long Description: A tip box provides guidance that To see the formulas, hold down the control key left parenthesis C t r l right parenthesis and press the grave accent key, which is usually found above the Tab key. A pop up box on the Excel chart instructs you to enter the profits in the main body of the data table. Enter probabilities in the first row if you want to compute the expected value. The screenshot is divided roughly into three vertical sections. The top section spans rows seven through twelve. The middle section spans rows fourteen through seventeen. The bottom section spans rows nineteen through twenty five. The topmost third consists of two data tables. The first data table contains three columns, labeled Profit, Favorable Market, and Unfavorable Market. Input for the Profit column, descending, is as follows, Probability, Large plant, Small plant, and Do nothing. Input for the Favorable Market, descending, is as follows, 0.5, 200000, 100000, and zero. Input for the Unfavorable Market column, descending, is as follows, 0.5, negative 180000, negative 20000, and zero. The second data table is adjacent to the first table, a single blank column, column D, separates the two. This second table contains three columns, labeled E M V, Minimum, and Maximum. Input for the E M V column, descending, is BLANK, 10000, 40000, and zero. Input for the Minimum column, descending, is BLANK, negative 180000, negative 20000, and zero. Input for the Maximum column, descending, is BLANK, 200000, 100000, and zero. Underneath this table is a row titled Maximum. 40000 appears under the E M V column, zero appears underneath the minimum column, and 200000 appears underneath the maximum column. The middle third begins with the following text in row fourteen, Expected value of perfect information. Row fifteen, cell A reads Column best. Row fifteen, cell B contains the number 200000 and row fifteen, column C contains the number zero. To the right of that is a table that spans two columns, D and E. Column D is blank, Column E contains the following numbers, descending, 100000 (labeled Expected value WITH perfect information), 40000 (labeled Best expected value), and 60000 (labeled Expected value OF perfect information. The bottom third of the chart begins with row nineteen, which reads Regret. Underneath that word is a table that spans Columns A through F. The data in this table is as follows, Column A, descending, Blank cell Probability Large plant Small plant Do nothing Column B, descending, Favorable Market 0.5 Zero 100000 200000 Column C, descending, Unfavorable Market 0.5 180000 20000 Zero Column D, descending, Blank cell Blank cell Blank cell Blank cell Blank cell Minimum Column E, descending, Expected Blank cell 90000 60000 100000 60000 Column F, descending, Maximum Blank cell 180000 100000 200000 100000
  • #39 Long Description: This screenshot focuses in on the E M V, Minimum, Maximum table from the top third of the output screen, the Expected Value table from the middle third of the output screen, and the Expected, Maximum information from the bottom third of the output screen. The screenshot shows three columns, E, F, and G, and rows nine through twenty five. Data in Column E, descending, are as follows, Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals SUM PRODUCT left parenthesis B dollar sign 8 Equal MAX left parenthesis E 9 colon E 11 Blank cell Blank cell Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals E 12 Equals E 15 minus E 12 Blank cell Blank cell Expected Blank cell Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals SUM PRODUCT left parenthesis B dollar sign 8 Equals MIN left parenthesis E 22 colon E 24 Data in Column F, descending, are as follows, Equals MIN left parenthesis B 9 colon C 9 right parenthesis Equals MIN left parenthesis B 10 colon C 10 right parenthesis Equals MIN left parenthesis B 11 colon C 11 right parenthesis Equals MAX left parenthesis F 9 colon F 11 right parenthesis Blank cell Blank cell Expected value under certainty Best expected value Expected value of perfect information Blank cell Blank cell Maximum Blank cell Equals MAX left parenthesis B 22 colon C 22 right parenthesis Equals MAX left parenthesis B 23 colon C 23 right parenthesis Equals MAX left parenthesis B 24 colon C 24 right parenthesis Equals MIN left parenthesis F 22 colon F 24 right parenthesis Data in Column G, descending, are as follows, Equals MAX left parenthesis B 9 colon C 9 right parenthesis Equals MAX left parenthesis B 10 colon C 10 right parenthesis Equals MAX left parenthesis B 11 colon C 11 right parenthesis Equals MAX left parenthesis G 9 colon G 11 right parenthesis
  • #42 Long Description: The first line is labeled construct large plant and extends to state-of-nature node 1. Two lines, labeled favorable market and unfavorable market, extend from this node. The second line from the decision node is labeled construct small plant and extends to state-of-nature node 2. Two lines, labeled favorable market and unfavorable market, extend from this node. The third line from the decision node is labeled do nothing.
  • #43 Long Description: State of Nature Node 2 is labeled E M V for Node 2 equals forty thousand dollars. Formulas and payoff amounts are included on the tree. State of Nature Node 1 has the following formula next to it, The sum of 0.5 times two hundred thousand dollars added to the sum of 0.5 times negative one hundred and eighty thousand dollars. State of Nature Node 2 has the following formula next to it, The sum of 0.5 times one hundred thousand dollars added to the sum of 0.5 times negative twenty thousand dollars. The Favorable and Unfavorable Market branches all include the number 0.5 at the end of their title, payoff amounts are listed as follows, Construct Large Plant, Favorable Market equals two hundred thousand dollars Construct Large Plant, Unfavorable Market equals negative one hundred and eighty thousand dollars Construct Small Plant, Favorable Market equals one hundred thousand dollars Construct Small Plant, Unfavorable Market equals negative twenty thousand dollars Do Nothing equals zero
  • #44 Long Description: Two additional branches come off the Conduct Market Survey branch, Survey Results Favorable left parenthesis 0.45 right parenthesis and Survey Results Negative left parenthesis 0.55 right parenthesis. There is now a vertical row of three square decision nodes marked Second Decision Point that leads to branches for plant construction options and payoff amounts. The data on the decision tree from the Second Decision Point is as follows, The square decision node stemming from favourable survey results branches into five additional branches, Large Plant, State of Nature Node 2, Favorable Market left parenthesis 0.78 right parenthesis equals a payoff of one hundred and ninety thousand dollars. Large Plant, State of Nature Node 2, Unfavorable Market left parenthesis 0.22 right parenthesis equals a payoff of negative one hundred and ninety thousand dollars. Small Plant, State of Nature Node 3, Favorable Market left parenthesis 0.78 right parenthesis equals a payoff of ninety thousand dollars. Small Plant, State of Nature Node 3, Unfavorable Market left parenthesis 0.22 right parenthesis equals a payoff of negative thirty thousand dollars. No plant equals a payoff of negative ten thousand dollars.     The square decision node stemming from negative survey results branches into five additional branches, Large Plant, State of Nature Node 4, Favorable Market left parenthesis 0.27 right parenthesis equals a payoff of one hundred and ninety thousand dollars. Large Plant, State of Nature Node 4, Unfavorable Market left parenthesis 0.73 right parenthesis equals a payoff of negative one hundred and ninety thousand dollars. Small Plant, State of Nature Node 5, Favorable Market left parenthesis 0.27 right parenthesis equals a payoff of ninety thousand dollars. Small Plant, State of Nature Node 3, Unfavorable Market left parenthesis 0.73 right parenthesis equals a payoff of negative thirty thousand dollars. No plant equals a payoff of negative ten thousand dollars.   The square decision node stemming from Do Not Conduct Survey branches into five additional branches, Large Plant, State of Nature Node 6, Favorable Market left parenthesis 0.50 right parenthesis equals a payoff of two hundred thousand dollars. Large Plant, State of Nature Node 6, Unfavorable Market left parenthesis 0.50 right parenthesis equals a payoff of negative one hundred and eighty thousand dollars. Small Plant, State of Nature Node 7, Favorable Market left parenthesis 0.50 right parenthesis equals a payoff of one hundred thousand dollars. Small Plant, State of Nature Node 7, Unfavorable Market left parenthesis 0.50 right parenthesis equals a payoff of negative twenty thousand dollars. No plant equals a payoff of zero.
  • #45 Long Description: Equals E M V, left parenthesis, large plant vertical bar positive survey, right parenthesis, equals, left parenthesis, 0.78, right parenthesis, left parenthesis, 190,000 dollars, right parenthesis, plus, left parenthesis, 0.22, right parenthesis, left parenthesis, negative 190,000 dollars, right parenthesis, equals 106,400 dollars. E M V, node 3, equals E M V, left parenthesis, small plant vertical bar positive survey, right parenthesis, equals, left parenthesis, 0.78, right parenthesis, left parenthesis, 90,000 dollars, right parenthesis, plus, left parenthesis, 0.22, right parenthesis, left parenthesis, negative 30,000 dollars, right parenthesis, equals 63,600 dollars. E M V for no plant equals negative 10,000.
  • #46 Long Description: Equals E M V, left parenthesis, large plant vertical bar negative survey, right parenthesis, equals, left parenthesis, 0.27, right parenthesis, left parenthesis, 190,000 dollars, right parenthesis, plus, left parenthesis, 0.73, right parenthesis, left parenthesis, negative 190,000 dollars, right parenthesis, equals negative 87,400 dollars. E M V, node 5, equals E M V, left parenthesis, small plant vertical bar negative survey, right parenthesis, equals, left parenthesis, 0.27, right parenthesis, left parenthesis, 90,000 dollars, right parenthesis, plus, left parenthesis, 0.73, right parenthesis, left parenthesis, negative 30,000 dollars, right parenthesis, equals 2,400 dollars. E M V for no plant equals negative 10,000.
  • #47 Long Description: Equals E M V, left parenthesis, large plant, right parenthesis, equals, left parenthesis, 0.50, right parenthesis, left parenthesis, 200,000 dollars, right parenthesis, plus, left parenthesis, 0.50, right parenthesis, left parenthesis, negative 180,000 dollars, right parenthesis, equals 10,000 dollars. E M V, node 7, equals E M V, left parenthesis, small plant, right parenthesis, equals, left parenthesis, 0.50, right parenthesis, left parenthesis, 100,000 dollars, right parenthesis, plus, left parenthesis, 0.50, right parenthesis, left parenthesis, negative 20,000 dollars, right parenthesis, equals 40,000 dollars. E M V for no plant equals 0 dollar.
  • #48 Long Description: The first decision point is at 49,200 dollars. The first decision point branches out into two as follows. Conduct market survey that runs to node 1 with 49,200 dollars and do not conduct survey that runs to second decision point with 40,000 dollars. The options after conducting survey are as follows. Survey results favorable with probability of 0.45 that runs to second decision point with 106,400 dollars, and survey results negative with probability of 0.55 that runs to second decision point with 2,400 dollars. 106,400 dollars at the top of the second decision point branches into the following. Large plant that runs to node 2, small plant that runs to node 3, and no plant with negative 10,000 dollars. Node 2 with 106,400 dollars branches into the following. Favorable market with probability of 0.78 and 190,000 dollars, unfavorable market with probability of 0.22 and negative 190,000 dollars. Node 3 with 63,600 dollars branches into the following. Favorable market with probability of 0.78 and 90,000 dollars, unfavorable market with probability of 0.22 and negative 30,000 dollars. 2,400 dollars at the mid section of the second decision point branches into the following. Large plant that runs to node 4, small plant that runs to node 5, and no plant with negative 10,000 dollars. Node 4 with negative 87,400 dollars branches into the following. Favorable market with probability of 0.27 and 190,000 dollars, unfavorable market with probability of 0.73 and negative 190,000 dollars. Node 5 with 2,400 dollars branches into the following. Favorable market with probability of 0.27 and 90,000 dollars, unfavorable market with probability of 0.73 and negative 30,000 dollars. 40,000 dollars at the bottom of the second decision point branches into the following. Large plant that runs to node 6, small plant that runs to node 7, and no plant with 0 dollars. Node 6 with 10,000 dollars branches into the following. Favorable market with probability of 0.50 and 200,000 dollars, unfavorable market with probability of 0.50 and negative 180,000 dollars. Node 7 with 40,000 dollars branches into the following. Favorable market with probability of 0.50 and 100,000 dollars, unfavorable market with probability of 0.50 and negative 20,000 dollars.
  • #53 Long Description: P, left parenthesis, unfavorable market, left parenthesis, U M, right parenthesis, vertical bar survey results positive, right parenthesis, equals 0.22. P, left parenthesis, favorable market, left parenthesis, F M, right parenthesis, vertical bar survey results negative, right parenthesis, equals 0.27. P, left parenthesis, unfavorable market, left parenthesis, U M, right parenthesis, vertical bar survey results negative, right parenthesis, equals 0.73.
  • #56 P(FM| survey positive) = (0.7 × 0.5)/(0.7 × 0.5 + 0.2 × 0.5) = 0.35/0.45 = 0.78 P(UM| survey positive) = (0.2 × 0.5)/(0.2 × 0.5 + 0.7×0.5) = 0.1/0.45 = 0.22
  • #57 P(FM| survey negative) = (0.3 × 0.5)/(0.3 × 0.5 + 0.8 × 0.5) = 0.15/0.55 = 0.27 P(UM| survey negative) = (0.8 × 0.5)/(0.8 × 0.5 + 0.3 × 0.5) = 0.40/0.55 = 0.73
  • #58 Long Description: Two data tables, Probability Revisions Given a Positive Survey and Probability Revisions Given a Negative Survey, appear on the screen. Probability Revisions for a positive survey are calculated at 0.45, while Probability Revisions for a negative survey are calculated at 0.55. Each probability revision table consists of five columns of four rows each. The Probability Revisions Given a Positive Survey table is as follows, Column A, descending, State of Nature F M U M Column B, descending, P left parenthesis Sur. Pos. 0.7 0.2 Column C, descending, Prior Prob. 0.5 0.5 P left parenthesisSur.pos right parenthesis equals Column D, descending, Joint Prob. 0.35 0.1 0.45 appears in bold text Column E, descending, Posterior Probability 0.78 0.22 Blank cell The Probability Revisions Given a Negative Survey table is as follows, Column A, descending, State of Nature F M U M Column B, descending, P left parenthesis Sur. Pos. 0.3 0.8 Column C, descending, Prior Prob. 0.5 0.5 P left parenthesisSur.neg right parenthesis equals Column D, descending, Joint Prob. 0.15 0.4 0.55 appears in bold text Column E, descending, Posterior Probability 0.27 0.73 Blank cell
  • #59 Long Description: The first row of the screenshot reads, from left to right, 0.7, 0.5, equals B 7 times C 7, equals D 7 forward slash dollar sign D dollar sign 9 The second row reads 0.2, equals 1 minus C 7, equals B 8 times C 8, equals D 8 forward slash dollar sign D dollar sign 9 The third row reads Blank cell, P left parenthesis Sur.pos. right parenthesis equals, equals SUM left parenthesis D 7 colon D 8 right parenthesis The fourth and fifth rows are blank. The sixth row reads P left parenthesis Sur. Pos. state of, Prior Prob., Joint Prob., and Posterior Probability The seventh row reads = 1 minus B 7, equals C 7, equals B 13 times C 13, equals D 13 forward slash dollar sign D dollar sign 15 The eighth row reads equals 1 minus B 8, equals C 8, equals B 14 times C 14, equals D 14 forward slash dollar sign D dollar sign 15 The ninth row reads Blank cell, P left parenthesis Sur. neg. right parenthesis equals, equals SUM left parenthesis D 13 colon D 14 right parenthesis
  • #62 Long Description: The Reject Offer branch ends in a state of nature node labeled E M V equals two million, five hundred dollars. That node branches into a Heads left parenthesis 0.5 right parenthesis branch with zero dollars appearing at the end and a Tails left parenthesis 0.5 right parenthesis branch with five million dollars appearing at the end.
  • #63 Expected utility of alternative 2 = Expected utility of alternative 1 Utility of other outcome = p×(utility of best outcome, which is 1) + (1-p)×(utility of worst outcome, which is 0) Utility of other outcome = p×(1)+(1-p)×0 = p Long Description: The Alternative 1 branch ends in a state of nature node, two branches stem from it, left parenthesis p right parenthesis that ends with the text Best Outcome Utility equals 1 and left parenthesis 1 minus p right parenthesis that ends with the text Worst Outcome Utility equals zero. The Alternative 2 branch ends with the text Other Outcome Utility equals question mark.
  • #65 Assess other utility values: Utility for $7,000 = 0.9 Utility for $3,000 = 0.5 Use the three different dollar amounts and assess utilities. Long Description: Along the bottom of the diagram is the following equation, Utility for five thousand dollars equals U times five thousand dollars equals the product of p times U times ten thousand dollars the whole added to the product of 1 minus p times U times zero dollars equals the sum of 0.8 times 1and 0.2 times zero equals 0.8. The first branch extending from the decision node is labeled Invest in Real Estate. There is a state of nature node at the end, it branches into the following, P equals 0.80 which results in ten thousand dollars, U times ten thousand dollars equals 1.0 Left parenthesis 1 minus p right parenthesis equals 0.20 which results in zero dollars, U times 0 dollars equals 0.0 The second branch extending from the decision node is labeled Invest in Bank. It ends with the data five thousand dollars, U times five thousand dollars equals p equals 0.80
  • #66 Long Description: The line graph has Monetary Value, ranging from zero to ten thousand dollars in increments of one thousand, on the horizontal axis and Utility, ranging from zero to 1.0 in increments of 0.1, on the vertical axis, plots the following data, U times zero dollars equals zero, U times three thousand dollars equals 0.50, U times five thousand dollars equals 0.80, U times seven thousand dollars equals 0.90, and U times ten thousand dollars equals 1.0. The graph starts at ($0, 0), rises through ($3,000, 0.5), ($5,000, 0.80), ($7,000, 0.90), ($10,000, 1.0).
  • #67 Long Description: A straight line bisects the graph area into two triangular halves, the top area shows a curved line bending downward toward the bisector and is labeled Risk Avoider. The bottom area shows a curved line bending upward toward the bisector and is labeled Risk Seeker. The bisecting line is labeled Risk Indifference.
  • #68 Long Description: Alternative 1 Mark plays the game come to a state of nature node with two additional branches, Tack lands point up left parenthesis 0.45 right parenthesis which would yield ten thousand dollars, and Tack lands point down left parenthesis 0.55 right parenthesis which would yield negative ten thousand dollars. Alternative 2 Mark does not play the game would result in zero dollars.
  • #69 Long Description: Utility is plotted on the vertical axis, ranging from zero to 1.00 in the following increments, 0.05, 0.15, 0.25, 0.30, 0.50, 0.75, and 1.00. The line curves up and to the right, crossing the following intersections, ten thousand dollars and 0.05, zero dollars and 0.15, ten thousand dollars and 0.30. The graph starts at ($ negative 20,000, 0), and rises through (negative 10,000, 0.05), ($0, 0.15), ($10,000, 0.30) to the first quadrant.
  • #70 Long Description: Utility values have been added to each branch of the tree. Tack Lands Point Up has a utility of 0.30, Tack Lands Point Down has a utility of 0.05, and Don’t Play has a utility of 0.15. There is a pair of slash lines through the Don’t Play branch.