3. Analysis of First Order
Systems
A first order system is represented by
Where input is R(s) and Process is
𝑎
𝑠+𝑎
,
So C(s) /R(s) =
𝑎
𝑠+𝑎
If R(s) = 1/s, then
4. Analysis of First Order Systems
C(s) =
1
𝑠
∗ (
𝑎
𝑠+𝑎
) ;
Which can be solved further by,
C(s) =
𝐴′
𝑆
+
𝐵′
𝑠+𝑎
Then, A′=1 and B′= -(1/𝑎)
Therefore,
C(s) =
1
𝑆
−
1
𝑠+𝑎
5. Analysis of First Order Systems
Applying Inverse Laplace transforms,
C(s) = L-1(
1
𝑆
) − L−1(
1
𝑠+𝑎
)
C(t) = 1- e-at ------ (1)
To Draw the Waveform, we need to Substitute,
t =
1
𝑎
𝑖𝑛 𝑒𝑞𝑢 (1),