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SAIFUDDEEN BIN HASNAS@ ABD MANAF. (54270211069)



       From this experiment, we can compare the result from measurement and calculation. In this
experiment we use single phase full wave uncontrolled bridge rectifier circuit to measure the result. We
used two loads which are resistive load and inductive load for this experiment.

A half cycle for uncontrolled rectifier with resistive, the diode will turn on when the voltage at the anode
is positive. This is because of the operation of the diode is in forward bias condition. Therefore, it does
allow a current through the load resistor R. During negative cycle, there no current flow through R it
means in reverse bias condition. The current waveform is actually the same shape as the voltage
waveform.

From the experiment of resistive load and inductive load, the value of Vin(rms) from experiment should
be drop because of the occurrence of resistance in the circuit from calculation. So, for resistive load the
value of Vin(rms) for measurement is (98V) should be same the value of Vin(rms) at calculation where
Vin(rms) is 98.01. From the theoretical value of the calculation value is correct solution because using the
formula for voltage, Vin(rms)=Iin(rms)/R.

For the resistive load or task 1a, the load current path through D4, through R, and through D1 to the
source. The current path through R is in the same direction as before, so there is positive drop across R
during both half cycles. From the result for measurement, the input current Iin(rms) is 341mA and then
output current Io(rms) is 308mA. The result for calculation, the input current Iin(rms) is 363mA and then
output current Io(rms) is 2257mA. Measurement and calculation seen a decline in current. Where the
current input Iin(rms) is higher than output current Io(rms). The difference between measurement and
calculation is not the same value. It's because the cable connections affect the result. The average output
voltage and current, there are some difference for the value which are the 72V in measurement and 88.14
in calculation. It same goes to current value Io(avg), for measurement is 240mA and for calculation is
0.326A. By referring to the tabulated data, the value in current of RMS (Irms) is also shown a little bit
difference in value.

For the inductive load or task 1b, For the measurement, average output value of voltage is equal to 78V
where as for calculation it gets 88.143V. It same goes to current value, for measurement is 240mA and for
calculation is 0.326A. By referring to the tabulated data, the value in voltage and current of RMS are also
shown a little bit difference in value. Possibility of technical problems with the circuit or measurement
error in the multimeter.

there are some differences related between resistive load and reactive load. For resistive load, the current
path through R is in the same direction as before, so there is positive drop across R during both half
cycles.thus the full wave bridge rectifier caose the load current flow during both half cycle. While for
inductive load, when increase the load inductance until it os much larger than R,the ripple across the load
become small. If we assume an infinite load inductance, the the load current become constant and the
circuit behaviour is as shown by the waveform.

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Analisis result power e

  • 1. SAIFUDDEEN BIN HASNAS@ ABD MANAF. (54270211069) From this experiment, we can compare the result from measurement and calculation. In this experiment we use single phase full wave uncontrolled bridge rectifier circuit to measure the result. We used two loads which are resistive load and inductive load for this experiment. A half cycle for uncontrolled rectifier with resistive, the diode will turn on when the voltage at the anode is positive. This is because of the operation of the diode is in forward bias condition. Therefore, it does allow a current through the load resistor R. During negative cycle, there no current flow through R it means in reverse bias condition. The current waveform is actually the same shape as the voltage waveform. From the experiment of resistive load and inductive load, the value of Vin(rms) from experiment should be drop because of the occurrence of resistance in the circuit from calculation. So, for resistive load the value of Vin(rms) for measurement is (98V) should be same the value of Vin(rms) at calculation where Vin(rms) is 98.01. From the theoretical value of the calculation value is correct solution because using the formula for voltage, Vin(rms)=Iin(rms)/R. For the resistive load or task 1a, the load current path through D4, through R, and through D1 to the source. The current path through R is in the same direction as before, so there is positive drop across R during both half cycles. From the result for measurement, the input current Iin(rms) is 341mA and then output current Io(rms) is 308mA. The result for calculation, the input current Iin(rms) is 363mA and then output current Io(rms) is 2257mA. Measurement and calculation seen a decline in current. Where the current input Iin(rms) is higher than output current Io(rms). The difference between measurement and calculation is not the same value. It's because the cable connections affect the result. The average output voltage and current, there are some difference for the value which are the 72V in measurement and 88.14 in calculation. It same goes to current value Io(avg), for measurement is 240mA and for calculation is 0.326A. By referring to the tabulated data, the value in current of RMS (Irms) is also shown a little bit difference in value. For the inductive load or task 1b, For the measurement, average output value of voltage is equal to 78V where as for calculation it gets 88.143V. It same goes to current value, for measurement is 240mA and for calculation is 0.326A. By referring to the tabulated data, the value in voltage and current of RMS are also shown a little bit difference in value. Possibility of technical problems with the circuit or measurement error in the multimeter. there are some differences related between resistive load and reactive load. For resistive load, the current path through R is in the same direction as before, so there is positive drop across R during both half cycles.thus the full wave bridge rectifier caose the load current flow during both half cycle. While for inductive load, when increase the load inductance until it os much larger than R,the ripple across the load become small. If we assume an infinite load inductance, the the load current become constant and the circuit behaviour is as shown by the waveform.