The ABO and MN blood groups are given below for four sets of parents (1 to 4) and four children (a to d). Recall that the ABO blood group has three alleles, I^A, I^B, and i. The MN blood group has two codominant alleles, M and N. When all the genetic data is considered together and by the process of elimination you should be able to match each of the four children with the correct set of parents. Solution Beginning from the first set of parents, let us try to determine the genotype of all sets. Parents 1: The father can be IBIB or IBi and the mother can be IAIAor IAi. For the MN group, The father is NN and the mother is MN. So, their children can of A, B, AB or O blood type and of either MN or N blood group. Parents 2: The father can be IAIA or IAi and the mother can be IAIAor IAi. For the MN group, The father is NN and the mother is also NN. So, their children can of A or O blood type and of N blood group. Parents 3: The father can be IAIAor IAi and the mother is IAIB. For the MN group, both the parents are of MN type. So, their children can of A, B, or AB blood type and of either M, N or MN blood group. Parents 4: The father is ii and the mother is IAIAor IAi. For the MN group, both the parents are of MM type. So, their children can of A or O blood type and of M blood group. Amongst the given set of children only one has the N type blood group. So this child (a) definitely belongs to the parents who can have children with only N blood group i.e. Parents 2. For the remaining 3 cases (b, c and d), we want parents with possibility of giving children of M type blood for children (c) and (d). Parents 1 cannot give an offspring with M type blood group, so it has to be matched with child (b) where it can easily give AB and MN blood types. For child (d), Only parents 4 are a match because that is the only set of parents from the remaining parents which can have a child with O blood group. That leaves parents 3 to give birth to child (c) with A blood group and M blood type and it is possible. So, 1- b, 2- a, 3-c, 4-d.