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2020 . .
EJERCICIOS RESUELTOS DE ALGEBRA
PREUNIVERSITARIA
POTENCIAS Y RADICALES
Ing. WIDMAR AGUILAR, Msc
Noviembre 2020
2020 . .
1)
= 1 + 2 + 6 1 + 6
= 1 + 4 + 6 − 6 + 5
$ = %3 + 2'( = 9 + 16 /
$ = 25
+
, = 5
+ $= 5+5=10
2)
2020 . .
=
,-..,.+ ,/.,.-
. 00
1 0-.0,.0.-
=
,-..,.+ ,/.,.-
. ,2
[ 1 0,
]
=
,-.,/.,.+.,.-
. ,2
2,
=
,0
. ,2
2,
=
1. ,2
2,
=
05
2,
= 36 7
3)
=(
8
6
/
9
.:,5;
.
+
5
=
8
6
/
9
. , .+
=
8
6<
/
9
=
.
+
,
=
8
6<
9
/
=
+
,
= /
6
0,
+
,
,,
+
,
= /
6
0
, = 2'
0
, = 28
=64
2020 . .
4)
=>
8?. 8@. ?. ,@
A?. A@
@
=
. ?. 8@. ?. ,@
A?. A@
+
@
= [
?. ?. ?. ,@. 8@
A?. A@
+
@ =
?. , ?B@ . 8@
?.C?. @.C@
+
@
= (
?.C?.C@. 8@
?.C?. @.C@
+
@ =
8 D
+
@
= 8
5)
E F =(√F
0 6H
+
0.H
,
0
= √F
0 6HI H
.
-
0
si : x= 3
f x L M
= 36 .
0
0
= 36 .+
2020 . .
f x L M
=
+
0 =
.+
+
0
= 36
+
0
6)
= >FD.F
@
?
?
= >FDN
@
?
?
= >F
?@B@
?
?
= F
?@B@
?,
ODND
O,
= 4 ;
Q FON D?,
= √F ODND?,
= F
, ?@B@
?,
= F '
= FA
------------el exponente es 8.
2020 . .
7)
R =
6S
= >
O
O
+
T
U
= [
O
O
+
T
]
+
U = 6V
+
U
=
T.+
T
.
+
U =
+
+.U
.+
+
+.U
.
+
U
=
+.+BU
+.U
+
+.U
.
+
U
= S.
+
U
IO
8)
=
>
√3
0 √
0 UB0√0
0 U
= √3
0 √
0 UB0 +
√0
0 U
= > √3
0 √
0 U
. √
0 0< √0
0
=
U
= > √3
0 √
0 U
.
< √0
0
=
U
=W √3
0 . √
0 U
X
+
< √0
0
=
U
= √3
0
= 3
2020 . .
9)
: ZF >F … … … … . QF √F
UUUU
= √F
U
U.+
U.+
m =100 ; n=2
= √F
,+]]
,+]].+
,.+
= F
,+]].+
,.+ ,+]]
= F
,+]].+
,+]]
10)
4H
. 8H
. 8 = 2 H
. 26
. 16 H
. 166
2 H
. 2 H
. 2 = 2 H
. 26
. 2' H
. 2' 6
2 H
. 2 = 26
. 26 H
. 26A
0-
+,-
= 26
. 26A
. 26
26CH
= 26
-9x = -12 : 3x = 4
2020 . .
X =
'
11)
2' ,_
= 2 ',_
2'. ,_
= 2 .',_
; 4.3 `
= 3. 4 `
,_
',_
= <'
=
'
H
=
'
; 2x =1
x = →
b
c
; d = 1 e f = 2
p+q = 1+2 =3
12)
√3
√
-
= 3
√3
-
,
= 3 ; √3
-
, = 3
2020 . .
3
-
, = 3
H
= 2
X = 4
13)
FH
= 6 . 8
FH
= 6 .8,
= 6 8
FH
= 36 8
; F = 36
E = √F +
H
'
= √36 +
8
'
E =6+9 ; E = 15
14)
FH
=
+
9
FH
= [
7
+
0]
+
9 =
7
+
,2
Por analogía:
2020 . .
X =
7
= 0
= 36
15)
<
H-6H+0
H026H-=
+
-.+0
=
H
H
-
-.+06H
+0
-.+0
H
02
-.+06H
+0
-.+0
=
H
H H
-
-.+06H
+0
-.+0
H
02
-.+06H
+0
-.+0
= 1
H
-
-.+0
B+
6H
+0
-.+0
B+
H
02
-.+06H
+0
-.+0
= 1
F
,-.+0
-.+0 − F
-
-.+0 = F
02
-.+0 − F
+0
-.+0
F
,-.+0
-.+0 = F
02
-.+0
Luego:
H6
H6
=
7
H6
; 2x = 50
X = 25
16)
2020 . .
= -(1)-4(1)+( + <
g
A
=
= -5 +
7
A
+
g
A
=
6'hN 7Ng
A
=
A
A
= 1
17)
= [ ]6[
+
9
][
+
0
]
.[
+
9
][0]
= [ ]6[
+
9
][
+
0
].0
= [ ]
6<
+
9
= 0
= < =
6
= 3 = 27
18)
2020 . .
=
[g/-.0]
[[gj],k
],0.k
'g6H
. 5
5
=
g/-.0./5.-
.g0,
gj ,k.,0.k
=
g/-.0B5.-
.g0,
gj ,kB0.k =
g/,
.g0,
gj.1
=5 8N 6'A
= 5h
= 1
19)
= [(8
,UB+ 5U
+]U]0.+
= [ 8
UB+ 5U
5U.,U]
+
0
= [ 8
UB+ .U
]
+
0
= (8
U. . .U +
0 = 8
+
0 = 64
+
0
= 4
20)
2020 . .
Haciendo: √F
5
= l ; F = lg
P(x) = [ml6 n5
0
5
o
n
]n
= [ l6n0 n,
]
P(x) = l6n5
=
np5 =
H
+
5 -
P(x) =
H
-
5
; q 5 = ?
P(5) =
g
5
5
=
g
= 56
21)
= >FD6 . F
s
?
?
= FD6 N
s
?
+
? = F
@?.?Bs
?,
ODNt6O
O,
= 5 ; ab+c =a+5
ab+c = a(5a+1)
En: Q FgON O?@Bs
= F
5?,B?
?@Bs = F
5?,B?
5?,B?
= F
El ex[onente es ----- 1
2020 . .
22)
= >
O
O
U.+
U
U
=
O
+
U
O.O
.
+
U
+
U
=
O
+
U
O
+
U.O
.
+
U,
=
O
.
+
U,
=
+
U,
= √
U,
23)
=
>
√5
5 √g
5 UB5√5
5 U
=
>
√5
5 √g
5 U
. √g
5 5√5
5 U
= >
√5
5 √g
5 U
.g
√5
5 U
=
>
√5
5 g. √g
5 U√5
5 U
= √5
5 g. √g
5 U +
√5
5 U
= 5
+
5 g
= 5
2020 . .
24)
=[ + 1 ON
]
+
???
= [ + 1 ON
]
+
??B+
= [ O O?
]O. ?B+
= O.O?.O.?.O.+
= O+B?.?.+
= O]
= =
25)
3'
. 36H
. 3 8NH
. 3 h6H
= 3' 'NH
3'
. 36H
. 3 . 3 H
. 3 h
. 36 H
= 3 8
.3'H
3 H6H6 H
. 3 N'N h
= 3 8
. 3'H
3'86'H
= 3 8N'H
46-2x = 16+4x
6x = 30
X =5
26)
2020 . .
3' ,-
= 3 ',-
3'. ,-
= 3 .',-
4. 3 H
= 3. 4 H
,-
',-
= <'
=
'
-
= <'
= ; 2F = 1
X =
27)
4H
. 4 = 2'
. 3 − 2 H
. 2
2 H
. 2 = 2'
. 3 − 2 H
. 2
4.2 H
+ 8. 2 H
= 2'
. 3
12. 2 H
= 48
2 H
=22
2x =2
X =1
28)
2020 . .
5
+
j
-
,
= 5
+
,
5
0
-
,
j = 5
+
, ;
-
,
8
=
3
H
= 3
H
= 1
X =2
29)
2 H
= 2
2x = 32
X =16
30)
g+56g-
g-.g.+6g/
= 58
5 g
− 5H
= 58
. 5H
. 56
− 58
. 5'
5 g
+ 5 h
= 58NH6
+ 5H
2020 . .
5 h
5g
+ 1 = 5gNH
+5H
5 h
5g
+ 1 = 5g
. 5H
+5H
5 h
5g
+ 1 = 5H
5g
+ 1 ; 5 h
= 5H
X =10
31)
FH
= >g
5/
FH
= Q 56 g5/.5
FH
= Q 56 g55
FH
= 56g
+
55
; FH
= 56g g.5
X = 56g
32)
2020 . .
M =
U. .'.,U.'NA.U.A,
8. .0U
=
U. . , .,U.'N A.U.A,
8. .0U
=
UB+./UB,N .0U. j
/. .0U
=
0.0UN j.0U
/.0U
= 26 '6 S
.( 2 6 S
+ 286 S
= 26'N S
. 2 6 S
+ 286 S
= 26'N
. 2 S6 S
+ 286'
. 2 S6 S
= 26
+ 2 = + 4
M = 4,5
33)
=
-B
0
,.'
.
-
/-
.+.
+
- -,
=
-.
0
,. , .
+
/
.+. -
=
0
,.
.
+
,
.+
= 2. 2
0
,.26
+
,
= 2 N
0
,
6
+
, = 2
= 4
2020 . .
34)
M = √F
- +B-+B-
. √FHH+B-+B-
= F
+
- +B-+B-
. (FHH
+
+B-+B-
= F
+
- +B-+B-
. F
--
+B-+B-
= F
+
- +B-+B- N
--
+B-+B-
= F
+B--.-
- +B-+B-
M = F
:+B-+B-;
-:+B-+B-;
`= u
+
_
M = √u
_
35)
M= [√8
√A
√A
]√
√, √,.j
2020 . .
= [√8
√A
√A
]√
, .j√,
= [√8
√
√
]√
, .j√,
= √8
√
,√,
.√
,.j√,
= √8
,√,.√
,√,
.√
,.j√,
2 √ = [ √2 '
]√ = √2
'√
M= √8
,√,.√
,√,
.√
,
.√
.j√,
M = √8
,√,.√
,./√,
= √8
√
/√,
.√
,./√,
M= √8
√
/√,B,./√,
.
= √8
√
,
.
M= √8 = 8
36)
USAR: Q √ = √ . Q√
= > Q2 √C
0+B √0
0√0
0
.
Z > Q2 √C
0+B √0
0√0
0√0
0
= Q2 √ ,0√0
0
+B √0
0
. > Q2 √ ,0+B √0
0√0
0 ,
2020 . .
= > 2 √ ,0
+
√0
0
+B √0
0
.
Z
2 √ ,0
+
< √0
0
=
,
+B √0
0
= Q2 √
0+B √0
0
. √2
+B √0
0
= Q2 √ N
0+B √0
0
= 2
+B √0
0
+B √0
0
= 2
37)
27
0 -B+
= 3
, -.,
27
0-B0
= 3
,-./
3
0-B0
= 3
,-./
3
0-. /
= 3
,-./
3
0-B/
= 3
,-./
; 3 HN'
= 3 H6'
3F + 4 = 2F − 4
X = -8
38)
>
v,k
k.v
k.+
= 3
>
v,k.,B,
kB+.+.v
k.+
= 3
>
v,.v, k.+
k.+. v
k.+
= 3 ; >
v.v, k.+
k.+.8
k.+
= 3
2020 . .
:v.v, k.+ ;
+
k.+
8. k.+
+
k.+
= 3 ;
v
+
k.+.v,
8
+
k.+
.+,
= 3
e
N
+
k.+ = 36. 6
+
k.+
e
,k.+
k.+ = 6 . 6
+
k.+
e
,k.+
k.+ = 6
N
+
k.+
e
,k.+
k.+ = 6
,k.+
k.+
Finalmente: y =6
39)
-.+
, .
,-B+
0 .
,.0-
/ = 1
Considerando: w
= 1
-.+
, .
,-B+
0 .
,.0-
/ = w
-.+
,
N
,-B+
0
N
,.0-
/ = w
H6
+
HN
+
6 H
'
= 0
mcm = 12
6(x-1) +4(2x+1)+3(2-3x) = 0
6x-6+8x+4+6+9x =0
5x = -4
F = −
'
g
2020 . .
40)
4H,
. 4
+
, = 3H,
.36
+
, + 3H,
. 3
+
,
4H,
. 4
+
, =
-,
+
,
+ 3H,
. 3
+
,
4H,
. 4
+
, =
-,
√
+ 3H,
. √3
2. 4H,
=
-,
N . -,
√
2. 4H,
=
'. -,
√
4H,
=
. -,
√
;
'-,
-, =
√
' H,
=
'
+
,
+
,
;
' H,
=
' +
,
F = ; F =
√
; F = −
√
H+
H,
=
+
√,
6
+
√,
= −1
2020 . .
41)
Si: x -√2 = t → F = l + √2
x -√2 = √2
:-.√,;
,
t = √2
p,
l = 2
+
p,
; ln,
= 2
ln,
= [√2] Q
,
t = √2
x = √2+√2
F = 2√2
42)
2020 . .
FHH HU.-
= FH--U
FH-.HU.-
= FH--U
; FH-.HU.-
= FH--U
FH-BU.-
= FH--U
FHU
= FH--U
FS
= FH-U
x = FHU
; xS
= FHU S
xS
= FS.HU
xS
= FS HU
n = FS
x = x
+
U → F = √x
U
43)
[ ] H
. [ ]6
. [
C
'
]CH
. [
C
'
]6'
=[ ]6 CH
. [
A
7
] 7
[ ] H
. [ ] . [
C
'
]CH
. [
'
C
]'
=[ ]6 CH
. [
A
7
] 7
0
0
.
'/
C/
.
,-
,-
.
C9-
'9-
=
+9-
+9-
.
A,2
7,2
0
0
.
'/
C/
.
,-
,-
.
+1-
+1-
=
+9-
+9-
.
A,2
7,2
2020 . .
0
0
.
'/
C/
. [2 H6 AH]. [3 AH6 H
] =
+9-
+9-
.
A,2
7,2
0
0
.
1
C/
. [26 8H]. [3 8H
] =
+9-
+9-
.
A,2
,2.C,2
5
.0
. [26 8HN CH]. [3 8H6 CH
] =
A,2
,2.C,0
5
.0
. [2 H]. [36 H
] =
,2.0
,2. ,0.,
0-
0- =
2j
2j
H
= 78
3x =76
F =
78
44)
= √FV . >QFy. √Fz50
= √FV. >Fy. QH{5j
= √FV . QFy
j
Q√Fz5j
= F
T
,.F
|
j . F
{
0]
De las condición dada, se tiene:
2020 . .
→
V
+
y
8
+
z
h
= 1
3R + } =
z
g
15R + 5}+ ~ = 30 -----(a)
5(3R + }) = ~
De (a) se tiene:
5(3R + } + ~ = 30
~ + ~ = 30
2 ~ = 30
~ = 15
45)
Si O
= 2 , hallar el valor de E= O?B+
+
g-B/6g-B,Ng-B06g-B+
g-B06g-B+
a) 6 b) 15 c)10 d)12
O?B+
= O?.O
= O O?
= 2 = 4
E = 4+
g-.g/6g-.g,Ng-.g06g-.g+
g-.g06g-.g+
E= 4+
g- g/6g,Ng06g
g- g06g
E = 4+
g g06g g,6
g g,6
E = 4+
g6gN g6
'
E = 4+
gh68
'
= 4+
''
'
E= 4+6
E = 10

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Algebra preuniversitaria widmar aguilar

  • 1. 2020 . . EJERCICIOS RESUELTOS DE ALGEBRA PREUNIVERSITARIA POTENCIAS Y RADICALES Ing. WIDMAR AGUILAR, Msc Noviembre 2020
  • 2. 2020 . . 1) = 1 + 2 + 6 1 + 6 = 1 + 4 + 6 − 6 + 5 $ = %3 + 2'( = 9 + 16 / $ = 25 + , = 5 + $= 5+5=10 2)
  • 3. 2020 . . = ,-..,.+ ,/.,.- . 00 1 0-.0,.0.- = ,-..,.+ ,/.,.- . ,2 [ 1 0, ] = ,-.,/.,.+.,.- . ,2 2, = ,0 . ,2 2, = 1. ,2 2, = 05 2, = 36 7 3) =( 8 6 / 9 .:,5; . + 5 = 8 6 / 9 . , .+ = 8 6< / 9 = . + , = 8 6< 9 / = + , = / 6 0, + , ,, + , = / 6 0 , = 2' 0 , = 28 =64
  • 4. 2020 . . 4) => 8?. 8@. ?. ,@ A?. A@ @ = . ?. 8@. ?. ,@ A?. A@ + @ = [ ?. ?. ?. ,@. 8@ A?. A@ + @ = ?. , ?B@ . 8@ ?.C?. @.C@ + @ = ( ?.C?.C@. 8@ ?.C?. @.C@ + @ = 8 D + @ = 8 5) E F =(√F 0 6H + 0.H , 0 = √F 0 6HI H . - 0 si : x= 3 f x L M = 36 . 0 0 = 36 .+
  • 5. 2020 . . f x L M = + 0 = .+ + 0 = 36 + 0 6) = >FD.F @ ? ? = >FDN @ ? ? = >F ?@B@ ? ? = F ?@B@ ?, ODND O, = 4 ; Q FON D?, = √F ODND?, = F , ?@B@ ?, = F ' = FA ------------el exponente es 8.
  • 6. 2020 . . 7) R = 6S = > O O + T U = [ O O + T ] + U = 6V + U = T.+ T . + U = + +.U .+ + +.U . + U = +.+BU +.U + +.U . + U = S. + U IO 8) = > √3 0 √ 0 UB0√0 0 U = √3 0 √ 0 UB0 + √0 0 U = > √3 0 √ 0 U . √ 0 0< √0 0 = U = > √3 0 √ 0 U . < √0 0 = U =W √3 0 . √ 0 U X + < √0 0 = U = √3 0 = 3
  • 7. 2020 . . 9) : ZF >F … … … … . QF √F UUUU = √F U U.+ U.+ m =100 ; n=2 = √F ,+]] ,+]].+ ,.+ = F ,+]].+ ,.+ ,+]] = F ,+]].+ ,+]] 10) 4H . 8H . 8 = 2 H . 26 . 16 H . 166 2 H . 2 H . 2 = 2 H . 26 . 2' H . 2' 6 2 H . 2 = 26 . 26 H . 26A 0- +,- = 26 . 26A . 26 26CH = 26 -9x = -12 : 3x = 4
  • 8. 2020 . . X = ' 11) 2' ,_ = 2 ',_ 2'. ,_ = 2 .',_ ; 4.3 ` = 3. 4 ` ,_ ',_ = <' = ' H = ' ; 2x =1 x = → b c ; d = 1 e f = 2 p+q = 1+2 =3 12) √3 √ - = 3 √3 - , = 3 ; √3 - , = 3
  • 9. 2020 . . 3 - , = 3 H = 2 X = 4 13) FH = 6 . 8 FH = 6 .8, = 6 8 FH = 36 8 ; F = 36 E = √F + H ' = √36 + 8 ' E =6+9 ; E = 15 14) FH = + 9 FH = [ 7 + 0] + 9 = 7 + ,2 Por analogía:
  • 10. 2020 . . X = 7 = 0 = 36 15) < H-6H+0 H026H-= + -.+0 = H H - -.+06H +0 -.+0 H 02 -.+06H +0 -.+0 = H H H - -.+06H +0 -.+0 H 02 -.+06H +0 -.+0 = 1 H - -.+0 B+ 6H +0 -.+0 B+ H 02 -.+06H +0 -.+0 = 1 F ,-.+0 -.+0 − F - -.+0 = F 02 -.+0 − F +0 -.+0 F ,-.+0 -.+0 = F 02 -.+0 Luego: H6 H6 = 7 H6 ; 2x = 50 X = 25 16)
  • 11. 2020 . . = -(1)-4(1)+( + < g A = = -5 + 7 A + g A = 6'hN 7Ng A = A A = 1 17) = [ ]6[ + 9 ][ + 0 ] .[ + 9 ][0] = [ ]6[ + 9 ][ + 0 ].0 = [ ] 6< + 9 = 0 = < = 6 = 3 = 27 18)
  • 12. 2020 . . = [g/-.0] [[gj],k ],0.k 'g6H . 5 5 = g/-.0./5.- .g0, gj ,k.,0.k = g/-.0B5.- .g0, gj ,kB0.k = g/, .g0, gj.1 =5 8N 6'A = 5h = 1 19) = [(8 ,UB+ 5U +]U]0.+ = [ 8 UB+ 5U 5U.,U] + 0 = [ 8 UB+ .U ] + 0 = (8 U. . .U + 0 = 8 + 0 = 64 + 0 = 4 20)
  • 13. 2020 . . Haciendo: √F 5 = l ; F = lg P(x) = [ml6 n5 0 5 o n ]n = [ l6n0 n, ] P(x) = l6n5 = np5 = H + 5 - P(x) = H - 5 ; q 5 = ? P(5) = g 5 5 = g = 56 21) = >FD6 . F s ? ? = FD6 N s ? + ? = F @?.?Bs ?, ODNt6O O, = 5 ; ab+c =a+5 ab+c = a(5a+1) En: Q FgON O?@Bs = F 5?,B? ?@Bs = F 5?,B? 5?,B? = F El ex[onente es ----- 1
  • 14. 2020 . . 22) = > O O U.+ U U = O + U O.O . + U + U = O + U O + U.O . + U, = O . + U, = + U, = √ U, 23) = > √5 5 √g 5 UB5√5 5 U = > √5 5 √g 5 U . √g 5 5√5 5 U = > √5 5 √g 5 U .g √5 5 U = > √5 5 g. √g 5 U√5 5 U = √5 5 g. √g 5 U + √5 5 U = 5 + 5 g = 5
  • 15. 2020 . . 24) =[ + 1 ON ] + ??? = [ + 1 ON ] + ??B+ = [ O O? ]O. ?B+ = O.O?.O.?.O.+ = O+B?.?.+ = O] = = 25) 3' . 36H . 3 8NH . 3 h6H = 3' 'NH 3' . 36H . 3 . 3 H . 3 h . 36 H = 3 8 .3'H 3 H6H6 H . 3 N'N h = 3 8 . 3'H 3'86'H = 3 8N'H 46-2x = 16+4x 6x = 30 X =5 26)
  • 16. 2020 . . 3' ,- = 3 ',- 3'. ,- = 3 .',- 4. 3 H = 3. 4 H ,- ',- = <' = ' - = <' = ; 2F = 1 X = 27) 4H . 4 = 2' . 3 − 2 H . 2 2 H . 2 = 2' . 3 − 2 H . 2 4.2 H + 8. 2 H = 2' . 3 12. 2 H = 48 2 H =22 2x =2 X =1 28)
  • 17. 2020 . . 5 + j - , = 5 + , 5 0 - , j = 5 + , ; - , 8 = 3 H = 3 H = 1 X =2 29) 2 H = 2 2x = 32 X =16 30) g+56g- g-.g.+6g/ = 58 5 g − 5H = 58 . 5H . 56 − 58 . 5' 5 g + 5 h = 58NH6 + 5H
  • 18. 2020 . . 5 h 5g + 1 = 5gNH +5H 5 h 5g + 1 = 5g . 5H +5H 5 h 5g + 1 = 5H 5g + 1 ; 5 h = 5H X =10 31) FH = >g 5/ FH = Q 56 g5/.5 FH = Q 56 g55 FH = 56g + 55 ; FH = 56g g.5 X = 56g 32)
  • 19. 2020 . . M = U. .'.,U.'NA.U.A, 8. .0U = U. . , .,U.'N A.U.A, 8. .0U = UB+./UB,N .0U. j /. .0U = 0.0UN j.0U /.0U = 26 '6 S .( 2 6 S + 286 S = 26'N S . 2 6 S + 286 S = 26'N . 2 S6 S + 286' . 2 S6 S = 26 + 2 = + 4 M = 4,5 33) = -B 0 ,.' . - /- .+. + - -, = -. 0 ,. , . + / .+. - = 0 ,. . + , .+ = 2. 2 0 ,.26 + , = 2 N 0 , 6 + , = 2 = 4
  • 20. 2020 . . 34) M = √F - +B-+B- . √FHH+B-+B- = F + - +B-+B- . (FHH + +B-+B- = F + - +B-+B- . F -- +B-+B- = F + - +B-+B- N -- +B-+B- = F +B--.- - +B-+B- M = F :+B-+B-; -:+B-+B-; `= u + _ M = √u _ 35) M= [√8 √A √A ]√ √, √,.j
  • 21. 2020 . . = [√8 √A √A ]√ , .j√, = [√8 √ √ ]√ , .j√, = √8 √ ,√, .√ ,.j√, = √8 ,√,.√ ,√, .√ ,.j√, 2 √ = [ √2 ' ]√ = √2 '√ M= √8 ,√,.√ ,√, .√ , .√ .j√, M = √8 ,√,.√ ,./√, = √8 √ /√, .√ ,./√, M= √8 √ /√,B,./√, . = √8 √ , . M= √8 = 8 36) USAR: Q √ = √ . Q√ = > Q2 √C 0+B √0 0√0 0 . Z > Q2 √C 0+B √0 0√0 0√0 0 = Q2 √ ,0√0 0 +B √0 0 . > Q2 √ ,0+B √0 0√0 0 ,
  • 22. 2020 . . = > 2 √ ,0 + √0 0 +B √0 0 . Z 2 √ ,0 + < √0 0 = , +B √0 0 = Q2 √ 0+B √0 0 . √2 +B √0 0 = Q2 √ N 0+B √0 0 = 2 +B √0 0 +B √0 0 = 2 37) 27 0 -B+ = 3 , -., 27 0-B0 = 3 ,-./ 3 0-B0 = 3 ,-./ 3 0-. / = 3 ,-./ 3 0-B/ = 3 ,-./ ; 3 HN' = 3 H6' 3F + 4 = 2F − 4 X = -8 38) > v,k k.v k.+ = 3 > v,k.,B, kB+.+.v k.+ = 3 > v,.v, k.+ k.+. v k.+ = 3 ; > v.v, k.+ k.+.8 k.+ = 3
  • 23. 2020 . . :v.v, k.+ ; + k.+ 8. k.+ + k.+ = 3 ; v + k.+.v, 8 + k.+ .+, = 3 e N + k.+ = 36. 6 + k.+ e ,k.+ k.+ = 6 . 6 + k.+ e ,k.+ k.+ = 6 N + k.+ e ,k.+ k.+ = 6 ,k.+ k.+ Finalmente: y =6 39) -.+ , . ,-B+ 0 . ,.0- / = 1 Considerando: w = 1 -.+ , . ,-B+ 0 . ,.0- / = w -.+ , N ,-B+ 0 N ,.0- / = w H6 + HN + 6 H ' = 0 mcm = 12 6(x-1) +4(2x+1)+3(2-3x) = 0 6x-6+8x+4+6+9x =0 5x = -4 F = − ' g
  • 24. 2020 . . 40) 4H, . 4 + , = 3H, .36 + , + 3H, . 3 + , 4H, . 4 + , = -, + , + 3H, . 3 + , 4H, . 4 + , = -, √ + 3H, . √3 2. 4H, = -, N . -, √ 2. 4H, = '. -, √ 4H, = . -, √ ; '-, -, = √ ' H, = ' + , + , ; ' H, = ' + , F = ; F = √ ; F = − √ H+ H, = + √, 6 + √, = −1
  • 25. 2020 . . 41) Si: x -√2 = t → F = l + √2 x -√2 = √2 :-.√,; , t = √2 p, l = 2 + p, ; ln, = 2 ln, = [√2] Q , t = √2 x = √2+√2 F = 2√2 42)
  • 26. 2020 . . FHH HU.- = FH--U FH-.HU.- = FH--U ; FH-.HU.- = FH--U FH-BU.- = FH--U FHU = FH--U FS = FH-U x = FHU ; xS = FHU S xS = FS.HU xS = FS HU n = FS x = x + U → F = √x U 43) [ ] H . [ ]6 . [ C ' ]CH . [ C ' ]6' =[ ]6 CH . [ A 7 ] 7 [ ] H . [ ] . [ C ' ]CH . [ ' C ]' =[ ]6 CH . [ A 7 ] 7 0 0 . '/ C/ . ,- ,- . C9- '9- = +9- +9- . A,2 7,2 0 0 . '/ C/ . ,- ,- . +1- +1- = +9- +9- . A,2 7,2
  • 27. 2020 . . 0 0 . '/ C/ . [2 H6 AH]. [3 AH6 H ] = +9- +9- . A,2 7,2 0 0 . 1 C/ . [26 8H]. [3 8H ] = +9- +9- . A,2 ,2.C,2 5 .0 . [26 8HN CH]. [3 8H6 CH ] = A,2 ,2.C,0 5 .0 . [2 H]. [36 H ] = ,2.0 ,2. ,0., 0- 0- = 2j 2j H = 78 3x =76 F = 78 44) = √FV . >QFy. √Fz50 = √FV. >Fy. QH{5j = √FV . QFy j Q√Fz5j = F T ,.F | j . F { 0] De las condición dada, se tiene:
  • 28. 2020 . . → V + y 8 + z h = 1 3R + } = z g 15R + 5}+ ~ = 30 -----(a) 5(3R + }) = ~ De (a) se tiene: 5(3R + } + ~ = 30 ~ + ~ = 30 2 ~ = 30 ~ = 15 45) Si O = 2 , hallar el valor de E= O?B+ + g-B/6g-B,Ng-B06g-B+ g-B06g-B+ a) 6 b) 15 c)10 d)12 O?B+ = O?.O = O O? = 2 = 4 E = 4+ g-.g/6g-.g,Ng-.g06g-.g+ g-.g06g-.g+ E= 4+ g- g/6g,Ng06g g- g06g E = 4+ g g06g g,6 g g,6 E = 4+ g6gN g6 ' E = 4+ gh68 ' = 4+ '' ' E= 4+6 E = 10