Above is a trace depicting mechanical activity of frog heart. A stud.pdf
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Above is a trace depicting mechanical activity of frog heart. A student tapped the table when atria were contracting. Indicate what peaks 1 and 2 represent Tapping noise Solution Now any other stimulation to ventricle during diastole creates an extrasystole and it will be followed by a very long diastole which is called a compensatory pause.
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For a given H0 and level of significance, if you reject the H0 for a.pdf
For a given H0 and level of significance, if you reject the H0 for a one tailed-test, you would also
reject H0 for a two-tailed test. true or false
Solution
[ANSWER] False.
For two tailed , the critical value in table is diffrent. It higher than the value achived in One tail at
the same level of singnificance. If we Reject H0 in One tail it may or may n\'t Reject in two tail.
Find all elements of our ring R that have norm 1. Show that no elemen.pdf
Find all elements of our ring R that have norm 1. Show that no element has norm 2 or 3.
Solution
a) This element is clearly non-zero, and not a unit. If it is a product of two
non-units, then its norm is a product of two integers of absolute value greater than
1, a contradiction
b) for this we will assume that P is the principal
We need to show that
P s not principal, since
P^2= (2) (easy to check by direct
computation) its order in the class group divides 2, Now P has one generator , then the norm of
this generator is 2
so we can say in the equation it has no principal
it means if it has no principal with elements it has no norm
so we orove for 3 similarly.
Evaluate the decision to have a computer usage policy and the potent.pdf
Evaluate the decision to have a computer usage policy and the potential problems associated with
such a policy.
Solution
Georgia Tech’s Computer and Network Usage and Security Policy (CNUSP) provides the
guiding principles for use of Information Technology (IT) Resources at Georgia Tech. It is the
policy of the Institute that its IT resources be used ethically and legally, in accord with applicable
licenses and contracts, and according to their intended use in support of the Institute’s mission.
Faculty, staff, and students are expected to behave in an ethical1 and professional manner when
using IT Resources.
The CNUSP establishes the necessary balance between Georgia Tech’s culture of openness,
trust, and integrity and the appropriate level of security to protect resources. The principles
established are:
Respect for Users
Members of the Georgia Tech community have the responsibility to respect the privacy of
others.
Data Confidentiality and Integrity
Users of Georgia Tech IT resources are responsible for upholding the confidentiality and
integrity of data to which they have access.
Users of Georgia Tech IT resources are responsible for upholding the confidentiality and
integrity of data to which they have access. Users are prohibited from inspecting, copying,
altering, distributing or destroying anyone else’s files or network traffic, including but not
limited to those related to Institute business, research, and teaching, without proper authorization.
Proper authorization may be required not only from the person from whom the data originated,
but also from Institute management or Institute data stewards. If there is a question, users are
encouraged to check with their management before attempting to access the data without
permission.
Users who are authorized to access sensitive data (e.g. student data) are not authorized to
distribute this data to other uses or grant other users access to the same data without permission
from the Data Steward. Permission to access sensitive data may be obtained through Data
Stewards per the Data Access Procedures.
Protection of IT Resources
Georgia Tech users are expected to respect the integrity of Georgia Tech IT resources to which
they have access.
This includes but is not limited to modifying sftware, systems, or networks that are not owned or
managed by the user; accessing systems that you are not authorized to access; knowingly
installing or running malicious or disruptive sftware.
Authorized users have a responsibility to ensure the security and integrity of personally owned or
managed systems, as well as Institute Data accessed through such systems. Unit Technical Leads
have the responsibility to authorize connections to the unit or departmental networks, excluding
LAWN connections. Users may consult with their Technical Leads on security and system
administration issues and responsibilities, although Technical Leads bear no responsibility for
maintaining personally owned systems. Systems connecti.
(java) eclipse PleaseDevelop an application that implements a pro.pdf
.(java) eclipse Please:
Develop an application that implements a prototype user interface for composing an email
message. The application should have text fields for the To, Cc, and Bcc address lists and subject
line, and one for the message body. Include a button labeled Send. When the send button is
pushed, the program should print the contents of all fields to standard output using println
statements. I need the send button to work.
Solution
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Email {
private JFrame mainFrame;
private JPanel controlPanel;
private JLabel output;
public Email(){
createForm();
}
public static void main(String[] args){
Email emailprog = new Email();
emailprog.sendButton();
}
private void createForm(){
mainFrame = new JFrame(\"Email\");
mainFrame.setSize(600,600);
mainFrame.setLayout(new GridLayout(2,2));
mainFrame.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent windowEvent){
System.exit(0);
}
});
output = new JLabel(\"Output: \");
controlPanel = new JPanel();
controlPanel.setLayout(new GridLayout(10,2));
mainFrame.add(controlPanel);
mainFrame.add(output);
mainFrame.setVisible(true);
}
private void sendButton(){
JLabel to = new JLabel(\"To: \");
JLabel cc = new JLabel(\"Cc: \");
JLabel bcc = new JLabel(\"Bcc: \");
JLabel subject = new JLabel(\"Subject: \");
JLabel msg = new JLabel(\"Message: \");
final JTextField toText = new JTextField(50);
final JTextField ccText = new JTextField(50);
final JTextField bccText = new JTextField(50);
final JTextArea subjectText = new JTextArea(10,50);
final JTextArea msgText = new JTextArea(20,50);
JButton send = new JButton(\"SEND\");
send.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
String data = \"To \" + toText.getText() + \"
Cc \" + ccText.getText() + \"
Bcc \" + bccText.getText() + \"
Subject \" + subjectText.getText() + \"
Message \" + msgText.getText();
output.setText(\"\"+data+\"\");
}
});
controlPanel.add(to);
controlPanel.add(toText);
controlPanel.add(cc);
controlPanel.add(ccText);
controlPanel.add(bcc);
controlPanel.add(bccText);
controlPanel.add(subject);
controlPanel.add(subjectText);
controlPanel.add(msg);
controlPanel.add(msgText);
controlPanel.add(send);
mainFrame.setVisible(true);
}
}
At a sudden contraction in a pipe the diameter changes from D_1 to D_.pdf
At a sudden contraction in a pipe the diameter changes from D_1 to D_2. The pressure drop.
Delta p, which develops across the contraction is a function of D_1 and D_2. as well as the
velocity, V, in the larger pipe, and the fluid density, and viscosity, mu. Use Du K and n as
repeating variables to determine a suitable set of dimensionless parameters. Why would it be
incorrect to include the velocity in the smaller pipe as an additional variable?
Solution
Let DP= F(D1,d2,v,RHO,MU)
units dims pressure F/L^2
L
V =L/t
D = L
rho = FL^-4T^2
Mu= F L^-2T
First dimensionless group using D1 V mu are recurring variables
Pi1 = DelP * D1^a V^b MU^c
since this is non dim, obtains Pi1 = DELP *D1/(V*MU)
Similarly for P2: new entering variable D2, obtain D2/D1
Similarly Pi3, using rho as entering variable,
Pi3 = Rho*D1*V/Mu.
A gymnosperm, such as Juniperus virginiana, that produces female con.pdf
A gymnosperm, such as Juniperus virginiana, that produces female cones on one individual and
male cones on a different individual is monoecious/dioecious/hermaphrodite?
Solution
Monoecious plants have both the male and female flowers on the same plant. Monoecious plants
are also referred to as hermaphroditic plants. Dioeciuos plants are those that bear the male and
female flowers on different individuals. Juniperus virginiana, where the male and female cones
are present on different individuals, is a dioecious plant..
Write short descriptive answer to the following questions Discuss wh.pdf
Write short descriptive answer to the following questions Discuss whether the Internet (Web)
enjoys freedom of speech similar to the Print media or, Broadcast or, both or, none. Discuss
three reasons why the Internet could be considered a relatively easier medium to protect freedom
of speech. Describe two examples of contents on the Web (other than that are already censored
by laws) that should be considered for censorship. Provide reasoning for your answer. Various
organizations and members of Congress suggest requiring Web sites that contain material
\"harmful to minors\" to move to a new domain \" xxx\". Give (with justification) two reasons in
favor and two reasons against such a requirement.
Solution
1.Now a days Internet offers extraordinary opportunities for \"speakers,\" broadly defined.
Political candidates, cultural critics, corporate gadflies -- anyone who wants to express an
opinion about anything -- can make their thoughts available to a world-wide audience far more
easily than has ever been possible before.
Mass Media (one to many): Similar to mass media (radio, television, print media),
Internet allows the broadcaster to reach a large audience. But, unlike mass media,
Internet enables any user to be a publisher or broadcaster since editorial control is
shifted from a small elite; editors and producers, to every user. Where mass media
represent a closed, edited, communication system, Internet holds an open, interactive
communication sphere where everyone can be both speaker and listener.
2..
Why should anyone else care about what I do with my sewage on my own .pdf
Why should anyone else care about what I do with my sewage on my own property? Integrate
specific examples from course material in your response.
Solution
Anyone is going to care what you are going to do with house hold sewage generation and
disposal of sewage into the environment because sewage may causes high environmental
problem - climate change due to presence more non-degradable phosphorous & organic
compounds.
Human impacts on environmental change via sewage are leading to the following imbalance in
the ecosystem at trophic levels. Household-sewage and toxic lead pollutants are other factors
responsible for death of the photosynthetic microalgae & macroalgae result in dead zone with
photosynthetic biomass. This dead zone formation is mainly have higher impact on nitrogen
cycle level of water and nitrogen cycle is going to increase due to higher farm fertilizers mixing
into the aquatic zone via storm water finally bacterial activity is going to reduce “dissolved
oxygen level” available to the other aquatic species dramatically via aerobic respiration.
Recommended
For a given H0 and level of significance, if you reject the H0 for a.pdf
For a given H0 and level of significance, if you reject the H0 for a one tailed-test, you would also
reject H0 for a two-tailed test. true or false
Solution
[ANSWER] False.
For two tailed , the critical value in table is diffrent. It higher than the value achived in One tail at
the same level of singnificance. If we Reject H0 in One tail it may or may n\'t Reject in two tail.
Find all elements of our ring R that have norm 1. Show that no elemen.pdf
Find all elements of our ring R that have norm 1. Show that no element has norm 2 or 3.
Solution
a) This element is clearly non-zero, and not a unit. If it is a product of two
non-units, then its norm is a product of two integers of absolute value greater than
1, a contradiction
b) for this we will assume that P is the principal
We need to show that
P s not principal, since
P^2= (2) (easy to check by direct
computation) its order in the class group divides 2, Now P has one generator , then the norm of
this generator is 2
so we can say in the equation it has no principal
it means if it has no principal with elements it has no norm
so we orove for 3 similarly.
Evaluate the decision to have a computer usage policy and the potent.pdf
Evaluate the decision to have a computer usage policy and the potential problems associated with
such a policy.
Solution
Georgia Tech’s Computer and Network Usage and Security Policy (CNUSP) provides the
guiding principles for use of Information Technology (IT) Resources at Georgia Tech. It is the
policy of the Institute that its IT resources be used ethically and legally, in accord with applicable
licenses and contracts, and according to their intended use in support of the Institute’s mission.
Faculty, staff, and students are expected to behave in an ethical1 and professional manner when
using IT Resources.
The CNUSP establishes the necessary balance between Georgia Tech’s culture of openness,
trust, and integrity and the appropriate level of security to protect resources. The principles
established are:
Respect for Users
Members of the Georgia Tech community have the responsibility to respect the privacy of
others.
Data Confidentiality and Integrity
Users of Georgia Tech IT resources are responsible for upholding the confidentiality and
integrity of data to which they have access.
Users of Georgia Tech IT resources are responsible for upholding the confidentiality and
integrity of data to which they have access. Users are prohibited from inspecting, copying,
altering, distributing or destroying anyone else’s files or network traffic, including but not
limited to those related to Institute business, research, and teaching, without proper authorization.
Proper authorization may be required not only from the person from whom the data originated,
but also from Institute management or Institute data stewards. If there is a question, users are
encouraged to check with their management before attempting to access the data without
permission.
Users who are authorized to access sensitive data (e.g. student data) are not authorized to
distribute this data to other uses or grant other users access to the same data without permission
from the Data Steward. Permission to access sensitive data may be obtained through Data
Stewards per the Data Access Procedures.
Protection of IT Resources
Georgia Tech users are expected to respect the integrity of Georgia Tech IT resources to which
they have access.
This includes but is not limited to modifying sftware, systems, or networks that are not owned or
managed by the user; accessing systems that you are not authorized to access; knowingly
installing or running malicious or disruptive sftware.
Authorized users have a responsibility to ensure the security and integrity of personally owned or
managed systems, as well as Institute Data accessed through such systems. Unit Technical Leads
have the responsibility to authorize connections to the unit or departmental networks, excluding
LAWN connections. Users may consult with their Technical Leads on security and system
administration issues and responsibilities, although Technical Leads bear no responsibility for
maintaining personally owned systems. Systems connecti.
(java) eclipse PleaseDevelop an application that implements a pro.pdf
.(java) eclipse Please:
Develop an application that implements a prototype user interface for composing an email
message. The application should have text fields for the To, Cc, and Bcc address lists and subject
line, and one for the message body. Include a button labeled Send. When the send button is
pushed, the program should print the contents of all fields to standard output using println
statements. I need the send button to work.
Solution
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
public class Email {
private JFrame mainFrame;
private JPanel controlPanel;
private JLabel output;
public Email(){
createForm();
}
public static void main(String[] args){
Email emailprog = new Email();
emailprog.sendButton();
}
private void createForm(){
mainFrame = new JFrame(\"Email\");
mainFrame.setSize(600,600);
mainFrame.setLayout(new GridLayout(2,2));
mainFrame.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent windowEvent){
System.exit(0);
}
});
output = new JLabel(\"Output: \");
controlPanel = new JPanel();
controlPanel.setLayout(new GridLayout(10,2));
mainFrame.add(controlPanel);
mainFrame.add(output);
mainFrame.setVisible(true);
}
private void sendButton(){
JLabel to = new JLabel(\"To: \");
JLabel cc = new JLabel(\"Cc: \");
JLabel bcc = new JLabel(\"Bcc: \");
JLabel subject = new JLabel(\"Subject: \");
JLabel msg = new JLabel(\"Message: \");
final JTextField toText = new JTextField(50);
final JTextField ccText = new JTextField(50);
final JTextField bccText = new JTextField(50);
final JTextArea subjectText = new JTextArea(10,50);
final JTextArea msgText = new JTextArea(20,50);
JButton send = new JButton(\"SEND\");
send.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
String data = \"To \" + toText.getText() + \"
Cc \" + ccText.getText() + \"
Bcc \" + bccText.getText() + \"
Subject \" + subjectText.getText() + \"
Message \" + msgText.getText();
output.setText(\"\"+data+\"\");
}
});
controlPanel.add(to);
controlPanel.add(toText);
controlPanel.add(cc);
controlPanel.add(ccText);
controlPanel.add(bcc);
controlPanel.add(bccText);
controlPanel.add(subject);
controlPanel.add(subjectText);
controlPanel.add(msg);
controlPanel.add(msgText);
controlPanel.add(send);
mainFrame.setVisible(true);
}
}
At a sudden contraction in a pipe the diameter changes from D_1 to D_.pdf
At a sudden contraction in a pipe the diameter changes from D_1 to D_2. The pressure drop.
Delta p, which develops across the contraction is a function of D_1 and D_2. as well as the
velocity, V, in the larger pipe, and the fluid density, and viscosity, mu. Use Du K and n as
repeating variables to determine a suitable set of dimensionless parameters. Why would it be
incorrect to include the velocity in the smaller pipe as an additional variable?
Solution
Let DP= F(D1,d2,v,RHO,MU)
units dims pressure F/L^2
L
V =L/t
D = L
rho = FL^-4T^2
Mu= F L^-2T
First dimensionless group using D1 V mu are recurring variables
Pi1 = DelP * D1^a V^b MU^c
since this is non dim, obtains Pi1 = DELP *D1/(V*MU)
Similarly for P2: new entering variable D2, obtain D2/D1
Similarly Pi3, using rho as entering variable,
Pi3 = Rho*D1*V/Mu.
A gymnosperm, such as Juniperus virginiana, that produces female con.pdf
A gymnosperm, such as Juniperus virginiana, that produces female cones on one individual and
male cones on a different individual is monoecious/dioecious/hermaphrodite?
Solution
Monoecious plants have both the male and female flowers on the same plant. Monoecious plants
are also referred to as hermaphroditic plants. Dioeciuos plants are those that bear the male and
female flowers on different individuals. Juniperus virginiana, where the male and female cones
are present on different individuals, is a dioecious plant..
Write short descriptive answer to the following questions Discuss wh.pdf
Write short descriptive answer to the following questions Discuss whether the Internet (Web)
enjoys freedom of speech similar to the Print media or, Broadcast or, both or, none. Discuss
three reasons why the Internet could be considered a relatively easier medium to protect freedom
of speech. Describe two examples of contents on the Web (other than that are already censored
by laws) that should be considered for censorship. Provide reasoning for your answer. Various
organizations and members of Congress suggest requiring Web sites that contain material
\"harmful to minors\" to move to a new domain \" xxx\". Give (with justification) two reasons in
favor and two reasons against such a requirement.
Solution
1.Now a days Internet offers extraordinary opportunities for \"speakers,\" broadly defined.
Political candidates, cultural critics, corporate gadflies -- anyone who wants to express an
opinion about anything -- can make their thoughts available to a world-wide audience far more
easily than has ever been possible before.
Mass Media (one to many): Similar to mass media (radio, television, print media),
Internet allows the broadcaster to reach a large audience. But, unlike mass media,
Internet enables any user to be a publisher or broadcaster since editorial control is
shifted from a small elite; editors and producers, to every user. Where mass media
represent a closed, edited, communication system, Internet holds an open, interactive
communication sphere where everyone can be both speaker and listener.
2..
Why should anyone else care about what I do with my sewage on my own .pdf
Why should anyone else care about what I do with my sewage on my own property? Integrate
specific examples from course material in your response.
Solution
Anyone is going to care what you are going to do with house hold sewage generation and
disposal of sewage into the environment because sewage may causes high environmental
problem - climate change due to presence more non-degradable phosphorous & organic
compounds.
Human impacts on environmental change via sewage are leading to the following imbalance in
the ecosystem at trophic levels. Household-sewage and toxic lead pollutants are other factors
responsible for death of the photosynthetic microalgae & macroalgae result in dead zone with
photosynthetic biomass. This dead zone formation is mainly have higher impact on nitrogen
cycle level of water and nitrogen cycle is going to increase due to higher farm fertilizers mixing
into the aquatic zone via storm water finally bacterial activity is going to reduce “dissolved
oxygen level” available to the other aquatic species dramatically via aerobic respiration.
Why do viral particles, zymosan on fungi, endotoxin (LPS) from gram .pdf
Why do viral particles, zymosan on fungi, endotoxin (LPS) from gram negative bacteria,
bacterial DNA, and bacterial flagellin each induce the same proinflammatory response, and
especially the production of IL-8, IL-12, IL-1, IL-6, and TNF-alpha?
What is the link between this and c-reactive protein levels in the blood stream?
Solution
The immune system is comprised of two branches: innate and acquired immunity. The innate
immune system is the first line of host defense against pathogens and is mediated by phagocytes
including macrophages and dendritic cells (DCs).
The innate immune response relies on recognition of evolutionarily conserved structures on
pathogens, termed pathogen-associated molecular patterns (PAMPs), through a limited number
of germ line-encoded pattern recognition receptors (PRRs), Upon PAMP recognition, PRRs
present at the cell surface or intracellularly signal to the host the presence of infection and trigger
proinflammatory and antimicrobial responses by activating a multitude of intracellular signaling
pathways, including adaptor molecules, kinases, and transcription factors. Several classes of
PRRs, including Toll-like receptors triggers functional maturation of dendritic cells and leads to
initiation of antigen-specific adaptive immune responses.
Macrophages activated at sites of tissue injury produce a number of cytokines into the
bloodstream, most notable of which are the interleukins IL-1, IL-6 and IL-8, and TNF-, which
induces hepatocytes to synthesize acute phase proteins (APP) including C- reactive protein. The
level of CRP in blood plasma can rise as high as 1000-fold with inflammation. Thus the greatly
raised level of c- reactive protein in the blood stream can be viewed as a strategy to overcome the
poplulation of pathogens..
Which of the following used historicalcomparative methods in their .pdf
Which of the following used historical/comparative methods in their research? Select one: a.
Durkheim, for Elementary Forms of Religion Life b. Marx, for Das Capital c. All of the above d.
Weber, for Protestant Ethic.
Solution
d. Weber, for Protestant Ethic has used historical/comparative methods in their research.
Comparative or historical research examines historical events in order to create explanations
which are valid beyond a particular time and place..
Which of following is not a class of the phylum platyhelminthes Tre.pdf
Which of following is not a class of the phylum platyhelminthes? Trematoda Turbellaria
Nemertea Monogenea. Cestoda Which one of the following statements regarding the origin of
metazoans has the most support? Ancient metazoans, similar to members of the phylum
Placozoa, have been ruled out as ancestral metazoans. The choanoflagellates share features with
the sponges, like having collars of surrounding a flagellum and being colonial. These shared
features suggest a link to at least metazoan lineage. Metazoans are derived from many separate
of unicellular organisms. Modern sponges have a genetic makeup that reflects their ancestral
status. The traditional view of cnidarians relative to germ layers is that cnidaria possess two
germ layers, ectoderm and endoderm. only one germ layer, the ectoderm, that differentiates into
the two tissue layers. two germ layers, ectoderm and mesoderm. definitely all three germ layers
including the mesoglea as it is derived from ectoderm. two germ layers, endoderm and
mesoderm. Throughout most cnidarian groups, the basal or pedal disc serves to be the base of
the tentacles. harbor sensory cells. generate buds. perform extracellular digestion. attach the
cnidarian to the substrate. How are schistosomes unique, compared to other trematodes? They
strike the rich and the poor, educated and ignorant, alike Infections are easy to cure by drugs
surgery All species must cycle through humans to survive They have in their life do they leave
the body of the bost larger separate male and female individuals, and the male is larger which of
the following is a characteristic of stauromedusans? The planula swims initially and then
becomes sessile The top of the polyp has nine extensions Polyps reproduce asexual They have
a solitary polyp body They do not have a mouth If a sponge is fragmented and cells are
dissociated from one another, the cells will reorganize their structure and function, and clumps
of isolated cells will form a new. reproduce sexually. form spicules in the pattern of the cloth.
die from being separated.
Solution
14] nemertea is not a class of platyhelmenthes
Answer = c) Nemertea
Nemertea is a phylum not a class
is phylum of invertebrate animals also known as ribbon worm or proboscis worm
explaination = Phylum Platyhelhelminthes divided into four 4 classes
1] Turbellaria = include mainly free living marine species
2] Monogenea = these are ectoparasites mostly of fish
3] Trematoda = Are internal parasites of mollusca & humans
4] Cestoda = Are internal parasites of vertebrates.
What is wrong with this code Please fix.code#include stdio.h.pdf
What is wrong with this code? Please fix.
code:
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
double main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };
display(mat);
return 0;
}
void display(double nums[ROWS][COLS]) {
double rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf(\"%1.1s\", nums[rowNum][colNum]);
printf(\"\ \");
}
}
Solution
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
int main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };
display(mat);
return 0;
}
void display(double nums[][COLS]) {
//problem with declaring array subscripts with double, so changed to int
int rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf(\"%1.1f\\t\", nums[rowNum][colNum]);
printf(\"\ \");
}
}.
What are two ways that meiosis could produce gametes that contai.pdf
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
Solution
Answer:
The two ways that meiosis could produce gametes which differ genetically from its parent cells
are as under:
(1) During meiosis, homologous chromosomes undergo independent assortment. This means that
the chromosomes associate in no way with one another. Thus, the gametes so formed may have
any combination of paternal and maternal chromosomes.
(2) Crossing over results in the exchange of genetic material between homologous chromosomes,
resulting in recombinant chromosomes. It occurs during the pachytene stage of meiosis I. This
process gives rise to new recombinant varieties and thus the gamete so produced differ
genetically from the parentals..
what is the process in society that made this change to advertising .pdf
what is the process in society that made this change to advertising objective throughout history?
what objective in the list of advertising objectives bears a qualitative change in it or represents a
new level of diff
Solution
Over the years, the advertising objectives has changed with change in societal structure and its
morality. Advertising is a process to attract customer towards a product or service and it takes
the route to arouse various emotion of the target audience. As the societal value has changed
over the years, so has changed the pattern of advertisement to lure the consumer. In earlier days,
when advertisindg came into picture, the society used to be closely knitted and had joint families.
Hence, it was possible to capture a large audience at a go and that too with a well directed
common messaage that includes the societal value of being together. As time progressed,
families broken apart and nuclear families arose in the scene-so advertisers started targeting
individual people\'s choices and came up with 2-3 versions of a single advertisement that can
attract different customers having a same choice but with different mentality. Moreover, the
division of society into high income group, middle income group and lower income group made
the advertiser think in different ways.The concept of niche-advertising crept in- advertisers
started targeting people based on their income. Then came the era of internet that changed the
advertising objective all together. Initially the case was to attract the customer towards a product
now marketers try to present their product at a place and time when customers need it, Today
consumer is busy, having various options to compare - so reaching to the customer at a right time
and at a right place is very necessary-so came the practice of using direct mail communication,
tracking customer search history to know his/her preferences and present him/her with the exact
product they want, came the concept of testimony from satisfied customer to gain confidence of
other customers.
Qualitative changes over the years that represents a new level of difference:
- Niche advertising- Targeting preferences of individual class
- Personal Targeting through internet- helped to save conumer efforts and made the experience
rich..
What is the best way to go about designing an Android AppSoluti.pdf
What is the best way to go about designing an Android App?
Solution
The best way to design an Android App is the Eclipse ADT. The Android Development Tools
(ADT) with Eclipse IDE gives a powerful, intergrated environment in which the Android
Application is built.
ADT enlarge the capabilities of Eclipse to rapidly set up a new Android project, create an
application UI, add packages based on the Android Framework API, debug the applications with
the Android SDK tools, and even send signed or unsigned .apk files in order to share the
application..
Use the following word bank to complete the numbers 51-100. Acoeloma.pdf
Use the following word bank to complete the numbers 51-100. Acoelomate Arthropoda
Alternation alveolus Book lungs cloaca cephalopoda chitin ditellim emulsification Conjugation
companion filter feeding gametes lacteals Custaceans endotherm hemaphrodite closed
circulation inferior vena cava Liver monotremes Operculum Pancreas Parazoa Protonephridium
Plasmodium Phototrophs protein sino atrial node sporozoan pulmonary circuit Spinnerets shell
spiral systole opposable thumb Stomata Kelps tracheids tracheal tube radial It.ventrides
Radially trypanosomes monotremes dosed mycelium vessel elements rhizoids sieve tube
elements This structure protects fish gills. This is the site in mammals where gases are
exchanged with the environment This is the site of gas exchange in insects This vein collects
blood from the lower body and carries it to the heart The common opening of the digestive
system, the excretory system and the reproductive system is known as the Bile is produced in
the Phloem, responsible for transporting nutrients in plants is composed of two types of cells
and cells. These organs in spiders produce silk _In this kind of circulatory system blood is
carried entirely in vessels: This organ is both and endocrine and exocrine gland This group
includes platypus and spiny anteaters.
Solution
51 - This structure protects fish gills OPERCULUM
52 - This is the site in mammals where gases are exchange with the environment LUNGS
53 - This is the site of gas exchange in insects TRACHEAL TUBE
54 - This vein collect blood from the lower body and carries it to the heart INFERIOR VENA
CAVA
55 - The common opening of digestive system , excretory system and reproductive system is
known as CLOACA
56 - Bile is produced in the LIVER
57 - Phloem , responsible for transporting nutrients in plants is composed of two types of cells
SIEVE TUBE ELEMENTS AND COMPANION CELLS
59 - These organs in spiders produce silk SPINNERETS
60 - In these kind of circulatory system blood is carried entirely in vessels CLOSED
CIRCULATORY SYSTEM
61 - This organ is both an endocrine and exocrine gland PANCREAS
62 - This group includes platypus and spiny anteaters MONOTREMES.
Two cards are randomly selected from a 52-card deck. What is the pro.pdf
Two cards are randomly selected from a 52-card deck. What is the probability that the draw will
yield an ace and a face card?
Solution
There are 52C2 = 1326 ways to pick 2 cards in that order.
There are 4 ways to pcik an ace, and 12 ways to pick a face card. Those are 4*12 = 48 ways in
total.
Hence
P(ace and face) = 48/1326 = 0.036199095 [ANSWER].
Two labs are being compared to determine if they are providing the sa.pdf
Two labs are being compared to determine if they are providing the same sulfur analyses. The
results of the analysis of ten samples are provided below. (The samples differ from day to day;
however, on any given day, the sample going to Lab 1 is identical to the sample going to Lab 2.)
Is there strong evidence that the labs are not giving the same results? Use alpha = 0.05.
Solution.
Todopackage hwk6; This class contains the configuration of a t.pdf
Todo
package hwk6;
// This class contains the configuration of a type of apartment
public class Apartment {
int numOfUnits; // the number of apartments of this type
Room[] rooms; // rooms in this type of apartment
Apartment(int numOfUnits, Room[] rooms) {
this.numOfUnits = numOfUnits;
this.rooms = rooms;
}
// return an array of window orders for one unit of this type of apartment
WindowOrder[] orderForOneUnit() {
// TODO
}
// return an array of window orders for all units of this type of apartment
WindowOrder[] totalOrder() {
// TODO
}
// return text like:
//
// 15 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window))
public String toString() {
// TODO
}
}
class OneBedroom extends Apartment {
OneBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom() });
}
}
class TwoBedroom extends Apartment {
TwoBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new
GuestRoom() });
}
}
class ThreeBedroom extends Apartment {
ThreeBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new
GuestRoom(), new GuestRoom() });
}
// return an array of window orders for all units of this type of apartment
//
// Notice we have two guest rooms and they have the same size of windows.
// override the inherited method to merge the order for the two guest rooms since their
windows have the same size
@Override
WindowOrder[] orderForOneUnit() {
// TODO
}
}
package hwk6;
public class Building {
Apartment[] apartments;
public Building(Apartment[] apartments) {
this.apartments= apartments;
}
// Return an array of window orders for all apartments in the building
// Ensure that the orders for windows of the same sizes are merged.
WindowOrder[] order() {
// TODO
}
// return a string to represent all types of apartments in the building such as:
// 20 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))
// 15 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))
// 10 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))(Guest room: 2 (5 X 6 window))
//
public String toString() {
// TODO
}
}
package hwk6;
public class Hwk6 {
public static void main(String[] args) {
Apartment[] apartments = { new OneBedroom(20), new TwoBedroom(15), new
ThreeBedroom(10) };
Building building = new Building(apartments);
WindowOrder[] orders = building.order();
System.out.println(building);
System.out.println(\"Window orders are: \");
for(WindowOrder order: orders) {
System.out.println(order);
}
}
}
package hwk6;
public class Room {
Window window;
int numOfWindows;
Room(Window window, int numOfWindows) {
this.window = window;
this.numOfWindows = numOfWindows;
}
WindowOrder order() {
return new WindowOrder(window, numOfWindows);
}
// Print text like: 5 (6 X 8 window)
@Override
publ.
This question refers to the ABO blood type locus. Remember that the A.pdf
This question refers to the ABO blood type locus. Remember that the A and B alleles are
codominant to each other and both are dominant to the O allele. Assume no epistatic interactions
with the H locus. A man has blood type A. Mark all genotypes below that are possible for this
man. Select one or more: AA AB AO BB BO OO
Solution
Hence both A and B are codominant and dominant over O, the possible genotype of man having
blood group A are AA and AO.
Explanation:
As both A and B are codominant if both are present iegenotype AB results in AB blood group
BB and BO results in B blood group (as there is no A in genotype and B is dominant over O)
OO results in O bllod group(Absence of both A and B in genotype).
This is testing Algorithm Writing For this assessment we will be c.pdf
This is testing Algorithm Writing
For this assessment we will be combining while and if control structures together.
(A):Write a pseudocode (pen and paper) algorithm that solves the ODE y\'= f(t, y) using Euler’s
method.
(B):Convert this algorithm into MATLAB syntax, as the function euler method .
B1:Your inputs should be the start time t0, the end time tend, the function f, an initial condition
y0 and an initial step size h.
B2:If h × f(t, y) at any point exceeds 1, your function should halve the step size h.
B3:Equally, if h × f(t, y) at any point drops below 0.01, your function should double the step
size h.
B4:You should also make sure that the final solution step doesn’t ‘overshoot’ tend. (i.e. change
h during the final step to exactly reach tend).
B5:Your MATLAB code should use the function header below, and be wellcommented with a
sensible layout.
(C)Include your pseudocode algorithm, as well as the MATLAB code in your Portfolio
submission. Also include a discussion of when the code could break, or give incorrect outputs
(you DO NOT need to design your code to avoid these).
Solution
Answer:)
A)
The derivative term in the first order ivp:
y\' = f(t, y),
y(t0) = y0
is approtimated by making use of Taylor series approtimation of the dependent variable y(t) at
the point ti+1. That is
y(ti+1) = y(ti+ Dt) = y(ti) + Dty\'(ti) + (Dt2 / 2)y\'\'(ti) + . . .
= y(ti) + Dtf(ti, yi) + (Dt2 / 2)y\'\'(ti) + . . .
(... y\'(ti) = f(ti, yi))
if the infinite series is truncated from the term Dt2 onwards, then
y(ti+1) = y(ti) + Dt y\'(ti) (or)
yi+1 = yi + Dt fi for all i
That is,
for i = 0, y1 = y0 + Dt f0
i = 1, y2 = y1 + Dt f1
!
i = n-1, yn = yn-1 + Dt fn-1
Since y0 and hence f0 are known (from initial condition) in the equation corresponding to i = 0,
all the terms on the r.h.s are known. So y1 that is, y at t1 is calculated easily from this equation.
Similarly once y1 is known, r.h.s of the equation corresponding to i = 1 is also known so y2 can
be computed. As we proceed in the same way until i = n-1, yn can be obtained. This is an etplicit
method because in any equation there is only one unknown which can be separated to the left
side of the equation.
Local truncation error :
The error in the approtimation, that is the difference between the exact solution at ti+1 and the
numerical solution yi+1 is called the local truncation error (assumed that yi+1 is calculated with
exact arithmetic with out any round off error).
Ti+1 = y(ti+1) - yi+1
= y(ti+1) - yi - Dtfi
= h2/2 y\'(t) (by Taylor series & remainder theorem)
where ti < t < ti+1. Hence the order of the local truncation error for Euler scheme is
O(Dt2) as Dt -> 0.
The rest of the headings are explailalUly sell 5) ABOVE THE CHART AT .pdf
The rest of the headings are explailalUly sell 5) ABOVE THE CHART AT THE TOP OF THE
PAGE... write the Characteristics that the KINGDOM PLANTAE has (All Plants have that the
Green Algae/Charophytes do NOT) Ex: Antheridia.
Solution
Charophytes are considered ancestors to land plants as they share many common characteristics
but some of the differences originated when plants started migrating from water to land or
adapting to land environment. Differences are as follows,
1) Plants produce embryos and protect them in enclosed spaces
2) Plants have true roots, stems, leaves and adaptation to land has acquired waxy cuticles,
stomata, and vasculature.
The hepatic portal system, pulmonary circulation and fetal circulati.pdf
The hepatic portal system, pulmonary circulation and fetal circulation all vary from the “normal”
pattern of blood flow. Be able to describe these special cases.
Solution
1. HEPATIC PORTAL SYSTEM
2. PULMONARY CIRCULATION
In Pulmonary circulation, deoxygenated blood from the right ventricle is carried to the air sacs of
the lungs and returns oxygenated blood from the lungs to the left atrium.
In hepatic portal circulation, blood is carried from capillaries of the gastrointestinal organs and
spleen to sinusoids of the liver. The liver stores, modifies, or detoxifies some of the substances
that have been absorbed by the gastrointestinal tract.
The hepatic portal system includes the veins that drain blood from the pancreas, spleen, stomach,
intestines, and gallbladder and transport it to the hepatic portal vein.
The pulmonary and systemic circulations are different in several ways:
a. Blood in the pulmonary circulation need not be pumped as far as blood in the systemic
circulation
b. Pulmonary arteries have larger diameters, thinner walls, and less elastic tissue; consequently,
resistance to blood flow is very low and therefore less pressure is needed to move blood through
the lungs.
c. As a result, normal pulmonary capillary hydrostatic pressure is lower than average systemic
capillary hydrostatic pressure.
3. FETAL CIRCULATION
Featal circulation exists only in the fetus and consists of structures that permit exchange of
substances between the developing fetus and its mother.
i. The fetal circulation permits the fetus to obtain oxygen and nutrients from the maternal blood
and eliminate its carbon dioxide and wastes into the maternal blood.
ii. The exchange of substances between the fetal blood and maternal blood occurs through the
placenta, which attaches to the navel (umbilicus) of the fetus by the umbilical cord.
iii. Deoxygenated blood flows from the fetus to the placenta via two umbilical arteries.
iv. Oxygenated blood returns from the placenta to the fetus via one umbilical vein which
delivers its blood primarily to the ductus venosus(fetal blood vessel that joins aorta and
pulmonary artery) that drains into the inferior vena cava.
.
The expriment is (solution chemical and physical properties of ethan.pdf
The expriment is (solution chemical and physical properties of ethanol in water)
I need ur help on this experiment, provides me the Literture review of this topic, like the form
what i attached on the the paper
I would be thankful for that
Thank u Literature Review Citation Authors Historically, the introduction of synthetic ion
exchange resin Abrams I. M et is developed by two treatment expert and polymer chemist is al,
1997 and Dale B. A. Adams and E. L. Holmes on 1935 which is do the J. A. et al, 1992. reaction
of formaldehyde with phenolic or amine derivatives to create phenol-formaldehyde structure by
condensation of resin. From the condensate resin era in early 1940, with continue with addition
polymer in ate 1950, and transforming into new adsorbents for varies of application. A class of
polymer beads such a macroporous polymer beads Wheaton R. M et was contained a fixed well-
developed porous structure in al, 2000 withered state, that having a wide range of applications
such as water softening, dealkalization, purification, and many more. The benefit of the porous
system is a sensitive function of the diameter of internal pores, their division, and morphology
Sulfonation reaction can operate at monomer before Meyer M. et al. polymerization or during
post-polymerization. It will affect 2013 the degree of sulfonation and the final ion exchange
capacities of the sulfonated polymer. Most commonly during
Solution
Answer :
Ethanol
Ethanol, C2H5OH, (also called Ethyl Alcohol) is the second member of the aliphatic alcohol
series. It is a clear colourless liquid with a pleasant smell. Except for alcoholic beverages, nearly
all the ethanol used industrially is a mixture of 95% ethanol and 5% water, which is known
simply as 95% alcohol. Although pure ethyl alcohol (known as absolute alcohol) is available, it
is much more expensive and is used only when definitely required.
Preparation
Ethanol is prepared as 95% alcohol (i.e. a 95% solution of ethanol in water) by distillation of the
solution which results from the fermentation of sugars.
Manufacture
There are two major industrial pathways to ethanol. Ethanol which is intended for industrial use
is made by the first method, while ethanol intended for food use tends to be made by the second
method.
Reaction of Ethene with Steam
Most of the ethanol used in industry is made, not by alcoholic fermentation, but by an addition
reaction between ethene and steam.
Alcoholic Fermentation
The fermentation process takes three days and is carried out at a temperature between 250C and
300C. The ethanol is then obtained by fractional distillation..
The ABO and MN blood groups are given below for four sets of parents .pdf
The ABO and MN blood groups are given below for four sets of parents (1 to 4) and four
children (a to d). Recall that the ABO blood group has three alleles, I^A, I^B, and i. The MN
blood group has two codominant alleles, M and N. When all the genetic data is considered
together and by the process of elimination you should be able to match each of the four children
with the correct set of parents.
Solution
Beginning from the first set of parents, let us try to determine the genotype of all sets.
Parents 1: The father can be IBIB or IBi and the mother can be IAIAor IAi. For the MN group,
The father is NN and the mother is MN. So, their children can of A, B, AB or O blood type and
of either MN or N blood group.
Parents 2: The father can be IAIA or IAi and the mother can be IAIAor IAi. For the MN group,
The father is NN and the mother is also NN. So, their children can of A or O blood type and of N
blood group.
Parents 3: The father can be IAIAor IAi and the mother is IAIB. For the MN group, both the
parents are of MN type. So, their children can of A, B, or AB blood type and of either M, N or
MN blood group.
Parents 4: The father is ii and the mother is IAIAor IAi. For the MN group, both the parents are
of MM type. So, their children can of A or O blood type and of M blood group.
Amongst the given set of children only one has the N type blood group. So this child (a)
definitely belongs to the parents who can have children with only N blood group i.e. Parents 2.
For the remaining 3 cases (b, c and d), we want parents with possibility of giving children of M
type blood for children (c) and (d). Parents 1 cannot give an offspring with M type blood group,
so it has to be matched with child (b) where it can easily give AB and MN blood types.
For child (d), Only parents 4 are a match because that is the only set of parents from the
remaining parents which can have a child with O blood group.
That leaves parents 3 to give birth to child (c) with A blood group and M blood type and it is
possible.
So, 1- b, 2- a, 3-c, 4-d.
Table 19.1Table 20.3 Construct an evolutionary history.pdf
Table 19.1
Table 20.3
Construct an evolutionary history using the information in Table 19.1 in Chapter 19 and Table
20.3 Use names. Include only the 4 traits listed in these tables. You will need to lumpsome
organisms of the groups of and some traits. The is a colonial ancestral protist derived is trait
distinguishing from the animals, the the new) t at the end of the branches coming off the main
slanted line. Recall that the progression of evolution (and time) is from bottom to top (outgroup)
(Parazoa) groups here) (5 groups here) (2 animals multicellularity
Solution
Embryonic
Development.
Radial (Adults)
Bilatetal (Larvae)PhylumOrganizationSymmetryGerm layers
Embryonic
Development.PoriferaCellAssymetrical2N/ACnidariaTissueRadial2N/APlatyhelminthsOrganBil
ateral3ProtostomesNematodaOrganBilateral3protostomeMolluscaOrganBilateral (some are
assymetrical)3protostomesAnnelidaOrganBilateral3ProtostomesArthropodaOrganBilateral3Proto
stomesEchinodermataOrgan
Radial (Adults)
Bilatetal (Larvae)3DeuterostomesChordataOrganBilateral3Deuterostomes.
Suppose memory for the address space (process image) is allocated co.pdf
Suppose memory for the address space (process image) is allocated contiguously using dynamic
memory allocation. What extra hardware is needed to generate a physical address and why?
Solution
Memory management is the functionality of an operating system which handles or manages
primary memory and moves processes back and forth between main memory and disk during
execution. Its function i to track whenever some memory gets freed or unallocated .It then
updates the status.There are 2 ways dynamic and static.
dynamic routines of the library are stored on a disk in relocatable form and are loaded into
memory only when they are needed by the program.A reference to the dynamic module is not
used to link the library with the program when dynamic linking is used. Dynamic Link Libraries
(DLL) in Windows and Shared Objects in Unix are examples of dynamic libraries.memory pool
allocation is used. virtual memory may also be used.The Translation Lookaside Buffer (TLB ) is
the main component of the processor responsible for virtual-memory..
Select three methods in the ObjectList class to work through algori.pdf
Select three methods in the ObjectList class to work through algorithmically. Describe any
special cases or boundary conditions that might exist for each of the three methods selected. Be
sure to draw pictures as you work through the methods. Remember that you cannot work on
linked lists without drawing pictures. The homework will not be accepted without submitting the
pictures! Write a Java method with the signature: public objectList intersect (objectList list1,
objectList list2) that accepts two unordered linear linked lists and returns a third linear linked list
whose nodes contains the intersection of the two original linear linked lists. Note that the
intersection of two lists is a new list containing the elements that the two lists have in common,
without modifying the two original lists. Describe any boundary conditions that might exist.
Solution
Node.java
//Defines each node of a linked list
public class Node{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
ObjectList.java
public class ObjectList{
public Node head;
/* Utility function to print list */
public void printList()
{
Node temp = head;
while(temp != null)
{
System.out.print(temp.data+\" \");
temp = temp.next;
}
System.out.println();
}
/* Inserts a node at start of linked list */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);
/* 3. Make next of new Node as head */
new_node.next = head;
/* 4. Move the head to point to new Node */
head = new_node;
}
/* A utilty function that returns true if data is present
in linked list else return false */
public boolean isPresent (int data){
Node t = this.head;
while (t != null)
{
if (t.data == data)
return true;
t = t.next;
}
return false;
}
}
Intersection.java
//Implements the intersection method.
class Intersection{
static public ObjectList intersect(ObjectList list1, ObjectList list2){
ObjectList result = new ObjectList();
//Node t1 = head1;
Node t1 = list1.head;
Node t2 = list2.head;
// Traverse list1 and search each element of it in list2.
// If the element is present in list 2, then insert the
// element to result
while (t1 != null){
if (list2.isPresent(t1.data))
result.push(t1.data);
t1 = t1.next;
}
return result;
}
/* Driver program to test above functions */
public static void main(String args[]){
ObjectList llist1 = new ObjectList();
ObjectList llist2 = new ObjectList();
ObjectList unin = new ObjectList();
ObjectList intersecn = new ObjectList();
/*create a linked lits 10->15->5->20 */
llist1.push(20);
llist1.push(4);
llist1.push(15);
llist1.push(10);
/*create a linked lits 8->4->2->10 */
llist2.push(10);
llist2.push(2);
llist2.push(4);
llist2.push(8);
intersecn = intersect(llist1, llist2);
intersecn.printList();
}
}.
2024.06.01 Introducing a competency framework for languag learning materials ...
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
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Why do viral particles, zymosan on fungi, endotoxin (LPS) from gram .pdf
Why do viral particles, zymosan on fungi, endotoxin (LPS) from gram negative bacteria,
bacterial DNA, and bacterial flagellin each induce the same proinflammatory response, and
especially the production of IL-8, IL-12, IL-1, IL-6, and TNF-alpha?
What is the link between this and c-reactive protein levels in the blood stream?
Solution
The immune system is comprised of two branches: innate and acquired immunity. The innate
immune system is the first line of host defense against pathogens and is mediated by phagocytes
including macrophages and dendritic cells (DCs).
The innate immune response relies on recognition of evolutionarily conserved structures on
pathogens, termed pathogen-associated molecular patterns (PAMPs), through a limited number
of germ line-encoded pattern recognition receptors (PRRs), Upon PAMP recognition, PRRs
present at the cell surface or intracellularly signal to the host the presence of infection and trigger
proinflammatory and antimicrobial responses by activating a multitude of intracellular signaling
pathways, including adaptor molecules, kinases, and transcription factors. Several classes of
PRRs, including Toll-like receptors triggers functional maturation of dendritic cells and leads to
initiation of antigen-specific adaptive immune responses.
Macrophages activated at sites of tissue injury produce a number of cytokines into the
bloodstream, most notable of which are the interleukins IL-1, IL-6 and IL-8, and TNF-, which
induces hepatocytes to synthesize acute phase proteins (APP) including C- reactive protein. The
level of CRP in blood plasma can rise as high as 1000-fold with inflammation. Thus the greatly
raised level of c- reactive protein in the blood stream can be viewed as a strategy to overcome the
poplulation of pathogens..
Which of the following used historicalcomparative methods in their .pdf
Which of the following used historical/comparative methods in their research? Select one: a.
Durkheim, for Elementary Forms of Religion Life b. Marx, for Das Capital c. All of the above d.
Weber, for Protestant Ethic.
Solution
d. Weber, for Protestant Ethic has used historical/comparative methods in their research.
Comparative or historical research examines historical events in order to create explanations
which are valid beyond a particular time and place..
Which of following is not a class of the phylum platyhelminthes Tre.pdf
Which of following is not a class of the phylum platyhelminthes? Trematoda Turbellaria
Nemertea Monogenea. Cestoda Which one of the following statements regarding the origin of
metazoans has the most support? Ancient metazoans, similar to members of the phylum
Placozoa, have been ruled out as ancestral metazoans. The choanoflagellates share features with
the sponges, like having collars of surrounding a flagellum and being colonial. These shared
features suggest a link to at least metazoan lineage. Metazoans are derived from many separate
of unicellular organisms. Modern sponges have a genetic makeup that reflects their ancestral
status. The traditional view of cnidarians relative to germ layers is that cnidaria possess two
germ layers, ectoderm and endoderm. only one germ layer, the ectoderm, that differentiates into
the two tissue layers. two germ layers, ectoderm and mesoderm. definitely all three germ layers
including the mesoglea as it is derived from ectoderm. two germ layers, endoderm and
mesoderm. Throughout most cnidarian groups, the basal or pedal disc serves to be the base of
the tentacles. harbor sensory cells. generate buds. perform extracellular digestion. attach the
cnidarian to the substrate. How are schistosomes unique, compared to other trematodes? They
strike the rich and the poor, educated and ignorant, alike Infections are easy to cure by drugs
surgery All species must cycle through humans to survive They have in their life do they leave
the body of the bost larger separate male and female individuals, and the male is larger which of
the following is a characteristic of stauromedusans? The planula swims initially and then
becomes sessile The top of the polyp has nine extensions Polyps reproduce asexual They have
a solitary polyp body They do not have a mouth If a sponge is fragmented and cells are
dissociated from one another, the cells will reorganize their structure and function, and clumps
of isolated cells will form a new. reproduce sexually. form spicules in the pattern of the cloth.
die from being separated.
Solution
14] nemertea is not a class of platyhelmenthes
Answer = c) Nemertea
Nemertea is a phylum not a class
is phylum of invertebrate animals also known as ribbon worm or proboscis worm
explaination = Phylum Platyhelhelminthes divided into four 4 classes
1] Turbellaria = include mainly free living marine species
2] Monogenea = these are ectoparasites mostly of fish
3] Trematoda = Are internal parasites of mollusca & humans
4] Cestoda = Are internal parasites of vertebrates.
What is wrong with this code Please fix.code#include stdio.h.pdf
What is wrong with this code? Please fix.
code:
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
double main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };
display(mat);
return 0;
}
void display(double nums[ROWS][COLS]) {
double rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf(\"%1.1s\", nums[rowNum][colNum]);
printf(\"\ \");
}
}
Solution
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
int main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };
display(mat);
return 0;
}
void display(double nums[][COLS]) {
//problem with declaring array subscripts with double, so changed to int
int rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf(\"%1.1f\\t\", nums[rowNum][colNum]);
printf(\"\ \");
}
}.
What are two ways that meiosis could produce gametes that contai.pdf
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
What are two ways that meiosis could produce gametes that contain genetic material that is
different from the parent cell?
Solution
Answer:
The two ways that meiosis could produce gametes which differ genetically from its parent cells
are as under:
(1) During meiosis, homologous chromosomes undergo independent assortment. This means that
the chromosomes associate in no way with one another. Thus, the gametes so formed may have
any combination of paternal and maternal chromosomes.
(2) Crossing over results in the exchange of genetic material between homologous chromosomes,
resulting in recombinant chromosomes. It occurs during the pachytene stage of meiosis I. This
process gives rise to new recombinant varieties and thus the gamete so produced differ
genetically from the parentals..
what is the process in society that made this change to advertising .pdf
what is the process in society that made this change to advertising objective throughout history?
what objective in the list of advertising objectives bears a qualitative change in it or represents a
new level of diff
Solution
Over the years, the advertising objectives has changed with change in societal structure and its
morality. Advertising is a process to attract customer towards a product or service and it takes
the route to arouse various emotion of the target audience. As the societal value has changed
over the years, so has changed the pattern of advertisement to lure the consumer. In earlier days,
when advertisindg came into picture, the society used to be closely knitted and had joint families.
Hence, it was possible to capture a large audience at a go and that too with a well directed
common messaage that includes the societal value of being together. As time progressed,
families broken apart and nuclear families arose in the scene-so advertisers started targeting
individual people\'s choices and came up with 2-3 versions of a single advertisement that can
attract different customers having a same choice but with different mentality. Moreover, the
division of society into high income group, middle income group and lower income group made
the advertiser think in different ways.The concept of niche-advertising crept in- advertisers
started targeting people based on their income. Then came the era of internet that changed the
advertising objective all together. Initially the case was to attract the customer towards a product
now marketers try to present their product at a place and time when customers need it, Today
consumer is busy, having various options to compare - so reaching to the customer at a right time
and at a right place is very necessary-so came the practice of using direct mail communication,
tracking customer search history to know his/her preferences and present him/her with the exact
product they want, came the concept of testimony from satisfied customer to gain confidence of
other customers.
Qualitative changes over the years that represents a new level of difference:
- Niche advertising- Targeting preferences of individual class
- Personal Targeting through internet- helped to save conumer efforts and made the experience
rich..
What is the best way to go about designing an Android AppSoluti.pdf
What is the best way to go about designing an Android App?
Solution
The best way to design an Android App is the Eclipse ADT. The Android Development Tools
(ADT) with Eclipse IDE gives a powerful, intergrated environment in which the Android
Application is built.
ADT enlarge the capabilities of Eclipse to rapidly set up a new Android project, create an
application UI, add packages based on the Android Framework API, debug the applications with
the Android SDK tools, and even send signed or unsigned .apk files in order to share the
application..
Use the following word bank to complete the numbers 51-100. Acoeloma.pdf
Use the following word bank to complete the numbers 51-100. Acoelomate Arthropoda
Alternation alveolus Book lungs cloaca cephalopoda chitin ditellim emulsification Conjugation
companion filter feeding gametes lacteals Custaceans endotherm hemaphrodite closed
circulation inferior vena cava Liver monotremes Operculum Pancreas Parazoa Protonephridium
Plasmodium Phototrophs protein sino atrial node sporozoan pulmonary circuit Spinnerets shell
spiral systole opposable thumb Stomata Kelps tracheids tracheal tube radial It.ventrides
Radially trypanosomes monotremes dosed mycelium vessel elements rhizoids sieve tube
elements This structure protects fish gills. This is the site in mammals where gases are
exchanged with the environment This is the site of gas exchange in insects This vein collects
blood from the lower body and carries it to the heart The common opening of the digestive
system, the excretory system and the reproductive system is known as the Bile is produced in
the Phloem, responsible for transporting nutrients in plants is composed of two types of cells
and cells. These organs in spiders produce silk _In this kind of circulatory system blood is
carried entirely in vessels: This organ is both and endocrine and exocrine gland This group
includes platypus and spiny anteaters.
Solution
51 - This structure protects fish gills OPERCULUM
52 - This is the site in mammals where gases are exchange with the environment LUNGS
53 - This is the site of gas exchange in insects TRACHEAL TUBE
54 - This vein collect blood from the lower body and carries it to the heart INFERIOR VENA
CAVA
55 - The common opening of digestive system , excretory system and reproductive system is
known as CLOACA
56 - Bile is produced in the LIVER
57 - Phloem , responsible for transporting nutrients in plants is composed of two types of cells
SIEVE TUBE ELEMENTS AND COMPANION CELLS
59 - These organs in spiders produce silk SPINNERETS
60 - In these kind of circulatory system blood is carried entirely in vessels CLOSED
CIRCULATORY SYSTEM
61 - This organ is both an endocrine and exocrine gland PANCREAS
62 - This group includes platypus and spiny anteaters MONOTREMES.
Two cards are randomly selected from a 52-card deck. What is the pro.pdf
Two cards are randomly selected from a 52-card deck. What is the probability that the draw will
yield an ace and a face card?
Solution
There are 52C2 = 1326 ways to pick 2 cards in that order.
There are 4 ways to pcik an ace, and 12 ways to pick a face card. Those are 4*12 = 48 ways in
total.
Hence
P(ace and face) = 48/1326 = 0.036199095 [ANSWER].
Two labs are being compared to determine if they are providing the sa.pdf
Two labs are being compared to determine if they are providing the same sulfur analyses. The
results of the analysis of ten samples are provided below. (The samples differ from day to day;
however, on any given day, the sample going to Lab 1 is identical to the sample going to Lab 2.)
Is there strong evidence that the labs are not giving the same results? Use alpha = 0.05.
Solution.
Todopackage hwk6; This class contains the configuration of a t.pdf
Todo
package hwk6;
// This class contains the configuration of a type of apartment
public class Apartment {
int numOfUnits; // the number of apartments of this type
Room[] rooms; // rooms in this type of apartment
Apartment(int numOfUnits, Room[] rooms) {
this.numOfUnits = numOfUnits;
this.rooms = rooms;
}
// return an array of window orders for one unit of this type of apartment
WindowOrder[] orderForOneUnit() {
// TODO
}
// return an array of window orders for all units of this type of apartment
WindowOrder[] totalOrder() {
// TODO
}
// return text like:
//
// 15 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window))
(Guest room: 2 (5 X 6 window))
public String toString() {
// TODO
}
}
class OneBedroom extends Apartment {
OneBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom() });
}
}
class TwoBedroom extends Apartment {
TwoBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new
GuestRoom() });
}
}
class ThreeBedroom extends Apartment {
ThreeBedroom(int numOfUnits) {
super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new
GuestRoom(), new GuestRoom() });
}
// return an array of window orders for all units of this type of apartment
//
// Notice we have two guest rooms and they have the same size of windows.
// override the inherited method to merge the order for the two guest rooms since their
windows have the same size
@Override
WindowOrder[] orderForOneUnit() {
// TODO
}
}
package hwk6;
public class Building {
Apartment[] apartments;
public Building(Apartment[] apartments) {
this.apartments= apartments;
}
// Return an array of window orders for all apartments in the building
// Ensure that the orders for windows of the same sizes are merged.
WindowOrder[] order() {
// TODO
}
// return a string to represent all types of apartments in the building such as:
// 20 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))
// 15 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))
// 10 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6
window))(Guest room: 2 (5 X 6 window))(Guest room: 2 (5 X 6 window))
//
public String toString() {
// TODO
}
}
package hwk6;
public class Hwk6 {
public static void main(String[] args) {
Apartment[] apartments = { new OneBedroom(20), new TwoBedroom(15), new
ThreeBedroom(10) };
Building building = new Building(apartments);
WindowOrder[] orders = building.order();
System.out.println(building);
System.out.println(\"Window orders are: \");
for(WindowOrder order: orders) {
System.out.println(order);
}
}
}
package hwk6;
public class Room {
Window window;
int numOfWindows;
Room(Window window, int numOfWindows) {
this.window = window;
this.numOfWindows = numOfWindows;
}
WindowOrder order() {
return new WindowOrder(window, numOfWindows);
}
// Print text like: 5 (6 X 8 window)
@Override
publ.
This question refers to the ABO blood type locus. Remember that the A.pdf
This question refers to the ABO blood type locus. Remember that the A and B alleles are
codominant to each other and both are dominant to the O allele. Assume no epistatic interactions
with the H locus. A man has blood type A. Mark all genotypes below that are possible for this
man. Select one or more: AA AB AO BB BO OO
Solution
Hence both A and B are codominant and dominant over O, the possible genotype of man having
blood group A are AA and AO.
Explanation:
As both A and B are codominant if both are present iegenotype AB results in AB blood group
BB and BO results in B blood group (as there is no A in genotype and B is dominant over O)
OO results in O bllod group(Absence of both A and B in genotype).
This is testing Algorithm Writing For this assessment we will be c.pdf
This is testing Algorithm Writing
For this assessment we will be combining while and if control structures together.
(A):Write a pseudocode (pen and paper) algorithm that solves the ODE y\'= f(t, y) using Euler’s
method.
(B):Convert this algorithm into MATLAB syntax, as the function euler method .
B1:Your inputs should be the start time t0, the end time tend, the function f, an initial condition
y0 and an initial step size h.
B2:If h × f(t, y) at any point exceeds 1, your function should halve the step size h.
B3:Equally, if h × f(t, y) at any point drops below 0.01, your function should double the step
size h.
B4:You should also make sure that the final solution step doesn’t ‘overshoot’ tend. (i.e. change
h during the final step to exactly reach tend).
B5:Your MATLAB code should use the function header below, and be wellcommented with a
sensible layout.
(C)Include your pseudocode algorithm, as well as the MATLAB code in your Portfolio
submission. Also include a discussion of when the code could break, or give incorrect outputs
(you DO NOT need to design your code to avoid these).
Solution
Answer:)
A)
The derivative term in the first order ivp:
y\' = f(t, y),
y(t0) = y0
is approtimated by making use of Taylor series approtimation of the dependent variable y(t) at
the point ti+1. That is
y(ti+1) = y(ti+ Dt) = y(ti) + Dty\'(ti) + (Dt2 / 2)y\'\'(ti) + . . .
= y(ti) + Dtf(ti, yi) + (Dt2 / 2)y\'\'(ti) + . . .
(... y\'(ti) = f(ti, yi))
if the infinite series is truncated from the term Dt2 onwards, then
y(ti+1) = y(ti) + Dt y\'(ti) (or)
yi+1 = yi + Dt fi for all i
That is,
for i = 0, y1 = y0 + Dt f0
i = 1, y2 = y1 + Dt f1
!
i = n-1, yn = yn-1 + Dt fn-1
Since y0 and hence f0 are known (from initial condition) in the equation corresponding to i = 0,
all the terms on the r.h.s are known. So y1 that is, y at t1 is calculated easily from this equation.
Similarly once y1 is known, r.h.s of the equation corresponding to i = 1 is also known so y2 can
be computed. As we proceed in the same way until i = n-1, yn can be obtained. This is an etplicit
method because in any equation there is only one unknown which can be separated to the left
side of the equation.
Local truncation error :
The error in the approtimation, that is the difference between the exact solution at ti+1 and the
numerical solution yi+1 is called the local truncation error (assumed that yi+1 is calculated with
exact arithmetic with out any round off error).
Ti+1 = y(ti+1) - yi+1
= y(ti+1) - yi - Dtfi
= h2/2 y\'(t) (by Taylor series & remainder theorem)
where ti < t < ti+1. Hence the order of the local truncation error for Euler scheme is
O(Dt2) as Dt -> 0.
The rest of the headings are explailalUly sell 5) ABOVE THE CHART AT .pdf
The rest of the headings are explailalUly sell 5) ABOVE THE CHART AT THE TOP OF THE
PAGE... write the Characteristics that the KINGDOM PLANTAE has (All Plants have that the
Green Algae/Charophytes do NOT) Ex: Antheridia.
Solution
Charophytes are considered ancestors to land plants as they share many common characteristics
but some of the differences originated when plants started migrating from water to land or
adapting to land environment. Differences are as follows,
1) Plants produce embryos and protect them in enclosed spaces
2) Plants have true roots, stems, leaves and adaptation to land has acquired waxy cuticles,
stomata, and vasculature.
The hepatic portal system, pulmonary circulation and fetal circulati.pdf
The hepatic portal system, pulmonary circulation and fetal circulation all vary from the “normal”
pattern of blood flow. Be able to describe these special cases.
Solution
1. HEPATIC PORTAL SYSTEM
2. PULMONARY CIRCULATION
In Pulmonary circulation, deoxygenated blood from the right ventricle is carried to the air sacs of
the lungs and returns oxygenated blood from the lungs to the left atrium.
In hepatic portal circulation, blood is carried from capillaries of the gastrointestinal organs and
spleen to sinusoids of the liver. The liver stores, modifies, or detoxifies some of the substances
that have been absorbed by the gastrointestinal tract.
The hepatic portal system includes the veins that drain blood from the pancreas, spleen, stomach,
intestines, and gallbladder and transport it to the hepatic portal vein.
The pulmonary and systemic circulations are different in several ways:
a. Blood in the pulmonary circulation need not be pumped as far as blood in the systemic
circulation
b. Pulmonary arteries have larger diameters, thinner walls, and less elastic tissue; consequently,
resistance to blood flow is very low and therefore less pressure is needed to move blood through
the lungs.
c. As a result, normal pulmonary capillary hydrostatic pressure is lower than average systemic
capillary hydrostatic pressure.
3. FETAL CIRCULATION
Featal circulation exists only in the fetus and consists of structures that permit exchange of
substances between the developing fetus and its mother.
i. The fetal circulation permits the fetus to obtain oxygen and nutrients from the maternal blood
and eliminate its carbon dioxide and wastes into the maternal blood.
ii. The exchange of substances between the fetal blood and maternal blood occurs through the
placenta, which attaches to the navel (umbilicus) of the fetus by the umbilical cord.
iii. Deoxygenated blood flows from the fetus to the placenta via two umbilical arteries.
iv. Oxygenated blood returns from the placenta to the fetus via one umbilical vein which
delivers its blood primarily to the ductus venosus(fetal blood vessel that joins aorta and
pulmonary artery) that drains into the inferior vena cava.
.
The expriment is (solution chemical and physical properties of ethan.pdf
The expriment is (solution chemical and physical properties of ethanol in water)
I need ur help on this experiment, provides me the Literture review of this topic, like the form
what i attached on the the paper
I would be thankful for that
Thank u Literature Review Citation Authors Historically, the introduction of synthetic ion
exchange resin Abrams I. M et is developed by two treatment expert and polymer chemist is al,
1997 and Dale B. A. Adams and E. L. Holmes on 1935 which is do the J. A. et al, 1992. reaction
of formaldehyde with phenolic or amine derivatives to create phenol-formaldehyde structure by
condensation of resin. From the condensate resin era in early 1940, with continue with addition
polymer in ate 1950, and transforming into new adsorbents for varies of application. A class of
polymer beads such a macroporous polymer beads Wheaton R. M et was contained a fixed well-
developed porous structure in al, 2000 withered state, that having a wide range of applications
such as water softening, dealkalization, purification, and many more. The benefit of the porous
system is a sensitive function of the diameter of internal pores, their division, and morphology
Sulfonation reaction can operate at monomer before Meyer M. et al. polymerization or during
post-polymerization. It will affect 2013 the degree of sulfonation and the final ion exchange
capacities of the sulfonated polymer. Most commonly during
Solution
Answer :
Ethanol
Ethanol, C2H5OH, (also called Ethyl Alcohol) is the second member of the aliphatic alcohol
series. It is a clear colourless liquid with a pleasant smell. Except for alcoholic beverages, nearly
all the ethanol used industrially is a mixture of 95% ethanol and 5% water, which is known
simply as 95% alcohol. Although pure ethyl alcohol (known as absolute alcohol) is available, it
is much more expensive and is used only when definitely required.
Preparation
Ethanol is prepared as 95% alcohol (i.e. a 95% solution of ethanol in water) by distillation of the
solution which results from the fermentation of sugars.
Manufacture
There are two major industrial pathways to ethanol. Ethanol which is intended for industrial use
is made by the first method, while ethanol intended for food use tends to be made by the second
method.
Reaction of Ethene with Steam
Most of the ethanol used in industry is made, not by alcoholic fermentation, but by an addition
reaction between ethene and steam.
Alcoholic Fermentation
The fermentation process takes three days and is carried out at a temperature between 250C and
300C. The ethanol is then obtained by fractional distillation..
The ABO and MN blood groups are given below for four sets of parents .pdf
The ABO and MN blood groups are given below for four sets of parents (1 to 4) and four
children (a to d). Recall that the ABO blood group has three alleles, I^A, I^B, and i. The MN
blood group has two codominant alleles, M and N. When all the genetic data is considered
together and by the process of elimination you should be able to match each of the four children
with the correct set of parents.
Solution
Beginning from the first set of parents, let us try to determine the genotype of all sets.
Parents 1: The father can be IBIB or IBi and the mother can be IAIAor IAi. For the MN group,
The father is NN and the mother is MN. So, their children can of A, B, AB or O blood type and
of either MN or N blood group.
Parents 2: The father can be IAIA or IAi and the mother can be IAIAor IAi. For the MN group,
The father is NN and the mother is also NN. So, their children can of A or O blood type and of N
blood group.
Parents 3: The father can be IAIAor IAi and the mother is IAIB. For the MN group, both the
parents are of MN type. So, their children can of A, B, or AB blood type and of either M, N or
MN blood group.
Parents 4: The father is ii and the mother is IAIAor IAi. For the MN group, both the parents are
of MM type. So, their children can of A or O blood type and of M blood group.
Amongst the given set of children only one has the N type blood group. So this child (a)
definitely belongs to the parents who can have children with only N blood group i.e. Parents 2.
For the remaining 3 cases (b, c and d), we want parents with possibility of giving children of M
type blood for children (c) and (d). Parents 1 cannot give an offspring with M type blood group,
so it has to be matched with child (b) where it can easily give AB and MN blood types.
For child (d), Only parents 4 are a match because that is the only set of parents from the
remaining parents which can have a child with O blood group.
That leaves parents 3 to give birth to child (c) with A blood group and M blood type and it is
possible.
So, 1- b, 2- a, 3-c, 4-d.
Table 19.1Table 20.3 Construct an evolutionary history.pdf
Table 19.1
Table 20.3
Construct an evolutionary history using the information in Table 19.1 in Chapter 19 and Table
20.3 Use names. Include only the 4 traits listed in these tables. You will need to lumpsome
organisms of the groups of and some traits. The is a colonial ancestral protist derived is trait
distinguishing from the animals, the the new) t at the end of the branches coming off the main
slanted line. Recall that the progression of evolution (and time) is from bottom to top (outgroup)
(Parazoa) groups here) (5 groups here) (2 animals multicellularity
Solution
Embryonic
Development.
Radial (Adults)
Bilatetal (Larvae)PhylumOrganizationSymmetryGerm layers
Embryonic
Development.PoriferaCellAssymetrical2N/ACnidariaTissueRadial2N/APlatyhelminthsOrganBil
ateral3ProtostomesNematodaOrganBilateral3protostomeMolluscaOrganBilateral (some are
assymetrical)3protostomesAnnelidaOrganBilateral3ProtostomesArthropodaOrganBilateral3Proto
stomesEchinodermataOrgan
Radial (Adults)
Bilatetal (Larvae)3DeuterostomesChordataOrganBilateral3Deuterostomes.
Suppose memory for the address space (process image) is allocated co.pdf
Suppose memory for the address space (process image) is allocated contiguously using dynamic
memory allocation. What extra hardware is needed to generate a physical address and why?
Solution
Memory management is the functionality of an operating system which handles or manages
primary memory and moves processes back and forth between main memory and disk during
execution. Its function i to track whenever some memory gets freed or unallocated .It then
updates the status.There are 2 ways dynamic and static.
dynamic routines of the library are stored on a disk in relocatable form and are loaded into
memory only when they are needed by the program.A reference to the dynamic module is not
used to link the library with the program when dynamic linking is used. Dynamic Link Libraries
(DLL) in Windows and Shared Objects in Unix are examples of dynamic libraries.memory pool
allocation is used. virtual memory may also be used.The Translation Lookaside Buffer (TLB ) is
the main component of the processor responsible for virtual-memory..
Select three methods in the ObjectList class to work through algori.pdf
Select three methods in the ObjectList class to work through algorithmically. Describe any
special cases or boundary conditions that might exist for each of the three methods selected. Be
sure to draw pictures as you work through the methods. Remember that you cannot work on
linked lists without drawing pictures. The homework will not be accepted without submitting the
pictures! Write a Java method with the signature: public objectList intersect (objectList list1,
objectList list2) that accepts two unordered linear linked lists and returns a third linear linked list
whose nodes contains the intersection of the two original linear linked lists. Note that the
intersection of two lists is a new list containing the elements that the two lists have in common,
without modifying the two original lists. Describe any boundary conditions that might exist.
Solution
Node.java
//Defines each node of a linked list
public class Node{
int data;
Node next;
Node(int d)
{
data = d;
next = null;
}
}
ObjectList.java
public class ObjectList{
public Node head;
/* Utility function to print list */
public void printList()
{
Node temp = head;
while(temp != null)
{
System.out.print(temp.data+\" \");
temp = temp.next;
}
System.out.println();
}
/* Inserts a node at start of linked list */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);
/* 3. Make next of new Node as head */
new_node.next = head;
/* 4. Move the head to point to new Node */
head = new_node;
}
/* A utilty function that returns true if data is present
in linked list else return false */
public boolean isPresent (int data){
Node t = this.head;
while (t != null)
{
if (t.data == data)
return true;
t = t.next;
}
return false;
}
}
Intersection.java
//Implements the intersection method.
class Intersection{
static public ObjectList intersect(ObjectList list1, ObjectList list2){
ObjectList result = new ObjectList();
//Node t1 = head1;
Node t1 = list1.head;
Node t2 = list2.head;
// Traverse list1 and search each element of it in list2.
// If the element is present in list 2, then insert the
// element to result
while (t1 != null){
if (list2.isPresent(t1.data))
result.push(t1.data);
t1 = t1.next;
}
return result;
}
/* Driver program to test above functions */
public static void main(String args[]){
ObjectList llist1 = new ObjectList();
ObjectList llist2 = new ObjectList();
ObjectList unin = new ObjectList();
ObjectList intersecn = new ObjectList();
/*create a linked lits 10->15->5->20 */
llist1.push(20);
llist1.push(4);
llist1.push(15);
llist1.push(10);
/*create a linked lits 8->4->2->10 */
llist2.push(10);
llist2.push(2);
llist2.push(4);
llist2.push(8);
intersecn = intersect(llist1, llist2);
intersecn.printList();
}
}.
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