Cell Image Cell type eukaryotic cell t prokaryotic cell Solution.pdf

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Cell Image Cell type eukaryotic cell t prokaryotic cell Solution 1st image: Prokaryotic cell. No clear nuclear membrane 2nd image: Prokaryotic cell.No clear nuclear membrane 3rd image: Prokaryotic cell.- Cellwall, nucleoid, ribosomes 4th image:Eukaryotic cell.- Clear nucleus, Clear nuclear membrane, etc.,.

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How do humans detect color? Considering your answer to this question, predict why some \"colorblind\" individuals are unable to distinguish between certain colors. Solution Human eye is impartent and comlicated . human eye is just like camera and having the ability of self focusing .Light from an external object is refracted as it move through the cornea and move to the pupil .Light again refracted by the lens which project image on the ratina .In tatina light is absorbed by cone and rod cells .there are 6-7 million cones in ratina . three different type of cone is present in ratina sensitive to short medium and long wevelength .cones respond to red blue and green light .the signals from cones transmited to brain by nerve . the ganglion of brain cells determine the colour. Colour blind human are unable to distiguish between certai colour due to insensitivity of cone cells . When the cone cells are insensitive to long wavelength red colour look darker than they actually are . the green tend to look similar to red . when cones are insensitive to medium wavelength and human can not see red and green colour . when cones are insensitive to shoet wavelength light human can not distinguish blue and green colour ..

How do humans detect color Considering your answer to this question.pdf

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Identify the unique characteristics of auditing profession Solution ANSWER: Auditing refers to evaluating the effectiveness of a company\'s internal controls. An audit is an assessment of an individual, process, system, firm, organization, institution, company, project, or product. Audits are carried out to check and verify the reliability of any given information and give an evaluation of the internal control of the system. Unique Characteristics of auditing profession: --Pursue goals: A unique auditing profession is a important because it facilitates to pursue for the attainment of several corporate purposes. It helps to prevent and identify irregular transaction, measure the performance of the corporate, maintain adequate business records and to enhance the productivity. --Fraud Prevention: Auditing serves vital role for companies in the prevention of fraud. Recurring analysis of the operations and maintaining rigorous systems in the company can prevent and detect various forms of accounting irregularities and other fraud activities. Audit professionals helps in the design and modification of the control systems the purpose of which includes, among other things, prevention of fraud. -- Cost of Capital: Unique audit systems profession reduces the several forms of risk in an enterprise, including its information risk (the risk of material misstatement in financial reporting), the risk of suboptimal management due to insufficient information on its operations and also the risk of fraud and misappropriation of assets. --Prevents debilitating misstatements: A unique auditing system helps in preventing debilitating misstatements in a company’s records and reports --A thirst for knowledge: Auditors needs to strive to cultivate a deep knowledge of the company consisting of its culture, key players and competitive environment. It is main factor that is guaranteed to set audit apart from other auditing and risk compliance professionals --Innovation: Every company has its own inner workings and to be a unique auditing manager or compliance officer needs creativity. Combine innovation with current company\'s processes to provide impressive results. --Communication/People skills: The ability to read people and adapt for any given situation is a key driver in those who progress up the internal or external auditing career ladder effectively..

Identify the unique characteristics of auditing professionSoluti.pdf

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Hemophilia is a recessive trait. The dominant trait is normal blood dotting A gene that can cause hemophilia is located on the X chromosome. If a homozygous normal female marries a normal male, they children might have which of the following phenotypes: Select one: a. normal females, hemophiliac females, and hemophiliac males. b. normal females, hemophiliac females, normal males, and hemophiliac males. c. normal females and hemophiliac males d. normal females and normal mates. e. normal females, normal males or hemophiliac males. Solution In X - linked recessive inheritance males are more prone to disease because they carry the disease trait. If the affected offspring’s mother has brother or father containing the same trait then the mother pass the trait to her offspring. The affected males produce unaffected daughters who can produce 50% affected sons. Hemophilia is the example of X - linked recessive trait. When a homozygous normal female marries to a normal male the offspring produced are normal females and normal males. Option d is correct..

Hemophilia is a recessive trait. The dominant trait is normal blood d.pdf

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Explain the purpose of the Medium Access Control (MAC) timing parameters Short InterFrame- Space (SIFS), Point (coordination function) Interframe Space (PIFS), and Distributed (coordination function) Interframe Space (DIFS). Explain why they should be carefully chosen. Why has a station at least to wait one DIFS prior to transmission? Solution Answer The purpose of the given MAC timing parameters are as below: SIFS : Short Interframe Space, is the amount of time in microseconds needed by a wireless interface to process a received frame and to respond with a response frame. It is given by the difference in time of the first symbol of the response frame in the air and the last symbol of the received frame in the air. A SIFS time comprises of the delay in receiver RF, PLCP delay and the MAC processing delay, which depends on the physical layer used. Point (co-ordination function) Interframe Space: it co-ordinates the communication within a network.It is the time or duration for which PCF waits to grasp a channel. Distributed (co-ordination function) Interface Space: it controls the access to the physical medium. If DFC protocol finds that the medium is continuously idle for DIFS duration, it is then permitted to transmit a frame. If during the DIFS interval the channel is found busy then that channel is discarded and another channel is looked for. A station has to wait for atleast one DIFS prior to transmission because generally it waits for PIFS duration which is of shorter duration than DIFS and if PIFS is not available it moves to DIFS duration which gets lapsed if a channel is not found. Therefore, atleast one DIFS duration wait is required to know if a channel is found for the transmission or not..

Explain the purpose of the Medium Access Control (MAC) timing paramet.pdf

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find the payment necessary to amortize 8 loan of $1500 for 19 compo.pdf

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explain why HCO3- levels can be calculated from pH and pCO2 levels Solution pH is defined as the negative log of the Hydrogen ion concentration: -log[H+]. (also, pH=pK+log [HCO3]/ 0.03 x pCO2). The pH is the product of two components, respiratory and metabolic, thus allowing for the effect of the pCO2, ie, any change in the pH unexplained by the pCO2 resulting ina metabolic abnormality. CO2 and water combine to form carbonic acid or H2CO3, present with concentrations of bicarbonate (HCO3-)and hydrogen ions (H+) in equilibrium amounts. A change in the concentration of the reactants on either side of the equation affects the subsequent direction of the reaction. Eg., a rise in CO2 will also raise carbonic acid formation (H2CO3) which leads to raised levels of both HCO3- and H+ (\\pH)..

explain why HCO3- levels can be calculated from pH and pCO2 levels.pdf

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Describe the arrangement of neurons in the primary motor cortex Solution The primary motor cortex or M1 is found to be located in the dorsal portion of the frontal lobe in the brain. This is the region which is involved in coding force and direction of movement and M1 works along with posterior parietal cortex, premotor cortex, the supplementary motor area etc to execute its actions. In M1 region we can find Betz cells (large neurons) along with other cortical neurons, these will send long axons till the end of the spinal cord, so that they can synapse onto the interneuron circuitry of the spinal cord. They also send neurons on the alpha motor neurons located in the spinal cord to have connection with the muscles. Using Golgi method, the morphology and the spatial arrangement of neurons in the primary motor cortex has been studies, which revealed the presence of great variety of pyramidal and non-pyramidal cells in M1 region and main difference between these cells is due to their difference in shape, size and also with respect to dimensions and distribution of dendritic trees. It has been reported that columnar aggregation formed were observed in sub-layers III b and c, formed by the somata and dendritic trees of pyramidal and non-pyramidal cells, these are 100- 300 micron wide and are found to be separated by cell-sparse spaces of 50-100 micron width. In these aggregations, we can find several bundles formed by apical dendrites of pyramidal cells. The columnar width was not surpassed by most non-pyramidal cells of dendrites. In layers III and V, the dendrites and somata of pyramidal cells were found to be showing a preferential orientation in the same direction and they will run parallel to the main axis of the gyrus. But in layers II, IV, and V, what aggregations we found in layer III were not found but in layer V, around the giant Betz cells, there was a loose assemblage of neurons of all sizes group were found to be located. The radii of myelinated fibers entering and leaving the white matter were found to be forming radial appearance in Layer VI. The vertical, columnar organization and the asymmetry of somata and dendritic trees were found to be more pronounced when it comes to the boundary of the central sulcus and boundary of precentral gyrus..

Describe the arrangement of neurons in the primary motor cortexS.pdf

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An inbred line of Drosophila will drink sugar water to which small amounts of a bitter substance, quinine, has been added. The variance in quinine concentration tolerated is 200. They are crossed with a different inbred line whose variance in quinine concentration tolerated is 110. Their F_1S have a variance of 110, and their F_2S have a variance of 210. What is the heritability of this trait? Solution Generation Variance P1 200 P2 110 F1 110 F2 210 VE = {VF1 + (VP1+ VP2)/2}/2 = {110 + (110 + 200)/2}/2 = 132.5 VP = 210 Vg = VP – VE = 210 – 132.5 = 77.5 Heritiablity H2 = Vg /VP = 77.5 / 210 = 0.369 Generation Variance P1 200 P2 110 F1 110 F2 210.

An inbred line of Drosophila will drink sugar water to which small am.pdf

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ACC312 Federal Taxation Tax avoidance/Tax evasion questions 1. The entity variable: Which entity undertakes the transaction? 2. The time period variable: During which tax year or years does the transaction occur? 3. The jurisdiction variable: In which tax jurisdiction does the transaction occur? 4. The character variable: What is the tax character of the income from the transaction? Solution Tax evasion is the illegal means of reducing taxes. tax planning has four variables. 1. entity 2. Time period 3. Jurisdiction 4. Character so, the above four questions are based on the tax planning variables..

ACC312 Federal TaxationTax avoidanceTax evasion questions1. The.pdf

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a total of 100 students are taking a history exam. each student is r.pdf

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A case study of a young man with a viral infection In the late winter of 2009 Jeff, a 19 year old male, living in the dorms at college came down suddenly with a virus which kept him out of classes for 3 days. Jeff\'s day started out as a regular day and he went to his classes as he normally does. As the day went on Jeff began to tired and worn out but he figured it was just due to a lack of sleep and feel stress. That night he laid down for bed and recognized he was running a slight fever so he thought he would just sleep it off and feel better in the morning. The next morning when he awoke he had a high fever, chills, body aches and nausea. Jeff only left his bed that day to go to the bathroom a couple times fever, or to get a glass of water. As day went on his symptoms only got worse, by that night his fever chills, and aches were also accompanied by diarrhea. The next day Jeff then began experiencing it vomiting on top of his current symptoms and was unable to drink water or eat any food without 2 days making his stomach feel worse. By that night he was beginning to feel much better, and within 2 days he had almost fully recovered. What was Jeff suffering from? How do we know this wasn\'t the flu? How should his illness have been treated? What were his risk factors for becoming infected? How many people are infected each year in the US with this virus? How can you prevent infection with this virus? What is the mode of transmission and reservoir for this virus? Solution ANSWER: 1) jeff was suffering from Gastroenteritis... 2)We know that was not flu because the symptoms of flu was highfever,bodyaches, chills and sweat, persistent cough,headache,nasalcongestion,sorethoratand weakness.diarrhea not occur in flu.... 3)Drinking enough fluids, and learning what to eat will keep you comfortable. have to manage diarrhea,control nausea,and vomiting and get plenty of rest will help to treat disease.... 4)RISK FACTORS: Gastroenteritis is caused by the people with weak immune system , ingestion of viruses, certain bacteria, or parasites. Food that has spoiled may also cause illness. Young children may develop signs and symptoms of gastroenteritis as a reaction to a new food. HIGH RISK FACTORS INCLUDE: 5)It is estimated that three to five billion cases of gastroenteritis resulting in 1.4 million deaths occur globally each year.IN U.S 10,00O PEOPLE ARE INFECTED...... 6)Prevention:Wash your hands after using the toilet and before handling food. Don’t prepare food for other people until your symptoms improve. Avoid close contact with others during your illness. After your symptoms stop, try to wait at least 48 hours before returning to work. You can also help prevent bacterial gastroenteritis infections by avoiding unpasteurized milk, raw meat, or raw shellfish. Use separate cutting boards and utensils for raw and cooked meats when preparing meals. Wash salads and vegetables thoroughly. Make sure to store food at either very hot or very cold temperatures i.

A case study of a young man with a viral infection In the late winte.pdf

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A child drops a ball from a bridge. The ball strikes the water under the bridge 2.0 seconds later. What is the velocity of the ball when it strikes the water? Solution V=U+AT=0+32*2=64 FT/SEC...OR IN MKS UNITS.... V=0+9.8*2=19.6 M/SEC SEE BELOW FOR EXPLANATION A boy throws a rock straight up into the air. It reaches the highest point of its flight after 2.5 seconds. How fast was the rock giong when it left the boys hand? 1 solutions Answer 17643 by venugopalramana(1171) About Me on 2006-03-21 11:25:11 (Show Source): THE FORMULA TO BE USED IS V=U+AT...WHERE V=FINAL VELOCITY....FT/SEC. U=INITIAL VELOCITY....FT/SEC. A = ACCELERATION ..HERE IT IS DUE TO GRAVITY WHICH IS ACTING AGAINST THE MOTION ..ITS VALUE IS -32 FT/SEC.SEC. T=TIME OF TRAVEL...SEC WE HAVE U=? V=0....AS IT REACHED THE HIGHEST POINT AND WILL STOP AND FALL BACK FROM THERE. T=2.5 SEC. 0=U-32*2.5 U=32*2.5=80 FT/ SEC. IF YOU ARE IN MKS UNITS THEN A=-9.8 M/SEC.SEC U=9.8*2.5=24.5 M/SEC.

A child drops a ball from a bridge. The ball strikes the water under.pdf

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2. A resistant inbred cultivar and a susceptible inbred cultivar are crossed to generate an F1. You observe that the F1 has a level of resistance that is intermediate between the parents. Circle the genetic mechanism below that would NOT explain this observation. A. The resistance is controlled quantitatively. B. The resistance is controlled by a single gene with incomplete dominance alleles. C. The resistance is controlled two dominant genes with epistasis. D. The resistance is controlled by two genes that are acting additively with no epistasis. Solution The correct answer is: C.The resistance is controlled two dominant genes with epistasis. Reason: In case of dominanat epistatis, one dominant gene completely masks the effect of other dominant gene when present together.In this case, we get an intermediate phenotype.So, this cannot be controlled by two dominant genes with epistatis..

2. A resistant inbred cultivar and a susceptible inbred cultivar are.pdf

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Write the program in MIPS that declares an array of positive integer.pdf

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Why does a diploid mother cell that undergoes meiosis produce four haploid cells? Explain what happens during meiosis (i.e. what events take place during meiosis) that helps achieve this goal (four haploid cells). Solution To maintain the stability in chromosome number, diploid mother cell that undergoes meiosis produces four haploid cells Meiosis includes two phases, which are Meiosis I and Meiosis II. (The meiosis classified as divisons for our ...) Each phase includes, Prophase, Metaphase, Anaphase and Telophase. Meiosis I - The major event is Chromosomal segregation. As the presence of chromosomal segregation, in this phase the chromosome number reduced to half of the original number. Prophase, Metaphase, Anaphase and Telophases of Meiosis I are ended with I. Prophase I : includes the following sub stages. Leptotene - thin threads : Boutique stage Zygotene - mating threads : bivalent or tetrad chromosomes. Pachytene - thick threads : chiasmata can observe Diplotene - two threads : homologous chromosomes separate from one another a little. Diakinesis - moving threads : chiasmata clearly visible Metaphase I : Homologous pairs move together along the metaphase plate Anaphase I : homologous chromosomes moves to opposite poles. Telophase I : chromosomes arrive at the poles. Meiosis II - The major event is Chromatid segregation. As the presence of chromatid segregation, in this phase the chromosome number maintained to half of the original number. Prophase, Metaphase, Anaphase and Telophases of Meiosis II are ended with II. Prophase II : shortening and thickening of the chromatids Metaphase II : Chromatids move together along the metaphase plate Anaphase II : Chromatid moves to opposite poles. Telophases II : Chromatid arrive at the poles..

Why does a diploid mother cell that undergoes meiosis produce four h.pdf

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What is an intumescent material? Where is it used? Solution An intumescent material is one that undergoes a chemical change when exposed to heat or flames, becoming viscous then forming expanding bubbles that harden into a dense, heat insulating multi-cellular char. The objectives of intumescent technology are the containment of fire and toxic gases by inhibiting flame penetration, heat transfer and transport of toxic gases from the site of a fire to other parts of a structure. A typical, practical application of intumescence is in fire seal technology, where stips of intumescent material in a carrier are fitted around the perimeter of a fire door. During a fire the fire seals intumescence (expand and char) to resist fire penetration and prevent the spread of fumes. Intumescent technologies are widely used in passive fire protection systems, where potential pathways for the spread of flames and fumes, such as conduits, wall openings and ventilation grilles are fitted with fire retardant products. Passive fire protection materials are usually combined with \"active\" fire supression technologies such as sprinklers, foam generation and inert gas systems. fireproofing items such as - fire seals, smoke seals, letter box systems, pipe collars, pipe sleeves, pipe wraps, duct wrap, fire grilles, cladding seals, fire rated foams, downlighter covers, lighting canopies, luminaire covers. Intumescents are used to achieve passive fire protection for such applications as firestopping, fireproofing, gasketing and window casings. Such applications are relevant for buildings, offshore constructions, ships and aircraft..

What is an intumescent material Where is it used SolutionAn .pdf

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1. How can a computer with only 2G of physical memory run two programs that both use 1.5G each? 2. How is virtual memory related to physical memory? 3. What is the role of the CMOS in the boot process? 4. What happens immediately after the computer is powered up? 5. What steps occur in the POST? 6. What is stored in the boot sector of a fixed disk? 7. A typical Windows machine has two boot sectors- what are they called? 8. What is protected mode? What features become available? 9. What difference is there between kernel mode and user mode? 10. How can the attacker exploit the Windows boot process? Solution 1) using virtual memory and Demand-paging concept 2) Virtual memory mapps real physical address to the virtual memory address to transfer the data between RAM and hard drive 3)CMOS is RAM and it stores the parameters of the devices which are in BIOS.and also it runs our system clock. 4)When power is on two things done in two steps >POST (power-on Self Test) >Operating system loading these two are done in sequence and it first is fails then second will not be happen. POST : It check whether all the necessary things are present and they are working well Operation System Loading : After successfull of POST, CPU searches for storage device to load the special files which indicates the starting of the operating system. 5) > First CPU is reset > CPU check itself and POST is loaded into BIOS > CPU runs BIOS to check componenents connected to PC >DRAM is checke with sample reading and writing of every byte. > keyboard is checked for any key is pressed. > if any key is pressed it goes to BIOS settings to change them. > Hard drives are checked whether they are present or not. > Presence of mouse is also checked. > lastly test results are checked with the data in BIOS > IF any mis matches found then POST will results in failure. 6) Some configuaration files and operating system 8)protected mode is first added in x86 machine and it is also called as protected virtual address mode. It provides access to Virtual address, Paging and multitasking for system software to have control over application software. 9)Kernel Mode is to have communication with hardware and it happens under OS. >Kernel mode programs are most supervised. >these may terminate the process > any clashes comes system may crashes --->User mode is just excuting porgrams and he has no permission to have connection with hardware. >less priority >any clashes comes nothing is going to happen.

1. How can a computer with only 2G of physical memory run two progra.pdf

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this is VerilogHDL classAre these legal identifiersa. system1.pdf

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Transactions made by Ivanhoe Company for the month of March are shown below. 1. The company performed $19,650 of services for customers on account. 2. The company received $19,650 in cash from customers who had been billed for services [in transaction (1) 3. The company received a bill for $3,450 of advertising but will not pay it until a later date 4. Ivanhoe Company paid a cash dividend of $4,000 Prepare a tabular analysis that shows the effects of these transactions on the expanded accounting equation. (If a transaction causes a decrease in Assets, Liabilities or Stockholders Equity, place a negative sign (or parentheses) in front of the amount entered for the particular Asset, Liability or Equity item that was reduced. See Ilustration 3-3 for example.) Liabilities+ Stockholders\' Equity Cash + Accounts Receivable = Accounts Payable + Common Stock + Retained Earnings RevenuesExpensesDividends Solution solution :-CashAccounts ReceivableAccounts PayableCommon StockRetained EarningRevenuesExpensesDividends1)+$19650+$196502)+$19650-$196503)+$3450-$34504)- $4000-$4000.

Transactions made by Ivanhoe Company for the month of March are shown.pdf

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The plastic behavior of materials is explained by dislocation theory..pdf

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