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ADDITION AND SUBTRACTION OF
4.4       POLYNOMIALS

a Add polynomials.
b Simplify the opposite of a polynomial.
c Subtract polynomials.
d Use polynomials to represent perimeter and
  area.




  Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
Objective            a


Add polynomials.




       Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 2
Example A
Add. (6x3 + 7x  2) + (5x3 + 4x2 + 3)

Solution
(6x3 + 7x  2) + (5x3 + 4x2 + 3)
     = (6 + 5)x3 + 4x2 + 7x + (2 + 3)
     = x3 + 4x2 + 7x + 1




         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 3
Example B
Add: (3  4x + 2x2) + (6 + 8x  4x2 + 2x3)

Solution
(3  4x + 2x2) + (6 + 8x  4x2 + 2x3)
      = (3  6) + (4 + 8)x + (2  4)x2 + 2x3
      = 3 + 4x  2x2 + 2x3




         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 4
Example C
Add: 10x5  3x3 + 7x2 + 4 and 6x4  8x2 + 7 and
4x6  6x5 + 2x2 + 6
Solution
             10x5  3x3 + 7x2 + 4
                 6x4        8x2 + 7
       4x6  6x5           + 2x2 + 6
      4x6 + 4x5 + 6x4  3x3 + x2 + 17
The answer is 4x6 + 4x5 + 6x4  3x3 + x2 + 17.


         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 5
Objective            b


Simplify the opposite of a polynomial.




       Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 6
Opposites of Polynomials
To find an equivalent polynomial for the
opposite, or additive inverse, of a polynomial,
change the sign of every term. This is the same
as multiplying by 1.




          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 7
Example D
Simplify: (8x4  3 x3 + 9x2  2x + 72)
                   4


Solution
     (8x 4
          4  3 x3 + 9x2  2x + 72)



                                 9x2 + 2x  72
                     3 3
     =   8x4   +     4x




          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 8
Objective            c


Subtract polynomials.




       Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 9
Subtraction of Polynomials

We can now subtract one polynomial from another by
adding the opposite of the polynomial being
subtracted.




          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 10
Example E                Subtract:
(10x5 + 2x3  3x2 + 5)  (3x5 + 2x4  5x3  4x2)

Solution
(10x5 + 2x3  3x2 + 5)  (3x5 + 2x4  5x3  4x2)

= 10x5 + 2x3  3x2 + 5 + 3x5  2x4 + 5x3 + 4x2

= 13x5  2x4 + 7x3 + x2 + 5

         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 11
Example F
Subtract: (8x5 + 2x3  10x)  (4x5  5x3 + 6)


Solution
(8x5 + 2x3  10x)  (4x5  5x3 + 6)
      = 8x5 + 2x3  10x + (4x5) + 5x3  6
      = 4x5 + 7x3  10x  6




          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 12
Example G
Write in columns and subtract:
(6x2  4x + 7)  (10x2  6x  4)

Solution
             6x2  4x + 7
           (10x2  6x  4)                                              Remember to change
                                                                         the signs
           4x2 + 2x + 11



           Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley      Slide 4- 13
Objective            d


Use polynomials to represent
perimeter and area.




       Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 14
Example H
A 6-ft by 5-ft hot tub is installed on an outdoor
deck measuring w ft by w ft. Find a polynomial
for the remaining area of the deck.
Solution
1. Familiarize. We make a drawing of the
   situation as follows.
                                                                         5 ft             w ft
                                                                                   7 ft

                                                                             w ft


          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley          Slide 4- 15
continued
2. Translate.
   Rewording: Area of         Area of       Area
                  deck  tub            = left over
Translating: w ft  w ft  5 ft  7 ft = Area left over
3. Carry out.
     w2 ft2  35 ft2 = Area left over.
4. Check. As a partial check, note that the units in the
   answer are square feet, a measure of area, as
   expected.
5. State. The remaining area in the yard is (w2  35)ft2.

           Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 16
1. Add: (6x5 – x3 + 4x2 + x) +
                 (x4 – x3 + 8x2 – x + 2).

              a) 7x5 – 2x3 + 12x2 + 2x + 2

              b) 6x5 + x4 – 2x3 + 12x2 + 2

              c) 7x5 – 2x3 + 12x2 + 2

              d) 6x5 + x4 + 12x2 + 2


Section 4.4         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 17
1. Add: (6x5 – x3 + 4x2 + x) +
                 (x4 – x3 + 8x2 – x + 2).

              a) 7x5 – 2x3 + 12x2 + 2x + 2

              b) 6x5 + x4 – 2x3 + 12x2 + 2

              c) 7x5 – 2x3 + 12x2 + 2

              d) 6x5 + x4 + 12x2 + 2


Section 4.4         Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 18
2. Subtract: (1.1x3 – 8x2 + 4.5x) –
                 (3x3 – x2 + 0.5x – 6).

              a) –2.2x3 – 7x2 + 4x + 6

              b) –1.9x3 – 7x2 + 4x + 6

              c) –2.9x3 – 7x2 + 4x + 6

              d) –1.9x3 – 9x2 + 4x + 6


Section 4.4          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 19
2. Subtract: (1.1x3 – 8x2 + 4.5x) –
                 (3x3 – x2 + 0.5x – 6).

              a) –2.2x3 – 7x2 + 4x + 6

              b) –1.9x3 – 7x2 + 4x + 6

              c) –2.9x3 – 7x2 + 4x + 6

              d) –1.9x3 – 9x2 + 4x + 6


Section 4.4          Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley   Slide 4- 20

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Add subpolyspowepoint

  • 1. ADDITION AND SUBTRACTION OF 4.4 POLYNOMIALS a Add polynomials. b Simplify the opposite of a polynomial. c Subtract polynomials. d Use polynomials to represent perimeter and area. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley
  • 2. Objective a Add polynomials. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 2
  • 3. Example A Add. (6x3 + 7x  2) + (5x3 + 4x2 + 3) Solution (6x3 + 7x  2) + (5x3 + 4x2 + 3) = (6 + 5)x3 + 4x2 + 7x + (2 + 3) = x3 + 4x2 + 7x + 1 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 3
  • 4. Example B Add: (3  4x + 2x2) + (6 + 8x  4x2 + 2x3) Solution (3  4x + 2x2) + (6 + 8x  4x2 + 2x3) = (3  6) + (4 + 8)x + (2  4)x2 + 2x3 = 3 + 4x  2x2 + 2x3 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 4
  • 5. Example C Add: 10x5  3x3 + 7x2 + 4 and 6x4  8x2 + 7 and 4x6  6x5 + 2x2 + 6 Solution 10x5  3x3 + 7x2 + 4 6x4  8x2 + 7 4x6  6x5 + 2x2 + 6 4x6 + 4x5 + 6x4  3x3 + x2 + 17 The answer is 4x6 + 4x5 + 6x4  3x3 + x2 + 17. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 5
  • 6. Objective b Simplify the opposite of a polynomial. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 6
  • 7. Opposites of Polynomials To find an equivalent polynomial for the opposite, or additive inverse, of a polynomial, change the sign of every term. This is the same as multiplying by 1. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 7
  • 8. Example D Simplify: (8x4  3 x3 + 9x2  2x + 72) 4 Solution (8x 4 4  3 x3 + 9x2  2x + 72)  9x2 + 2x  72 3 3 = 8x4 + 4x Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 8
  • 9. Objective c Subtract polynomials. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 9
  • 10. Subtraction of Polynomials We can now subtract one polynomial from another by adding the opposite of the polynomial being subtracted. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 10
  • 11. Example E Subtract: (10x5 + 2x3  3x2 + 5)  (3x5 + 2x4  5x3  4x2) Solution (10x5 + 2x3  3x2 + 5)  (3x5 + 2x4  5x3  4x2) = 10x5 + 2x3  3x2 + 5 + 3x5  2x4 + 5x3 + 4x2 = 13x5  2x4 + 7x3 + x2 + 5 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 11
  • 12. Example F Subtract: (8x5 + 2x3  10x)  (4x5  5x3 + 6) Solution (8x5 + 2x3  10x)  (4x5  5x3 + 6) = 8x5 + 2x3  10x + (4x5) + 5x3  6 = 4x5 + 7x3  10x  6 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 12
  • 13. Example G Write in columns and subtract: (6x2  4x + 7)  (10x2  6x  4) Solution 6x2  4x + 7 (10x2  6x  4) Remember to change the signs 4x2 + 2x + 11 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 13
  • 14. Objective d Use polynomials to represent perimeter and area. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 14
  • 15. Example H A 6-ft by 5-ft hot tub is installed on an outdoor deck measuring w ft by w ft. Find a polynomial for the remaining area of the deck. Solution 1. Familiarize. We make a drawing of the situation as follows. 5 ft w ft 7 ft w ft Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 15
  • 16. continued 2. Translate. Rewording: Area of Area of Area deck  tub = left over Translating: w ft  w ft  5 ft  7 ft = Area left over 3. Carry out. w2 ft2  35 ft2 = Area left over. 4. Check. As a partial check, note that the units in the answer are square feet, a measure of area, as expected. 5. State. The remaining area in the yard is (w2  35)ft2. Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 16
  • 17. 1. Add: (6x5 – x3 + 4x2 + x) + (x4 – x3 + 8x2 – x + 2). a) 7x5 – 2x3 + 12x2 + 2x + 2 b) 6x5 + x4 – 2x3 + 12x2 + 2 c) 7x5 – 2x3 + 12x2 + 2 d) 6x5 + x4 + 12x2 + 2 Section 4.4 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 17
  • 18. 1. Add: (6x5 – x3 + 4x2 + x) + (x4 – x3 + 8x2 – x + 2). a) 7x5 – 2x3 + 12x2 + 2x + 2 b) 6x5 + x4 – 2x3 + 12x2 + 2 c) 7x5 – 2x3 + 12x2 + 2 d) 6x5 + x4 + 12x2 + 2 Section 4.4 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 18
  • 19. 2. Subtract: (1.1x3 – 8x2 + 4.5x) – (3x3 – x2 + 0.5x – 6). a) –2.2x3 – 7x2 + 4x + 6 b) –1.9x3 – 7x2 + 4x + 6 c) –2.9x3 – 7x2 + 4x + 6 d) –1.9x3 – 9x2 + 4x + 6 Section 4.4 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 19
  • 20. 2. Subtract: (1.1x3 – 8x2 + 4.5x) – (3x3 – x2 + 0.5x – 6). a) –2.2x3 – 7x2 + 4x + 6 b) –1.9x3 – 7x2 + 4x + 6 c) –2.9x3 – 7x2 + 4x + 6 d) –1.9x3 – 9x2 + 4x + 6 Section 4.4 Copyright © 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Slide 4- 20