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Quotient rule applied to trig, finding second derivatives, third derivatives, and so on!
Say what?  Why would those be the derivatives?  Let’s look at tan x:
Now I want you students to figure out why the rest work.  On the given sheet, show your group’s work.  Step 1: Define as quotient.  Step 2: Derive Step 3: Simplify Group 1:  find y’ when y = csc x  Group 2:  find y’ when y = sec x Group 3:  find y’ when y = cot x
So how to memorize?  Compare and contrast and come up with some patterns.
Ex 8 p.124  Differentiating Trigonometric Functions ,[object Object],[object Object],[object Object]
Ex 9 p. 124  Different Forms of a Derivative Differentiate both forms of First form: 2 nd  Form: Are these equivalent?  Check it out!
Much of the work in calculus comes AFTER taking the derivative.  Characteristics of a simplified form? Absence of negative exponents Combining of like terms Factored forms
Higher-Order Derivatives Just as velocity is the derivative of a position function,  acceleration  is the derivative of a velocity function. s(t) Position Function. . . . v(t) = s’(t) Velocity Function. . . . a(t) = v’(t) = s”(t) Acceleration Function. a(t) is the second derivative of s(t) – which is the derivative of a derivative!
Notations for higher-order derivatives:
Ex 10 p. 125  Finding Acceleration Due to Gravity Because the moon has no atmosphere, a falling object on the moon hits no air resistance.  In 1971, astronaut David Scott showed that a hammer and a feather fell at the same rate on the moon. is the position function where s(t) is the height in meters and t is time in seconds.  What is the ratio of the Earth’s gravitational force to the moon’s? To find acceleration due to gravity on moon, differentiate twice.
Assignment 2.3b  p. 126 #45, 61, 73-78, 83-87 odd, 93-101 odd

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Calc 2.3b

  • 1. Quotient rule applied to trig, finding second derivatives, third derivatives, and so on!
  • 2. Say what? Why would those be the derivatives? Let’s look at tan x:
  • 3. Now I want you students to figure out why the rest work. On the given sheet, show your group’s work. Step 1: Define as quotient. Step 2: Derive Step 3: Simplify Group 1: find y’ when y = csc x Group 2: find y’ when y = sec x Group 3: find y’ when y = cot x
  • 4. So how to memorize? Compare and contrast and come up with some patterns.
  • 5.
  • 6. Ex 9 p. 124 Different Forms of a Derivative Differentiate both forms of First form: 2 nd Form: Are these equivalent? Check it out!
  • 7. Much of the work in calculus comes AFTER taking the derivative. Characteristics of a simplified form? Absence of negative exponents Combining of like terms Factored forms
  • 8. Higher-Order Derivatives Just as velocity is the derivative of a position function, acceleration is the derivative of a velocity function. s(t) Position Function. . . . v(t) = s’(t) Velocity Function. . . . a(t) = v’(t) = s”(t) Acceleration Function. a(t) is the second derivative of s(t) – which is the derivative of a derivative!
  • 10. Ex 10 p. 125 Finding Acceleration Due to Gravity Because the moon has no atmosphere, a falling object on the moon hits no air resistance. In 1971, astronaut David Scott showed that a hammer and a feather fell at the same rate on the moon. is the position function where s(t) is the height in meters and t is time in seconds. What is the ratio of the Earth’s gravitational force to the moon’s? To find acceleration due to gravity on moon, differentiate twice.
  • 11. Assignment 2.3b p. 126 #45, 61, 73-78, 83-87 odd, 93-101 odd