The document explains mesh analysis in electrical circuit analysis, defining key terms such as nodes, junctions, loops, and meshes. It provides step-by-step instructions for applying Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) to solve for mesh currents in a given circuit. The content includes equations and example calculations for two circuits, culminating in a mesh analysis assignment.

1. CLASS 1- MESH ANALYSIS
22EE31-ELECTRIC CIRCUIT ANALYSIS

2. CIRCUIT TERMINLOGIES
• Node is a point in a network where two or
more circuit elements are connected.
• Junction: A point where three or more branches
meet
• Loop: Any close path in the circuit can be called
as a loop.
• Mesh: If the loop in the circuit does not enclose
any other loop inside it then that loop can be
called as a mesh.

3. NODE & JUNCTION
ALL JUNCTIONS ARE NODES BUT
ALL NODES ARE NOT JUNCTIONS

4. MESH & LOOP
ALL MESH ARE LOOP BUT
ALL LOOPS ARE NOT MESH

5. FIND THE NODES, JUN, LOOP & MESH

6. FIND THE NODES, JUN, LOOP & MESH
NODES- A, B, C. D
JUNCTION- B,D
E & F ARE MERGED WITH D- REF NODE
LOOP- ABCEDFA, ABDFA, BCEDB
MESH- ABDFA, BCEDB
E
F

7. MESH ANALYSIS- CIRCUIT 1
I2
I1
ASSUME- CURRENT IN MESH 1- I1, CURRENT IN MESH 2-I2 ; DIRECTIONS AS SHOWN
IN THE CIRCUIT
CURRENT THROUGH R1- I1, THROUGH R2- I2, THROUGH R3- I1 + I2
IN VOLTAGE SOURCE- CURRENT FLOW FROM NEGATIVE TO POSITIVE- POTENTIAL
RISE
CURRENT FLOW FROM POSITIVE TO NEGATIVE- POTENTIAL DROP

8. A
B
C
D
CONSIDER ,MESH 1-
ABEFA- APPLY KVL-SUM OF POT RISE=
SUM OF POT DROP
POT RISE- BY SOURCE BATTERY-V1-
CURRENT FLOW ASSUMED FROM – VE
TO +VE HENCE POT RISE
DROP ACROSS RESISTOR 1 = I1R1 (BY
OHMS LAW)
DROP ACROSS RESISTOR 3= (I1+I2) R3
APPLY KCL AT JUNCTION B
SUM OF CURRENTS ENTERING= SUM OF
CURRENTS LEAVING---- I1+ I2 = I3
HENCE…KVL FOR MESH 1-
V1= I1RI + (I1+ I2)R3
10= I110I + (I1+ I2)40--------(1)
E
F
SOLN:
FIND THE NUMBER OF MESH
NUMBER OF MESH= NUMBER
OF EQUATIONS
HERE
NO OF MESH- 2
THEREFORE NO OF EQN = 2
UNKNOWN- 2 CURRENTS I1, I2
I3 CAN BE FOUND BY ADDING I1
AND I2

9. A
B
C
D
CONSIDER ,MESH 2-
BCDEB- APPLY KVL-SUM OF POT RISE=
SUM OF POT DROP
POT RISE- BY SOURCE BATTERY-V2-
CURRENT FLOW ASSUMED FROM – VE
TO +VE HENCE POT RISE
DROP ACROSS RESISTOR 2 = I2R2 (BY
OHMS LAW)
DROP ACROSS RESISTOR 3= I3 R3
= (I1+I2) R3
HENCE…KVL FOR MESH 2-
V2= I2R2 + (I1+ I2)R3
20= I220 + (I1+ I2)40-------(2)
E
F
NOW SOLVE EQN (1) AND (2)
TO FIND CURRENT I1 AND I2,
HENCE FIND I3
10= I110 + (I1+ I2)40--------(1)
20= I220 + (I1+ I2)40-------(2)
EQN (1)-----10= 50 I1 + 40 I2
EQN (2)-----20= 40 I1 + 60 I2
Complete the solution
and submit as assignment

10. MESH ANALYSIS- CIRCUIT 2- ASSIGNMENT
I1 I2
FIND I1 AND I2 USING MESH ANALYSIS