2. Co-ordinate system in two dimension:
Suppose two straight lines XOX’ and YOY’
intersect each other at right angle at the point
o in the plane of paper.
The line XOX’ is called x-axis and line YOY’
is called y-axis.
The point o is called the origin.
Two lines also called co-ordinate axes.
They divide the plane in to four parts or
regions namely XOY, X’OY, X’OY’ and
XOY’.
These regions are respectively called first,
second, third and fourth quadrants.
6. Distance between two points:
Let P and Q be feet of perpendiculars on the
X-axis of the points A and B and let R and S
be feet of perpendiculars on the Y-axis of
these points.
In right angled ΔABC,
AB2 = AC2 + BC2
= PQ2 + RS2
=
2 2
2 1 2 1AB x x y y
2 2
2 1 2 1x x y y
7. Slope of a line:
Let A(x1, y1) and B(x2, y2) be any two
points where x1 ≠ x2 i.e. AB is not parallel
to Y-axis.
Then the slope m of the line AB is defined
as
m =
=
y-coordinates
x-coordinates
difference of
difference of
1 2
1 2
y y
x x
8. Slope of parallel and perpendicular lines:
Let l1 and l2 be two lines having slopes m1
and m2 respectively. Then
(1) If m1 = m2, then and then l1 ║ l2
(2) If m1 * m2 = -1, then and then l1┴ l2
9. (1) Equation of a line joining two points:
Let A(x1, y1) and B(x2, y2) be two points in
the plane XOY, where x1 ≠ x2 and y1 ≠ y2.
Let P(x, y) be any point on the line AB.
Thus, the point A, P and B are collinear.
slope of = slope of AP AB
6
10. (2) Equation of line passing through
A (x1, y1) and having slope m:
Let the slope of the line l be m.
Let A (x1, y1) be a point on the line l.
Let P (x, y) be any point on the line l.
Now, slope of line AP = slope of l
y – y1 = m (x – x1)
This is the required equation of the line l.
1
1
y y
m
x x
11. (3) Equation of a line having slope m
and making intercept c on Y-axis:
Suppose the line l has slope m and it makes an
intercept of length c on Y-axis.
Hence A (0,c) is a point on the line l.
Let P (x,y) be any point on the line l.
Hence slope of line AP = slope of l.
Therefore, y – c = mx
Y = mx + c
This is the required equation of the line l.
0
y c
m
x
12. (4) Equation of line making
intercepts a and b on the axes:
Suppose a line l makes an intercept of
measure ‘a’ on X-axis and ‘b’ on Y-axis.
Hence A (a,0) and B (0,b) are the points on
the axes.
Let P (x,y) be any point on the line l.
Now, slope of line AP = slope of line AB
0 0
0
y b
x a a
13. y b
x a a
Therefore, ay = - b (x –a)
ay = -bx + ab
ay + bx = ab
Dividing both sides by ab, we get
This is required equation of the line l.
1
x y
a b
14. (5) General equation of a line.
The general form of the equation of a line
is Ax + By + C = .
Now, find the slope and intercepts on axes
of this line.
Ax + By + C = 0
Therefore, By = -Ax - C
Dividing both sides by B, we get
0.
A C
y x ifB
B B
15. Comparing this equation with y = mx + c,
we get
Also, Ax + By + C = 0 gives Ax + By = -C.
Comparing this with x/a + y/b = 1, we get
( )
( )
( )
A coefficientof x
slope m
B coefficientof y
1
Ax By
C C
1
x y
C C
A B