PHY 406
Chapter 1:
Measurement
Dr. Suraya Ahmad Kamil
At the end of this chapter, students should be able to:-
❖State basic quantities with their respective SI units: length (m),
time (s), mass (kg), electrical current (A), temperature (K) and
amount of substance (mol).
❖State derive quantities and their respective units and symbols:
velocity (ms-1
), acceleration (ms-2
), work (J), Force (N),
pressure (Pa), energy (J), power (W) and frequency (Hz).
❖Perform dimensional analysis and conversion units.
OUTLINE
1.1 Physical quantities: Basic and derived quantities
1.2 System of unit: SI unit and unit conversion
1.3 Dimension and Dimensional Analysis
Chapter 1
• Physical quantity is defined as a quantity which can be
measured.
• It can be categorised into two types
1.Basic (base) quantity
2.Derived quantity
• Basic quantity is defined as a quantity which cannot be
derived from any physical quantities.
• Derived quantity is defined as a quantity which can be
expressed in term of base quantity which is a combination of
two or more physical quantities.
Basic (base) quantity
Chapter 1
Derived Quantity
Chapter 1
UNITS
Chapter 1
• Physics experiments involve the measurement of a variety
of quantities.
• These measurements should be accurate and reproducible.
• The first step in ensuring accuracy and reproducibility is
defining the units in which the measurements are made.
Unit is defined as a standard size of measurement of
physical quantities.
Examples:
- 1 second is defined as the time required for 9,192,631,770
vibrations of radiation emitted by a caesium-133 atom.
- 1 kilogram is defined as the mass of a platinum-iridium
cylinder kept at International Bureau of Weights and
Measures Paris.
- 1 meter is defined as the length of the path travelled by
light in vacuum during a time interval of 1/299,792,458 of a
second.
Chapter 1
The common system of units used today are:-
• S.I unit (International System of Units)
e.g: meter, kilogram, second.
• CGS Unit- UK.
e.g: centimetre, gram, second.
Chapter 1
PREFIXES OF UNIT
• It is used for presenting larger and smaller values.
• Written in the following form (standard scientific
notation)
Example:
An electron mass is about 0.000 000 000 000 000 000
000 000 000 000 910 938 22 kg.
In scientific notation, written as 9.1093822 x 10-31
kg.
Chapter 1
A x 10b
• Table shows all the unit prefixes
Chapter 1
Chapter 1
DIMENSIONAL ANALYSIS
Dimension is defined as a technique or method which the physical
quantity can be expressed in terms of combination of basic quantities.
• It can be written as [physical quantity or its symbol]
• Table shows the dimension of basic quantities.
Chapter 1
DIMENSIONAL ANALYSIS
• Dimension can be treated as algebraic quantities through the procedure
called dimensional analysis.
• The uses of dimensional analysis are:-
✓ to determine the unit of the physical quantity.
✓ to determine whether a physical equation is correct or not
dimensionally by using the principle of homogeneity.
✓ to derive a physical equation.
Note:
• Dimension of dimensionless constant is 1.
• Dimensions cannot be added or subtracted.
• The validity of an equation cannot determined by dimensional analysis.
• The validity of an equation can only be determined by experiment.
Chapter 1
EXERCISE 1:
Determine a dimension and S.I unit for the following quantities:
a) Velocity
b) Acceleration
c) Linear momentum
d) Force
Answers:
c) MLT-1
, kgms-1
d) MLT-2
, kgms-2
EXERCISE 2:
(a)
(b)
(c)
Checking the homogeneity/consistency of an equation.
𝑣=𝑢+𝑎𝑡
𝑠=𝑢𝑡+
1
2
𝑎𝑡
2
𝑠=𝑎𝑡 +
1
2
𝑢𝑡
2
Answers:
b) not homogen
c) homogen
Exercise 3 :
The period, T of a simple pendulum depends on its length l, acceleration due
to gravity, g and mass, m. By using dimensional analysis, obtain an equation
for period of the simple pendulum.
Constructing an equation using dimensional analysis
EXERCISE 4
The velocity of wave depends on the wavelength , surface tension and water
density . Determine the wave velocity equation by using dimensional analysis.
Answers:
𝑘
√𝛾
𝜆𝜌
CONVERSION OF UNITS
Chapter 1
Length Mass Force
1 mile = 1609 m = 1.609 km 1 metric ton = 10 kg
3 1 lb = 4.448 N
1 ft = 0.3048 m = 30.48 cm 1 slug =14.59 kg 1 N = 0.2248 lb = 10 dyne
5
1 m = 39.37 in = 3.281 ft
1 in. = 0.0254 m = 2.54 cm
CONVERSION FACTORS TO REMEMBER
1 km = 1000 m
1 km = 0.621 mi
1 m = 100 cm
1 cm = 10 mm
1 inch = 2.54 cm
1 kg = 1000 g
1 h = 60 min
1 min = 60 s
1 h = 3600 s
Chapter 1
Reasoning Strategy: Converting Between Units
1. In all calculations, write down the units explicitly.
2. Treat all units as algebraic quantities. When identical units are
divided, they are eliminated algebraically.
3. Use the conversion factors located on the page facing the
inside cover. Be guided by the fact that multiplying or dividing
an equation by a factor of 1 does not alter the equation.
Exercise 5: The World’s Highest Waterfall
The highest waterfall in the world is Angel Falls in Venezuela, with a
total drop of 979.0 m. Express this drop in feet.
Exercise 6:
A solid cube of copper has a density of 8.94 g/cm3
. Convert this value to kg/m3
.
Exercise 7:
Bicyclists in the Tour de France cycle at a speed of 34.0 miles per hour (mi/h) on flat
sections of the road. What is this speed in
a) kilometers per hour (km/h)
b) meters per second (m/s)
(1.609 km = 1 mi, 1 mi = 1609 m, 1 h = 3600s)
Answers:
a) 54.7 km/h b) 15.2 m/s
Exercise 9:
Answer: 6.67 X 10-5
mm3
g-1
s-2
.
Given that the gravitational constant, G = 6.673 X 10-11
m3kg-1
s-2
. Determine its value in
mm3
g-1
s-2
.
Exercise 8:
Calculate the area of a rectangle, in km2, where the sides of the rectangle are 7 inches
and 13 inches respectively. Given 1 inch = 2.54 cm.
Answer: 5.87 X 10-8
km2
.
Exercise 10:
Change 17.7 µm/1.6 X 10-3
ps into its SI unit.
Answer: 1.106 X 10-10
m/s
ACCURACY AND PRECISION
ACCURACY
• In the fields of engineering, industry and statistics, the accuracy of a
measurement system is the degree of closeness of measurements of a
quantity to its actual (true) value.
of
a
system,
PRECISION
• The
precision
measurement
also
called reproducibility or
repeatability, is the degree
to which
measurements
unchanged
repeated
under
conditions
show the same results.
Low Accuracy High Accuracy High Accuracy
High Precision Low Precision High
Precision
SIGNIFICANT FIGURE
• There are 2 kinds of numbers:
– Exact: the amount of money in your account. Known
with
certainty.
– Approximate: weight, height—anything
MEASURED. No measurement is perfect.
• When a measurement is recorded only those digits that
are
dependable are written down.
• If you measured the width of a paper with your ruler you might
record 21.7 cm.
• To a mathematician 21.70, or 21.700 is the same but,
to a
scientist 21.7 cm and 21.70 cm is NOT the same
• 21.700 cm to a scientist means the measurement is accurate to
within one thousandth of a cm.
• The significant figures (also called significant digits and
abbreviated sig figs, sign.figs or sig digs) of a number are those
digits that carry meaning contributing to its precision.
• Zeroes are sometime used to locate the decimal point, when the
zeroes are used in that way we say that they are not significant.
SIGNIFICANT FIGURES (SF) Chapter 1
1. All non zero digits in a
number are SF.
2. Zero in between two non
zero digits are SF.
3. For any whole number,
zero at the end of a
number can be a SF or not
a SF It
. depends on the
precision of the reading.
Example
1. (i) 3421 : 4 sf
(ii) 62.5 : 3 sf
2. (i) 503 : 3 sf
(ii) 1.006 : 4 sf
3. (i) 63 000 : 2 sf if the precision
is to the nearest thousand.
(ii) 63 400 : 3 sf if the precision
is to the nearest hundred.
SIGNIFICANT FIGURES (SF)
Chapter 1
4. For a decimal number less
than 1, zero placed before any
non-zero digit is not a sf
5. For a decimal number, zero
placed after a non-zero digit is
a sf.
Example
4. (i) 0.0028 : 2 sf
(ii) 0.0902 : 3 sf
5. (i) 7.40 : 3 sf
(ii) 0.020 : 2 sf
SIGNIFICANT FIGURES (SF):
Addition and Subtraction
• The final results of addition or subtraction should no more
precise than the least precise number used
• E.g : Calculate 4.231 + 3.51
• Ans: 7.741= 7.74
Least no of SF
The final results of multiplication or division should have
only as many digits as the number with the least number of
significant figures used in the calculation.
E.g : Calculate the area of a rectangle 11 .3 cm by 6.8 cm.
Ans: 76.84 cm = 77 cm
2 2
SIGNIFICANT FIGURES (SF):
Multiplication & Division
Chapter 1
Least no of SF
How many sig figs?
7
40
0.5
0.00003
7 x 103
7,000,000
3401
2100
2100.0
5.00
0.00412
8,000,050,000
END OF CHAPTER 1

Chapter 1 Measurement.pptx PHY406 BASIC PHYSICS

  • 1.
  • 2.
    At the endof this chapter, students should be able to:- ❖State basic quantities with their respective SI units: length (m), time (s), mass (kg), electrical current (A), temperature (K) and amount of substance (mol). ❖State derive quantities and their respective units and symbols: velocity (ms-1 ), acceleration (ms-2 ), work (J), Force (N), pressure (Pa), energy (J), power (W) and frequency (Hz). ❖Perform dimensional analysis and conversion units.
  • 3.
    OUTLINE 1.1 Physical quantities:Basic and derived quantities 1.2 System of unit: SI unit and unit conversion 1.3 Dimension and Dimensional Analysis
  • 4.
    Chapter 1 • Physicalquantity is defined as a quantity which can be measured. • It can be categorised into two types 1.Basic (base) quantity 2.Derived quantity • Basic quantity is defined as a quantity which cannot be derived from any physical quantities. • Derived quantity is defined as a quantity which can be expressed in term of base quantity which is a combination of two or more physical quantities.
  • 5.
  • 6.
  • 7.
    UNITS Chapter 1 • Physicsexperiments involve the measurement of a variety of quantities. • These measurements should be accurate and reproducible. • The first step in ensuring accuracy and reproducibility is defining the units in which the measurements are made.
  • 8.
    Unit is definedas a standard size of measurement of physical quantities. Examples: - 1 second is defined as the time required for 9,192,631,770 vibrations of radiation emitted by a caesium-133 atom. - 1 kilogram is defined as the mass of a platinum-iridium cylinder kept at International Bureau of Weights and Measures Paris. - 1 meter is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second. Chapter 1
  • 9.
    The common systemof units used today are:- • S.I unit (International System of Units) e.g: meter, kilogram, second. • CGS Unit- UK. e.g: centimetre, gram, second. Chapter 1
  • 10.
    PREFIXES OF UNIT •It is used for presenting larger and smaller values. • Written in the following form (standard scientific notation) Example: An electron mass is about 0.000 000 000 000 000 000 000 000 000 000 910 938 22 kg. In scientific notation, written as 9.1093822 x 10-31 kg. Chapter 1 A x 10b
  • 11.
    • Table showsall the unit prefixes Chapter 1
  • 12.
    Chapter 1 DIMENSIONAL ANALYSIS Dimensionis defined as a technique or method which the physical quantity can be expressed in terms of combination of basic quantities. • It can be written as [physical quantity or its symbol] • Table shows the dimension of basic quantities.
  • 13.
    Chapter 1 DIMENSIONAL ANALYSIS •Dimension can be treated as algebraic quantities through the procedure called dimensional analysis. • The uses of dimensional analysis are:- ✓ to determine the unit of the physical quantity. ✓ to determine whether a physical equation is correct or not dimensionally by using the principle of homogeneity. ✓ to derive a physical equation. Note: • Dimension of dimensionless constant is 1. • Dimensions cannot be added or subtracted. • The validity of an equation cannot determined by dimensional analysis. • The validity of an equation can only be determined by experiment.
  • 14.
    Chapter 1 EXERCISE 1: Determinea dimension and S.I unit for the following quantities: a) Velocity b) Acceleration c) Linear momentum d) Force Answers: c) MLT-1 , kgms-1 d) MLT-2 , kgms-2
  • 15.
    EXERCISE 2: (a) (b) (c) Checking thehomogeneity/consistency of an equation. 𝑣=𝑢+𝑎𝑡 𝑠=𝑢𝑡+ 1 2 𝑎𝑡 2 𝑠=𝑎𝑡 + 1 2 𝑢𝑡 2 Answers: b) not homogen c) homogen
  • 16.
    Exercise 3 : Theperiod, T of a simple pendulum depends on its length l, acceleration due to gravity, g and mass, m. By using dimensional analysis, obtain an equation for period of the simple pendulum. Constructing an equation using dimensional analysis
  • 17.
    EXERCISE 4 The velocityof wave depends on the wavelength , surface tension and water density . Determine the wave velocity equation by using dimensional analysis. Answers: 𝑘 √𝛾 𝜆𝜌
  • 18.
    CONVERSION OF UNITS Chapter1 Length Mass Force 1 mile = 1609 m = 1.609 km 1 metric ton = 10 kg 3 1 lb = 4.448 N 1 ft = 0.3048 m = 30.48 cm 1 slug =14.59 kg 1 N = 0.2248 lb = 10 dyne 5 1 m = 39.37 in = 3.281 ft 1 in. = 0.0254 m = 2.54 cm
  • 19.
    CONVERSION FACTORS TOREMEMBER 1 km = 1000 m 1 km = 0.621 mi 1 m = 100 cm 1 cm = 10 mm 1 inch = 2.54 cm 1 kg = 1000 g 1 h = 60 min 1 min = 60 s 1 h = 3600 s Chapter 1
  • 20.
    Reasoning Strategy: ConvertingBetween Units 1. In all calculations, write down the units explicitly. 2. Treat all units as algebraic quantities. When identical units are divided, they are eliminated algebraically. 3. Use the conversion factors located on the page facing the inside cover. Be guided by the fact that multiplying or dividing an equation by a factor of 1 does not alter the equation.
  • 21.
    Exercise 5: TheWorld’s Highest Waterfall The highest waterfall in the world is Angel Falls in Venezuela, with a total drop of 979.0 m. Express this drop in feet.
  • 22.
    Exercise 6: A solidcube of copper has a density of 8.94 g/cm3 . Convert this value to kg/m3 . Exercise 7: Bicyclists in the Tour de France cycle at a speed of 34.0 miles per hour (mi/h) on flat sections of the road. What is this speed in a) kilometers per hour (km/h) b) meters per second (m/s) (1.609 km = 1 mi, 1 mi = 1609 m, 1 h = 3600s) Answers: a) 54.7 km/h b) 15.2 m/s
  • 23.
    Exercise 9: Answer: 6.67X 10-5 mm3 g-1 s-2 . Given that the gravitational constant, G = 6.673 X 10-11 m3kg-1 s-2 . Determine its value in mm3 g-1 s-2 . Exercise 8: Calculate the area of a rectangle, in km2, where the sides of the rectangle are 7 inches and 13 inches respectively. Given 1 inch = 2.54 cm. Answer: 5.87 X 10-8 km2 . Exercise 10: Change 17.7 µm/1.6 X 10-3 ps into its SI unit. Answer: 1.106 X 10-10 m/s
  • 24.
  • 25.
    ACCURACY • In thefields of engineering, industry and statistics, the accuracy of a measurement system is the degree of closeness of measurements of a quantity to its actual (true) value.
  • 26.
    of a system, PRECISION • The precision measurement also called reproducibilityor repeatability, is the degree to which measurements unchanged repeated under conditions show the same results.
  • 27.
    Low Accuracy HighAccuracy High Accuracy High Precision Low Precision High Precision
  • 28.
    SIGNIFICANT FIGURE • Thereare 2 kinds of numbers: – Exact: the amount of money in your account. Known with certainty. – Approximate: weight, height—anything MEASURED. No measurement is perfect. • When a measurement is recorded only those digits that are dependable are written down. • If you measured the width of a paper with your ruler you might record 21.7 cm. • To a mathematician 21.70, or 21.700 is the same but, to a scientist 21.7 cm and 21.70 cm is NOT the same • 21.700 cm to a scientist means the measurement is accurate to within one thousandth of a cm.
  • 29.
    • The significantfigures (also called significant digits and abbreviated sig figs, sign.figs or sig digs) of a number are those digits that carry meaning contributing to its precision. • Zeroes are sometime used to locate the decimal point, when the zeroes are used in that way we say that they are not significant.
  • 30.
    SIGNIFICANT FIGURES (SF)Chapter 1 1. All non zero digits in a number are SF. 2. Zero in between two non zero digits are SF. 3. For any whole number, zero at the end of a number can be a SF or not a SF It . depends on the precision of the reading. Example 1. (i) 3421 : 4 sf (ii) 62.5 : 3 sf 2. (i) 503 : 3 sf (ii) 1.006 : 4 sf 3. (i) 63 000 : 2 sf if the precision is to the nearest thousand. (ii) 63 400 : 3 sf if the precision is to the nearest hundred.
  • 31.
    SIGNIFICANT FIGURES (SF) Chapter1 4. For a decimal number less than 1, zero placed before any non-zero digit is not a sf 5. For a decimal number, zero placed after a non-zero digit is a sf. Example 4. (i) 0.0028 : 2 sf (ii) 0.0902 : 3 sf 5. (i) 7.40 : 3 sf (ii) 0.020 : 2 sf
  • 32.
    SIGNIFICANT FIGURES (SF): Additionand Subtraction • The final results of addition or subtraction should no more precise than the least precise number used • E.g : Calculate 4.231 + 3.51 • Ans: 7.741= 7.74 Least no of SF
  • 33.
    The final resultsof multiplication or division should have only as many digits as the number with the least number of significant figures used in the calculation. E.g : Calculate the area of a rectangle 11 .3 cm by 6.8 cm. Ans: 76.84 cm = 77 cm 2 2 SIGNIFICANT FIGURES (SF): Multiplication & Division Chapter 1 Least no of SF
  • 34.
    How many sigfigs? 7 40 0.5 0.00003 7 x 103 7,000,000 3401 2100 2100.0 5.00 0.00412 8,000,050,000
  • 35.