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Name the domain and range for the relation shown in each graph D = {x | x is a real number} D = {x | x is a real number} R = {y | y β‰₯ 0} R = {y | y β‰₯ -2} Lesson 2 Contents
In a linear equation, each term is either a constant or the product of a constant and (the first power of) a single variable. Which of these represent linear functions? linear nonlinear linear nonlinear Example 2-1a
Slope-intercept form 	   y = mx + b  	f(x) = mx + b m is the slope of the line b is the y-intercept What are the slope and y-intercept of the line                   ? Slope = 3 y-intercept = -9 Example 2-1d
The graph of a linear equation is a line. Graph the line                    y-intercept = -9 Slope = 3 Slope = Ξ”yΞ”x Example 2-1d
Standardform  Ax + By = C  ,[object Object]
 A is positive
A and B are not both zero3x + 5y = -2 is in standard form Example 2-1d
Write the equation in standard form. Identify A, B, and C.  Ax + By = C Simplified? 2      2      2 Example 2-3c
Write the equation in standard form. Identify A, B, and C.  Ax + By = C Simplified? Example 2-3a
Write the equation in standard form. Identify A, B, and C.  Ax + By = C -3                        (-3) Simplified? Example 2-3b
Find the x- and y- intercepts of  -2x + y – 4 = 0 x-intercept -2x + 0 – 4 = 0 -2x – 4 = 0 -2x = 4 x = -2 The x-intercept is -2 	(-2, 0) y-intercept -2(0) + y – 4 = 0 0 + y – 4 = 0 y – 4 = 0 y = 4 The y-intercept is 4 	(0, 4) Example 2-4b
(0, 4) (–2, 0) Graph -2x + y – 4 = 0 x-intercept : –2 y-intercept: 4 Example 2-4c
Slope 	m = vertical change	       Horizontal change 	m = Ξ”yΞ”x 	m = rise		run Any two points on a line can be used to determine its slope.

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Procuring digital preservation CAN be quick and painless with our new dynamic...
Procuring digital preservation CAN be quick and painless with our new dynamic...Procuring digital preservation CAN be quick and painless with our new dynamic...
Procuring digital preservation CAN be quick and painless with our new dynamic...
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Alg2 lesson 2.2 and 2.3

  • 1. Name the domain and range for the relation shown in each graph D = {x | x is a real number} D = {x | x is a real number} R = {y | y β‰₯ 0} R = {y | y β‰₯ -2} Lesson 2 Contents
  • 2. In a linear equation, each term is either a constant or the product of a constant and (the first power of) a single variable. Which of these represent linear functions? linear nonlinear linear nonlinear Example 2-1a
  • 3. Slope-intercept form y = mx + b f(x) = mx + b m is the slope of the line b is the y-intercept What are the slope and y-intercept of the line ? Slope = 3 y-intercept = -9 Example 2-1d
  • 4. The graph of a linear equation is a line. Graph the line y-intercept = -9 Slope = 3 Slope = Ξ”yΞ”x Example 2-1d
  • 5.
  • 6. A is positive
  • 7. A and B are not both zero3x + 5y = -2 is in standard form Example 2-1d
  • 8. Write the equation in standard form. Identify A, B, and C. Ax + By = C Simplified? 2 2 2 Example 2-3c
  • 9. Write the equation in standard form. Identify A, B, and C. Ax + By = C Simplified? Example 2-3a
  • 10. Write the equation in standard form. Identify A, B, and C. Ax + By = C -3 (-3) Simplified? Example 2-3b
  • 11. Find the x- and y- intercepts of -2x + y – 4 = 0 x-intercept -2x + 0 – 4 = 0 -2x – 4 = 0 -2x = 4 x = -2 The x-intercept is -2 (-2, 0) y-intercept -2(0) + y – 4 = 0 0 + y – 4 = 0 y – 4 = 0 y = 4 The y-intercept is 4 (0, 4) Example 2-4b
  • 12. (0, 4) (–2, 0) Graph -2x + y – 4 = 0 x-intercept : –2 y-intercept: 4 Example 2-4c
  • 13. Slope m = vertical change Horizontal change m = Ξ”yΞ”x m = rise run Any two points on a line can be used to determine its slope.
  • 14. Find the slope of a line passing through (-3,5) & (2,1)
  • 15. Classification of lines by slope Positive slope Zero slope Negative slope Undefined slope
  • 16. Graph x = 1 Graph y = 3
  • 17. Parallel lines have equal slopes. Perpendicular lines have slopes that are opposite reciprocals.
  • 18. Graph the line that passes through (2, 1) that is parallel to the graph of 4x – 2y = 10 4x – 2y =10 -2y = -4x + 10 -2 -2 -2 y = 2x – 5 m = 2 , b = -5 Parallel slope = 2
  • 19. Graph the line that passes through (2, 1) that is perpendicular to the graph of 4x – 2y = 10 4x – 2y =10 -2y = -4x + 10 -2 -2 -2 y = 2x – 5 m = 2 , b = -5 Perpendicular slope = -1/2