Break- Even Rolston Corporation is comparing two different capital str.docx
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Break- Even Rolston Corporation is comparing two different capital structures,an all equity plan (Plan 1) and a levered plan (Plan II0. Under Plan I, Rolston would have 265,000 shares of stock outstanding. Under Plan II, there would be 185,000 share of stock outstanding and 2.8 million in debt outstanding. The interest rate on the debt is 10 percent and there is no taxes A. If EBIT is $750,000, which plan will result in higher EPS B. If EBIT is 1,500,000, which plan will result in the higher EPS C. What is the break-even EBIT Solution Part C (EBIT - INterest)(1- tax rate)/N = (EBIT - INterest)(1- tax rate)/N (EBIT-0)/265000 = (EBIT - 280000)/185000 Solving for EBIT = 927500 answer .
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BONUS- Option 2- Dietary lipids (triacylglycerols) can be classified a.docx
BONUS- Option 2: Dietary lipids (triacylglycerols) can be classified as saturated fats or unsaturated fats. Which is a solid at room temperature? Which is a liquid at room temperature? How is the melting point related to intermolecular forces and structure? Explain.
Solution
saturated fats are solid at room temperature and unsaturated fats are liquids at room temperature.
Saturated fats are long chains of hydrocarbons which pack tightly with each other due to hydrophobic interactions and form high density of intermolecular contacts. So they are solids at room temperature.
Unsaturated fats are irregular in shape and cannot pack tightly. So, they are liquids at room temperature.
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blemID-100742571 Animation-Dissolution of NaCl in water Identify the type of interactions Drag the a View Available Hint(s) attractions
Solution
Part A)
Interaction during dissolution of NaCl in water
Solvent-solvent interaction
Interaction between H2O molecules
Interactions involving dipole-dipole attractions
Solute-solute interaction
Interaction between ions of NaCl
Interactions involving ion-ion interaction
Solute-solvent interaction
Interaction between Na+ and Oxygen of water
Interaction between Cl- and hydrogen of water
---
Part C)
dissolution of substances in water
Ion-ion forces
CuSO4
dipole-dipole forces
AlCl3
CH3OH
Ion-dipole forces
CuSO4
HF
London-dispersion forces
HF
CH3OH
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Bonds payable are usually classified on the balance sheet as- long.docx
Bonds payable are usually classified on the balance sheet as:
Solution
a) Long-term liabilities
Bonds are usually issued in order to secure long term debt and hence categorised under long term liabilities. They have a fixed maturity and payout fixed interest on quarter / semi-annual / annual basis.
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Book value of common stockholders Book value of common stockho.docx
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Binary Trees in C Write a C function that accepts a pointer to a binar.docx
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Calculate the molarity of a solution made by adding 42-3 mL of concent.docx
Calculate the molarity of a solution made by adding 42.3 mL of concentrated ammonia (28.0 wt%, density 0.880 g/mL) to some water in a volumetric flask, then adding water to the mark to make exactly 250 mL of solution. (It is important to add concentrated acid or base to water, rather than the other way, to minimize splashing and maximize safety.) Number [NH,]- 74
Solution
Mass of ammonia Solution = volume * density
= 42.3*0.880
= 37.224 grams
Now mass of ammonia = 28% of the solution
= 37.224 * 28 / 100
= 10.42272
Moles of ammonia = mass / molar mass
= 10.42272 / 17
= 0.61310
Molarity = moles / volume ( in litre)
= 0.61310 / 0.250
= 2.4524 M
If you satisfied with the solution please like it thankxx
If you have any query please comment
.
Calculate the H+ concentration in an aqueous solution that contains 2-.docx
Calculate the H + concentration in an aqueous solution that contains 2.50 x 10 -3 M hydroxide ion.
4.00 x 10 -10
4.00 x 10 -11
5.00 x 10 -12
4.00 x 10 -12
Solution
Hydroxide ion concentration, [OH - ] = 2.50 x 10 -3 M
We know that, [H + ] [OH - ] = 1 x 10 -14
or, [H + ] = (1 x 10 -14 ) / [OH - ] = (1 x 10 -14 ) / (2.50 x 10 -3 ) = 4 x 10 -12 M
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Brent gets a loan from San Fransisco Bank- Brent signs a standard form.docx
Brent gets a loan from San Fransisco Bank. Brent signs a standard form note prepared by the bank. The note obligates Brent to pay the bank the amount of the loan, plus interest. The bank is the:
A) Maker of the note.
B) Drawer of the note.
C) Drawee of the note.
D) Payee of the note.
Solution
Promissory note
A promissory note is a written document which is prepared at the time of getting loan. It contains terms and conditions of loan including amount of loan, interest rate, repayment schedule , manner of repayment of loan etc. The note is signed by the borrower and then it is kept by lender as a evidence of loan. Promissory note is a negotiable instrument.
A note has two original parties.
Therefore in the given question San Fransisco is the payee of the notes.
Option D
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BONUS- Option 2: Dietary lipids (triacylglycerols) can be classified as saturated fats or unsaturated fats. Which is a solid at room temperature? Which is a liquid at room temperature? How is the melting point related to intermolecular forces and structure? Explain.
Solution
saturated fats are solid at room temperature and unsaturated fats are liquids at room temperature.
Saturated fats are long chains of hydrocarbons which pack tightly with each other due to hydrophobic interactions and form high density of intermolecular contacts. So they are solids at room temperature.
Unsaturated fats are irregular in shape and cannot pack tightly. So, they are liquids at room temperature.
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Solution
Part A)
Interaction during dissolution of NaCl in water
Solvent-solvent interaction
Interaction between H2O molecules
Interactions involving dipole-dipole attractions
Solute-solute interaction
Interaction between ions of NaCl
Interactions involving ion-ion interaction
Solute-solvent interaction
Interaction between Na+ and Oxygen of water
Interaction between Cl- and hydrogen of water
---
Part C)
dissolution of substances in water
Ion-ion forces
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dipole-dipole forces
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CH3OH
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Bonds payable are usually classified on the balance sheet as- long.docx
Bonds payable are usually classified on the balance sheet as:
Solution
a) Long-term liabilities
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Binary Trees in C Write a C function that accepts a pointer to a binar.docx
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Calculate the molarity of a solution made by adding 42-3 mL of concent.docx
Calculate the molarity of a solution made by adding 42.3 mL of concentrated ammonia (28.0 wt%, density 0.880 g/mL) to some water in a volumetric flask, then adding water to the mark to make exactly 250 mL of solution. (It is important to add concentrated acid or base to water, rather than the other way, to minimize splashing and maximize safety.) Number [NH,]- 74
Solution
Mass of ammonia Solution = volume * density
= 42.3*0.880
= 37.224 grams
Now mass of ammonia = 28% of the solution
= 37.224 * 28 / 100
= 10.42272
Moles of ammonia = mass / molar mass
= 10.42272 / 17
= 0.61310
Molarity = moles / volume ( in litre)
= 0.61310 / 0.250
= 2.4524 M
If you satisfied with the solution please like it thankxx
If you have any query please comment
.
Calculate the H+ concentration in an aqueous solution that contains 2-.docx
Calculate the H + concentration in an aqueous solution that contains 2.50 x 10 -3 M hydroxide ion.
4.00 x 10 -10
4.00 x 10 -11
5.00 x 10 -12
4.00 x 10 -12
Solution
Hydroxide ion concentration, [OH - ] = 2.50 x 10 -3 M
We know that, [H + ] [OH - ] = 1 x 10 -14
or, [H + ] = (1 x 10 -14 ) / [OH - ] = (1 x 10 -14 ) / (2.50 x 10 -3 ) = 4 x 10 -12 M
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Brent gets a loan from San Fransisco Bank- Brent signs a standard form.docx
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A) Maker of the note.
B) Drawer of the note.
C) Drawee of the note.
D) Payee of the note.
Solution
Promissory note
A promissory note is a written document which is prepared at the time of getting loan. It contains terms and conditions of loan including amount of loan, interest rate, repayment schedule , manner of repayment of loan etc. The note is signed by the borrower and then it is kept by lender as a evidence of loan. Promissory note is a negotiable instrument.
A note has two original parties.
Therefore in the given question San Fransisco is the payee of the notes.
Option D
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Calculate the cell potential (Ecell for the following lead concentrati.docx
Calculate the cell potential (Ecell for the following lead concentration cell at 298 K. Pb(+) Pb21 [Pb21 Pb21-0.00700 MlI [Pb21-2.75 M
Solution
For concentration cell, cathode and anode are same electrode
So, Eo = 0
Number of electron being transferred in balanced reaction is 2
So, n = 2
right cell is cathode and left cell is anode
use:
E = Eo - (2.303*RT/nF) log {[Pb2+] at anode/[Pb2+]at cathode}
Here:
2.303*R*T/F
= 2.303*8.314*298.15/96500
= 0.0592
So, above expression becomes:
E = Eo - (0.0592/n) log {[Pb2+] at anode/[Pb2+]at cathode}
E = 0 - (0.0592/2) log (0.007/2.75)
E = 7.673*10^-2 V
Answer: 7.67*10^-2 V
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Calculate -OH-- concentration of solutions with the following pH value.docx
Calculate [OH-] concentration of solutions with the following pH values. Show your work.
(a) 10.66
(b) 2.35
(c) 6.02
(d) 13.42
Solution
We know that [H + ][OH - ] = 10 -14
Putting log on both sides,
- log [H + ] - log [OH - ] = - log (10 -14 )
pH + pOH = 14
pOH = - log [OH - ]
[OH - ] = 10 -pOH
1. pOH = 14 - 10.66 = 3.34
[OH - ] = 0.00046 M
2. pOH = 14 - 2.35 = 11.65
[OH - ] = 2.24 x 10 -12 M
3. pOH = 14 - 6.02 = 7.98
[OH - ] = 1.05 x 10 -8 M
4. pOH = 14 - 13.42 = 0.58
[OH - ] = 0.263 M
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2.Flexibility of cafeteria plans help meet various employee needs
3.Cafeteria plans can help control employer costs since employees select only the benefits that they want.
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Solution
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See,
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C++
a) What is a null pointer?
b) Give an example of a function that returns a pointer.
Solution
a)
A pointer that is assigned NULL is called a null pointer.
The NULL pointer is a constant with a value of zero defined in several standard libraries, including iostream.
It is always a good practice to assign the pointer NULL to a pointer variable in case you do not have exact address to be assigned.
Example : int *ptr = NULL; // integer pointer pointing to NULL
b)
// function that returns a pointer to integer variable
int *add(int a, int b){
int c = a+ b;
int *iptr = &c; // pointer that stores address of c
return iptr;
}
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Solution
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By how much will the pH change if 0-025 mol of HCl is added to 1-00 L.docx
By how much will the pH change if 0.025 mol of HCl is added to 1.00 L of the buffer that contains 0.15 M HC 2 H 3 O 2 and 0.25 M C 2 H 3 O 2 – ? Use K a = 1.8 × 10 –5 for HC 2 H 3 O 2 .
Solution
Moles of HC2H3O2 = 0.15M*1L = 0.15moles
Moles of C2H3O2- = 0.25M*1L = 0.25moles
Moles of HCl added = 0.025moles
HCl will react with C2H3O2- to form HC2H3O2
HCl + C2H3O2- --> HC2H3O2 + Cl-
So, moles of C2H3O2- = 0.25moles-0.025moles = 0.225moles
Moles of HC2H3O2 = 0.15moles + 0.025moles = 0.175moles
pH = pKa + log[C2H3O2-]/[HC2H3O2]
Ka = 1.8*10 -5
pKa = -logKa = 4.74
pH = 4.74 + log0.225/0.175
= 4.85
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Answer
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Solution
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(b) 2.35
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Solution
We know that [H + ][OH - ] = 10 -14
Putting log on both sides,
- log [H + ] - log [OH - ] = - log (10 -14 )
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b) Give an example of a function that returns a pointer.
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a)
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By how much will the pH change if 0.025 mol of HCl is added to 1.00 L of the buffer that contains 0.15 M HC 2 H 3 O 2 and 0.25 M C 2 H 3 O 2 – ? Use K a = 1.8 × 10 –5 for HC 2 H 3 O 2 .
Solution
Moles of HC2H3O2 = 0.15M*1L = 0.15moles
Moles of C2H3O2- = 0.25M*1L = 0.25moles
Moles of HCl added = 0.025moles
HCl will react with C2H3O2- to form HC2H3O2
HCl + C2H3O2- --> HC2H3O2 + Cl-
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Moles of HC2H3O2 = 0.15moles + 0.025moles = 0.175moles
pH = pKa + log[C2H3O2-]/[HC2H3O2]
Ka = 1.8*10 -5
pKa = -logKa = 4.74
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Solution
Answer
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(𝐓𝐋𝐄 𝟏𝟎𝟎) (𝐋𝐞𝐬𝐬𝐨𝐧 𝟏)-𝐏𝐫𝐞𝐥𝐢𝐦𝐬
𝐃𝐢𝐬𝐜𝐮𝐬𝐬 𝐭𝐡𝐞 𝐄𝐏𝐏 𝐂𝐮𝐫𝐫𝐢𝐜𝐮𝐥𝐮𝐦 𝐢𝐧 𝐭𝐡𝐞 𝐏𝐡𝐢𝐥𝐢𝐩𝐩𝐢𝐧𝐞𝐬:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
𝐄𝐱𝐩𝐥𝐚𝐢𝐧 𝐭𝐡𝐞 𝐍𝐚𝐭𝐮𝐫𝐞 𝐚𝐧𝐝 𝐒𝐜𝐨𝐩𝐞 𝐨𝐟 𝐚𝐧 𝐄𝐧𝐭𝐫𝐞𝐩𝐫𝐞𝐧𝐞𝐮𝐫:
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skeleton System.pdf (skeleton system wow)
🔥🔥🔥🔥🔥🔥🔥🔥🔥
إضغ بين إيديكم من أقوى الملازم التي صممتها
ملزمة تشريح الجهاز الهيكلي (نظري 3)
💀💀💀💀💀💀💀💀💀💀
تتميز هذهِ الملزمة بعِدة مُميزات :
1- مُترجمة ترجمة تُناسب جميع المستويات
2- تحتوي على 78 رسم توضيحي لكل كلمة موجودة بالملزمة (لكل كلمة !!!!)
#فهم_ماكو_درخ
3- دقة الكتابة والصور عالية جداً جداً جداً
4- هُنالك بعض المعلومات تم توضيحها بشكل تفصيلي جداً (تُعتبر لدى الطالب أو الطالبة بإنها معلومات مُبهمة ومع ذلك تم توضيح هذهِ المعلومات المُبهمة بشكل تفصيلي جداً
5- الملزمة تشرح نفسها ب نفسها بس تكلك تعال اقراني
6- تحتوي الملزمة في اول سلايد على خارطة تتضمن جميع تفرُعات معلومات الجهاز الهيكلي المذكورة في هذهِ الملزمة
واخيراً هذهِ الملزمة حلالٌ عليكم وإتمنى منكم إن تدعولي بالخير والصحة والعافية فقط
كل التوفيق زملائي وزميلاتي ، زميلكم محمد الذهبي 💊💊
🔥🔥🔥🔥🔥🔥🔥🔥🔥
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