Is there a vertex common to every longest path in the following graph.pdf
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Is there a vertex common to every longest path in the following graph? Solution No, there is no such vertex common to any of the two similar longer paths. Suppose, if we consider the two equal horizontal lines of the bigger rectangle we can clearly see there is no common vertex and similarly for others..
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Need help finding the error in my code. Wherever theres a player.pdf
Need help finding the error in my code. Wherever there\'s a \"player.\" something netbeans
shows an error saying \"cannot find symbol\".
import java.util.Scanner;
public class DicePlayer {
private boolean player;
private String name;
private double cash;
Scanner scnr=new Scanner(System.in);
public void setName()
{
System.out.println(\"Enter the name of the player\ \");
name=scnr.next();
}
public void setCash ()
{
System.out.println(\"Give the amount on the hand\ \");
cash=scnr.nextDouble();
}
public String getName()
{
return name;
}
public double getCash()
{
return cash;
}
public boolean addCash()
{
double add;
System.out.println(\"Give the amount to add\ \");
add=scnr.nextInt();
if (add>0)
{
cash=cash+add;
return true;
}
else
return false;
}
public boolean subCash()
{
double sub;
System.out.println(\"Give the amount to sub\ \");
sub=scnr.nextInt();
if (sub>0 && sub
Solution
I have spotted following errorsin your code:
//private boolean player; // as you are not using this variable , so, i have commented it.
private String name;
private double cash;
Scanner scnr=new Scanner(System.in);
public void setName(String name)
{
System.out.println(\"Enter the name of the player\ \");
// name=scnr.next();
this.name=name;
}
public void setCash (int cash)
{
System.out.println(\"Give the amount on the hand\ \");
//cash=scnr.nextDouble();
this.cash=cash;
}
public String getName()
{
return name;
}
public double getCash()
{
return cash;
}
public boolean addCash(double a)
{
double add;
System.out.println(\"Give the amount to add\ \");
//add=scnr.nextInt();
add=a;
if (add>0)
{
cash=cash+add;
return true;
}
else
return false;
}
public boolean subCash(double s)
{
double sub=s;
System.out.println(\"Give the amount to sub\ \");
// sub=scnr.nextInt();
if (sub>0 && sub.
Match the following cell structures in the Amoeba to their definition.pdf
Match the following cell structures in the Amoeba to their definitions of functions. cell
membrane nucleus ribosome molecules cytoplasm pseudo pod contractile vacuole food
vacuole The part of the cell inside the cell membrane (except for the section enclosed by the
nuclear membrane). it contains the organelles A membrane-bound organelle responsible for
storing and digesting food molecules Stores genetic information, synthesizes RNA & DNA,
unique to eukaryotes Defines cell boundary; regulates molecule passage into and out of a cell
Makes proteins An organelle that expects excess water from the cell by contracting Temporary
extensions of the cell that are used for feeding and movement Makes ribosome\'s
Solution
Cell membrane
D. Defines cell boundary, regulates molecular passage into and out of a cell.
Nucleus
C stores genetic information, synthesizes RNA and DNA, unique to eukaryotes.
Ribosomes
E. Makes proteins.
Nucleolus
H. Makes ribosomes.
Cytoplasm
A. The part of the cell inside the cell membrane and contain the organelles.
Psedopod
G. Temporary extensions of the cell that are used for movement and feeding.
Contractile vacuole
F. An organelle that expels excess water from the cell by contracting
Food vacuole
B. A membrane bound organelle responsible for storing and digesting food molecules..
Let D P2(R) P1(R) defined by D(p) = p . Where p is the deriva.pdf
Let D : P2(R) P1(R) defined by D(p) = p\' . Where p\' is the derivative of p. Find the null space
of D. Is this map injective ?
Solution
Any constant scaling of that function will be zero as well.
Since the null space is not just 0, then any two vectors in the null space map to zero, thus it
cannot be one one.
T(1,x,x2) = (0,1,x) The transformation doesn\'t contain the {0} therefore null D 0 therefore the
map is not injective..
Islam and Supply-Side EconomicsSupply-side economics has a long hi.pdf
Islam and Supply-Side Economics
Supply-side economics has a long history, dating back to at least the fourteenth century. The
greatest of medieval historians, Abu Zayd Abd-ar-Rahman Ibn Khaldun (1332–1406), included
in his book, The Muqaddimah (1377), an Islamic view of supply-side economics. He pointed out
that “when tax assessments . . . upon the subjects are low, the latter have the energy and desire to
do things. Cultural enterprises grow and increase . . . (Therefore) the number of individual
imposts (taxes) and assessments mounts.” If taxes are increased in both size and rates, “the result
is that the interests of subjects in cultural enterprises disappears, because when they compare
expenditures and taxes with their income and gain and see little profit they make, they lose all
hope.” Ibn Khaldun concluded that “at the beginning of a dynasty, taxation yields large revenue
from small assessments. At the end of a dynasty, taxation yields small revenue from large
assessments.”
(A) How do this Islamic scholar’s theories apply to the modern world?
Solution
Ans:
In the course of the most recent 50 years there has been reestablished enthusiasm for Islamic
nations in looking at the relationship in the middle of Islam and science in the range of its
history. In the wake of picking up autonomy the majority of the Islamic nations have been
attempting to deal with their religious convictions and the Western ideas of science and training.
The instruction frameworks embraced by the greater part of the Islamic nations have been
founded on supposed common Western training. Subsequently a social dichotomy is seen in their
social orders between a conventional Islamic training from one viewpoint confined to religious
gatherings, and a common Western instruction in standard schools, schools and colleges.
Training is seen as a method for securing logical learning and innovation, so as to advance
monetarily in the cutting edge world. On the other hand, training has unsuccessfully attempted to
mix Islamic thinking with this Western instruction framework.
Islamic Nature view :
The Islamic perspective of nature amid the Golden Age was for humankind \'to study nature with
a specific end goal to find God and to utilize nature for the advantage of humanity\'. Nature
could be utilized to give sustenance to humankind and its abundance was to be similarly
circulated among all people groups. All exercises that made damage humanity and thus
devastated nature were illegal. Devastation of the common equalization was disheartened, for
instance, pointless executing of creatures or evacuation of vegetation may thus prompt starvation
because of absence of nourishment. This perspective was an expansion of the thought that
\"man\" had been set on earth as God\'s illustrative.
Supply-side financial aspects is a macroeconomic hypothesis which contends that monetary
development can be most adequately made by putting resources into capital, and by bringing
down boundaries on the .
Increasingly there is political discussion in carbon dioxide as well.pdf
Increasingly there is political discussion in carbon dioxide as well as CO as a pollutant. Clearly
all hydrocarbons have CO2 as a product. Discuss how coal and methane rate in terms of carbon
dioxide.
Solution
The amount of CO2 produced when a fuel is burned is a function of the carbon content of the
fuel. The heat content, or the amount of energy produced when a fuel is burned, is mainly
determined by the carbon (C) and hydrogen (H) content of the fuel. Heat is produced when C and
H combine with oxygen (O) during combustion. Natural gas is primarily methane ( CH4), which
has a higher energy content relative to other fuels, and thus, it has a relatively lower CO2-to-
energy content. Water and various elements, such as sulfur and non-combustible elements in
some fuels reduce their heating values and increase their CO2-to-heat contents..
In the following diagram, identify the labeled bony landmarks and ope.pdf
In the following diagram, identify the labeled bony landmarks and openings. Identify the bones
by using the colors indicated. In the following diagram, identify the labeled bony landmarks and
openings. Identify the bones by using the colors indicated.
Solution
Answer:
13. Ethmoid bone
14. Foramen rotundum
15. Foramen ovale
16. Foramen spinosum
17. Foramen lacerum
18. Internal acoustic meatus
19. Foramen magnum
20. Lesser wing of sphenoid
21. Greater wing of sphenoid
22. Hypophyseal fossa
23. Temporal bone (petrous portion)
24. Jugular foramen
25. Medial pterygoid plate of sphenoid bone
26. lateral pterygoid plate of sphenoid bone
27. Foramen ovale
28. styloid process
29. Jugular foramen
30. Foramen magnum
31. Temporal bone (zygomatic process)
32. carotid canal
33. Mastoid process
34. Occipital condyle.
In January 2017, Bramble Corp., a newly formed company, issued 10400.pdf
In January 2017, Bramble Corp., a newly formed company, issued 10400 shares of its $8 par
common stock for $13 per share. On July 1, 2017, Bramble Corp. reacquired 1040 shares of its
outstanding stock for $10 per share. The acquisition of these treasury shares
increased total stockholders\' equity.
Solution
If company acquired treasury stock then company\'s total stockholder\'s equity decreased in total.
but does not decrease number of issued shares but decrease no. of outstanding share.
If company acquired treasury shares then (1040*10) = 10400
then total stockholder\'s equity decreased by $10400
so answer is d) decreased total stockholders\' equity..
How do humans detect color Considering your answer to this question.pdf
How do humans detect color? Considering your answer to this question, predict why some
\"colorblind\" individuals are unable to distinguish between certain colors.
Solution
Human eye is impartent and comlicated . human eye is just like camera and having the ability of
self focusing .Light from an external object is refracted as it move through the cornea and move
to the pupil .Light again refracted by the lens which project image on the ratina .In tatina light
is absorbed by cone and rod cells .there are 6-7 million cones in ratina . three different type of
cone is present in ratina sensitive to short medium and long wevelength .cones respond to red
blue and green light .the signals from cones transmited to brain by nerve . the ganglion of brain
cells determine the colour.
Colour blind human are unable to distiguish between certai colour due to insensitivity of cone
cells . When the cone cells are insensitive to long wavelength red colour look darker than they
actually are . the green tend to look similar to red .
when cones are insensitive to medium wavelength and human can not see red and green colour .
when cones are insensitive to shoet wavelength light human can not distinguish blue and green
colour ..
Recommended
Need help finding the error in my code. Wherever theres a player.pdf
Need help finding the error in my code. Wherever there\'s a \"player.\" something netbeans
shows an error saying \"cannot find symbol\".
import java.util.Scanner;
public class DicePlayer {
private boolean player;
private String name;
private double cash;
Scanner scnr=new Scanner(System.in);
public void setName()
{
System.out.println(\"Enter the name of the player\ \");
name=scnr.next();
}
public void setCash ()
{
System.out.println(\"Give the amount on the hand\ \");
cash=scnr.nextDouble();
}
public String getName()
{
return name;
}
public double getCash()
{
return cash;
}
public boolean addCash()
{
double add;
System.out.println(\"Give the amount to add\ \");
add=scnr.nextInt();
if (add>0)
{
cash=cash+add;
return true;
}
else
return false;
}
public boolean subCash()
{
double sub;
System.out.println(\"Give the amount to sub\ \");
sub=scnr.nextInt();
if (sub>0 && sub
Solution
I have spotted following errorsin your code:
//private boolean player; // as you are not using this variable , so, i have commented it.
private String name;
private double cash;
Scanner scnr=new Scanner(System.in);
public void setName(String name)
{
System.out.println(\"Enter the name of the player\ \");
// name=scnr.next();
this.name=name;
}
public void setCash (int cash)
{
System.out.println(\"Give the amount on the hand\ \");
//cash=scnr.nextDouble();
this.cash=cash;
}
public String getName()
{
return name;
}
public double getCash()
{
return cash;
}
public boolean addCash(double a)
{
double add;
System.out.println(\"Give the amount to add\ \");
//add=scnr.nextInt();
add=a;
if (add>0)
{
cash=cash+add;
return true;
}
else
return false;
}
public boolean subCash(double s)
{
double sub=s;
System.out.println(\"Give the amount to sub\ \");
// sub=scnr.nextInt();
if (sub>0 && sub.
Match the following cell structures in the Amoeba to their definition.pdf
Match the following cell structures in the Amoeba to their definitions of functions. cell
membrane nucleus ribosome molecules cytoplasm pseudo pod contractile vacuole food
vacuole The part of the cell inside the cell membrane (except for the section enclosed by the
nuclear membrane). it contains the organelles A membrane-bound organelle responsible for
storing and digesting food molecules Stores genetic information, synthesizes RNA & DNA,
unique to eukaryotes Defines cell boundary; regulates molecule passage into and out of a cell
Makes proteins An organelle that expects excess water from the cell by contracting Temporary
extensions of the cell that are used for feeding and movement Makes ribosome\'s
Solution
Cell membrane
D. Defines cell boundary, regulates molecular passage into and out of a cell.
Nucleus
C stores genetic information, synthesizes RNA and DNA, unique to eukaryotes.
Ribosomes
E. Makes proteins.
Nucleolus
H. Makes ribosomes.
Cytoplasm
A. The part of the cell inside the cell membrane and contain the organelles.
Psedopod
G. Temporary extensions of the cell that are used for movement and feeding.
Contractile vacuole
F. An organelle that expels excess water from the cell by contracting
Food vacuole
B. A membrane bound organelle responsible for storing and digesting food molecules..
Let D P2(R) P1(R) defined by D(p) = p . Where p is the deriva.pdf
Let D : P2(R) P1(R) defined by D(p) = p\' . Where p\' is the derivative of p. Find the null space
of D. Is this map injective ?
Solution
Any constant scaling of that function will be zero as well.
Since the null space is not just 0, then any two vectors in the null space map to zero, thus it
cannot be one one.
T(1,x,x2) = (0,1,x) The transformation doesn\'t contain the {0} therefore null D 0 therefore the
map is not injective..
Islam and Supply-Side EconomicsSupply-side economics has a long hi.pdf
Islam and Supply-Side Economics
Supply-side economics has a long history, dating back to at least the fourteenth century. The
greatest of medieval historians, Abu Zayd Abd-ar-Rahman Ibn Khaldun (1332–1406), included
in his book, The Muqaddimah (1377), an Islamic view of supply-side economics. He pointed out
that “when tax assessments . . . upon the subjects are low, the latter have the energy and desire to
do things. Cultural enterprises grow and increase . . . (Therefore) the number of individual
imposts (taxes) and assessments mounts.” If taxes are increased in both size and rates, “the result
is that the interests of subjects in cultural enterprises disappears, because when they compare
expenditures and taxes with their income and gain and see little profit they make, they lose all
hope.” Ibn Khaldun concluded that “at the beginning of a dynasty, taxation yields large revenue
from small assessments. At the end of a dynasty, taxation yields small revenue from large
assessments.”
(A) How do this Islamic scholar’s theories apply to the modern world?
Solution
Ans:
In the course of the most recent 50 years there has been reestablished enthusiasm for Islamic
nations in looking at the relationship in the middle of Islam and science in the range of its
history. In the wake of picking up autonomy the majority of the Islamic nations have been
attempting to deal with their religious convictions and the Western ideas of science and training.
The instruction frameworks embraced by the greater part of the Islamic nations have been
founded on supposed common Western training. Subsequently a social dichotomy is seen in their
social orders between a conventional Islamic training from one viewpoint confined to religious
gatherings, and a common Western instruction in standard schools, schools and colleges.
Training is seen as a method for securing logical learning and innovation, so as to advance
monetarily in the cutting edge world. On the other hand, training has unsuccessfully attempted to
mix Islamic thinking with this Western instruction framework.
Islamic Nature view :
The Islamic perspective of nature amid the Golden Age was for humankind \'to study nature with
a specific end goal to find God and to utilize nature for the advantage of humanity\'. Nature
could be utilized to give sustenance to humankind and its abundance was to be similarly
circulated among all people groups. All exercises that made damage humanity and thus
devastated nature were illegal. Devastation of the common equalization was disheartened, for
instance, pointless executing of creatures or evacuation of vegetation may thus prompt starvation
because of absence of nourishment. This perspective was an expansion of the thought that
\"man\" had been set on earth as God\'s illustrative.
Supply-side financial aspects is a macroeconomic hypothesis which contends that monetary
development can be most adequately made by putting resources into capital, and by bringing
down boundaries on the .
Increasingly there is political discussion in carbon dioxide as well.pdf
Increasingly there is political discussion in carbon dioxide as well as CO as a pollutant. Clearly
all hydrocarbons have CO2 as a product. Discuss how coal and methane rate in terms of carbon
dioxide.
Solution
The amount of CO2 produced when a fuel is burned is a function of the carbon content of the
fuel. The heat content, or the amount of energy produced when a fuel is burned, is mainly
determined by the carbon (C) and hydrogen (H) content of the fuel. Heat is produced when C and
H combine with oxygen (O) during combustion. Natural gas is primarily methane ( CH4), which
has a higher energy content relative to other fuels, and thus, it has a relatively lower CO2-to-
energy content. Water and various elements, such as sulfur and non-combustible elements in
some fuels reduce their heating values and increase their CO2-to-heat contents..
In the following diagram, identify the labeled bony landmarks and ope.pdf
In the following diagram, identify the labeled bony landmarks and openings. Identify the bones
by using the colors indicated. In the following diagram, identify the labeled bony landmarks and
openings. Identify the bones by using the colors indicated.
Solution
Answer:
13. Ethmoid bone
14. Foramen rotundum
15. Foramen ovale
16. Foramen spinosum
17. Foramen lacerum
18. Internal acoustic meatus
19. Foramen magnum
20. Lesser wing of sphenoid
21. Greater wing of sphenoid
22. Hypophyseal fossa
23. Temporal bone (petrous portion)
24. Jugular foramen
25. Medial pterygoid plate of sphenoid bone
26. lateral pterygoid plate of sphenoid bone
27. Foramen ovale
28. styloid process
29. Jugular foramen
30. Foramen magnum
31. Temporal bone (zygomatic process)
32. carotid canal
33. Mastoid process
34. Occipital condyle.
In January 2017, Bramble Corp., a newly formed company, issued 10400.pdf
In January 2017, Bramble Corp., a newly formed company, issued 10400 shares of its $8 par
common stock for $13 per share. On July 1, 2017, Bramble Corp. reacquired 1040 shares of its
outstanding stock for $10 per share. The acquisition of these treasury shares
increased total stockholders\' equity.
Solution
If company acquired treasury stock then company\'s total stockholder\'s equity decreased in total.
but does not decrease number of issued shares but decrease no. of outstanding share.
If company acquired treasury shares then (1040*10) = 10400
then total stockholder\'s equity decreased by $10400
so answer is d) decreased total stockholders\' equity..
How do humans detect color Considering your answer to this question.pdf
How do humans detect color? Considering your answer to this question, predict why some
\"colorblind\" individuals are unable to distinguish between certain colors.
Solution
Human eye is impartent and comlicated . human eye is just like camera and having the ability of
self focusing .Light from an external object is refracted as it move through the cornea and move
to the pupil .Light again refracted by the lens which project image on the ratina .In tatina light
is absorbed by cone and rod cells .there are 6-7 million cones in ratina . three different type of
cone is present in ratina sensitive to short medium and long wevelength .cones respond to red
blue and green light .the signals from cones transmited to brain by nerve . the ganglion of brain
cells determine the colour.
Colour blind human are unable to distiguish between certai colour due to insensitivity of cone
cells . When the cone cells are insensitive to long wavelength red colour look darker than they
actually are . the green tend to look similar to red .
when cones are insensitive to medium wavelength and human can not see red and green colour .
when cones are insensitive to shoet wavelength light human can not distinguish blue and green
colour ..
Identify the unique characteristics of auditing professionSoluti.pdf
Identify the unique characteristics of auditing profession
Solution
ANSWER:
Auditing refers to evaluating the effectiveness of a company\'s internal controls. An audit is an
assessment of an individual, process, system, firm, organization, institution, company, project, or
product. Audits are carried out to check and verify the reliability of any given information and
give an evaluation of the internal control of the system.
Unique Characteristics of auditing profession:
--Pursue goals: A unique auditing profession is a important because it facilitates to pursue for the
attainment of several corporate purposes. It helps to prevent and identify irregular transaction,
measure the performance of the corporate, maintain adequate business records and to enhance
the productivity.
--Fraud Prevention: Auditing serves vital role for companies in the prevention of fraud.
Recurring analysis of the operations and maintaining rigorous systems in the company can
prevent and detect various forms of accounting irregularities and other fraud activities. Audit
professionals helps in the design and modification of the control systems the purpose of which
includes, among other things, prevention of fraud.
-- Cost of Capital: Unique audit systems profession reduces the several forms of risk in an
enterprise, including its information risk (the risk of material misstatement in financial
reporting), the risk of suboptimal management due to insufficient information on its operations
and also the risk of fraud and misappropriation of assets.
--Prevents debilitating misstatements: A unique auditing system helps in preventing debilitating
misstatements in a company’s records and reports
--A thirst for knowledge: Auditors needs to strive to cultivate a deep knowledge of the company
consisting of its culture, key players and competitive environment. It is main factor that is
guaranteed to set audit apart from other auditing and risk compliance professionals
--Innovation: Every company has its own inner workings and to be a unique auditing manager or
compliance officer needs creativity. Combine innovation with current company\'s processes to
provide impressive results.
--Communication/People skills: The ability to read people and adapt for any given situation is a
key driver in those who progress up the internal or external auditing career ladder effectively..
Hemophilia is a recessive trait. The dominant trait is normal blood d.pdf
Hemophilia is a recessive trait. The dominant trait is normal blood dotting A gene that can cause
hemophilia is located on the X chromosome. If a homozygous normal female marries a normal
male, they children might have which of the following phenotypes: Select one: a. normal
females, hemophiliac females, and hemophiliac males. b. normal females, hemophiliac females,
normal males, and hemophiliac males. c. normal females and hemophiliac males d. normal
females and normal mates. e. normal females, normal males or hemophiliac males.
Solution
In X - linked recessive inheritance males are more prone to disease because they carry the
disease trait. If the affected offspring’s mother has brother or father containing the same trait
then the mother pass the trait to her offspring. The affected males produce unaffected daughters
who can produce 50% affected sons. Hemophilia is the example of X - linked recessive trait.
When a homozygous normal female marries to a normal male the offspring produced are normal
females and normal males. Option d is correct..
Explain the purpose of the Medium Access Control (MAC) timing paramet.pdf
Explain the purpose of the Medium Access Control (MAC) timing parameters Short InterFrame-
Space (SIFS), Point (coordination function) Interframe Space (PIFS), and Distributed
(coordination function) Interframe Space (DIFS). Explain why they should be carefully chosen.
Why has a station at least to wait one DIFS prior to transmission?
Solution
Answer
The purpose of the given MAC timing parameters are as below:
SIFS : Short Interframe Space, is the amount of time in microseconds needed by a wireless
interface to process a received frame and to respond with a response frame. It is given by the
difference in time of the first symbol of the response frame in the air and the last symbol of the
received frame in the air. A SIFS time comprises of the delay in receiver RF, PLCP delay and the
MAC processing delay, which depends on the physical layer used.
Point (co-ordination function) Interframe Space: it co-ordinates the communication within a
network.It is the time or duration for which PCF waits to grasp a channel.
Distributed (co-ordination function) Interface Space: it controls the access to the physical
medium. If DFC protocol finds that the medium is continuously idle for DIFS duration, it is then
permitted to transmit a frame. If during the DIFS interval the channel is found busy then that
channel is discarded and another channel is looked for.
A station has to wait for atleast one DIFS prior to transmission because generally it waits for
PIFS duration which is of shorter duration than DIFS and if PIFS is not available it moves to
DIFS duration which gets lapsed if a channel is not found. Therefore, atleast one DIFS duration
wait is required to know if a channel is found for the transmission or not..
find the payment necessary to amortize 8 loan of $1500 for 19 compo.pdf
find the payment necessary to amortize 8% loan of $1500 for 19 compound quarterly payments.
the payment size is????
Solution
payment size=P[r(1+r)n]/[(1+r)n-1]
r =interest/4 =0.08/4 =0.02
P=1500
n= 19
payment size=1500*[0.02(1+0.02)19]/[(1+0.02)19-1]
payment size=1500*[0.02(1.02)19]/[(1.02)19-1]
payment size=95.67$.
explain why HCO3- levels can be calculated from pH and pCO2 levels.pdf
explain why HCO3- levels can be calculated from pH and pCO2 levels
Solution
pH is defined as the negative log of the Hydrogen ion concentration: -log[H+].
(also, pH=pK+log [HCO3]/ 0.03 x pCO2). The pH is the product of two components,
respiratory and metabolic, thus allowing for the effect of the pCO2, ie, any change in the pH
unexplained by the pCO2 resulting ina metabolic abnormality.
CO2 and water combine to form carbonic acid or H2CO3, present with concentrations of
bicarbonate (HCO3-)and hydrogen ions (H+) in equilibrium amounts. A change in the
concentration of the reactants on either side of the equation affects the subsequent direction of
the reaction. Eg., a rise in CO2 will also raise carbonic acid formation (H2CO3) which leads to
raised levels of both HCO3- and H+ (\\pH)..
Describe the arrangement of neurons in the primary motor cortexS.pdf
Describe the arrangement of neurons in the primary motor cortex
Solution
The primary motor cortex or M1 is found to be located in the dorsal portion of the frontal lobe in
the brain.
This is the region which is involved in coding force and direction of movement and M1 works
along with posterior parietal cortex, premotor cortex, the supplementary motor area etc to
execute its actions.
In M1 region we can find Betz cells (large neurons) along with other cortical neurons, these will
send long axons till the end of the spinal cord, so that they can synapse onto the interneuron
circuitry of the spinal cord. They also send neurons on the alpha motor neurons located in the
spinal cord to have connection with the muscles.
Using Golgi method, the morphology and the spatial arrangement of neurons in the primary
motor cortex has been studies, which revealed the presence of great variety of pyramidal and
non-pyramidal cells in M1 region and main difference between these cells is due to their
difference in shape, size and also with respect to dimensions and distribution of dendritic trees.
It has been reported that columnar aggregation formed were observed in sub-layers III b and c,
formed by the somata and dendritic trees of pyramidal and non-pyramidal cells, these are 100-
300 micron wide and are found to be separated by cell-sparse spaces of 50-100 micron width.
In these aggregations, we can find several bundles formed by apical dendrites of pyramidal cells.
The columnar width was not surpassed by most non-pyramidal cells of dendrites.
In layers III and V, the dendrites and somata of pyramidal cells were found to be showing a
preferential orientation in the same direction and they will run parallel to the main axis of the
gyrus.
But in layers II, IV, and V, what aggregations we found in layer III were not found but in layer
V, around the giant Betz cells, there was a loose assemblage of neurons of all sizes group were
found to be located.
The radii of myelinated fibers entering and leaving the white matter were found to be forming
radial appearance in Layer VI.
The vertical, columnar organization and the asymmetry of somata and dendritic trees were found
to be more pronounced when it comes to the boundary of the central sulcus and boundary of
precentral gyrus..
Cell Image Cell type eukaryotic cell t prokaryotic cell Solution.pdf
Cell Image Cell type eukaryotic cell t prokaryotic cell
Solution
1st image: Prokaryotic cell. No clear nuclear membrane
2nd image: Prokaryotic cell.No clear nuclear membrane
3rd image: Prokaryotic cell.- Cellwall, nucleoid, ribosomes
4th image:Eukaryotic cell.- Clear nucleus, Clear nuclear membrane, etc.,.
An inbred line of Drosophila will drink sugar water to which small am.pdf
An inbred line of Drosophila will drink sugar water to which small amounts of a bitter
substance, quinine, has been added. The variance in quinine concentration tolerated is 200. They
are crossed with a different inbred line whose variance in quinine concentration tolerated is 110.
Their F_1S have a variance of 110, and their F_2S have a variance of 210. What is the
heritability of this trait?
Solution
Generation
Variance
P1
200
P2
110
F1
110
F2
210
VE = {VF1 + (VP1+ VP2)/2}/2 = {110 + (110 + 200)/2}/2 = 132.5
VP = 210
Vg = VP – VE = 210 – 132.5 = 77.5
Heritiablity H2 = Vg /VP = 77.5 / 210 = 0.369
Generation
Variance
P1
200
P2
110
F1
110
F2
210.
ACC312 Federal TaxationTax avoidanceTax evasion questions1. The.pdf
ACC312 Federal Taxation
Tax avoidance/Tax evasion questions
1. The entity variable: Which entity undertakes the transaction?
2. The time period variable: During which tax year or years does the transaction occur?
3. The jurisdiction variable: In which tax jurisdiction does the transaction occur?
4. The character variable: What is the tax character of the income from the transaction?
Solution
Tax evasion is the illegal means of reducing taxes.
tax planning has four variables.
1. entity
2. Time period
3. Jurisdiction
4. Character
so, the above four questions are based on the tax planning variables..
a total of 100 students are taking a history exam. each student is r.pdf
a total of 100 students are taking a history exam. each student is required to write an essay on
one of six possible topics. What is the fewest possible number of students who could have
chosen the topic selected by most students?
Solution
This is possible event
17,17,17,17,16,16
Fewest number is 17 whichi is most number of syudent.
A case study of a young man with a viral infection In the late winte.pdf
A case study of a young man with a viral infection In the late winter of 2009 Jeff, a 19 year old
male, living in the dorms at college came down suddenly with a virus which kept him out of
classes for 3 days. Jeff\'s day started out as a regular day and he went to his classes as he
normally does. As the day went on Jeff began to tired and worn out but he figured it was just due
to a lack of sleep and feel stress. That night he laid down for bed and recognized he was running
a slight fever so he thought he would just sleep it off and feel better in the morning. The next
morning when he awoke he had a high fever, chills, body aches and nausea. Jeff only left his bed
that day to go to the bathroom a couple times fever, or to get a glass of water. As day went on his
symptoms only got worse, by that night his fever chills, and aches were also accompanied by
diarrhea. The next day Jeff then began experiencing it vomiting on top of his current symptoms
and was unable to drink water or eat any food without 2 days making his stomach feel worse. By
that night he was beginning to feel much better, and within 2 days he had almost fully recovered.
What was Jeff suffering from? How do we know this wasn\'t the flu? How should his illness
have been treated? What were his risk factors for becoming infected? How many people are
infected each year in the US with this virus? How can you prevent infection with this virus?
What is the mode of transmission and reservoir for this virus?
Solution
ANSWER:
1) jeff was suffering from Gastroenteritis...
2)We know that was not flu because the symptoms of flu was highfever,bodyaches, chills and
sweat, persistent cough,headache,nasalcongestion,sorethoratand weakness.diarrhea not occur in
flu....
3)Drinking enough fluids, and learning what to eat will keep you comfortable. have to manage
diarrhea,control nausea,and vomiting and get plenty of rest will help to treat disease....
4)RISK FACTORS: Gastroenteritis is caused by the people with weak immune system ,
ingestion of viruses, certain bacteria, or parasites. Food that has spoiled may also cause illness.
Young children may develop signs and symptoms of gastroenteritis as a reaction to a new food.
HIGH RISK FACTORS INCLUDE:
5)It is estimated that three to five billion cases of gastroenteritis resulting in 1.4 million deaths
occur globally each year.IN U.S 10,00O PEOPLE ARE INFECTED......
6)Prevention:Wash your hands after using the toilet and before handling food. Don’t prepare
food for other people until your symptoms improve. Avoid close contact with others during your
illness. After your symptoms stop, try to wait at least 48 hours before returning to work.
You can also help prevent bacterial gastroenteritis infections by avoiding unpasteurized milk,
raw meat, or raw shellfish. Use separate cutting boards and utensils for raw and cooked meats
when preparing meals. Wash salads and vegetables thoroughly. Make sure to store food at either
very hot or very cold temperatures i.
A child drops a ball from a bridge. The ball strikes the water under.pdf
A child drops a ball from a bridge. The ball strikes the water under the bridge 2.0 seconds later.
What is the velocity of the ball when it strikes the water?
Solution
V=U+AT=0+32*2=64 FT/SEC...OR IN MKS UNITS....
V=0+9.8*2=19.6 M/SEC
SEE BELOW FOR EXPLANATION
A boy throws a rock straight up into the air. It reaches the highest point of its flight after 2.5
seconds. How fast was the rock giong when it left the boys hand?
1 solutions
Answer 17643 by venugopalramana(1171) About Me on 2006-03-21 11:25:11 (Show Source):
THE FORMULA TO BE USED IS
V=U+AT...WHERE
V=FINAL VELOCITY....FT/SEC.
U=INITIAL VELOCITY....FT/SEC.
A = ACCELERATION ..HERE IT IS DUE TO GRAVITY WHICH IS ACTING AGAINST
THE MOTION ..ITS VALUE IS -32 FT/SEC.SEC.
T=TIME OF TRAVEL...SEC
WE HAVE U=?
V=0....AS IT REACHED THE HIGHEST POINT AND WILL STOP AND FALL BACK
FROM THERE.
T=2.5 SEC.
0=U-32*2.5
U=32*2.5=80 FT/ SEC.
IF YOU ARE IN MKS UNITS THEN A=-9.8 M/SEC.SEC
U=9.8*2.5=24.5 M/SEC.
2. A resistant inbred cultivar and a susceptible inbred cultivar are.pdf
2. A resistant inbred cultivar and a susceptible inbred cultivar are crossed to generate an F1. You
observe that the F1 has a level of resistance that is intermediate between the parents. Circle the
genetic mechanism below that would NOT explain this observation.
A. The resistance is controlled quantitatively.
B. The resistance is controlled by a single gene with incomplete dominance alleles.
C. The resistance is controlled two dominant genes with epistasis.
D. The resistance is controlled by two genes that are acting additively with no epistasis.
Solution
The correct answer is: C.The resistance is controlled two dominant genes with epistasis.
Reason: In case of dominanat epistatis, one dominant gene completely masks the effect of other
dominant gene when present together.In this case, we get an intermediate phenotype.So, this
cannot be controlled by two dominant genes with epistatis..
Write the program in MIPS that declares an array of positive integer.pdf
Write the program in MIPS that declares an array of positive integers. The size of the array is not
fixed. The final element of the array should have the value of 0xF, which is not used in
calculations, and should be used to calculate the size of the array. The program can prompt the
user for an integer input. Compare the input with the array. Display the index of the input in the
array if found. If the number does not match any element in the array, insert the number in the
array in sorted order. The program is terminated when input a negative integer. Print the new
array with appropriate message on the screen. For example assume an array as follows:
(array: .word 4, 5, 23, 5, 8, 3, 15, 67, 8, 9, 0xF)
Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 23, 67
Enter a number to search: 20
Number not found. Added to array.
Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 20, 23, 67
Enter a number to search: 5
Number at index 2
Solution
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a.
Why does a diploid mother cell that undergoes meiosis produce four h.pdf
Why does a diploid mother cell that undergoes meiosis produce four haploid cells? Explain what
happens during meiosis (i.e. what events take place during meiosis) that helps achieve this goal
(four haploid cells).
Solution
To maintain the stability in chromosome number, diploid mother cell that undergoes meiosis
produces four haploid cells
Meiosis includes two phases, which are Meiosis I and Meiosis II. (The meiosis classified as
divisons for our ...)
Each phase includes, Prophase, Metaphase, Anaphase and Telophase.
Meiosis I - The major event is Chromosomal segregation. As the presence of chromosomal
segregation, in this phase the chromosome number reduced to half of the original number.
Prophase, Metaphase, Anaphase and Telophases of Meiosis I are ended with I.
Prophase I : includes the following sub stages.
Leptotene - thin threads : Boutique stage
Zygotene - mating threads : bivalent or tetrad chromosomes.
Pachytene - thick threads : chiasmata can observe
Diplotene - two threads : homologous chromosomes separate from one another a little.
Diakinesis - moving threads : chiasmata clearly visible
Metaphase I : Homologous pairs move together along the metaphase plate
Anaphase I : homologous chromosomes moves to opposite poles.
Telophase I : chromosomes arrive at the poles.
Meiosis II - The major event is Chromatid segregation. As the presence of chromatid
segregation, in this phase the chromosome number maintained to half of the original number.
Prophase, Metaphase, Anaphase and Telophases of Meiosis II are ended with II.
Prophase II : shortening and thickening of the chromatids
Metaphase II : Chromatids move together along the metaphase plate
Anaphase II : Chromatid moves to opposite poles.
Telophases II : Chromatid arrive at the poles..
What is an intumescent material Where is it used SolutionAn .pdf
What is an intumescent material? Where is it used?
Solution
An intumescent material is one that undergoes a chemical change when exposed to heat or
flames, becoming viscous then forming expanding bubbles that harden into a dense, heat
insulating multi-cellular char.
The objectives of intumescent technology are the containment of fire and toxic gases by
inhibiting flame penetration, heat transfer and transport of toxic gases from the site of a fire to
other parts of a structure.
A typical, practical application of intumescence is in fire seal technology, where stips of
intumescent material in a carrier are fitted around the perimeter of a fire door. During a fire the
fire seals intumescence (expand and char) to resist fire penetration and prevent the spread of
fumes.
Intumescent technologies are widely used in passive fire protection systems, where potential
pathways for the spread of flames and fumes, such as conduits, wall openings and ventilation
grilles are fitted with fire retardant products. Passive fire protection materials are usually
combined with \"active\" fire supression technologies such as sprinklers, foam generation and
inert gas systems.
fireproofing items such as - fire seals, smoke seals, letter box systems, pipe collars, pipe sleeves,
pipe wraps, duct wrap, fire grilles, cladding seals, fire rated foams, downlighter covers, lighting
canopies, luminaire covers.
Intumescents are used to achieve passive fire protection for such applications as firestopping,
fireproofing, gasketing and window casings. Such applications are relevant for buildings,
offshore constructions, ships and aircraft..
1. How can a computer with only 2G of physical memory run two progra.pdf
1. How can a computer with only 2G of physical memory run two programs that both use 1.5G
each?
2. How is virtual memory related to physical memory?
3. What is the role of the CMOS in the boot process?
4. What happens immediately after the computer is powered up?
5. What steps occur in the POST?
6. What is stored in the boot sector of a fixed disk?
7. A typical Windows machine has two boot sectors- what are they called?
8. What is protected mode? What features become available?
9. What difference is there between kernel mode and user mode?
10. How can the attacker exploit the Windows boot process?
Solution
1) using virtual memory and Demand-paging concept
2) Virtual memory mapps real physical address to the virtual memory address to transfer the data
between RAM and hard drive
3)CMOS is RAM and it stores the parameters of the devices which are in BIOS.and also it runs
our system clock.
4)When power is on two things done in two steps
>POST (power-on Self Test)
>Operating system loading
these two are done in sequence and it first is fails then second will not be happen.
POST : It check whether all the necessary things are present and they are working well
Operation System Loading : After successfull of POST, CPU searches for storage device to load
the special files which indicates the starting of the operating system.
5)
> First CPU is reset
> CPU check itself and POST is loaded into BIOS
> CPU runs BIOS to check componenents connected to PC
>DRAM is checke with sample reading and writing of every byte.
> keyboard is checked for any key is pressed.
> if any key is pressed it goes to BIOS settings to change them.
> Hard drives are checked whether they are present or not.
> Presence of mouse is also checked.
> lastly test results are checked with the data in BIOS
> IF any mis matches found then POST will results in failure.
6) Some configuaration files and operating system
8)protected mode is first added in x86 machine and it is also called as protected virtual address
mode.
It provides access to Virtual address, Paging and multitasking for system software to have
control over application software.
9)Kernel Mode is to have communication with hardware and it happens under OS.
>Kernel mode programs are most supervised.
>these may terminate the process
> any clashes comes system may crashes
--->User mode is just excuting porgrams and he has no permission to have connection with
hardware.
>less priority
>any clashes comes nothing is going to happen.
this is VerilogHDL classAre these legal identifiersa. system1.pdf
this is VerilogHDL class
Are these legal identifiers?
a. system1
b. 1reg
c. $latch
d. exec$
Solution
the legal identifiers means it is having an unique name to use or identify the object.the identifiers
can contains \"text\" or \"_\" or \"$\" or numbers.
so only system1 is legal identifier remaining all are not a legal identifiers..
Transactions made by Ivanhoe Company for the month of March are shown.pdf
Transactions made by Ivanhoe Company for the month of March are shown below. 1. The
company performed $19,650 of services for customers on account. 2. The company received
$19,650 in cash from customers who had been billed for services [in transaction (1) 3. The
company received a bill for $3,450 of advertising but will not pay it until a later date 4. Ivanhoe
Company paid a cash dividend of $4,000 Prepare a tabular analysis that shows the effects of
these transactions on the expanded accounting equation. (If a transaction causes a decrease in
Assets, Liabilities or Stockholders Equity, place a negative sign (or parentheses) in front of the
amount entered for the particular Asset, Liability or Equity item that was reduced. See Ilustration
3-3 for example.) Liabilities+ Stockholders\' Equity Cash + Accounts Receivable = Accounts
Payable + Common Stock + Retained Earnings RevenuesExpensesDividends
Solution
solution :-CashAccounts ReceivableAccounts PayableCommon StockRetained
EarningRevenuesExpensesDividends1)+$19650+$196502)+$19650-$196503)+$3450-$34504)-
$4000-$4000.
The plastic behavior of materials is explained by dislocation theory..pdf
The plastic behavior of materials is explained by dislocation theory. Substitution AL atoms tend
to be larger than interstitial ones. Electronegativity is a measure of how much one atom will
repel another atom, n metallic bonding, the valence electrons are able to move freely throughout
the crystal.
Solution
1.True
2.True
3.False
4.True.
A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance
Thesis Statement for students diagnonsed withADHD.ppt
Presentation required for the master in Education.
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Identify the unique characteristics of auditing professionSoluti.pdf
Identify the unique characteristics of auditing profession
Solution
ANSWER:
Auditing refers to evaluating the effectiveness of a company\'s internal controls. An audit is an
assessment of an individual, process, system, firm, organization, institution, company, project, or
product. Audits are carried out to check and verify the reliability of any given information and
give an evaluation of the internal control of the system.
Unique Characteristics of auditing profession:
--Pursue goals: A unique auditing profession is a important because it facilitates to pursue for the
attainment of several corporate purposes. It helps to prevent and identify irregular transaction,
measure the performance of the corporate, maintain adequate business records and to enhance
the productivity.
--Fraud Prevention: Auditing serves vital role for companies in the prevention of fraud.
Recurring analysis of the operations and maintaining rigorous systems in the company can
prevent and detect various forms of accounting irregularities and other fraud activities. Audit
professionals helps in the design and modification of the control systems the purpose of which
includes, among other things, prevention of fraud.
-- Cost of Capital: Unique audit systems profession reduces the several forms of risk in an
enterprise, including its information risk (the risk of material misstatement in financial
reporting), the risk of suboptimal management due to insufficient information on its operations
and also the risk of fraud and misappropriation of assets.
--Prevents debilitating misstatements: A unique auditing system helps in preventing debilitating
misstatements in a company’s records and reports
--A thirst for knowledge: Auditors needs to strive to cultivate a deep knowledge of the company
consisting of its culture, key players and competitive environment. It is main factor that is
guaranteed to set audit apart from other auditing and risk compliance professionals
--Innovation: Every company has its own inner workings and to be a unique auditing manager or
compliance officer needs creativity. Combine innovation with current company\'s processes to
provide impressive results.
--Communication/People skills: The ability to read people and adapt for any given situation is a
key driver in those who progress up the internal or external auditing career ladder effectively..
Hemophilia is a recessive trait. The dominant trait is normal blood d.pdf
Hemophilia is a recessive trait. The dominant trait is normal blood dotting A gene that can cause
hemophilia is located on the X chromosome. If a homozygous normal female marries a normal
male, they children might have which of the following phenotypes: Select one: a. normal
females, hemophiliac females, and hemophiliac males. b. normal females, hemophiliac females,
normal males, and hemophiliac males. c. normal females and hemophiliac males d. normal
females and normal mates. e. normal females, normal males or hemophiliac males.
Solution
In X - linked recessive inheritance males are more prone to disease because they carry the
disease trait. If the affected offspring’s mother has brother or father containing the same trait
then the mother pass the trait to her offspring. The affected males produce unaffected daughters
who can produce 50% affected sons. Hemophilia is the example of X - linked recessive trait.
When a homozygous normal female marries to a normal male the offspring produced are normal
females and normal males. Option d is correct..
Explain the purpose of the Medium Access Control (MAC) timing paramet.pdf
Explain the purpose of the Medium Access Control (MAC) timing parameters Short InterFrame-
Space (SIFS), Point (coordination function) Interframe Space (PIFS), and Distributed
(coordination function) Interframe Space (DIFS). Explain why they should be carefully chosen.
Why has a station at least to wait one DIFS prior to transmission?
Solution
Answer
The purpose of the given MAC timing parameters are as below:
SIFS : Short Interframe Space, is the amount of time in microseconds needed by a wireless
interface to process a received frame and to respond with a response frame. It is given by the
difference in time of the first symbol of the response frame in the air and the last symbol of the
received frame in the air. A SIFS time comprises of the delay in receiver RF, PLCP delay and the
MAC processing delay, which depends on the physical layer used.
Point (co-ordination function) Interframe Space: it co-ordinates the communication within a
network.It is the time or duration for which PCF waits to grasp a channel.
Distributed (co-ordination function) Interface Space: it controls the access to the physical
medium. If DFC protocol finds that the medium is continuously idle for DIFS duration, it is then
permitted to transmit a frame. If during the DIFS interval the channel is found busy then that
channel is discarded and another channel is looked for.
A station has to wait for atleast one DIFS prior to transmission because generally it waits for
PIFS duration which is of shorter duration than DIFS and if PIFS is not available it moves to
DIFS duration which gets lapsed if a channel is not found. Therefore, atleast one DIFS duration
wait is required to know if a channel is found for the transmission or not..
find the payment necessary to amortize 8 loan of $1500 for 19 compo.pdf
find the payment necessary to amortize 8% loan of $1500 for 19 compound quarterly payments.
the payment size is????
Solution
payment size=P[r(1+r)n]/[(1+r)n-1]
r =interest/4 =0.08/4 =0.02
P=1500
n= 19
payment size=1500*[0.02(1+0.02)19]/[(1+0.02)19-1]
payment size=1500*[0.02(1.02)19]/[(1.02)19-1]
payment size=95.67$.
explain why HCO3- levels can be calculated from pH and pCO2 levels.pdf
explain why HCO3- levels can be calculated from pH and pCO2 levels
Solution
pH is defined as the negative log of the Hydrogen ion concentration: -log[H+].
(also, pH=pK+log [HCO3]/ 0.03 x pCO2). The pH is the product of two components,
respiratory and metabolic, thus allowing for the effect of the pCO2, ie, any change in the pH
unexplained by the pCO2 resulting ina metabolic abnormality.
CO2 and water combine to form carbonic acid or H2CO3, present with concentrations of
bicarbonate (HCO3-)and hydrogen ions (H+) in equilibrium amounts. A change in the
concentration of the reactants on either side of the equation affects the subsequent direction of
the reaction. Eg., a rise in CO2 will also raise carbonic acid formation (H2CO3) which leads to
raised levels of both HCO3- and H+ (\\pH)..
Describe the arrangement of neurons in the primary motor cortexS.pdf
Describe the arrangement of neurons in the primary motor cortex
Solution
The primary motor cortex or M1 is found to be located in the dorsal portion of the frontal lobe in
the brain.
This is the region which is involved in coding force and direction of movement and M1 works
along with posterior parietal cortex, premotor cortex, the supplementary motor area etc to
execute its actions.
In M1 region we can find Betz cells (large neurons) along with other cortical neurons, these will
send long axons till the end of the spinal cord, so that they can synapse onto the interneuron
circuitry of the spinal cord. They also send neurons on the alpha motor neurons located in the
spinal cord to have connection with the muscles.
Using Golgi method, the morphology and the spatial arrangement of neurons in the primary
motor cortex has been studies, which revealed the presence of great variety of pyramidal and
non-pyramidal cells in M1 region and main difference between these cells is due to their
difference in shape, size and also with respect to dimensions and distribution of dendritic trees.
It has been reported that columnar aggregation formed were observed in sub-layers III b and c,
formed by the somata and dendritic trees of pyramidal and non-pyramidal cells, these are 100-
300 micron wide and are found to be separated by cell-sparse spaces of 50-100 micron width.
In these aggregations, we can find several bundles formed by apical dendrites of pyramidal cells.
The columnar width was not surpassed by most non-pyramidal cells of dendrites.
In layers III and V, the dendrites and somata of pyramidal cells were found to be showing a
preferential orientation in the same direction and they will run parallel to the main axis of the
gyrus.
But in layers II, IV, and V, what aggregations we found in layer III were not found but in layer
V, around the giant Betz cells, there was a loose assemblage of neurons of all sizes group were
found to be located.
The radii of myelinated fibers entering and leaving the white matter were found to be forming
radial appearance in Layer VI.
The vertical, columnar organization and the asymmetry of somata and dendritic trees were found
to be more pronounced when it comes to the boundary of the central sulcus and boundary of
precentral gyrus..
Cell Image Cell type eukaryotic cell t prokaryotic cell Solution.pdf
Cell Image Cell type eukaryotic cell t prokaryotic cell
Solution
1st image: Prokaryotic cell. No clear nuclear membrane
2nd image: Prokaryotic cell.No clear nuclear membrane
3rd image: Prokaryotic cell.- Cellwall, nucleoid, ribosomes
4th image:Eukaryotic cell.- Clear nucleus, Clear nuclear membrane, etc.,.
An inbred line of Drosophila will drink sugar water to which small am.pdf
An inbred line of Drosophila will drink sugar water to which small amounts of a bitter
substance, quinine, has been added. The variance in quinine concentration tolerated is 200. They
are crossed with a different inbred line whose variance in quinine concentration tolerated is 110.
Their F_1S have a variance of 110, and their F_2S have a variance of 210. What is the
heritability of this trait?
Solution
Generation
Variance
P1
200
P2
110
F1
110
F2
210
VE = {VF1 + (VP1+ VP2)/2}/2 = {110 + (110 + 200)/2}/2 = 132.5
VP = 210
Vg = VP – VE = 210 – 132.5 = 77.5
Heritiablity H2 = Vg /VP = 77.5 / 210 = 0.369
Generation
Variance
P1
200
P2
110
F1
110
F2
210.
ACC312 Federal TaxationTax avoidanceTax evasion questions1. The.pdf
ACC312 Federal Taxation
Tax avoidance/Tax evasion questions
1. The entity variable: Which entity undertakes the transaction?
2. The time period variable: During which tax year or years does the transaction occur?
3. The jurisdiction variable: In which tax jurisdiction does the transaction occur?
4. The character variable: What is the tax character of the income from the transaction?
Solution
Tax evasion is the illegal means of reducing taxes.
tax planning has four variables.
1. entity
2. Time period
3. Jurisdiction
4. Character
so, the above four questions are based on the tax planning variables..
a total of 100 students are taking a history exam. each student is r.pdf
a total of 100 students are taking a history exam. each student is required to write an essay on
one of six possible topics. What is the fewest possible number of students who could have
chosen the topic selected by most students?
Solution
This is possible event
17,17,17,17,16,16
Fewest number is 17 whichi is most number of syudent.
A case study of a young man with a viral infection In the late winte.pdf
A case study of a young man with a viral infection In the late winter of 2009 Jeff, a 19 year old
male, living in the dorms at college came down suddenly with a virus which kept him out of
classes for 3 days. Jeff\'s day started out as a regular day and he went to his classes as he
normally does. As the day went on Jeff began to tired and worn out but he figured it was just due
to a lack of sleep and feel stress. That night he laid down for bed and recognized he was running
a slight fever so he thought he would just sleep it off and feel better in the morning. The next
morning when he awoke he had a high fever, chills, body aches and nausea. Jeff only left his bed
that day to go to the bathroom a couple times fever, or to get a glass of water. As day went on his
symptoms only got worse, by that night his fever chills, and aches were also accompanied by
diarrhea. The next day Jeff then began experiencing it vomiting on top of his current symptoms
and was unable to drink water or eat any food without 2 days making his stomach feel worse. By
that night he was beginning to feel much better, and within 2 days he had almost fully recovered.
What was Jeff suffering from? How do we know this wasn\'t the flu? How should his illness
have been treated? What were his risk factors for becoming infected? How many people are
infected each year in the US with this virus? How can you prevent infection with this virus?
What is the mode of transmission and reservoir for this virus?
Solution
ANSWER:
1) jeff was suffering from Gastroenteritis...
2)We know that was not flu because the symptoms of flu was highfever,bodyaches, chills and
sweat, persistent cough,headache,nasalcongestion,sorethoratand weakness.diarrhea not occur in
flu....
3)Drinking enough fluids, and learning what to eat will keep you comfortable. have to manage
diarrhea,control nausea,and vomiting and get plenty of rest will help to treat disease....
4)RISK FACTORS: Gastroenteritis is caused by the people with weak immune system ,
ingestion of viruses, certain bacteria, or parasites. Food that has spoiled may also cause illness.
Young children may develop signs and symptoms of gastroenteritis as a reaction to a new food.
HIGH RISK FACTORS INCLUDE:
5)It is estimated that three to five billion cases of gastroenteritis resulting in 1.4 million deaths
occur globally each year.IN U.S 10,00O PEOPLE ARE INFECTED......
6)Prevention:Wash your hands after using the toilet and before handling food. Don’t prepare
food for other people until your symptoms improve. Avoid close contact with others during your
illness. After your symptoms stop, try to wait at least 48 hours before returning to work.
You can also help prevent bacterial gastroenteritis infections by avoiding unpasteurized milk,
raw meat, or raw shellfish. Use separate cutting boards and utensils for raw and cooked meats
when preparing meals. Wash salads and vegetables thoroughly. Make sure to store food at either
very hot or very cold temperatures i.
A child drops a ball from a bridge. The ball strikes the water under.pdf
A child drops a ball from a bridge. The ball strikes the water under the bridge 2.0 seconds later.
What is the velocity of the ball when it strikes the water?
Solution
V=U+AT=0+32*2=64 FT/SEC...OR IN MKS UNITS....
V=0+9.8*2=19.6 M/SEC
SEE BELOW FOR EXPLANATION
A boy throws a rock straight up into the air. It reaches the highest point of its flight after 2.5
seconds. How fast was the rock giong when it left the boys hand?
1 solutions
Answer 17643 by venugopalramana(1171) About Me on 2006-03-21 11:25:11 (Show Source):
THE FORMULA TO BE USED IS
V=U+AT...WHERE
V=FINAL VELOCITY....FT/SEC.
U=INITIAL VELOCITY....FT/SEC.
A = ACCELERATION ..HERE IT IS DUE TO GRAVITY WHICH IS ACTING AGAINST
THE MOTION ..ITS VALUE IS -32 FT/SEC.SEC.
T=TIME OF TRAVEL...SEC
WE HAVE U=?
V=0....AS IT REACHED THE HIGHEST POINT AND WILL STOP AND FALL BACK
FROM THERE.
T=2.5 SEC.
0=U-32*2.5
U=32*2.5=80 FT/ SEC.
IF YOU ARE IN MKS UNITS THEN A=-9.8 M/SEC.SEC
U=9.8*2.5=24.5 M/SEC.
2. A resistant inbred cultivar and a susceptible inbred cultivar are.pdf
2. A resistant inbred cultivar and a susceptible inbred cultivar are crossed to generate an F1. You
observe that the F1 has a level of resistance that is intermediate between the parents. Circle the
genetic mechanism below that would NOT explain this observation.
A. The resistance is controlled quantitatively.
B. The resistance is controlled by a single gene with incomplete dominance alleles.
C. The resistance is controlled two dominant genes with epistasis.
D. The resistance is controlled by two genes that are acting additively with no epistasis.
Solution
The correct answer is: C.The resistance is controlled two dominant genes with epistasis.
Reason: In case of dominanat epistatis, one dominant gene completely masks the effect of other
dominant gene when present together.In this case, we get an intermediate phenotype.So, this
cannot be controlled by two dominant genes with epistatis..
Write the program in MIPS that declares an array of positive integer.pdf
Write the program in MIPS that declares an array of positive integers. The size of the array is not
fixed. The final element of the array should have the value of 0xF, which is not used in
calculations, and should be used to calculate the size of the array. The program can prompt the
user for an integer input. Compare the input with the array. Display the index of the input in the
array if found. If the number does not match any element in the array, insert the number in the
array in sorted order. The program is terminated when input a negative integer. Print the new
array with appropriate message on the screen. For example assume an array as follows:
(array: .word 4, 5, 23, 5, 8, 3, 15, 67, 8, 9, 0xF)
Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 23, 67
Enter a number to search: 20
Number not found. Added to array.
Sorted array: 3, 4, 5, 5, 8, 8, 9, 15, 20, 23, 67
Enter a number to search: 5
Number at index 2
Solution
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
System.out.print(\"Ascending Order:\");
for (int i = 0; i < n - 1; i++)
import java.util.Scanner;
public category Ascending _Order
for (int i = 0; i < n; i++)
temporary worker = a[i];
a[i] = a[j];
a.
Why does a diploid mother cell that undergoes meiosis produce four h.pdf
Why does a diploid mother cell that undergoes meiosis produce four haploid cells? Explain what
happens during meiosis (i.e. what events take place during meiosis) that helps achieve this goal
(four haploid cells).
Solution
To maintain the stability in chromosome number, diploid mother cell that undergoes meiosis
produces four haploid cells
Meiosis includes two phases, which are Meiosis I and Meiosis II. (The meiosis classified as
divisons for our ...)
Each phase includes, Prophase, Metaphase, Anaphase and Telophase.
Meiosis I - The major event is Chromosomal segregation. As the presence of chromosomal
segregation, in this phase the chromosome number reduced to half of the original number.
Prophase, Metaphase, Anaphase and Telophases of Meiosis I are ended with I.
Prophase I : includes the following sub stages.
Leptotene - thin threads : Boutique stage
Zygotene - mating threads : bivalent or tetrad chromosomes.
Pachytene - thick threads : chiasmata can observe
Diplotene - two threads : homologous chromosomes separate from one another a little.
Diakinesis - moving threads : chiasmata clearly visible
Metaphase I : Homologous pairs move together along the metaphase plate
Anaphase I : homologous chromosomes moves to opposite poles.
Telophase I : chromosomes arrive at the poles.
Meiosis II - The major event is Chromatid segregation. As the presence of chromatid
segregation, in this phase the chromosome number maintained to half of the original number.
Prophase, Metaphase, Anaphase and Telophases of Meiosis II are ended with II.
Prophase II : shortening and thickening of the chromatids
Metaphase II : Chromatids move together along the metaphase plate
Anaphase II : Chromatid moves to opposite poles.
Telophases II : Chromatid arrive at the poles..
What is an intumescent material Where is it used SolutionAn .pdf
What is an intumescent material? Where is it used?
Solution
An intumescent material is one that undergoes a chemical change when exposed to heat or
flames, becoming viscous then forming expanding bubbles that harden into a dense, heat
insulating multi-cellular char.
The objectives of intumescent technology are the containment of fire and toxic gases by
inhibiting flame penetration, heat transfer and transport of toxic gases from the site of a fire to
other parts of a structure.
A typical, practical application of intumescence is in fire seal technology, where stips of
intumescent material in a carrier are fitted around the perimeter of a fire door. During a fire the
fire seals intumescence (expand and char) to resist fire penetration and prevent the spread of
fumes.
Intumescent technologies are widely used in passive fire protection systems, where potential
pathways for the spread of flames and fumes, such as conduits, wall openings and ventilation
grilles are fitted with fire retardant products. Passive fire protection materials are usually
combined with \"active\" fire supression technologies such as sprinklers, foam generation and
inert gas systems.
fireproofing items such as - fire seals, smoke seals, letter box systems, pipe collars, pipe sleeves,
pipe wraps, duct wrap, fire grilles, cladding seals, fire rated foams, downlighter covers, lighting
canopies, luminaire covers.
Intumescents are used to achieve passive fire protection for such applications as firestopping,
fireproofing, gasketing and window casings. Such applications are relevant for buildings,
offshore constructions, ships and aircraft..
1. How can a computer with only 2G of physical memory run two progra.pdf
1. How can a computer with only 2G of physical memory run two programs that both use 1.5G
each?
2. How is virtual memory related to physical memory?
3. What is the role of the CMOS in the boot process?
4. What happens immediately after the computer is powered up?
5. What steps occur in the POST?
6. What is stored in the boot sector of a fixed disk?
7. A typical Windows machine has two boot sectors- what are they called?
8. What is protected mode? What features become available?
9. What difference is there between kernel mode and user mode?
10. How can the attacker exploit the Windows boot process?
Solution
1) using virtual memory and Demand-paging concept
2) Virtual memory mapps real physical address to the virtual memory address to transfer the data
between RAM and hard drive
3)CMOS is RAM and it stores the parameters of the devices which are in BIOS.and also it runs
our system clock.
4)When power is on two things done in two steps
>POST (power-on Self Test)
>Operating system loading
these two are done in sequence and it first is fails then second will not be happen.
POST : It check whether all the necessary things are present and they are working well
Operation System Loading : After successfull of POST, CPU searches for storage device to load
the special files which indicates the starting of the operating system.
5)
> First CPU is reset
> CPU check itself and POST is loaded into BIOS
> CPU runs BIOS to check componenents connected to PC
>DRAM is checke with sample reading and writing of every byte.
> keyboard is checked for any key is pressed.
> if any key is pressed it goes to BIOS settings to change them.
> Hard drives are checked whether they are present or not.
> Presence of mouse is also checked.
> lastly test results are checked with the data in BIOS
> IF any mis matches found then POST will results in failure.
6) Some configuaration files and operating system
8)protected mode is first added in x86 machine and it is also called as protected virtual address
mode.
It provides access to Virtual address, Paging and multitasking for system software to have
control over application software.
9)Kernel Mode is to have communication with hardware and it happens under OS.
>Kernel mode programs are most supervised.
>these may terminate the process
> any clashes comes system may crashes
--->User mode is just excuting porgrams and he has no permission to have connection with
hardware.
>less priority
>any clashes comes nothing is going to happen.
this is VerilogHDL classAre these legal identifiersa. system1.pdf
this is VerilogHDL class
Are these legal identifiers?
a. system1
b. 1reg
c. $latch
d. exec$
Solution
the legal identifiers means it is having an unique name to use or identify the object.the identifiers
can contains \"text\" or \"_\" or \"$\" or numbers.
so only system1 is legal identifier remaining all are not a legal identifiers..
Transactions made by Ivanhoe Company for the month of March are shown.pdf
Transactions made by Ivanhoe Company for the month of March are shown below. 1. The
company performed $19,650 of services for customers on account. 2. The company received
$19,650 in cash from customers who had been billed for services [in transaction (1) 3. The
company received a bill for $3,450 of advertising but will not pay it until a later date 4. Ivanhoe
Company paid a cash dividend of $4,000 Prepare a tabular analysis that shows the effects of
these transactions on the expanded accounting equation. (If a transaction causes a decrease in
Assets, Liabilities or Stockholders Equity, place a negative sign (or parentheses) in front of the
amount entered for the particular Asset, Liability or Equity item that was reduced. See Ilustration
3-3 for example.) Liabilities+ Stockholders\' Equity Cash + Accounts Receivable = Accounts
Payable + Common Stock + Retained Earnings RevenuesExpensesDividends
Solution
solution :-CashAccounts ReceivableAccounts PayableCommon StockRetained
EarningRevenuesExpensesDividends1)+$19650+$196502)+$19650-$196503)+$3450-$34504)-
$4000-$4000.
The plastic behavior of materials is explained by dislocation theory..pdf
The plastic behavior of materials is explained by dislocation theory. Substitution AL atoms tend
to be larger than interstitial ones. Electronegativity is a measure of how much one atom will
repel another atom, n metallic bonding, the valence electrons are able to move freely throughout
the crystal.
Solution
1.True
2.True
3.False
4.True.
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Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Francesca Gottschalk - How can education support child empowerment.pptx
Francesca Gottschalk - How can education support child empowerment.pptx
"Protectable subject matters, Protection in biotechnology, Protection of othe...
"Protectable subject matters, Protection in biotechnology, Protection of othe...
Is there a vertex common to every longest path in the following graph.pdf
- 1. Is there a vertex common to every longest path in the following graph? Solution No, there is no such vertex common to any of the two similar longer paths. Suppose, if we consider the two equal horizontal lines of the bigger rectangle we can clearly see there is no common vertex and similarly for others.